please please please please please please ​

Answer:

Gravitational force related to distance because when an object is closer to the center of the earth the stronger the gravitational force is the farther an objects it from the center of the earth the weaker the gravitational force is. For example if you are on the moon there is no gravity because the gravitational force of the moon to the center of the earth is father away then for example standing on earth.

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

Know more about   kinetic energy  here:

https://brainly.com/question/8101588

#SPJ8

Answer:

P=1200watts

Explanation:

Power=voltage*current

V=120v

I=10A

P=120v*10A

P=1200watts

The correct option about power rating is, “1200 V”.

The quantity of energy moved or transformed per unit of time is known as power, and its unit is "watt".

We have given Potential Difference and current

So, we can use the formula which contain Potential Difference and current.

Which is,

Power = Potential Difference × Current

Power = 120 × 10 watts

Power = 1200 watts

Hence the power rating came out to be 1200 watt after solving.

Learn more about Electric Power here:

https://brainly.com/question/3631756

#SPJ2

To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0

F_tension = F_friction_lowerF_friction_lower = u_k * N_lower

F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.

The expression is: m*x''(t) + mk*x'(t) + f(t) = 0.This expression represents a second order differential equation describing the motion of a particle under the influence of a force, f(t).

Motion is the action or process of moving or being moved from one place to another. It is a fundamental property of all matter, as all physical objects possess the ability to move. Motion occurs when a force is applied to an object and causes it to change shape, direction, speed, or orientation. Motion can be described in terms of displacement, velocity, acceleration, momentum, and force. It involves an interaction between an object and its environment, and is often characterized by a change in energy. Motion can be studied through the fields of mechanics, kinematics, and dynamics.

To learn more about motion

https://brainly.com/question/28205978

#SPJ1

Answer:

Hello i hope this helps you! Potential and Kinetic EnergyHold the car at the top of the ramp, and release to demonstrate the two main kinds of energy. Potential energy is placed into the car when it's lifted from the floor, and that energy is released as the car rolls down the ramp.

Explanation:

hope this helps

Answer:

Conductivity, \(\sigma=500\ (\Omega-m)^{-1}\)

Explanation:

Given that,

The resistivity of a material, \(\rho=2\times 10^{-3}\ \Omega-m\)

We need to find the conductivity of the material.

We know that the reciprocal of resistivity is called conductivity.

\(\sigma=\dfrac{1}{\rho}\\\\\sigma=\dfrac{1}{2\times 10^{-3}}\\\\\sigma=500\ (\Omega-m)^{-1}\)

So, the conductivity of the material is \(500\ (\Omega-m)^{-1}\).

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

Know more about  plate boundaries    here:

https://brainly.com/question/30407141

#SPJ8

Answer:

8.51 m/s

Explanation:

Velocity = Displacement/Time

Velocity = 400 m ÷ 47 s

Velocity = 8.51 m/s

The force that will balance the two forces is 6.4 N

The resultant force, F can be obtained as follow:

F = √(F₁² + F₂²)

F = √(4² + 5²)

F = √(16 + 25)

F = √41

F = 6.4 N

Thus, the force that will balance the two forces is 6.4 N

See attached photo

Learn more about resultant force:

https://brainly.com/question/25239010

The force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

The Resultant of the two forces 4.0 N and %.0 N acting perpendicular to each other is calculated using the formula:

R² = A² + B²

where A and B are the two forces acting perpendicular to each other.

R² = 4² + 5²

R² = 41

R = 6.4 N

Therefore, the force that will counterbalance two forces 4.0 N and 5.0 N acting perpendicular to each other is a force of 6.4 N acting in an opposite direction to the resultant of the two forces.

Learn more about resultant and equilibrant forces at: https://brainly.com/question/8045102

Answer:

\(c.) \: systematic \: error \\ \\ = > it \: is \: the \: error \: caused \: \\ \\ due \: to \: the \: procedure \\ \\ \: and \: used \: apparatuses \\ \\ \huge\mathfrak\red{Hope \: it \: helps}\)

Answer: The correct answer is formation of four haploid nuclei.

The event occurring during telophase II includes formation of four haploid daughter cells. Telophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the nuclear spindle. During this stage both the daughter cells get divided forming four haploid cells. The development of the nuclear envelope around each set of the chromosome and cytokinesis also takes place during telophase II.

Explanation:

???

Answer:

the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.

Explanation:

imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line

The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for t.

Hence, the time it takes the stone to fall is 1.2 seconds.

Learn more about time here: https://brainly.com/question/26046491

#SPJ1

The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

for more such questions on force

https://brainly.com/question/12785175

#SPJ8

Elements are most simply made up of atoms. A pure element will only have one type of atom, for example, a pure chunk of gold will only have gold atoms, making it chemically pure.

