Answer:
the answer is A . Disruption to electricity power grid :)
Explanation:
In a class experiment to determine information about free-fall acceleration, a watermelon and a pumpkin are each set to fall from the back of the stands at your football stadium.
a. If the watermelon and the pumpkin are both dropped at the same time, which one will hit the ground first?
b. If the watermelon is thrown downward with an initial speed of 10 m/s and the pumpkin is dropped, which one will hit the ground first? Show calculation to support your answer.
c. If it takes the watermelon 1 second to reach the ground when it is thrown downward at 10 m/s, how tall are the stands?
d. How long does it take the pumpkin to reach the ground if it is dropped from this height you calculated in part c?
Answer:
a) They both hit the ground at the same time
b) Watermelon will hit first, since its speed is faster than the pumpkin speed
c) h = 29,6 m
d)t = 3,02 sec
Explanation:
Equations for fall free movement are:
vf = v₀ + g*t when v₀ = 0 (dropped case) vf = g*t
h = v₀*t + 1/2*g*t²
a) For both ( watermelon and pumpkin) the equation of speed is the same:
vf = g*t² Both will have the same speed second through second
They both hit the ground at the same time
b) Now is watermelon is thrown with v₀ = 10 m/s
Watermelon will hit first since its speed is faster than the pumpkin speed
vf(watermelon) = 10 + g*t
vf₂ (pumpkin) = g*t
c) h = v₀*t + (1/2)*g*t²
h = (10)*1 + (1/2)*9,8*1
h = 10 + 19,6
h = 29,6 m
d) h = g*t
t = 29,6/9,8
t = 3,02 sec
Assume you are a trainer at a local gym. There is evidence that intense or exhaustive physical exercise can increase the production of free radicals. Antioxidants can be used to combat the damage caused by free radicals. One of your competitive athletes has heard bits and pieces of this information and asks you more about it. How would you counsel him?
Use language that the average person will understand, respond to this athlete and be sure to include the following information as a part of your response:
What is meant by oxidation and why can it be damaging to cells?What are free radicals?Why do we produce free radicals if they can damage my body?What are antioxidants? How do antioxidants combat free radicals?What foods are high in antioxidants?Should your friend buy an antioxidant supplement?
5 points
15. *
15. Which one of the following
quantities is NOT a vector?
A velocity
B acceleration
C distance
D displacement
A
B
С
Answer:
distance is not a vector. it is scalar
Consider the figure below, with three links, each with the specified transmission rate and link length. +Link 1 Link 2 +Link 3 Transmission rate: 10 Mbps Link Length: 2 km Transmission rate: 1000 Mb Link Length: 2 km Transmission rate: 10 Mbps Link Length: 500 km Find the end-to-end delay (including the transmission delays and propagation delays on each of the three links, but ignoring queueing delays and processing delays) from when the left host begins transmitting the first bit of a packet to the time when the last bit of that packet is received at the server at the right. The speed of light propagation delay on each link is 3x108 m/sec. Note that the transmission rates are in Mbps and the link distances are in Km. Assume a packet length of 8000 bits. Give your answer in milliseconds.
Each link's speed of light propagation latency is 3x108 meters per second. Assume a 4.2 millisecond packet duration of 8000 bits.
What is the light's speed?The speed of light, a known physical constant with a frequency of 299,792,458 kilometers per second, is the rate at which electromagnetism moves through a vacuum.
How do we impact the speed of light?Everything would be slowed if the speed of the light were to be decreased, and just as in a moving picture, you wouldn't perceive it. Therefore, altering this same speed of light wouldn't change anything.
For Link 1,
Propogation Delay = (3 * 103) / (3 * 108)
= 0.00001 seconds
Transmission Delay = (120000) / (100 * 106)
= 0.0012 seconds
For Link 2,
Propogation Delay = (500 * 103) / (3 * 108)
= 0.001666667 seconds
Transmission Delay = (120000) / (1000 * 106)
= 0.00012 seconds
For Link 3,
Propogation Delay = (1 * 103) / (3 * 108)
= 0.000003333 seconds
Transmission Delay = (120000) / (100 * 106)
= 0.0012 seconds
Thus, total delay
= 0.00001 + 0.0012 + 0.001666667 + 0.00012 + 0.000003333 + 0.0012
= 0.0042 seconds
= 4.2 milliseconds
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Mona said, "I think that, when there is no lid, convection is the main way that
energy escapes from the water."
Has she drawn a good conclusion from her results? Explain your ideas
Mona's conclusion that convection is the main way that energy escapes from the water when there is no lid may or may not be a good conclusion, depending on the context and information provided.
