Answer:
ultrasound tech, insurance building inspecto, pilot who needs to avoid bad weather
Explanation:
A,B,D
The three workers who use technologies that apply the Doppler effect are an ultrasound technician, a race-car mechanic, and a pilot who needs to avoid bad weather.
What is the Doppler effect?A sudden change in the frequency due to the distance between the objects and source is explained by the doppler effect.
As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.
A passing siren's rapid change in pitch, as well as astronomers' redshift, are both caused by this phenomenon.
Applications of the doppler effect;
In various forms of radar, the Doppler effect is utilized to determine the velocity of observed objects.
As it approaches or recedes from the radar source, a radar beam is fired at a moving target. such as an automobile, as police employ radar to identify speeding motorists.
The three workers use technologies that apply the Doppler effect are;
A. An ultrasound technician
C. A race-car mechanic
D. A pilot who needs to avoid bad weather
Hence the three correct options are A, C, and D.
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A source produces 20 crests and 20 troughs in 4 seconds. The second crest is 3 cm away from the first crest.Calculate :
i. Wavelength [ Ans : 3 × \( {10}^{ - 2} \) m ]
ii. Frequency [ Ans : 5 Hz ]
iii. Wave speed [ Ans : 1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \) ]
Show your workings !
*Irrelevant / Random answers will be reported!
Answer:
Solution given:
No of waves[N] =20crests & 20 troughs
=20waves
Time[T]=4seconds
distance[d]=3cm=0.03m
Now
Wave length=3cm=3 × \( {10}^{ - 2}m \)
Frequency=\( \frac{No of waves}{time}\)
=\( \frac{20}{4} \)=5Hertz
and
Wave speed:wave length×frequency=3 × \( {10}^{ - 2}m \)×5=1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \).
The amount of lateral strain in a tension member can be calculated using OA the coeficient of expansion B the moment of inertia OCthe yield stress OD Poisson's rati
The amount of lateral strain in a tension member can be calculated using Poisson's ratio.
To calculate the lateral strain, we can use the equation: ε_lateral = -ν * ε_longitudinal
Where:
ε_lateral = Lateral strain
ν = Poisson's ratio
ε_longitudinal = Longitudinal strain
Poisson's ratio (ν) is a material property that describes the ratio of lateral strain to longitudinal strain when a material is subjected to an axial load. It is defined as the negative ratio of the transverse strain to the longitudinal strain.
Calculating the lateral strain involves determining the longitudinal strain, which can be calculated using the equation:ε_longitudinal = ΔL / L
Where:
ε_longitudinal = Longitudinal strain
ΔL = Change in length of the tension member
L = Original length of the tension member
Once the longitudinal strain is calculated, we can use Poisson's ratio to determine the lateral strain by multiplying the longitudinal strain by the negative value of Poisson's ratio.
It is important to note that the lateral strain is typically very small compared to the longitudinal strain in a tension member, especially for materials with a low Poisson's ratio.
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A 15.00 cm long solenoid with radius 2.50 cm is closely wound with 600 turns of wire. The current in the windings is 8.00 A. What is the magnetic field at a point near the center of the solenoid?
A) 4.80 T
B) 0.006 T
C) 0.4020 T
D) 0.0402 T
The magnetic field at a point near the center of the solenoid can be calculated using the formula B = μ₀ * n * I, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current in the windings.
First, we need to find the number of turns per unit length, which can be calculated by dividing the total number of turns by the length of the solenoid.
n = 600 / 15.00 cm = 40 turns/cm
Next, we need to convert the radius of the solenoid from centimeters to meters, as the unit for permeability is in Tesla meters per ampere (Tm/A).
r = 2.50 cm = 0.025 m
Now we can plug in the values into the formula: B = μ₀ * n * I
B = (4π * 10^-7 Tm/A) * 40 turns/cm * 8.00 A
B = 0.0402 T
Therefore, the magnetic field at a point near the center of the solenoid is 0.0402 T, which corresponds to option D in the given choices.
