(a) The 90% confidence interval for the average content of juice per bottle can be calculated using the formula: sample mean ± (critical value * standard deviation/square root of sample size). The critical value for a 90% confidence interval is obtained from the t-distribution. Repeat the same process to calculate the 95% confidence interval.
(b) The sample size required to estimate the average contents to within 0.5cl at the 95% confidence level can be determined using the formula: sample size = (z-score * standard deviation / margin of error)^2, where the z-score corresponds to the desired confidence level.
Here,
we would calculate the t-value and compare it with the critical value. If the t-value falls in the rejection region, we can reject the hypothesis that the average content per bottle is less than or equal to 45cl.
a) To calculate the confidence intervals, we will use the formula:
Confidence Interval = Sample Mean ± (Critical Value) * (Standard Deviation / sqrt(Sample Size))
For a 90% confidence interval:Sample Mean = 48cl
Standard Deviation = 5clSample Size = 100
Critical Value for 90% confidence level = 1.645
Confidence Interval = 48 ± (1.645) * (5 / sqrt(100))Confidence Interval = 48 ± 0.8225
Confidence Interval = (47.1775, 48.8225)
For a 95% confidence interval:Critical Value for 95% confidence level = 1.96
Confidence Interval = 48 ± (1.96) * (5 / sqrt(100))
Confidence Interval = 48 ± 0.98
Confidence Interval = (47.02, 48.98)
b) To calculate the required sample size, we can use the formula:
Sample Size = (Z² * StdDev²) / (Margin of Error²)
Margin of Error = 0.5cl
Critical Value for 95% confidence level = 1.96Standard Deviation = 5cl
Sample Size = (1.96² * 5²) / (0.5²)
Sample Size = 384.16Rounding up, the required sample size is 385.
Regarding the second part of the question:a) To test the hypothesis that the average content per
sample of 36 bottles with an average content of 48.5cl, we can calculate the t-value and compare it with the critical value.
b) To test the hypothesis that the average content per bottle is less than or equal to 45cl at the 5% significance level, we can use the same one-sample t-test. Again,
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What is the area of this rectangle?
Answer:
11 1/4
Step-by-step explanation:
1. count all the wholes -> 8
2. add all the halves ->there are 6 halves which is 3 wholes
3. add 1/4
4. add it all -> 8+3+1/4=10 1/4
Saumya read one third of book on Monday, two fifth of the remaining book on Tuesday, and still 60 pages were left to read. Find the total number of pages she read on Monday and Tuesday.(1) 90(2) 50(3) 40(4) 60
Fraction : Word problems may involve fractions if we are dealing with partial values coming from a whole.
Total number of pages she read on Monday are 50 pages .
Total number of pages she read on Tuesday are 40 pages .
Operations with Fractions:
we have to remeber some important rules, making fractions similar for addition and subtraction, and applying the reciprocal for the divisor in division. The operations would depend on the analysis of the problem.
We have given in the problem that on Monday, Saumya read 1/3 of a book and on Tuesday, she read 2/5 of the remaining pages. After those, the remaining number of pages is 60
Firstly, we have to find the total number of pages the book has.
We will begin by finding the remaining fraction of pages after Saumya read on Monday. We will subtract 1/3 from 1 whole since she read from the beginning of the book.
1 − 1/3 = 2/3
Now, we know that on Tuesday, Saumya began reading with 2/3 remaining in the book. We will now find the fraction of the pages Saumya read on Tuesday. We know that it's 2/5 of the remaining pages, so it's 2/5 of 2/3
=> 2/5× 2/3 = 4/15 of the total number of pages of the book on Tuesday. So now, we will find the total fraction of the number of pages of the book that Samuya has read so far. This is so we can compare this fraction with the number of pages remaining. For this, we will add
1/3 + 4/15 = (5 + 4)/15 = 9/15
then 1 - 9/15 = (15-9)/15 = 6/15
This means that there would be another 6/15
= 2/5 of the book remaining and
that the remaining 2/5 of the book = 60 pages the total number of pages = 60/2/5
= 60×5/2 = 150
Therefore, the book has a total of 150 pages.
Total number of pages she read on Monday
= 1/3 of 150 = 50 pages
Total number of pages she read on Tuesday
= 4/15 of 150 = 40 pages
Hence, the total number of pages she read on Monday and Tuesday are 50 pages and 40 pages respectively.
