pls wawawa 20000+8000+40+502+79805

Answer:

x^4-16

Step-by-step explanation:

(x^2+4)(x^2-4)

x^4+4x^2-4x^2-16

x^4-16

Answer:

The number is -37.

Step-by-step explanation:

2(x - 8) = 3(x + 7)

2x - 16 = 3x + 21

x = -37

The three expressions all represent the same value: \(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4\),\) but they are expressed in different forms.

To express the fraction \(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4\)\) in different ways, we can use algebraic expressions, decimal numbers, and mixed numbers. Here are three different expressions that are equal to\(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4\):\)
1. Algebraic expression: \(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4 = \frac{5}{16} \cdot 4 = \frac{20}{16}\)\)
2. Decimal number:\(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4 = 0.25 \cdot 1.25 \cdot 4 = 1.25\)\)
3. Mixed number:\(\(\frac{1}{4} \cdot \frac{5}{4} \cdot 4 = \frac{1}{4} \cdot \frac{5}{1} = \frac{5}{4} = 1 \frac{1}{4}\)\)
In the first expression, we simplified the product of the fractions by multiplying the numerators and denominators. Then, we simplified the resulting fraction to its lowest terms.

In the second expression, we converted each fraction to a decimal number and multiplied them together.

In the third expression, we converted the fractions to a mixed number by dividing the numerator by the denominator. This gives us the whole number part and the remaining fraction.

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Answer:

Perimeter= 40

Area= 120.71

Step-by-step explanation:

Answer:

Liz is correct

Step-by-step explanation:

Given

See attachment for complete question

Required

Who is correct? Daniel or Liz

From the attached data, we have:

\(Time: 1\frac{3}{4},\ 2\frac{1}{2},\ 2,\ 2\frac{3}{4},\ 1,\ 1\frac{3}{4},\ 1\frac{1}{4},\ 3,3\frac{1}{4},\ 3\frac{3}{4},\ 2,\ 2\)

The total number of students is:

\(n = 12\)

The data that represents  \(2\frac{1}{2}\) or more is:

\(Time: 2\frac{1}{2},\ 2\frac{3}{4},\ 3,3\frac{1}{4},\ 3\frac{3}{4}\)

The frequency of this is 5

The frequency that represents \(2\frac{1}{2}\) or less will be 7

This means that less than half spend \(2\frac{1}{2}\) or more

and more than half spend \(2\frac{1}{2}\) or more

Hence, Daniel is incorrect. Liz is correct

The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

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The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

Answer:

United States:34

Canada:17

Answer:

17 and 34

Step-by-step explanation:

the United States earned 34, while the Canada earned 17

Based on the information, we can infer that all the options are examples of situations in which the heuristics can be applied.

Heuristics is a term that refers to a strategy or technique whose main objective is to establish a procedure to advance in the process of solving a problem. In heuristics, the information is usually organized by means of a figure or a scheme to present it in a schematic way and solve it easily.

According to the above, the problems in which it is appropriate to use a heuristic solution are:

In this case, they are all problems in which the heuristic method can be applied because they involve different steps to have a solution.

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The perimeter of small polygon is 50 units. The length of sides of the larger polygon is 7.5, 10.5, 12, 16.5, 28.5 units.

Polygon in geometry is "any closed curve consisting of set line segments connected such that two segment across".

According to the question,

Lengths of sides of polygon is 5 units, 7 units, 8 units, 11 units, and 19 units.

Formula for Polygon = sum of sides

Perimeter of first polygon =  5 + 7 + 8 + 11 +19

                                           =  50 units.

Perimeter of second polygon = 75 units.

Divide second polygon by first polygon =  75/50 = 1.5 units

This conclude, second polygon is  1.5 units larger than first polygon.

In order to find the length of the sides of  larger polygon by given, first polygon and second polygon are similar polygon multiply 1.5 units to the  length sides of first Polygon.

5 * 1.5 = 7.5

7 * 1.5 = 10.5

8 * 1.5 = 12

11 * 1.5 = 16.5

19 * 1.5 =  28.5

Hence, the length of sides of the larger polygon is 7.5, 10.5, 12, 16.5, 28.5 units.

