Please help will give brainliest please

The sales price of the item after deduction of percentage discount is: $18

The regular price is defined as the price at which similar goods or services are regularly sold on the market.

The discount is defined as an amount or perhaps percentage deducted from the normal selling price of something.

The sales price is defined as the actual amount for which a good is sold after deduction of discount if any.

The parameters given are:

Regular Price = $20

Percentage Discount = 10%

Thus:

Discount = 10% * 20

Discount = $2

Thus:

Sales Price = $20 - $2

= $18

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c)17

Step-by-step explanation:

Answer:

I believe it is 3?

Step-by-step explanation:

Answer: D (3)

Step-by-step explanation:

Edge2020

Answer:

0.5

Step-by-step explanation:

4 is in the tenths place and 6 is in the hundredths place

Since the digit in the hundredths place (6) is greater than or equal to 5, add 1 to the digit in the tenths place (4)

1 + 4 = 5, so the digit in the tenths place becomes 5

The digit in the hundredths place is dropped

0.46 rounded to the nearest tenth (one decimal place) = 0.5

Answer:

the answer is D

Step-by-step explanation:

y=\(x^{2}\)+1

Answer:A

Step-by-step explanation:

It is a solid line and the area below is shaded so it has to be less than the slope, hope this helped!

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Answer:

Its A because you find the slope, -1/3 which is followed by x.  The x intercept is 1 so you do plus one.  Because the line is solid and negative, it makes it a less-than equal to sign.  Hope this helps at all!

Step-by-step explanation:

Total number of people 400 started at the beginning. To calculate the percentage, divide the value by the total value and multiply the result by 100.

Therefore,

Percentage of students dropped = 3%

Number of people dropped this year= 12

To find Total students = (12/3) * 100 = 400

That is to find how many people dropped is = 400 *(3/100) = 12

so we  can rearrange the  formula .

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Answer:

45

Step-by-step explanation:

g of x = g of 4

4 is the x

so 6(4) +21 is 24 + 21 which = 45

Answer:

-3

Step-by-step explanation:

a) The probability mass function of X is 0.0083

b) The modified p.m.f. of X, under this new situation is 0.1007

The probability of getting k red marbles and 5-k blue marbles on 5 draws without replacement is given by:

P(k red, 5-k blue) = (12 choose k) x (10 choose 5-k) / (22 choose 5)

where the binomial coefficients are the same as before, but the denominator is now the total number of ways to choose 5 marbles from a set of 22 marbles, without replacement.

Using this formula, we can find the probability of each value of X, as we did before:

P(X = -5) = P(0 red, 5 blue)

P(X = -5) = (12 choose 0) x (10 choose 5) / (22 choose 5) = 0.0083

The modified probability mass function of X, under this new situation is calculated as,

P(X = -3) = P(1 red, 4 blue) + P(0 red, 5 blue)

P(X = -3) = (12 choose 1) x (10 choose 4) / (22 choose 5) + (12 choose 0) x (10 choose 5) / (22 choose 5) = 0.1007

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(a) The percentage of SAT verbal scores that are less than 625 can be determined by finding the area under the normal distribution curve to the left of 625.

To do this, we need to standardize the value of 625 using the formula z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation.

Using the given values:

x = 625

μ = 510

σ = 124

Calculating the z-score:

z = (625 - 510) / 124

z = 1.01

Next, we consult the standard normal table to find the cumulative probability associated with the z-score of 1.01. Looking up the value in the table, we find that the cumulative probability is approximately 0.8431.

To convert this probability to a percentage, we multiply it by 100:

Percentage = 0.8431 * 100

Percentage ≈ 84.31%

Therefore, approximately 84.31% of SAT verbal scores are less than 625.

(b) To estimate the number of SAT verbal scores that would be greater than 525 out of a random sample of 1000 scores, we can use the mean and standard deviation of the distribution. The proportion of scores greater than 525 can be approximated by finding the area under the curve to the right of 525.

