Answers
1. The volume of the gas is 40.6 mL
2. This is synthesis reaction
3. The reaction is 3H2 + N2 ---> 2NH3 and the number of moles are balanced.
4. The total mass of the reactants is equal to the total mass of teh products
5. We would have 0.12 moles of ammonia
What is gas laws?The general gas law shows us the relationship between the temperature, pressure and volume of a gas all at once.
Using the general gas equation;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 45 * 97.5 * 273/101.3 * 291
= 40.6 mL
Using the ideal gas law;
PV = nRT
n = PV/RT
n = 1.2 * 4/0.082 * 323
n = 0.18 moles
If 3 moles of hydrogen produce 2 moles of ammonia
0.18 moles of hydrogen produces 0.18 * 2/3
= 0.12 moles of ammonia
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Related Questions
Identify the following examples as either physical or chemical change.
(Ill give brainliest if right)
Answers
Answer:
7. Chemical
8. Chemical
9. Physical
10. Physical
11. Physical
12. Physical
Explanation:
answer for the rate please help me with my chemistry homework thank you so much
Answers
Answer:
Rate cup 1: 36.00 tsp/h.
Rate cup 2: 59.50 tsp/h.
Rate cup 3: 70.13 tsp/h.
Explanation:
Based on the given example, the units must be in tsp/hour. To do this we just have to divide tsp by seconds and then convert it to hours remembering that 1 hour equals 3600 seconds.
Let's calculate each case:
- Cup 1: 1 tsp, 1 minute 40 seconds. Remember that 1 minute equals 60 seconds, so 1 minute and 40 seconds equals 100 seconds. The calculation of the rate will look like this:
\(\frac{1\text{ tsp}}{100\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=36.00\frac{tsp}{h}.\)The rate of cup 1 is 36.00 tsp/h.
- Cup 2: 2 tsp, 2 minutes 1 second. As we saw before 1 minute equals 60 seconds, so 2 minutes equals 120 seconds. 2 minutes and 1 second equals 121 seconds. The rate of cup 2 will be calculated as:
\(\frac{2\text{ tsp}}{121\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=59.50\frac{tsp}{h}.\)The rate of cup 2 is 59.50 tsp/h.
- Cup 3: 3 tsp, 2 minutes 34 seconds. 2 minutes are the same that 120 seconds, so 2 minutes 34 seconds equals 154 seconds. The rate of cup 3 is calculated as follows:
\(\frac{3\text{ tsp}}{154\text{ s}}\cdot\frac{3600\text{ s}}{1\text{ h}}=70.13\frac{tsp}{h}.\)The rate of cup 3 is 70.13 tsp/h.
When the volume of a gas is
changed from m3 to 15.5 m3
the temperature will change from
159 K to 456 K.
Assume that the number of moles and the
pressure remain constant.
Answers
Charles law states that there is a directly proportional relationship between the volume and the temperature of the gas at certain pressure.
Therefore,
V1/T1 = V2/T2
V1 is unknown
T1 = 159K
V2 = 15.5m3
T2 = 456K
V1/159 = 15.5/456
V1 = (15.5*159)/456 = 5.404m3.
When the volume of a gas is changed from 5.404 m3 to 15.5 m3 the temperature will change from 159 K to 456 K.
is riding a bike or bus quicker way to get to school?
IV:_____________
DV:____________
Hypothesis:________________________________________________
Answers
things that happened to the organisms I tracked: (example: was eaten by other organisms)
Answers
Reproduced, transferred their genes to progeny, died from natural causes, fell ill or contracted a disease, became prey for a predator or were devoured by a scavenger, or moved to a new area.
What kind of non-living entity might be present in an ecosystem?Non-living things include items like rocks, water, the atmosphere, the climate, and natural occurrences like earthquakes and rockfalls. One of the qualities that characterises living beings is their capacity for reproduction.
What are five non-living examples?Its definition includes glass, the sun, water, sand, and rock as non-living objects. They show absolutely no signs of life. Some people define a non-living object as anything that once belonged to a live entity.
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can anyone tell me "what are the exceptions of law of reciprocal proportions??"
Answers
Two materials A and B are heated separately in air. The product formed is dissolved in water. How will you identify which one is metal?
Answers
what is the difference between biology and anatomy?
Answers
Answer:
Biology is the study of nature, like plants and animals, while anatomy is the study of the human body, like our bones and muscles.
Explanation:
Hope it helped!
How many grams of sodium are in
1.000 mole of sodium?
