Answer:
B
Explanation:
VOLUME is how big an object is.....the amount of space it takes
Forces that cancel each other are called_ forces \
Answer:
balanced forces
The Mississippi River is continually forming and changing the land mass in the southern part of Louisiana. This kind of build up of land is called a
Answer:
dfdfsdf s
Explanation:
fsdfsd fsd fds f vsdvads
If an object is placed at a distance of 10 cm in front of a concave mirror of focal length 4 cm, find the position and characteristics of the image formed. Also, find the magnification.
Answer:
Explanation:
Focal length f = - 4 cm
Object distance u = - 10 cm
v , image distance = ?
Mirror formula
\(\frac{1}{v} +\frac{1}{u} = \frac{1}{f}\)
Putting the given values
\(\frac{1}{v} - \frac{1}{10} = - \frac{1}{4}\)
\(\frac{1}{v}= - \frac{3}{20}\)
v = - 6.67 cm .
magnification
m = v / u
= - 6.67 / - 10
= .667
so image will be smaller in size in comparison with size of object .
Characteristics will be that ,
1 ) it will be inverted and
2 ) it will be real image .
Matter is made of small particles to small to be seen. Which of these best describe evidence of this statement? 1. Tara’s crayons melted when she left them under the sun. 2. Kerris glass of water overflowed when she added ice. 3. Sams basketball expands as he pumps air into it. 4. Stephanie dropped a vase and it broke into pieces.
Answer:
Explanation:
I think the answer is statement no 3.
Hope it helps.
Answer:
1 Tara's crayons melted when she left them under the sun
A 2.5 kg block is initially at rest on a horizontal surface.A horizontal force of magnitude 6.0 N and a vertical force are
then applied to the block (Fig. 6-17).The coefficients of friction for
the block and surface are ms " 0.40 and mk " 0.25. Determine the
magnitude of the frictional force acting on the block if the magnitude
of is (a) 8.0 N, (b) 10 N, and (c) 12 N.
To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.
First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:
W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N
Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:
Fv = is sinθ
where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.
(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:
Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N
(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:
Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N
(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:
Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N
Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.
(a) When the horizontal force is 8 N the frictional force is 11.8 N.
(b) when the applied force is 10 N; the frictional force is 13.8 N.
(c) when the applied force is 12 N; the frictional force is 15.8 N.
What is the magnitude of the frictional force acting on the block?(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;
F - Ff = ma
where;
F is the horizontal force appliedFf is the frictional forcem is the massa is the accelerationF - μmg = ma
6 - 0.4 x 2.5 x 9.8 = 2.5 a
2.5 a = -3.8
a = -3.8/2.5
a = -1.52 m/s²
when the applied force is 8 N;
8 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 11.8 N
(b) when the applied force is 10 N;
10 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 13.8 N
(c) when the applied force is 12 N;
12 N - Ff = -1.52 m/s² x 2.5 kg
Ff = 15.8 N
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Question: imagine the decay of a very unusual particle that has a charge of Q = +24e. If it decays into 12 particles, 3 of which have electrical charges of +2e each, what is the collective charge of the other 9 particles?
According to the law of charge conservation,
The net charge of the system before and after the decay should remain constant.
As the charge before the decay is +24e.
Thus, the net charge after the decay should be +24e.
Given that, the charge on 3 particles out of 12 is +2e each.
Thus, collective charge of the other 9 particles is,
\(\begin{gathered} q=Q-3(+2e) \\ q=24e-6e \\ q=+18e \end{gathered}\)Thus, the collective charge on the other 9 particles is +18e.
How is a population with a clumped distribution different from a population with a uniform distribution?
Answer:
The organisms in a population may be distributed in a uniform, random, or clumped pattern. Uniform means that the population is evenly spaced, random indicates random spacing, and clumped means that the population is distributed in clusters.
Explanation:
What do primary lymphoid tissues do?
drain escaped plasma
filter lymph
create and develop white blood cells
remove lymph from the body
Answer: the answer is C- create and develop white blood cells
Explanation:
the combined effect of all forces acting on an object is the ___ force
Answer:
net force
Explanation:
When the car is sitting and not moving, inertia is in control and ___
exists.
