please PLEASE PLEASE PLEASE PLEASE HELPPPOO ILL LITERALLY BEG

The metric system contains seven fundamental units of measure. The seven base units of measure in the metric system are length, mass, time, electric current, temperature, luminous intensity, and amount of substance.

These base units are used to measure different types of physical quantities in the metric system.What is the metric system?The metric system is a measuring system that is used throughout the world, and it is based on the decimal system. I

t is easy to use because it is based on powers of ten. This means that each unit is ten times larger than the previous unit and ten times smaller than the next unit.The International System of Units (SI), also known as the metric system, is a globally accepted system of measurement that is used to measure different physical quantities.

It consists of a set of fundamental units of measure, derived units, and prefixes that are used to express the units of measure.The metric system is a standard system of measurement that is used worldwide, and it has become the standard system of measurement for science, engineering, and commerce.

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Answer:

The formula for the volume of a sphere is. V = (4/3)πr3. If the diameter is 18 inches, then the radius is 9 inches.

Answer:

B. 6

Step-by-step explanation:

I had the same question and 6 was correct.

hope this helps :)

Answer:

Step-by-step explanation:

Answer:

The percent error of Jack's measurement was 3.6%, to the nearest tenth of a percent. This is calculated by subtracting the actual length (16.6 inches) from the measured length (17.2 inches) and dividing by the actual length, then multiplying by 100.

Step-by-step explanation:

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There are infinitely many even integers that are divisible by 5.

By considering how any even integer can be represented as 2m, where m is an integer, it becomes evident that if 2m happens to be divisible by 5, then m will also have this quality because 5, which is a prime number, cannot divide into 2.

As a result, all even integers that aredivisible by 5 can be expressed in the format of 10n, with any n being acceptable. Examples of such numbers include:

0 (from 10 x 0 = 0)

10 (from 10 x 1 = 10)

-10 (through 10 x -1 = -10)

20 (by evaluating 10 x 2 = 20)

And similarly when exploring negative values:  

-20 (since 10 x -2 = -20), and so on.

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The lines y = 2 and x = 4 are neither parallel nor perpendicular.

The given lines are y = 2 and x = 4.

The line y = 2 is a horizontal line because the value of y remains constant at 2, regardless of the value of x. This means that all points on the line have the same y-coordinate.

On the other hand, the line x = 4 is a vertical line because the value of x remains constant at 4, regardless of the value of y. This means that all points on the line have the same x-coordinate.

Since the slope of a horizontal line is 0 and the slope of a vertical line is undefined, we can determine that the slopes of these lines are not equal. Therefore, the lines y = 2 and x = 4 are neither parallel nor perpendicular.

Parallel lines have the same slope, indicating that they maintain a consistent distance from each other and never intersect. Perpendicular lines have slopes that are negative reciprocals of each other, forming right angles when they intersect.

In this case, the line y = 2 is parallel to the x-axis and the line x = 4 is parallel to the y-axis. Since the x-axis and y-axis are perpendicular to each other, we might intuitively think that these lines are perpendicular. However, perpendicularity is based on the slopes of the lines, and in this case, the slopes are undefined and 0, which are not negative reciprocals.

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The matrix of \(t\) relative to the basis \(b'\) is \(A' = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\).

\(\textbf{To find the matrix of } t \textbf{ relative to the basis } b', \textbf{we have to follow some steps. The steps are described below:}\)

First, we have to find the images of basis vectors under the transformation \(t\). \(t(-1,1) = (-9,7)\) and \(t(1,-5) = (-37,43)\).

Represent the image vectors of the basis in the standard basis. We use these vectors as columns in the matrix of \(t\) in the basis \(b'\).

\((-9,7) = -9(1,0) + 7(0,1) = (-9,7) = -9(-1,1) + 7(1,-5)\)

\((-37,43) = -37(1,0) + 43(0,1) = (-37,43) = -37(-1,1) + 43(1,-5)\)

Hence, we can write the following equation: \(A[x]_{b'} = [x]_S\)

Where \(A[x]_{b'}\) is the main answer in the form of a matrix, and \([x]_S\) is the coordinate of \([x]_{b'}\) with respect to the standard basis.