Answers
Answer:
Explanation:
How many atoms are in a 3.5 g sample of sodium (Na)? In this example, multiply the grams of Na by the conversion factor 1 mol Na/ 22.98 g Na, with 22.98g being the molar mass of one mole of Na, which then allows cancelation of grams, leaving moles of Na.
Answer:
ONE MOLE of any element has 6.023x1023 atoms of that element. Therefore 1 mole or 22.99 grams of Na = 6.023x1023 atoms of Na.
Explanation:
what is the advantage of highly diverse ecosystem
Answers
Answer:
Biodiversity boosts ecosystem productivity where each species, no matter how small, all have an important role to play. For example, A larger number of plant species means a greater variety of crops. Greater species diversity ensures natural sustainability for all life forms
Explanation:
electrons tend to occupy the ___________available energy level.
Answers
Electrons tend to occupy the lowest available energy level.
This is in accordance with the Aufbau principle, which states that electrons fill orbitals in order of increasing energy levels. Electrons prefer to occupy lower energy orbitals because they are more stable, and therefore, require less energy to maintain their current state. The electron configuration of an atom describes the arrangement of its electrons in various orbitals.
The energy levels of electrons in atoms are described using the principal quantum number (n). The first energy level (n = 1) is the lowest energy level, and it is closest to the nucleus. As the value of n increases, so does the energy level of the electron, and the distance from the nucleus increases as well. In summary, electrons tend to occupy the lowest available energy level because they are more stable and require less energy.
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Which of the following combinations can be used to make a buffer? (Assume equal
volumes are used.)
A) 0.20 M NH, and 0.20 M HCI
B) 0.20 M NH, and 0.10 M NH CI
C) 0.20 M NH, and 0.10 M HF
D) 0.10 M NH CI and 0.10 M NaF
Answers
0.20 M NH₄, and 0.20 M HCI and 0.20 M NH₄, and 0.10 M HF are combinations that can be used to make a buffer. Thus option A and C are correct.
A buffer solution is an acid or a base aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.Its pH changes very little when a small amount of strong acid or base is added to it.
Buffer solutions are used as a means of keeping pH at a nearly constant value in a wide variety of chemical applications. In nature, there are many living systems that use buffering for pH regulation. For example, the bicarbonate buffering system is used to regulate the pH of blood, and bicarbonate also acts as a buffer in the ocean.
As the combination of HCl and NH₄, and NH₄ and HF are combinations that can be used to make a buffer. Thus option A and C are correct.
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In one of NASA's space tether experiments, a 20.0 km-iong conducting wire was deployed by the space shuttle as it orbited at 7.86×10^3m/s around Earth and across Earth's magnetic field lines. The resulting motional emf was used as a power source. If the component of Earth's magnetic field perpendicular to the tether was 1.31×10^−5T, determine the maximum possible potential difference (in V) between the two ends of the tether. 2,375 V 1,900 V 1,980 V 2,130 V 2,060 V 1,840 V 2,120 V
Answers
The maximum possible potential difference between the two ends of the tether is approximately 2.06 × 10³ V. Thus, the correct answer is 2.06 × 10³ V.
The maximum possible potential difference (V) between the two ends of the tether can be calculated using the formula:
V = B * L * v
where B is the magnetic field strength, L is the length of the wire, and v is the velocity of the wire.
In this case, we have the following values:
B = 1.31 × 10⁻⁵ T (magnetic field strength)
L = 20.0 km = 20,000 m (length of the wire)
v = 7.86 × 10³ m/s (velocity of the wire)
Plugging these values into the formula, we can calculate the potential difference:
V = (1.31 × 10⁻⁵ T) * (20,000 m) * (7.86 × 10³ m/s)
Calculating this value:
V ≈ 2.06 × 10³ V
Therefore, the maximum possible potential difference between the two ends of the tether is approximately 2.06 × 10³ V. Thus, the correct answer is 2.06 × 10³ V.
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What is the∆S° of 0₂
Answers
Answer:0
Explanation: zero because it is the most stable form of oxygen in its standard state
What might happen to the cryosphere if the insulating effect of the atmosphere increased?
Answers
Answer:
Acting like a highly reflective blanket, the cryosphere protects Earth from getting too warm. Snow and ice reflect more sunlight than open water or bare ground. Changes in snow and ice cover affect air temperatures, sea levels, ocean currents, and storm patterns all over the world.
Explanation: Hope this answers your question
Using the equation 40kJ+2SO3(g)-->2SO2(g) + O2(g), if pressure is added what way
does equilibrium shift?
