PLEASE HELP!

what would the answer be?

Answer:

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

Explanation:

The volume flow rate of the blood in the artery can be given by the following formula:

\(V = Av\)

where,

V = Volume flow rate = ?

A = cross-sectional area of artery = πd²/4 = π(0.004 m)²/4 = 1.26 x 10⁻⁵ m²

v = velcoity = 0.28 m/s

Therefore,

\(V = (1.26\ x\ 10^{-5}\ m^2)(0.28\ m/s)\)

V = 3.5 x 10⁻⁶ m³/s = 3.5 cm³/s

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

The diagram that shows the greatest magnitude net torque with a zero net force is the diagram in second option.

option B is the correct answer.

The net torque is the sum of the individual torques. The torque itself is obtained from the product of applied force and the perpendicular distance of the force.

In rotational equilibrium, there is no net torque on the object. There may be individual torques, but they add up to zero and cancel each other out.

Mathematically, the formula for torque is given as;

τ = Fr

where;

The torque applied to an object increases with increase in the perpendicular distance.

To obtain a zero net force, sum of all the opposite forces applied to an object must be equal to zero.

The forces must be equal in magnitude but opposite in direction, and the diagram that meets this specification is the last graph.

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Answer:

3.0 m/s²

Explanation:

Given:

v₀ = 8.0 m/s

v = 14 m/s

t = 2.0 s

Find: a

v = at + v₀

14 m/s = a (2.0 s) + 8.0 m/s

a = 3.0 m/s²

The mass of the picture is approximately 5.19 kilograms.

The deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).

The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:

τ = G * γ

To find the weight of the picture, we need to calculate the shear stress first:

The cross-sectional area A of the nail is given by the formula for the area of a circle:

A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².

The shear strain γ is given by:

γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.

The shear stress τ can now be calculated by rearranging the formula:

τ = G * γ

=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²

The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:

τ = F / A

=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.

Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:

m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.

So, the mass of the picture is approximately 5.19 kilograms.

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Explanation:

The work that leads towards the open mindness of people without any discrimination that contribute to a moral development is positive work

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

Vb = 0.334 m/s

Va = -1.265 m/s

Vc = 1.424 m/s

Explanation:

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Initial momentum = 255(2) – 242.5(1.5) = 146.25

Final momentum = 255Va + 290Vb + 242.5 Vc = 146.25

Vb - Va = 0.8(2) = 1.6

Vc - Vb = 0.8(1.5) = 1.2

Va = Vb -1.6

Vc = Vb + 1.2

255(Vb -1.6) + 290Vb + 242.5(Vb + 1.2) = 146.25

255 Vb – 408 + 290 Vb + 242.5 Vb + 291 = 146.25

787.5 Vb = 263.25

Vb = 0.334 m/s

Va = Vb -1.6 = 0.334 – 1.6 = -1.265 m/s

Vc = Vb + 1.2 = 0.224 + 1.2 = 1.424 m/s

Answer: a . it decreases

Explanation:

Answer:

0.610m/s^2

Explanation:

Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.

Answer:

1/2mv²=0

1/2(4kg)(v²)=0

2=-v²

square root -2=v

v=1.414

Block A of mass 1 kg and block B has a mass of 3 kg, then the blocks collide and stick together so the kinetic energy of block A is one-third of the kinetic energy of the block.

Kinetic energy is a type of power that an item or particle possesses as a result of motion. When an item undergoes work—the transfer of energy—by having subject to a net force, it accelerates and consequently obtains kinetic energy. An object in motion or particle's kinetic energy, which depends on both mass and speed, is one of its features. Any combination of motions, including translation, rotation about an axis, and vibration, may be used as the type of motion.

A body's translational kinetic energy is equal to 1/2mv², or one-half of the sum of its mass, m, and the square of its velocity, v.

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An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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i) The initial deceleration of the car is -1.6 m/s² and  the time taken is 5 seconds

ii) The final deceleration is -1 m/s²

iii) The total dispalcement = 1016 m

The initial deceleration of the car is given by the formula below:

v² = u² + 2as

where;

Solving for a;

12² = 20² + 2 * a * 80

a = -1.6 m/s²

Time taken, t = v - u / a

t = 12 - 20 / (-1.6)

t = 5 seconds

Final deceleration:

a = v - u / t

a = 0 - 12 / 12

a = -1 m/s²

iii) Displacement at constant velocity = 12 * 1 * 60

Displacement at constant velocity = 720 m

Final displacement, s = ut + 0.5at²

s = 12 * 12 + 0.5 * 1 * 12²

s = 216 m

Total dispalcement = 80 + 720 + 216

Total dispalcement = 1016 m

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Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

The speed of the puck is 3.67 m/s.

To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.

Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:

= m1 * v^2 / R

where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.

For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:

T = m2 * g

where g is the acceleration due to gravity.

Combining these two equations, we can solve for the speed of the puck:

v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)

Substituting the given values, we get:

v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s

Therefore, the speed of the puck is 3.67 m/s.

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The net force on particle q₁ is approximately +25.6 N.

The electrostatic forces between particle q1 and the other two particles, q2 and q3, must be taken into account in order to determine the net force on particle q1. Coulomb's Law describes the electrostatic force between two charged particles:

F = k * |q₁ * q₂| / r²

F is the force, k is the electrostatic constant (9 x 109 N m2/C2), q1 and q2 are the charges' magnitudes, and r is the distance separating them.

Let's first determine the force between q1 and q2:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9 x 10^9 N m²/C²) * |(-29.6 μC) * (+37.7 μC)| / (0.630 m)²

F₁₂ = (9 x 10^9 N m²/C²) * (29.6 x 10^-6 C) * (37.7 x 10^-6 C) / (0.630 m)²

F₁₂ ≈ -7.45 N

The absence of a positive sign suggests an attractive force between q1 and q2.

Let's next determine the force between q2 and q3:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9 x 10^9 N m²/C²) * |(+37.7 μC) * (-10.8 μC)| / (0.315 m)²

F₂₃ = (9 x 10^9 N m²/C²) * (37.7 x 10^-6 C) * (10.8 x 10^-6 C) / (0.315 m)²

F₂₃ ≈ +33.05 N

The presence of a positive sign suggests a repulsive force between q2 and q3.

We must now add all the forces in order to determine the net force on q1:

Net force = F₁₂ + F₂₃

Net force ≈ -7.45 N + 33.05 N

Net force ≈ +25.6 N

The presence of a positive sign implies that the net force is pointing to the right, in the same direction as particle q2.

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To determine the speed of B when A and B pass each other, we need to first gather information about their initial velocities, relative speeds, and direction of motion.

The speed of A is given and we need to find the speed of B. The formula for relative speed can be used, which states that the relative speed of two objects is equal to the sum of their individual speeds when they are moving in the same direction, and the difference of their speeds when they are moving in opposite directions. In this case, if A and B are moving in opposite directions, then their relative speed is equal to the speed of A plus the speed of B.

It is important to note that the speed of B must be expressed in the same unit as the speed of A (e.g. miles per hour) to allow for accurate comparison and calculation. Once the relative speed is known, it can be used to determine the speed of B by solving for it algebraically. The answer should be a numerical value in miles per hour.

It is also important to take into consideration any external factors that may affect the motion of the objects such as friction, air resistance, and changes in direction or speed. These factors can impact the accuracy of the calculation and should be accounted for if possible.

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Answer:

C the metal handle because it is a good conductor

Answer:

D.

Explanation:

Although the metal handle will last longer, if heated up enough it could burn her hand.

(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Answer:206.3

Explanation:

The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms

The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

With the above formula, we can obtain the value of R₂. Details below:

Rₜ = (R₁ × R₂) / (R₁ + R₂)

2 = (6 × R₂) / (6 + R₂)

2 = 6R₂ / (6 + R₂)

Cross multiply

2 × (6 + R₂) = 6R₂

Clear bracket

12 + 2R₂ = 6R₂

Collect like terms

12 = 6R₂ - 2R₂

12 = 4R₂

Divide both sides by 4

R₂ = 12 / 4

R₂ = 3 ohms

Thus, we can conclude that the value of R₂ is 3 ohms

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When a transverse wave passes from a flexible spring into a heavier stiffer spring, the wave will have a greater speed in the stiffer spring due to the increased stiffness of the material. As a result, when the wave reaches the end of the stiffer spring, some of the energy from the wave will be reflected back towards the flexible spring.

The reflected wave in the flexible spring will be inverted, meaning that it will be flipped upside down. Additionally, the amplitude of the reflected wave will depend on the amount of energy that was transmitted into the stiffer spring.

If a large amount of energy was transmitted, then the reflected wave will have a higher amplitude. Conversely, if only a small amount of energy was transmitted, then the reflected wave will have a lower amplitude.

Overall, the reflected wave in the flexible spring will experience a change in both its orientation and amplitude due to the transmission and reflection of the initial wave in the stiffer spring.

When a transverse wave passes from a flexible spring into a heavier, stiffer spring where the wave has a greater speed, the reflected wave in the flexible spring will have a reduced amplitude and undergo a phase change of 180 degrees, resulting in an inverted waveform.

This occurs due to the impedance mismatch between the two springs, causing part of the wave energy to be reflected and part to be transmitted.

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The vector characteristics of the electric field allow to find the result for the electric field at the point of interest is;

Given parameters.

