Question 1
Answer: A
Jose is walking fifteen minutes a day so an example of progression would be him increasing the amount of time he walks per day.
Question 2
Answer: C
If Laura does her exercise program consistently her progression will eventually peak. That is why to keep progressing new goals have to be set. Thus, increasing/changing intensity, duration, and frequency will give her room to progress.
how long will it take you to travel 20 miles on a bus that drives 60 miles/h?
Answer:
20 Minutes
Explanation:
Well we know Mph (Miles per hour) is distance over time : \(\frac{distance}{time} \\\)
R (rate) = 60
d (distance) = 20
t (time) = Unknown
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
R = \(\frac{d}{t} \)
↓
60 = \(\frac{20}{t}\)
↓
t = \(\frac{20}{60} \)
↓
t = \(\frac{1}{3} \) or 0.3333
So basically it would take one third of an hour. Lets change these units to minutes.
60 * 0.333333 = 20
So it would take you 20 minutes to drive 20 miles on a bus that drives 60 mph
Hope that helps
~Siascon~
what is the velocity between 0s & 5s. (picture is given) Please assist (will give branliest)
Answer: the velocity is -2
Explanation: good luck don't think its wrong everyone calls me the human calculator
An open course offers an orderly way to complete a course sequentially. Group of answer choices
Opportunities for collaboration, enhancing the learning experience, own pace, within a defined timeline, and accommodating different learning styles and schedules. is the benefit of an open course in terms of completing a course sequentially
An open course typically offers learners an orderly way to complete a course sequentially by breaking down the course material into smaller modules or units.
An open course allows learners to access course materials and complete assignments in a structured, step-by-step manner.
An open course provides a clear path for learners to follow, making it easier to stay organized and on track.
An open course often includes interactive features and opportunities for collaboration, enhancing the learning experience.
An open course typically allows learners to work at their own pace, within a defined timeline, accommodating different learning styles and schedules.
An open course can be accessed from anywhere with an internet connection, allowing for greater flexibility and accessibility.
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Question
What is the benefit of an open course in terms of completing a course sequentially?
YALLL I NEED HELP ASAP... THIS DUE AT 11:59 AND ITS 10.42 RIGHT NOW
Suppose you were looking at two stars, both at the same distance, but while star A is a G5 I, star B is a G5 III. How would they look different to you in a telescope?A. Star A would be brighterB. Star B would be brighterC. Both the same brightness
If you were looking at two stars, both at the same distance, with star A being a G5 I (a supergiant) and star B being a G5 III (a giant), the difference in appearance through a telescope would be their brightness. In this case, star A (G5 I) would be brighter, making option A the correct answer.
Both stars would appear the same brightness in a telescope because their distance is the same. However, the main difference between them is their luminosity class, with star A being a main sequence star (luminosity class I) and star B being a giant star (luminosity class III). This difference in luminosity class suggests that star B is older and has exhausted more of its fuel than star A, which is still in its main sequence phase.
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What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying
What is overtraining?
A.
overloading the muscles too often
B.
progressing through exercises too quickly
C.
muscles that aren't adapting quickly enough
D.
when muscles start atrophying
Answer:
A. overloading the muscles too often
Overtraining is overloading your muscles.
What is overtraining?
Overtraining refers to a process when a person continue to exercise despite that he has reach the limit of his ability and ignores the signs of and continues to train. Many believe they need to stress their muscles to be morefit and improve their performance.
Therefore, Overtraining is overloading your muscles.
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Astronomers now know that surrounding the main body of our galaxy (which our various kinds of telescopes have shown to us) and our fainter halo of stars there is:________.
Astronomers now know that surrounding the main body of our galaxy (which our various kinds of telescopes have shown to us) and our fainter halo of stars there is: a spherical halo of dust and gas.
What is milky way?
There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms. The Milky Way's center would take you about 25,000 years to reach, even if you could move at the speed of light (300,000 km/s, or 186,000 mph).
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When was World War 3 Started?
Answer:
Korean War: 25 June 1950 – 27 July 1953
Many then believed that the conflict was likely to soon escalate into a full-scale war between the three countries, the US, the USSR, and China. CBS war correspondent Bill Downs wrote in 1951 that, "To my mind, the answer is: Yes, Korea is the beginning of World War III.
Explanation:
Answer:
1950-1953
Explanation:
A person sitting on the outer edge of a merry-go-round travels _____________ a person sitting near the center.
Answer:
It’s fun
Explanation:
If a person sitting on the outer edge of a merry-go-round travels at a greater speed than a person sitting near the center because the linear velocity is a product of the angular velocity and the perpendicular distance from the center .
