A 90% confidence interval for a sample proportion (p-hat) of 0.45 and sample size (n) of 560 can be calculated using the formula CI = 0.45 ± 1.645 * sqrt((0.45 * (1 - 0.45)) / 560). This interval provides the population proportion estimate with 90% confidence.
In this case, the sample size (n) is 560 and the sample proportion (p-hat) is 0.45. We want to calculate a confidence interval with a confidence level of 90%.
First, we need to determine the critical value (z-score) corresponding to the desired confidence level. For a 90% confidence level, the critical value is approximately 1.645.
Next, we substitute the values into the formula:
CI = 0.45 ± 1.645 * sqrt((0.45 * (1 - 0.45)) / 560)
By evaluating this expression, we can calculate the lower and upper bounds of the confidence interval.
Therefore, the 90% confidence interval for the population proportion is [lower bound, upper bound].
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Two angles are complementary. The measure of
one angle is 125% of the other. Find the
measures of both angles.
Answer:
2
Step-by-step explanation:
Mike constructed a kite by attaching two congruent triangles as shown in the diagram below.
Which equation can Mike use to determine the amount of material, in square inches, needed to create the kite?
F. A=[12(12)(8)]⋅2
G.A=[12(6)(8)]⋅2
H.A=[(12)(4)]⋅2
J.A=[(6)(10)]⋅2
The amount of material, in square inches, needed to create the kite is A = [1/2(6)(8)].2. Option G is the correct answer.
What is area of an isosceles triangle?Either of a triangle's two sides that are equal in length is said to be isosceles. This characteristic equates to the triangle's two angles being equal. Two of the sides and two of the angles of an isosceles triangle are equal. An isosceles triangle has three sides that are all the same length, have the same angles, and meet at symmetrical corners. Two right-angle triangles are produced if a perpendicular line is traced from the junction of two equal sides to the base of the unequal side.
The area of the triangle is given as:
A = 1/2(b)(h)
Here, the base = 6 and height = 8 in.
Thus, the area of the triangle is:
A = 1/2(6)(8)
The figure consists of 2 similar triangles. So, the area of the second triangle is added to get the final area.
A = [1/2(6)(8)].2
Hence, the amount of material, in square inches, needed to create the kite is A = [1/2(6)(8)].2. Option G is the correct answer.
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Can someone please explain this step by step.
Answer:
-5 and 2
-3 and 0
-2 and -1
...gives -3
Step-by-step explanation:
Answer:
Step-by-step explanation:
(-5,2), (-2,-1), (-3,0)
all pairs add up to -3
The rate at which people enter an amusement park on a given day is modeled by the function E defined by. E(t) = 15600/(12 - 241 +160).
The rate at which people enter the amusement park on that day is -226.08 people per unit time
How we do the Calculation of E(t)?The formula given is E(t) = 15600/(12 - 241 +160).
Simplifying the expression inside the parentheses, we get:
\(E(t) = 15600/(12 - 241 +160) = 15600/(-69)= -226.08\)
The given function E(t) represents the rate at which people enter an amusement park on a given day. Here, we are asked to find the value of E(t) for a given day, where the value of the expression inside the parentheses is 12 - 241 + 160.
By simplifying the expression inside the parentheses, we get -69. Substituting this value in the formula for E(t), we get -226.08 as the value of E(t) for that day.
the value of E(t) is negative, this means that the number of people leaving the park is higher than the number of people entering the park on that day.
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Please hellp this is do today I will give brainlyest
Answer:
Step-by-step explanation:
Answer is B.
