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The domain and range are the set of x and values of the function are in the table.

the function as a table,

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

What is the domain and range?

The domain and range are fundamental concepts in mathematics that are used to describe the input and output values of a function or relation.

The domain of a function refers to the set of all possible input values, or x-values, for which the function is defined.

The range of a function refers to the set of all possible output values, or y-values.

To find the domain and range of functions and represent them in different formats.

To find the domain and range of a function:

The domain refers to the set of all possible input values (x-values) for the function.

The range refers to the set of all possible output values (y-values) for the function.

To represent the function as a table, you would list the input-output pairs. For example:

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

To represent the function as a mapping, you would indicate the correspondence between the input and output values.

For example:

-3     ->   -4

-1     ->     2

0     ->     0

-3    ->     5

2     ->     4

To represent the function as a graph, The x-values would be on the horizontal axis, and the y-values would be on the vertical axis.

The points (-3, -4), (-1, 2), (0, 0), (-3, 5), and (2, 4) would be plotted accordingly.

Hence, The domain and range are the set of x and values of the function are in the table.

the function as a table,

Input (x) | Output (y)

-3         |        -4

-1          |         2

0         |         0

-3         |         5

2         |         4

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In a two-factor experiment, the expected value of the mean square for the major factor

(a) can differ depending on whether the minor factor

(b) is fixed or random.

Both parts are briefly discussed belwo.

If the minor factor (b) is fixed, it means that the levels of the minor factor are chosen by the experimenter, and they are held constant throughout the experiment.

In this case, the expected value of the mean square for the major factor (a) is calculated by dividing the sum of squares for the major factor by the degrees of freedom for the major factor.

The degrees of freedom for the major factor are equal to the number of levels of the major factor minus one.

On the other hand, if the minor factor (b) is random, it means that the levels of the minor factor are chosen randomly from a population of possible levels, and they are not held constant throughout the experiment.

In this case, the expected value of the mean square for the major factor (a) is calculated by dividing the sum of squares for the major factor by the degrees of freedom for the major factor and the degrees of freedom for the interaction between the major and minor factors.

The degrees of freedom for the interaction are equal to the product of the degrees of freedom for the major and minor factors.

The reason why the expected value of the mean square for the major factor (a) differs depending on whether the minor factor (b) is fixed or random is that in the fixed case.

The variability due to the minor factor is accounted for in the error term, while in the random case, the variability due to the minor factor is accounted for in the interaction term.

Therefore, the degrees of freedom for the major factor are different in the two cases, and this affects the expected value of the mean square for the major factor.

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Answer:

A). h = 20 w

B). m = 10.5h

Step-by-step explanation:

Part (A).

Let the total number of hours Hector worked = h

And total number of weeks worked by Hector = w

Therefore, number of hours Hector worked in a week = \(\frac{h}{w}\)

Since, total number of hours worked in a week = 20

Equation will be,

20 = \(\frac{h}{w}\)

h = 20w

Part (B).

Per hour earning of Hector = \(\frac{\text{Total earning}}{\text{Number of hours worked}}=\frac{210}{20}\)

\(\frac{m}{h}=10.5\)

m = 10.5h

The second graph, first quadrant of coordinate plane titled Marie's round of golf could represent Marie's situation.

A coordinate plane is a two-dimensional plane made up of the x-axis and y-axis, two perpendicular number lines. Using the coordinates (x, y), which stand for the horizontal and vertical distances from the origin (the point where the x- and y-axes cross), it is possible to find locations in a two-dimensional space. The first quadrant, second quadrant, third quadrant, and fourth quadrant of the coordinate plane are designated in order anticlockwise.

Given that, she stayed at the first hole for the first 30 minutes. Then she drove away from the first hole for the next 2 hours.

The situation is best described by the graph 2, first quadrant of coordinate plane titled Marie's round of golf with the x axis labeled time in hours and the y axis labeled distance in miles, with a line segment from 0 comma 0 to one half comma 0, a line segment from one half comma 0 to 2 and a half comma 5, and a line segment from 2 and a half comma 5 to 4 and a half comma 0.

Hence, the second graph could represent Marie's situation.

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Answer:

the answer is the graph shone below

i took the test and  IT WAS RIGHT  

Step-by-step explanation:

have a good day!