What is an uniform circular motion?It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion .
Because the linear velocity is a function of the angular velocity and the perpendicular distance from the center .
Thus, the person seated on the outside edge of a merry-go-round will move more quickly than a person seated near the center .
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A 2.5 –g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree’s trunk. What force was exerted on the bullet in bringing it to rest?
Answer:
A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct.Jan 8, 2020
Explanation:
A school bus has a mass of 18,200 kg k g . The bus moves at 15.5 m/s m / s .
Answer:
whatttt
Explanation:
what do u ask boy? just ask.
Which of the following is a real-life example of a rotation?
a ceiling fan
a butterfly's wings
O going down a slide
opening a sliding glass patio door
None of the other answers are correct
Answer:
a ceiling fan a ceiling fan
A block weighing 2 kg i in the hape of a cube of ide 10 cm. It i kept on a horizontal table. Find the preure on the portion of the table where the block i kept
Answer:
pressure= 2000 Pa
Explanation:
pressure= force/area
ρ=\(\frac{F}{A}\)
We don't have the force but we know that force and weight are the same things as they have the same unit.
weight= mass × gravitational force (gravitational force is constant at the value 10)
w= 2 × 10
w = 20N
So force= 20N
To find the area of the portion of the cube:
= 10 × 10
= 100 cm²
we should convert this to m²
100/10000
= 0.01 m²
ρ= \(\frac{20}{0.01}\)
ρ= 2000 Pa
Pressure= 2000 Pa
A plane is landing. It started at 400m/s and ended up at 50m/s after 30 seconds. What is it's acceleration?
{middle school}
Give u = start velocity
v = end velocity
v = u + at
50 = 400 + a*30
30a = -350
a = -116.67 m/\(s^{2}\)
**Why the accecleration is negative number**
Because displacement, velocity, and acceleration are VECTOR QUANTITIES.
Vector Quantity must have direction.
explain the effect of impurities on melting and boiling point
i only know the example :- adding salt to water will lead to increase in its boiling point .
A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
Answer:
Explanation:
F = ma and
\(a=\frac{v}{t}\)
We have F, we have m, but in order to solve for v, we need a.
30.0 = 3.00a so
a = 10.0 m/s/s. Plug that in for a in the second equation and solve for v:
\(10.0=\frac{v}{3.00}\) so
v = 10.0(3.00) so
v = 30.0 m/s
a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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An electric circuit is a closed loop or pathway that allows electric charges to flow
An electric circuit is a closed loop or pathway that allows electric charges to flow. This statement is True.
What is charge?The charge is the physical quantity which experiences electrostatic force depending on its own polarity.
An electric circuit a kind of closed loop, with a voltage source and resistors connected.
The positive terminal of voltage source emits the charges towards the negative terminal completing the pathway of circuit.
Thus, the given statement is true.
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two spheres stick together and move horizontally for an instant after the collision. During the collision, what is the change in the kinetic energy
The change in the kinetic energy of the two spheres during the collision will depend on the nature of the collision.
If the collision is perfectly inelastic, the two spheres will stick together after the collision and move as one object. In this case, some of the kinetic energy of the spheres will be converted into other forms of energy such as heat and sound, resulting in a decrease in kinetic energy.
If the collision is elastic, the two spheres will bounce off each other after the collision and move away from each other with the same speed and direction as before the collision. In this case, the kinetic energy of the spheres will be conserved, and there will be no change in kinetic energy during the collision.
The magnitude of the change in kinetic energy will depend on the mass and velocity of the spheres before and after the collision, as well as the nature of the collision itself.
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A dog and a cat sit on a merry-go-round. The dog sits 0.3 m from the center. The cat sits 1.5 m from the center. The whole merry-go round rotates with an angular speed of 5 rad/s. Which animal, if either, is experiencing a higher velocity? Which animal, if either, is experience a higher angular speed?
Answer:
hope that pic helps!! let me know!!
Explanation:
or this expert answers from expert
What is the earliest time at which the force of
the spring shown below is zero?
(Unit = s)
Answer:
0.45
Explanation:
Answer:
Explanation:
The answer is C.
For extra credit, you can point out that even at C, the spring force is not exactly zero as there is a tension force equal to the weight of the mass.