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Answer:

get smart

Step-by-step explanation:

dont cheat there is no good out of cheating

Answer:

G=3

3.3 x 3 =9.9 9.9 + 6 =15.9

1.3 x 3 =3.9 3.9 + 12 =15.9

So, G=3

Answer:

Diagram 1

Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)

Add a point on the circumference of the circle (point C2)

Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).

Diagram 2

The red circle intersects the black circle at two points (D and E).

Connect these 2 points of intersection with a line segment.

Diagram 3

Draw a third circle with center D and radius DE (shown in blue)

This circle intersects the black circle at point F.

Diagram 4

Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!

The number of keys required to fully implement a symmetric algorithm with 10 participants is: 45 (Option C)

Symmetric encryption or Algorithm is a kind of encryption that uses a single key (a secret key) to encrypt and decode electronic data.

The key must be exchanged between the organizations communicating using symmetric encryption so that it may be utilized in the decryption process.

The formula that determines the number of keys necessary for a symmetric algorithm is given as;

(n*(n-1))/2,

which is 45 in this situation, when n = 10.

That is

(10 * (10-1))/2

= 45.

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Full Question:

How many keys are required to fully implement a symmetric algorithm with 10 participants?

A. 10

B. 20

C. 45

D. 100

Answer:

l = 194999.45

Step-by-step explanation:

I'm going to assume that you meant 3.14 by 3,14.

336,765 = 3.14 × 0.55 × (l + 0.55)

336,765 ÷ (3.14 × 0.55) = l + 0.55

(336,765 ÷ (3.14 × 0.55)) - 0.55 = l

l = 194999.45

The minimum value of PQ is 2 units.

To find the minimum value of PQ, we need to determine the position of P that minimizes the distance between P and Q.

The line y = x + 2 represents the original line. To rotate this line 90 degrees clockwise about (0,0), we need to swap the x and y coordinates and negate the new x coordinates. The equation of the new line, L, becomes x = y + 2.

Since Q is given as (0,2), we can substitute these coordinates into the equation of line L:

x = y + 2

0 = 2 + 2

0 = 4

As the equation is not satisfied, the point (0,2) does not lie on line L.

However, we can still find the minimum value of PQ. The minimum value occurs when P is located on the line perpendicular to L and passing through Q. This perpendicular line has the equation x = -2.

Substituting this equation into the distance formula, we get:

PQ = sqrt((x2 - x1)^2 + (y2 - y1)^2)

= sqrt((-2 - 0)^2 + (y - 2)^2)

= sqrt(4 + (y - 2)^2)

= sqrt(4 + y^2 - 4y + 4)

= sqrt(y^2 - 4y + 8)

To find the minimum value of PQ, we can complete the square:

PQ = sqrt((y - 2)^2 + 4)

= sqrt(y^2 - 4y + 4 + 4)

= sqrt(y^2 - 4y + 8)

The minimum value of PQ occurs when the expression inside the square root is minimized. The vertex of the parabola y^2 - 4y + 8 is given by the x-coordinate x = -(-4) / (2*1) = 2. Therefore, the minimum value of PQ is obtained when y = 2.

Substituting y = 2 into the expression for PQ, we get:

PQ = sqrt(2^2 - 4*2 + 8)

= sqrt(4 - 8 + 8)

= sqrt(4)

= 2

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9x=5x+20

9x-5x=20

4x=20

x=5

Answer:

180

Step-by-step explanation:

take 72+72 +36  to get your answer .

Answer:

180 miles

Step-by-step explanation:

Assuming that the speed of the motorcycle is constant, the following equation, (\(speed * time = distance\)) can be used to find the distance that a vehicle traveled when one is given the time and speed at which the vehicle operates. Substitute in these values, and solve,

\((72)*(2\frac{1}{2})\\\\= 72 * \frac{5}{2}\\\\= 180\)

Answer:

The fraction 6/2 in it's simplest form is simply 3 :)

Step-by-step explanation:

The solution for the fraction 6/2 in simplest form is, 3

We have to given that,

To change the fraction 6/2 in simplest form.

