Plsssss HELPPP PLSSSSS IM BEGGING

Answer:

(-6, -29)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

-5x + y = 1

9x - 2y = 4

Step 2: Rewrite Systems

-5x + y = 1

Step 3: Redefine Systems

y = 5x + 1

9x - 2y = 4

Step 4: Solve for x

Substitution

Step 5: Solve for y

The equation provided is: ρ²(sin²(φ)sin²(θ) + cos²(φ)) = 16, This equation is in spherical coordinates,

where ρ represents the radial distance from the origin, φ is the polar angle (or the angle between the positive z-axis and the vector), and θ is the azimuthal angle (or the angle between the positive x-axis and the projection of the vector onto the xy-plane).

Now, let's analyze the equation further: 1. Divide both sides of the equation by 16 to isolate ρ²: ρ² = 16 / (sin²(φ)sin²(θ) + cos²(φ)) 2. Take the square root of both sides to find ρ: ρ = √(16 / (sin²(φ)sin²(θ) + cos²(φ))).

From this, we can see that the surface is defined by the radial distance ρ, which depends on the angles φ and θ. This indicates that the given equation represents a 3-dimensional surface in spherical coordinates.

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Answer:

y = -3x + 20

Step-by-step explanation:

Slope: - 3

b = -1 - (-3)(7) = -1 + 21 = 20

The required difference of the polynomial functions is -9s^2 + 4s - 2

Given the following difference of polynomial expressed as:

(–6s2 + 12s – 8) – (3s2 + 8s – 6)

We are to find the difference

(–6s2 + 12s – 8) – (3s2 + 8s – 6)

Expand

–6s^2 + 12s – 8 - 3s^2 - 8s + 6

Collect the like terms

–6s^2- 3s^2 + 12s - 8s - 8 + 6

-9s^2 + 4s - 2

Hence the required difference of the polynomial functions is -9s^2 + 4s - 2

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complete question

Find each difference.

(–6s2 + 12s – 8) – (3s2 + 8s – 6) =

–9s2 + 4s – 14

–9s2 + 4s – 2

–9s2 + 20s – 14

–9s2 + 20s – 2

Answer:

30

Step-by-step explanation:

Answer:

3/2

Step-by-step explanation:

7 x 3/14 can be simplified to 21/14, which is written in simplest form as 3/2.

Hope can help :)

The simplest form of the fraction of the expression is 3/2.

We have,

The expression:

7 x 3/14

Now,

14 is a multiple of 7.

i.e

7 x 2 = 14

So,

7 x 3/(7 x 2)

7 gets canceled.

= 3/2

Thus,

The simplest form of the fraction of the expression is 3/2.

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To find the height and width of the rectangle inscribed in the parabola y = 10 - x^2 with the maximum area, we can use calculus.

Let's consider a rectangle with its base on the x-axis and its upper corners on the graph of the parabola y = 10 - x^2. The rectangle's height will be the y-coordinate of its upper corners, given by 10 - x^2. The width will be twice the x-coordinate of the upper corner, as the rectangle is symmetric about the y-axis.

The area of the rectangle can be expressed as A = 2x(10 - x^2), where 2x represents the width and 10 - x^2 represents the height. To find the maximum area, we can take the derivative of the area function with respect to x and set it equal to zero. By solving this equation, we can find the critical points. Taking the derivative of A with respect to x, we get dA/dx = 2(10 - 3x^2). Setting this equal to zero, we have 10 - 3x^2 = 0. Solving for x, we find x = ±√(10/3).

We discard the negative solution since the rectangle is inscribed in the first quadrant. Now, plugging the value of x = √(10/3) back into the height formula, we find the corresponding height h = 10 - (√(10/3))^2 = 10 - (10/3) = 20/3. Therefore, the height of the rectangle with maximum area is 20/3, and the width is twice the value of x, which is 2√(10/3).

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The administration's willingness to pay to save a student's statistics life is no more than option c) $100,000.

To estimate the administration's willingness to pay to save a student's statistical life, we need to calculate the cost per statistical life saved. Currently, the probability of a student dying from the plague is 1/3,000. If the rats are eradicated, this probability is reduced to zero. The cost of eradicating the rats is $1,000,000. To calculate the cost per statistical life saved, we divide the cost by the number of statistical lives saved.