Now, we will write the equations with the coordinates of the basis vectors of \(b'\).

\(A[1,0] = [-9, -37]\) and \(A[0,1] = [7, 43]\)

Now we will write the matrix of \(A\) as follows:

\(A = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\)

Thus, the matrix of \(t\) relative to the basis \(b'\) is \(A' = \begin{bmatrix} -9 & 7 \\ -37 & 43 \end{bmatrix}\).

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Answer:

D) 2/4

Step-by-step explanation:

2/4 is equivalent to 4/8 which is less than 5/8

The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.

The hypotheses for the test are:

H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.

To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.

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Answer:

a

Step-by-step explanation:

you were right.

hope this helps

Answer:

35 - 20n

Step-by-step explanation:

Use destributive property.

5 * 7 = 35

5 * 4n = 20n

35 - 20n

The two planes will meet 6 hours after they start, i.e. at 3 pm.

Two planes leave at 9 am from airports that are 2700 miles apart and fly towards each other at a speed of 200 mph and 250 mph. At what time will they pass each other?

Let's assume the planes A and B leave the two airports that are 2700 miles apart at the same time. The speed of the first plane is 200 mph and the speed of the second plane is 250 mph. To find out the time at which they pass each other, we need to calculate the distance between them and divide it by the sum of their speeds.

Distance traveled by the first plane in time t1 is equal to 200t1.Distance traveled by the second plane in time t2 is equal to 250t2.The distance covered by the first plane and the second plane together will be 2700 miles.Time taken by both the planes to meet can be calculated as below:

t1 + t2 = 2700/(200+250) = 6 hoursAs both the planes start at 9 am, they will meet each other after 6 hours of their journey. Therefore, they will pass each other at 3 pm. This is the required answer. Explanation: So, the two planes will meet 6 hours after they start, i.e. at 3 pm.

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Answer:

x = 7, x = 5

Step-by-step explanation:

\(\frac{3x+3}{8}\) = 2x - 11 ( multiply both sides by 8 to clear the fraction )

3x + 3 = 16x - 88 ( subtract 3x from both sides )

3 = 13x - 88 ( add 88 to both sides )

91 = 13x ( divide both sides by 13 )

7 = x

--------------------------------------------------------------

\(\frac{4x-6}{7}\) = 2 ( multiply both sides by 7 )

4x - 6 = 14 ( add 6 to both sides )

4x = 20 ( divide both sides by 4 )

x = 5

3x + 3 / 8 = 2x - 11

Multiply both sides by 8

8 × ( 3x + 3 / 8 ) = 8 × ( 2x - 11 )

3x + 3 = 16x - 88

Add both sides 88

3x + 3 + 88 = 16x - 88 + 88

3x + 91 = 16x

Subtract both sides 3x

3x - 3x + 91 = 16x - 3x

91 = 13x

Divide both sides by 13

91 ÷ 13 = 13x ÷ 13

7 = x

x = 7

_________________________________

4x - 6 / 7 = 2

Multiply both sides by 7

( 4x - 6 / 7 ) × 7 = 2 × 7

4x - 6 = 14

Add both sides 6

4x - 6 + 6 = 14 + 6

4x = 20

Divide both sides by 4

4x ÷ 4 = 20 ÷ 4

x = 5

Main Answer:The circumstances under which the shape of the sampling distribution of pn is approximately normal.

Supporting Question and Answer:

What is the Central Limit Theorem and how does it relate to the shape of the sampling distribution of pn?

The Central Limit Theorem states that, under certain conditions, the sampling distribution of the sample mean (or sum) approaches a normal distribution as the sample size increases, regardless of the shape of the population distribution. This theorem is applicable to the sampling distribution of pn (proportion) because the proportion can be considered as the sample mean of a binary variable (success or failure). As the sample size increases, the Central Limit Theorem ensures that the sampling distribution of pn becomes more approximately normal, making it a useful approximation for making inferences about the population proportion.

Body of the Solution:The shape of the sampling distribution of pn (proportion) is approximately normal under certain circumstances. These circumstances are related to the properties of the population being sampled and the sample size. Here are the key factors:

1.Large sample size: The sampling distribution of pn tends to become more approximately normal as the sample size increases. This is known as the Central Limit Theorem. As the sample size grows larger, the distribution of sample proportions approaches a normal distribution regardless of the shape of the population distribution.