Two identical atoms bonded chemically, most frequently by covalent bonds, to form a molecule. Halogens are typically diatomic molecules; for example, chlorine is known as Cl2.

A pure substance is made up of various elements that have been chemically combined. Ionic chemicals that are connected by ionic bonds are the most common way to observe this. Please remember that a compound is not the same as a mixture! Keep in mind that a combination is not linked chemically.

to know more about molecules, compounds and pure substances, see

https://brainly.com/question/475709

https://brainly.com/question/26487468

https://brainly.com/question/18634105

Answer:

400 N

Explanation:

F = G m1 m2 / r^2        now double the masses

   F2 = G 2m1 2m2 / r^2

         = 4  G m1 m2 / r^2     < ==== this is 4 times the original force

100 N * 4 = 400 N

Answer:

a = - 0.3376 g's

Explanation:

The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s

It brakes and now comes to a stop in 3.6 s.

Thus final velocity = 0 m/s

Formula for acceleration is;

a = (v - u)/t

a = (0 - (164/13.77))/3.6

a = -3.308 m/s²

In terms of g's", where 1.00 g = 9.80 m/s², we have;

a = -3.308/9.8 g's

a = - 0.3376 g's

Answer:

x-component = 7.1

Explanation:

x-component = 9cos38 = 7.09 =7.1

Answer:

7.1

Explanation:

use cos

For the following are four electrical components:

a. For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction.

For the following are four electrical components:

a. Sketches of current-voltage characteristics:

For components A and B, both of which obey Ohm's law, the current-voltage characteristics would be a straight line passing through the origin. The slope of the line for component B would be steeper than that of component A, indicating higher resistance.

  Current (I)

     ^

     |          B

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

     Current (I)

     ^

     |          A

     |         /

     |        /

     |       /

     |      /

     |     /

     |    /

     |   /

     |  /

     | /

     |/

     +------------------> Voltage (V)

For component C, a filament lamp, the current-voltage characteristic would be a curve that is not linear. It would exhibit a non-linear increase in current with increasing voltage. At lower voltages, the lamp would have low resistance, but as the voltage increases, the resistance of the filament also increases due to the phenomenon of thermal self-regulation. This leads to a slower increase in current at higher voltages.

For component D, a component that does not obey Ohm's law, the current-voltage characteristic could be any non-linear curve depending on the specific component chosen. Examples of components that do not obey Ohm's law include diodes and transistors.

b. The shape of the characteristic for component C, the filament lamp, can be explained by its construction. A filament lamp consists of a filament made of a resistive material, typically tungsten, which heats up and emits light when an electric current passes through it. As the voltage across the filament increases, the temperature of the filament increases as well, causing its resistance to increase. This increase in resistance results in a slower increase in current with increasing voltage, leading to the characteristic non-linear curve observed.

c. The component chosen for D, which does not obey Ohm's law, could be a diode. A diode is a two-terminal electronic component that allows the current to flow in only one direction. It exhibits a non-linear current-voltage characteristic where it conducts current only when the voltage is above a certain threshold, known as the forward voltage. Below this threshold, the diode has a high resistance and blocks current flow in the reverse direction. The characteristic curve of a diode would show negligible current flow until the forward voltage is reached, after which it exhibits a rapid increase in current with a relatively constant voltage.

For more such questions on electrical components, click on:

https://brainly.com/question/28630529

#SPJ8

Explanation:

The range R of a projectile is given the equation

\(R = \dfrac{v_0^2}{g}\sin{2\theta}\)

The maximum range is achieved when \(\theta = 45°\) so our equation reduces to

\(R_{max} = \dfrac{v_0^2}{g}\)

We can solve for the initial velocity \(v_0\) as follows:

\(v_0^2 = gR_{max} \Rightarrow v_0 = \sqrt{gR_{max}}\)

or

\(v_0 = \sqrt{(9.8\:\text{m/s}^2)(9.5×10^6\:\text{m})}\)

\(\:\:\:\:\:\:\:=9.6×10^3\:\text{m/s}\)

To find the maximum altitude H reached by the missile, we can use the equation

\(v_y^2 = v_{0y}^2 - 2gy = (v_0\sin{45°})^2 - 2gy\)

At its maximum height H, \(v_y = 0\) so we can write

\(0 = (v_0\sin{45°})^2 - 2gH\)

or

\(H = \dfrac{(v_0\sin{45°})^2}{2g}\)

\(\:\:\:\:\:\:= \dfrac{[(9.6×10^3\:\text{m/s})\sin{45°}]^2}{2(9.8\:\text{m/s}^2)}\)

\(\:\:\:\:\:\:= 2.4×10^6\:\text{m}\)

Complete question is;

At one instant, v = (−2.00 i^ +4 .00 j^ − 6.00 k^)m/s is the velocity of a proton in a uniform magnetic field B = (2.00 i^ − 4.00 j^ +8 .00 k^) mT. At that instant, what are;

(a) the magnetic force acting on the proton, in unit-vector notation

(b) the angle between the velocity and magnetic field

Answer:

A) F = [1.28 × 10^(-21)] i^ + [6.4 × 10^(-22)] j^

B) θ = 151.02°

Explanation:

A) Since the unit of magnetic field is given in mT, let's convert it to T.