Convection is a process of heat transfer that involves the movement of fluids (in this case, the water) due to differences in temperature. It occurs when warmer portions of the fluid rise and cooler portions sink, creating a circulating flow.
To determine if Mona's conclusion is valid, additional information is needed. Factors such as the presence of other heat transfer mechanisms (such as radiation or evaporation), the specific setup of the experiment, and the conditions under which the observations were made are essential.
If Mona's experiment only considered convection as the primary mechanism for energy escape and excluded other factors, her conclusion might be incomplete or inaccurate. To draw a more comprehensive conclusion, it is necessary to consider other potential heat transfer mechanisms and perform further investigations or provide additional supporting data.
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The diameter of 0-gauge copper wire is 8.252 mm. Find the resistance of a 1.00-km length of such wire used for power transmission.
Answer:
The value is \(R = 0.321 \ \Omega\)
Explanation:
From the question we are told that
The diameter is \(d = 8.252 \ mm = 0.008252 \ m\)
The length of the wire is \(l = 1.0 \ km = 1000 \ m\)
Generally the cross sectional area of the copper wire is mathematically represented as
\(A = \pi * \frac{d^2}{4}\)
=> \(A = 3.142 * \frac{ 0.008252^2}{4}\)
=> \(A = 5.349 *10^{ - 5} \ m^2\)
Generally the resistance is mathematically represented as
\(R = \frac{\rho * l }{A }\)
Here \(\rho\) is the resistivity of copper with the value \(\rho = 1.72*10^{-8} \ \Omega \cdot m\)
=> \(R = \frac{1.72 *10^{-8} * 1000 }{5.349 *10^{ - 5} }\)
=> \(R = 0.321 \ \Omega\)
A ball is dropped off a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window what is the distance from the top of the building to the top of the window?
draw diagram of how a reflecting telescope works. show how the angles of reflection would work with mirrors placed at 2 different angles
Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.
What is Telescope?Curved mirrors are used by the majority of telescopes nowadays to collect light from the night sky. Light is focused by a telescope's mirror or lens' shape.
Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky.
The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light. The "optics" of a telescope are the mirrors or lenses. Strong telescopes may view objects that are extremely faint and incredibly far away.
Therefore, Lenses, which are pieces of curved, clear glass, were employed in early telescopes to focus light.
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help please Derive an equation
Ta=1.44T1/2
Explanation:
To derive an equation you must indicate the variable you want to solve for.
Here we have tension of an object A and Tension 1.
Two variables or unknown are given hence we cannot derive any other equations.
A block of wood
wood, with mass 1.34 kg rests stationary
on horizontal ground.
The coefficient of Kinetic
friction between the block and the ground is 0.966.
A bullet, with mass 0.250kg, moving horizontally
hits and sticks into the block of wood. We find
that the speed of the block of wood, with the
ballet embedded in it, just after collision is 11.9 m/s.
A) calculate the speed of the bullet before hitting the block of wood.
it, just after the collision
is 11-9mis.
as calculate the speed of the bullet before
s
hitting the block of wood.
Answer:
Explanation:
conservation of momentum
m(u) + M(0) = (m + M)v
u = (m + M)v/m
u = (0.250 + 1.35)(11.9) / 0.250
u = 76.16
u = 76.2 m/s
That's a fairly massive, and slow, bullet.
A piece of clay flies off a pottery wheel and sticks to a potter walking by.
The initial momentum of the clay was 3.0 kg.
m
and the initial
m
momentum of the potter was -85 kg
kg.
FUSORE
ku
m
PREDME
S
-
What is the final momentum of the artist-clay system immediately after
the collision?
Your answer should have two significant figures.
S
The final momentum of the artist-clay system immediately after collision is -82 kgm/s.
How to calculate final momentum?Assuming that the initial momentum of the clay was 3.0 kgm/s and the initial momentum of the potter was -85 kgm/s, we can use the law of conservation of momentum to find the final momentum of the artist-clay system immediately after the collision:
Initial momentum = Final momentum
(3.0 kgm/s) + (-85 kgm/s) = Final momentum
-82 kg×m/s = Final momentum
Therefore, the final momentum of the artist-clay system immediately after the collision is -82 kgm/s.
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A 109 kg softball player slides across the ground and comes to a stop. Her average acceleration while she stops is -0.737. Calculate the magnitude of the stop force.
Answer:96.1
Explanation:
Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if it flies past you at a speed of u=0.75c?