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the whole problem is in the pic below
Answer:
301.733% increase
Step-by-step explanation:
McMahon Hall on UW’s North Campus has 11 floors. You observe 7 people entering the elevator on the ground floor. In the absence of additional information, you assume that every person is equally likely to leave the elevator on any floor. What is the probability that on each floor at most 1 person leaves the elevator?
The probability that on each floor at most 1 person leaves the elevator is approximately 0.00048828125 or 0.0488%.
To determine the probability that on each floor at most 1 person leaves the elevator, we can approach this problem using the concept of independent events.
Let's consider each floor as an independent event where a person can either leave the elevator (event A) or not leave the elevator (event B). We want to find the probability that on each floor, at most 1 person leaves the elevator.
For each floor, there are two possibilities: either 0 person leaves (event B) or 1 person leaves (event A). Since we assume that each person is equally likely to leave the elevator on any floor, the probability of event A (one person leaving) is 1/2, and the probability of event B (no person leaving) is also 1/2.
Since there are 11 floors in total, and each floor's event is independent, we can use the multiplication rule for independent events to find the overall probability.
The probability that on each floor at most 1 person leaves the elevator is:
\((1/2)^11\)
This can be calculated as (1/2) multiplied by itself 11 times.
Therefore, the probability is approximately:
0.00048828125
So, the probability that on each floor at most 1 person leaves the elevator is approximately 0.00048828125 or 0.0488%.
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The f-test for equality of variances assumes: group of answer choices normal populations. equal sample sizes. equal means. equal means and sample sizes
Among all the options given the assumption that f test for equality of variances assumes that the population is normally distributed.
Given that f test for equality of variances has been taken.
We are required to give answer to the question that what f test for equality of variances assumes.
F test is basically any statistical test in which the test statistic has an F distribution under the null hypothesis. It is often used when comparing statistical models that have been fitted to a data set,in order to identify the model that fits the population from which the data were sampled.
F test for equality of variances assumes that the population is normally distributed.
Normal distribution is basically a distribution that is symmetric about the mean,showing that data near the mean are more frequent in occurrence than data far from the mean.
Hence among all the options given the assumption that f test for equality of variances assumes that the population is normally distributed.
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he purchase order amounts for books on a publisher's Web site is normally distributed with a mean of $36 and a standard deviation of $8 Find the probability that: a) someone's purchase amount exceeds $40. b) the mean purchase amount for 16 customers exceeds $40. Can use NORM.DIST function in Excel to answer the above.
This gives us a probability of approximately 0.3085, or 30.85%. This gives us a probability of approximately 0.0228, or 2.28%.
a) To find the probability that someone's purchase amount exceeds $40, we need to find the z-score first:
z = (40 - 36) / 8 = 0.5
Then we can use the NORM.DIST function in Excel to find the probability:
=NORM.DIST(0.5,TRUE,FALSE)
b) To find the probability that the mean purchase amount for 16 customers exceeds $40, we need to use the formula for the distribution of sample means:
μX = μ = $36
σX = σ/√n = $8/√16 = $2
Then we can find the z-score for this distribution:
z = (40 - 36) / 2 = 2
Using the NORM.DIST function in Excel, we can find the probability of the sample mean exceeding $40:
=NORM.DIST(2,TRUE,FALSE)
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Is (3, –4) a solution to the equation y = x + –7?
The point (3, -4) is indeed a solution to the equation y = x + -7.
To solve this problemWe can change the values of x and y into the equation and check to see if it still holds true to see whether the point (3, -4) is a solution to the equation y = x + -7.
Let's change x = 3 and y = -4 in the formula:
-4 = 3 + -7
Simplifying the right side of the equation:
-4 = -4
Both sides of the equation are equal, so the point (3, -4) is indeed a solution to the equation y = x + -7.
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plz help me
The container below contains 2 gray. 1 white, and 4 black marbles. Without looking, if Eric chooses a marble from the container will the probability be closer to O or to 1 that Eric will select a white marble? A gray marble? A black marble? Justify each of your predictions.
Step-by-step explanation:
Probability of Grey ball = 2/7 or 0.285. It is closer to 0
Probability of White marble = 1/7 or 0.142. It is closer to 0
Probability of Black marble = 4/7 or 0.571. It is closer to 1
Please help I need this
Answer:
11 inches
Step-by-step explanation:
The sides of the teacher's model are 110 inches
Henry's model should be 10 times shorter.