The COBE mission and WMAP mission provide evidence to support the
A. Big Bang Theory
B. Steady State Theory
C. Hubble's Law
D. Doppler Effect
\(\huge{\textbf{\textsf{{\color{navy}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}\)
A. Big Bang Theory.Cosmic Background Explorer (COBE), U.S. satellite placed in Earth orbit in 1989 to map the “smoothness” of the cosmic background radiation field and, by extension, to confirm the validity of the big bang theory of the origin of the universe.WMAP measures anisotropy* with much finer detail and greater sensitivity than COBE did. These measurements reveal the size, matter content, age, geometry and fate of the universe. They also reveal the primordial structure that grew to form galaxies and will test ideas about the origins of these primordial structures.Answer:
I think it is Big Band theory
Explanation:
Evaluate tan(249).
O A. 1.36
B. 0.45
C. 0.41
D. 0.91
Answer:
tan 249 = 2.61
tan 249 = tan (249 - 180) = tan 69 = 2.61
the surface of venus is permanently covered by a thick layer of clouds, so astronomers have studied the surface by manned missions to the surface. images sent back by spacecraft that have landed on the surface. radar from spacecraft that have landed on venus' largest moon. telescope observations in visible light.
Venus has a very hot, dense atmosphere. You couldn't breathe the atmosphere, you would be crushed under the weight of the atmosphere, and you would burn up in temperatures
on the surface that were hot enough to melt lead. After the Sun and the Moon, Venus is the brightest object in the sky. In the morning or evening sky, Venus can occasionally be mistaken for a bright star. The planet is comparable to Earth on the inside and is a tad smaller than Earth. Venus's surface is atmosphere by dense clouds, so we can't see it from Earth.
The NASA spacecraft Mariner 2 successfully flew by and examined Venus, the first planet to be explored by a spacecraft.
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green light has a wavelength of 500 nm calculate the frequency.
Answer:
Solution: Given, the wavelength of the photon particle = 500 nm. In order to calculate the frequency of the photon particle, we use the formula given above. The frequency of the wave is equal to 6×10-4 Hz.
Originally Answered: The frequency of a green light is 6×10^14. What is its wavelength? In your case, the wavelength is 500 nm. What is the wavelength of 675 kHz? Should you leave more than $1,000 in a checking account? What is the frequency of a light that has a wavelength of 550 nm? Why would you even want to know this?
You have been given the wavelength λ (pronounced lambda) in nanometers, but not the frequency. Fortunately, a relationship between wavelength, frequency, and the speed of light, c exists, such that c = λ ⋅ ν. To determine the frequency from the wavelength, divide c by λ:
Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm? The answer is 3.54 ×10−19 J. The equation for determining the energy of a photon of electromagnetic radiation is E = hν, where E is energy in Joules, h is Planck's constant, 6.626 × 10−34J ⋅ s, and ν (pronounced "noo") is the frequency.
Explanation:
(2) Put 5kg mass at left side (at 2m). This is fixed throughout the experiment! (3) Try to balance by putting 5kg mass at the right side. Write the position of the 5kg mass. Calculate the net torque. Torque= mass * g*length, and the unit for torque is N.m (4) Try to balance by putting 10kg mass at the right side. Write the position of the 10kg mass. Calculate the net torque. (5) Try to balance by putting 20kg mass at the right side. Write the position of the 20kg mass. Calculate the net torque. (6) What do you conclude?
We can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.
What is torqueThe torque experienced by an object a given position is the product of the applied force and the perpendicular distance of the object.
When 5 kg mass is at 2 m on the left, another 5 kg at 2 m on the right will balance it.