Thus;

B = (0.002 i^ − 0.004 j^ + 0.008 k^) T

Formula for the magnetic force is;

F = qVB

Where q = 1.6 × 10^(-19) C

Since V and B are in vector notation, the way to multiply it is;

(v_y•B_z - v_z•B_y)i^ + (v_z•B_x - v_x•B_z) j^ + (v_x•B_y - v_y•B_x) k^

Thus;

F = 1.6 × 10^(-19)((v_y•B_z - v_z•B_y)i^ + (v_z•B_x - v_x•B_z) j^ + (v_x•B_y - v_y•B_x) k^)

Plugging in the relevant values;

F = 1.6 × 10^(-19)[{(4 × 0.008) - (-6 × -0.004)} i^ + {(-6 × 0.002) - (-2 × 0.008)} j^ + {(−2 × -0.004) - (4 × 0.002)} k^]

Multiplying out gives;

F = [1.28 × 10^(-21)] i^ + [6.4 × 10^(-22)] j^

B) Angle between the 2 vectors gotten for the velocity and magnetic field is given by the formula;

Cos θ = (a•b)/(|a| × |b|)

(a•b) = (−2.00 i^ + 4.00 j^ − 6.00 k^) • (0.002 i^ − 0.004 j^ + 0.008 k^)

>> (2 × 0.002) + (4 × -0.004) + (-6 × 0.008) = -0.06

|a| = √((-2)² + (4)² + (-6)²)

|a| = √56

|b| = √((0.002)² + (-0.004)² + (0.008)²)

|b| = 0.009165

Thus;

Cos θ = -0.06/(0.009165 × √56)

Cos θ = -0.8748

θ = cos^(-1) -0.8748

θ = 151.02°

ANSWER:

STEP-BY-STEP EXPLANATION:

Light travels faster in air than in glass because air is an optically rarer medium.

The term speed of light refers to the speed with which light travels through diverse materials. We know that light travels faster in air than in glass owing the the difference in the nature and composition of the two materials.

Hence, the explanation of the student concerning the differences in angles does not account for the differences in the speed of light in materials. Light travels faster in air than in glass because air is an optically rarer medium.

Learn more about speed of light: https://brainly.com/question/394103

The speed of the block when it reaches marker 1 is given by √(v₀² + 2aL).

The block spends (-v₀ + √(v₀² + 8aD)) / (2a) seconds between marker 1 and marker 2.

Part A:

To determine the speed of the block when it reaches marker 1, use the equations of motion. The block starts with an initial speed of v0 and experiences a constant deceleration of magnitude a.

Using the equation of motion:

v₁² = v₀² + 2aΔx

where v₁ = speed at marker 1, v₀ = initial speed, a = acceleration, and Δx = distance traveled.

Since the block slows down, the final speed v₁ at marker 1 is less than the initial speed v₀. The distance traveled from the initial position to marker 1 is L.

Therefore, the equation becomes:

v₁² = v₀² + 2aL

Taking the square root of both sides:

v₁ = √(v₀² + 2aL)

So the speed of the block when it reaches marker 1 is given by √(v₀² + 2aL).

Part B:

To determine the time the block spends between the two markers, use the equation of motion:

Δx = v₀t + (1/2)at²

where Δx = distance between marker 1 and marker 2, v₀ = initial speed, a = acceleration, t = time, and t = time between the two markers.

Since the block slows down, the final speed at marker 2 is 0. Therefore, the distance between marker 1 and marker 2 is D.

The equation becomes:

D = v₀t + (1/2)at²

Rearranging the equation:

at² + v₀t - 2D = 0

This is a quadratic equation in t. Solve it using the quadratic formula:

t = (-v₀ ± √(v₀² + 8aD)) / (2a)

Since the block slows down, the time between the two markers is the positive root of the quadratic equation:

t = (-v₀ + √(v₀² + 8aD)) / (2a)

So the block spends (-v₀ + √(v₀² + 8aD)) / (2a) seconds between marker 1 and marker 2.

Find out more on speed and time here; https://brainly.com/question/4931057

#SPJ1

The kinematics of the uniform motion and the addition of vectors allow finding the results are:

Vectors are quantities that have modulus and direction, so they must be added using vector algebra.