The number of statistical lives saved is the product of the number of students on campus (30,000) and the reduction in probability (1/3,000).
Cost per statistical life saved = $1,000,000 / (30,000 * (1/3,000))
                         = $1,000,000 / (30,000 * 1/3,000)
                         = $1,000,000 / 10
                         = $100,000
Therefore, the correct answer is option c) $100,000.

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Answer:

5 : 7

Step-by-step explanation:

groom's side: 40

bride's side: 56

ratio groom to bride = 40/56 = 20/28 = 10/14 = 5/7

Answer: 5 : 7

Answer:

-63/28 or 2 1/4

Step-by-step explanation:

when dividing you will be multiplying by the reciprocal of the second fraction. SO it will be...

-9/14 times 7/2

this is... -63/28

Answer:

-9/4

Step-by-step explanation:

   -9

  -----

   14

------------

     2

    ----

      7

To divide -9/14 by 2/7, invert 2/7 and multiply instead:

   -9        7

 ------- * -----

   14        2

Reducing, we get:

(-9)(1)

---------  = -9/4

(2)(2)

Answer:

The answer would be the amount of money you make in one day multiplied by 6. This gets you the amount of money you get each week in this case.

Diversified Citrus Industries will sell Zap to wholesalers at a price of $0.035 per 8-ounce can. The contribution per unit for Zap is -$0.205, indicating potential profitability issues.

a. To determine the price at which Diversified Citrus Industries will be selling its product to wholesalers, we need to consider the suggested retail price, the unit variable costs, and the desired margins for retailers and wholesalers. The suggested retail price to the consumer for the 8-ounce can is $0.05. The unit variable costs for the product are $0.18 for materials and $0.06 for labor. The company intends to give retailers a margin of 20% off the suggested retail price and wholesalers a margin of 10% of the retailer's cost.

Price to Wholesalers = Suggested Retail Price - Retailer's Margin - Wholesaler's Margin

Price to Wholesalers = $0.05 - ($0.05 * 20%) - ($0.05 * 10%)

Price to Wholesalers = $0.05 - $0.01 - $0.005

Price to Wholesalers = $0.035

Therefore, Diversified Citrus Industries will be selling its product to wholesalers at a price of $0.035 per 8-ounce can.

The contribution per unit for Zap can be calculated by subtracting the unit variable costs from the selling price to wholesalers:

Contribution per Unit = Price to Wholesalers - Unit Variable Costs

Contribution per Unit = $0.035 - ($0.18 + $0.06)

Contribution per Unit = $0.035 - $0.24

Contribution per Unit = -$0.205

Since the contribution per unit is negative, it means that the variable costs exceed the price to wholesalers. This suggests that the product may not be profitable in its current pricing and cost structure.

The break-even unit volume in the first year can be calculated by dividing the fixed overhead costs by the contribution per unit:

Break-even Unit Volume = Fixed Overhead Costs / Contribution per Unit

Break-even Unit Volume = $90,000 / (-$0.205)

However, since the contribution per unit is negative, the break-even unit volume cannot be determined using this approach.

The first-year break-even share of the market cannot be determined based on the information provided. The total market size and the expected sales volume of Zap are not specified, making it impossible to calculate the market share at the break-even point.

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The feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

To determine whether the feasible set for each system of constraints is convex, we need to analyze the constraints individually and examine their intersection.

a) (x1)² + (x2)² > 9

This constraint represents points outside the circle with a radius of √9 = 3. The feasible set includes all points outside this circle.

b) x1 + x2 ≤ 10

This constraint represents points that lie on or below the line x1 + x2 = 10. The feasible set includes all points on or below this line.

c) x1, x2 > 0

This constraint represents points in the positive quadrant, where both x1 and x2 are greater than zero.

Now, let's analyze the intersection of these constraints:

Considering the first two constraints (a and b), we can see that the feasible set consists of all points outside the circle (constraint a) and below or on the line x1 + x2 = 10 (constraint b).

To determine whether the feasible set is convex, we need to check if any two points within the set create a line segment that lies entirely within the set.

