Answer:
Explanation:
I'm not sure, don't hate me if i'm wrong but i think the third one is the answer.
Answer:
The question is asking what does not have anything to do with the bond formation.
The molecular formula of an antibacterial drug is C, H, FN,O,. How many fluorine atoms are in a 150-mg tablet of this drug?
Answer:
To find the number of fluorine atoms in a 150-mg tablet of the antibacterial drug, you need to know the molecular weight of the drug and the number of moles in 150 mg.
Since the molecular formula is given as C, H, F, N, O, you can determine the molecular weight by adding the atomic weights of each element.
For example, if the atomic weights of C, H, F, N, and O are 12, 1, 19, 14, and 16, respectively, the molecular weight of the drug is (12 x C) + (1 x H) + (19 x F) + (14 x N) + (16 x O).
Knowing the molecular weight and the number of moles, you can use Avogadro's number to find the number of fluorine atoms. Avogadro's number is 6.022 x 10^23.
Since the information about the molecular weight, number of moles, and molecular formula is not given, it's not possible to determine the number of fluorine atoms in a 150-mg tablet of this drug.
Explanation:
According to Avogadro's number, there are 0.0145×10²³ atoms present in a 150-mg tablet of this drug.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, substitution of values in formula gives number of atoms= 0.15/62×6.022×10²³= 0.0145×10²³.
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How many electrons are in the valence shell of the sodium atom shown below?
Answer:
answer is one
Explanation:
valency is the amount of electrons on the last shell
What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
Answer:
168.75 ml
Explanation:
M1V1=M2V2
375ml*.45M=1M*V2
write word equation for the reaction between dil hydrochloric acid with zinc oxide
Answer:
Zinc Oxide + Dil. Hydrochloric Acid -----> Zinc Chloride + Water
Which is an important function of lipids in the body?
provide the body with energy and fiber
provide the body with vitamins and bile salts
provide the building blocks for muscle tissue
provide control of substances going into and out of cells
Answer:
One of the main functions lipids do is storing energy.
provide the building blocks for muscle tissue
Answer:
c
Explanation:
edge
What is the fluoride ion concentration for a saturated solution of BaF 2 if the K sp for BaF 2 is 1.8 × 10 -7 ?
\(\\ \rm\rightarrowtail BaF_2\longrightarrow Ba^{2+}+2F-\)
BaF_2 be xBa2+ is also xF- is 2xNow
\(\\ \rm\Rrightarrow K_{sp}=[Ba^2+][F-]^2\)
\(\\ \rm\Rrightarrow 1.8\times 10^{-7}=x(2x)^2\)
\(\\ \rm\Rrightarrow 4x^3=1.8\times 10^{-7}\)
\(\\ \rm\Rrightarrow x^3=0.45\times 10^{-7}\)
\(\\ \rm\Rrightarrow x=\sqrt[3]{0.000000045}\)
\(\\ \rm\Rrightarrow x=0.00376M\)
\(\\ \rm\Rrightarrow x=3.8\times 10^{-3}M\)
So
\(\\ \rm\Rrightarrow [F-]=2x=7.6\times 10^{-3}M\)
2) Liquid soap is dissolve in water to make a soap solution. Why is this
solution called a mixture?
Explanation:
Soap solution is called a mixture because you're combining a ratio of liquid soap and water to make a mixture.
A certain element contains eleven atoms of mass 95.952 u for every four atoms of mass 98.949 u. Compute the average atomic weight of this element.
The average atomic weight of the given element is calculated based on the given data, which indicates that for every four atoms of mass 98.949 u, there are 11 atoms of mass 95.952 u.
The first step is to compute the total mass of the 15 atoms.15 atoms of the element contain 11 atoms of mass 95.952 u and 4 atoms of mass 98.949 u.The total mass of 11 atoms of mass 95.952 u is given by 11 x 95.952 u = 1055.472 u.
The total mass of 4 atoms of mass 98.949 u is given by 4 x 98.949 u = 395.796 u.The total mass of the 15 atoms of the given element is 1055.472 + 395.796 = 1451.268 u.
The average atomic weight of an element is the ratio of the total mass of all the atoms in the element to the number of atoms in the element.15 atoms of the element have a total mass of 1451.268 u.
The average atomic weight of the given element is given by: Average atomic weight = Total mass of the 15 atoms of the given element / Total number of atoms of the given element= 1451.268 / 15= 96.751 u.
Therefore, the average atomic weight of the given element is 96.751 u.
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A sample of argon gas is cooled and its volume went from 380 mL to 250 20 points
ml. If its final temperature was -55°C, what was its original temperature?
Answer:
Applying the Laws of Thermodynamics we get as,
Explanation:
V1/T1 = V2/T2
According to the law of Gaseous states.
so we get as,
V1 = 380 ml, V2 = 250 ml, T2 = -55°C ==> 273-55 ==> 218 Kelvin.
so now substituting we get as,
380/ T1 =250/218
==> 380*(218) /250 = T1
==> T1 = 331.36 ===>T1 = 331 K approx
So the Original Temperature was 331 K,
Option 1.) is correct.
why cant the minority carrier diffussion equations be used to determine the minority carrier concentrations and currents in the depletion region
The minority carrier diffusion equations are based on the assumption that the carrier concentrations are spatially uniform, which means that they do not vary with position. However, in the depletion region of a p-n junction, the carrier concentrations are not spatially uniform.
The depletion region is characterized by a sharp variation in the doping concentration, which leads to a strong electric field that causes the majority carriers (electrons in the n-type material and holes in the p-type material) to be swept away from the region, leaving behind a region depleted of majority carriers. This depletion region acts as a barrier to the minority carriers (holes in the n-type material and electrons in the p-type material), resulting in a non-uniform concentration distribution of minority carriers. As a result, the diffusion equations cannot be used to accurately determine the minority carrier concentrations and currents in the depletion region because they do not take into account the spatial variation of carrier concentrations. Instead, more advanced models such as the drift-diffusion model or the Shockley-Read-Hall model are used to describe the behavior of minority carriers in the depletion region of a p-n junction. These models take into account the non-uniform carrier concentrations and the effects of recombination and generation of minority carriers within the depletion region.
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someone pls answer i will in fact give u brainliest
Answer:
d. Solid
Explanation:
It is frozen to be a glacier
Hope this helps :)
If I initally have a gas at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
Answer: 30 L
Explanation: Use the combined gas law: P1V1/T1 = P2V2/T2
We want V2, so rearrange:
V2 = V1(T2/T1)(P1/P2)
Note how I've grouped the temperature and pressure into ratios. This allows us to cancle those units quickly and gives a perspective on what we should expect. Enter the data:
V2 = (23L)*(0.6667)*(0.8571)
V2 = 29.6 L 30 L for 2 sig figs
Cases of smallpox were very rare worldwide by 1980. Which most likely explains this? A. an increase in disease education B. a decrease in world travel C. an increase in number of vaccinations of young children D. a decrease in regulations on food preparation
Answer:
C.
Explanation:
The main reason for this decrease is an increase in the number of vaccinations of young children. The smallpox vaccine which was created in 1796 completely allows individuals to easily and quickly fight off the smallpox disease if they were to get it. By being able to fight the disease quickly and effectively it provides less time for the disease to affect another individual. Therefore, causing cases to decrease and become very rare as time goes on.
9.
Name the type of structure shown in the diagram:
Answer:
covalent bond is shown in this diagram.
determine the ph of a 0,681 m solution of nan3 (ka for hn3 = 1.9 × 10−5).
To determine the pH of a solution of NaN3, we need to first consider the dissociation of HN3, the acid form of NaN3, in water. The equilibrium equation for the dissociation of HN3 is:
HN3 + H2O ⇌ H3O+ + N3-
The acid dissociation constant, Ka, for HN3 is given as 1.9 × 10−5. This means that at equilibrium, the concentration of H3O+ and N3- can be determined using the following equation:
Ka = [H3O+][N3-]/[HN3]
Since NaN3 is a salt, it dissociates completely in water to form Na+ and N3-. However, N3- can react with water to form HN3 and OH-. Therefore, the concentration of HN3 can be determined using the equilibrium equation for the reaction of N3- with water:
N3- + H2O ⇌ HN3 + OH-
The equilibrium constant for this reaction is Kw/Ka, where Kw is the ion product constant of water and has a value of 1.0 × 10^-14 at 25°C.
Kw/Ka = (1.0 × 10^-14)/(1.9 × 10^-5) = 5.26 × 10^-10
Let x be the concentration of HN3 and [OH-] be the concentration of hydroxide ions. Then the concentration of N3- is also x, and the concentration of H3O+ is (Ka/x). Using the equilibrium constant expression for the reaction of N3- with water, we have:
Kw/Ka = [HN3][OH-]/[N3-]
Substituting the values for Kw/Ka and the concentrations of HN3 and N3-, we get:
5.26 × 10^-10 = [(Ka/x)(x + [OH-])]/x
Simplifying and rearranging the equation, we get:
x^2 + Ka[OH-] - Kw = 0
Substituting the values for Ka and Kw, we get:
x^2 + (1.9 × 10^-5)[OH-] - 1.0 × 10^-14 = 0
Solving for [OH-], we get:
[OH-] = (−Ka ± √(Ka^2 + 4Kw))/2 = (−1.9 × 10^-5 ± √(1.9 × 10^-5)^2 + 4(1.0 × 10^-14))/2
Taking the positive value of [OH-] (since pH = -log[H3O+], and [OH-][H3O+] = Kw), we get:
[OH-] = 2.4 × 10^-6 M
The pH of the solution can be calculated as:
pH = -log[H3O+] = -log(Ka/[OH-]) = -log(1.9 × 10^-5/[2.4 × 10^-6]) = 3.58
Therefore, the pH of a 0.681 M solution of NaN3 is approximately 3.58.
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How is the bond between carbon and hydrogen in methane DIFFERENT from the bond
between potassium and hydrogen in potassium hydride?
Answer:
How is the bond between carbon and hydrogen in methane DIFFERENT from the bond
Explanation:
What is the freezing point of a solution containing 8.1 g HBr in 100g water assuming?
The freezing point of the solution is -3.53°C.
The Chemical equation of the HBr is -
HBr → H⁺ + Br ⁻
Initial - 1 0 0
Final - 1-α α α
The total moles = 1 - α + α + α
= 1 + α
half factor = i = Total mol / Initial mol
= 1 + α / 1
= 1 + α
Now, Evolution in freezing point
ΔT f = i Kf m
kf = 1.86 (given)
m(molality = mass of solute / solvent (Kg))
Δ T f = (1 + α) × 1.86 × (mass/molar mass ) / solvent
[ α = 90/100 = 0.9 because 90% ionised]
putting the values in above equation -
= (1 + 0.9) × 1.86 × (8.1 × 1000) / 81 × 100(gm)
ΔT = 3.53°C
Then freezing point T f = T° f - ΔT
= 0 - 3.53°C
T f = -3.53°C
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Complete Question -
What is the freezing point of a solution containing 8.1 g HBr in 100gm. water assuming the acid to be 90% ionised:
[Kf for water =1.86Kmolarity^−1 ]
Humans have altered the composition
of Earth's atmosphere by
A. Making the air pressure drop
B. Making the air temperature drop
C. Polluting it with excess ozone
D. Polluting it with carbon dioxide gas
The answer is most likely D
The force of attraction that holds two atoms together within a molecule is
A
thermonuclear bonding
B
chemical bonding
crystal bonding
D
an atomic number
What happens to the moon every month? Science
Answer:
Every month Earth's moon goes through its phases, waning and waxing in its constant transformation from new moon to full moon and back again. This lunar cycle happens in part because the moon does not produce its own light; the silvery glow we see comes from sunlight reflecting off the moon's monochrome surface.
On the bottom beam of the triple beam balance, each small division stands for
A.) one centimeter
B.) one milliliter
C.) one gram
D.) one-tenth of a gram
Answer:
Hello There!!
Explanation:
I believe the answer is D.) one-tenth of a gram.
hope this helps,have a great day!!
~Pinky~
\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)
D.) one-tenth of a gram
Thanks.Hope it helps.Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the acti
brief evaluation of your work.
Activity
In the lesson, you saw how to perform three types of calculations related to solution concentration:
1. calculate molarity when given the components of the solution
2. calculate the amount of solute (in moles and grams) required to make a solution of a designated volume
3. calculate the volume of solution of a given molarity when the amount of solute is known
Now you will perform your own calculations. For each scenario below, list which calculation you are being asked to perform (A, B, or C fre
above) and then solve the problem.
Part A
Suppose you wanted to make an aqueous solution of sodium hydroxide that is 1.8 M. You want to make 250 ml of the solution. How man
of sodium hydroxide are needed to make this solution? Note which type of calculation you need to perform, and then perform the calcul
To create this solution, 0.450 moles of sodium hydroxide are required.
What is moles?The mole is the amount of stuff in a system that has as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is "mol". A mole is the mass of a material containing 6.023 x 1023 particles of that substance. The mole is the SI unit of material quantity. It is represented by the symbol mol. 1 mol of carbon-12 has a mass of 12 grams and a carbon atom count of 6.022140857 x 1023. (to 10 significant figures).
Here,
To find the amount of sodium hydroxide needed to make a 1.8 M solution of 250 ml, we need to multiply the molarity (1.8 M) by the volume (250 ml) and convert the volume to liters.
1.8 M * 0.250 L = 0.450 mol
So, 0.450 moles of sodium hydroxide are needed to make this solution.
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George has several plants in his garden once in a while he adds fertilizer to the soil then leaves absorb the nutrients in the fertilizer and you look healthy if a cell is compared to a plant which organelle helps transport fertilizer from the soil to leaf?
A. lysosome
B. mitochondrion
C. vacuole
D. vesicle
What is the final temperature of 100 g of water at -15°C added to a styrofoam cup filled with 220 g of water at 32°C?
Answer:
367g yan po ang answer ko sa module ko po
Explanation:
sana makatulong
A lump of zinc is tossed into a beaker of 500L of 14M hydrochloric acid. this reaction produces Hydrogen Gas and zinc (II) chloride. If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, what is the mass of the zinc?
If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .
Using the ideal gas law equation:
PV = nRT
n = (PV) / (RT)
= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)
= 42.71 moles
the balanced equation for the reaction between zinc and hydrochloric acid:
Zn + 2HCl -> \(ZnCl_{2}\) + \(H_{2}\)
1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.
The molar mass of zinc is 65.38 g/mol.
Mass of zinc = moles of zinc * molar mass of zinc
= 42.71 moles * 65.38 g/mol
= 2796.96 g
Therefore, the mass of the zinc is 2796.96 grams.
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Consider the reaction below: Na(s) + H₂O(l)= NaOH(aq) + H₂(g) 1. Indicate that the reaction is an oxidation-reduction reaction . 2.State the substances oxidized and reduced. 3.State the reducing agent and the oxidizing agent. 4. Write the balance half ionic equation for the oxidation and reduction equation.
The reaction is an oxidation-reduction reaction because here Sodium is oxidized from Na to Na⁺ while hydrogen is reduced from H⁺ to H₂⁰.
The reaction below: 3Na(s) + 3H₂O(l)= 3NaOH(aq) + H₂(g)
1. The reaction is an oxidation-reduction reaction because here Sodium is oxidized from Na to Na⁺ while hydrogen is reduced from H⁺ to H₂⁰.
2. The substances oxidized are Na and reduced. is H⁺.
3. The reducing agent is Na and the oxidizing agent is H₂O.
4. half ionic equation for the oxidation
Na => Na⁺ + e⁻
The half ionic equation for the reduction equation.
H₂O + e⁻ => H₂
An oxidation-reduction reaction is any chemical response in which the oxidation number of a molecule, atom, or ion changes by way of gaining or losing an electron. Redox reactions are common and crucial to some of the basic features of lifestyles, such as photosynthesis, respiration, combustion, and corrosion or rusting.
Oxidation is a chemical procedure. it is defined as a method that occurs whilst atoms or agencies of atoms lose electrons. some other manner to define oxidation is when a chemical species gains oxygen or loses hydrogen. whilst these activities occur, oxidation takes area.
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A lab technician needs to make 2.50 L of a 1.50 M solution of
NH4CI (molar mass = 53.5 g/mol). What mass of NH4CI is required?0.
O 0.07g
3.75g
80.3g
201.0g
Answer:
\( \huge{ \boxed{201.0 \: g}}\)
Explanation:
The mass of \( NH_4Cl \) required to make the solution can be found by using the formula;
\( c = \dfrac{m}{M \times v} \)
c is the concentration in M , mol/dm³ or mol/L
v is the volume in L or dm³
M is the molar mass in g/mol
m is the mass in grams
Making m the subject;
m = c × M × V\(m = 1.5 \times 53.5 \times 2.5 \\ = 200.625 \approx201.0\)
We have the final answer as
201.0 gWhat is the product of the reaction of propanamide with methylmagnesium bromide (1 eq.)?
The reaction of propanamide with methylmagnesium bromide (1 eq.) yields a tertiary amide.
Reversible addition-elimination nucleophilic substitution reactions take place in this reaction mechanism, involving the bimolecular attack of the nucleophile (methylmagnesium bromide) and the displacement of the leaving group (bromide) from the substrate (propanamide).
This yields a carbocation intermediate, which is then attacked by water. The resulting alcohol undergoes dehydration through an acid-catalyzed cyclization to form an α,β-unsaturated intermediate. After protonation, the π-bond of the intermediate is eliminated and the tertiary amide is formed.
The overall stoichiometry of the reaction is 1:1, with one equivalent of propanamide and one equivalent of methylmagnesium bromide reacting to form the product tertiary amide. This reaction is useful in organic synthesis, as the tertiary amide can be hydrolyzed in acidic media to produce an amine, which can be used in further synthetically reactions.
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According to octet rule, atoms tends to acheive _____ electrons in the outermost shell.A. sixB. fourC. eightD. one
According to the octet rule, atoms tend to achieve eight electrons in their outermost shell. So the correct answer is C. eight.
The octet rule is a chemical rule of thumb that states that atoms of low atomic number tend to combine in such a way that they each have eight electrons in their valence shells, giving them the same electronic configuration as a noble gas. The rule is applicable to the main-group elements, especially carbon, nitrogen, oxygen, and the halogens. It is based on the observation that when atoms have eight electrons in their outermost shell, they are chemically stable and less likely to react with other atoms.
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what elements react with mercury?
fluorine, F2, chlorine, Cl2, bromine, Br2, or iodine, I2