Answers
In an equation, 40kJ + 2SO₃ (g) -->2SO₂(g) + O₂(g), if pressure added, the equilibrium shifts to the left side of the reaction because it has fewer moles of gas.
What is Le Ch atelier's principle?Le Ch atelier's principle states that if the pressure is added in a nay reaction, then the equilibrium will be shifted toward the side where there are fewer atoms.
In this case, there are fewer moles on the left side.
Thus, when pressure is added, the equilibrium shift to the left side due to Le Ch atelier's principle.
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do you think a decomposer and detritivore would compete with each other? justify your answer (pls just type the answer) :)
Answers
Explanation:
I don't think a decomposer and detritvore would compete with each other because decomposers job is to break down dead, organic materials and detritvores feed on dead organisms
Trimethylamine, (CH3)2N is a weak base (K6 = 6.3 x 10-5). What volume of this gas, measured at STP, must be dissolved in 2.5 L of solution to give that solution a pOH of 2.50?
PLEASE HELP ITS DUE IN 20 mins :(((((
Answers
The volume of the gas = 9.133 L
Further explanationGiven
Kb = 6.3 x 10⁻⁵
2.5 L solution
pOH= 2.5
Required
Volume of gas
Solution
pOH = 2.5
\(\tt [OH^-]=10^{-2.5}=0.0032=3.2\times 10^{-3}\)
For weak base :
\(\tt [OH^-]=\sqrt{Kb.M}\\\\(3.2\times 10^{-3})^2=6.3\times 10^{-5}\times M\\\\M=0.163\)
mol = M x V
mol = 0.163 x 2.5 L
mol = 0.408
Use ideal gas law at STP(1 atm, 273 K) :
\(\tt V=\dfrac{nRT}{P}=\dfrac{0.408\times 0.082\times 273}{1}=9.133~L\)
How many moles of oxygen gas could be produced by 120 moles of lead (II) nitrate?
Answers
Answer:
9 moles of O²
Explanation:
Hope this helped,
Philip
Brainliest always appreciated! <3
A swimming pool is 10m long, 5m wide, and 2m deep. ( 1 cm 3 = 1 ml 1m 3 = 1000000 cm 3 1 L = 1000 cm 3 ) a.) What is the volume of the swimming pool in milliliters?
Answers
V=(10)(5)(2)
V=100M
i’m not sure what the measurements in the parentheses means but the volume is 100Meters
Neglect overpotential and determine the minimum potential required to electrolyze molten CrClz How grams of Cr would be deposited and how many liters of Clz gas would be produced at 194 cC and 1.68 atm by passing current of 17.0 for 11.0 hrs? 221.49 79.604
Answers
To determine the minimum potential required to electrolyze molten CrCl2, we need to consider the electrochemical cell potential. Given the current and time, we can calculate the amount of Cr deposited and the volume of Cl2 gas produced using Faraday's laws and stoichiometry.
To determine the minimum potential required to electrolyze molten CrCl2, we need to consider the reduction half-reaction that occurs at the cathode during electrolysis. In this case, the reduction of Cr3+ to Cr occurs:
Cr3+ + 3e- → Cr
The standard reduction potential for this reaction can be found in electrochemical tables. By applying Faraday's laws, we can relate the amount of charge (Q) passed through the cell to the moles of electrons transferred. The potential required can be calculated using the equation:
E = (Q * E°) / (n * F)
where E is the cell potential, Q is the charge passed, E° is the standard reduction potential, n is the number of moles of electrons transferred, and F is Faraday's constant.
Given the current of 17.0 A and the time of 11.0 hours, we can calculate the total charge passed using Q = I * t. Substituting the values into the equation and solving for E will give the minimum potential required to electrolyze molten CrCl2.
To determine the amount of Cr deposited and the volume of Cl2 gas produced, we need to use the stoichiometry of the balanced equation for the reaction. From the balanced equation:
1 mole of Cr3+ + 3 moles of e- → 1 mole of Cr
2 moles of Cl- → 1 mole of Cl2
Using the calculated charge passed and Faraday's constant, we can calculate the moles of electrons transferred. From the stoichiometry, we can then determine the moles of Cr deposited and the moles of Cl2 produced. Finally, we can convert the moles of Cr to grams and the moles of Cl2 to liters at the given temperature and pressure.
By following these steps and performing the necessary calculations, we can determine the minimum potential required to electrolyze molten CrCl2, the amount of Cr deposited in grams, and the volume of Cl2 gas produced in liters.