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An object starts at position -2m with an initial velocity of -4 m/s and a constant acceleration of +3 m/s^2.
a. In which direction is the object traveling initially?
b. What will be the object's velocity after 1s, 2s, 3s?
c. What will the objects position be after 3s?
Answer:
here is the answer
Explanation:
a) since displacement is given as a negative value, object must travelling i the negative direction (with respect to a cartesian plane).
b) after 1 second
v = u + at
v = -4 + 3× 1
v = -4 + 3
v = -1 m/s
after 2 seconds
v = -4 + 3×2
v = -4 + 6
v = 2 m/s
after 3 seconds
v = -4 + 3×3
v = -4 + 9
v = 5 m/s
c) we need to find the position after three seconds
initial velocity= u= -4m/s
final velocity = v= 5 m/s ( as previously calculated)
acceleration=3m/s²
s = ut + 1/2 × at²
s = -4×3 + 1/2 × 3×(3)²
s = -12 + 1/2 × 27
s = -12 + 27/2
s = 1.5 meters ( in the positive direction; as time has increased and acceleration in positive)
position = -2 + 1.5 = -0.5 meters
(s indicates distance travelled)
Find an expression for the maximum tension Tmax for which the small box rides on top of the large box without slipping Express your answer in terms of the variables M, m,, and appropriate constants A large box of mass M is pulled across a horizontal, frictionless surface by a horizontal rope with tension T. A small box of mass m sits on top of the large box. The coefficients of static and kinetic friction between the two boxes are μ, and respectively Subrnit Incorrect Try Again: 5 attempts remaining Part B A horizontal rope pulls a 12 kg wood sled across frictionless snow. A 5.0 kg wood box rides on the sled. What is the largest tension force for which the box doesn't slip? Assume that , 0.50 Express your answer to two significant figures and include the appropriate units. T-Value Units
To find the expression for the maximum tension Tmax for which the small box rides on top of the large box without slipping, we need to consider the forces and friction acting on the system.
The maximum tension Tmax occurs when the static friction between the small box and the large box is at its maximum value. This occurs just before slipping begins.
The static friction force (Fs) can be calculated using the equation Fs ≤ μs * N, where μs is the coefficient of static friction and N is the normal force.
In this case, the normal force N is equal to the weight of the small box, which is given by N = m * g, where m is the mass of the small box and g is the acceleration due to gravity.
Therefore, the maximum tension Tmax can be expressed as Tmax = Fs = μs * N = μs * m * g.
Substituting the given values, where μs = 0.50, m = 5.0 kg, and g ≈ 9.81 m/\(s^2\), we can calculate the maximum tension:
Tmax = (0.50) * (5.0 kg) * (9.81 m/\(s^2\)) ≈ 24.5 N.
Hence, the largest tension force for which the box doesn't slip is approximately 24.5 N.
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A negatively charged balloon touching a wooden wallPulls positive charge on the wall surface toward it Pushed negative charge in a wall away from itPolarizes molecules on the wall All of the above
Given that the balloon is negatively charged and it is touching a wooden wall, the ballon will perform all the actions given in the answer choices.
A negatively charged balloon will pull positive charge on the wall surface towards it, since opposite charges attract each other.
Also, the negatively charged balloon touching a wooden wall will push any negative charge in the wall away from it. This is because like charges repel each other.
The negatively charged balloon also polarizes the molecules on the wall. This is because in molecules, atoms are bonded together since protons in one atom attract the electrons in the cloud of another atom.
Therefore, the correct choice is All of the above
ANSWER:
All of the above
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec2 in the forward direction. What is the net force acting on the automobile?
\(\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}\)
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?
_________________________________________
\(\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}\)
➢ Mass of the automobile = 1250 kg➢ Acceleration of the body = 4m/sec²_________________________________________
\(\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}\)
Net force acting on the automobile = ?_________________________________________
\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}\)
➯ Force is defined as the product of the mass of the body and its acceleration.