If we consider the points (5, 5) and (3, 7), both points satisfy the individual constraints (a) and (b). However, the line segment connecting these two points, which is the line segment between (5, 5) and (3, 7), exits the feasible set since it passes through the circle (constraint a) and above the line x1 + x2 = 10 (constraint b).

Therefore, the feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

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Answer:

12% of 7.99

=0.96$

so...

The cost after Markup

=7.99$+0.96$

answer/explanation:

carry out these steps: 12% of 7.99 = $0.96 and use fraction if u may like. therefore the new cost after the markup is $7.99 + $0.96 which is then equal to your final answer - $8.95!

The test statistic for the population mean has a t-distribution with 9 degrees of freedom. Correct option is D.

The test statistic for the population mean in this scenario is a t-distribution with 9 degrees of freedom (option D).

To determine the test statistic, we need to use the formula:

t = (x' - μ) / (s / √n)

where x' is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

In this case, the hypothesized population mean is 2.5 grams, the sample mean is 2.47 grams, the sample standard deviation is 0.04 gram, and the sample size is 10.

Plugging these values into the formula, we get:

t = (2.47 - 2.5) / (0.04 / √10) ≈ -1.58

Since the sample size is less than 30, we use a t-distribution instead of a standard normal distribution. The degrees of freedom for the t-distribution is equal to n - 1, which in this case is 10 - 1 = 9.

We can use this distribution to calculate the p-value and make inferences about the population mean based on the sample data. Therefore, the correct option is D.

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The cone cup can hold 6.14 cubic inches of water.

A volume refers to the space occupied within the boundaries of an object in three-dimensional space.

To get volume of the cone cup, we will use formula for the volume of a cone \(V = (1/3)\pi r^2h\) where r is the radius of the base and h is the height.

Given:

Diameter (d) = 2.5 inches

Radius (r) = d/2 = 2.5/2 = 1.25 inches

Height (h) = 3.75 inches

Volume (V) = (1/3)π(1.25)²(3.75)

= (1/3)π(1.5625)(3.75)

= 6.13592315154

= 6.14 cubic inches.

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Answer:

c

Step-by-step explanation:

The answer is M

Step-by-step explanation:

Cosine: this is the length of the side right next to the angle divided by the longest side/ hypotenuse.

Tan: this is the length of the side opposite of the angle divided by the side directly adjacent/ next to the angle.

In this case, cosine would be 6/10 which Is also 3/5. the angle right next to 6 is Angle M

Answer:

Step by step explanation:

Here it is given that a boat travelled each way downstream and back . So while going back it would have travelled upstream.

And the time taken to go downstream is 6hrs and that of upstream is 126 hrs . So let us take ,

\(\longrightarrow v_{boat}= x \\\)

\(\longrightarrow v_{current}= y\)

As we know that ,

While going downstream, the speed will be ,

\(\longrightarrow v_d= x + y \dots (i) \)

And while up stream,

\(\longrightarrow v_u = x - y\dots (ii)\)

Also , we know that ,

\(\longrightarrow v = s\times t , \)

So that, while going downstream,

\(\longrightarrow v_d = \dfrac{126}{6}\\ \)

\(\longrightarrow v_d = 21 \dots (iii) \)

Again, while going upstream,

\(\longrightarrow v_u = \dfrac{126}{126}\\ \)

\(\longrightarrow v_u = 1 \dots (iv) \)

From equation (i) and (iii) , we have,

\(\longrightarrow x + y = 21 \dots (v)\)

And from (ii) and (iv) , we have,

\(\longrightarrow x-y = 1 \dots(vi)\)

On adding equation (v) and (vi) , we have;

\(\longrightarrow x+y+x-y = 21 +1 \\\)

\(\longrightarrow 2x = 22\\ \)

\(\longrightarrow x =\dfrac{22}{2} \)

\(\longrightarrow \underline{\underline{x = 11\ miles/hr }} \)

Substitute for x in (vi) ,

\(\longrightarrow 11 - y =1\\ \)

\(\longrightarrow y = 11-1\\\)

\(\longrightarrow \underline{\underline{ y = 10\ miles/hr}}\)

The speed of the boat in still water is 11 mph.

The speed of the current is 10 mph.

The speed of the boat in still water is calculated as follows;

va + vb = d/t

where;

va + vb = 126/6

va + vb = 21 ----(1)

The speed of the boat against the current is calculated as follows;

va - vb = d/t

va - vb = 126/126

va - vb = 1 ------ (2)

From equation (2) vb = 1 + va

va + 1 + va = 21

2va = 20

va = 10 mph

vb = 1 + 10 = 11 mph

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answer

use pythagorean theorem:

d^2 = 12^2 + 5^2

d^2 = 144 + 25

d^2 = 169

d = sqrt(169)

d = 13

the length of the diagonal should be 13 feet

Here, we are supposed to find the value of the stock. Let's begin by determining the expected dividends: Expected dividends1st year dividend (D1)

= $1.55(1 + 26.56%)

= $1.96Second-year dividend (D2) = $1.96(1 + 26.56%) = $2.48Third-year dividend (D3)

= $2.48(1 + 26.56%)

= $3.

= D1/(1+r)^1 + D2/(1+r)^2 + D3/(1+r)^3 + D4/(1+r)^4...∞Where r

= required rate of return Let us substitute the values now PV of the future dividends

= $1.96/(1 + 14.40%)^1 + $2.48/(1 + 14.40%)^2 + $3.14/(1 + 14.40%)^3 + $3.25/(1 + 14.40%)^4...∞PV of the future dividends = $1.96/1.1440^1 + $2.48/1.1440^2 + $3.14/1.1440^3 + $3.25/1.1440^4...∞PV of the future dividends

= $1.72 + $1.92 + $2.04 + $1.86...∞PV of the future dividends

= $7.54We know that the value of the stock is the present value of the expected dividends, so we can calculate it as follows: Value of the stock

= PV of the future dividends Value of the stock

= $7.54

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Differential equations and boundary value problems are mathematical equations that contain derivatives of unknown functions and their variables.

These equations are used to model a wide range of physical, biological, and chemical processes. The seventh edition of Fundamentals of Differential Equations and Boundary Value Problems by R. Kent Nagle, Edward B. Saff, and Arthur David Snider is a comprehensive textbook that covers the fundamentals of these equations.Differential equations and boundary value problems are mathematical equations that contain derivatives of unknown functions and their variables.  It includes topics such as first order equations, higher order linear equations, systems of equations, Laplace transforms, Fourier series, and numerical methods. It also contains a variety of worked examples, exercises, and applications to help students understand the material. Examples include solving initial value problems, boundary value problems, and inverse problems. The book also provides a step-by-step approach to solving problems, including the use of formulas such as the Euler-Cauchy formula, the Picard-Lindelof formula, the Runge-Kutta formula, the Laplace transform, and the Fourier series.

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Complete question:

Find the solution to the differential equation dy/dx + 4y = 0, given the boundary values y(0) = 2 and y(2) = 0.

Answer:

D :)

Step-by-step explanation:

The remainder when the sum \($1^5 2^5 3^5 \cdots 99^5 100^5$\) is divided by 4 is 0.

Explanation:

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A 99% confidence interval on the population mean alcohol level in this situation is 0.0347.

A sample of 57 observations for alcohol levels randomly taken on highway 6 at 3am on Saturday, resulted in a mean of 0.057 and a variance of 0.0075 respectively.

n= 57

x=0.037

σ\(^{2}\) = 0.0001099

σ = √σ2

=√0.0001099

σ = 0.01048

90% confidence interval,

d= 1-0.9=0.1

From z-table, \(z_{\frac{2}{z} }=z_{0.05}=1.645\)

90% confidence interval,

δ= x±\(z_{\frac{\alpha }{2} }\).σ/√n

= 0.037±1.645×\(\frac{0.01048}{\sqrt{57} }\)

= \(0.037\)±0.0023

= (0.0347, 0.0393)

Lower limit = 0.0347

Upper limit = 0.0393

Therefore, the lower limit is 0.347.

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Answer: 14%

Step-by-step explanation:

Complete question is provided in the attachment below:

Probability that members of the junior varsity swim team wear glasses = 55%=0.55

Given: P(wear glasses) = 0.55

P(not wear glasses) = 1-0.55 = 0.45

P(member in 10th grade | not wear glasses) = 30%

Using conditional probability formula:

\(P(B|A)=\dfrac{P(A\text{ and } B)}{P(A)}\)

\(\Rightarrow\ 0.30=\dfrac{P(\text{not wear glasses and in 10th grade})}{0.45}\\\\\Rightarrow\ P(\text{not wear glasses and in 10th grade})=0.45\times0.30\\\\0.135=13.5\%\approx14\%\)

Hence, the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade = 14%.

So, the correct option is "14%".

Answer:

4

Step-by-step explanation:

Cause 4×8 is 32.Am I right.Hpoe it helps.

Answer:

n=4

Step-by-step explanation:

n * 8 = 32

Do it backwards now

32 / 8 to make 4.\To check,

4*8 = 32

The increase in the selling price is 1.818.

Test statistic:

A test statistic is a statistic used in statistical hypothesis testing. A hypothesis test is typically specified in terms of a test statistic, considered as a numerical summary of a data-set that reduces the data to one value that can be used to perform the hypothesis test.

The given values are:

a = 0.1

x = 94

μ = 90

The formula for test statistic will be:

t = ((x- μ) / (\(\frac{s}{vn}\))

Now put the values in the given equation we have:

t = (94-90) / (\(\frac{22}{10}\))

 = 4/2.2

  = 1.818

Therefore the increase in the selling price is 1.818.

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a) The pet shelter has 40% cats (20% black, 5% adopted), and 60% dogs (10% black, 10% adopted). 50% of non-black cats and dogs are adopted, b) 0.45, c) 0.19, d) 0.15, e) 0.375, f) 0.6.

a) The probability tree would look like this:

P(Cat) = 40%

P(Black Cat) = 20%

P(Adopted Black Cat) = 5%

P(Not Adopted Black Cat) = 95%

P(Not Black Cat) = 80%

P(Adopted Not Black Cat) = 50%

P(Not Adopted Not Black Cat) = 50%

P(Dog) = 60%

P(Black Dog) = 10%

P(Adopted Black Dog) = 10%

P(Not Adopted Black Dog) = 90%

P(Not Black Dog) = 90%

P(Adopted Not Black Dog) = 50%

P(Not Adopted Not Black Dog) = 50%

b) P(Not Black Dog & Adopted) = P(Not Black Dog) * P(Adopted | Not Black Dog) = 0.90 * 0.50 = 0.45

c) P(Black Cat & Not Adopted) = P(Black Cat) * P(Not Adopted | Black Cat) = 0.20 * 0.95 = 0.19

d) P(Adopted) = P(Adopted Black Cat) + P(Adopted Not Black Cat) + P(Adopted Black Dog) + P(Adopted Not Black Dog) = 0.05 + 0.50 + 0.10 + 0.50 = 0.15

e) P(Adopted | Cat) = P(Adopted & Cat) / P(Cat) = (0.05 + 0.50) / 0.40 = 0.375

f) P(Cat | Adopted) = P(Cat & Adopted) / P(Adopted) = (0.05 + 0.50) / 0.15 = 0.6.

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Complete question:

Pet shelters typically have special adoption events for black cats and dogs, since their adoption rate is lower. One specific pet shelter (which has only cats and dogs) has 40% cats and 60% dogs. Twenty percent of the cats are black, and 10% of the dogs are black. The adoption percentage for black cats is 5%, and for black dogs is 10%. Cats that are not black are equally likely to be adopted as not adopted, and this is the same for dogs that are not black. For (b)-(f), write the probability statement and then calculate your answer.

a) Draw the probability tree and label all events and probabilities in it.

b) What is the probability that a randomly chosen animal is not black, a dog, and is adopted?

c) What is the probability that a randomly chosen animal is black, a cat, and is not adopted?

d) What is the probability that a randomly chosen animal is adopted?

e) Suppose a randomly chosen animal is a cat, what is the probability that it is adopted?

f) Suppose a randomly chosen animal is adopted, what is the probability that it is a cat?