2.Random sampling: The sample should be selected randomly from the population to ensure that each member of the population has an equal chance of being included in the sample. Random sampling helps to ensure that the sample is representative of the population.

3.Independence assumption: The sampled observations should be independent of each other. This means that the selection of one observation should not influence the selection or behavior of other observations. Independence is crucial to ensure that the sampling distribution accurately reflects the population distribution.

4.Adequate population size: If the population size is sufficiently large,

relative to the sample size, the shape of the sampling distribution of pn is approximately normal. In practice, if the population is at least 10 times larger than the sample size, this condition is considered to be met.

5.Binomial distribution approximation: The shape of the sampling distribution of pn is also approximately normal when the underlying population distribution follows a binomial distribution. The binomial distribution is characterized by a fixed number of trials and two possible outcomes (success or failure) for each trial.

Final Answer: These circumstances increase the likelihood of the sampling distribution of pn being approximately normal, it does not guarantee it in all cases. In practice, checking the normality of the sampling distribution can be done using statistical tests or graphical methods, such as a histogram or a normal probability plot.  

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The circumstances under which the shape of the sampling distribution of pn is approximately normal.

The Central Limit Theorem states that, under certain conditions, the sampling distribution of the sample mean (or sum) approaches a normal distribution as the sample size increases, regardless of the shape of the population distribution. This theorem is applicable to the sampling distribution of pn (proportion) because the proportion can be considered as the sample mean of a binary variable (success or failure). As the sample size increases, the Central Limit Theorem ensures that the sampling distribution of pn becomes more approximately normal, making it a useful approximation for making inferences about the population proportion.

The shape of the sampling distribution of pn (proportion) is approximately normal under certain circumstances. These circumstances are related to the properties of the population being sampled and the sample size. Here are the key factors:

1.Large sample size: The sampling distribution of pn tends to become more approximately normal as the sample size increases. This is known as the Central Limit Theorem. As the sample size grows larger, the distribution of sample proportions approaches a normal distribution regardless of the shape of the population distribution.

2.Random sampling: The sample should be selected randomly from the population to ensure that each member of the population has an equal chance of being included in the sample. Random sampling helps to ensure that the sample is representative of the population.

3.Independence assumption: The sampled observations should be independent of each other. This means that the selection of one observation should not influence the selection or behavior of other observations. Independence is crucial to ensure that the sampling distribution accurately reflects the population distribution.

4.Adequate population size: If the population size is sufficiently large,

relative to the sample size, the shape of the sampling distribution of pn is approximately normal. In practice, if the population is at least 10 times larger than the sample size, this condition is considered to be met.

5.Binomial distribution approximation: The shape of the sampling distribution of pn is also approximately normal when the underlying population distribution follows a binomial distribution. The binomial distribution is characterized by a fixed number of trials and two possible outcomes (success or failure) for each trial.

These circumstances increase the likelihood of the sampling distribution of pn being approximately normal, it does not guarantee it in all cases. In practice, checking the normality of the sampling distribution can be done using statistical tests or graphical methods, such as a histogram or a normal probability plot.  

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Answer:

-1.5

Step-by-step explanation:

m=-6/4

m=-3/2

-1.5

Answer:

-3/2

Step-by-step explanation:

[4-(-2)] / [1-5] = 6 / -4 = -3/2

The probability the coin lands heads on a single toss is 0.625

Let's assume that the probability of getting heads on a single toss is denoted by p.

The probability of getting 2 heads out of 7 tosses is given by the binomial distribution

P(2 heads) = (7 choose 2) × p^2 × (1-p)^5

Similarly, the probability of getting 3 heads out of 7 tosses is

P(3 heads) = (7 choose 3) × p^3 × (1-p)^4

We are given that P(2 heads) = P(3 heads), so we can set these two equations equal to each other:

(7 choose 2) × p^2 × (1-p)^5 = (7 choose 3) × p^3 × (1-p)^4

Simplifying this equation, we get

21 × p^2 × (1-p)^5 = 35 × p^3 × (1-p)^4

Dividing both sides by p^2 * (1-p)^4, we get

21/(1-p) = 35/p

Solving for p, we get:

p = 35/(21+35) = 35/56 = 0.625

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Answer:

0 8 ohms

Step-by-step explanation:

Answer: answer is 8 ohms

Step-by-step explanation:

The probability is approximately 0.6915, or 69.15%..

Given that the mean (μ) of VO₂MAX scores for men aged 20 to 29 is 42 ml/min/kg and the standard deviation (σ) is 6 ml/min/kg, we can standardize the value of 45 ml/min/kg to calculate the probability using the z-score formula: z = (x - μ) / σ.

Substituting the values into the formula,

z = (45 - 42) / 6 = 0.5

Using a standard normal distribution table or calculator, we find the probability corresponding to a z-score of 0.5 is approximately 0.3085.

To find the probability of a score greater than 45 ml/min/kg, we subtract the obtained probability from 1:

1 - 0.3085 = 0.6915

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The area of the pool increasing at the rate of 753.98 cm²/min when the radius is 5 cm

Given:

radius of the pool increases at a rate of 24 cm/min

To Find:

How quickly does the pool's area grow when the radius is 5 cm?

Solution:

we are given with the circular pool

hence the area of the circular pool =

A = πr²-----------------------------(1)

The area of the pool os increasing at the rate of 24 cm/min, meaning that the area of the pool is changing with respect to time t

so differentiating eq (1)  with respect to t , we have

dA/dt =π 2r dr/dt

we have to find  dA/dt    with  dr/dt  = 24 cm/min and  r =  5cm

substituting the values

dA/dt = π 2(5)24

dA/dt =  π 26*8

dA/dt =  π 240

dA/dt =240π

dA/dt = 753.98

The area of the pool increasing at the rate of 753.98 cm²/min when the radius is 5 cm

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Answer:

4.32

Step-by-step explanation:

Call the unknown number = x

We have: 1000x = 4320

=> x = \(\frac{4320}{1000}\) = 4.32

=> The number we need to find is 4.32

Answer:

4.32

Step-by-step explanation:

Answer:

5/6 is the simplest form

Hope that helps

The answer is (D) 10. The geometric mean between 20 and 5 is 10.

The geometric mean between two numbers can be found by taking the square root of their product. In this case, we want to find the geometric mean between 20 and 5.

The geometric mean = √(20 * 5)

Calculating the product:

20 * 5 = 100

Taking the square root of 100:

√100 = 10

Therefore, the geometric mean between 20 and 5 is 10.

The answer is (D) 10.

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a. It will take a dozen hens the same amount of time, a day and a half, to lay a dozen eggs.

The given information states that a hen and a half (1.5 hens) lay an egg and a half (1.5 eggs) in a day and a half. This implies that each hen lays 1 egg in 1 day.

Therefore, a dozen hens (12 hens) will lay a dozen eggs (12 eggs) in the same time frame, which is a day and a half.

b. It will take 9 days for 20 painters to paint 20 houses.

Given that 10 painters can paint 15 houses in 9 days, we can calculate the rate at which painters can paint houses.

This means that each painter can paint 1.5 houses in 9 days.

Therefore, to paint 20 houses, we need 20 painters, and the number of days required remains the same. So, 20 painters will also take 9 days to paint 20 houses.

c. It will take 14 days for 8 painters to paint 10 houses.

If 5 painters can paint 3 houses in 7 days, we can calculate the rate at which painters can paint houses.

This means that each painter can paint 0.6 houses in 7 days. Therefore, to paint 10 houses, we need 8 painters, and we can calculate the time required.

Hence, each painter can paint 0.6 houses in 7 days, so to paint 10 houses, 8 painters will take 14 days.

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The evaluations are as follows: a) log(15) ≈3.9. , b) log(1.8) ≈ 0.26, c) log(0.6) ≈ -0.22, d) log(√5) ≈ 0.66, and e) log(81) ≈ 4.