Using the given values:

x = 525

μ = 510

σ = 124

Calculating the z-score:

z = (525 - 510) / 124

z = 0.12

We consult the standard normal table again to find the cumulative probability associated with the z-score of 0.12. The table shows that the cumulative probability is approximately 0.5480.

To estimate the number of scores greater than 525 out of a sample of 1000, we multiply the probability by the sample size:

Number of scores = 0.5480 * 1000

Number of scores ≈ 548

Therefore, we would expect approximately 548 out of 1000 SAT verbal scores to be greater than 525.

(a) approximately 84.31% of SAT verbal scores are less than 625, and (b) we would expect about 548 out of 1000 SAT verbal scores to be greater than 525.

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The final grade you will have using a mixture word problem is 85%.

The mixture word method or mixture word problem is a method in mathematics to solve the problem when creating a mixture of two or more different things. This method will solve the problem of determining the quantity of mixture result.

In the question, we will mix two grades. So,

= (current grade * current worth grade) + (final exam grade * final exam worth grade)

= (85% * (100%-10%)) + (85% * 10%)

= 76.5% + 8.5%

= 85%

Thus, your final grade doesn't change if you get 85% on a final exam.

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The researcher should use a sample size of approximately 312 middle school students to conduct the research.

To determine the sample size needed for the researcher to create a 95% confidence interval with a margin of error of 0.5 days, we can use the formula:

\(\[ n = \left(\frac{Z \cdot \sigma}{E}\right)^2 \]\)

Where:

- \(\( n \)\) is the sample size

- \(\( Z \)\) is the z-score corresponding to the desired confidence level (for 95% confidence, Z is approximately 1.96)

- \(\( \sigma \)\) is the known standard deviation of the population

- \(\( E \)\) is the desired margin of error

Plugging in the values, we get:

\(\[ n = \left(\frac{1.96 \cdot 4.5}{0.5}\right)^2 \]\)

To solve the equation for the required sample size, we can substitute the given values into the formula:

\(\[ n = \left(\frac{1.96 \cdot 4.5}{0.5}\right)^2 \]\)

Calculating this expression gives us:

\(\[ n = \left(\frac{8.82}{0.5}\right)^2 \]\)

\(\[ n = (17.64)^2 \]\)

\(\[ n \approx 311.1696 \]\)

Therefore, the researcher should use a sample size of approximately 312 middle school students to conduct the research.

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(a) System (a) is causal and stable.

(b) System (b) is causal and stable.

(c) System (c) is causal but unstable.

(d) System (d) is non-causal and unstable.

To determine causality, we need to check if the impulse response h[n] is non-zero only for non-negative values of n. If h[n] = 0 for n < 0, the system is causal.

(a) For system (a), h[n] = ()"u[n]. Here, h[n] is non-zero only for n ≥ 0, which satisfies the condition for causality. Therefore, system (a) is causal.

(b) For system (b), h[n] = (0.8)"u[n+2]. Here, h[n] is non-zero only for n+2 ≥ 0, which implies n ≥ -2. Hence, the system is causal.

(c) For system (c), h[n] = ()"u[n]. In this case, h[n] = 0 for n < 0, satisfying the condition for causality. However, the impulse response is unbounded as n → ∞ since ()"u[n] does not decay with increasing n. Therefore, system (c) is unstable.

(d) For system (d), h[n] = (5)"u[3 - n]. Here, the impulse response is non-zero for n > 3, violating the condition for causality. Hence, system (d) is non-causal.

To determine stability, we need to check if the impulse response h[n] is absolutely summable, i.e., ∑|h[n]| < ∞. If the sum is finite, the system is stable.

(a) For system (a), ()"u[n] is a geometric series that converges to a finite value for all n. Therefore, system (a) is stable.

(b) For system (b), (0.8)"u[n+2] is also a geometric series that converges to a finite value. Hence, system (b) is stable.