The spaceship from Part A has a large clock attached to its side. This clock ran at the same rate as your watch when you were in the same reference frame. How much time ?t will pass on your watch as 80 s passes on the clock attached to the ship?
If the captain of ship A fires a missile, counts 10.0 s on his watch, and then fires a second missile, how much time ?t will the captain of ship B measure to have passed between the firing of the two missiles?
The captain of ship B knows that ship A uses 2-m-long missiles. She measures the length of the first missile, once it has finished accelerating, and finds it to be only 0.872 m long. What is the speed u of the missile, relative to ship B?
Answer:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
Explanation:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
A rocket is launched straight up with a speed of 12 meters per second near the surface of Earth. [Neglect air friction.]
Answer:
Explanation:
H = V² / (2·g)
H = 12² / (2·9.8) ≈ 7,3 m
Answer:
By conservation of energy,
Kinetic energy of launched rocket = change in potential energy of rocket at maximum height.
→ Ig h is maximum height reached:
A cart of mass M is on a level, horizontal track. The cart is attached to one end of an ideal spring, and the other end of the spring is attached to a vertical support. The spring has a spring constant k. The cart is pulled to the right, stretching the spring a distance d, as shown above, and released from rest at time t = 0. The cart-spring system begins to oscillate, and the position x of the cart as a function of time t is given by the equation x(t) = d cos(ωt) , where x is in meters, ω is in rad/s , and t is in seconds. Assume the mass of the cart’s wheels to be negligible.
(a) Derive an equation for the velocity of the cart v as a function of time t .
(b) On the axes below, sketch a graph of the velocity v of the cart as a function of time t for two complete oscillations. On the graph, T represents the time for one complete oscillation. Explicitly label asymptotes, maxima, or minima with algebraic expressions, as appropriate.
(c) Express all answers in part (c) in terms of ω, t, M, d, k, and physical constants, as appropriate.
i. Determine an expression for the kinetic energy K of the system as a function of time t.
ii. Determine an expression for the potential energy U of the system as a function of time t.
iii. Using the equations from parts (c)i and (c)ii, show that the rate of change of the total energy of the system dE/dt is zero.
Two springs identical to the spring above are attached to each side of the cart of unknown mass M, as shown in Figure 1 above. The cart is on a level, horizontal track of negligible friction. A piece of clay is added to the top of the cart so that it will stick to the cart. The cart is displaced to the left a distance d and released from rest, as shown in Figure 2 above. The period of oscillation is recorded. This procedure is repeated for several different pieces of clay of different masses. In each trial, the cart is displaced the same distance d. The data are shown below on the linear graph of T2 as a function of mC , where T is the period of oscillation and mC represents the mass of the clay.
(d) From the graph, determine the following.
k, the spring constant of each spring
M, the mass of the cart
(e) The experiment is repeated, but in a second set of trials, the cart is pulled back a distance D, where D > d . Describe any changes that will occur for the straight line on the graph in part (d).
Justify your answer.
An equation for the velocity of the cart v as a function of time t is v(t) = -dw sinwt
What is velocity?Velocity, a physical entity quantifying the rate at which an object alters it's location over a precise duration, stands as a vector quantity with both magnitude and direction.
Conventionally expressed in meters per second (m/s) or equivalent units of stretch distance versus duration, average velocity is worked out by partitioning an object's displacement over the time taken to complete said displacement. The formula for the same is quite simple:
Average Velocity = Displacement / Duration
Wherein, Displacement reflects the alteration in position of an object, and span denotes the interval consumed during that change.
Check the attachment.
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*10) A horizontal force of 7N is pushing an object to the left and a second force of
12N is applied at an angle of 30% below the horizontal. The resultant horizontal force on the object is?
A) 13.8 to the right
B) 19N to the left
C) 3.4 to the right
D) 1N to left
Identify the processes that are necessary for continued growth and division in a normal body cell
Please hurry!
-Thank you
Answer:
In a normal body cell, the processes that are necessary for continued growth and division is referred to as cell cycle. Cell cycle is the procedure by which cells divide and grow, consisting of specific step by step phases. INTERPHASE is the phase in which the dividing cells spends most of the time resting as it grows to prepare for cell division.
You are at the controls of a particle accelerator, sending a beam of 2.10×107 m/s protons (mass m) at a gas target of an unknown element. Your detector tells you that some protons bounce straight back after a collision with one of the nuclei of the unknown element. All such protons rebound with a speed of 1.80×107 m/s. Assume that the initial speed of the target nucleus is negligible and the collision is elastic.
A) Find the mass of one nucleus of the unknown element.
B) What is the speed of the unknown nucleus immediately after such a collision?
Answer:
a
The mass is \(m_2 =21.75*10^{-27} \ kg\)
b
The velocity is \(v_2 = 3.0*10^{6} m/s\)
Explanation:
From the question we are told that
The speed of the protons is \(u_1 = 2.10*10^{7} m/s\)
The mass of the protons is \(m\)
The speed of the rebounding protons are \(v_1 = -1.80 * 10^{7} \ m/s\)
The negative sign shows that it is moving in the opposite direction
Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as
\(m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1\)
Where \(m_1\) is the mass of a single proton
So substituting values
\(m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1\)
\(m_2 =13 m_1\)
The mass of on proton is \(m_1 = 1.673 * 10^{-27} \ kg\)
So \(m_2 =13 ( 1.673 * 10^{-27} )\)
\(m_2 =21.75*10^{-27} \ kg\)
Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as
\(m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2\)
Now \(u_2\) because before collision the the nucleus was at rest
So
\(m_1 u_1 = m_1 v_1 + m_2v_2\)
=> \(v_2 = \frac{m_1(u_1 -v_1)}{m_2}\)
Recall that \(m_2 =13 m_1\)
So
\(v_2 = \frac{m_1(u_1 -v_1)}{13m_1}\)
=> \(v_2 = \frac{(u_1 -v_1)}{13}\)
substituting values
\(v_2 = \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}\)
\(v_2 = 3.0*10^{6} m/s\)
a farmer grows a bushel of wheat and sells it for $1. the miller turns the wheat into flour and then sells the flour to a baker for $3. The baker uses the flour to make bread and sells the bread to an engineer for $6. the engineer eats the bread. What is the value added by each person ? what is the bread's contribution to GDP ?
The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6
In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.
The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.
The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.
The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.
The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.
The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.
Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.
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What impulse is needed to stop a 10 kg bowling ball
moving at 6 m/s?
The impulse is needed to stop a 10 kg bowling ball moving at 6 m/s² is (F)= 60N.
What is force?The force phenomena means that a object of mass is struck by some external thing and move a distance then it is called a force. It is a vector quantity. It can be measured in Newton, Dyne.
How can we calculate the force?To calculate the force we are using the formula here is newtons first law of motion, F=ma
Now we are given,
m= The mass of the object. =10kg.
a =The acceleration of the object = 6 m/s².
we have to calculate the values of force= F N.
Now we put the values in above equation,
F=ma
Or, F= 10*6
Or, F= 60N
According to the formula we can say that, The impulse is needed to stop a 10 kg bowling ball moving at 6 m/s² is (F)= 60N.
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What impulse is needed to stop a 10 kg bowling ball moving at 6 m/s²?
I’ve been struggling with this question, help!
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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A child attempts to use a wrench to remove a nut on a bicycle. Removing the nut requires a torque of 10 N·m. The maximum force the child is capable of exerting at a 90°angle is 50 N. What is the length of the wrench the child must use to remove the nut?
The child must use a wrench that is at least 20 centimeters long to remove the nut with the maximum force they can exert.
The torque exerted by the child must be equal to or greater than the required torque of 10 N·m to remove the nut. The formula for torque is torque = force x length x sin(theta), where theta is the angle between the force and the wrench.
Rearranging the formula, we can find the required length of the wrench by dividing the required torque by the force and the sin of the angle.
Length = Torque / (Force x sin(theta))
Using the given values, we get:
Length = 10 N·m / (50 N x sin(90°))
sin(90°) = 1
Length = 0.2 meters or 20 centimeters
Therefore, the child must use a wrench that is at least 20 centimeters long to remove the nut with the maximum force it can exert.
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how many newtons does a 190 lb person weigh? express your answer in newtons. activate to select the appropriate template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type w
The weight of a 190 lb person is 844.5 N.
What is the definition of 1 Newton?Newton is the SI (International System) unit of force, named after Sir Isaac Newton, a famous physicist, and mathematician. It is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg m/s²).
To convert pounds (lb) to Newtons (N), we need to use the conversion factor:
1 lb = 4.45 N
Therefore, a 190 lb person weighs:
190 lb × 4.45 N/lb = 844.5 N
So the weight of a 190 lb person is 844.5 N.
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Multiple-point charges: Four-point charges are placed as shown in the figure. Q=5.0 μC. Find the net electric field at point P shown in the figure. (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)
It's important to note that without the specific distances provided in the figure, it is not possible to provide the exact numerical value of the net electric field at point P.
To find the net electric field at point P, we need to consider the contributions from each of the four point charges. The electric field from a point charge is given by Coulomb's law:
\(E = k * (Q / r^2)\)
Where:
E is the electric field,
k is the electrostatic constant (\(k = 8.99 * 10^9 N \∙ m^2/C^2\)),
Q is the charge of the point charge, and
r is the distance between the point charge and the point where the electric field is being calculated.
Let's consider each point charge one by one:
1. The charge at the top left:
The electric field at P due to this charge is directed to the right. Its magnitude is given by:
\(E1 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.06 m)^2\)
2. The charge at the top right:
The electric field at P due to this charge is directed to the left. Its magnitude is given by:
\(E2 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.04 m)^2\)
3. The charge at the bottom left:
The electric field at P due to this charge is directed upward. Its magnitude is given by:
\(E3 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.08 m)^2\)
4. The charge at the bottom right:
The electric field at P due to this charge is directed downward. Its magnitude is given by:
\(E4 = k * (Q / r^2) = 8.99 * 10^9 N \∙ m^2/C^2 * (5.0 * 10^-^6 C) / (0.1 m)^2\)
Once we have calculated the electric fields due to each point charge, we can add them vectorially to obtain the net electric field at point P. Since the electric fields have different directions, we need to take into account their signs.
Net electric field at\(P = E1 - E2 + E3 - E4\)
Performing the calculations and taking into account the signs, we can determine the net electric field at point P.
It's important to note that without the specific distances provided in the figure, it is not possible to provide the exact numerical value of the net electric field at point P.
The calculations outlined above allow for the determination of the magnitude and direction of the net electric field, but the specific numerical value depends on the distances between the charges and point P.
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You are working for a manufacturing company. Your supervisor has an idea for controlling the position of a small bead by using electric fields. The physical setup is shown in the figure below.
You are working for a manufacturing company, which is mathematically given as
\(m=3\sqrt{2}\)\(m=\frac{15\sqrt{5}}{16}\)x=0.747a\(m/n=\frac{(x^2+a^2)3/2}{x^3}\)What is the value of m that will place the movable bead in equilibrium at x-a a ....?
a)
Generally, the equation for the force of equilibrium is mathematically given as
F=2fcos\theta
Therefore
\(K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3\)
\(m=3\sqrt{2}\)
b)
By force equilibrium
\(K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}\)
Therefore
\(n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\\)
\(m=\frac{15\sqrt{5}}{16}\)
c)
\(K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}\)
x^2+a^2=(14/3)^{2/3}x^2
x=a/1.338
x=0.747a
d)
By force equilibrium
\(K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}\)
\(m/n=\frac{(x^2+a^2)3/2}{x^3}\)
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When is the ball in a state of free fall?? Please help
PLEASEEEEEE HELPPPPPPPPPPP
Describe how a battery works.
Answer:
A battery works because of the electrical energy inside of the battery, which is connected through a wire, which transmits energy through the metal inside of the wire to power to object that the wire is connected to.
Explanation:
Please mark as Brainliest!!!A pilot Air Niugini travelling at 400km/h no in fronte sees an airlines aeroplane directly her travelling south at 300km/h. It the two planes hit head on in a fog, what would be their impact speed?
100
Explanation:
cause 400-300 : 100 pray it's correct
Two identical ambulances with loud sirens are driving directly towards you at a speed of 40 mph. One ambulance is 2 blocks away and the other is 10 blocks away. Which of the following is true? [Note that pitch = frequency.]a) The siren from the closer ambulance sounds higher pitched to you.b) The siren from the farther ambulance sounds higher pitched to you.c) The pitch of the two sirens sounds the same to you.d) The siren from the farther ambulance sounds higher pitched, until the closer ambulance passes you.
Answer:
c) The pitch of the two sirens sounds the same to you
Explanation:
The pitch does not depend on the distance of the object from the observer.
As per the given data
pitch = frequency
Frequency = \(f_{0}\) \(\frac{V +- V_{0}}{V +- V_{s}}\)
\(f^{'}\) = \(f_{0}\) \(\frac{V }{V - V_{s}}\)
Hence, the pitch of the two sirens remains the same for the observer.
Answer:
c) The pitch of the two sirens sounds the same to you
Explanation:
What is the approximate momentum of a car with a mass of 1200 kg and a
velocity of 30.0 km/h? *
A. 13.0 N.S
B. 40.0 N.S
C.3.60 104 N.S
D. 5.40 x 104 N.S