Function 1: slope is 2
Function 2: (-5 + 4)/(2-1)= -1/1= -1
The 4th term in an arithmetic sequence is 18 and 9th term is 43. Find the first 5 terms of the sequence
Answer:
3, 8, 13, 18, 23
Step-by-step explanation:
The nth term of an arithmetic sequence is
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₄ = 18 and a₉ = 43 , then
a₁ + 3d = 18 → (1)
a₁ + 8d = 43 → (2)
Subtract (1) from (2) term by term, eliminating a₁
5d = 25 ( divide both sides by 5 )
d = 5
Substitute d = 5 into (1) for value of a₁
a₁ + 3(5) = 18
a₁ + 15 = 18 ( subtract 15 from both sides )
a₁ = 3 , then
a₂ = a₁ + 5 = 3 + 5 = 8
a₃ = a₂ + 5 = 8 + 5 = 13
a₄ = a₃ + 5 = 13 + 5 = 18
a₅ = a₄ + 5 = 18 + 5 = 23
The first 5 terms are 3, 8, 13, 18, 23
Suppose you are an engineer trying to recreate an experiment involving a weight on the end of a spring. This simulation will give you an idea of what the experiment will look like. For more information, you can visit this simple harmonic motion website. You are given the equation y(t)=2 sin 4 pi t + 5 cos 4pi t, which models the position of the weight, with respect to time. You need to find the amplitude of the oscillation, the angular frequency, and the initial conditions of the motion. You will also be required to find the time(s) at which the weight is at a particular position. To find this information, you need to convert the equation to the first form, y(t) = A sin (wt+0).
The canonical expression equivalent to sinusoidal model y(t) = 2 · sin (4π · t) + 5 · cos (4π · t) is y(t) = (√ 29) · sin (4π · t + 0.379π) .
How to find the canonical form of the equation for simple harmonic motion
Herein we have a simple harmonic motion model represented by a sinusoidal expression of the form y(t) = A · sin (C · t) + B · cos (C · t), which must be transformed into its canonical form, that is, y(t) = A' · sin (C · t + D). We proceed to perform the procedure by algebraic and trigonometric handling.
The amplitude of the canonical function is determined by the Pythagorean theorem:
A' = √(2² + 5²)
A' = √ 29
The angular frequency C is the constant within the trigonometric functions from the non-canonical formula:
C = 4π
Then, we find the initial position of the weight in time: (t = 0)
y(0) = 2 · sin (4π · 0) + 5 · cos (4π · 0)
y(0) = 5
And now we calculate the angular phase below: (A' = √ 29, C = 4π, y = 5)
5 = √ 29 · sin (4π · 0 + D)
5 / √ 29 = sin D
D ≈ 0.379π rad
The canonical expression equivalent to sinusoidal model y(t) = 2 · sin (4π · t) + 5 · cos (4π · t) is y(t) = (√ 29) · sin (4π · t + 0.379π) .
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How many different values of ml are possible when the principal quantum number is n = 4? A. 7 B. 9 C. 11 D. 14 E. 17
The magnetic quantum number (ml) represents the possible orientations of the orbital angular momentum of an electron in an atom. It can take integer values ranging from -l to +l, where l is the azimuthal quantum number.
The azimuthal quantum number (l) is related to the principal quantum number (n) by the inequality 0 ≤ l ≤ n-1. Therefore, for n = 4, the possible values of l are 0, 1, 2, and 3
For each value of l, the magnetic quantum number ml can take 2l + 1 different values. Therefore, the number of different values of ml for a given l is 2l + 1.
To determine the total number of different values of ml when n = 4, we calculate the sum of 2l + 1 for l = 0 to 3
(2(0) + 1) + (2(1) + 1) + (2(2) + 1) + (2(3) + 1)
= 1 + 3 + 5 + 7
= 16
So, when the principal quantum number is n = 4, there are 16 different values of ml possible.
None of the provided answer choices (A, B, C, D, E) matches the correct answer of 16.
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In how many ways can one write the numbers , , , , , and in a row so that given any number in the row, all of its divisors (not including itself) appear to its left
There are 6 ways to arrange the numbers 1, 2, 3, 4, 5, and 6 in a row such that all divisors of a number appear to its left.
To solve this problem, let's consider each number individually and determine its divisors.
Number 1 has no divisors, so it can be placed anywhere in the row.
Number 2 has only one divisor, which is 1. So, it can be placed to the right of 1.
Number 3 has two divisors, 1 and 2. Since 1 is already to the left of 3 and 2 is to the left of 1, 3 can only be placed to the right of 2.
Number 4 has three divisors, 1, 2, and 3. Since 1 is already to the left of 4 and 2 and 3 are to the left of 1, 4 can only be placed to the right of 3.
Number 5 has two divisors, 1 and 2. Similar to number 3, it can only be placed to the right of 2.
Number 6 has four divisors, 1, 2, 3, and 4. Since 1 is already to the left of 6, 2 and 3 are to the left of 1, and 4 is to the left of 2, 6 can only be placed to the right of 4.
Hence, the possible arrangements are:
1, 2, 3, 4, 5, 6
1, 2, 3, 5, 4, 6
1, 2, 5, 3, 4, 6
1, 5, 2, 3, 4, 6
5, 1, 2, 3, 4, 6
5, 1, 2, 4, 3, 6
There are a total of 6 ways to arrange the numbers 1, 2, 3, 4, 5, and 6 in a row such that all divisors of a number appear to its left. These arrangements are 1, 2, 3, 4, 5, 6; 1, 2, 3, 5, 4, 6; 1, 2, 5, 3, 4, 6; 1, 5, 2, 3, 4, 6; 5, 1, 2, 3, 4, 6; and 5, 1, 2, 4, 3, 6.
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Which of the following gives the value of
the expression below written in scientific
notation?
(9.1 x 10-3) + (5.8 x 10-2)
A. 1.49 x 10-4
B.
6.71 x 10-²
C. 9.68 x 10-3
D.
14.9 x 10-5
VD 4TO6
02
The Correct Option is C that 71 x 10-² of the following gives the value of the expression below written in scientific notation.
Why does scientific notation employ the number 10?The basic objective of scientific notation is to make computations with unusually big or small numbers simpler. The following examples demonstrate how all of the digits in a number in scientific notation are relevant because zeros are no longer utilised to set the decimal point.
What does math scientific notation mean?The statement for a number n in scientific notation is of the type a10b, where an is an integer such that 1|a|10. B is also an integer. Multiplication: To get the full amount in scientific notation, multiply the decimal values. Add the 10 power exponents after that.
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evaluate the expression 6x + 4 9/10 when x = 2/3.
x=2/3
6(2/3) + 4 9/10 =4 + 4 9/10 = 8 9/10
Answer:
2x-1=y,2y+3=x
Step-by-step explanation:
no explanation
d. Based on the December 31, Year 2, balance sheet, what is the largest cash dividend Dakota could pay
Based on the Year 2 balance sheet, the largest cash dividend that Dakota could pay is $16,500.
What is the largest cash dividend Dakota could pay?Cash dividends refers to the payments that companies make to their shareholders which is usually on the strength of earnings. They often represent opportunity for companies to share the benefit of business profits.
Based on the balance sheet, the largest cash dividend that Dakota could pay in Year 2 is:
= $ 31,500 + $ 5,000 - $ 20,000
= $ 16,500.
Missing questions:Dakota Company experienced the following events during Year 2:
Acquired $20,000 cash from the issue of common stock.
Paid $20,000 cash to purchase land.
Borrowed $2,500 cash.
Provided services for $40,000 cash.
Paid $1,000 cash for utilities expense.
Paid $20,000 cash for other operating expenses.
Paid a $5,000 cash dividend to the stockholders.
Determined that the market value of the land purchased in Event 2 is now $25,000.
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Which one is the linear function of x.
I know it is not A or C
Answer: d
Step-by-step explanation:
Find The Critical Points Of The Function F(X,Y)=X2+Y2−6x−8y. B) Using The Lagrange Multipliers Method Find
The critical points of the function f(x, y) = x^2 + y^2 - 6x - 8y are (3, 4).
To find the critical points of the function f(x, y) = x^2 + y^2 - 6x - 8y, we need to find the points where the gradient of the function is equal to zero.
Step 1: Find the partial derivatives of f(x, y) with respect to x and y:
∂f/∂x = 2x - 6
∂f/∂y = 2y - 8
Step 2: Set the partial derivatives equal to zero and solve for x and y:
2x - 6 = 0
2y - 8 = 0
Solving these equations, we find:
x = 3
y = 4
Therefore, the critical point of the function f(x, y) is (3, 4).
Now, using the Lagrange multipliers method, we can find the constrained critical points.
Let's say we have a constraint g(x, y) = k, where k is a constant. In this case, we don't have a specific constraint given, so we can skip this step.
Step 1: Set up the Lagrangian function L(x, y, λ) = f(x, y) - λ(g(x, y) - k). Since we don't have a constraint, we can set L(x, y, λ) = f(x, y).
L(x, y) = x^2 + y^2 - 6x - 8y
Step 2: Find the partial derivatives of L(x, y) with respect to x, y, and λ:
∂L/∂x = 2x - 6
∂L/∂y = 2y - 8
Step 3: Set the partial derivatives equal to zero and solve for x, y, and λ:
2x - 6 = 0
2y - 8 = 0
Solving these equations, we get:
x = 3
y = 4
Therefore, the critical point of the function f(x, y) using the Lagrange multipliers method is also (3, 4).
In summary, the critical points of the function f(x, y) = x^2 + y^2 - 6x - 8y are (3, 4).
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Suppose that you are headed toward a plateau 40 m high. If the angle of elevation to the top of the plateau is 20 degrees, how far are you from the base of the plateau?
We are approximately 17.88 meters from the base of the plateau.
What is an angle of elevation?An angle of elevation is the angle formed between a horizontal line and a line of sight that is directed upward to an object or point above the horizontal level. It is commonly used in trigonometry and geometry to determine the height or distance of an object, such as a building, tower, or mountain.
We can use trigonometry to solve this problem. Let's call the distance we are from the base of the plateau "x".
From the problem, we know that the height of the plateau (the opposite side) is 40m and the angle of elevation (the angle between the horizontal and the line of sight to the top of the plateau) is 20 degrees.
Using the tan function, we get,
tan(20) = 40/x
To solve for x, we can cross-multiply:
x * tan(20) = 40
Then, we can divide both sides by tan(20):
x = 40 / tan(20)
Using a calculator, we get:
x ≈ 17.8798 meters
Therefore, we are approximately 17.88 meters from the base of the plateau.
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1. five friends go to the movie theater together. (a) if there are 5 seats open in a row, how many ways can the friends choose seats? (b) if there are 7 seats open in a row, how many ways can the friends choose seats? (note that two seats will remain empty.) (c) repeat part (b), but where two of the friends are required to sit next to each other. (d) repeat part (b), but where two of the friends are required to not sit next to each other.
he number of ways the friends can choose seats without sitting next to each other is 7! - 4! = 5040
If there are 5 seats open in a row and no restrictions on the seating arrangement, each friend can choose one seat independently. Therefore, the total number of ways the friends can choose seats is 5 factorial (5!) which is equal to 5 × 4 × 3 × 2 × 1 = 120.
(b) If there are 7 seats open in a row and no restrictions on the seating arrangement, each friend can choose one seat independently. Therefore, the total number of ways the friends can choose seats is 7 factorial (7!) which is equal to 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.
(c) If two friends are required to sit next to each other, we can treat them as a single entity. This reduces the problem to arranging four entities (three individual friends and one pair of friends) and three empty seats. The total number of ways the friends can choose seats is then 4 factorial (4!) which is equal to 4 × 3 × 2 × 1 = 24.
(d) If two friends are required to not sit next to each other, we can count the complement of the situation in part (c). There are 7 factorial (7!) total seating arrangements without any restrictions. From part (c), we found that there are 4 factorial (4!) seating arrangements where the two friends sit next to each other. - 24 = 5016.