To evaluate the logarithmic expressions, we can use the properties of logarithms:

a) log(15) = log(3 * 5) = log(3) + log(5) ≈ 1.58 + 2.32 ≈ 3.9.

b) log(1.8) = log(18/10) = log(18) - log(10) = log(2 * 9) - log(10) = log(2) + log(9) - log(10) ≈ 0.30 + 0.96 - 1 ≈ 0.26.

c) log(0.6) = log(6/10) = log(6) - log(10) = log(2 * 3) - log(10) = log(2) + log(3) - log(10) ≈ 0.30 + 0.48 - 1 ≈ -0.22.

d) log(√5) = (1/2)  log(5) = (1/2)  2.32 ≈ 0.66.

e) log(81) = log(3^4) = 4  log(3) ≈ 4 * 1.58 ≈ 4.

Using the given logarithmic values and the properties of logarithms, we can evaluate the expressions as shown above.

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Answer:

the sequence is adding 5 the next number would be 22

hope this helps

have a good day :)

Step-by-step explanation:

7, 12, 17, 22, 27 . . .  (5n + 2)

n = 1, => 7

n = 2, => 12

n = 3, => 17

n = 4, => 22

Answer:

There were 60 kids in class.

Step-by-step explanation:

Since the kids had two choices and the ratio between them was for every 3 children that selected "Shin Chan" only 1 selected "Tom and Jerry", then in order to calculate the number of children in the class if 45 kids selected "Shin Chan", we first need to calculate the number of children that selected the other option. To do that we divide the number by 3. We have:

children(Tom and Jerry) = children(Shin Chan)/3

children(Tom and Jerry) = 45/3 = 15

Therefore the number of children in the class is:

children(class) = children(Tom and Jerry) + children(Shin Chan)

children(class) = 15 + 45 = 60

There were 60 kids in class.

Answer:

Approximately 0.1894 or 18.94% of the population is less than 10.0.

Step-by-step explanation:

On use the z-score formula and the standard normal distribution.

a. To compute the z-value associated with 14.3, we use the formula:z = (x - μ) / σWhere:

x = 14.3 (the value)

μ = 12.2 (mean)

σ = 2.5 (standard deviation)

Substituting the values:

z = (14.3 - 12.2) / 2.5

z = 2.1 / 2.5

z ≈ 0.84

Therefore, the z-value associated with 14.3 is approximately 0.84.

b. To obtain the proportion of the population between 12.2 and 14.3, we need to get the area under the standard normal distribution curve between the corresponding z-scores.

Using a standard normal distribution table or a calculator, we can find the area associated with each z-score.The z-value for 12.2 can be calculated using the same formula as in part a:

z1 = (12.2 - 12.2) / 2.5

z1 = 0 / 2.5

z1 = 0

The z-value for 14.3 is already known from part a: z2 ≈ 0.84.

Now, we obtain the proportion by subtracting the area associated with z1 from the area associated with z2:

Proportion = Area(z1 < z < z2)

Using a standard normal distribution table or a calculator, we obtain:

Area(z < 0) ≈ 0.5000 (from the table)

Area(z < 0.84) ≈ 0.7995 (from the table)

Proportion = 0.7995 - 0.5000

Proportion ≈ 0.2995

Therefore, approximately 0.2995 or 29.95% of the population is between 12.2 and 14.3.

c. To obtain the proportion of the population less than 10.0, we need to get the area under the standard normal distribution curve to the left of the corresponding z-score.Using the z-score formula:z = (x - μ) / σ

Where:

x = 10.0 (the value)

μ = 12.2 (mean)

σ = 2.5 (standard deviation)

Substituting the values:

z = (10.0 - 12.2) / 2.5

z = -2.2 / 2.5

z ≈ -0.88

Now, we obtain the proportion by looking up the area associated with z ≈ -0.88 using a standard normal distribution table or a calculator:

Area(z < -0.88) ≈ 0.1894 (from the table)

Therefore, approximately 0.1894 or 18.94% of the population is less than 10.0.

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Answer:

1, 2 and 3  (I, II and III)

Step-by-step explanation:

Since the slope is positive (3) in the equation y = 3x + 1, it means that the graph has a positive slope, meaning the line slopes up from left to right.

The y intercept is 1

the x intercept is:  

0 = 3x + 1

x = 1/3

Therefore, the graph of y = 3x + 1 lies in quadrants I, II and III.  Graph the equation to prove this.