please let me have premium i'll do something strange for a piece of change

A graph of the image after a dilation by a scale factor of 2 centered at the origin is shown below.

In Mathematics and Geometry, a dilation simply refers to a type of transformation which typically changes the size of a geometric object, but not its shape.

Next, we would apply a dilation to the coordinates of the pre-image by using a scale factor of 2 centered at the origin as follows:

Ordered pair R (0, -2) → Ordered pair R' (0 × 2, -2 × 2) = R' (0, -4).

Ordered pair S (0, 3) → Ordered pair S' (0 × 2, 3 × 2) = S' (0, 6).

Ordered pair T (2, -4) → Ordered pair T' (2 × 2, -4 × 2) = T' (4, -8).

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The total surface area is the sum of:

The Area of the rectangle on the base (36*40) = 1440 cm^2

Two triangles rectangles on the sides: 2*(36*27)/2 = 972 cm^2

One rectangle on the back of the figure: (40*27) = 1080 cm^2

And finally a inclined rectangle of base 40 and side we don't know but we can calculate: the side of this rectanlge is the hypotenuse ot the triangle rectangle of the side, so

Therefore the area of the inclined rectangle is (40*45) = 1800 cm^2

Total area = 1440+972+1080+1800 = 5292 cm^2

Answer:

5292 cm^2

Answer:

La altura del globo con respecto al suelo es 449,6 metros.

Step-by-step explanation:

La afirmación está incompleta. El enunciado completo es: "Un globo vuela entre dos ciudades A y B, que distan entre sí 1.500 m. Los tripulantes del globo ven la ciudad A con un ángulo de depresión de 27°, mientras que para ver la ciudad B es de 36°. ¿Cuál es la altura aproximada del globo con respecto al suelo?

El diagrama geométrico de la situación se encuentra descrita en el archivo adjunto. La altura aproximada del globo puede obtenerse con ayuda de las funciones trigonométricas, en este caso, se recomienda utilizar la función tangente de los ángulos de depresión:

Ciudad A

\(\tan 27^{\circ} = \frac{h}{1500\,m-x}\)

\(0,510 = \frac{h}{1500\,m-x}\)

Ciudad B

\(\tan 36^{\circ} = \frac{h}{x}\)

\(0,727 = \frac{h}{x}\)

Donde \(h\) y \(x\) son la altura con respecto al suelo y la distancia horizontal con respecto a la ciudad A.

A continuación, se elimina la altura de ambas ecuaciones por igualación y se determina la distancia horizontal del globo con respecto a la ciudad A:

\(0,727\cdot x = 0,510\cdot (1500\,m-x)\)

\(1,237\cdot x = 765\,m\)

\(x = 618,432\,m\)

Finalmente, la altura del globo con respecto al suelo es:

\(h = 0,727\cdot x\)

\(h = 0,727\cdot (618,432\,m)\)

\(h = 449,600\,m\)

La altura del globo con respecto al suelo es 449,6 metros.

Answer:

1:2

becuase it can be honestly

The value of the given sine function is √3/2, so the correct option is 2nd.

Given that an function Sin (-5π/3) we need to evaluate the expression,

To evaluate the trigonometric function sine of the angle (-5π/3), we can use the periodicity of the sine function.

Since the sine function has a period of 2, the sine of any given angle is equal to the sine of that angle plus or minus any multiple of 2.

To find an equal angle inside the main range (between -π and π), we can add 2 to the angle (-5/3).

Once adding 2:

(-5π/3) + 2π = (-5π/3) + (6π/3) = π/3

Now we can evaluate the sine of π/3, which is a commonly known angle. The sine of π/3 is √3/2.

Therefore, sin(-5π/3) = sin(π/3) = √3/2.

Hence the correct option is √3/2

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After finding the sides of the triangle using sine law, we found that the height of the flagpole is found to be 110.89 ft.

What is meant by sine law?

The law of sines specifies how many sides there are in a triangle and how their individual sine angles are equal. The sine law, sine rule, and sine formula are additional names for the sine law.

The side or unknown angle of an oblique triangle is found using the law of sine. Any triangle that is not a right triangle is referred to as an oblique triangle. At least two angles and their corresponding side measurements should be used at once for the sine law to function.

Given,

 The distance between two observers = 600 ft

The angle of elevation of the first observer = 19°

The angle of elevation of the second observer = 21°

We are asked to find the height of the flagpole.

The figure is given below.

There are 2 right triangles, ΔABD and ΔCBD.

We will start with ΔABC.

∠B = 180 - (∠A+∠C) = 180 - (21+19) = 140

Now using sine law, we can find lengths a and b.

According to sine law,

b/sin21 = a/sin 19 = 600/sin 140

From this,

b/sin 21 = 600/sin 140

b/0.36 = 933.43

b = 336.03ft

Also,

a/sin 19 = 600/sin 140

a/0.33 = 933.43

a = 308.03ft

Now using ΔABD,

sin 21  =h/a

0.36 = h/308.03

h = 110.89 ft

Therefore after finding the sides of the triangle using sine law, we found that the height of the flagpole is found to be 110.89 ft.

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Answer:

As, this question is incomplete and without data we can not answer this question. But we can make it complete by adding our own values. Let's do it and calculate.

Average Time = 23.4 minutes is the time that Mrs Brim wanted to see.

Step-by-step explanation:

As, this question is incomplete and without data we can not answer this question. But we can make it complete by adding our own values. Let's do it and calculate.

Let's suppose, there are 10 students in the class of Mrs. Brim and she took 5 tests on subsequent days and made chart to know the average time her students took to solve the test.

Total time of test = 30 minutes

Average time taken by the students to solve the test on Day 1 = 25 minutes.

Average time taken by the students to solve the test on Day 2 = 27 minutes.

Average time taken by the students to solve the test on Day 3 = 22 minutes.

Average time taken by the students to solve the test on Day 4  = 23 minutes.

Average time taken by the students to solve the test on Day 5 = 20 minutes.

Average Time in all Tests = Sum of all times / total number of days

Average Time = (25 + 27 + 22 + 23 + 20) / 5 days

Average Time = 117/5

Average Time = 23.4 minutes is the time that Mrs Brim wanted to see.

Based on the t-test assuming equal variances a. Examining the ratio of the variances, it is reasonable to conclude that the variances are unequal."

It is vital to establish whether or not the variances of the two groups being compared are indeed identical before performing a t-test under the assumption of equal variances. This is significant since the t-calculation statistic depends on the assumption that variances are equal.

One can look at the ratio of the variances between the two groups to evaluate the assumption of equal variances. Typically, it is acceptable to infer that the variances are not equal if the ratio of the variances is more than two or lower than half. One can presume that the variances are equal in the absence of such proof. Since the variances are not equal, it is not logical to infer that they are.

Complete and correct Question:

Based on the t-test assuming equal variances on the T-Test Equal worksheet, is it reasonable to assume that the variances are equal?
a. Examining the ratio of the variances, it is reasonable to conclude that the variances are unequal.
b. Whether the variances are equal or not is not relevant for this situation.
c. Examining the ratio of the variances, it is reasonable to conclude that the variances are equal.
d. It is impossible to determine if the variances are equal given the data we have.

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Answer:

(9.37, 17.7) ; (14.10, 19.42); (20.8, 22.3)

Step-by-step explanation:

For the first picture :

The missing angle :

180 - (32 + 90)

180 - (122) = 58°

To obtain the length of side x:

From ptthagoras:

Tan58° = opposite / Adjacent

1.6003345 = 15 / x

x = 15 / 1.6003345

= 9.37

y = sqrt(15^2 + 9.37^2)

y = sqrt(312.7969)

y = 17.7m

2)

Missing angle :

From ptthagoras :

Sin54° = opposite / hypotenus

0.8090169 = y/ 24

y = 0.8090169 * 24

y = 19.42

x = sqrt(24^2 - 19.42^2)

x = sqrt(198.8636)

x = 14.10

3)

Sin21° = opposite / hypotenus

0.3583679 = 8 /y

y = 8 / 0.3583679

y = 22.3

x = sqrt(22.3^2 - 8^2)

x = sqrt(433.29)

x = 20.8

Answer:

The answer would be Kevin,

Step-by-step explanation:

Kevin's trip would be the steepest because he is riding a bike, which may make him interact with hills, bumpy areas, etc.

Answer:

circle because circle does not have any edges

Answer:

\( {10}^{th} \: term = \frac{5}{512} \)

Step-by-step explanation:

geometric progression formula:

\( {n}^{th} \: term = ar ^{n - 1} \)

given:

common ratio, r = 1/2

\(first \: term \: = 5\)

1) find the value of a

\( {n}^{th} \: term \: = a {r}^{n - 1} \)

we're finding the 1st term, so substitute 1 into n:

\( {1}^{st} \: term = a( \frac{1}{2} ) {}^{1 - 1} \)

first term is 5. so we substitute 5 into the equation:

\(5 = a(1)\)

\(a = 5\)

2) find the 10th term

we're finding the 10th term, so substitute 10 into the equation and don't forget to substitute 5 into a:

\( {10}^{th} \: term = 5( \frac{1}{2} ) {}^{10 - 1} \)

\( {10}^{th} \: term = 5( \frac{1}{512} )\)

\( {10}^{th} \: term = \frac{5}{512} \)

Step-by-step explanation:

the output is 5 .........

The given values are 2,6,5,3,0,3,4,3,2,4,5,2,4

There are the following values as shown in the given data.

To find the mode first we have to assign each value that how many times it appears.

1. 2-3 the number 2 appears only Three times.

2. 6-1 the number 6 appears one time.

3. 5-2 the number 5 appears only two times.

4. 3-3 the number 3 appears only three times.

5. 0-1 the number 1 appears only one time.

6. 4-3 the number 4 appears only Three times.

So, the mode of the given data is 4,3,2 as it appears the most number of times.

If a given set of values with two modes is bimodal, a given set of numbers with three modes is trimodal, and any set of numbers with more than one mode is multimodal.

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The standard normal distribution  becomes smaller.

What is standard deviation?

As the number of degrees of freedom for a t distribution increases, the difference between the t distribution and the standard normal distribution

becomes smaller.

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The extent to which conclusions developed from data collected from a sample can be extended to the population is known as generalizability.

Generalizability is defined as the ability to extend the findings of a research study conducted on a sample to the population as a whole. The extent to which the research findings can be applied to other individuals, groups, or settings is determined by generalizability. The more representative the sample is of the population, the more generalizable the results will be to the population. However, if the sample is not representative of the population, the results may not be generalizable to the population as a whole. Therefore, it is important to ensure that the sample is representative of the population and that the study is conducted in a manner that minimizes bias and maximizes the validity of the results.

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Use one of the sets and divide them to find the proportional relationship.

3 / 43.5 = 0.06896

Now since it's not in the answer choices, you round it.

0.06896 rounded to the nearest tenths is 0.7

By solving the given equation f(x) = \(x^{2} +3x-40\), the zeroes are -3 and 5.

To solve the given equation we have to do the factorization.

What is factorization: Factorization is the method of writing numbers as the product of their factors or divisors.  In other words, we can say finding what to multiply together to get an expression.

To do the factorization, we have to follow the steps as shown below:

 \(x^{2} +3x-40\) \(= 0\)

\(-40 = 8 * -5\\\)                        [ multiplication of 8 and -5 is -40]

\(x^{2}+8x-5x -40\) \(= 0\)

\(x(x+8) -5(x+8)\) \(= 0\)

\((x-5)(x+8)\) \(= 0\)

\(x = 5\)   and  \(x = -8\)              [ The roots or zeroes]

From the above solution, we can conclude that the zeros of the given function \(x^{2} +3x-40\) are 5 and -8.

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The missing part of the equation is \(-7.0\times10^4 s^2kg⋅m^2 / 1000000.\)

To fill in the missing part of the equation, let's analyze the given information and the desired conversion. The equation is:

\((-7.0\times 10^4 s^2g⋅m^2)\cdot \pi = ? s^2kg\cdot m^2\)

In this equation, we have a quantity expressed in\(s^2g\cdot m^2\) units on the left-hand side. To convert it to \(s^2kg\cdot m^2\) units, we need to multiply it by a conversion factor.

To perform the conversion, we can use the fact that 1 kg is equal to 1000 g. Therefore, the conversion factor we need is:

1 kg / 1000 g

To ensure that the units cancel out correctly, we need to square this conversion factor because we have \(s^2g\cdot m^2\) on the left-hand side. So the missing part of the equation is:

\((-7.0\times 10^4 s^2g\cdot m^2)\cdot \pi = (-7.0\times 10^4 s^2g\cdot m^2)\cdot (1 kg / 1000 g)^2\)

Simplifying this expression, we get:

\((-7.0\times10^4 s^2g\cdot m^2)\cdot \pi = -7.0 \times10^4 s^2kg\cdot m^2 / 1000000\)

Therefore, the missing part of the equation is \(-7.0 \times 10^4 s^2kg\cdot m^2 / 1000000.\)

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Step-by-step explanation:

20 ml + 10 ml + 15 ml = 45 ml

\( \frac{15 \: ml \: of \: coconut \: milk}{45 \: ml \: total} = \frac{15}{45} = \frac{1}{3} \)

Yes, the forester was justified in using a Normal model to analyze the woods, because the histogram is unimodal and symmetric. So option A is correct.

A histogram is a type of graph that uses vertical bars to show the distribution of a set of data. This particular histogram is unimodal, meaning that it has one peak which is an indication that the data is distributed normally. Additionally, the histogram is symmetric, which is another indication that the data is normally distributed.
Using a Normal model to analyze the woods is a valid approach because it allows the forester to identify the average diameter of the trees, as well as the spread of the data. It also allows him to check for any outliers, or points that fall outside the normal range. With this information, the forester can determine if the woods is suitable for sale, or if the buyer should be aware of any unexpected features.
Overall, the histogram is an effective way for the forester to analyze the data and determine if a Normal model is appropriate. By noting the unimodal and symmetric nature of the histogram, the forester can be sure that a Normal model will accurately represent the data, allowing him to make an informed decision about the woods.

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when Justin recently bought an insurance policy with a $1,000 deductible and the $3,500 in damages from his previous week's highway rear-end collision, the total amount Justin is paying comes to $2500.

The insurance firm (the insurer) and the person(s), company, or other entity being covered have a legal agreement called an insurance policy (the insured). Reading your policy enables you to make sure that it addresses your needs and that you are aware of both your own and the insurance provider's obligations in the event of a loss.

Total amount of damage

= 3500$Total amount of insurance

= 1000$

So the total amount to be paid

= damage amount - insurance

= 3500 - 1000

=2500$

Hence the amount payable by  Justin is $2500.

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By calculating the range between the minimum value and the 25th percentile value, we can determine the approximate interval of rainfall for City A in the first quartile.

To find the approximate interval of rainfall for each city in the first quartile, we need to identify the range of values that represent the 25% percentile of precipitation. The first quartile is the value below which 25% of the data falls.

We can obtain this information by analyzing the dataset of precipitation values for each city. We calculate the first quartile by sorting the precipitation data in ascending order and finding the value at the 25th percentile. This value represents the lower boundary of the interval.

For example, if the first quartile precipitation value for City A is 1 inch and the first quartile precipitation value for City B is 0.5 inches, then the approximate interval of rainfall for each city in the first quartile is:

City A: Less than or equal to 1 inch

City B: Less than or equal to 0.5 inches

This means that 25% of the precipitation values in City A are 1 inch or less, and 25% of the precipitation values in City B are 0.5 inches or less. The interval represents the range of values within which the first quartile of rainfall falls for each city.

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Answer:

Step-by-step explanation:

tan30°=3/x

xtan30°=3

x=3/tan30°

x= 5.2

Answer:

$45

Step-by-step explanation:

so where the line intercepts the 2 hours is $45, and to find the .25 hours we take the $20 for working one hour and divide that by four, because .25 is 1/4 of an hour. so 20/4 is five. then you add 5 to 40 and we get $45 for work 2.25 hours. hope that helped