(c) For system (c), the impulse response ()"u[n] does not converge as n → ∞ since it does not decay. Therefore, system (c) is unstable.

(d) For system (d), (5)"u[3 - n] is also an unbounded sequence as n → ∞. Thus, system (d) is unstable.

(a) System (a) is causal and stable.

(b) System (b) is causal and stable.

(c) System (c) is causal but unstable.

(d) System (d) is non-causal and unstable.

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Answer:

Step-by-step explanation:

it is a

The correct missing statement and the reason is NP = NO + OP by Segment Addition Property

Given: MONP

Prove: MN = OP

The Segment Addition Property states that,

When three locations A, B, and C are on the same line and point B is located between points A and C, the length of the line segment AC is equal to the sum of the lengths of the three line segments AB and BC.

In mathematical notation, this property can be represented as:

AB + BC = AC

Statements                                                  Reasons

1. MO = NP                                                     1. Given

2. MO = MN+ NO                                     2. Segment Addition Property

3. NP = NO + OP                                      3. Segment Addition Property

4. MN+NO = NO+ OP                              4. Substitution Property

5. MN = OP                                              5. Subtraction Property of Equality

Hence the correct option is 2nd.

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Answer:

B.punctuality of payments

Step-by-step explanation:

sana matulong

The coordinates of the vertices of the preimage, given that the scale factor is 1/2, would be A. (0, 0) ( 0, 10 ) ( -8, 4)

To find the coordinates of the preimage, take the coordinates of the larger triangle.

The reason for this is simply that the scale factor is a fraction and when the scale factor of a dilation is less than 1, the resulting image would be smaller than the preimage.

The larger triangle is therefore the preimage as the scale factor is 1/2 and the coordinates of the vertices would be (0, 0) ( 0, 10 ) ( -8, 4).

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The greatest common factor (GCF) of the expression 12x^3y, 6x^2y^2, and -9xy^3 is 3xy, and factoring out this GCF yields 3xy(4x^2 - 2xy - 3y^2).

To factor the GCF, we need to identify the common factors present in all the terms. In this case, the common factors among the terms are 3, x, and y. By factoring out the GCF, we can rewrite the expression as 3xy multiplied by the remaining factors.

The GCF, 3xy, is then distributed to each term within the parentheses. This process leaves us with the expression (4x^2 - 2xy - 3y^2) within the parentheses. By factoring out the GCF, we have effectively extracted the common factors, leaving behind the remaining factors that differ from term to term.

Thus, the correct factorization of the GCF is 3xy(4x^2 - 2xy - 3y^2), where the GCF 3xy has been factored out, and the remaining factors are contained within the parentheses.

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Total stockholders’ equity 7,800,000

Statement of stockholders’ equity for CC for the year ended December 31, 2012:Particulars Amount ($)
Common Stock 100,000

Additional Paid-in Capital 4,100,000
Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
Total stockholders’ equity 7,800,000

Explanation:The given information is as follows:Common Stock on January 1, 2012 = $100,000Additional Paid-in Capital on January 1, 2012 = $4,100,000

Retained Earnings on January 1, 2012 = $3,000,000Net Income for the year ended December 31, 2012 = $800,000Cash Dividend Declared on July 1 and paid on July 31 = $200,000

To prepare the statement of stockholders’ equity for the year ended December 31, 2012, we will begin by preparing the opening balances of each of the equity accounts. We will then add the net income to the retained earnings account.

The closing balance for retained earnings is then computed by subtracting the cash dividend declared and paid from the total retained earnings. Finally, the total stockholders' equity is calculated by adding the balances of all the equity accounts.

Calculations:Opening balance of common stock = $100,000

Opening balance of additional paid-in capital = $4,100,000

Opening balance of retained earnings = $3,000,000

Net Income for the year ended December 31, 2012 = $800,000

Retained earnings (Opening Balance) = $3,000,000

Add: Net Income for the year ended December 31, 2012 = $800,000

Total retained earnings = $3,800,000Less: Cash Dividend Declared on July 1 and paid on July 31 = $200,000Retained earnings (Closing balance) = $3,600,000

Total stockholders’ equity = Common Stock + Additional Paid-in Capital + Retained Earnings (Closing balance) = $100,000 + $4,100,000 + $3,600,000 = $7,800,000

Therefore, the statement of stockholders’ equity for CC for the year ended December 31, 2012, is as follows:Particulars Amount ($)
Common Stock 100,000
Additional Paid-in Capital 4,100,000

Retained Earnings (Opening Balance) 3,000,000
Add: Net Income for the year ended December 31, 2012 800,000
Total retained earnings 3,800,000

Less: Cash Dividend Declared on July 1 and paid on July 31 (200,000)
Retained earnings (Closing balance) 3,600,000
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It is most important to have a random sample in inferential statistics, particularly in making statistical inferences about a population based on the sample data.

Random sampling is a critical component of inferential statistics because it helps to ensure that the sample is representative of the population. When a sample is randomly selected, each member of the population has an equal chance of being included in the sample, which reduces the risk of bias in the results. Without a random sample, the results of statistical analyses may not be accurate or generalizable to the population, and the conclusions drawn from the data may be flawed or misleading.

Therefore, random sampling is crucial in making valid statistical inferences about a population.

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The required solution to the equation 2x - 4 = 6 is x = 5.

Given equation: 2x - 4 = 6

To solve for x, we can add 4 to both sides of the equation:

2x - 4 + 4 = 6 + 4

Simplifying:

2x = 10

Finally, divide both sides of the equation by 2:

2x/2 = 10/2

x = 5

Therefore, the solution to the equation 2x - 4 = 6 is x = 5.

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Answer:

choice c has a value of .9, so c

Step-by-step explanation:

i hope this helps

Answer:

D.

Step-by-step explanation:

Because its three times as much as 42 so its opposite of multiplication so its division with is also 3x=42 and to solve that you divide 3x by 3 and just get x then you divide 42 and 3 and u get your answer( im not gonna do the math lol)

Answer:

x∈R

Step-by-step explanation:

\(y=2^{x}\)

2>0

The domain is all real numbers.

x∈R

A modified version of the original distribution, the sampling distributive of y(1) has an upper bound equal to the minimum value in the sample and a lower bound of 0.

Let y1,..., yn have an f-distribution and be independently and identically distributed (iid) (y).

Ascertain the y(1) = min I yi sampling distribution. The sampling distribution of y(1) has a lower bound of 0 and an upper bound that is equal to the minimum of the sample yi. It is a truncated distribution of the original distribution f(y).

By integrating the initial distribution f(y) from 0 to the minimum of the sample yi, get the probability of each value of y(1).

A reduced version of the original distribution f(y), with a lower bound of 0 and an upper bound equal to the minimum of the sample yi, is the sampling distribution of y(1). We must integrate the initial distribution f in order to calculate this distribution (y)

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the answer to 40 divided by 180 is 4.5

we have the following:

solving for b:

therefore, the answer is 16

Answer: b=16

Step-by-step explanation: The file

Answer:

what is this lol its not a question

Step-by-step explanation:

The solution of the quadratic equation is x=5±√35 .

A quadratic equation is given by the equation which can be written in the form ax²+bx +c.

the given quadratic equation is :

x²-10x+25=35

Simplifying the equation we get:

or, x²-10x+25-35=0

or, x²-10x-10=0

Now we will solve the equation by completion squares method:

x²-10x-10=0

or, x²-2×x×5+5²-5²-10=0

or, (x-5)²=35

or, x-5=±√35

or, x= 5±√35

Therefore the solution of the quadratic equation is 5+√35 and 5-√35 .

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Answer:

1 1/8

Step-by-step explanation:

3/4= 0.75

2/3 = 0.666666667 so on...

divide and you get 1.125 which is also written as 1 1/8