Please help!!
Write the equation of the line passing through (2,3) and perpendicular to y = 2/3 x + 7.

In this problem, and in general statistics, z represents the standard score of the data.

This standard score is the number of standard deviations that there are above or below a sample.

We have the mean: 173.38 cm

and the standard deviation: 8.78 cm

We first determined the standard score for the tallest living man:

We obtain the difference between this sample and the mean:

Then we calculate how many standard deviations are in this difference:

Then the standard score for the tallest living man is 9.87

We need to do the same to the shortest living man:

Remember that if the sample is minor than the mean we take the absolute value.

Then the standard score:

Then the standard score for the shortest living man is 7.38

The height that was more extreme is the height that has a standard score major, then we can conclude:

The standard score for the tallest living man is 9.87

The standard score for the shortest living man is 7.38

And the height that was more extreme is the tallest living man's height

Answer:

B because I had learned this at school.

Answer:

length = 13

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Step-by-step explanation:

the distance is 2500 m = 2.5 km, which we have to change into miles by using the factor of 1.6.

so, 2.5 km / 1.6 = 1.5625 miles.

or in fractions

5/2 / 16/10 = 5/2 / 8/5 = 5/2 × 5/8 = 25/16 = 1 9/16 miles

Adam drove these 1.5625 miles in 102 seconds.

to get mph we need to transform 102 into 3600 (seconds in an hour).

102x = 3600

x = 3600/102 = 1800/51 = 600/17 = 35.29411765...

(25/16 / 102) × (600/17 / 600/17) =

(25×600 / 16×17) / (102×600 / 17) =

(25×75 / 2×17) / (6 × 600) = (1875 / 34) / 3600 =

55.14705882.../1 hour = 55.14705882... mph

a) Adam was driving 55 mph.

b) now we have to calculate backwards.

he would drive 50 miles in 3600 seconds, so, how many seconds for 25/16 miles ?

the factor is

50 / 25/16 = 50/1 × 16/25 = 50×16 / 25×1 = 2×16 = 32

he drove only 1/32 of the 50 miles.

so, now we need to divide 3600 by 32

3600 / 32 = 225/2 = 112.5 seconds

rounded it should have taken him at least 113 seconds.

Answer:

46 i think because 20+26 is 46

Labor content (labor dollar per unit) is the total cost of labor required to produce one unit of a product. It can be calculated by dividing the total labor cost by the number of units produced.

In this scenario, we are given that an employee produces 17 parts during an 8-hour shift and earns $109 per shift.

To calculate the labor content, we first determine the labor cost per hour. This is done by dividing the total amount earned in the 8-hour shift by 8.

Labor cost per hour = $109 ÷ 8 = $13 per hour

Next, we calculate the number of parts produced per hour by dividing the total number of parts produced (17) by the duration of the shift (8 hours).

Parts produced per hour = 17 ÷ 8 = 2.125 parts per hour

Finally, we calculate the labor cost per part by dividing the labor cost per hour by the number of parts produced per hour.

Labor cost per part = $13 ÷ 2.125 = $6.12 per part

Therefore, the labor content (labor dollar per unit) of the product is $6.12 per part.

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\(b^3b^3=b^{3+3}=b^{\boxed{6}}\).

Hope this helps.

Answer & Step-by-step explanation:

2. Total income = Income from first r rows + Income from other last rows  

[(Price per first r rows' seat ) x (no of first r rows) x (no of seats per first r row) ] + [ (Price per other last rows' seat ) x (no of last rows) x (no of seats per last row) ]

= [ 20 x (r) x (no of seats per first r row) ] + [ 15 x (other last ie 'total - r' rows) x no of seats per last row

3. 20 x 16 x (no of seats per first r row) = 320 x (no of seats per first r row)

4. 15 x (other last ie 'total - 16' rows) x no of seats per last row

Therefore , the solution to the problem of percentage is valid and comes out to be p = 2%.

In terms of a fraction of 100, a percentage is a quantity or ratio. Always place the percent symbol (%) after the percentage number or ratio number. Different fields use percentage in different ways. It is frequently used in finance and accounting for things like taxation, sales, and profit margins.

Here,

The sample is objective because random sampling is only done every 50th phone. With a set item interval for the sample size, this is a systematic random sampling.

Thus, 4 of the 200 phones examined have defects. Use the percent calculation to determine what proportion of phones are defective.

Compose the % equation, part by part.

Replace the values in the provided problem.

Suppose p = %

4 = p. 200

4 = 200p

Divide each side by 200 to obtain p.

4/200 = 200p /200

0.02 = p

Decimal to percent conversion: multiply by 100 to get p = 0.02100 p = 2%

Therefore , the solution to the problem of percentage is valid and comes out to be p = 2%.

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Answer:

42

Step-by-step explanation:

fir a 100% is missing 40

divide 28 by 4 and then multiply by 6

Answer:

42 students

40%

72 (end of number line)

Explanation:

How to find the percentage for the 28 students:

100% - 60% = 40%

Knowing that, we now know 28 = 40%. We need to figure out what 10% is equal so we can figure out what 60% is equal.

How to find 10%:

28 ÷ 4 = 7

10% = 7 students

How to find 60% of students:

10 · 6 = 60

7 · 6 = 42

With that information, we can find out the final sum.

40% + 60% = 100%

28 + 42 = 72.

Answer:

y= \(\frac{3x}{4}\) + \(\frac{1}{4}\)

you first find the gradient of the line by picking out any two coordinates then u fill the values in the equation of a line

The dimensions of diameter of the circle is 6 inches which Jessa used to draw her circle.

The circumference of a circle is stated by the formula -

C = 2πr, where r refers to radius of the circle. Calculating radius now.

18.84 = 2πr

Rewriting the equation for radius of circle

r = 18.84/2×3.14

Performing division on Right Hand Side of the equation

r = 3 inches

As known, diameter is double the radius. Hence, diameter of the circle = 2×3

Performing multiplication on Right Hand Side of the equation

Diameter of the circle = 6 inches

Thus, the correct answer is A 6.

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The complete question is -

9.Jessa drew a circle with a circumference of 18.84 inches. Which of these dimensions could be the diameter, in inches Jessa used to draw her circle? Use 3.14 for pi.

A 6

B 15.7

C 3

D 9.42

The angle is 25 degrees

Let the measure of the angle be x

So, we have

Complement = 90 - x

Supplement = 180 - x

The sum is 220

So, we have

90 - x + 180 - x= 220

Evaluate the sum

-2x + 270 = 220

Solve for x

x = 25

Hence, the angle is 25 degrees

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The residual of the line of fit, along with the interpretation, is given as follows:

−2.2; The line of best fit overpredicts the temperature change.

For a data-set, the definition of a residual is that it represents the difference of the actual output value by the predicted output value, that is:

Residual = Observed - Predicted.

The observed value for this problem is given as follows:

20.7.

The predicted value is taken from the line of fit, as follows:

y = 0.6(23) + 9.1 = 22.9.

Then the residual is given as follows:

Residual = 20.7 - 22.9 = -2.2, meaning that the line of fit overpredicts the temperature change.

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The larger hospital to more closely match the population value

The binomial distribution, is a probability distribution that describes the number of successes (in this case, female births) in a fixed number of independent trials (in this case, the number of babies born in a week) when the probability of success is constant (in this case, 0.5).

Use the expected value of the binomial distribution to calculate the number of female births we expect in each hospital in a week, assuming that the probability of a baby being female is 0.5.

Here we have

Akron ohio is served by two hospitals.

In the larger hospital, about 50 babies are born each day, and in the smaller hospital, about 25 babies are born each day in the U.S about 50% of all babies born are girls.

Here can use the binomial distribution to calculate the expected number of female births in each hospital in a week, assuming that the probability of a baby being female is 0.5.