Answer:

6x^2 + 3x + 1

Step-by-step explanation:

( 5x^2 + 8x ) + ( x^2 - 5x + 1 )

= 5x^2 + x^2 + 8x - 5x + 1

= 6x^2 + 3x + 1

The mode of the normal distribution is x = 7

To find the mode of a normal distribution, we need to determine the value of x at which the probability density function (PDF) reaches its maximum.

In the given normal distribution, the PDF is given by y = (1/2)e^(-(x-7)^2/2).

To find the mode, we differentiate the PDF with respect to x and set the derivative equal to zero to find the critical points:

dy/dx = -(x-7)e^(-(x-7)^2/2) = 0

Simplifying the equation, we get:

x - 7 = 0

x = 7

Therefore, the mode of the normal distribution is x = 7, which is also equal to the mean of the distribution.

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This is Right answer....

Answer:

If they have the same variable you add or subtract them.

Step-by-step explanation:

Answer:

Your Answer is going to be C

The partial derivative diffusivity equation for spherical flow is ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t, and for hemispherical flow, it is the same equation.

1. The partial derivative diffusivity equation for spherical flow is derived from the spherical coordinate system and applies to radial flow in a spherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

2. The partial derivative diffusivity equation for hemispherical flow is derived from the hemispherical coordinate system and applies to radial flow in a hemispherical geometry. It can be expressed as ∂²p/∂r² + (1/r) ∂p/∂r = ϕμC/k ∂p/∂t.

1. For the derivation of the partial derivative diffusivity equation for spherical flow, we consider a spherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the polar angle (φ). By assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in spherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

2. Similarly, for the derivation of the partial derivative diffusivity equation for hemispherical flow, we consider a hemispherical coordinate system with the radial direction (r), the azimuthal angle (θ), and the elevation angle (ε). Again, assuming steady-state flow and neglecting the other coordinate directions, we focus on radial flow. Applying the Laplace operator (∇²) in hemispherical coordinates, we obtain ∇²p = (1/r²) (∂/∂r) (r² ∂p/∂r). Simplifying this expression, we arrive at ∂²p/∂r² + (1/r) ∂p/∂r.

In both cases, the term ϕμC/k ∂p/∂t represents the source or sink term, where ϕ is the porosity, μ is the fluid viscosity, C is the compressibility, k is the permeability, and ∂p/∂t is the change in pressure over time.

These equations are commonly used in fluid mechanics and petroleum engineering to describe radial flow behavior in spherical and hemispherical geometries, respectively.

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Answer:

KL = 3

Step-by-step explanation:

Point K is on line segment \overline{JL} JL .

Given:

JL=4x

JK=2x+3

KL=x

Determine the numerical length of KL .

Note that:

J-------K-------L

JK + KL = JL

Step 1

We solve for x

JL = JK + KL

4x = 2x + 3 + x

4x = 3x + 3

Collect like terms

4x - 3x = 3

x = 3

Step 2

We solve for KL

KL = x

x = 3

Hence,

KL = 3

Answer:

3

Step-by-step explanation:

It's correct

Answer:

3°C > - 2°C

Step-by-step explanation:

Ice cream 1 = - 2°C

Ice cream 2 = 3°C

Lower temperatures are colder (cooler) than higher temperature values.

Hence, ice cream at - 2°C is cooler than ice cream at 3°C.

Hence, a temperature of 3°C is higher (greater) than - 2°C. Hence - 2°C is cooler (colder) than 3°C

Hence,

3°C > - 2°C

Answer:

2.7

Step-by-step explanation:

Answer:43.289

Step-by-step explana

Answer:

E = 27.125

Step-by-step explanation:

Hope this helps you.

Answer:

e=56

Step-by-step explanation:

since the denominator is 8, what can you divide by 8 to get something that you can add to 23 and get 30.

30-23=7

56//8=7

Answer:

2450

Step-by-step explanation:

First you will divide;

200÷4=50

Then you multiply;

50×9=450

Last you add;

2000+450=2450

Hope this helps :D

Answer:

4949 is your answer

Step-by-step explanation:

The sum of the series, approximately correct to four decimal places, is 2.7183.

The given series is represented by the expression "Ë + (-1) n+1 6". To approximate the sum of this series, we can start by evaluating a few terms of the series and observing a pattern.

When n = 1, the term becomes Ë + (-1)^(1+1) / 6 = Ë - 1/6.

When n = 2, the term becomes Ë + (-1)^(2+1) / 6 = Ë + 1/6.

When n = 3, the term becomes Ë + (-1)^(3+1) / 6 = Ë - 1/6.

From these calculations, we can see that the series alternates between adding and subtracting 1/6 to the value Ë.

This can be expressed as Ë + (-1)^(n+1) / 6.

To find the sum of the series, we need to evaluate this expression for a large number of terms and add them up. However, since the series oscillates, the sum will not converge to a specific value. Instead, it will approach a limit.

By evaluating a sufficient number of terms, we find that the sum of the series is approximately 2.7183 when rounded to four decimal places. This value is an approximation of the mathematical constant e, which is approximately equal to 2.71828.

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The derivative of \( y(t) = \tan^{-1}(2t) \) is \( y'(t) = \frac{2}{1 + (2t)^2} \), representing the rate of change of \( y \) with respect to \( t \).

To find the derivative of \( y(t) = \tan^{-1}(2t) \), we can use the chain rule. The derivative of the inverse tangent function is given by the formula \( \frac{d}{dx} \tan^{-1}(u) = \frac{1}{1+u^2} \frac{du}{dx} \).

In this case, we have \( u = 2t \). Taking the derivative of \( u \) with respect to \( t \), we have \( \frac{du}{dt} = 2 \).

Substituting these values into the chain rule formula, we get \( y'(t) = \frac{1}{1+(2t)^2} \cdot 2 \).

Simplifying further, we have \( y'(t) = \frac{2}{1 + (2t)^2} \).

Therefore, the derivative of \( y(t) = \tan^{-1}(2t) \) is \( y'(t) = \frac{2}{1 + (2t)^2} \). This represents the rate of change of \( y \) with respect to \( t \).

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The sum of the cubes of the two numbers is -1.

Let's consider two numbers, denoted as x and y. If their sum is 1, we can express it as the equation x + y = 1. Similarly, if their product is 1, it can be represented as xy = 1.

To find the sum of their cubes, x³ + y³, we can use the identity (a³ + b³ = (a + b)(a² - ab + b²)). Applying this identity, we have:

x³ + y³ = (x + y)(x² - xy + y²)

Now, let's substitute the known values from the given equations:

x³ + y³ = (x + y)(x² - xy + y²)

        = (1)(x² - (1)(y) + y²)

        = x² - y + y²

Next, we express x² and y² in terms of x and y:

x² = (x + y)² - 2xy

y² = (x + y)² - 2xy

Substituting these expressions into x³ + y³ = x² - y + y², we get:

x³ + y³ = (x + y)² - 2xy - y + (x + y)² - 2xy

Considering the known values x + y = 1 and xy = 1:

x³ + y³ = (1)² - 2(1) - 1 + (1)² - 2(1)

        = 1 - 2 - 1 + 1 - 2

        = -1

Therefore, the sum of the cubes of the two numbers is -1.

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(I AM PRETTY SURE)

Answer:

The circle equals 8

The square equals 6

MEANING:

Circle = 8

Square = 6

Probability that none of the meals will exceed the cost covered by your company is 0.8863 or 88.63%

We need to use the normal distribution. Let's assume that the cost of meals follows a normal distribution with a mean of $20 and a standard deviation of $5.

The cost covered by your company is $30. To find the probability that none of the meals will exceed this cost, we need to find the probability that the cost of each meal is less than or equal to $30.

Using the standard normal distribution table or a calculator, we can find that the z-score for $30 is:

z = (30 - 20) / 5 = 2

The probability that a meal costs less than or equal to $30 is equivalent to the probability that a z-score is less than or equal to 2. This probability can be found from the standard normal distribution table or using a calculator as:

P(Z ≤ 2) = 0.9772

Probability is:

P(all meals ≤ $30) = P(Z ≤ 2)⁵ = 0.9772⁵ = 0.8863 (rounded to 4 decimals)

So, the probability that none of the meals will exceed the cost covered by your company is 0.8863 or 88.63% to four decimal places.

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Answer:

21

Step-by-step explanation:

1, 3, 7, 21

Answer:

This graph shows a function because no vertical line passes through more than one point on the graph.

Step-by-step explanation:

Given

A) The angles A and B are supplementary.

If,

B) The figure,

To find

A) The value of x.

B) The value of x.

Explanation:

A) It is given that,

Angle A and angle B are supplementary.

Then,

Hence, the error is in the statement,

Since the angles are supplementary, when added together they equal 90.

As, the correct answer is when added together they equal 180.

That implies,

Hence, the value of x is 18 degrees.

B) It is given that,

From, the figure the given angles are interior angles.

Also, the interior angles on the same side of the transversal is supplementary.

Which means when you add them they equal 180.

Hence, the error is in the statement,

Since the angles are adjacent, they are complementary angles.

Which means when you add them they equal 180.

As, the angles are interior angles on the same side of the transversal.

Also,

Hence, the value of x is 116 degrees.

First step is to write the equation in slope-intercept form

\(x - 5y = 5\\-5y = -x+5\)      To make simplification easier, multiply negative to both sides

\(5y = x-5\\\)  Now, you must divide 5 to both sides to isolate the variable

\(y = \frac{x}{5} - 1\) To tell the slope more easily, turn \(\frac{x}{5}\) into \(\frac{1}{5} x\)

To rewrite the equation: \(y = \frac{1}{5} x - 1\)

Now, you are able to see the slope(m) being \(\frac{1}{5}\)

Next, you use the formula y=mx+b to solve for b (replace your newly found slope and points "x" and "y"

\(20 = (\frac{1}{5} *-15) + b\\20 = -3 + b\\b -3 = 20\\b = 23\)

Final Answer:   \(y = \frac{1}{5} + 23\)

Hope this helps :)

The value of the expression (x != 7) && (x <= y) is: B. true

The expression is a combination of two logical conditions joined by the logical operator "&&" which means "and". The first condition "x != 7" checks if x is not equal to 7, which is true because x is 5. The second condition "x <= y" checks if x is less than or equal to y, which is also true because x is 5 and y is 7.

Since both conditions are true, the entire expression evaluates to true. The logical operator "&&" only returns true if both the conditions are true, else it will return false.

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Answer:

−5(t−3)^2+45

Ball reaches after 3 seconds

Step-by-step explanation:

took the dumb quiz

1)The vertex form of the function is \(h(t)=-5(t-3)^2+45\)

2)Time to reach maximum height is 3 seconds.

\(h(t)=-5t^{2} +30t\) which is a parabolic function.

The vertex form of a parabola is \(f(x)=a(x-h)^2+k\) where (h,k) is the vertex of the parabola. If a<0 then the maximum value of the function will be k.

So, \(h(t)=-5(t^{2} -6t)\)

h(t) can be written as:

\(h(t)=-5(t^{2} -6t+9-9)\)

\(h(t)=-5(t^{2} -6t+9) +45\)

\(h(t)=-5(t-3)^2+45\)

So, the vertex of h(t) will be (3,45)

So, the maximum height of the ball =45 m.

Time to reach maximum height = 3 seconds

Hence, 1)The vertex form of the function is \(h(t)=-5(t-3)^2+45\)

2)Time to reach maximum height is 3 seconds.

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Answer:

Could you please provide more information so I can help you with your problem?

Answer:

A) y = 2/5x^2 — 2

Step-by-step explanation:

We are given the parametric equation:

\(x=\sqrt{5t}\)

\(y=2t-2\)

To express y in terms of x, we solve for t in the first equation and substitute in the second equation.

Squaring:

\(x^2=(\sqrt{5t})^2\)

\(x^2=5t\)

Solving for t:

\(\displaystyle t=\frac{x^2}{5}\)

Substituting in the second parametric equation:

\(\displaystyle y=2\frac{x^2}{5}-2\)

\(\displaystyle y=\frac{2}{5}x^2-2\)

Correct choice: A) y = 2/5x^2 — 2

In this problem, we are given two sets V and W, and we need to determine whether they are subspaces of R². Subspaces are subsets of a vector space that satisfy certain properties.\

In this case, we need to verify if V and W satisfy these properties. After proving that both V and W are subspaces of R², we then need to show that their union V U W is not a subspace of R².

(a) To prove that V and W are subspaces of R², we need to show that they satisfy three properties: closure under addition, closure under scalar multiplication, and contain the zero vector. For V, we can see that it satisfies these properties since the sum of any two vectors in V is still in V, multiplying a vector in V by a scalar gives a vector in V, and the zero vector is included in V. Similarly, for W, it also satisfies these properties.

(b) To show that V U W is not a subspace of R², we need to find a counterexample where the union does not satisfy the closure under addition or scalar multiplication property. We can observe that if we take a vector from V and a vector from W, their sum will not be in either V or W since their components will not simultaneously satisfy the conditions of both V and W. Therefore, V U W fails the closure under addition property, making it not a subspace of R².

In conclusion, both V and W are subspaces of R², but their union V U W is not a subspace of R².

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