Since, An equal division of a whole number into smaller pieces is called a fraction. Alternately, a fraction is a number that has been represented as a quotient. It may be expressed using the p: q form, which is identical to p/q.

The number is,

⇒ 6 / 2

After divide as,

⇒ 3

Therefore, The solution for the fraction 6/2 in simplest form is, 3

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Answer:

Point of tangency is \(x=1\) or \((1,1)\)

Step-by-step explanation:

You don't really need to use Calculus here. You can just set each equation to each other and solve for x (the point of tangency):

\(x^2=2x-1\)

\(x^2-2x+1=0\)

\((x-1)(x-1)=0\)

\(x=1\)

Therefore, the point of tangency is \(x=1\) or \((1,1)\)

The solution to the equation (x+21)=7 is x = -14

The equation is given as:

(x+21)=7

Remove the brackets

x + 21 = 7

Subtract 21 from both sides

x + 21 - 21 = 7 - 21

Evaluate the expression

x = -14

Hence, the solution to the equation (x+21)=7 is x = -14

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0.80 = (x + 8)(0.05) is the equation used to find x.

Given,

Darryl has a solution of bleach with the concentration of 10%.

10% bleach solution means in 100 ml solution amount of bleach is 10 gm

Here,

Darryl wants to change the concentration of this solution to 5%, means he wants to add water so that amount of liquid will change but amount of bleach in grams will remain the same.

Amount of bleach in 8 gallons of 10% solution of bleach will be = (Volume)×(concentration) = 8(.10) gm

Let Darryl adds x gallons of water in 10% solution of bleach to make it 5% solution of bleach.

Amount of bleach in 5% solution of bleach = (x + 8)(0.05) gm

Now in both the concentrations of bleach solution amount of bleach will remain same.

So, 0.8 = (x + 8)(0.05) will be the equation from which he can find the value of x.

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Answer:

  36.4%

Step-by-step explanation:

You want the percentage change from $22 to $30.

The percentage change is given by the formula ...

  percent change = ((new value)/(old value) -1) × 100%

  = (30/22 -1)(100%) ≈ 36.4%

The stock increased in value by about 36.4%.

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Answer:

Scenario 1 represents a greater speed

Step-by-step explanation:

scenario 1 - find equation of line on graph to compare

- use the points given to find the slope

rate = slope = (y2-y1)/(x2-x1) = (240-60)/(4-1) = 60

y intercept = 0

line equation -> y = 60x

for every mile, 60 miles are traveled

scenario 2 - interpret the equation

for every mile, 50 miles are traveled

Scenario 1 represents a greater speed

If there are 1,000 phones in total and 100 of them have between 200 and 249 songs while 600 of them have between 150 and 199 songs, then there are more phones with between 150 and 199 songs.

We cannot determine whether there are more phones that have between 200 and 249 songs stored on them than have between 150 and 199 songs without additional information.

For example, if there are 1,000 phones in total and 500 of them have between 200 and 249 songs while 200 of them have between 150 and 199 songs, then there are more phones with between 200 and 249 songs. However, if there are 1,000 phones in total and 100 of them have between 200 and 249 songs while 600 of them have between 150 and 199 songs, then there are more phones with between 150 and 199 songs.

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Answer:

Slope= -3

Equation: y=-3x-44

Answer:

1/2 x -5/2 = -5/4

-1 1/4 + -1/4

-1 2/4

- 1 1/2

The probability that the obstetrician has delivered no child with polydactyly is 0.8187.

To find the probability that the obstetrician has delivered no child with polydactyly, we can use the formula:

P(no polydactyly) = \((1 - P(polydactyly))^{number of births}\)

First, we need to find the probability of a child having polydactyly. This is given as 1 in every 500, which can be expressed as a decimal: 1/500 = 0.002.

Next, we find the probability of a child not having polydactyly: 1 - 0.002 = 0.998.

Now, we can find the probability of the obstetrician delivering no child with polydactyly in 100 unrelated and independent births by raising the probability of no polydactyly to the power of the number of births (100):

P(no polydactyly in 100 births) = (0.998)¹⁰⁰ ≈ 0.8187

So, the probability that the obstetrician has delivered no child with polydactyly is approximately 0.8187.

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