110 ÷ 10 = 11
The function C(t)=C0(1+r)t models the rise in the cost of a product that has a cost of C0 today, subject to an average yearly inflation rate of r for t years. If the average annual rate of inflation over the next 14 years is assumed to be 2. 5%, what will the inflation-adjusted cost of a $131,500 house be in 14 years? Round to two decimal places
The formula C(t) = C0(1+r)t is used to model the rise in the cost of a product over time. By substituting the given values into the formula, we calculated that the inflation-adjusted cost of the $131,500 house in 14 years would be approximately $185,204.45.
In mathematics, a function is a relationship between a set of inputs (also known as the domain) and a set of outputs (also known as the range) such that each input is associated with exactly one output. It describes how elements from the domain are mapped to elements in the range.
A function is typically denoted by a symbol, such as "f," followed by parentheses containing the input value. The result of applying the function to a specific input is denoted as "f(x)," where "x" represents the input value.
The given function C(t) = C0(1+r)t represents the rise in the cost of a product over time, where C0 is the initial cost, r is the average yearly inflation rate, and t is the number of years.
To find the inflation-adjusted cost of the $131,500 house in 14 years, we need to substitute the given values into the formula.
C(t) = C0(1+r)
In this case, C0 is $131,500, r is 2.5% (which can be written as 0.025 in decimal form), and t is 14 years.
C(14) = $131,500(1+0.025)¹⁴
Now we can calculate the inflation-adjusted cost using a calculator or by hand. Remember to follow the order of operations (PEMDAS/BODMAS).
C(14) = $131,500(1.025)¹⁴
C(14) ≈ $131,500(1.4085519153)
C(14) ≈ $185,204.45
Therefore, the inflation-adjusted cost of the $131,500 house in 14 years, assuming an average annual inflation rate of 2.5%, is approximately $185,204.45.
In summary, the formula C(t) = C0(1+r)t is used to model the rise in the cost of a product over time. By substituting the given values into the formula, we calculated that the inflation-adjusted cost of the $131,500 house in 14 years would be approximately $185,204.45.
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The freshman convention was held at the activity center with 12 567 seats. If 120 seats were not occupied. How many seats were occupied?
determine the type of the function: f(x)=x⁵+x
odd or even
A builder is creating a scale drawing of a plot of land as shown. The original plot of land is 335 meters wide. The drawing uses a scale factor of 1500.
Find the missing side length of the original plot of land in meters and the missing side length of the scale drawing in centimeters.
Original plot of land's length:
m
Scale drawing width:
The calculated width of the scale drawing is 0.67 cm and the missing side length is undefined
Finding the missing side length in the original plotWe have the following statements from the question
The width of the original plot is 335 metersThe scale factor of the drawing is 1/500.The above statements means that the width of the scale is
Scale width = 335 cm * 1/500
When the products are evaluated, we have the following
Scale width = 0.67 cm
This means that the width of the scale drawing is 0.67 cm
Also, the missing side length of the original plot of land in meters cannot be calculated
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The 5. one please 100 points
Answer:
Ok so 5 and tens least common denominator is 10. So 6/10- 2/10 (1/5×2=2/10)= 4/10. so now take 4/10 and 1/4 and find the lcm Which is 20 so 4/10×2 is 8/20+10/20=
18/20
\(\\ \sf\longmapsto \dfrac{6}{10}-\dfrac{1}{5}+\dfrac{1}{4}\)
\(\\ \sf\longmapsto \dfrac{2-4+5}{20}\)
\(\\ \sf\longmapsto \dfrac{-2+5}{20}\)
\(\\ \sf\longmapsto \dfrac{3}{20}\)
Please help as much as u can!!
Based on the lengths provided, the triangles can be classified as follows:
1. 9 ft, 20 ft, 14 ft = Obtuse
2. 15 cm, 8 cm, 17 cm = Right Triangle
3. 12 in, 10 in, 8 in = Acute
4. 20 m, 8 m, 19 m = Acute
5. 16 ft, 30 ft, 34 ft = Right Triangle
6. 80 ml, 78 ml, 5 ml= Obtuse
How to determine the triangle typeIn order to determine the type of triangle, the writer ought to note that obtuse triangles are those in which the squares of the smaller lengths are less than that of the largest length.
Also, the right triangle has squares of smaller lengths equal to the length of the largest length. Finally, the squares of the smaller lengths of an acute triangle are greater than the square of the largest. With this knowledge we can arrive at the following:
1. 9² + 14² = 20²
277 less than 400
Therefore, the triangle is Obtuse.
2. 15² + 8² = 17²
289 equal 289
Therefore, the triangle is a Right triangle
3. 10² + 8² = 12²
164 is greater than 144
Therefore, the triangle is Acute.
4. 8² + 19² = 20²
425 is greater than 400
Therefore,the triangle is Acute.
5. 16² + 30² = 34²
1156 is equal to 1156
6. 78² + 5² = 80²
6109 is less than 6400
Therefore, the triangle is Obtuse.
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a. suppose you obtain a chi-square statistic of 3.86. Are your results statistically significant if the critical value obtained from the distribution of chi-square is 6.63 with an α Level of .01?
b. What about with a chi-square statistic of 67.81. Are the results significant if a critical value of the distribution is 3.84 with α level of .05?
a. The chi-square statistic is not significant at the α level of .01.
b. The chi-square statistic is significant at the α level of .05.
How to determine chi-square statistic is not significant at α level of .01?a. With a chi-square statistic of 3.86 and a critical value of 6.63 at α level of .01, we can compare the two values.
Since 3.86 < 6.63, this means that the chi-square statistic is not significant at the α level of .01.
In other words, the result is not statistically significant and we fail to reject the null hypothesis.
How to determine chi-square statistic is significant at α level of .05. ?b. With a chi-square statistic of 67.81 and a critical value of 3.84 at α level of .05, we can again compare the two values.
Since 67.81 > 3.84, this means that the chi-square statistic is significant at the α level of .05.
In other words, the result is statistically significant and we reject the null hypothesis.
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a scatterplot shows: a. the average value of groups of data. b. scores on one variable plotted against scores on a second variable. c. the frequency with which values appear in the data d. the proportion of data falling into different categories.
Scores on one variable plotted against scores on a second variable.
The correct answer is (b)
Now, According to the question:
Let's know:
A scatterplot shows:
A scatterplot shows the relationship between two quantitative variables measured for the same individuals. The values of one variable appear on the horizontal axis, and the values of the other variable appear on the vertical axis. Each individual in the data appears as a point on the graph.
Hence, The correct answer is (b) i.e.,
Scores on one variable plotted against scores on a second variable.
Given,
In the question:
A scatterplot shows:
a. the average value of groups of data.
b. scores on one variable plotted against scores on a second variable.
c. the frequency with which values appear in the data
d. the proportion of data falling into different categories.
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please help, i will mark you branniest :))
solve for k
3/k = 4/5
Answer:
3/k = 4/5
k = 3 divided by 4/5
k = 3.75
Step-by-step explanation:
NEED HELP ON THIS ASAP!!!!GIVING OUT BRAINLIST TO BEST ANSWERS!!!
Answer:
Only part a; still haven't figured out b
Step-by-step explanation:
For a) the answers would be:
x: -5 0 3
y: -3 2 5
The equation says add y = x+2
Replace x with let's say -5, and we get y = -5+2
-5+2=-3
19 less than 3 times a number is 8 more than half of the number.
An equation is
How can the statement be rewritten as a conditional statement in if-then form? Lines on a coordinate plane are perpendicular if they have opposite reciprocal slopes. If lines on a coordinate plane have opposite reciprocal slopes, then they are perpendicular. If lines are on a coordinate plane, then they are perpendicular. If lines are on a coordinate plane, then they have opposite reciprocal slopes. If lines have opposite reciprocal slopes and are perpendicular, then they are on a coordinate plane.
Answer:
The first option. "If lines on a coordinate plane have opposite reciprocal slopes, then they are perpendicular."
Step-by-step explanation:
It is the only one that makes sense, tbh. But, it includes the proper "if-then" form like the question requests it have. It also incorporates all aspects of the original statement-
a.) lines on a coordinate plane
b.) perpendicular
c.) opposite reciprocal slopes.
You're welcome. :D
Answer:
Its A
Step-by-step explanation:
edge 2021
construct a box plot from the given data. diameters of cans in an assembly line: 5.5,5.5,5.1,5.3,5.2,5.5,5.5,5.2,5.6,5.2
To construct a box plot from the given data, which represents the diameters of cans in an assembly line, we need to determine the five-number summary and plot the corresponding box and whisker plot.
The five-number summary consists of the minimum value, the first quartile (Q1), the median (Q2), the third quartile (Q3), and the maximum value.
To construct the box plot, we start by arranging the data in ascending order: 5.1, 5.2, 5.2, 5.2, 5.3, 5.5, 5.5, 5.5, and 5.6. The minimum value is 5.1, and the maximum value is 5.6. The median is the middle value, which in this case is 5.3.
To find the first quartile (Q1) and the third quartile (Q3), we divide the data into two halves. Q1 is the median of the lower half, which consists of 5.1, 5.2, 5.2, and 5.2. Q3 is the median of the upper half, which consists of 5.5, 5.5, 5.5, and 5.6. The box plot will show the minimum value, Q1, Q2 (median), Q3, and the maximum value, giving us a visual representation of the distribution and variability of the data.
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A square pyramid with a = 15 inches and d= 72 inches is shown.
b=
d
C =
a
What are the lengths of leg b and hypotenuse c in triangle abc?
Drag a number into each box.
in.
b
in.
C
The length of leg b is 36 in. and hypotenuse c is 39 in. for triangle abc as shown in figure.
Define the term Square pyramid?A square pyramid is a three-dimensional geometric shape that consists of a square base and four triangular faces that meet at a common vertex or apex. Each of the triangular faces is congruent (i.e., of the same shape and size) and is called a lateral face, while the square base is called the base face.
for square pyramid, d = 72 in
Then, b = d/2 = 36 in
and height of the pyramid, a = 15 in
Then, by using Pythagoras theorem;
c² = a² + b²
c² = 15²+36² = 1521
c = 39 in
Therefore, the values of b is 36 in. and c is 39 in.
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A square pyramid with base side length (a) equal to 15 inches, and the slant height (d) equal to 72 inches. We are asked to find the length of leg b (height of the pyramid) and the hypotenuse c (edge length) in the triangle abc.
To do this, we can use the Pythagorean theorem,
\(a² + b² = c².\)
In this case, we will first find b by forming a right triangle using half of the base side length, the height (b), and the slant height (d).
\((1/2 * a)² + b² = d²\)
\((1/2 * 15)² + b² = 72²\)
\((7.5)² + b² = 5184\)
\(b² = 5184 - 56.25\)
\(b² = 5127.75\)
\(b ≈ 71.6 inches\)
Now that we have b, we can find c using the same Pythagorean theorem with a and b.
\(a² + b² = c²\)
\(15² + 71.6² = c²\)
\(225 + 5127.75 = c²\)
\(5352.75 = c²\)
\(c ≈ 73.2 inches\)
So, the lengths of leg b and hypotenuse c in triangle abc are approximately:
\(b = 71.6 inches\)
\(c = 73.2 inches\)
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The conversion rates between kilograms and pounds are: 1 k g ≈ 2.2 l b s 1 l b ≈ 0.454 k g A. How many kilograms is a backpack that weighs 6 pounds? 2.724 B. How many pounds is a cat that weighs 11 kilograms?
Answer:
\(6\ lb = 2.724\ kg\)
\(11\ kg = 24.2\ lb\)
Step-by-step explanation:
Given
\(1\ kg = 2.2\ lb\)
\(1\ lb = 0.454\ kg\)
Required
- Convert 6 lb to kg
- Convert 11kg to lb
To solve for (a), we make use of the second conversion unit:
\(1\ lb = 0.454\ kg\)
Multiply both sides by 6
\(6 * 1\ lb = 0.454\ kg * 6\)
\(6\ lb = 2.724\ kg\)
Hence, a 6lb backpack weighs 2.724kg
Solving (b): 11 kg to lb
Here, we make use of the first conversion unit
\(1\ kg = 2.2\ lb\)
Multiply both sides by 11
\(11 * 1\ kg = 2.2\ lb * 11\)
\(11\ kg = 24.2\ lb\)
Hence, the cat weighs 24.2lb
I don't understand this someone help me please
The expression "the total of a number a and a number b" can be expressed as a + b and when a = 2 and b = 7, the expression evaluates to 9.
How to Write a Phrase as an Expression?The phrase "the total of a number a and a number b" can be expressed as a mathematical expression a + b, where a and b are the two numbers being added together.
When a = 2 and b = 7, substituting these values into the expression gives:
a + b = 2 + 7 = 9
Therefore, the total of a number 2 and a number 7 is 9. This means that if we add the two numbers 2 and 7 together, we get a result of 9.
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Three scenarios are given. Select the prevalent problem illustrated within that scenario.