\(\tau _{net} = (2 \times 5 \times 9.8) - (2 \times 5 \times 9.8)\\\\\tau _{net} = 0\)
Position of 10 kg mass on the rightApply principle of moment
\(F_1r_1 = F_2r_2\\\\(m_1gr_1) = (m_2gr_2)\\\\r_2 = \frac{m_1gr_1}{m_2g} \\\\r_2 = \frac{m_1 r_1}{m_2} \\\\r _2 = \frac{5 \times 2}{10} \\\\r_2 = 1 \ m\)
Net torque\(\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (10 \times 9.8 \times 1) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0\)
Position of the 20 kg mass\(r_2 = \frac{5 \times 2}{20} \\\\r_2 = 0.5 \ m\)
Net torque\(\tau_{et} = m_2gr_2 - m_1gr_1\\\\\tau_{et} = (20 \times 9.8 \times 0.5) - (5 \times 9.8 \times 2)\\\\\tau_{et} = 0\)
Thus, we can conclude that as the mass on the right increases, the distance of the mass towards the right decreases. Also when the two masses balance, the net torque is zero.
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A metal bar is in the xy-plane with one end of the bar at the origin. A force F⃗ =( 6.22 N )i^+( -2.81 N )j^ is applied to the bar at the point x= 3.58 m , y= 3.46 m .
\What are the magnitude of the torque with respect to the origin produced by F⃗ ?
man help me pleas e eso tilin baila tilin o dio smio tilin eso tilinnn
Why are Newton’s 3 laws important?
Answer:
Newton's law are very important because they tie into almost everything we see in everyday life. ... Newton's laws speak very generally all forces, but to use them for any specific problem, you have to actually know all the forces involved, like gravity, friction, and tension.
12.
A hiker walks for 5km on a bearing of 053" true (North 53° East). She then turns and
walks for another 3km on a bearing of 107° true (East 17° South).
(a)
Find the distance that the hiker travels North/South and the distance that she travels
East/West on the first part of her hike.
The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.
This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.
Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.
The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.
Angles will always be expressed in degrees in the solution.
The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.
The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.
Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.
The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.
The angle between the two is (180 - 53 - 17) = 110 degrees.
The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.
Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.
Distance Travelled East/WestThe hiker walked East for the second part of the hike.
To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.
The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.
Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.
To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.
The angle between the second vector and the Eastern direction is 17 degrees.
Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.
The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.
Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.
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Complete this paragraph, which describes an ice cube changing from a solid to a liquid to a gas
An ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.
What is a change of state process?A change of state process describes a process whereby a substance changes from one physical state to another.
The change of state processes are:
melting - solid changing to liquidvaporization - liquid changing to gasTherefore, an ice cube changing from a solid to a liquid is melting and then to a gas is vaporization.
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Which of the following is a good example of a contact force?
ОА.
Earth revolving around the Sun
OB.
a bridge suspended by cables
OC.
a ball falling downward a few seconds after being thrown upward
OD. electrically charged hairs on your head repelling each other and standing up
Answer:
A bridge suspended by cables
Explanation:
Both objects represent a contact force (in this case, normal force) acting on each other. The force occurs since both objects are in direct physical contact.
You push a cart with mass 15 kg forward, giving it an acceleration of 3 m/s2
How much force did you apply?
Answer:
45 N
Explanation:
F= ma (ie force is found by multiplying the mass of the object by its accerelation)
thus, F = 15 X 3 = 45 N
580 nm light shines on a double slit with d = 0.000125 m. What is the angle of the first bright interference maximum (m=1)?
PLS ANSWER
The angle of the first bright interference maximum (m=1) can be calculated using the equation: θ = sin-1(mλ/d).
What is equation ?An equation is a mathematical expression that uses symbols to describe a relationship between two or more variables. Equations are typically used to express relationships between physical quantities, such as forces and masses, or distances and times. They are also used to describe chemical reactions and other phenomena. Equations can be used to solve for unknown values, or to describe patterns or trends in data. Equations are typically written using algebraic notation, which includes variables, constants, and operators.
Substituting the given values, we get,θ = sin-1(1(580 × 10-9m)/(0.000125m)),θ = 0.00463 radians or 0.2637° .
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If you travel from Tucson to Argentina, you will see some different constellations in the night sky. true or false
Answer:
its true!!
Explanation: have a nice day !!
Archimedes' Principle states that a. the velocity of a fluid is directly proportional to the pressure exerted on the fluid. b. the pressure of a fluid is inversely proportional to the temperature of the fluid. c. the pressure in a fluid is directly related to the depth below the surface of the fluid. d. an object immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid.
Answer:
d. an object immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid.
Which term is the product of force and distance? power work net force acceleration please help
Answer: WORK
Explanation:
Answer:
work
Explanation:
got it right on edge:p
Which two atomic particles are found in the nucleus of an atom? Choose two.
* Nuetrons
* Electrons
* Protons
Neutrons and protons are the two atomic particles are found in the nucleus of an atom. Hence option 1 and 3 is correct.
What are atomic particles?Atomic particles are defined as a subatomic particle is an atom's constituent. The detection of more than 200 subatomic particles has been made thus far in highly developed particle accelerators.
The nucleus (or core) of an atom is composed of protons and neutrons. An extremely rare hydrogen isotope called tritium has a nucleus made up of one proton and two neutrons. The protons in an atom's nucleus are attracted to the electrons by the electromagnetic force.
Thus, neutrons and protons are the two atomic particles are found in the nucleus of an atom. Hence option 1 and 3 is correct.
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I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answer:
add molecules
10 points! Please HELP!
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough ________ _________, she can use a simple machine to help her lift the cage off the ground and into her car.
A. Big Muscles
B. Mechanical Force
C. Craft Supplies
D. Mechanical Advantage
Answer:
B- Mechanical Force
Explanation:
If Ms. Vetter who wants to work out, does not have enough mechanical force, she can use a simple machine to help her lift the cage off the ground and into her car. Thus, the correct option is B.
What is Mechanical force?Mechanical force is the force which is generated by the means of a machine is known as mechanical force. An example of mechanical force is when a car gets started, then its engine creates a mechanical force on the tyre of the car that help the car to accelerate with time. So here, the movement of the car occurs due to the force which is generated by the machine on the tyres.
Ms. Vetter wants to work out with her pet bunny after a long time, does not have enough mechanical energy, she can use a simple machine to help her lift the cage off the ground and into her car.
Therefore, the correct option is B.
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Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1100-kg car was moving at 10.9 m/s and stopped in 0.159 seconds.
The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.
What is Force?Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.
Mass of Kara's car = 1300 Kg
moving with speed = 11 m/s
time taken to stop = 0.14 s
final velocity = 0 m/s
distance between Lisa ford and Kara's car = 30 m
a) change in momentum of Kara's car
Δ P = m Δ v
Δ P = m(vf - vi)
Δ P = 1300 (0 - 11)
Δ P = -1.43 × 10⁴ kg.m/s
The impulse is equal to the change in momentum of the car
I = -1.43 × 10⁴ kg.m/s
Magnitude of the force experienced by Kara
I = F × t
where, I is impulse acting on the car
t is time
- 1.43 × 10⁴ = F × 0.14
F = -1.021 × 10⁵ N
Negative sign represents the direction of the force.
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Your question is incomplete, most probably the complete question is:
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.
a. Determine the momentum change of Kara's car.
b. Determine the impulse experienced by Kara's car.
c. Determine the magnitude of the force experienced by Kara's car.
How much work is required to lift a 3.07kg object from the bottom of a well 11.3 deep?
The work required to lift the 3.07 kg object from the bottom of the well 11.3 m deep is 340.03 joules.
What is Work?
In simple terms, work is done when a force moves an object over a certain distance. It is a measure of the energy transferred to or from an object as a result of an applied force. One joule of work is done when a force of one newton is applied to an object and it is moved one meter in the direction of the force.
The work required to lift a 3.07 kg object from the bottom of a well 11.3 m deep can be calculated using the formula:
Work = force x distance
To lift the object, we need to overcome the force of gravity pulling it downward.
force = mass x gravity
where mass = 3.07 kg (given) and gravity = 9.81 m/s²(acceleration due to gravity at the Earth's surface).
So, the force required to lift the object is:
force = 3.07 kg x 9.81 m/s²= 30.10 N
The distance over which the force needs to be applied is the depth of the well, which is given as 11.3 m.
Therefore, the work required to lift the object from the bottom of the well is:
Work = force x distance = 30.10 N x 11.3 m = 340.03 J
So, the work required to lift the 3.07 kg object from the bottom of the well 11.3 m deep is 340.03 joules.
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