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Calculate the % composition of these compounds:A. Ethane (C2H6)B. Sodium hydrogen sulfate (NaHSO4)
Answers
The percentage composition of ethane is 39.99% carbon
60.01% hydrogen and that of sodium hydrogen sulfate is 19.15% sodium 0.84% hydrogen 26.71% sulfur 53.30% oxygen
A. Ethane (C2H6)
To calculate the percent composition of ethane, we need to determine the molar mass of the compound, which is the sum of the atomic masses of all the atoms in the molecule.
Molar mass of ethane = (2 × molar mass of carbon) + (6 × molar mass of hydrogen)
= (2 × 12.011 g/mol) + (6 × 1.008 g/mol)
= 30.07 g/mol
Now we can calculate the percent composition of each element in ethane:
% composition of carbon = (2 × molar mass of carbon ÷ molar mass of ethane) × 100%
= (2 × 12.011 g/mol ÷ 30.07 g/mol) × 100%
= 39.99%
% composition of hydrogen = (6 × molar mass of hydrogen ÷ molar mass of ethane) × 100%
= (6 × 1.008 g/mol ÷ 30.07 g/mol) × 100%
= 60.01%
Therefore, the percent composition of ethane is:
39.99% carbon
60.01% hydrogen
B. Sodium hydrogen sulfate (NaHSO4)
To calculate the percent composition of sodium hydrogen sulfate, we need to determine the molar mass of the compound.
Molar mass of NaHSO4 = molar mass of Na + molar mass of H + molar mass of S + 4 × molar mass of O
= 22.99 g/mol + 1.008 g/mol + 32.06 g/mol + 4 × 16.00 g/mol
= 120.06 g/mol
Now we can calculate the percent composition of each element in sodium hydrogen sulfate:
% composition of sodium = (molar mass of Na ÷ molar mass of NaHSO4) × 100%
= (22.99 g/mol ÷ 120.06 g/mol) × 100%
= 19.15%
% composition of hydrogen = (molar mass of H ÷ molar mass of NaHSO4) × 100%
= (1.008 g/mol ÷ 120.06 g/mol) × 100%
= 0.84%
% composition of sulfur = (molar mass of S ÷ molar mass of NaHSO4) × 100%
= (32.06 g/mol ÷ 120.06 g/mol) × 100%
= 26.71%
% composition of oxygen = (4 × molar mass of O ÷ molar mass of NaHSO4) × 100%
= (4 × 16.00 g/mol ÷ 120.06 g/mol) × 100%
= 53.30%
Therefore, the percent composition of sodium hydrogen sulfate is:
19.15% sodium
0.84% hydrogen
26.71% sulfur
53.30% oxygen
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How many moles hydrogen can be produced from 4.53 moles of
aluminum?
Answers
Answer:
The answer to this question is 2.
when sodium chloride is formed sodium metal is mixed with chlorine has. How many grams are required to react completely with 2.00 mol of sodium
SHOW ALL WORK
Answers
The balanced chemical equation for the reaction is:
2 Na(s) + Cl2(g) -> 2 NaCl(s)
The molar ratio between Na and Cl2 in the reaction is 2:1. This means that for every 2 moles of Na, 1 mole of Cl2 is needed to react completely. Therefore, the number of moles of Cl2 needed to react with 2.00 mol of Na is:
2.00 mol Na x (1 mol Cl2 / 2 mol Na) = 1.00 mol Cl2
The molar mass of Cl2 is 70.90 g/mol. Therefore, the mass of Cl2 needed to react with 2.00 mol of Na is:
1.00 mol Cl2 x 70.90 g/mol = 70.90 g
So, 70.90 grams of Cl2 are required to react completely with 2.00 mol of sodium.
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you've been paying attention, you may have noticed that the names of certain types of biomolecules have certain characteristic endings. for example, the names of mono- and disaccharides typically end in -ose (ex: glucose, fructose, lactose). for each of the following names, see if you can use the ending of the name as a clue to what type of biomolecule it is! (hint: look at the names of other biomolecules of that type that might have been mentioned in your textbook or lecture notes.) thyroxine is likely to be a lactase is likely to be a raffinose is likely to be a lipase is likely to be a trehalose is likely to be a ornithine is likely to be a
Answers
Thyroxine is likely to be a hormone. Lactase is likely to be an enzyme.
Raffinose is likely to be a carbohydrate. Lipase is likely to be an enzyme.
Trehalose is likely to be a carbohydrate. Ornithine is likely to be an amino acid.
The "-ine" ending is not specific to a particular biomolecule type but often used for hormone names.
The "-ase" ending is commonly used for enzymes, indicating their catalytic activity.
The "-ose" ending suggests that it is a type of sugar or carbohydrate.
The "-ase" ending indicates that it is an enzyme involved in the breakdown or metabolism of lipids (fats).
The "-ose" ending suggests that it is a type of sugar or carbohydrate.
Many amino acids have names ending in "-ine" or "-ate." Ornithine is a non-protein amino acid involved in the urea cycle.
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which of the following could limit the accuracy of the qualitative analysis used here? one of the ions is present in trace amounts. the solution contains more than one ion. hydrochloric acid is contaminated with trace amounts of water. the identity of the counterion present in the solution.
Answers
The following could limit the accuracy of the qualitative analysis used here is one of the ions is present in trace amounts.
Th qualitative analysis is the determination of the information about the chemical species or the functional in the given sample. the quantitative analysis involves the data and the numbers, the quantitative analysis involves the method of analyzing the amount of chemical species in a sample. the amount is expressed in the numbers. while the qualitative analysis examine the information about whether an atom, ion functional group is present or absent.
Thus, the correct option is one of the ions is present in trace amounts will limit the accuracy of the qualitative analysis.
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Skepticism is important in this scenario because it would help him to learn from the investigations of his colleagues. Ask future questions related to the investigation. Communicate his results at a conference. Ensure that his conclusion is supported by evidence.
Answers
Answer:
hello your question is incomplete below is the missing part of the question
A biochemist performs an experiment to study the behavior of water molecules near proteins. He concludes that water molecules occur in groups of five in the presence of proteins.
answer : Ensure that his conclusion is supported by evidence.
Explanation:
Skepticism during the conduction of an experiment is an act/trait that a scientist possess that will make him/her repeat an experiment for the purpose of verifying the data gotten from the previous experiment
hence the answer to the question is to Ensure that his conclusion is supported by evidence.
ketoses such as fructose are expected to give a positive tollens test because:
Answers
Ketoses such as fructose are expected to give a positive Tollens test because of their ability to reduce Tollens' reagent.
What is the Tollens Test?The Tollens test is a chemical reaction used to test for the presence of aldehydes. The test is named after the German chemist Bernhard Tollens. The Tollens reagent is a solution of ammoniacal silver nitrate, Ag(NH3)2NO3. The test is based on the fact that aldehydes are readily oxidized to carboxylic acids by a solution of silver nitrate in ammonia.
This reaction is exothermic and produces a silver mirror on the inside of the test tube.The test solution is prepared by adding a few drops of a solution of Tollens' reagent to the substance being tested. The test solution is then heated in a water bath for a few minutes.
If the substance being tested is an aldehyde, it will reduce the silver ions in the Tollens' reagent to metallic silver. The metallic silver will form a mirror on the inside of the test tube. If the substance being tested is not an aldehyde, no mirror will form.The aldehydes are more easily oxidized than the ketoses.
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Find the reactant and product molar masses for this photosynthesis reaction reported to one place after the decimal point. A. The reactant mass is 186.0 grams, and the product mass is 186.0 grams. B. The reactant mass is 186.0 grams, and the product mass is 372.0 grams. C. The reactant mass is 372.0 grams, and the product mass is 186.0 grams. D. The reactant mass is 372.0 grams, and the product mass is 372.0 grams.
Answers
The reactant mass is 372.0 grams, and the product mass is 372.0 grams is the correct statement.
The balanced equation for photosynthesis is:
\(6 CO_{2} + 6 H_{2}O = > C_{6}H_{12}O_{6} + 6 O_{2}\)
From the given options:
A. The reactant mass is 186.0 grams, and the product mass is 186.0 grams.
This option is not balanced, as the total mass of the reactants and products should be equal. Therefore, option A is incorrect.
B. The reactant mass is 186.0 grams, and the product mass is 372.0 grams.
This option is not balanced either. The product mass is twice the reactant mass, which violates the law of conservation of mass. Therefore, option B is incorrect.
C. The reactant mass is 372.0 grams, and the product mass is 186.0 grams.
This option is also not balanced. The reactant mass is twice the product mass, which violates the conservation of mass. Therefore, option C is incorrect.
D. The reactant mass is 372.0 grams, and the product mass is 372.0 grams.
This option is balanced. The reactant mass is equal to the product mass, satisfying the conservation of mass. Therefore, option D is correct.
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How many moles of
C
O
2
COX
2
will be produced from
97.0
g
97.0 g97, point, 0, start text, space, g, end text of
C
3
H
8
CX
3
HX
8
, assuming
O
2
OX
2
is available in excess?
Answers
Answer:
Im highy
Explanation: