Plz help don’t understand

Answer:

There are 6 zeros in one million.

Step-by-step explanation:

1000000 (one million)

6 zeros

The steps of the analytical problem-solving model include: identifying the problem, exploring alternatives, building an implementation plan, implementing a solution, and evaluating the situation.

Analytical problem solving, as we've defined it above, refers to the approaches and methods you use rather than the particular issue you're trying to resolve.

Analytical issue solving is a crucial prerequisite for problem resolution; the problem itself does not determine whether you need it.

Analytical problem solving involves recognising a problem, investigating it, and then creating ideas (such as causes and solutions) around it.

Solving analytical problems calls for inquiry, examination, and analysis that encourages additional study of the subject (including causality, symptoms, and solution).

According to the steps involved in analytical problem solving model:

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Answer:

Step-by-step explanation:

Before we begin this, there are a few things that need to be said and a few formulas you need to know. First is that we need to use the work form of a parabola, which is

\(y=a(x-h)^2+k\)

All of the parabolas listed in blue highlight open either up or down, and this work form represents those 2 options. The only thing we need to know is that if there is a negative sign in front of the a, the parabola opens upside down like a mountain instead of up like a cup.

Another thing we need to know is how to find the focus of the parabola. The formula to find the focus for an "up" parabola is (h, k + p) and the formula to find the focus for an upside down parabola is (h, k - p). Then of course is the issue on how to find the p. p is found from the a in the above work form parabola, where

\(p=\frac{1}{4|a|}\) .

In order to accomplish what we need to accomplish, we need to put each of those parabolas into work form (as previously stated) by completing the square. I'm hoping that since you are in pre-calculus you have already learned how to complete the square on a polynomial in order to factor it.  Starting with the first one, we will complete the square. I'll go through each step one at a time, but will provide no explanation as to how I got there (again, assuming you know how to complete the square).

\(y=-x^2+4x+8\) and, completing the square one step at a time:

\(-x^2+4x=-8\) and

\(-(x^2-4x+4)=-8-4\) and

\(-(x-2)^2=-12\) and

\(-(x-2)^2+12=y\)

From this we can see that the h and k values for the vertex are h = 2 and k = 12. Now to find p.

\(|a|=1\), ∴

\(p=\frac{1}{4(1)}=\frac{1}{4}\)

Using the correct focus formula (h, k - p), we get that the focus is

\((2, 12-\frac{1}{4})\) which simplifies to (2, 11.75) which is choice 2 in your options.

Now for the second one (yes, this takes forever...)

\(y=2x^2+16x+18\) and completing the square one step at a time:

\(2x^2+16x=-18\) and

\(2(x^2+8x+16)=-18+32\) and

\(2(x+4)^2=14\) and

\(2(x+4)^2-14=y\)

From this we can see that the vertex is h = -4 and k = -14. Now to find p from a.

\(|a|=2\), ∴

\(p=\frac{1}{4(2)}=\frac{1}{8}\) .

Using the correct focus formula for an upwards opening parabola (h, k + p),

\((-4, -14+\frac{1}{8})\) which simplifies down to (-4, -13.875) which is choice 3 in your options.

Now for the third one...

\(y=-2x^2+5x+14\) and completing the square step by step:

\(-2x^2+5x=-14\) and

\(-2(x^2-\frac{5}{2}x+\frac{25}{16})=-14-\frac{50}{16}\) and

\(-2(x-\frac{5}{4})^2=-\frac{137}{8}\) and

\(-2(x-\frac{5}{4})^2+\frac{137}{8}=y\)

From that we can see the vertex values h and k. h = 1.25 and k = 17.125. Now to find p.

\(|a|=2\), ∴

\(p=\frac{1}{4(2)}=\frac{1}{8}\)

Using the correct focus formula for an upside down parabola (h, k - p),

\((1.25, 17.125-\frac{1}{8})\) which simplifies down to (1.25, 17) which is choice 4 in your options.

Now for the fourth one...

\(y=-x^2+17x+7\) and completing the square step by step:

\(-x^2+17x=-7\) and

\(-(x^2-17x)=-7\) and

\(-(x^2-17x+72.25)=-7-72.25\) and

\(-(x-8.5)^2=-79.25\) and

\(-(x-8.5)^2+79.25=y\)

From that we see that the vertex is h = 8.5 and k = 79.25. Now to find p.

\(|a|=1\), ∴

\(p=\frac{1}{4(1)}=\frac{1}{4}\)

Using the correct formula for an upside down parabola (h, k - p),

\((8.5, 79.25-\frac{1}{4})\) which simplifies down to (8.5, 79) and I don't see a choice from your available options there.

On to the fifth one...

\(y=2x^2+11x+5\) and again step by step:

\(2x^2+11x=-5\) and

\(2(x^2+\frac{11}{2}x+\frac{121}{16})=-5+\frac{242}{16}\) and

\(2(x+\frac{11}{4})^2=\frac{81}{8}\) and

\(2(x+\frac{11}{4})^2-\frac{81}{8}=y\)

from which we see that h = -2.75 and k = -10.125. Now for p.

\(|a|=2\), ∴

\(p=\frac{1}{4(2)}=\frac{1}{8}\)

Using the correct focus formula for an upwards opening parabola (h, k + p),

\((-2.75, -10.125+\frac{1}{8})\) which simplifies down to (-2.75, -10) which is choice 1 from your options.

Now for the last one (almost there!):

\(y=-2x^2+6x+5\) and

\(-2x^2+6x=-5\) and

\(-2(x^2-3x+2.25)=-5-4.5\) and

\(-2(x-1.5)^2=-9.5\) and

\(-2(x-1.5)^2+9.5=y\)

from which we see that h = 1.5 and k = 9.5. Now for p.

\(|a|=2\), ∴

\(p=\frac{1}{4(2)}=\frac{1}{8}\)

Using the formula for the focus of an upside down parabola (h, k - p),

\((1.5, 9.5-\frac{1}{8})\) which simplifies down to (1.5, 9.375) which is another one I do not see in your choices.

Good luck with your conic sections!!!

Answer:

\(x = \sqrt{ {16}^{2} + {21}^{2} } = \sqrt{256 + 441} = \sqrt{697} = 26.4\)

Answer:

The measure of angle C is 180 - 3α

Step-by-step explanation:

Given;

triangle ABC, ΔABC

angle A, ∠A  = α

angle B, ∠B = 2α

To calculate angle C, we must recall that, the sum of angles in a triangle is equal to  180°. Angle A, angle B, and angle C make up the total angle in the triangle.

∠A + ∠B  + ∠C = 180

where

∠C  is angle C

α + 2α + ∠C = 180

3α  + ∠C  = 180

∠C = 180 - 3α

∠C = 3(60 - α)

Therefore, the measure of angle C is 180 - 3α

Answer:

180°-3a

Step-by-step explanation:

YOU HAVE TO INSERT DEGREES SYMBOL

Answer:

$1772.10

Step-by-step explanation:

10% = 0.1

Take 1611 times 0.1 = $161.10

So, the 10% cheaper is $161.10

We add both numbers to find the price of last year's season ticket!

1611 + 161.10 = $1772.10

So, the price of last year season's ticket is $1772.10

Let's check to see if it is correct!

$1772.10 - $161.10 = $1611

So, my answer is correct!

Answer:

$1,790

Step-by-step explanation:

x -.1x = 1611  Combine like terms

.9x = 1611  Divide both sides by .9

x = 1790

Check:

1790 - .1(1790) = 1611

1790 - 179 = 1611

1611 = 1611

The probability distribution of all possible values of the sample mean is called the sampling distribution of the mean.

What is meant by the sampling distribution of the mean?

Why is sampling essential and what does it mean?

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\(sin^{-1} (sin(x)) = x\) is not always true, but sin(sin^{-1} (x)) = x is always true.

Suppose that f and g are two functions with domains Df and Dg, respectively, and codomains Rf and Rg, respectively. They are inverse functions if and only if:

f(g(x)) = x for all x ∈ Dg

g(f(x)) = x for all x ∈ Df

If these conditions are fulfilled, then the function g is known as the inverse function of f, or the function f is said to be invertible, and g is usually expressed as f-1(x) or inv(f)(x).