    1) Electric charges:

    2)Charge positions

   3) Points of interest r = (0,0,1) = 1 \(\hat k\)  

To find.

the electric field at point r.

The intensity of the electric field is given by the ratio of the electric force to the positive test charge at the point of interest.

          \(E= k \frac{q}{r^2 }\)  

where E is the electric field, k the constant of Coulomb, q the charge and r the distance.

In the attached we see a diagram of the test charges and the distance to the point of interest on the z axis.

The total field is the vector addition of the fields created by each charge

          \(E_{total} = E_1 +E_2\)

Let's look for the components of each electric field.

Field created by charge q₁

          tan θ = \(\frac{z}{x}\)  

          tan θ = 1/1 = 1

          tea = 45º

x-axis

          cos 45 = \(\frac{E_{1x}}{E_1}\)

z axis

          sin 45=  \(\frac{E_{1z}}{E_1}\)  

          E₁ₓ = E₁ cos 45

          \(E_{1z}\)  = E₁ sin 45

Field created by load 2

y-axis

        cos 45 = \(\frac{E_{2y}}{E_2}\)  

z- axis

        sin 45 = \(\frac{E_{2z}}{E_2}\)  

        \(E_{2y}\) = E2 cos 45

        \(E_{2z}\) = E2 sin 45

We look for the components of the total electric field, where the signs are taken from the direction of the vectors in the attached.

    \(E_{total} = - E_{1x} \hat i + E_{2y} \hat j + ( E_{1z} - E_{2z} ) \hat k\)

Let's substitute.

         \(E_{total } = - E_1 cos 45 \hat i + E_2 cos 45 \hat j + (E_1 sin 45 - E_2 sin 45) \hat k\)

Let's find the distance for each charge to the test point using the Pythagorean Theorem.

         r₁₃² = x² + z²

         r₁₃² = 1 + 1

         r₁₃² = 2

         r₂₃² = y² + z²

         r₂₃² = 1² + 1²

         r₂₃² = 2

Let's look for the magnitud of the electric fields.

Charge q₁

        \(E_1 = k \frac{q_1}{r_{13}^2}\)  

        E₁ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₁ = 20 N / m

Charge q₂

        \(E_2 = k \frac{q_2}{r_{23}^2}\)  

        E₂ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₂ = 20 C / N

Let's substitute in the expression of the total eletric field.

         \(E_{total} = -20 \ cos45 \ \hat i + 20 \ cos 45\ \hat j + ( 20 -20) sin 45 \ \hat k\)

         \(E_{total} = 14.1 ( - \hat i + \hat j) \ \frac{N}{C}\)  

In conclusion using the vector characteristics of the electric field we can find the result for the electric field at the point of interest is;

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During a short time, the air resistance acting on Nellie indeed exceeds the force of gravity and produces a momentary negative net force and negative acceleration.

This acceleration decreases her forward velocity but does not change its direction.

The change of speed continues until the air resistance builds up to the point where it is equal to the force of gravity, which stops the further change of speed.

The rate of change of displacement is known as velocity.

The rate at which velocity changes is called acceleration.

Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. Being the rate at which velocity changes, acceleration is likewise a vector quantity.

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The horizontal components of its launch velocity is 75.07m/s when a projectile is launched from the edge of a cliff.

Given mass of projectile (m) = 0.55kg

initial kinetic energy (KE1) = 1550J

displacement of projectile from launch pad (s) = 145m

The vertical component of velocity disappears at the point of maximum height, where y=140m, but the horizontal component stays the same as when the object was launched (if we neglect air friction).

Its kinetic energy at that moment is KE = 1/2mv^2

1550 = 1/2x0.55xv^2

v = 75.07m/s

Hence the horizontal components of its launch velocity = 75.07m/s

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Answer:

As the charge increases, the force decreases in strength

Explanation:

Experiments with electric charges have shown that if two objects each have electric charge, then they exert an electric force on each other. The magnitude of the force is linearly proportional to the net charge on each object and inversely proportional to the square of the distance between them...

Answer: The correct answer is: As the charge increases, the force increases in strength

Explanation:

Its kind of the obvious answer and other people don't know how to answer correctly. This was years ago but if anyone needs the answer today then here it is....

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The volume of the blocks has no bearing on the speed in the inclination plane. Even if the block's mass is doubled, the acceleration won't change..

When the angle rises, the physical viewpoint of view component of the incline decreases and awareness to the incline increases. The contemporaneous constituent of the force vector causes the acceleration. Accelerations are hence greater at steeper inclination degrees.

All variables in the movement equation for the mass on an air track are inversely correlated with mass since the normal force, like mass and drag, is determined by the weight of a sliding item. Hence, the speed at which an object slides along a plane shouldn't depend on its mass.

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