\( \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}\)
Where :
F = Force m = Mass of the bodya = acceleration due to gravity\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}\)
\(⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}\)
\(⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}\)
\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}\)
❝ The net force acting on the automobile is 5000 N. ❞
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
place in chronological order the material cultures of the upper paleolithic.
Cultural phases can overlap in different regions, and regional variations and local cultural developments may also exist within each period.
The Upper Paleolithic is a period of prehistoric human history that occurred approximately between 50,000 and 10,000 years ago. During this time, various material cultures emerged and evolved. While the specific chronology can vary depending on the region, here is a general chronological order of the material cultures of the Upper Paleolithic:
Initial Upper Paleolithic (50,000 - 40,000 years ago): This phase marks the transition from the Middle Paleolithic to the Upper Paleolithic. It is characterized by the emergence of anatomically modern humans (Homo sapiens) and the development of more sophisticated stone tools, including blades and bladelets.Aurignacian (40,000 - 28,000 years ago): The Aurignacian culture iassociated with the earliest Homo sapiens in Europe. It is characterized by the production of finely crafted tools made from bone, antler, and ivory. Artistic expression, such as cave art and personal adornments like beads, also emerged during this period.
Gravettian (28,000 - 22,000 years ago): The Gravettian culture is known for its innovative stone tools, including the widespread use of microliths. They created highly efficient hunting implements, such as harpoons and spear-throwers. Sculptures and engravings on bone and ivory are common in Gravettian archaeological sites.Solutrean (22,000 - 17,000 years ago): The Solutrean culture is characterized by the development of sophisticated stone tools, including finely crafted spear points with a distinctive leaf shape. They were skilled hunters, and their artifacts show evidence of pressure flaking and retouching techniques.
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What would be the mass of the same object on the moon, where gravity is one sixth of Earth gravity?
a train of length 200m passes over a bridge of length 600m how long does it take to cross the bridge with a uniform speed of 36kmph?
80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
Given data,
length of bridge = 600m
length of train = 200m
Length of bridge + Length of train is the total distance travelled by train to cross the bridge.
So, 600+200 = 800m = 0.8km
Now, applying the formula for time,
\(time =\frac{distance}{speed}\)
\(time = \frac{0.8}{36}\)
time = 0.022hours
time in seconds= 0.022×60×60
time in seconds= 1.33×60
time in seconds= 80seconds
Therefore, 80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
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Which of these statements does not describe electricity? (Apex)
a. Chaotic
b. Renewable
c. Unpredictable
d. Conductive
The statement that does not describe electricity is d. Conductive.
Electricity is a fundamental force of nature that is characterized by certain properties and behaviors. While conductive materials allow the flow of electricity, it is important to note that not all conductive materials are electricity themselves. Conductivity refers to the ability of a substance to transmit an electric current, but it does not encompass the complete nature of electricity.
Electricity can be defined as the flow of electric charge, typically carried by electrons, through a conductor. It is not inherently chaotic, as it follows specific laws and principles, such as Ohm's Law, which describes the relationship between current, voltage, and resistance. Furthermore, electricity can be harnessed and controlled for various applications, such as generating power or powering electronic devices, which demonstrates its predictability.
Additionally, electricity is not considered renewable or non-renewable, as these terms are more commonly associated with energy sources. Electricity can be generated from both renewable sources like solar, wind, and hydroelectric power, as well as non-renewable sources like fossil fuels or nuclear energy. Therefore, the statement "b. Renewable" does not exclude electricity.
In summary, the statement "d. Conductive" does not describe electricity because conductivity refers to the ability of a substance to transmit an electric current, while electricity itself encompasses broader properties and behaviors. It is not chaotic, can be predicted, and can be generated from both renewable and non-renewable sources.
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Given a helicopter flying up and sideways at a velocity of 95 m/s at an angle of 35º to the ground, find the horizontal component of the velocity.
