Answer:
no se lo siento nesesito puntos
6 The pressure of 8.06 L of an ideal gas in a flexible container is decreased to
one-third of its original pressure, and its absolute temperature is decreased by
one-half. What is the final volume of the gas?
The pressure of 8.06 L of an ideal gas in a flexible container is decreased to one-third of its original pressure, and its absolute temperature is decreased by one-half and the final volume of gas is 12.09 L
The volume of gas in a flexible container is 8.06 L
The pressure is P1=X atm
Temperature is T1=YK
Let us calculate the volume V2 if Pressure P2=X/3 atm
Temperature T2=Y/2 K
Using the ideal gas equation, we get
P1V1/T1=P2V2/T2
V2=V1P1T2/T1P2
V2=8.06LX atm×Y/2K/YK.X/3 atm
V2=8.06x3/2
V2=12.09 L
The combined gas law is an amalgamation of the three previously known laws which are- Boyle's law PV = K, Charles's law V/T = K, and Gay-Lussac's law P/T = K.Applications of the combined gas law exist. This rule is applicable when the pressure, volume, and temperature are constant but the quantity of gas varies. The law can predict things like cloud formation, refrigerators, and air conditioners, for instance.To learn more about combined gas law visit:
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What percentage of energy sources are found underground
Energy sources found underground Oil, natural gas, and coal are collectively called fossil fuels.
What energy sources are found underground?sources of energy are fossil fuels formed within the Earth from dead plants and animals over millions of years—hence the name “fossil” fuels. They are established in underground layers of rock and dregs. Nonrenewable energy resources involve coal, natural gas, and oil, ... They are found in underground layers of rock and lees.
Still oil and natural gas will pursue to be the world's top two energy sources accounting for about 60 percent of global demand main energy sources are generally restricted as renewable or nonrenewable on the basis of whether they draw on an exhausted energy resource.
So we can conclude that Even today, oil, coal, and gas serve about 80 chunks of our energy source needs.
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Gold has a density of 19.3 g/cm'. Find the volume, in cubic
centimeters, of a sample of gold that weighs 0.715 kg.
Answer:
37.05 cm³
Explanation:
0.715 kg = (0.715 × 1000) g = 715g
volume = mass/density = 715/19.3 = 37.05 cm³
A certain ore is 21.3% nickel by mass. How many kilograms of this ore would you need to dig up to have 20.0 g of nickel?
If a certain ore is 21.3% nickel by mass. The number of kilograms of this ore would you need to dig up to have 20.0 g of nickel is: 93.897 kg.
How to find the mass of ore?Using this formula to determine the mass of ore
Mass of ore = Mass of nickel / Percentage of nickel by mass
Convert the percentage to decimal form by dividing it by 100
0.213 = 21.3%.
So,
Mass of ore = (20.0 g) / (0.213)
Mass of ore = 93.897 kg
Therefore the mass of ore is 93.897 kg.
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Match the Isotopes to their uses. Drag the items on the left to the correct location on the right.
chlorine-36
uranlum-238
carbon-14
cobalt-60
dating bones
dating groundwater
killing cancerous cells
analyzing rocks
Radioisotopes like Chlorine-36 is used for dating groundwater, Uranium-238 is used for analyzing rocks, Carbon-14 is used for dating bones whereas Cobalt-60 is used in killing cancerous cells.
The radionuclides of a heavy element are known as radioisotopes. They are atoms that have an unstable mix of protons and neutrons. In their nucleus, there is excess energy.
Some elements could have one or more unstable isotopes. These unstable isotopes cause gamma rays and the Alpha particles they release to decay.
Radioactive isotopes or radioisotopes are isotopes that are unstable owing to the presence of additional neutrons in their nuclei and produce different forms of radiation.
For instance: Uranium-238, Cobalt-60, Carbon-14, and Chlorine-36
Use of Radioisotopes:
(i) Cancer patients receive therapy using them.
(ii) They are used to evaluate rock formations
(iii) To date groundwater
(iv) To date bones
(v) Medical professionals utilize radioactive isotopes as "tracers" to find malignancies and blood clots in patients.
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Which carries information by copying an original sound?
Answer:
frequency
Explanation:
i just did it
Answer:
A: analog signal
Explanation:
on edge2021!
Why is ocean water near the equator warmer than ocean water at the poles?