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what two numbers multiply to 10 and add up to 11
Answer:
1 and 10
Step-by-step explanation:
Answer:
1 and 10
Step-by-step explanation:
1×10=10
1+10=11
NEED HELP ASAP!! GIVING 50-100 BRAINLEST POINTS!! (6th Grade Math)
1/2 w + 2 =
Answer:
it cannot be simplified any further
Step-by-step explanation:
we need to know the value of w , if you dont know that value then the answer would just be 1/2w +2 because you can add 1w+2w but not 1w+2 because they have different values
A sample of 4 different calculators is randomly selected from a group containing 13 that are defective and 39 that have no defects. What is the probability that at least one of the calculators is defective? Show your answer in decimal format to three places (0.000).
The probability that at least one of the calculators is defective is approximately 0.522.
First, we need to find the probability that none of the calculators are defective.
The probability that the first calculator selected is not defective is 39/52. The probability that the second calculator selected is also not defective is 38/51. The probability that the third calculator selected is not defective is 37/50. And finally, the probability that the fourth calculator selected is also not defective is 36/49.
So, the probability that all four calculators are not defective is:
(39/52) * (38/51) * (37/50) * (36/49) ≈ 0.478
Therefore, the probability that at least one of the calculators is defective is:
1 - 0.478 ≈ 0.522
So, the probability that at least one of the calculators is defective is approximately 0.522.
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MALM Dion has two bunches of similar bananas. One bunch has 8 bananas, and the other bunch has 9 bananas. The list below shows the weight, in grams, of each of the bananas in the bunch of 8. 138 118 121 164 140 115 129 123 Which measurement is most likely closest to the total weight of the bunch of 9 bananas? ( 932 grams 1,048 grams
A932grams
B 1,048
C 1,179
D 1,368
i need an answer asap
The answer is C, 1179 grams. To calculate the total weight of the bunch of 9 bananas, we need to find the average weight of the bunch of 8 bananas.
What is average weight?It is calculated by taking the sum of all the weights during the period, then dividing it by the number of weights recorded.
To calculate the total weight of the bunch of 9 bananas, we need to find the average weight of the bunch of 8 bananas.
To do this, we add the weights of each banana in the bunch
(138 + 118 + 121 + 164 + 140 + 115 + 129 + 123 = 1048)
and divide by the total number of bananas (8).
This gives us the average weight of the bunch of 8 bananas, 131 grams. Adding 131 grams to the weight of the 9th banana gives us
= 131+1048
= 1179
Total weight of 1179 grams, which is the closest to the given choices.
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Which of these will not help you achieve a goal?
help please
Answer:
Hello! Mizuki here to help. The correct option you choose should be the second one(hoping you meet it)
Just hoping and not trying to achieve the goal won't help. The others are important step(s) to achieve a goal.
Step-by-step explanation:
3x2+(2y+z3) if x=4, y=5, and z=3
Answer:
43 or 25
Step-by-step explanation:
Plug all of the numbers into the equation.
(i'm not sure if the 3x2 is a letter or not, so i'll just solve it anyways for both.)
3(4)(2) + (2(5) +(3)(3) = 43
If it's not a letter then
3x2 + (2(5)+3(3)) = 25
In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
Option c) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B
According to the information given in the question,
A true proportion of 0.325 represents that the two simulations will be conducted for sampling proportions from a population
Simulation A -
Sample size - 100
Trials - 1500
Simulation B -
Sample size - 50
Trials - 2000
Now due to the relation of simulation A and simulation B, they are closely equal-
The total sample size of simulation A= 1500 x 100
= 150000
The total sample size of simulation B = 2000 x 50
= 100000
From the above calculations of simulations A and B, we can see that while comparing the,
Sample Size = Simulation A > Simulation B
Variability = Simulation B < Simulation B
Therefore, option c) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B is correct.
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In a recent survey, the proportion of adults who indicated mystery as their favorite type of book was 0.325. Two simulations will be conducted for the sampling distribution of a sample proportion from a population with a true proportion of 0.325. Simulation A will consist of 1,500 trials with a sample size of 100. Simulation B will consist of 2,000 trials with a sample size of 50. Which of the following describes the center and variability of simulation A and simulation B?