Answer:
The horizontal component of the velocity of the helicopter is approximately 77.82 m/s
Explanation:
The given parameters are;
The speed of the helicopter, v = 95 m/s
The angle in which the helicopter is flying = 35° to the ground
The horizontal component of the velocity is given by the component of the magnitude, R, of the velocity of the helicopter in the x-direction as follows;
\(v = \sqrt{v_x^2 + v_y^2}\)
Where;
vₓ = v × cos(θ) = The horizontal component
\(v_y = v \times sin(\theta)\) = The vertical component
∴ The horizontal component of the velocity, vₓ, of the helicopter with 95 m/s velocity moving at an angle of 35° to the horizontal is given as follos
vₓ = 95 × cos(35°) ≈ 77.82 m/s
The horizontal component of the velocity of the helicopter ≈ 77.82 m/s.
An observer recorded the following data for the motion of a car undergoing constant acceleration. What was the magnitude of the acceleration of the car?.
The magnitude of the acceleration of the car from the recorded the following data for the motion of a car undergoing constant acceleration is 2 m/s².
Acceleration is the term used to describe the rate of change in velocity.
Acceleration a = (V f - V₀)/ (t f - t₀)
where, V f is the final velocity
V₀ is the initial velocity
t f is the final time
t₀ is the initial time
Using the first two rows of the table in the attachment, we have,
a = (6 - 4)/(4 - 3) = 2/1 = 2 m/s²
Thus, the required magnitude of the acceleration of the car from the recorded the following data for the motion of a car undergoing constant acceleration is 2 m/s².
The given question is incomplete. The complete question is given in the attachment below.
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what is the acceleration of a box weighing 666N if a force of 777N is applied to it
Answer:
6.67
Explanation:
force=mass*gravity(10)
666/10=66.6
777/66.6=11.6666667
round off
Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 106 m from earth's center.
Answer:
\(F=683.790939\)N
Explanation:
From the Question we are told that
Earth mass \(m_1= 5.98 * 10^2^4 kg\)
Students mass \(m_2=70kg\)
Distance of student from earth center Radius \(r=6.39 * 10^6 m\)
Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by
\(F=\frac{Gm_1m_2}{r^2}\)
\(F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}\)
Therefore the force of attraction b/w the student and the earth is
\(F=683.790939N\)
\(F\approx 684N\)
why are cepheid variables so important for measuring distances in astronomy?
Cepheid variables are crucial for measuring distances in astronomy.
Cepheid variables are a type of pulsating star that undergoes regular changes in brightness over time. The period of their brightness variations is directly related to their intrinsic luminosity, meaning that brighter Cepheids have longer periods.
This relationship, known as the period-luminosity relationship, allows astronomers to use Cepheids as "standard candles" for distance measurements. By measuring the period of a Cepheid and comparing it to its observed brightness, astronomers can determine its intrinsic luminosity and then calculate its distance using the inverse square law.
Since Cepheids are observable in distant galaxies, they serve as reliable distance indicators and have played a vital role in determining the scale of the universe and studying cosmic expansion.
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Cepheid variables are important in astronomy due to their unique period-luminosity relationship allowing astronomers to measure stellar distances. This relation has helped in the discovery of the universe's expansion and breaking the distance confines of parallax, aiding exploration into more distant parts of our Galaxy and others.
Explanation:Cepheid variables are important for measuring distances in astronomy due to their unique period-luminosity relationship. The
period-luminosity relation
states that the longer the period (the time it takes for the star to vary), the greater the luminosity (brightness) of the Cepheid variable star is. This relationship is essential as it allows astronomers to measure the distance of these stars once the period has been determined.
To initially define this relationship with actual numbers, astronomers had to measure distances to a few nearby Cepheids in a different way, typically by finding Cepheids in clusters with stars whose distances could be estimated using spectral analysis. Once this period-luminosity relation was calibrated, it could be used to estimate the distance of any Cepheid, regardless of its location.
Cepheids have become crucial markers in space, acting as cosmic signposts. For instance, in the 1920s, Edwin Hubble used Cepheid variables to discover the expansion of the universe. They have been instrumental in breaking the distance confines of parallax, allowing astronomers to explore more distant parts of our Galaxy and others.
Today, the search continues with modern instruments including the Hubble Space Telescope, identifying and measuring individual Cepheids in galaxies farther and farther away. Some Cepheids are known to be about 60 million light-years away.
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The consumers of bottled water often do not dispose of the empty plastic bottles responsibly. Millions of throw away plastic water bottles end up in landfills and in the ocean, creating huge environmental damage. The government is constantly engaged in finding solutions to this environmental issue. a. Identidfy the economic concept that will explain the damage created by thrown away empty plastic water bottles. b. Analyse the market situation given above using the economic concept you identified in part a. Hint: explain the relevant economic concept and apply the key aspects of it to the given market situation. c. Describe two solutions available to the government to correct this environmental issue d. Explain how these solutions will correct the given situation.
The government can address the environmental damage caused by thrown-away plastic water bottles through solutions such as implementing a deposit and return system or imposing taxes, which incentivize responsible behavior, reduce plastic waste, and mitigate negative externalities.
a. The economic concept that explains the damage created by thrown-away empty plastic water bottles is "negative externality."
b. Negative externality occurs when the production or consumption of a good or service imposes costs on third parties who are not involved in the transaction. In this case, the irresponsible disposal of plastic water bottles creates environmental damage, such as pollution in landfills and oceans, affecting society as a whole. It is a market failure because the private cost of producing and consuming bottled water does not include the full social cost of the resulting environmental damage.
The market situation in this context involves a divergence between private and social costs. Consumers of bottled water do not bear the full cost of the environmental damage caused by the improper disposal of plastic bottles. Consequently, the market equilibrium for bottled water fails to account for the negative externalities imposed on society.
c. Two solutions available to the government to correct this environmental issue are:
Implementing a plastic bottle deposit and return system: The government can establish a system where consumers pay an additional deposit fee when purchasing plastic water bottles, which is refunded when they return the empty bottles to designated collection points. This incentivizes consumers to return the bottles for recycling or proper disposal, reducing environmental damage.
Imposing taxes or levies on plastic water bottles: The government can impose taxes or levies on the production or consumption of plastic water bottles. This increases the cost of bottled water, reflecting the social cost of environmental damage. The additional revenue generated from these taxes can be used to fund environmental conservation and recycling programs.
d. These solutions will correct the given situation by internalizing the external costs associated with plastic water bottle consumption. By implementing a deposit and return system or imposing taxes, consumers are incentivized to act responsibly by returning the bottles or opting for alternative packaging options. This reduces the amount of plastic waste in landfills and oceans, mitigating environmental damage.
The deposit and return system encourages recycling and reuse of plastic bottles, reducing the need for new bottle production and decreasing overall plastic waste. The taxes or levies increase the price of bottled water, making alternatives like reusable bottles or tap water more economically attractive. The revenue generated from these taxes can be utilized for environmental initiatives such as recycling infrastructure, public awareness campaigns, and research and development of sustainable packaging materials.
Therefore, by internalizing the negative externalities associated with plastic water bottle consumption, these solutions promote responsible behavior, reduce plastic waste, and mitigate the environmental damage caused by improper disposal.
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what can be respresented by a force arrow weight or mass
Answer:
Force arrows are used to represent both the magnitude and direction of forces. The length of the arrow corresponds to the magnitude of the force, with longer arrows indicating forces with larger magnitudes. The direction of the arrow corresponds to the actual direction that the force is being exerted. Force arrows are used by scientists and engineers to predict the motion of an object based on the forces that are applied to it.
Let's go back to Amil and his box for a moment. To represent the force that he is exerting on the box, we can draw the box and then show the force using a force arrow, like this:
Explanation:
How would our force arrow change if he pushed the box with twice as much force? Because the magnitude of the force is doubled, the length of the force arrow should also be doubled.
Now, what if he didn't push directly to the right, but instead his arms made a 30-degree angle with the ground? In that case, the direction of the force arrow needs to change to show the direction in which the force is applied.
why does lowered air pressure allow water to boil at room temperature
Answer:
As ambient air pressure decreases, molecules evaporating from a boiling liquid meet less resistance from air molecules and enter the air more easily. Because the vapor pressure can be reduced, the temperature needed to boil the liquid is also reduced.
Explanation:
Answer:
Less force pushes down on the liquid, making it easier for gas to escape.
Explanation:
I hope this helps and have a great day!
Which of the following frequencies produces the highest pitched
sound?
a 150 Hz
b 420 Hz
680 Hz
d 870 Hz
e None of the above
Answer:
d: 870 Hz
Explanation:
I need help ASAP pls be right sn know what your doing
Answer: Biology
This is because the first two make no sense and physics is the study of matter and energy. Biology, however, studies the life of plants and animals, which can be used for renewable energy.
Activity 3: musical instruments of mindanao ((moro/islamic musie))
write the different musical solo instruments and musical ensembles in mindanao instrumental music.
bamboo ensemble
kulintang ensemble
membranophones:
1.
2.
1.
2.
3.
metallophones:
1.
2.
3.
4.
5.
string/chordophones
1.
solo instruments
aerophones
1.
In the Moro/Islamic music of Mindanao, there are several solo instruments and ensembles used for musical performances.
Here are some of them:
Musical Ensembles:
1. Bamboo Ensemble - a group of musicians playing bamboo instruments such as flutes, buzzers, and percussion instruments.
2. Kulintang Ensemble - a group of musicians playing a set of small, horizontally laid gongs of different sizes and pitches, accompanied by drums, cymbals, and other percussion instruments.
Membranophones:
1. Dabakan - a large, single-headed cylindrical drum played with both hands.
2. Gandingan - a single-headed, cylindrical drum played with a single stick.
3. Agung - a large, double-headed gong played with a stick.
Metallophones:
1. Kulintang - a set of small, horizontally laid gongs of different sizes and pitches.
2. Gandingan - a set of four large, vertically hung gongs.
3. Agung - a set of two large, double-headed gongs.
4. Sarunay - a small, vertically hung gong.
5. Babandil - a small, single-headed gong.
String/Chordophones:
1. Kudyapi - a two-stringed lute played with a plectrum.
Solo Instruments:
1. Suling - a bamboo flute played solo or in an ensemble.
2. Kulintang a Tiniok - a small, handheld gong played solo or in an ensemble.
Aerophones:
1. Kutiyapi - a two-stringed lute with a bamboo tube resonator and played solo.
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quizlet According to the Stefan-Boltzman law, how does a small change in temperature impact the energy emitted by an object
The Stefan-Boltzman law states that the energy emitted by an object increases with the fourth power of the temperature and that the emitted radiation is proportional to the surface area of the object.
The Stefan-Boltzman law states that the power of radiation emitted by an object is proportional to the fourth power of the absolute temperature of the body. The formula for the Stefan-Boltzman law is given below:
P = σAT⁴
Where,σ is the Stefan-Boltzman constant A is the surface area of the object T is the temperature of the object in Kelvin P is the power of radiation emitted by the object
Therefore, a small change in temperature of an object according to Stefan-Boltzman's law impacts the energy emitted by an object significantly and it increases with the fourth power of the temperature.
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Which of these neutron stars must have had its angular momentum changed by a binary companion? (a) a pulsar that pulses 30 times per second (b) a pulsar that pulses 600 times per second (c) a neutron star that does not pulse at all.
The neutron star that pulses 600 times per second must have had its angular momentum changed by a binary companion.