For the larger hospital, we expect 50 x 7 to be born in a week.

Hence, the expected number of female births = 0.5 x 350 = 175.

For the smaller hospital, we expect 25 x 7 to be born in a week.

Hence, the number of female births is therefore 0.5 x 175 = 87.5.

Since the expected number of female births in the larger hospital is closer to the population value of 50%, we expect the larger hospital to more closely match the population value.  

Therefore,

The larger hospital to more closely match the population value

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The equation of the circle into the standard form will be (x + 7)² + (y + 15)² = 1.

It is the close curve of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

Let r be the radius of the circle and the location of the center of the circle be (h, k). Then the equation of the circle is given as,

(x - h)² + (y - k)² = r²

The area of the circle is 9π. Then the radius of the circle is given as,

A = π

πr² = π

r² = 1

The center of the circle is at (-7, -15). Then the equation of the circle is given as,

(x + 7)² + (y + 15)² = 1

The equation of the circle into the standard form will be (x + 7)² + (y + 15)² = 1.

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Answer:

The rock hits the ground between 2 seconds and 2.5 seconds after it is dropped

Step-by-step explanation:

The given table is presented as follows;

\(\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}\)

Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.

Answer:

  2

Step-by-step explanation:

Corresponding sides are proportional in these similar triangles.

__

  short side/long side = k/4 = 4/8

  k = 4(4/8) . . . . multiply by 4

  k = 2

_____

Additional comment

The lengths of the hypotenuses can be found the same way, or using the Pythagorean theorem. Using side ratios, we have ...

  l² = k(k+8) = 2(10) = 20 . . . . from MN/MO = ML/MN

  l = 2√5

  m² = 8(8+2) = 80 . . . . from LN/LO = LM/LN

  m = 4√5

The similarity statements are ...

  ΔLMN ~ ΔLNO ~ ΔNMO

Answer:

5

Step-by-step explanation:

G.C.F means greatest common factor

this means the highest number that will go into both 25 and 40

5 is the highest number that will divide into both

Answer:

ion know

Step-by-step explanation:

The red line is where seven is located on the graph and the red shaded area above it is all the possible values of y that are less than 7.

The value of horizontal thrust can be calculated using the following formula;  F_h= 1/2Pcot(a) Where P is the total load applied on the dome P = 1.5 kN/m.Cot a = 1.88F_h= 1/2 × 1.5 × 1.88= 1.41 kN/m Let us calculate the weight of the dome (W). W = unit weight of reinforced concrete × volume of the dome= 25 × t × [(π/6)(R³ + r³) + π Rr (H/2)] Where, R = base radius = 15 m, r = top radius = 14.925 m and H = total height of the dome= 3.75 m, t = thickness of the dome= 75 mm (0.075 m)π = 3.14W = 25 × 0.075 × [(π/6)(15³ + 14.925³) + π × 15 × 14.925 × (3.75/2)]= 1170 kNThe total horizontal force can be given as the sum of half the weight of the dome and the horizontal thrust. F = 1/2 W + F_h= 1/2 × 1170 + 1.41= 588 + 1.41= 589.41 kN The thickness of the ring beam can be calculated as follows; F/2 = [(π/4) (D² - d²) × f_c] + [A_s (f_y/γ_s) - A_p (f_p/γ_p)]Where, D = external diameter of the ring beam, d = internal diameter of the ring beam.f_c = permissible compressive stress in concrete at transfer = 14 N/mm²f_y = characteristic strength of reinforcement steel = 460 N/mm²γ_s = partial safety factor for reinforcement = 1.15A_s = area of reinforcement steel = (π/4) × (5 mm)² = 19.63 mm²/mf_p = initial prestressing force per unit length of wire= 1000 N/mm²A_p = area of the high tensile wire used for prestressing the ring beamγ_p = partial safety factor for prestressing steel = 1.05(1 - 0.75) = 0.25D - d = 0.3 mF/2 = [(π/4) (D² - d²) × f_c] + [A_s (f_y/γ_s) - A_p (f_p/γ_p)]589.41/2 = [(π/4) (D² - d²) × 14] + [19.63 × (460/1.15) - (π × 5²/4) × (1000 × 0.25)]294.705 = [(π/4) (D² - d²) × 14] + 241.509 - 245.04425.2405 = (π/4) (D² - d²) × 14+ D - d = 0.3 mD = d + 0.3∴D² - d² = (D - d) (D + d) = 0.3 × D25.2405 = (π/4) × 14 × 0.3 × D + 0.3 × D= 5.2665 D= 5.2665/0.3= 17.555 mLet us take the thickness of the ring beam as 300 mm (0.3 m).

Then the external diameter of the ring beam is given by;D = d + 0.3 m= 17.555 + 0.3= 17.855 mArea of steel required for the ring beam can be given as follows; A_s = [F/2 - {(π/4) (D² - d²) × f_c}]/[f_y/γ_s]= [294.705 - {(π/4) × 14 × 0.3 × 17.855²}]/[460/1.15]= 1609.7 mm²/m We can provide 4Nos. of T16 bars for effective reinforcement. Hence area provided, A_p = 4 × 201= 804 mm²/m Prestressing force per meter of high tensile wire, f_p= initial prestressing force per unit length of wire × loss ratio= 1000 × 0.75= 750 N/mm²A_p/f_p = length of high tensile wire required= 804/750= 1.072 m/mLet us take the vertical spacing of wire as 200 mm and the initial sag of the wire as 20 mm. The length of the wire required along the curve of the ring beam can be given as follows;L_c = 2πR/cos a = 2 × 3.14 × 15/0.8823= 106.78 m The length of the wire required can be given as follows;L = √((L_c/2)² + (H + S)²)= √((106.78/2)² + (3.75 + 0.2)²)= 53.4 m The number of wires required can be given as follows; N = (L × 1000)/S= (53.4 × 1000)/200= 267Nos.As per the design procedure, the design of reinforced concrete dome and the prestressed concrete ring beam is completed.

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The equation that match the table attached is

B. y = -5(2⁻ˣ) + 4

By analyzing the given equations we can see that option B match the table and this is shown below

Using calculator to set the equation shows that

for x = -2

y = -5(2⁻ˣ) + 4 = 2.75

for x = -1

y = -5(2⁻ˣ) + 4 = 1.5

for x = 0

y = -5(2⁻ˣ) + 4 = -1

for x = 1

y = -5(2⁻ˣ) + 4 = -6

Based on the comparison, the equation that corresponds to the table is:

OB.y = -5(2⁻ˣ) + 4

Therefore, the correct option is OB.

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An easy way to start a graph is by finding two points for the slope, and then a single point for the intercepts.

The two points I'll use are (0, 80) and (1, 120) (Keep in mind, you can use any two points, they'll all give you the rame ratio).

Use the slope equation:

\(b = \frac{(y_2-y_1)}{(x_2-x_1)} \\b=\frac{(120-80)}{(1-0)} \\b=\frac{40}{1} \\b=40\)

Now that we have our slope, we can use one of the points (I'll just use (0, 80)) to create the equation.

\(y-y_1=b(x-x_1)\\y-80=40(x-0)\\y-80=40x\\y=40x+80\)

So your final equation is y=40x+80.

* To solve for that second question, just plug in 10 for x and you should get the cost!