Therefore, sin^{-1}   and sin^{-1}  are inverse functions since

\(sin(sin^{-1} (x)) = x and sin^{-1} (sin(x)) = x\) are always true

However, \(sin^{-1} (sin(x)) = x\) is not always true.

To illustrate this, consider the following example:

if x = 7π/6, then sin(x) = sin(π/6)

= 1/2,

and \(sin^-1(sin(x)) = sin^-1(1/2) = π/6;\)

but \(sin^{-1} (sin(x)) ≠ x since π/6 ≠ 7π/6.\)

Thus, \(sin^{-1} (sin(x)) = x\) is not always true, but sin(sin^{-1} (x)) = x is always true.

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There were 204 participants from the three schools

The given parameters are:

X = 12 + Y

X = Z - 18

Girls = Boys + 50

The ratios of the number of boys to girls in the schools are:

1 : 2

1 : 5

2 : 1

This means that:

So, we have:

Boys = 1/3X + 1/6Y + 2/3Z

Girls = 2/3X + 5/6Y + 1/3Z

Substitute the above equations in Girls = Boys + 50

2/3X + 5/6Y + 1/3Z = 1/3X + 1/6Y + 2/3Z + 50

Evaluate the like terms

1/3X + 2/3Y - 1/3Z = 50

Multiply through by 3

X + 2Y - Z = 150

So, we have:

X = 12 + Y

X = Z - 18

X + 2Y - Z = 150

Substitute X = 12 + Y in X = Z - 18 and X + 2Y - Z = 150

12 + Y = Z - 18 ⇒ Y - Z = 30

12 + Y + 2Y - Z = 150 ⇒ 3Y - Z = 138

Subtract Y - Z = 30 from the equation 3Y - Z = 138 to eliminate Z

2Y = 108

Divide by 2

Y = 54

Substitute Y = 54 in X = 12 + Y

X = 12 + 54

X = 66

Substitute X = 66 in X = Z - 18

66 = Z - 18

Solve for Z

Z = 66 + 18

Z = 84

So, the total number of participants from the 3 schools is

Total = X + Y + Z

This gives

Total = 66 + 54 + 84

Evaluate the sum

Total = 204

Hence, there were 204 participants from the three schools

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Answer:

x= 2

Step-by-step explanation:

area= 1/2*length*breadth

       = 1/2*5*breadth

       = 5 units^2  

Let breadth be b.

1/2*5*b= 5

2.5b= 5

b= 2

x= 2 units

The measure of m∠JKL is found to be 22 degrees.

From the given question we are given the following:

Exterior angle

m ∠ J K L = ( 5 x − 3 )°

Interior angles;

m∠KIJ=(2x+8)°

m∠IJK=(x−1)°

Note that the sum of interior angles is equal to the exterior angles;

Hence, m∠KIJ +m∠IJK = m∠JKL

Substitute the given values;

2x+8 + x -1 = 5x - 3

3x + 7 = 5x - 3

Collect like terms;

3x - 5x = -3-7

-2x = -10

x = 10/2

x = 5

Get m∠JKL;

m∠JKL = 5x - 3

m∠JKL= 5(5)-3

m∠JKL = 25-3

m∠JKL = 22°

∴ Hence the measure of m∠JKL is 22 degrees.

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Answer:

($20/gal)r + ($30/gal)b ≤ $250

r + b ≤ 10 (gallons)

Step-by-step explanation:

Represent the amount of red paint by r and that of blue point by b.

Olivia must cover 5000 ft^2 with paint, which comes out to 5000/500, or 10, gallons total of red and blue paint.  The corresponding inequality is

r + b ≤ 10 (gallons)

She has onlyl $250 to spend.  Therefore, the following must hold true:

($20/gal)r + ($30/gal)b ≤ $250

The required sysstem of inequalities is thus

($20/gal)r + ($30/gal)b ≤ $250

r + b ≤ 10 (gallons)

Answer:

81 degrees

Step-by-step explanation:

Because of exterior angles u=u-41+u-40

Solve:

u=2u-81

0=u-81

u=81

I can't make out what the radius of the sphere is, but the equation you're looking for is:

\(V=\frac{4}{3}\pi r^3\)

For example:

If the radius of a sphere is 5 m, it's volume would be,

\(V=\frac{4}{3}\pi (5)^3\)

\(V=\frac{4}{3} (3.14)(5)^3\)

\(V=\frac{4}{3}(3.14)(125)\)

\(V=523.6 m^3\)

Answer:

Step-by-step explanation:

(a) and (b) see diagram

(c) you can see from the graph, the purple line hits the parabola twice which is y=6   or k=6

(d)  Solving simultaneously can mean to set equal

6x - x² = k                        >subtract k from both sides

6x - x² - k = 0                  >put in standard form

- x² + 6x - k = 0               >divide both sides by a -1

x² - 6x + k = 0

(e) The new equation is the same as the original equation just flipped (see image)

(f)  The discriminant is the part of the quadratic equation that is under the root. (not sure if they wanted the discriminant of new equation or orginal.  I chose new)

discriminant formula = b² - 4ac

equation:   x² - 6x + 6 = 0            a = 1      b=-6    c = 6

discriminant = b² - 4ac

discriminant= (-6)² - 4(1)(6)

discriminant = 36-24

discriminant = 12

Because the discriminant is positive, if you put it back in to the quadratic equation, you will get 2 real solutions.

Answer: One newton-meter is equal to 8.8507457676 inch pounds.

Step-by-step explanation:

As a simple example, if you wish to convert 5 newton-meters into inch pounds, you should multiply 5 by 8.8507457676 to give you a total of 44.253728838 inch pounds (or 44.254 rounded to 3 decimal places).

One newton-meter is equal to 8.8507457676 inch pounds.

What is nanometer ?

A nanometer (NM) is a unit of size this is equal to at least one billionth of a meter. it's miles extensively used as a scale for building tiny, complex, and atomic scale computing and digital additives - mainly in nanotechnology

As a simple example, if you wish to convert 5 newton-meters into inch pounds,

you should multiply 5 by 8.8507457676 to give you a total of 44.253728838 inch pounds (or 44.254 rounded to 3 decimal places).

Therefore, One newton-meter is equal to 8.8507457676 inch pounds.

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The linear velocity in MILES PER HOUR of the tip of a lawnmower blade pinning at 2700 revolution per minute in a lawnmower that cut a path that is 30 inches wide, is 0.134 miles per hour.

A lawnmower with a blade turning at 2700 revolutions per minute and cutting a 30-inch-wide swath.

f = 2700/30

f = 90

The frequency is 90 revolution per hours.

When converting from minutes to hours, there are 90 revolutions every hour.

The angular velocity(ω) = 2πf

ω = 2 × 3.14 × 90

ω = 565.2 rad/hr

The diameter of the circle centered at the blade's middle determines the path's breadth.

Diameter = 30

So, Radius = Diameter/2

Radius = 30/2

Radius = 15 inches

Inches to miles conversion

1 inch = 1.57828e^{-5}

15 inches = 15 × 1.57828e^{-5}

15 inches = 0.000236742 miles

Velocity is provided by,

V = ω × Radius

V = 565.2 × 0.000236742

V = 0.1338065784

V = 0.134

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Answer:

Length of one of the shorter congruent side is: 6 cm

Step-by-step explanation:

In order to find the length of congruent sides we have to solve the system of equations

Given systems of equation is:

y = x + 2

2x + 3y = 36

Putting y = x+2 in second equation

\(2x + 3(x+2) = 36\\2x+3x+6 = 36\\5x+6 = 36\\5x = 36-6\\5x = 30\\\frac{5x}{5} = \frac{30}{5}\\x =6\)

As we know that x represents the shorter side, the length of short side is: 6 cm

Hence,

Length of one of the shorter congruent side is: 6 cm

Answer:

5 servings

Step-by-step explanation:

there is not enough juice for 6 or more servings

Answer:

c

Step-by-step explanation:

Answer:

C

1 or more includes from the 1st quartile to the rest of the graph, so it is 75%

Semi perimeter:-

\(\\ \rm\rightarrowtail s=\dfrac{a+b+c}{2}\)

