pleaseeee helpppppp asapppp

If you draw all the diagonals of a normal hexagon, there are 3*6=18 possible triangles; however, three of those are identical (the equilateral triangles), leaving us with 18-3=15 triangle possibilities.

In terms of geometry, a hexagon is a closed, six-sided polygon in two dimensions. A hexagon has six angles and six vertices. Hexa and gonio both denote the number six. A hexagon can be found in the shapes of a honeycomb, a football, a pencil face, and floor tiles. a standard hexagonal 2D geometric polygon with six equal-length sides and six equal-sized angles. All of the lines are closed, and there are no curving edges. A regular hexagon has 720 degrees of internal angles. Additionally, these shapes have six rotating and six reflective symmetries.

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Answer:

It's B in my opinion

Step-by-step explanation:

I just looked at the coordinates of the original triangle and the realized that the new triangle must be the same but with the x values opposite

Answer:

D. 15

Step-by-step explanation:

I assume you know what pascal's triangle is if this is the work you must complete. If not, I have attached it below.

Now, raising (a+b) to the 6th term would expand to this, based on Pascal's triangle

\(\left(a+b\right)^6 = \quad a^6+6a^5b+15a^4b^2+20a^3b^3+15a^2b^4+6ab^5+b^6\)

Remember that terms are separated by addition or subtraction symbols.

The 5th term of this 7 term expansion would be 15a^2b^4. The coeffecient is 15 in this case.

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Answer:

1 1/2

Step-by-step explanation:

From the question;

we are to state the three reasons why a function might be discontinuous at the point x=c

A funtion f(x) is discontinuous at a point x = c if

1.

2.

3.

If all this condition are statisfied, then the function is discontinuous at x = c

The linear function for this problem is defined as follows:

y = x + 50.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

In which:

The graph touches the y-axis at y = 50, hence the intercept b is given as follows:

b = 50.

When x increases by 10, y also increases by 10, hence the slope m is given as follows:

m = 10/10

m = 1.

Hence the function is given as follows:

y = x + 50.

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The mode of the given data set is 0%.

The mode of a set of data represents the value or values that appear most frequently.

In the given data set:

0%, 0%, 8.1%, 13.6%, 19.4%, 20.7%, 10.0%, 14.2%

We can observe that the value 0% appears twice,

and no other value appears more than once.

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The committee can best catalog the data so it can be used to make meaningful changes by using a database management system (DBMS).

A database management system (DBMS) is a system that enables users to create, read, update, and delete data in a database. The DBMS is a tool that handles all data-related tasks. Organizations employ a DBMS to keep data organized and easy to access and manage.

DBMS provides a set of computerized tools for managing all types of data. A DBMS allows end-users to extract and analyze data from a database.

The committee can use a database management system to ensure that data is organized and easily retrievable. They can employ a DBMS to streamline data entry and report production for high-quality output.

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Answer:

98

Step-by-step explanation:86+86=172

368-172=196

196/2=98

Answer:

18

Step-by-step explanation

10=12

must mean 5=6

12+6=18

15=18

18 dollars

he also has diabetes and drinks diet coke

Answer:

8

Step-by-step explanation:

Vanillas percentage is 26%

26% of 50 is 13

Chocolates percentage is 42%

42% of 50 is 21

21-13=8

Using proportions, it is found that 8 more of Ursula’s classmates chose chocolate than chose vanilla.

In total, there are 50 students.

\(0.42(50) = 21\)

That is, 21 choose chocolate.

The sum is 100%, hence the percentage that choose vanilla is:

\(x + 14 + 18 + 42 = 100\)

\(x = 100 - 74\)

\(x = 26\)

26%, out of 50, hence:

\(0.26(50) = 13\)

13 choose vanilla.

21 - 13 = 8.

8 more of Ursula’s classmates chose chocolate than chose vanilla.

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Answer:

The answer is C because I dont know

Answer:

Lynn is correct because 5/2 is greater than 1.

Quota sampling is a method used in research to ensure that a sample represents the target population accurately and is free from bias. In quota sampling, researchers determine in advance how many individuals from certain groups or characteristics they need to include in the survey.

The main goal of quota sampling is to ensure that every person in the target population has an equal chance of being selected for the sample. This is achieved by selecting individuals based on specific characteristics or demographics that are representative of the population being studied.

For example, let's say a researcher wants to conduct a survey about favorite ice cream flavors among teenagers. They may decide that they need an equal number of male and female participants and an equal representation from different age groups within the teenage population. The researcher would then set quotas for each of these groups and select participants accordingly.

It's important to note that quota sampling does not involve pre-planning or random selection. Instead, researchers use their judgment to select individuals who meet the predetermined quotas as they encounter them in the target population.

By using quota sampling, researchers can ensure that their sample is diverse and representative of the population they are studying. This method helps reduce bias and provides a more accurate understanding of the target population's opinions or behaviors.

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The first-order optimality condition for convex optimization problems can be applied to characterize the optimal point, x* in the given optimization problem.

The first-order optimality condition states that if x* is an optimal point for the given convex optimization problem, then there exists a vector v* such that:

∇f(x*) + v* = 0

Here, ∇f(x*) is the gradient of the objective function f(x) evaluated at x*, and v* is the Lagrange multiplier associated with the constraint x ∈ C.

In the given optimization problem, the objective function is ∥a−x∥², and the constraint set is C.

To apply the first-order optimality condition, we need to find the gradient of the objective function. The gradient of ∥a−x∥² is given by:

∇f(x) = 2(x - a)

Now, let's apply the first-order optimality condition to the given problem:

∇f(x*) + v* = 0

Substituting the gradient expression:

2(x* - a) + v* = 0

Rearranging the equation:

x* = a - (v*/2)

This equation provides a characterization of the optimal point x* in terms of the Lagrange multiplier v*. By solving the equation, we can find the optimal point x*.

It's important to note that the Lagrange multiplier v* depends on the constraint set C. The specific form of v* will vary depending on the nature of the constraint set. In some cases, it may be necessary to further analyze the specific properties of the constraint set C to fully characterize the optimal point x*.

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According to the question, The annual rate of interest is 5% for the first 5 years and 7% for the last 11 years. the present value of the annuity at time 0 is approximately $802.34.

To calculate the present value (PV) of the annuity, we need to determine the present value of each individual cash flow and sum them up.

For the first 5 years, the effective annual interest rate is 5%. Using the formula for the present value of an annuity:

\(\[ PV = PMT \times \frac{{(1 - (1 + r)^{-n})}}{{r}} \]\)

where PV is the present value, PMT is the annual deposit, r is the interest rate per period, and n is the number of periods.

Plugging in the values:

\(\[ PMT = \$50, \quad r = 5\% = 0.05, \quad n = 5 \text{ years} \]\)

we can calculate:

\(\[ PV_1 = 50 \times \frac{{(1 - (1 + 0.05)^{-5})}}{{0.05}} \]\)

For the next 11 years, the effective annual interest rate is 7%. Using the same formula:

\(\[ PMT = \$50, \quad r = 7\% = 0.07, \quad n = 11 \text{ years} \]\)

we can calculate:

\(\[ PV_2 = 50 \times \frac{{(1 - (1 + 0.07)^{-11})}}{{0.07}} \]\)

To find the total present value, we sum \(\(PV_1\) and \(PV_2\)\):

\(\[ PV = PV_1 + PV_2 \]\)

Calculating the values:

\(\[ PV_1 \approx 50 \times \frac{{(1 - 0.78353)}}{{0.05}} \approx \$432.94 \]\)

\(\[ PV_2 \approx 50 \times \frac{{(1 - 0.51316)}}{{0.07}} \approx \$369.40 \]\)

\(\[ PV \approx 432.94 + 369.40 \approx \$802.34 \]\)

Therefore, the present value of the annuity at time 0 is approximately $802.34."

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The measurement of the angle OP is 39

The given parameters that will help us to answer the question are

R is mid point of OQ

S is mid point of PQ

RS = 3x + 38

OP = 4x- 14

R is mid point of OQ and S is mid point of PQ;

By using mid point theorem

[1/2][OP] = RS

This implies that So,

[1/2][3x + 38] = [4x- 14]

[3x+38] = 2[4x- 14]

Opening the brackets we have

3x+38=8x-28

Collecting like terms

3x-8x=-28-38

-5x=-66

Making x the subject of the relation we have

x = -66 / -5

x = 13.2

Therefore RS = 3(13.2) + 38 = -11.4

OP = 4(13.2)- 14=38.8

Measurement of OP = 39 approximately

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Answer:

28

Step-by-step explanation:

Since B is the midpoint of AC, that means AB = BC. That means 3x+4 = 5x-6. We can now set up an equation to solve for x:

3x+4 = 5x-6

3x+10 = 5x

10 = 2x

x = 5

Now that we know what x is, we can just plug x into the expression of AB and multiply it by 2:

(3*(5)+4)*2

=(15+4)*2

=19*2

=28

(side note: we could have plugged x into the expression of BC as well, but in this case plugging it into AB tends to be easier to solve)

Therefore, the length of AC is 28.

Answer:

13.8 oz

14.15 oz

14.2 oz

Step-by-step explanation:

trust me

Answer:

B, C, D

Step-by-step explanation:

Answer:

100

Step-by-step explanation:

160 * (5/8) = 100

Answer: Yes, it does.

Step-by-step explanation: Let x represent the price of gas today. 200% of x=200/100*x, which can be written as 2x because 200/100=2. 2x is x doubled, and therefore, it does mean the price has doubled.

Answer:

yes, the price has doubled

The probability of making the wrong decision is approximately 0.0082.

According to the central limit theorem, the distribution of the sample mean of a large number of independent and identically distributed random variables approaches a normal distribution. In this case, the random variable is the number of odd outcomes in 100 rounds of the roulette.

As each outcome has an equal probability of being odd, the distribution of the number of odd outcomes is binomial with parameters n=100 and p=1/2.

Using the mean and variance of a binomial distribution, we have:

mean = np = 100 x 1/2 = 50

variance = np(1-p) = 100 x 1/2 x (1 - 1/2) = 25

The standard deviation of the distribution is the square root of the variance, which is 5. Therefore, the z-score for a count of 55 is:

z = (55 - 50) / 5 = 1

Using a standard normal distribution table or calculator, we find that the probability of a z-score greater than 1 (i.e., a count of 55 or more) is approximately 0.1587. However, we are interested in the probability of making the wrong decision, which is the probability of a count of 55 or more given that the roulette is fair.

This probability is equal to the significance level of the test, which is the probability of rejecting the null hypothesis (fair roulette) when it is actually true.

Assuming a significance level of 0.05, the probability of making a Type I error (rejecting a true null hypothesis) is 0.05. Therefore, the probability of making the wrong decision is approximately 0.05 x 0.1587 = 0.0082.

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Thread left on the spool in meters is 6.3152 meter (Approx.)

Given that;

Total spool = 8 yards

Allison used = 1 meter of spool

Find:

Thread left on the spool in meters

Computation:

Total spool = 8 yards

Total spool in meter = 8 × 0.9144

Total spool in meter = 7.3152 meter (Approx.)

Thread left on the spool in meters = Total spool in meter - Allison used

Thread left on the spool in meters = 7.3152 - 1

Thread left on the spool in meters = 6.3152 meter (Approx.)

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The first scenario described is an example of a retrospective cohort study.  The second scenario suggests a retrospective cohort study as well. The third scenario represents a cross-sectional study, where researchers conduct a survey among high school students to assess the prevalence of obesity and diabetes.

1. In the first scenario, a retrospective cohort study is conducted by tracking individuals over a 20-year period. The study begins in 1960 and collects data on cigar smoking practices. After 20 years, the participants are followed up to determine if they developed any cancers. This type of study design allows researchers to examine the long-term effects of smoking Cuban cigars.

2. The second scenario involves a retrospective cohort study as well. The objective is to study the long-term neurological effects of a discontinued anesthetic agent. The researchers identify patients who received the drug before it was discontinued and then assess the occurrence of subsequent neurological disorders. This study design allows for the examination of the relationship between exposure to the anesthetic agent and the development of neurological disorders.

3. The third scenario represents a cross-sectional study. Researchers aim to assess the prevalence of obesity and diabetes among high school students during their junior year. They conduct a survey to gather information on the students' current weight, diabetes status, and other relevant factors. A cross-sectional study provides a snapshot of the population at a specific point in time, allowing researchers to examine the prevalence of certain conditions or characteristics.

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Answer:

Answer is 6.

Step-by-step explanation:

1--1/2 ÷ 1/4 = 6

Answer: Your answer is A they gained 2 yards.

For the first question: The obtained Chi-square value of 23.45 is greater than the critical Chi-square value of 9.488. In a Chi-square test, when the obtained Chi-square value exceeds the critical Chi-square value, we reject the null hypothesis. Therefore, the correct conclusion is:

a. Reject the null hypothesis, church attendance and marital status are dependent.

This means that there is a statistically significant relationship between marital status and church attendance based on the data analyzed.

For the second question:

The obtained Chi-square value of 12.2 is greater than the critical Chi-square value of 9.488. Following the same reasoning as above, we reject the null hypothesis. Therefore, the correct conclusion is:

c. The variables are dependent.

This indicates that there is a statistically significant relationship between arrests and the socioeconomic class of the offender based on the data analyzed.

Option d. "the probability of getting these results by random chance alone is 0.5" is not a valid conclusion to draw from the Chi-square test. The Chi-square test does not provide information about the probability of obtaining the results by random chance alone.

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Answer: 40 seconds per worksheet

Step-by-step explanation:

From the information given in the question, we are informed that Robert took 8 minutes to complete his 12 worksheets.

Based on this, his unit rate of completing worksheets will be given as:

= 8 minutes / 12

= 480 seconds / 12

= 40 seconds per worksheet

Note 1 minute = 60 seconds

8 minutes = 8 × 60 = 480 seconds