Neutron stars that pulse are known as pulsars and their pulses are caused by their rotation. The rate of pulsation is directly related to the neutron star's angular momentum. A pulsar that pulses faster must have a smaller radius and higher angular velocity than a pulsar that pulses slower.
Therefore, a pulsar that pulses 600 times per second must have a very small radius and high angular velocity, which can only be achieved by a change in its angular momentum. The most likely cause of this change in angular momentum is a binary companion transferring angular momentum to the pulsar.
In conclusion, a neutron star that pulses 600 times per second is the one that must have had its angular momentum changed by a binary companion.
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Two pieces of the same glass are covered with thin films of different materials. In reflected sunlight, however, the film have different colors. Why? a. The films could have the same thickness, but different refractive indices. b. The films could have different thicknesses, but the same refractive indices.
The interference of light waves causes the observed variation in colors when the films are subjected to Reflected sunlight.
The reason two pieces of the same glass covered with thin films of different materials appear to have different colors in reflected sunlight is because of the interference of light waves. This phenomenon can occur due to two factors:
The films could have the same Thickness, but different refractive indices. Different refractive indices cause the light waves to interact differently, leading to the interference that produces various colors.
The films could have different thicknesses, but the same refractive indices. In this case, the difference in thickness results in different path lengths for the light waves, which also leads to the interference and the appearance of different colors.
In both cases, the interference of light waves causes the observed variation in colors when the films are subjected to reflected sunlight.
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A car accelerates from rest at 7.2 m/s 2 . How much time does it need to attain a speed of 4 m/s? Answer in units of s.
Answer:
The time is 0.6 sec.
Explanation:
Given that,
Acceleration of car = 7.2 m/s²
Speed = 4 m/s
We need to calculate the time
Using equation of motion
\(v=u+at\)
Where, u = initial velocity
v = final velocity
a = acceleration
t = time
Put the value in the equation
\(4=0+7.2\times t\)
\(t=\dfrac{4}{7.2}\)
\(t=0.6\ sec\)
Hence, The time is 0.6 sec.
In fig. p6.110 the pipe entrance is sharp-edged. if the flow rate is 0.004 m3/s, what power, in w, is extracted by the turbine?
The power extracted by the turbine can be calculated by multiplying the flow rate of 0.004 m3/s with the appropriate fluid power equation.
To determine the power extracted by the turbine, we need to use the fluid power equation. The fluid power equation relates the flow rate of a fluid, the pressure difference across the turbine, and the power extracted. In this case, we are given the flow rate of 0.004 m3/s.
To calculate the power, we need additional information such as the pressure difference or head across the turbine. Without this information or any additional context provided, it is not possible to directly determine the power extracted by the turbine.
The power extracted by a turbine is influenced by various factors, including the design of the turbine, the efficiency of the turbine, and the specific properties of the fluid being used. These factors would need to be considered and additional information provided to accurately calculate the power extracted.
It is important to note that the power extracted by the turbine represents the energy being converted from the fluid flow into mechanical work. The efficiency of the turbine will also play a role in determining the actual power output.
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The eficiency of a
simple machine can never be 100% why?
Answer:
Systems always tend toward a state of decreasing order unless more energy is provided into the system to counteract this tendency.
Which two of the following are the waste products of anaerobic
respiration in yeast?
A sugar
B carbon dioxide
C water
D ethanol
for the following stress states, sketch the stress element, draw the appropriate mohr’s circle, determine the prin- cipal stresses and their directions, and sketch the princi- pal stress elements
The maximum shear stress at 18 degrees and the primary stress, respectively, are both 36.05 mpa.
The Mohr method is a very useful tool for finding primary stress, maximum shear stress, principle plane, or angle of the action. It is a technique that plots a circle using a graphical way in order to gather the necessary information.
Shear stress= 30
Tensile stress= 40
Compressive Stress= -40
Mohr circle using data is:
Figure
And the principal stress will be 36.05 mpa and maximum shear stress would be 36.05 mpa at 18 degrees.
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