A) The centers will roughly be equal, and the variabilities will roughly be equal.
B) The centers will roughly be equal, and the variability of simulation A will be greater than the variability of simulation B.
C) The centers will roughly be equal, and the variability of simulation A will be less than the variability of simulation B.
D) The center of simulation A will be greater than the center of simulation B, and the variability of simulation A will roughly be equal to the variability of simulation B.
E) The center of simulation A will be less than the center of simulation B, and the variability of simulation A will be greater than the variability of simulation B.
g identify the straight-line solutions. b) write the general solution. c) describe the behavior of solutions, including classifying the equilibrium point at (0, 0).
1. The straight-line solutions are of the form y = kx + c, where k and c are constants.
2. The general solution is f(x) = kx + c, where k and c can be any real numbers.
3. The behavior of solutions depends on the value of k: if k > 0, the solutions increase as x increases; if k < 0, the solutions decrease as x increases; and if k = 0, the solutions are horizontal lines. The equilibrium point at (0, 0) is classified as a stable equilibrium point.
a) To identify the straight-line solutions, we need to find the points on the graph where the slope is constant. This means the derivative of the function with respect to x is a constant. Let's assume our function is f(x).
So, we have f'(x) = k, where k is a constant.
By integrating both sides, we get f(x) = kx + c, where c is an arbitrary constant.
Therefore, the straight-line solutions are of the form y = kx + c, where k and c are constants.
b) The general solution can be written as f(x) = kx + c, where k and c can be any real numbers.
c) The behavior of solutions depends on the value of k.
- If k > 0, the solutions will be increasing lines as x increases.
- If k < 0, the solutions will be decreasing lines as x increases.
- If k = 0, the solutions will be horizontal lines.
The equilibrium point at (0, 0) is classified as a stable equilibrium point because any small disturbance will bring the system back to the equilibrium point.
In summary, the straight-line solutions are of the form y = kx + c, where k and c are constants. The behavior of solutions depends on the value of k, and the equilibrium point at (0, 0) is a stable equilibrium point.
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How on earth do u do this?
Answer:
ΔABC ≅ ΔZXN
Step-by-step explanation:
Find the letters of the matching parts of the triangles.
A is the right angle; as is Z.
B is the angle where 10 meets 26; as is X.
C is the remaining angle; as is N.
__
Corresponding vertices are listed in the same order:
ΔABC ≅ ΔZXN
any one know the mixed number for this question?
4 1/4 - 5/6
Answer:
4 5/12
Step-by-step explanation:
Find the LCM of 6 and 4
This would be 12.
Multiply so that both denominators are 12.
For \(5\frac{1}{4}\) multiply both the numerator and denominator by 3.
\(5\frac{3}{12}\)
For \(\frac{5}{6}\) multiply both the numerator and denominator by 2.
\(\frac{10}{12}\)
Substitute the new values into the expression.
\(5\frac{3}{12} - \frac{10}{12}\)
Solve
\(5\frac{3}{12} - \frac{10}{12} \\\\4\frac{15}{12} - \frac{10}{12} \\\\=4\frac{5}{12}\)
please help me on this will give you brainliest
Answer:
31/10, 3 1/9, 3.115, 3.45 in that order.
Step-by-step explanation:
T/F: at each iteration of the algorithm, the correct position in the sorted section is found for the next element in the unsorted section.
True.
In an algorithm like insertion sort, at each iteration, the algorithm finds the correct position in the sorted section for the next element in the unsorted section.
The algorithm iterates through the unsorted section, compares each element with the elements in the sorted section, and inserts the element in the correct position to maintain the sorted order.
This process continues until all elements in the unsorted section are inserted into their correct positions, resulting in a fully sorted array.
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through (-5.-2) with a slope = 4/5
please help this is due at 12:20
Answer:
B
Step-by-step explanation: