Please solve this i will mark brainlist

Answer:To find how many valence electrons are in an element, simply locate the column number that it is in, and that determines the number of valence electrons in an element. This rule works only for elements excluding the transition metals.

Explanation:The number of valence electrons that an atom has is equal to the group number of that atom.

Hope this helps! ^w^

The highest boiling point based on the data is option 4

Compared to alcohols of comparable molecular weight, carboxylic acids often have higher boiling temperatures. Between the hydrogen atoms of adjacent molecules and the oxygen in the carboxyl group of carboxylic acids, strong intermolecular hydrogen bonds can develop. Because it takes more energy to break the intermolecular interactions and change the substance from a liquid to a gas during boiling, these hydrogen bonds help materials have higher boiling temperatures.

Although carboxylic acids and alcohols are both capable of forming hydrogen bonds, carboxylic acids have higher boiling temperatures due to the extra carboxyl group that they contain.

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0.595 moles of water can be made at 112.6 grams of \(HNO_{3}\) are consumed

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we use the equation's stoichiometry and molar masses.

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we need to use the molar mass of \(HNO_{3}\) and the stoichiometric coefficients of the balanced chemical equation.

The molar mass of \(HNO_{3}\) is calculated as follows:

1 mole of hydrogen (H) = 1 g/mol

1 mole of nitrogen (N) = 14 g/mol

3 moles of oxygen (O) = 3 × 16 g/mol = 48 g/mol

Adding these together, the molar mass of \(HNO_{3}\) is 1 + 14 + 48 = 63 g/mol.

Now, we can set up a conversion factor using the stoichiometry of the balanced equation:

From the equation: 5 + 6 \(HNO_{3}\) -> \(H_{2}SO_{4}\) + 6 \(NO_{2}\) + 2 \(H_{2}O\)

From the coefficients: 6 moles of \(HNO_{3}\) produce 2 moles of \(H_{2}O\)

To find the moles of water produced, we use the following calculation:

112.6 g \(HNO_{3}\) × (1 mol \(H_{2}O\) / 63 g \(HNO_{3}\)) × (2 mol \(H_{2}O\) / 6 mol \(HNO_{3}\)) = 0.595 mol \(H_{2}O\)

Therefore, when 112.6 grams of \(HNO_{3}\) are consumed, approximately 0.595 moles of water can be produced according to the given balanced equation and molar masses.

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Answer:

1500ml

Explanation:

molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1

Answer:

A) 14,500 kPa

B)  6 atm

C)  23.443 atm

D)  898.6  mmHg

Explanation:

Answer:

3. d

4. c

5. i

6. h

7. a

8. g

9. j

10. b

11. e

12. f

Explanation:

Answer:

PO4^3-, HPO4^2-

Explanation:

If an acid gives out a proton, the acid then changes to its corresponding base. Similarly, if a base takes in a proton, it changes to its corresponding acid. If a pair of acid and base differ only by the presence or absence of a proton, then they are referred to as a conjugate acid-base pair.

Let us look at this;

HPO4^2-(aq) ----> H^+(aq) + PO4^3-(aq)

HPO4^2- and PO4^3- differ only in the presence or absence of a proton (H^+) hence they constitute a conjugate acid-base pair.

Answer:

slowing the transfer of thermal energy from the air outside the bag

Answer:

D slowing the transfer of thermal energy from the food inside the bag to the air outside the bag

Explanation:

D

Moles of HNO  3

​  = 6.3/63 = 0.1 moles  

HNO3  has 1 atom of H , 1 atom of N , 3 atoms of O

No of atoms = moles of molecule × atomicity of atom × avogadro number

No of atoms of H =0.1×1×6.023×10^23

 = 6.023×10^22  

No of atoms of N =0.1×1×6.023×10^23

 = 6.023×10  ^22

No of atoms of O =0.1×3×6.023×10  ^23

 =  18.069×10 ^22

Answer:

\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\( \bold{n = \frac{N}{L} \\ }\)

where

n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question.

N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules

\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)

We have the final answer as.

Answer:

yes

Explanation:

Better temperatures can growth the quantity of water vapor withinside the air, that could growth the probability of precipitation.

Different factors, inclusive of air pressure, wind, and atmospheric instability, additionally play a function withinside the formation of rain, and the connection among temperature and precipitation may be complicated. The temperature of atmospheric gases could have a substantial effect at the manufacturing of rain. The environment is a complicated device that performs a vital function with inside the Earth`s water cycle, which incorporates the system of precipitation, inclusive of rain. Precipitation takes place while water vapor with inside the air condenses into liquid droplets or ice crystals, which fall to the floor as rain, snow, or hail. The temperature of the environment impacts the quantity of water vapor that the air can preserve. As temperature increases, the air can preserve extra water vapor, that could cause better tiers of humidity. When the air will become saturated with water vapor, it reaches its dew point, and the extra water vapor condenses into liquid droplets or ice crystals, that could shape clouds and subsequently precipitation. In addition, international warming, that's inflicting an growth in atmospheric temperatures, can cause modifications in precipitation styles and extra severe climate events. Understanding the connection among temperature and precipitation is vital for predicting and mitigating the affects of weather change.

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Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Answer:

yes its correct

Explanation:

Answer: the balanced equation is the same.

Explanation:

Every element must have the same number of atoms on each side of the equation (law of conservation of mass).

2. Balancing the equation can be done only by adjusting the coefficients.

C

is a balanced element because there is the same number of atoms of

C

in each side of the equation.

C

is a balanced element

H

is a balanced element because there is the same number of atoms of

H

in each side of the equation.

H

is a balanced element

O

is a balanced element because there is the same number of atoms of

O

in each side of the equation. O is a balanced element. Na is a balanced element because there is the same number of atoms of Na on each side of the equation. Na is a balanced element H is a balanced element because there is the same number of atoms of H on each side of the equation. H is a balanced element C is a balanced element because there is the same number of atoms on each side of the equation. C is a balanced element. O

is a balanced element because there is the same number of atoms of

O in each side of the equation. O is a balanced element. All elements have the same number of atoms on each side of the equation, which means that the law of conservation of mass is satisfied and thus the chemical equation is balanced.

The balloon contains 22.4 liters of N2 gas.

Several gas assumptions made by the ideal gas law aren't always true.  Explanation: For instance, the ideal gas law makes the assumption that gas particles don't have any volume and aren't drawn to one another. The gas law notion is constrained for the following reason.

We must first compute the number of moles of N2 before we can calculate the volume of N2 gas in liters. N2 has a molar mass of 28.02 g/mol.

n = mass / molar mass

n = 28.9 g / 28.02 g/mol

n = 1.031 moles

Now, we can use the ideal gas law to calculate the volume of N2 gas:

PV = nRT

V = nRT / P

V = (1.031 moles) x (0.08206 L·atm/K·mol) x (273.15 K) / (1 atm)

V = 22.4 L.

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

color

Explanation:

The reaction of 2-Bromo-2-Ethyl-3-Methylbutane with methanol is an example of a nucleophilic substitution reaction.

In this reaction, the methanol molecule acts as a nucleophile and attacks the carbon atom of the bromoalkane, resulting in the displacement of the leaving group (bromine) and the formation of a new carbon-oxygen (C-O) bond.

The reaction mechanism can be described as follows:

Protonation: In the first step, the methanol molecule acts as a base and abstracts a proton from the sulfuric acid catalyst to form the methoxide ion (CH3O-).

Nucleophilic attack: The methoxide ion then attacks the carbon atom of the bromoalkane, which is electrophilic due to the electron-withdrawing effect of the bromine atom. The attack results in the formation of a transition state in which the carbon-bromine bond is weakened and the carbon-oxygen bond is forming.

Elimination: The transition state then collapses to form the product, methylethylmethylcarbinol, with the simultaneous loss of the bromide ion. This step is known as the elimination step and occurs as the newly formed C-O bond is more stable than the weakened C-Br bond.

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Answer:

The number of molecules of water us 1.50× 10²⁵ molecules

Explanation:

From N=nL

where L =avogadro number ( 6.02× 10^²³ entities)

The number of the molecules of water =1

n (amount of substance)=25 moles

hence (N) = 25×1×6.02×10^²³

=1.50×10²⁵ molecules of H2O

Dipole-dipole interactions between molecules that do not include a covalent bond to a hydrogen atom are known as hydrogen bonds. The attraction between two incredibly electronegative atoms, such N, O, or F, and a hydrogen atom that is covalently bonded to one of them causes it to occur.

Any electronegative atom, such as oxygen, chlorine, or fluorine, may make up the other atom, whereas one of the atoms is hydrogen. Between molecules or between two different molecules, hydrogen bonds can develop between the atoms.

How to determine hydrogen bonding?

Determine whether hydrogen bonds are likely by looking at the molecule's Lewis structure. The electronegative atom needs one or more unshared electron pairs and a negative partial charge, much like oxygen and nitrogen do.

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To calculate the concentration of sodium ions in sea water in units of mol/L, we need to use Avogadro's number to convert the number of ions to moles, and then divide by the volume of the solution in liters.

Avogadro's number is the number of atoms or molecules in one mole of a substance, and it is approximately 6.022 x 10²³.

First, we need to calculate the number of moles of sodium ions in the solution:

Number of moles of Na+ = (2.7 x 10²²) / (6.022 x 10²³) = 0.0448 mol

Next, we need to calculate the concentration of sodium ions in the solution:

Concentration of Na+ = (0.0448 mol) / (0.120 L) = 0.373 mol/L

Therefore, the concentration of sodium ions in sea water is approximately 0.373 mol/L.

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Answer:

4.50x10^5

Explanation:

dont forget the zero on the 4.50

Answer:

The epic emotional journey of a suburban African American family as they navigate love, forgiveness and coming together in the wake of a tragic loss.

Explanation:

hope thsi helps if so please brainliest

Merry Christmas

The theoretical yield of NH₃ produced under the given conditions is 11.75 g.

The balanced equation for the reaction between hydrogen (H₂) and nitrogen (N₂) to form ammonia (NH₃) is;

N₂ + 3H₂ → 2NH₃

To determine the theoretical yield of NH₃ produced from the given amounts of H₂ and N₂, we need to calculate the limiting reactant and then use stoichiometry to find the maximum amount of NH₃ which can be produced.

The molar masses of H₂, N₂, as well as NH₃ are;

H₂; 2.02 g/mol

N₂; 28.02 g/mol

NH₃; 17.03 g/mol

The number of the moles of each reactant will be calculated as;

moles of H₂ = mass of H₂ / molar mass of H₂ = 1.40 g / 2.02 g/mol = 0.693 mol

moles of N₂ = mass of N₂ / molar mass of N₂ = 9.66 g / 28.02 g/mol = 0.345 mol

To determine the limiting reactant, we need to compare the mole ratios of H₂ and N₂ in the balanced equation with the actual mole ratios of the reactants. The balanced equation shows that 1 mole of N₂ will reacts with 3 moles of H₂ to produce a 2 moles of NH₃. The actual mole ratio of N₂ to H₂ in the reaction mixture is;

moles of N₂ / moles of H₂ = 0.345 mol / 0.693 mol

= 0.498

This ratio is less than the required ratio of 1/3, which means that N₂ is the limiting reactant. This means that all the N₂ will be consumed in the reaction and the amount of NH₃ produced will depend on the amount of N₂ present.

Using the mole ratio from the balanced equation, we can calculate the theoretical yield of NH₃ that can be produced from the 0.345 mol of N₂;

moles of NH₃ = (0.345 mol N₂) × (2 mol NH3 / 1 mol N₂)

= 0.690 mol NH₃

The mass of this amount of NH₃ can be calculated as;

mass of NH₃ = moles of NH₃ × molar mass of NH₃ = 0.690 mol × 17.03 g/mol = 11.75 g

Therefore, the theoretical yield is 11.75 g.

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Answer:

C.

Explanation:

When the pH is 7 there is equal amount of H+ and OH so the solution added must be strong enough to nuetralize the acid. So option A is out B is wrong because adding a acidic solution to an acidic solution wont nuetralize it, D is wrong because if the 2 solution was already equal in both it would essentaly be water. ALthough water would raise the pH it would not nuetralize it to a even 7.

Answer:

0.0064 qt

Explanation:

Given data:

Density of mercury = 13.6 g/cm³

Mass of mercury = 83.0 g

How many quarts mercury have = ?

Solution:

First of all we will calculate the volume in cm³.

d = m/v

13.6 g/cm³ = 83.0 g / volume

Volume = 83.0 g /  13.6 g/cm³

Volume = 6.1 cm³

cm³ to L:

6.1 cm³ × 1 L / 1000  cm³

0.0061 L

In quarts:

1 L = 1.06 qt

0.0061 L × 1.06 qt / 1 L

0.0064 qt

In order to find the result we will have to do some stoichiometry in this question, first we need to set up the reaction:

3 NO2 + H2O -> 2 HNO3 + NO, the reaction is already properly balanced, but there could be some stoichiometry questions in which you need to balance it first

Now, we have 60 grams of NO2, and we want to know how many grams of NO will be produced, let's check the molar ratio between the two compounds

If we have 3 moles of NO2 we will end up with 1 mol of NO, therefore the molar ratio is 3:1