A gull can fly at a speed of 22 miles per hour i.e. equal to 116,160feett/hour and An AMTRAK train travels at 125 miles per hour i.e. equal to 2.1 miles/minute

Given that 1)A gull can fly at a speed of 22 miles per hour and asked to convert its units to  foot/hour

2)An AMTRAK train travels at 125 miles per hour and is asked to convert its units to  miles/minute

1 mile=5280 feet

22 miles/hour=22 × 5280 foot/hour

22 miles/hour=116,160 foot/hour

1 hour=60 minute

125 miles/hour= 125/60 miles/minutes

125 miles/hour= 2.083 miles/minutes≈ 2.1miles/minutes

Therefore, A gull can fly at a speed of 22 miles per hour i.e. equal to 116,160 feet/hour and An AMTRAK train travels at 125 miles per hour i.e. equal to 2.1 miles/minute

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The set of integers is closed under the operation of addition because the sum of any two integers is always another integer and is therefore in the set of integers.

What are integers ?

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14, .

According to the Property of Closure, A set has the closure property under a particular operation if the result of the operation is always an element in the set.  If a set has the closure property under a particular operation, then we say that the set is “closed under the operation.”

Hence ,  the set of integers is closed under the operation of addition because the sum of any two integers is always another integer and is therefore in the set of integers.

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The angle labelled ? is calculated using the sum of angles in a straight line to be 85 degrees

The sum of angles in a straight line is 180 degrees

starting from the straight line by the left, let the required will be x in each case

115 + x = 180

x = 180 - 115

x = 65 degrees

solving for the angles in the triangle

65 + 85 + y = 180

y = 180 - 65 - 85

y = 30 degrees

30 + 90 + z = 180   (angles on a straight line)

z = 180 - 90 - 30

z = 60 degrees

155 + a = 180 (angles on a straight line)

a = 180 - 155

a = 25 degrees

solving for the angles in the triangle

z + a + b = 180

60 + 25 + b = 180

b = 180 - 60 - 25

b = 95 degrees

b + ? = 180  (angles on a straight line)

? = 180 - 95

? = 85 degrees

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Answer:

96 cm^2

Step-by-step explanation:

The triangle can be split into 2 6-8-10 triangles, each with area 24. The bottom parallelogram area is base times height, or 8 * 6, so 48. 24 + 24 + 48 is 96.

An inequality that can be written in the form ax + by < c (where a and b are not both zero) is called a linear inequality in two variables.

An inequality that represents a line in a two-dimensional coordinate system is referred to as a linear inequality. The set of points that satisfies the inequality is a half-plane bounded by a line that may be dashed or solid.

In contrast to a linear equation, which represents a line, a linear inequality represents a half-plane. The points on one side of the line, rather than the points on the line, are solutions to the inequality.

The method of shading is used to graph a linear inequality in two variables. First, graph the boundary line, which is usually represented by a solid or dashed line, and then select a test point on one side of the line. Shaded regions of the half-plane containing the test point satisfy the inequality.

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The task is to determine the combination of dollars, dimes, and pennies that adds up to $3.25 while using the fewest number of bills and coins.

To find the combination of bills and coins that adds up to $3.25 with the fewest number of units, we need to consider the denominations of dollars, dimes, and pennies. Since we want to minimize the number of bills and coins, it makes sense to use the highest denomination first. In this case, a dollar bill is the highest denomination. We can start by subtracting as many dollar bills as possible from $3.25 until the remaining amount is less than a dollar.

Next, we can move on to dimes, which have a value of 10 cents. We want to use the fewest number of dimes, so we'll subtract as many dimes as possible from the remaining amount until the value is less than 10 cents. Finally, we can use pennies, which have a value of 1 cent, to make up the remaining amount. Again, we want to use the fewest number of pennies possible. To find the specific combination, we can go through a step-by-step process:

Start with $3.25.

Subtract one dollar bill ($1) from $3.25, leaving $2.25.

Subtract two dimes (2 x $0.10 = $0.20) from $2.25, leaving $2.05.

Subtract four pennies (4 x $0.01 = $0.04) from $2.05, leaving $2.01.

Subtract two dollars ($2) from $2.01, leaving $0.01.

The remaining $0.01 cannot be broken down further using the given denominations. Therefore, the fewest combination of bills and coins that adds up to $3.25 is 1 dollar bill, 2 dimes, and 4 pennies.

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