\(\\ \rm\rightarrowtail s=\dfrac{1.8+2.4+3}{2}\)

\(\\ \rm\rightarrowtail s=\dfrac{7.2}{2}=3.6cm\)

Apply heron s formula

Area:-

\(\\ \rm\rightarrowtail \sqrt{s(s-a)(s-b)(s-c)}\)

\(\\ \rm\rightarrowtail \sqrt{3.6(3.6-1.8)(3.6-3)(3.6-2.4)}\)

\(\\ \rm\rightarrowtail \sqrt{3.6(1.8)(0.6)(1.2)}\)

\(\\ \rm\rightarrowtail \sqrt{4.6656}\)

\(\\ \rm\rightarrowtail 2.16cm^2\)

Answer:

\(\sf Area \ of \ a \ Triangle=\dfrac12bh\)

(where b is the base of the triangle and h is the height)

Given:

Substitute the given values into the formula:

\(\sf \implies Area=\dfrac12 \cdot 2.4 \cdot 1.8\)

               \(\sf =2.16 \ cm^2\)

Answer:

5) 2(4 - n) = -3n

2 × 4 - 2 × n = -3n

8 - 2n = -3n

-2n + 3n = -8

1n = -8

n = -8/1

n = -8

6) 5 - 3(2 + 2w) = -7

5 - 3 × 2 + -3 × 2w = -7

5 - 6 - 6w = -7

-1 - 6w = -7

-6w = -7 + 1

-6w = -6

w = -6/-6

w = 1

7) 5(2r + 3) - 5 = 0

5 × 2r + 5 × 3 - 5 = 0

10r + 15 - 5 = 0

10r + 10 = 0

10r = -10

r = -10/10

r = -1

8) 3 - 5(2d - 3) = 4

3 - 5 × 2d - 5 × -3 = 4

3 - 10d + 15 = 4

-10d + 15 + 3 = 4

-10d + 18 = 4

-10d = 4 - 18

-10d = -14

d = -14/-10

d = 7/5

hope this helps you!!

Answer:

x² + y² - 3x - y - 13/2 = 0

Step-by-step explanation:

I think thats the answer if it is right pls mark me as brainliest and learn well

Ethernet LANs are usually arranged in a star topology with computers wired to central switching circuitry that is incorporated in modern routers.

Ethernet is a family of computer networking technologies that is used in LAN, metropolitan area networks (MAN), and wide area networks (WAN). It was first introduced in 1980 by Xerox Corporation, and later standardized by the Institute of Electrical and Electronics Engineers (IEEE) as IEEE 802.3.

Ethernet networks can be implemented in different topologies, such as a bus, star, or mesh topology. However, the most common topology for Ethernet LANs is a star topology, in which computers are wired to a central switching circuitry that is incorporated in modern routers. This allows for efficient communication between the computers on the network.In addition to LANs, Ethernet is also used for other networking applications such as Internet access, wireless networking, and broadband access. Overall, Ethernet is a widely used technology that has become an important component of modern computer networking.

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The point \(2\sqrt{46},19,19\) is not on the unit circle. The point \(178,19,19\) is on the unit circle.

A point lies on the unit circle if and only if its distance from the origin is equal to one. Therefore, to determine whether the point lies on the unit circle or not, we will find its distance from the origin. Using the Pythagorean theorem, we get:

[\begin{aligned} &\sqrt{(2\sqrt{46})^2+(-178)^2+(19)^2+(19)^2}

&=\sqrt{184+31684+361+361}\\

&=\sqrt{32590}\\

&=\sqrt{50^2\cdot13}\\

&=50\sqrt{13}.

\end{aligned}\].

Since the distance from the origin is not equal to one, the point \((2\sqrt{46},

-178,19,19)\)

is not on the unit circle.

The point \(O(178,19,19)\) is on the unit circle because its distance from the origin is equal to one:

\[\sqrt{(178)^2+(19)^2+(19)^2}

=\sqrt{33436}

=2\sqrt{836}

=2\cdot2\sqrt{209]

=4\sqrt{209}.

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