A simple method to perform this addition in the algebraic method which has several parts:

 Indicate that Barry's velocity is constant, let's find using the uniform motion thatthe distance traveled in ad case

              v = \(\frac{\Delta d}{t}\)

              Δd = v t

Where  v is the average velocity, Δd the displacement and t the time

We look for the first distance traveled at speed v₁ = 600 m / s for a time

          t₁ = 2 min = 120 s

          Δd₁ = v₁ t₁

          Δd₁ = 600 120

          Δd₁ = 72 10³ m

Now we look for the second distance traveled for the velocity v₂ = 400 m/s    

  time t₂ = 1 min = 60 s

          Δd₂ = v₂ t₂

          Δd₂ = 400 60

          Δd₂ = 24 103 m

In the attached we can see a diagram of the different Barry trajectories and the coordinate system for the decomposition,

We must be careful all the angles must be measured counterclockwise from the positive side of the axis ax (East)

Let's use trigonometry for each distance

Route 1

          cos (180 -35) = \(\frac{x_1}{\Delta d_1}\)

          sin 145 = \(\frac{y_1}{\Delta d1}\)

          x₁ = Δd₁ cos 125

          y₁ = Δd₁ sin 125

          x₁ = 72 103 are 145 = -58.98 103 m

          y₁ = 72 103 sin 155 = 41.30 10³ m

Route 2

          cos (90+ 30) = \(\frac{x_2}{\Delta d_2}\)

          sin (120) = \(\frac{y_2}{\Delta d_2}\)

          x₂ = Δd₂ cos 120

          y₂ = Δd₂ sin 120

          x₂ = 24 103 cos 120 = -12 10³ m

           y₂ = 24 103 sin 120 = 20,78 10³ m

The component of the resultant vector are

              Rₓ = x₁ + x₂

              R_y = y₁ + y₂

              Rx = - (58.98 + 12) 10³ = -70.98 10³ m

              Ry = (41.30 + 20.78) 10³ m = 62.08 10³ m

We construct the resulting vector

Let's use the Pythagoras' Theorem for the module

             R = \(\sqrt{R_x^2 +R_y^2}\)

             R = \(\sqrt{70.98^2 + 62.08^2}\)   10³

             R = 94.30 10³ m

We use trigonometry for the angle

             tan θ ’= \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{R_y}{R_x}\)

             θ '= tan⁻¹ \(\frac{62.08}{70.98}\)

             θ ’= 41.2º

Since the offset in the x axis is negative and the displacement in the y axis is positive, this vector is in the second quadrant, to be written with respect to the positive side of the x axis in a counterclockwise direction

            θ = 180 - θ'

            θ = 180 -41.2

            θ = 138.8º

Finally, let's calculate the speed for the way back, since the total of the trajectory must be 5 min and on the outward trip I spend 3 min, for the return there is a time of t₃ = 2 min = 120 s.

The average speed of the trip should be

             v = \(\frac{\Delta R}{t_3}\)  

             v = \(\frac{94.30}{120} \ 10^3\)

              v = 785.9 m / s

in the opposite direction, that is, the angle must be

               41.2º to the South of the East

In conclusion, using the kinematics of the uniform motion and the addition of vectors, results are:

Learn more here:  brainly.com/question/15074838

Answer:

a) 1.1418 kg

b) 0.9135 kg/s

Explanation:

Given data :

spring constant ( k ) = 3 kg/s^2

amplitude of vibrations will decay like :  

The mass of the object will be 1.418 kg and the value of the friction coefficient, b is 0.9135 kg/s.

In physics, a periodic motion is a movement that repeats at regular intervals. A swing in motion, a rocking chair, a bouncing ball, a tuning fork vibrating, the Earth orbiting the Sun, and a water wave are all examples of periodic motion. The time interval for repetition, or cycle, of the motion, is referred to in each case as a period, and the frequency is the number of periods per unit of time.

According to the question, the given values are :

Spring constant, k = 3 kg/s²,

Time, T₁ = 4 sec

r = 0.4

The formula for damped oscillation is : \(e^-^r^t\)

r = b / 2 m

w₁ = \(\sqrt{w_0^2-r^2}\)

T₁ = 2π / w₁

= 2 π /        \(\sqrt{w_0^2-r^2}\)

w₀ = \(\sqrt{4 \pi^2/T_1 +r^2}\)

\(\sqrt{k/m}\) = \(\sqrt{4 \pi^2/T_1 +r^2}\)

M = k / \({4 \pi^2/T_1 +r^2}\)

M = 3/ (4π/4² +(0.4)²)

M = 1.1418 kg

b = 2 Mr = 2 × 1.1418 × 0.4

b = 0.9135 kg/s

Hence, the mass of the object is 1.1418 kg and the friction coefficient is 0.9135 kg/s.

To get more information about Periodic motion :

https://brainly.com/question/28249471

#SPJ2