O A. The sun's rays strike the water more directly near the equator.
O B. Deep sea vents pump steam into the conveyor belt near the
equator.
O C. The water is denser and saltier near the equator, so it holds more
heat.
D. Due to Earth's rotation, gyres near the equator flow clockwise.
SUBM
Welcome to Gboard clipboard, any text that you copy will be saEnglish Language Test
14:50
1. I don’t think the boss is very ............. to agree.
a) probable
b) likely
c) suitable
d) talkativeved here.
The most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Option B)
Based on the given context, the word that best fits the sentence is "likely."
The sentence implies that the speaker doubts the boss's willingness to agree with something. In this case, "likely" expresses the probability or possibility of the boss agreeing. It suggests that the boss is not expected to be receptive or open to the idea.
"Probable" implies a higher degree of certainty or likelihood, which may not be suitable in this context since the sentence indicates skepticism about the boss's agreement.
"Suitable" means appropriate or fitting, but it does not convey the sense of agreement or willingness.
"Talkative" refers to someone who is inclined to talk a lot, which is unrelated to the boss's agreement.
Therefore, the most suitable choice is "likely" to convey the doubt or uncertainty regarding the boss's willingness to agree. Hence option B) is correct.
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Which phrase accurately describes an elliptical galaxy?
Answer:
Elliptical galaxies are one of the three types of galaxies. They have a rounded shape of an ellipse, like a stretched-out circle. They lack the swirling arms that are a main feature of spiral galaxies.
What is the phase of water at 0.25 atm and 0°C?A. GasB. Solid and liquidC. Solid and gasD. Solid
Explanation:
We have to find the phase of water at 0.25 atm and 0°C. If we look at the phase diagram of water and throw the lines we will find that the phase of water at those conditions is solid.
Answer: d. Solid
What volume in milliliters of a 0.111 M NaOH solution is required to reach the equivalence point in the complete titration of a 12.0 mL sample of 0.132 M H2SO4?
The volume of the base that we are going to require in the process would be 28.5 mL
What is neutralization reaction?A neutralization reaction is a chemical reaction that occurs when an acid reacts with a base to form a salt and water. It is called a neutralization reaction because the resulting solution is neutral, with a pH of around 7.
We have that;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.132 * 12 * 2/0.111 * 1
VB = 28.5 mL
We are going to use the base that would have a volume of 28.5 mL
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1s22s22p 3s23p5
Which element is this
Answer:
The electron configuration 1s22s22p3s23p5
is the element Silicon.
Can somebody please help me!!
Answer:
position
Explanation:
The position of an object is its location in a space.
what is the molar mass of PbCO₄
Answer:
283.211
Explanation:
Consider the schematic nanostructure depicted below.
Which of the following statements is FALSE regarding this schematic structure?
(Do not extrapolate the field of view. Consider only what you are shown)
.
DO 0000
0
A) One of the phases present features interstitial impurities.
B) The microstructure features exactly two components and two different phases.
C) One grain boundary is depicted.
D) Only one phase boundary is depicted.
E) Each of the phases features a similar concentration of vacancies.
The microstructure features exactly two components and two different phases in the given nanostructure. Therefore, the correct option is option B.
What is phase diagram?Within physical chemistry, engineering, mining, as well as materials science, a phase diagram is a specific kind of diagram that displays the parameters at which thermodynamically different phases arise and coexist at equilibrium.
Lines of equilibrium, also known as phase boundaries, or circumstances under which different phases may coexist at equilibrium, are typical elements of a phase diagram. The microstructure features exactly two components and two different phases in the given nanostructure.
Therefore, the correct option is option B.
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How many moles of He are in a
container with a volume
of 5.6 L at STP?
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.
One mole of ideal gas has 22.4L volume at STP.
number of moles of Helium = Given volume ÷volume occupied by gas at STP
Given volume of helium = 5.6 L
Substituting all the given values, we get
number of moles of Helium = 5.6 L ÷22.4L
number of moles of Helium =0.25moles
Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
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Answer: 0.25 moles
Explanation:
Given volume of helium = 5.6 L
Substituting all the given values, we get
number of moles of Helium = 5.6 L ÷22.4L
number of moles of Helium =0.25moles
Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
What are the main parts of a simple electrie motor, like the one found inside a remote control car? O a generator, wires, and turbine magnets and coils of wire O electromagnets only
Answer:
A DC power supply, commutator, rotor armature, axle, and a field magnet.
