PLEASEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPPP
Examine the data table below from a student’s measurements of water. How would you describe the trend in the data presented? Explain your choice. Make sure you proofread your response.
Mass of water (g)
V no olume of water (mL)
25
25
50
50
100
100
Criteria
Exemplary
Good
Poor
Trend/Relationship
Correct - 5 pts
----
Incorrect - 0 pts
Explanation
5 pts
3 pts
1 pt
Mechanics
Give an original example of a statement that could be a scientific hypothesis. Describe how a scientist would try to prove the hypothesis. Make sure to proofread your response. The rubric below is how you will be scored on this question:
Answers
Answer:
100000000000000000000000000
Related Questions
When zinc reacts with copper sulfate solution, zinc sulfate solution and copper are formed.(i) An experiment was carried out to measure the temperature change when zinc powder reactswith copper sulfate solution.initial temperature of copper sulfate solution = 20 °Cfinal temperature of mixture after the reaction = 46 °CExplain what the temperature readings show about the type of heat change that occurs duringthis reaction.
Answers
The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.
In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.
The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.
During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.
The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.
The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.
In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.
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What happens to the amount of solution when we add food colour to it?
Answers
Answer:
We need more? What else is in the question? This is unanswerable.
Explanation:
What is the specific heat capacity of gold if it requires 48.8 J to raise the temperature of 15 grams of gold 25oC?
Answers
Answer:
0.13 J/gC i believe.
Explanation:
Answer:
130.133 J/(kg·K)
Explanation:
Result in other units:
0.130133 J/(g·K)
31.0876675695 cal/(kg·K)
0.0310876675695 kcal/(kg·K)
0.130133 J/(g·°C)
Select the proper IUPAC name for the following compound, including the (R) or (S) designation where appropriate.
Answers
The IUPAC designation for the halogenated chemical with the following structural formula will be trans-1,3-Dichlorocyclohexane.
What does IUPAC mean?The longest chain of carbons connected by a single bond, whether in a continuous chain or a ring, serves as the foundation for IUPAC nomenclature. Any variations, whether involving numerous bonds or atoms other than carbon and hydrogen, are indicated by prefixes or suffixes in accordance with a particular set of priorities.
What is a good IUPAC example?Thus, the IUPAC name is 2,5,5-trimethyl-2-hexene. The longest chain in example (2) that contains both carbon atoms from the double bond is five atoms long. There is a seven-carbon chain present, however there is only one double-bonded carbon atom in the chain. Consequently, this compound's root name will be
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What word means the same as Chordata?
A. non-vertebrate
B. vertebrate
Answers
n. urochordate, cephalochordate, tunicate, craniate, urochord, vertebrate.
How many moles of nitrogen gas would be produced if 6.42 moles of
copper(II)oxide were reacted with excess ammonia in the following
chemical reaction?
2 NH3(g) + 3 CuO (s) → 3 Cu(s) + N₂(g) + 3 H₂O(g)
Answers
2 NH3(g) + 3 CuO(s) → 3 Cu(s) + N2(g) + 3 H2O(g)
The stoichiometry of the reaction shows that for every 3 moles of CuO reacted, 1 mole of N2 is produced. Therefore, we can set up a proportion:
3 mol CuO / 2 mol NH3 = 6.42 mol CuO / x mol N2
Cross-multiplying and solving for x, we get:
x = (2 mol NH3 x 6.42 mol CuO) / 3 mol CuO
x = 4.28 mol N2
Therefore, 4.28 moles of nitrogen gas would be produced if 6.42 moles of copper(II) oxide were reacted with excess ammonia.
In the chemical reaction given, 3 moles of copper(II)oxide produce 1 mole of nitrogen gas. Therefore, if we start with 6.42 moles of copper(II)oxide, we would produce 2.14 moles of nitrogen gas.
Explanation:In this problem, we're trying to figure out how many moles of nitrogen gas get produced from a reaction involving copper(II)oxide and ammonia. We can figure this out by using stoichiometric ratios from the balanced chemical equation. In the equation, we see that 3 moles of copper(II)oxide produce 1 mole of nitrogen. So, we can set up a ratio: 3 moles of copper(II)oxide : 1 mole of nitrogen corresponds to 6.42 moles of copper(II)oxide : X moles of nitrogen. Solving for X gives us X = 6.42 * (1/3) = 2.14. Therefore, if 6.42 moles of copper(II)oxide are reacted with excess ammonia, 2.14 moles of nitrogen gas are produced.
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what is a nucleus and what are the functions?
Answers
Which of the following best describes the number of atoms for each element in the chemical reaction? A. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the product side. B. There are 6 carbon atoms, 12 hydrogen atoms and 8 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the product side. C. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms, and 3 oxygen atoms on the product side. D. There are 6 carbon atoms, 12 hydrogen atoms and 12 oxygen atoms on the reactant side and 1 carbon atom, 2 hydrogen atoms, and 3 oxygen atoms on the product side.
Answers
The correct answer is A. There are 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the reactant side, and 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the product side.
This is because of the law of conservation of matter, which states that matter cannot be created or destroyed by a chemical reaction. Therefore, the number of atoms of each element must remain the same on both sides of the reaction.
In this case, the number of carbon, hydrogen, and oxygen atoms must remain the same on both the reactant and product sides.
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How many moles of C5H120 would it take to generate 4.2 moles of CO2 from combustion?
2 CsH120 + 15 O2 → 10 CO2 + 12 H2O
Answers
Answer:
0.84 moles
Explanation:
from the equation 2 moles of pentanol generated 10 moles of CO2 therefore, x mol of pentanol will generate 4.2mol of CO2.
making x the subject of formula=4.2*2/10
=0.84 moles of
pentanol
How many internal parts or “organelles” are there in a plant cell?
please i need a answer!
Answers
Answer: it has 2 parts
Explanation:
Firstly, plant cells have a cell wall that surrounds the cell membrane, whereas animal cells do not. Plant cells also possess two organelles that animal cells lack: chloroplasts and a large central vacuole
How many moles of H20 are contained in 4.21 x 1024 molecules of H2O?
O A 2.53 x 1048 moles
OB. 2.34 x 1023 moles
C. 6.99 moles
OD. 0.143 moles
Answers
Answer:
C. 6.99 moles
Explanation:
To convert molecules to moles we simply divide the given number of molecules by Avogadro's number, 6.022 x 10²³
Given number of molecules : 4.21 x 10^24
Number of moles : 4.21 x 10^24 / 6.022 x 10²³ = 6.99 moles ( rounded )
The answer is C
PLZ Answer ASAP
I need help with this thank you if you get it right
Answers
Answer:
A) -277.6 KJ/mol
Explanation:
The enthalpy data for first equation is not given but it should be somewhere around ΔH = –1367 kJ/mol.
So, Basically you want to rearrange the given three equations to match the equation they want you to have. To get the final equation, reverse reaction first reaction (turn its value into positive), multiply second equation by 2, multiply third equation by 3 and you add em all up:
You get 1367 + (2* -393.5) + (3 * -285.8) ~ -277.6 KJ/mol
The photo shows a Newton's cradle. The ball on the left can be pulled away
from the others. After the ball is released, it strikes the next ball in line and
the ball on the far right side of the toy moves up and away,
What most likely explains the motion of the ball on the far right?
A. The mechanical energy of the ball on the left is transferred in the
form of waves to the ball on the right
B. The potential energy of the ball on the left is transferred directly to
the ball on the right
C. The potential energy of the ball on the left is transferred in the
form of waves to the ball on the root
D. The mechanical energy of the ball on the left is transferred through
the other balls to the ball on the right
Answers
The characteristics of the conservation of energy and momentum allow to find the result for the movement of the balls, the correct answer is:
D. The mechanical energy of the ball on the left is transferred through
the other balls to the ball on the right.
Mechanical energy is the sum of the kinetic energy and the potential energies. In the case that there is no friction, the mechanical energy is conserved.
The momentum is defined by the product of the mass and the velocity of the body, in an isolated system the momentum is conserved and the shocks can be of two types:
Inelastic. Where part of the energy is transformed into internal energy and the kinetic energy is not conserved. Elastic. Where kinetic energy is conserved.
In the case indicated, when removing the ball, it gains a height, therefore if the initial mechanical energy is
Em₀ = mgh
When it reaches the lowest point, just before it hits the ball its energy is:
\(Em_f\) = 1 / 2m v²
Em₀ = Em_f
v = \(\sqrt{2gh}\)
collides with the other ball and transfers its momentum in an elastic collision, the balls do not stick, as all the energy of the ball is kinetic, this energy is transferred to each ball until it reaches the last one, where the kinetic energy is transformed into potential energy a increases its height.
Let's analyze the answers:
A. False. This is a collision of particles there are no waves.
B. False. At the lowest point the ball on the left has kinetic energy.
C. False. It is a collision of particles, there are no waves.
D. True. The energy from the elastic collisions is transferred through each ball until it reaches the last ball.
In conclusion, using the characteristics of the conservation of energy and momentum, we can find the result for the movement of the balls, the correct answer is:
D. The mechanical energy of the ball on the left is transferred through the other balls to the ball on the right
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All of the bond lengths in a compound having resonating structures are identical.
A. True
B. False
Answers
Answer:true
Explanation:
Which is the correct statement regarding the relative Rf values of the starting methyl benzoate vs the product, methyl m-nitrobenzoate on a silica gel TLC plate. The product has a higher Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is less polar than the starting methyl benzoate. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. The product has a lower Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate. 1.5 points QUESTION 2 Methyl benzoate is more reactive than benzene in Electrophilic Aromatic Substition [EAS] reactions. True False 1 points QUESTION 3 Methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition [EAS] reactions. True False
Answers
Answer:
1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.
2. False
3. True
Explanation:
In chromatography, there is a stationary phase and a mobile phase. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
Since silica gel is a polar solvent, it will retain the more polar product methyl m-nitrobenzoate compared to the methyl benzoate starting material.
In comparing the electrophillic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition
The final result has a higher Rf value because the TLC plate has more polarity than the other compound.
The answer to the following question is as follows:-
False True
In chromatography, it is a process that is used to separate the different components on the basis of their votality. The ratio of the distance moved by a component and the distance moved by the solvent gives the retention factor (Rf).
In comparing the electrophilic aromatic substitution of m-nitrobenzoate and methyl benzoate, we must remember that the presence of electron-withdrawing groups on the aromatic compound deactivates.
The compound towards electrophilic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substitution and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substitution.
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What is the pH of a 50.0 mL solution of a 0.250 M HC2H3O2 solution after the
addition of 50 mL of 0.250 M NaOH to it? The Ka value for HC2H3O2 is 1.8 x 10-5
.
Answers
A 50.0 mL solution of 0.250 M HC₂H₃O₂ before and after adding 50 mL of 0.250 M NaOH has a pH of 2.87, the pH changes due to the formation of a buffer solution, which can be calculated using the Henderson-Hasselbalch equation.
How to calculate pH of the solution?This problem requires us to calculate the pH of a buffer solution after the addition of a strong base. A buffer solution is one that resists pH changes when modest amounts of acid or base are added. The buffer system in this case is the weak acid, acetic acid (HC₂H₃O₂) and its conjugate base, acetate ion (C₂H₃O₂-).
Before the addition of NaOH, we have a solution of 0.250 M HC₂H₃O₂, which we can assume to be completely dissociated in water:
HC₂H₃O₂ + H₂O ⇌ H₃O+ + C₂H₃O₂-
HC₂H₃O₂ has a Ka value of 1.8 x 10-5. We can use this Ka value to calculate the equilibrium concentration of H3O+ and C₂H₃O₂- in the solution.
First, we need to calculate the initial concentrations of HC₂H₃O₂ and C₂H₃O₂-.
moles of HC₂H₃O₂ = 0.250 M × 0.0500 L = 0.0125 mol
moles of C₂H₃O₂- = 0 mol (since there is no NaOH added yet)
Since HC₂H₃O₂ is a weak acid, it only partially dissociates in water. The equilibrium concentrations of H₃O+ and C₂H₃O₂- can be calculated using the Ka expression:
Ka = [H₃O+][C₂H₃O₂-]/[HC₂H₃O₂]
We can assume that the initial concentration of H3O+ is negligible compared to the amount that will be produced by the dissociation of HC₂H₃O₂, so we can simplify the expression to:
Ka = [H₃O+]²/[HC₂H₃O₂]
[H₃O+]² = Ka × [HC₂H₃O₂]
[H₃O+]² = 1.8 × 10⁻⁵ × 0.0125
[H₃O+] = 1.34 × 10⁻³ M
Now that we know the equilibrium concentration of H₃O+, we can use the pH formula to calculate the pH:
pH = -log[H₃O+]
pH = -log(1.34 × 10⁻³)
pH = 2.87
This is the pH of the buffer solution before the addition of NaOH.
Next, we add 50 mL of 0.250 M NaOH to the solution. NaOH is a strong base, so it completely dissociates in water to produce OH- ions:
NaOH → Na+ + OH-
The OH- ions will react with the acetate ions in the buffer solution to form water and acetate ions:
OH- + C₂H₃O₂- → H₂O + C₂H₃O₂-
This reaction will consume some of the acetate ions in the buffer solution, causing the equilibrium to shift to the left to produce more acetate ions.
To calculate the new concentrations of H₃O+ and C₂H₃O₂-, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([C₂H₃O₂-]/[HC₂H₃O₂])
where pKa = -log(Ka), [C₂H₃O₂-] is the equilibrium concentration of acetate ions, and [HC₂H₃O₂] is the equilibrium concentration of acetic acid.
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if 100s of heat is added to a system and 0.100ks of work is done by the system, what is the value of DE
Answers
If 100 s of heat is added to a system and 0.100 ks of work is done by the system, then the value of ΔE or DE (change in internal energy) is 200 J, which is in option A. This is as per the first rule of thermodynamics.
ΔE = Q - W
ΔE (change in internal energy)
Given that 100 J (joules) of heat is added to the system (Q = 100 J) and 0.100 kJ (kilojoules) of work is done by the system (W = -0.100 kJ), we need to ensure that the units are consistent.
Since 1 kJ = 1000 J, we can convert the work done to joules:
W = -0.100 kJ = -0.100 × 1000 J = -100 J
Now one can substitute the values into the equation:
ΔE = Q - W
= 100 J - (-100 J)
= 100 J + 100 J
= 200 J
Therefore, the value of ΔE (change in internal energy) is 200 J.
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complete question is below
if 100s of heat is added to a system and 0.100ks of work is done by the system, what is the value of DE
A. 200 j
B.50 j
C.2 j
D. 10000j
draw styrene
draw the structure of cyrene
Answers
Object X carries a net negative charge. Danny touches object X and all of the excess negative charge leaves it. Danny effectively grounds object X by touching it.
Answers
Answer: B.) Object X Is A Conductor
Explanation: Since object X was able to lose all of its charge by being grounded, this means that its charges were able to move about freely. This strongly suggests that object X is a conductor. If object X had been an insulator, the ground would have had virtually no effect on its net charge.
Bauxite is best used for making (1 point)
nails
wires
paints
drains
***missed it on test when answered wires****
Answers
To solve this we must be knowing each and every concept related to ore and bauxite. Therefore, Bauxite is best used for making wires. The correct option is option B.
What is bauxite?Aluminum's primary source of supply is bauxite. Due to its small weight and ease of molding into fine wire or sheets, aluminum is particularly useful.
All across the world, bauxite may be found. The greatest deposits of this ore are in Australia and Guinea, an African nation. Although bauxite was initially found in France, it may now be found all over the world, such as the Caribbean.
Therefore, Bauxite is best used for making wires. The correct option is option B.
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What sample at STP has the same number of molecules as 5 L of NO2
Answers
Answer:
5l NO
2
at STP
No. of molecules=
22.4
5
mol=
22.4
5
×N
A
molecules
A) 5ℊ of H
2
(g)
No. of moles=
2
5
mol=
2
5
×N
A
molecules
B) 5l of CH
4
(g)
No. of moles of CH
4
=
22.4
5
mol=
22.4
5
N
A
molecules
C) 5 mol of O
2
=5N
A
O
2
molecules
D) 5×10
23
molecules of CO
2
(g)
Molecules of 5l NO
2
(g) at STP=5l of CH
4
(g) molecules at STP
Therefore, option B is correct.
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Which amphibian organ has a high blood supply and many folds to increase surface area?
a. heart
b. stomach
c. lungs
d. brain
Answers
Answer:
lungs
Explanation:
How do "rules" help scientists understand the world?
O A. Rules of nature are created by scientists.
B. Scientists use rules to form their hypotheses.
C. Rules help scientists know which scientific question to ask.
D. Rules govern how the world behaves.
Answers
Answer:
B.Scientists use rules to form their hypotheses.
Explanation:
I already know the answer because it is our lesson last quarter.Answer:
D. rules govern how the world behaves
Explanation:
What units are carbon emissions measured in?
Answers
Answer:
GHG emissions are often measured in carbon dioxide (CO2) equivalent. To convert emissions of a gas into CO2 equivalent, its emissions are multiplied by the gas's Global Warming Potential (GWP).
hi how do i do d (ii)? thanks!
Answers
A solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.
We must first convert the amount of nitrate(V) ions in drinking water to moles per litre since the threshold concentration over which "Blue-Baby" Syndrome might manifest is 0.05 mg/cm3.
It is necessary to know the molar mass of nitrate(V) ions in order to convert from mg/cm3 to moles per litre (NO3-).
The formula below can be used to determine NO3-'s molar mass:
N: 14.01 g/mol for the atomic mass
O: 16.00 g/mol is the atomic mass (3 oxygen atoms in NO3-)
NO3-'s total molar mass is equal to 14.01 + 16.00 x 3 = 62.01 g/mol.
Let's now translate the specified concentration from mg/cm3 to moles/liter (M).
As 1 g = 1000 mg, 1 mg/cm3 is 0.001 g/cm3.
1 cm3 = 0.001 g/mL multiplied by 0.001 g/cm3
1 L/1000 mL x 0.001 g/mL = 0.001 g/L
We must change the grams into moles using the molar mass in order to get the molarity:
1.61 × 10-5 mol/L = 0.001 g/L / 62.01 g/mol
As a result, a solution with nitrate(V) ion concentrations over 0.05 mg/cm3 has a molarity of around 1.61 x 10-5 mol/L.
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Which is NOT a property of metals?
Answers
Answer:
Silicon????
Explanation:
I searched your question and it gave me that. I hope it helps. If not sorry!
Hydrogen
Carbon
Nitrogen
oxygen
But silicone is both is a metal but also a non metal so it both that’s is call metalloids
CAN SOMEONE HELP WITH THIS QUESTION?✨
It takes 29.61 mL of 0.246 M sodium hydroxide to titrate 10.00 mL of sulfuric acid solution. What is the molarity of sulfuric acid?
Answers
Answer:
The balanced equation for the reaction between sodium hydroxide and sulfuric acid is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From this equation, we can see that one mole of sulfuric acid reacts with two moles of sodium hydroxide.
The amount of sodium hydroxide used in the titration is:
n(NaOH) = C(NaOH) x V(NaOH) = 0.246 M x 29.61 mL = 0.007298 moles of NaOH
Since two moles of NaOH react with one mole of H2SO4, the amount of H2SO4 present in the sample is:
n(H2SO4) = 0.007298 moles of NaOH / 2 = 0.003649 moles of H2SO4
The volume of the sulfuric acid solution used in the titration is 10.00 mL. Therefore, the molarity of the sulfuric acid solution is:
M(H2SO4) = n(H2SO4) / V(H2SO4) = 0.003649 moles / 10.00 mL = 0.3649 M
So, the molarity of sulfuric acid is 0.3649 M.
What would happen if the number of protons were to change in an atom?
Answers
Answer: you will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive. If you change the number of neutrons in an atom, you get an isotope of the same element.
Explanation:
How many significant figures are in the following number? 3,000.0 x 10⁴ grams
Answers
Answer:
5 significant figures.
Explanation:
The decimal place makes the zeros significant.
true or false. for all atoms of the same element the 4s orbital is larger than the 3s orbital
Answers
Answer:
Between 4s and 3s orbital , 3s has more energy .
Explanation:
According to the rule , the lower the value of (n+l) for an orbital , the lower is it's energy . And if two orbitals have the same value of (n+l), the orbital with lower value of n will have the lower energy .
The statement " for all atoms of the same element the 4s orbital is larger than the 3s orbital" is definitely true.
What is an Element?An element may be defined as a type of substance that significantly cannot be dilapidated into simpler components by any non-nuclear chemical reaction. It is a type of chemical substance that bears unique properties based on numerous attributes.
The 4s orbital is the outermost and highest energy orbital, as compared to the 3s orbital. The 4s orbital penetrates more into the nucleus. This is because the s-orbital has the highest penetrating effect as compared to other orbitals.
The size of the 4s orbital is usually larger than the 3s orbital for all the atoms of the same element. This is because the electrons are filled in these orbitals systematically in the order s, p, d, and f. In the s-orbital first, 1s, 2s, 3s, 4s, and so on depending on the atomic number of the atom or element.
Therefore, the statement " for all atoms of the same element the 4s orbital is larger than the 3s orbital" is definitely true.
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