An aircraft with a mass of 3 x 10ʻ kg is flying at 100 m/s in steady level flight far from the ground. Its wing span (from wing tip to wing tip) is 50 m, and the lift distribution may be considered uniform over the wing span. The tail-plane (i.e., horizontal stabilizer) is located 25 m behind the wing at the same horizontal level. The tail-plane is a symmetric airfoil. Estimate the downwash, relative to the horizontal, that the tail-plane experiences. Be sure to show all of your work. Hint 1: Assume a very simple horseshoe vortex model of the lifting wing. as dū = I dixi h P Hint 2: The Biot-Savart law has been previously given We then integrated this equation to 41 1731 derive an equation for the total velocity V induced by an infinite line vortex. It can be shown that the integral of this for a section of a line vortex can be written as V = r (cos a + cos B) where h, a, and ß are 4th defined as in the sketch to the right and V is the total velocity induced at point P. a Note: Even without a calculator, it should be possible to give the final answer (or very near the final answer) as a number. However, if that is not something you can do, feel free to carry the symbols through and give the answer as an expression.
According to the question The tail-plane experiences a downwash of 0.5 m/s relative to the horizontal.
To estimate the downwash experienced by the tail-plane, we can use the horseshoe vortex model and the Biot-Savart law. Let's denote the downwash as \(\(d_w\)\) and the induced velocity as \(\(V\)\).
Given:
Aircraft mass, \(\(m = 3 \times 10^6\)\) kg
Flight velocity, \(\(V_f = 100\)\) m/s
Wing span, \(\(b = 50\)\) m
Distance from wing to tail-plane, \(\(d = 25\)\) m
Using the horseshoe vortex model, we consider a single vortex of strength \(\(I\)\) shed from each wingtip and extending vertically downwards. The induced velocity at the tail-plane is given by the equation:
\(\(V = I \int \frac{d\xi}{r}\)\)
where \(\(I\)\) is the vortex strength, \(\(d\xi\)\) is an element of vortex length, and \(\(r\)\) is the distance from the vortex element to the point where we want to calculate the induced velocity.
The horseshoe vortex model assumes that the lift distribution over the wing is uniform. Therefore, we can consider the induced velocity at the tail-plane to be the average of the induced velocities caused by the two vortices shed from the wingtips.
To calculate the induced velocity at the tail-plane, we need to determine the vortex strength \(\(I\)\). The vortex strength can be related to the lift \(\(L\)\) generated by the wing using the equation:
\(\(L = \rho \cdot V_f \cdot b \cdot I\)\)
where \(\(\rho\)\) is the air density.
Rearranging the equation to solve for \(\(I\)\), we get:
\(\(I = \frac{L}{\rho \cdot V_f \cdot b}\)\)
The lift \(\(L\)\) can be calculated using the equation:
\(\(L = m \cdot g\)\)
where \(\(g\)\) is the acceleration due to gravity.
Substituting the given values:
\(\(L = (3 \times 10^6 \text{ kg}) \cdot (9.8 \text{ m/s}^2) = 29.4 \times 10^6 \text{ N}\)\)
Now, let's calculate \(\(I\):\)
\(\(I = \frac{29.4 \times 10^6 \text{ N}}{\rho \cdot 100 \text{ m/s} \cdot 50 \text{ m}}\)\)
To estimate the downwash, we need to calculate the induced velocity \(\(V\)\)at the tail-plane. Using the formula derived from the Biot-Savart law:
\(\(V = r \cdot (\cos \alpha + \cos \beta)\)\)
where \(\(r\)\) is the distance from the vortex element to the point P (tail-plane in this case), and \(\(\alpha\) and \(\beta\)\) are defined as shown in the sketch.
In this scenario, \(\(r\)\) is the horizontal distance from the wing to the tail-plane, which is given as 25 m. Also, since the tail-plane is at the same horizontal level as the wing, \(\(\alpha = \beta = 0\).\)
Substituting these values into the equation:
\(\(V = 25 \cdot (\cos 0 + \cos 0) = 25 \cdot (1 + 1) = 50\) m/s\)
Therefore, the induced velocity at the tail-plane is \(\(50\) m/s.\)
Finally, we can calculate the downwash \(\(d_w\)\) by dividing the induced velocity by the flight velocity:
\(\(d_w = \frac{V}{V_f} = \frac{50 \text{ m/s}}{100 \text{ m/s}} = 0.5\)\)
Hence, the downwash experienced by the tail-plane is \(\(0.5\) or \(0.5\) m/s\) relative to the horizontal.
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.What two horizontal forces are present as a car is pushed down the driveway?
push, velocity
power, friction
power, weight
push, friction
The two horizontal forces that are present as a car is pushed down the driveway are push and friction.
What is force?
A force is a push or pull upon an object that alters the object's state of motion. This occurs as a result of a body interacting with its surroundings. Forces can cause an object to accelerate, decelerate, change direction, or change shape.When an object is in motion, there are two main factors that affect its kinetic energy: the push or force applied to it and the friction it experiences.
What is friction?
Friction is a force that opposes the motion of an object when it comes into contact with another surface.Friction acts in the opposite direction to the object's motion, and it can reduce the object's kinetic energy. When an object moves through a surface with friction, some of its energy is converted into heat and other forms of energy, leading to a decrease in kinetic energy. The amount of friction depends on factors such as the roughness of the surfaces in contact and the normal force between them.What is velocity?
The velocity of an object refers to the rate at which it moves in a particular direction. It can be calculated by determining the distance travelled by an object over time, as well as the direction in which it is moving.Learn more about velocity:
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Help needed for science homework
A plane lands and comes to a complete stop through 180 m of runway with a deceleration of 6.25 m/s2 [N]. Determine the plane’s velocity when it first touched the landing strip.
Answer:
47.43 m/s
Explanation:
Given that,
Final speed of a plane, v = 0
Distance, d = 180 m
Acceleration of the plane, a = -6.25 m/s² (deceleration )
We need to find the plane's velocity. Let it was u. So, using the third equation of kinematics as :
\(v^2-u^2=2ad\\\\u^2=0^2-2\times (-6.25)\times 180\\\\u=\sqrt{2250} \\\\u=15\sqrt{10}\ m/s\\ \\\text{or}\\\\u=47.43\ m/s\)
So, the plane's velocity when it first touched the landing strip is 47.43 m/s.
Drag each tile to the correct box.
Arrange the images in order to show how lake-effect snow occurs.
The images below demonstrate how lake effect snow occurs:
Cold Arctic air is passing over warm lake waters.
The surface of the lake adds heat and water vapour to the cold air mass.
Water vapour condenses in rising air to form clouds.
Snow blankets the lake and the downwind shore.
Where does lake effect snow most commonly occur?Lake effect snow most commonly occurs in the Great Lakes region of North America, which includes parts of the United States and Canada. The Great Lakes generate significant amounts of moisture, and when cold air passes over the relatively warm water, it picks up moisture and heat, leading to the formation of clouds and precipitation. As the air moves over land, it can release large amounts of snowfall in areas downwind of the lakes. This phenomenon is most common during the winter months and can produce heavy snowfalls that can impact transportation, infrastructure, and daily life in affected areas.
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If the student repeated the experiment by replacing the water in the calorimetry device with an ice bath at 0°C, how would the experimental results differ?
If the student replaced the water in the calorimetry device with an ice bath at 0°C, the experimental results would differ in several ways:
Temperature Change: Instead of measuring the change in temperature of the water, the student would measure the change in temperature of the ice bath. As heat is transferred from the surroundings to the ice bath, the ice will melt and the temperature of the ice bath will increase until it reaches 0°C. The temperature change observed in the experiment would be different from that of the water bath.
Heat Capacity: The heat capacity of the ice bath would be different from that of the water bath. Ice has a lower heat capacity than water, meaning it requires less heat energy to raise its temperature. This would affect the amount of heat absorbed or released during the reaction and lead to different experimental results.
Enthalpy Change: The enthalpy change calculated from the experiment would be specific to the reaction being studied. However, the enthalpy change determined using an ice bath would be based on the heat exchange with the ice bath, rather than the water bath. The enthalpy change values would differ due to the different heat capacities and temperature changes involved.
Overall, using an ice bath instead of a water bath would result in different temperature changes, heat capacities, and enthalpy change values in the experimental results.
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4. Where would a tsunami be most likely to occur?
a. Cuba
coast of Ireland
b. New York City
d. Indonesia
Answer:
D. Indonesia
Explanation:
Indonesia's high frequency of tsunamis, due to its location along the Pacific Ring if Fire
What is the specific heat capacity of a material if 2000 J of heat energy can raise the temperature of 10 g of it by 140°C?
Answer:
Specific heat capacity, = 1.43 J/g°C
Explanation:
Given the following data;
Mass = 10 g
Change in temperature = 140°C
Quantity of heat = 2000 J
To find the specific heat capacity;
Heat capacity is given by the formula;
\( Q = mcdt\)
Where;
Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity of water. dt represents the change in temperature.Making c the subject of formula, we have;
\( c = \frac {Q}{mdt} \)
Substituting into the equation, we have;
\( c = \frac {2000}{10*140} \)
\( c = \frac {2000}{1400} \)
Specific heat capacity, = 1.43 J/g°C
The statement “the scientific process is open-ended “means
We have that the statement "The scientific process is open-ended" means that the process is continues in summary,
From the Question we are told that
The scientific process is open-ended
It is important to note that"The scientific process is open-ended" simply refers to a process can go in different Patterns. Means that questions can have many Reconciliations. experiments are continues and other scientists can added there concepts.
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