Which is the correctly balanced equation?
A) Cl2 + 2NaI = 2NaCl + I2
B) NaOH +HCl = NaCl + H2O2
C) 2HgO = Hg + O2
D) 2Li + H2O = 2LiOH + H2
PLS HURRY, TAKING TEST, NEED HELP NOW
Answer:
A) Cl2 + 2NaI = 2NaCl + I2
What is the concentration in molarity of an aqueous solution which contains 1.41% by mass acetone (MM = 58.08 g/mol)? The density of the solution is 0.971 g/mL.
The solution's volume is 100 divided by 0.971 to get 102.98 mL. The number of moles of the solute (acetone) per litre of the solution is its molarity. Divide the mass by the molar mass to get the number of moles of acetone: 1.41 g / 58.08 g/mol = 0.0243 mol.
What is the molarity of the an aqueous solution's concentration?Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in litres, is the most widely used unit to express solution concentration: litres of solution/moles of solute equals M. One litre of a solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.
What is the concentration calculation formula?The proportion of the solute that is dissolved in a solution is indicated by the solution's concentration. This formula can be used to determine a solution's concentration: Concentration is calculated as Volume of Solute multiplied by 100 and Volume of Solution (ml).
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why do people think there are more than 2 genders?
Answer:
Because People think they can be someone else instead of themselves. They don't want to be labeled, and they don't want to be insecure.
Explanation: Just be yourself. No one else.
The enthalpy combustion of ethanol is -1430 kJ/mol. Determine heat given off from the combustion of 1 dm³ of ethanol. Given density of ethanol is 0.79 gcm³. (molar mass ethanol = 46 g/mol)
Answer:
The enthalpy of combustion of ethanol is -1430 kJ/mol, which means that for every mole of ethanol that is burned, 1430 kJ of heat is released.
To determine the amount of heat given off from the combustion of 1 dm³ of ethanol, we need to first calculate the number of moles of ethanol in 1 dm³.
1 dm³ is equivalent to 1000 cm³. Since the density of ethanol is 0.79 g/cm³, the mass of 1 dm³ of ethanol can be calculated as:
mass = density x volume
mass = 0.79 g/cm³ x 1000 cm³
mass = 790 g
To convert this mass to moles, we need to divide by the molar mass of ethanol:
moles = mass / molar mass
moles = 790 g / 46 g/mol
moles = 17.17 mol
Therefore, 1 dm³ of ethanol contains 17.17 moles of ethanol.
To calculate the heat given off from the combustion of 1 dm³ of ethanol, we can use the following equation:
heat = enthalpy of combustion x moles of ethanol
heat = -1430 kJ/mol x 17.17 mol
heat = -24,551 kJ
Therefore, the heat given off from the combustion of 1 dm³ of ethanol is -24,551 kJ, or approximately 24,551 kJ of heat is released.
HELP PLEASE PLEASE PLEASE. Can anyone tell me how to separate the following mixture
A) ethanol in water
B) boiling the mixture of chloride crystals with water
C) pure water from muddy water
D) sodium chloride in water
E) sodium carbonate in water
F) chlorophyll from leaves
G) mixture of acetic acid and alcohol
H) serum from blood sample
I) kerosene from water
J) ammonium chloride in sand
I NEED CORRECT ANSWERS ONLY.
HURRY UP PLEASE. I WILL MARK AS BRAINLIEST
A) Ethanol in water: Distillation.
B) Boiling the mixture of chloride crystals with water: Evaporation.
C) Pure water from muddy water: Filtration.
D) Sodium chloride in water: Evaporation or Crystallization.
E) Sodium carbonate in water: Filtration or Evaporation.
F) Chlorophyll from leaves: Extraction using a suitable solvent like ethanol.
G) Mixture of acetic acid and alcohol: Distillation.
H) Serum from blood sample: Centrifugation.
I) Kerosene from water: Separatory funnel or Decantation.
J) Ammonium chloride in sand: Sublimation or Dissolving in water and Filtration.
A) Ethanol in water: Distillation can be used to separate ethanol from water based on their different boiling points.
B) Boiling the mixture of chloride crystals with water: By heating the mixture, the water will evaporate, leaving behind the chloride crystals.
C) Pure water from muddy water: Filtration can be used to separate the solid particles (mud) from the water.
D) Sodium chloride in water: Evaporation can be used to separate sodium chloride from water by heating the mixture until the water evaporates, leaving behind the salt.
E) Sodium carbonate in water: Filtration can be used to separate solid sodium carbonate from water, similar to muddy water.
F) Chlorophyll from leaves: Extraction using a suitable solvent like ethanol or acetone can be used to separate chlorophyll from leaves.
G) Mixture of acetic acid and alcohol: Distillation can be used to separate the mixture based on their different boiling points.
H) Serum from blood sample: Centrifugation can be used to separate the serum, which is the liquid part of blood, from the solid components like cells.
I) Kerosene from water: Separatory funnel or decantation can be used to separate the immiscible liquids by pouring off the top layer (kerosene) from the bottom layer (water).
J) Ammonium chloride in sand: Sublimation can be used to separate ammonium chloride by heating the mixture, causing the ammonium chloride to vaporize and then condense back into solid form in a cooler region, leaving the sand behind.
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A square chunk of plastic has a length of 5 cm,
width of 5 cm, and a height of 5 cm. It has a
g. What is its density?
mass of 200
The density of plastic of length of 5 cm, width of 5 cm, and a height of 5 cm would be 1.6 gm / cm3.
In this case
The dimensions of a square chunk of plastic is 5 cm x 5 cm x 5cm.
Mass, m = 200 gm
Density = Mass / Volume
It will form a cube. Hence, the Volume = side x side x side
So ,
d = 200 gm / 5cm x 5 cm x 5 cm
d = 1.6 gm / cm3
Hence , Density is equal to 1.6 gm / cm3.
What is density explain?
Density can be defined as the mass per unit volume. Density Symbol.
Density Formula: ρ = m/V,
where ρ is the density
m is the mass of the object and V can be defined as Volume.
What is a unit of density?
It is commonly expressed in units of grams per cubic cm.
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Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this:
CaCO3(s)→CaO(s)+CO2(g)
At a certain temperature, a chemist finds that a 9.0L reaction vessel containing a mixture of calcium carbonate, calcium oxide, and carbon dioxide at equilibrium has the following composition:
Compound Amount
CaCO3 25.3 g
CaO 14.9 g
CO2 33.7 g
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.
Answer: The value of the equilibrium constant Kc for this reaction is 0.088
Explanation:
\(Molarity=\frac{x}{M\times V_s}\)
where,
x = given mass
M = molar mass
\(V_s\) = volume of solution in L
Equilibrium concentration of \(CaCO_3\) = \(\frac{25.3}{100\times 9.0}=0.028M\)
Equilibrium concentration of \(CaO\) = \(\frac{14.9}{56\times 9.0}=0.029M\)
Equilibrium concentration of \(CO_2\) = \(\frac{33.7}{44\times 9.0}=0.085M\)
The given balanced equilibrium reaction is,
\(CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)\)
The expression for equilibrium constant for this reaction will be,
\(K_c=\frac{[CaO]\times [CO_2]}{[CaCO_3]}\)
Now put all the given values in this expression, we get :
\(K_c=\frac{0.029\times 0.085}{0.028}=0.088\)
The liquid hydrogen/oxygen rocket will burn for about 8 minutes at a rate of 90,000 gallons of liquid hydrogen per minute. The density of liquid hydrogen is 70.85 g/L. How many moles of water vapor will be generated during the 8 minute burn of this rocket?
The number of moles of the water that was evaporated is 12083467.5 moles of water.
What moles of water is evaporated?We know that the number of moles that we have can be gotten as the ratio of the mass to the number of moles of the object. Now we know that from the question, we have the volume of the hydrogen to be 90,000 gallons. We have to convert this volume to liters.
Given that;
1 gallon = 3.79 L
90,000 gallons = 90,000 gallons * 3.79 L/1 gallon
= 341100 L
Then we have the density of the hydrogen to be 70.85 g/L
Mass of the hydrogen = 70.85 g/L * 341100 L
= 24166935 g
Number of moles of the hydrogen reacted = 24166935 g/2 g/mol
= 12083467.5 moles
If 2 mole of hydrogen gives 2 moles of water
12083467.5 moles of hydrogen gives 12083467.5 moles of water
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Many of these prefixes you see everyday in different applications. A good example is
computer memory. You probably have hard drives at home with gigabytes or terabytes
of storage memory. A single byte consists of 8 bits. How many bits are contained in 1
terabyte of storage.
O 8x1012
1x1012
O8x109
O 1x10-12
Answer: 8 x 10^12
Explanation:
The prefix tera means 10^12. Each byte is 8 bits, so a terabyte is 8 x 10^12 bits.
In 1 Terbyte of storage there are \(8\times 10^{12}\).
Explanation:
In in terabyte there are 1000 gigabytes1 Terabyte = 1000 Gigabyte
In megabyte there are 1000 megabytes:1 Gigabyte= 1000 Megabytes
In in megabyte there are 1000 kilobytes1 Megabytes= 1000 Kilobyte
In kilobyte there are 1000 megabytes:1 Kilobyte = 1000 Bytes
Given:
A single byte consists of 8 bits
To find:
The number of bits in 1 Terabyte of storage.
Solution:
1 Byte = 8 bits
So, in Bytes in 1 Terabyte:
\(1 terabytes= 1000\times 1000\times 1000\times 1000 Bytes=10^{12} Bytes\)
Now number of bits in \(10^{12}\) bytes:
\(1Byte=8bits\\10^{12} Bytes=10^{12}\times 8 bits=8\times 10^{12} bits\)
In 1 Terabyte of storage there are \(8\times 10^{12}\) bits.
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Many kinds of animals eat blackberries. Which of the following will most likely happen to the seeds of a blackberry plant after the fruit is eaten by an animal?
A.
The seeds will begin to grow inside the intestine of the animal.
B.
The seeds will change shape and become a new species of plant.
C.
The seeds will be ruined by the animal and will no longer be able to grow into a new blackberry plant.
D.
The seeds will be deposited in the animal's waste so that they can grow into a new blackberry plant.
Answer:
D.
Explanation:
Unlike the fruits that the animals have eaten, the seeds do not get digested and instead pass through the digestive track intact. Once the fruit is eaten by the animal the seeds will be deposited in the animal's waste so that they can grow into a new blackberry plant. The waste actually acts as a fertilizer which helps the seed grow once it falls into the ground where it can get the rest of the resources it needs to grow properly. This is one of many ways that animals help plants grow.
=> A ball of 100 g mass is thrown with a velocity of 100m/s . The wavelength of the de broglie wave associated with the ball is about...
a) 6.63 × 10-³⁵ m
b) 6.63 × 10-³⁰ m
c) 6.63 × 10-³⁵ cm
d) 6.63 × 10-³³ m
De-Broglie wavelength λ for wave association with object of mass m moving with velocity v is given by-
\(\boxed{\sf{\lambda = \frac{h}{mv}}}\)
Here, h = Planck constant( value ≈ 6.63 ×10-³⁴ joules second )
Putting Values -
λ = 6.63×10-³⁴/100×0.1
=>6.63×10-³⁴/10
=>6.63 × 10-³⁵ m
Thus, option (a) is correct.
Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K
At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
1: Write the balanced chemical equation:
\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)
2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.
Initial:
\(C_O\)(g) = 0.3500 mol
\(Cl_2\)(g) = 0.05500 mol
\(C_OCl_2\)(g) = 0 mol
Change:
\(C_O\)(g) = -x
\(Cl_2\)(g) = -x
\(C_OCl_2\)(g) = +x
Equilibrium:
\(C_O\)(g) = 0.3500 - x mol
\(Cl_2\)(g) = 0.05500 - x mol
\(C_OCl_2\)(g) = x mol
3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:
Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]
4: Substitute the given equilibrium constant (Kc) value into the expression:
1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)
5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:
1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x
6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.
7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.
8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):
\(Cl_2\)(g) = 0.05500 - x
9: Calculate the value of \(Cl_2\)(g) at equilibrium:
\(Cl_2\)(g) = 0.05500 - x
\(Cl_2\)(g) = 0.05500 - (positive value of x)
10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.
Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.
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11. The pH values of some solutions are given below pH 14.0 1.0 L 8.0 N 6.5 n P 7.0 Solution M Z (a) Identify the solution with the lowest concentration of hydrogen ion. Give reason for your (1mk) answer
Answer: 14.0
Explanation: 14.0 is a base. The more basic, the less hydrogen ion concentration.