Please help what is the answer?

Answer:

Area= 24ft squared

Step-by-step explanation:

Area= 1/2 Bh

A= 1/2 9(6)

A= 1/2 48

A= 24ft

The multiple of 28 are;

Thus, the factor pairs are;

I'm not sure,, is there a paper or written length of the sharks,, or is it going off of searching it on the internet?

You haven't given the length of each shark so we can't really calculate the total length of the 7 sharks but I'll just give a strategy to find it.

let \(x\) be the length of the blacktop sharks and let \(y\) be the length of the tiger sharks. In order to figure out their total length, you can use this formula:

\(3x\ +\ 4y\ =total\ length\ of\ sharks\)

Answer:

$20400

Step-by-step explanation:

8 percent *55000 =

(8:100)*55000 =

(8*55000):100 =

440000:100 = $4400

16000+4400 =$20400

The values of the missing sides of the similar shapes are:

x = 7

y = 10

z = 20

Similar shapes have side lengths whose ratios are the same, or have proportional side lengths.

Use the following ratios to find the missing lengths of the two similar shapes in the given diagram:

35/14 = 17.5/x

Cross multiply

(35)(x) = (17.5)(14)

35x = 245

Divide both sides by 35

35x/35 = 245/35

x = 7

35/14 = 25/y

Cross multiply

(35)(y) = (25)(14)

35y = 350

35y/35 = 350/35

y = 10

35/14 = z/8

(35)(8) = 14z

280 = 14z

z = 280/14

z = 20

Therefore, the values of the missing sides of the similar shapes are:

x = 7

y = 10

z = 20

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Answer:

O 12,017 cubic millimeters

Step-by-step explanation:

Volume of cylinder = height x cross-section area(in this question, it's a circle) = hpr^2

17ml x (15ml)^2 x p(ill calculate it in calculator, not as 3.14)

= (approximately) 12017ml^3

A. In the alternate universe, the p subshell would have 5 orbitals.

B. In the alternate universe, the d subshell would have 10 orbitals.

In the alternate universe where the possible values of mℓ range from -l-1 to l+1, the number of orbitals in each subshell can be determined.

A. For the p subshell, the value of l is 1. Therefore, the range of mℓ would be -1, 0, and 1. Including the additional values of -2 and 2 from the alternate universe, the total number of orbitals in the p subshell would be 5 (mℓ = -2, -1, 0, 1, 2).

B. For the d subshell, the value of l is 2. In the conventional universe, the range of mℓ would be -2, -1, 0, 1, and 2, resulting in 5 orbitals. However, in the alternate universe, the range would extend to -3 and 3. Including these additional values, the total number of orbitals in the d subshell would be 10 (mℓ = -3, -2, -1, 0, 1, 2, 3).

Therefore, in the alternate universe, the p subshell would have 5 orbitals, and the d subshell would have 10 orbitals.

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Answer:

V=1837.5

Step-by-step explanation:

use the equation V= lwh

15.87 % percent of batteries have lifetimes more than 561 days.

Given:

battery lifetime is normally distributed for large samples. the mean lifetime is 500 days and the standard deviation is 61 days.

μ = 500

σ = 61

we know that

z = X - μ / σ

z score :

A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.

Given X = 561 days

substitute

z = 561 - 500 / 61

= 61 / 61

z = 1

At z = 1 p value is 0.8413

1 - 0.8413 = 0.1587

= 0.1587 * 100 %

= 15.87 %

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Answer:

4

Step-by-step explanation:

\(3x+2+3x+3=5x+9 \\ \\ 6x+5=5x+9 \\ \\ x=4\)

Step-by-step explanation:

\(x = \frac{4}{3} \)

\(1. \: 6x + 6 = 5 + 9 \\ 2. \: 6x + 6 = 14 \\ 3. \: 6x = 14 - 6 \\ 4. \: 6x = 8 \\ 5. \: x = \frac{8}{6} \\ 6. \: x = \frac{4}{3} \)

B. Homer was a poet who made use of oral tradition to compose the Iliad and the Odyssey, stories of the Trojan war and its aftermath that were important later Greeks as a means of teaching the aristocratic values of honor and courage.

Homer was significant to education after the collapse of the Mycenaean civilization as he authored the Iliad and Odyssey which became an important source of education for the Greeks in later years.

They were taught to the aristocratic Greeks who learned from the values of honor and courage portrayed in the stories. The poems of Homer were recited and taught for years in the form of an oral tradition by bards until they were written down.

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Answer:

c = 16

Step-by-step explanation:

We have (a + b)² = a² + 2ab + b²

x² + 8x + c is of the form a² + 2ab + b²

where x² = a²

8x = 2ab

and c = b²

⇒ x² + 8x + c = (x + √c)² which is a perfect square

x² = a² ⇒ x = a

8x = 2ab

⇒ 8x = 2xb

⇒ b = 8x/(2x)

⇒ b = 4

c = b²

⇒ c = 4²

⇒ c = 16

(x + √c)² = (x + √16)²

= (x + 4)²

= x² + 2(x)(4) + 4²

= x² + 8x + 16

Therefore, c = 16 makes the expression a perfect square

Applying the inscribed angle theorem, the measure of ∠BDA is: A. 83°.

When an angle is inscribed in a circle, the measure of the angle equals half the measure of the intercepted arc, according to the inscribed angle theorem.

Given the following:

Applying the inscribed angle theorem, we have:

m∠BDA = 1/2(166)

m∠BDA = 83°

Thus, applying the inscribed angle theorem, the measure of ∠BDA is: 83°.

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Answer:

The original fraction is \(\frac{2}{5}\)

Step-by-step explanation:

Let the numerator by X

Denominator is three more than its numerator i.e X +3

When both the numerator and denominator are increased by one the fraction becomes 1/2

\(\frac{X + 1}{X+3+1} = \frac{1}{2} \\\frac{X+1}{X+4} = \frac{1}{2} \\2X + 2 = X+4\\X = 2\)

Thus, numerator = 2

Denominator = X +3 = 2+3 = 5

The original fraction is \(\frac{2}{5}\)

The two aircraft are 128.535 far away.

What is the distance formula?

The d-distance between two places is calculated using the distance formula. The Euclidean distance formula is another name for the formula used to calculate the separation between two points on a two-dimensional plane.

Here, we have

Given: Two radars A and B are 80km apart and B is due to the east of A. One aircraft is on a bearing of 030 degrees from A and 346 degrees from B. A second aircraft is on a bearing 325 degrees from A and 293 degrees from B.

Calculating the Slope of AC,  tan60° = 1.732

Calculating the Slope of BC, tan104° = -4.011

Calculating the Slope of AD, tan125° = -1.482

Calculating the Slope of BD, tan157° = -0.424

When pointing C intercepts:

y₁ = 1.732x₁....(1)

y₁ = -4.011(x₁-80)....(2)

Solving equation(1) and(2) , we get

x₁ = 55.873

y₁ = 96.772

When point D intercepts:

y₂ = -1.428x₂....(3)

y₂ = 0.424(x₂-80)....(4)

Solving equations (3) and (4), we get

x₂ = 18.315

y₂  = -26.154

Calculating distance by applying the distance formula:

D = \(\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\)

D = \(\sqrt{(-26.154-96.772)^2+(18.315-55.873)^2}\)

D = \(\sqrt{4986.9019+1410.6033}\)

D = 128.535

Hence, the two aircraft are 128.535 far away.

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Answer:

1350

Step-by-step explanation:

1) The statement of Lin is correct.

2) (a) When scale factor, k = 9, area of the new triangle = 8100 square inches

(b) When k = 3/4, area of the new triangle = 56.25 square inches.

Given that,

A triangle has area 100 square inches.

It's dilated by a factor of k = 0.25.

When the triangle is dilated by a scale factor of k, then, each of the base and height is dilated by the scale factor of k.

So new area of the triangle after the dilation with the original triangle having base = b and height = h is,

Area of new triangle = 1/2 (kb)(kh) = k² (1/2 bh) = k² × Area of original triangle

Here original area = 100 square inches.

k = 0.25

New area = (0.25)² 100 = 6.25 square inches

So the correct statement is that of Lin.

Mai may found the new area by just multiplying the scale factor with 100, instead of taking the square of the scale factor. That is why she got 25 square inches as the new area.

2) (a) When k = 9,

Area of the new triangle = 9² (100) = 8100 square inches

(b) When k = 3/4

Area of the new triangle = (3/4)² (100) = 56.25 square inches

Hence the areas are found.

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hi

x² + 1 / x+ 7  

with  x = -9

A =  ((-9)² +1  )   /  ((-9) +7 )  

A =   ( 81 +1)  / -2  

A =  82 / -2

A =   - 82/2

A =   -41

Answer: 19 days

Step-by-step explanation:

Answer:

115 + 10x = 305

x = 19

It will take her 19 days to finish.

B. \( |2x + 1| + 1\)

\(( |2x + 1| + 3) - 2\)

\( |2x + 1| + 3 - 2\)

\( |2x + 1| + (3 - 2)\)

\( = |2x + 1| + 1\)

Answer:

30.6452% decrease.

Step-by-step explanation:

\(\frac{10.75}{15.50} =69.354\)%

100-69.354 ≈ 30.6452%

The Lagrangian for maximizing Will's utility subject to his budget constraint can be written as the correct answer is A. L = xy^4 - λ(12x + 11y - 118).

The Lagrangian for maximizing Will's utility subject to his budget constraint can be written as

L = xy^4 - λ(p_x*x + p_y*y - m),

where x and y are goods, p_x and p_y are the prices of goods x and y respectively, and m is income.
In this case, Will has a Cobb-Douglas utility function, xy^4. His income is $118, the price of x is $12, and the price of y is $11.
To find the Lagrangian for maximizing Will's utility, we substitute the values into the equation:
L = xy^4 - λ(12x + 11y - 118).
Therefore, the correct answer is A. L = xy^4 - λ(12x + 11y - 118).

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The hotel owner needs approximately 2,248 square feet of fabric to make a pool covering for the winter for their regular hexagonal pool with a side-to-side length of 30 feet.

To calculate the area of the pool, we first need to find the apothem (the distance from the center of the hexagon to the midpoint of any side). For a regular hexagon, the apothem is equal to the side length times the square root of 3 divided by 2. So, the apothem of this hexagonal pool is:

apothem = 30 × √3/2 = 25.980762

The area of a regular hexagon is given by the formula:

area = 3 × √3/2 × apothem^2

Substituting the value of the apothem, we get:

area = 3 × √3/2 × 25.980762^2 = 2247.72

Rounding this to the nearest square foot, the hotel owner will need approximately 2,248 square feet of fabric to construct the cover for the pool.

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Answer:

Step-by-step explanation:

Since there are four aces and 52 total cards.

P(A)=4/52=1/13

Answer:

The probability that you would draw an ace in a deck of cards would be 8%

Answer:

D. x^2 -3x-10

Step-by-step explanation:

The graph that has a linear fit that is best for the data that Alex collected is the graph attached.

A linear fit that would be best for Alex's data is one that tries to get an equal number of shoe sizes on both sides of the line.

The shoe sizes should also be a roughly equal distance to the line and the line should be drawn in the middle of the data. The line that does this best is shown attached.

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Answer:

The range of this quadratic function is

-infinity < y ≤ 2.

Answer:

∠ F ≈ 24.2°

Step-by-step explanation:

using the tangent ratio in the right triangle

tan F = \(\frac{opposite}{adjacent}\) = \(\frac{GH}{FG}\) = \(\frac{9}{20}\) , then

F = \(tan^{-1}\) ( \(\frac{9}{20}\) ) ≈ 24.2° ( to the nearest tenth )