Scenario one: Students at a local high school taking algebra are allowed to choose either a regular classroom instruction or a self-paced computer-based instruction. Some of these students took an algebra prep course over the summer, but this was not recorded during the study. The same quiz will be administered to all students taking algebra. To understand the effectiveness of the two different types of instruction (regular vs self-paced), the average quiz scores will be compared.
a. Placebo effect
b. Confounding variable
c. Response bias
d. Selection bias
Scenario 2: Counselors at a local high school would like to revisit the academic integrity standards at the school. Counselors ask a random sample of students if they have ever cheated on an exam.
a. Placebo effect
b. Confounding variable
c. Response bias
d. Selection bias
Scenario 3: Lunch administrators at a local high school would like to assess if students like the new lunch options offered by the cafeteria. Administrators ask 40 students who have brought their own lunch from home.
a. Placebo effect
b. Confounding variable
c. Response bias
d. Selection bias
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The prevalent problem illustrated within the given scenarios are given below:
Scenario 1: The prevalent problem illustrated in scenario 1 is Selection bias.
Scenario 2: The prevalent problem illustrated in scenario 2 is Response bias.
Scenario 3: The prevalent problem illustrated in scenario 3 is Selection bias.
Explanation:
Scenario 1: The prevalent problem illustrated in scenario 1 is Selection bias. It occurs when individuals or groups of individuals are more likely to be selected to participate in a study than others, based on their particular characteristics or traits.
Scenario 2: The prevalent problem illustrated in scenario 2 is Response bias. It occurs when the subjects' answers are influenced by factors unrelated to the questions being asked or the content of the survey.
Scenario 3: The prevalent problem illustrated in scenario 3 is Selection bias.
It occurs when individuals or groups of individuals are more likely to be selected to participate in a study than others, based on their particular characteristics or traits.
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Justin divided 403 by a number and got a quotient of 26 with a remainder of 13. What was the number Justin divided by
given the following information, the test statistic is n = 49, xbar= 50, s = 7, h0: m => 52 ha: m < 52 the test statistic for the above information is
In this scenario, we are given the following information: sample size (n) is 49, sample mean (P) is 50, sample standard deviation (s) is 7, null hypothesis (H₀) states that the population mean (μ) is greater than or equal to 52, and the alternative hypothesis (Hₐ) states that the population mean is less than 52.
The test statistic for this situation is the t-statistic, which measures the difference between the sample mean and the hypothesized population mean, taking into account the sample size and the sample standard deviation. It is used to assess the evidence against the null hypothesis. In this case, since the alternative hypothesis states that the population mean is less than 52, we have a left-tailed test. To calculate the t-statistic, we use the formula:
t = (P - μ) / (s / √n)
Plugging in the given values:
t = (50 - 52) / (7 / √49) = -2 / (7 / 7) = -2
Therefore, the test statistic for the provided information is -2. This value represents the standardized difference between the sample mean and the hypothesized population mean, accounting for the sample size and standard deviation. It indicates that the sample mean is 2 standard deviations below the hypothesized population mean of 52.
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A. A simple random sample from a population with a normal distribution of 107 body temperatures hasxˉ=98.40∘Fands=0.69∘F. Construct a99%confidence interval estimate of the standard deviation of body temperature of all healthy humans. Is it safe to conclude that the population standard deviation is less than1.80∘F?
The 99% confidence interval for the population standard deviation of body temperature is (0.61°F, 0.80°F). Since the entire interval is below 1.80°F, it is safe to conclude that the population standard deviation is less than 1.80°F.
To construct a confidence interval estimate of the standard deviation of body temperature, we can use the formula:
s/sqrt(n-1) * sqrt((n-1)/chi-square(alpha/2, n-1)) < σ < s/sqrt(n-1) * sqrt((n-1)/chi-square(1-alpha/2, n-1))
where s is the sample standard deviation, n is the sample size, α is the significance level (1- confidence level), and chi-square is the chi-square distribution function.
Plugging in the values given, we get:
0.69/sqrt(107-1) * sqrt((107-1)/chi-square(0.01/2, 107-1)) < σ < 0.69/sqrt(107-1) * sqrt((107-1)/chi-square(1-0.01/2, 107-1))
0.69/10.344 * sqrt(106/71.605) < σ < 0.69/10.344 * sqrt(106/146.577)
0.177 < σ < 0.233
Therefore, we can say with 99% confidence that the population standard deviation of body temperature is between 0.177 and 0.233.
As for whether it is safe to conclude that the population standard deviation is less than 1.80°F, we can see that the confidence interval we calculated does not include this value. However, we cannot definitively say that the population standard deviation is less than 1.80°F without further evidence or a wider confidence interval.
To learn more about confidence interval visit;
brainly.com/question/24131141
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Please help I will give brainlyest
Answer: you’re just full of questions today aren’t you :)
Step-by-step explanation:
Just multiply both sides And you should get what you need
have a good day