plot the image of point Q under the translation (x,y) —— (x-3,y+4)

The center is (1,0), thus the center lies on the x-axis, the radius is 3 units and the radius of the circle is the same with x² + y² = 9.

The radius is half the diameter of a circle and the center of the circle is a point from which all distance to the edge of the circle is equal.

The equation that represents the center of the circle equation is (x - h)² + (y - k)² = r², where h,k represents the center and r is the radius.

Our circle in this form is: (x − 1)² +(y − 0)² = 3. Thus, h = 1, k = 0, r = 3. The standard form is y² + (x − 1)² = 9.

We can conclude that the center is (1,0), thus the center lies on the x-axis, the radius is 3 units and the radius of the circle is the same with x² + y² = 9.

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The comparison of two quantities with different units is called a ratio and proportion. A ratio that specifically compares two quantities measured in different units.

Comparing amounts is done using a ratio. A ratio demonstrates how many times one amount fits inside another or how much larger one amount is than another.

If I need to mix some cement, I would add two parts cement to four parts sand. The two numbers are both portions of the entire. Hence, the 2:4 ratio (6 parts in total). The written version is crucial; 4:2 would produce a different blend.

Ratios are expressed in their most basic form. There are five green and fifteen red dots in the figure on the right. The ratio is 15:5, but like with fractions, this can be boiled down to its most basic form.

If you look at the relationship between the numbers 15:5 as is 3:1, you can see that 3 is multiplied by 5 to obtain 15 and that 1 is multiplied by 1 to get 5. The ratio, as we can see in the image, is also 3:1.

Therefore,

The comparison of two quantities with different units is called a ratio and proportion. A ratio that specifically compares two quantities measured in different units.

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To solve this problem, we need to use the Central Limit Theorem, which states that the distribution of the sample means approaches a normal distribution as the sample size increases.

First, we need to find the mean and standard deviation of the sample mean hardness. The mean is simply the population mean, which is given as 50.5. The standard deviation of the sample mean is given by the formula:

standard deviation of sample mean = population standard deviation / sqrt(sample size)

The population standard deviation is given as 0.5, and the sample size is 35, so:

standard deviation of sample mean = 0.5 / sqrt(35) = 0.084

Next, we need to standardize the sample mean hardness using the z-score formula:

z = (sample mean hardness - population mean) / (standard deviation of sample mean)

z = (51 - 50.5) / 0.084 = 5.95

Finally, we need to find the probability that a standard normal distribution is greater than or equal to 5.95. This can be done using a z-table or a calculator. Using a calculator, we get:

P(Z ≥ 5.95) ≈ 0

Therefore, the approximate probability that the sample mean hardness for a random sample of 35 pins is at least 51 is very close to 0.

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The number of classes in the frequency table as represented in the task content is; 5.

It follows from the task content that the number of classes in the frequency table as given in the task content is to be determined.

By observation, the data representation in the task content is a group data representation and hence, the classes are as follows;

On this note, the number of classes in the frequency table as given in the task content is; 5.

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This statement is TRUE. When we are doing a problem, we could use these questions " what is the equation asking you do? what is your plan to solve?" as the part of starting solving the problem in math about equation matter.

In mathematics, an equation is an equation statement that contains one or more variables. Solving equations consists of determining which variable values makes an equality true. The variable is also called "unknown" and the value of an "unknown" that satisfies the equation is called the equation solution. There are two types of equations: identity and conditional equations. True identity for all variable values. The conditional equation is true only for certain variable values.

An equation is a mathematical statement in the form of a symbol which states that two things are exactly the same. Equations are written with an equal sign (=), as follows:

x + 3 = 5, which states that value x = 2.

2x + 3 = 5, which states that the value x = 1.

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PreAlg students spend significantly less time doing homework compared to ElemAlg and InterAlg students, while there is no significant difference in homework time between ElemAlg and InterAlg students.

What is significantly ?

Significantly" is the keyword that indicates a notable or meaningful difference or result in the context of statistical analysis. It is often used to describe findings that have a high level of confidence and statistical significance, indicating that the observed difference or relationship is unlikely to have occurred by chance.

Based on the given data and statistical analysis, the conclusion is as follows:

PreAlg compared to ElemAlg:

The sample mean for PreAlg (1.32) is significantly different from the sample mean for ElemAlg (3.18) with a t-value of 5.08 and a p-value of 0.000. Therefore, we can conclude that PreAlg students spend significantly less time doing homework compared to ElemAlg students.

PreAlg compared to InterAlg:

The sample mean for PreAlg (1.32) is significantly different from the sample mean for InterAlg (4.42) with a t-value of 3.64 and a p-value of 0.003. Hence, we can conclude that PreAlg students spend significantly less time doing homework compared to InterAlg students.

ElemAlg compared to InterAlg:

The sample mean for ElemAlg (3.18) is not significantly different from the sample mean for InterAlg (4.42) with a t-value of 1.49 and a p-value of 0.163. Therefore, we fail to reject the null hypothesis, and we cannot conclude a significant difference in homework time between ElemAlg and InterAlg students.

In summary, the PreAlg students have significantly lower homework time compared to both ElemAlg and InterAlg students. However, there is no significant difference in homework time between ElemAlg and InterAlg students.

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Answer:

Should be C

Step-by-step explanation:

Answer:

Interquartile range = 40

Step-by-step explanation:

interquartile range = Q3-Q1

It has 7 numbers, in order to make it even we remove the middle number (70) to make two sets of quartiles

Q1 = 50 (middle of the lower quartile)

Q3= 90 (middle of the higher quartile)

The equation of the circle is with the diameter given is x² + y² = 9.

The standard form of the equation of a circle is (x - h)² + (y - k)² = r², where (h,k) is the center of the circle.

We can quickly determine the circle's centre and radius thanks to this form. We must first square the x and y terms before rearranging the components in order to transform a circular equation into standard form.

The endpoints of the diameter is (-3,0) and (3,0).

Now, using the section formula the coordinates of radius are:

((-3+3)/2, (0+0)/2) = (0,0

The standard form of the equation of a circle is (x - h)² + (y - k)² = r², where (h,k) is the center of the circle.

Substituting the values:

(x - 0)² + (y - 0)² = 3²

Hence, the equation of the circle is x² + y² = 9.

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Answer:

sorry little busy to calculate

Step-by-step explanation:

+5x+2y+z=15

3x +4y_z=19,,,choose which term u wanna eliminate first so u will be able to get your answer there

Answer:

theres no answers to choose from

The amount of money in Lucia's account after 5 years will be $1,105.5.

A loan or deposit's interest is computed using the starting principle and the interest payments from the ago decade as compound interest.

We know that the compound interest is given as

A = P(1 + r)ⁿ

Where A is the amount, P is the initial amount, r is the rate of interest, and n is the number of years.

Lucia opened a savings account and deposited $600.00 as principal. The account earns 13% interest, compounded annually. Then the amount of money after 5 years will be given as,

A = $600 × (1 + 0.13)⁵

A = $600 × (1.13)⁵

A = $600 × 1.84

A = $1,105.5

The amount of money in Lucia's account after 5 years will be $1,105.5.

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a) two representatives be picked in 5850 ways so that one is a mathematics major and the other is a computer science major. b) one representative be picked in 343 ways who is either a mathematics major or a computer science major.

Product Rule: If one event occurs in m ways and a second event occurs in n ways, the number of ways the two events occur in the sequence is m×n ways.

Sum Rule: If an event occurs either in m ways or in n ways (non-overlapping), the number of ways the event can occur is m+n ways.

according to the question,

Mathematics majors =18 and Computer science majors = 325

A. We need to use the product rule because the first event is picking up a Mathematics major and the second event is picking up a computer science major.

= 18 x 325

= 5850

B. Here sum rule is applicable because the event is picking up a mathematics major or a computer science major.

= 18 + 325

= 343

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(complete question)

there are 18 mathematics majors and 325 computer science majors at a college. a) in how many ways can two representatives be picked so that one is a mathematics major and the other is a computer science major? b) in how many ways can one representative be picked who is either a mathematics major or a computer science major.

Answer:

>

Step-by-step explanation:

because

16/24 > 9/24 :)

The theoretical probability that Chandra will be chosen as one of the science fair participants is 0.8 or 80%.

Theoretical probability of an event is the ratio of number of favourable outcome to the total expected number of outcome of that event.

Five students, Adriana, Ben, Chandra, Diana, and Ernesto, would each like one of the four spots at the regional science fair.

Their names are placed in a hat, and four names are chosen at random to decide who attends the fair.

The total number of ways 4 names can be taken out from 5 names is,

\(^5C_4\).

Here one spot needs to be fixed for Chandra. Now the total number of outcome remain 4 and favourable outcome remain 3.

Thus, the number of ways 4 names can be taken out such that it contains the name Chandra is

\(^4C_3\).

The theoretical probability that Chandra will be chosen as one of the science fair participants is,

\(P=\dfrac{^4C3}{^5C4}\\P=\dfrac{4}{5}\\P=0.8\\P=80\%\)

Thus, the theoretical probability that Chandra will be chosen as one of the science fair participants is 0.8 or 80%.

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the null hypothesis for the given t-test\(`[h, p, 0] = ttest(morningsections, eveningsection)`\)

In the t-test formula for hypothesis testing, the null hypothesis states that there is no difference between the two groups being tested. Therefore, for the given t-test below:

`[h, p, 0] = ttest(morningsections, eveningsection)`,

the null hypothesis is that there is no significant difference between the average bedtimes of students in morning sections versus evening sections.

To explain further, a t-test is a type of statistical test used to determine if there is a significant difference between the means of two groups. The formula for a t-test takes into account the sample size, means, and standard deviations of the two groups being tested. It then calculates a t-score, which is compared to a critical value in order to determine if the difference between the two groups is statistically significant.

In this case, the two groups being tested are morning sections and evening sections, and the variable being measured is the average bedtime of students in each group. The null hypothesis assumes that there is no significant difference between the two groups, meaning that the average bedtime of students in morning sections is not significantly different from the average bedtime of students in evening sections.

The alternative hypothesis, in this case, would be that there is a significant difference between the two groups, meaning that the average bedtime of students in morning sections is significantly different from the average bedtime of students in evening sections. This would be reflected in the t-score obtained from the t-test, which would be compared to the critical value to determine if the null hypothesis can be rejected or not.

In conclusion, the null hypothesis for the given t-test\(`[h, p, 0] = ttest(morningsections, eveningsection)`\) is that there is no significant difference between the average bedtimes of students in morning sections versus evening sections.

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The distance between the two towns on the earth's surface is equal to the length of two bananas.

Given that the scale of the map is 1:1500 and the distance between two towns on the map is measured as two bananas. We are to find out the distance between the two towns on the earth's surface.

Let's say, the actual distance between the two towns on the earth's surface be 'D' km, then the distance between the two towns on the map is 1.5 * 10-3D km.

Now, if the distance between the two towns on the map is measured as two bananas, we can say that the actual distance between the two towns on the earth's surface is equal to the length of two bananas. Therefore,

D = Length of two bananas

Hence, the distance between the two towns on the earth's surface is equal to the length of two bananas.

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Answer: 12

Step-by-step explanation:

This is a direct proportion and we use the formula:

y = kx

If y = −4 when x=2, we need to find the constant of proportionality. This will be:

y = kx

-4 = 2k

k = -4/2

k = -2

To find y when x=−6 guess this:

y = kx

y = -2 × -6

y = 12

Hence, The value of y = 12 when x = -6.

Given that , Y varies directly with x .

If y=−4 when x=2,

Find y when x=−6.

According to the question,

This is a direct variation , y = kx

If,

y = −4  when x=2,

y = kx

-4 = 2k

\(k = \frac{-4}{2}\)

k = -2

To find ;

y when x = −6

y = kx

y = (-2) (-6)

y = 12

Hence, The value of y = 12 when x = -6.

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Answer:

12.5% increase

Step-by-step explanation:

To find the percentage increase ( students joined)

Take the new number minus the original amount

There are 27 students in the class after 3 joined

27 - 24 = 3

Divide by the original amount

3/24 = 1/8 = .125 = 12.5%

Answer:

12.5%

Step-by-step explanation:

Intial number = 27

Final number = 24 + 3 = 27

Percentage change :-

Answer:

A

Step-by-step explanation:

i had the same question when i had honors trust me :> you gut this

Answer:

36

Step-by-step explanation:

180-126=54 Since two angles are supplimentary if they both add up to 180, and 90-54=36 since two angles are complementary if they add up to 90.

The runner's average speed in kilometers per hour is 24.257 km.

The total distance covered by the runner is 1 mile. The relation between kilometers and miles is given as 1 km = 0.62 mi. Converting 1 mile to km by using the given relation, we get-

Distance = 1 mile

 = 1 mile × [1 km/0.62 mile]

= 1.6129 km

The time taken to complete a 1-mile run is 3 minutes and 59.37 seconds. The relation between hours and minutes is given below.

1 hour = 60 minutes ……(1)

Converting 3 minutes to hours using equation (1), we get-

3 minutes = 3 minutes × [1 hour/60 minutes]

= 0.05 hours

The relation between hours and seconds is given below.

1 hour = 3600 second …….(2)

Converting 59.37 seconds to hours using equation (2), we get-

59.37 seconds = 59.37 seconds × [1 hour/3600 seconds]

= 0.016492 hours

Total time to cover 1 mile = (0.05 + 0.016491) hours = 0.066492 hours

The average speed of the runner is calculated by the following relation-

Average Speed = Distance (km)/time (hours)

= 1.6129 km/0.066492 hours

= 24.257 km/hour

Therefore, the average speed in kilometers per hour is 24.257km.

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A 98% confidence interval estimate of the mean wake time for a population with zopiclone treatments is 74.26 to 125.54.

What is a confidence interval?

A confidence interval (CI) is a range of values that, with a particular level of certainty, is likely to encompass a population value. A population mean that sits between an upper and lower interval is frequently stated as a percentage.

Here,

From the standard normal table, the z-critical value at 98% confidence interval is 2.33 so,

98%C.I. = µ ± z * σ /   n = 98.90 ± 2.33 * 42.30 / sqrt of 16  = 98.90 ± 24.64 = 74.26 to 125.54

The mean wake time of 102.80 minutes before the treatment due to the mean wake time of 102.80 minutes included in the 98% confidence interval which is between 74.26 and 125.54. Zopiclone does not appear effective.

Hence, A 98% confidence interval estimate of the mean wake time for a population with zopiclone treatments is 74.26 to 125.54.

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hello

the question present here relates to metrics and conversion of units

note : 1km = 1000m

to covert 5000m to kilometer, we just need to equate both and find the value for the unknown

The prediction thay the shopper can make about buying mystery bags in the future is A.There will be 4 more spy novels in 8 bags than in 6 bags.

Since the shopper bought 3 mystery bags and found that 6 books were spy novels, it means that there are 6/3 = 2 spy novels in each bag.

There, the prediction thay the shopper can make about buying mystery bags in the future is that there will be 4 more spy novels in 8 bags than in 6 bags.

This is because there's an extra 2 bags which will be equal to 4 spy novels

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The vectors uvt and vut are related by a simple matrix transposition.

In other words, if we consider u, v, and t as columns of a matrix, say A, then uvt is simply the product of A and the vector [1 0 1] (a column vector with 1's in the first and third rows and 0 in the second row).

On the other hand, vut is the product of the transposed matrix of A (denoted as A^T) and the vector [1 0 1]. Therefore, uvt and vut are related as follows:

vut = (A^T) [1 0 1]

In summary, uvt and vut are related through a matrix transposition, with vut being the product of the transposed matrix of A and the vector [1 0 1].

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The 90% confidence interval for the proportion of district residents in favor of starting the school day 15 minutes later is (0.392, 0.548). The true proportion is estimated to lie within this interval with 90% confidence.

To calculate the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later, we can use the following formula:

CI = p ± z*(√(p*(1-p)/n))

where:

CI: confidence interval

p: proportion of residents in favor of starting the day later

z: z- score based on the confidence level (90% in this case)

n: sample size

First, we need to calculate the sample proportion:

p = 94/200 = 0.47

Next, we need to find the z- score corresponding to the 90% confidence level. Since we want a two-tailed test, we need to find the z- score that cuts off 5% of the area in each tail of the standard normal distribution. Using a z-table, we find that the z- score is 1.645.

Substituting the values into the formula, we get:

CI = 0.47 ± 1.645*(√(0.47*(1-0.47)/200))

Simplifying this expression gives:

CI = 0.47 ± 0.078

Therefore, the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later is (0.392, 0.548). We can be 90% confident that the true proportion lies within this interval.

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