Please help The half-life of argon-44 is 12 minutes. Suppose you start with 20 atoms of
argon-44 and wait 12 minutes. How many atoms of argon-44 will be left?
A. 20 atoms
B. 40 atoms
C. 5 atoms
D. 10 atoms

Answers

Answer 1

Answer:

D. 10 atoms

Explanation:


Related Questions

A car moves with an average speed of 75 kmh^-1 from town P to town Q in 2 hours. By using information, you may calculate the distance between two towns. state a derived quantity and its S.I unit​

Answers

Answer:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

Explanation:

patron

Explanation:

 The patron is something or someone who defends some cause or point of view. In the art field, for example, the patron may be considered a sponsor, that is, someone who is known for defending a particular group of people or specific situation.

  The patron is one who advocates, advises and directs. In the military, patrons are heroic figures who are chosen to defend a military unit, for example.

Distance = speed * time,
D = (75)(2)
D = 150 km.
Therefore, the distance between town p and town q is 150 km.

pleaseeee help mehhhh​

pleaseeee help mehhhh

Answers

A

The answer is a .

Have a great day

A wheel of radius 30.0 cm is rotating at a rate of 3.10 revolutions every 0.0710 s
Through what angle does the wheel rotate in 1.00 s?

Answers

To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

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What is the best description of the function of stars?


Stars are the recycling centers of the universe.
Stars are the light bulbs of the universe.
Stars are the batteries of the universe.
Stars are the motors of the universe.

Answers

Answer:

Stars are the light bulbs of the universe.

Answer:

Stars are the recycling centers of the universe

Explanation:

I just did on edge C

You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?

A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.

Answers

Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

Calculate the flow rate of blood (of density 0.846 g/cm3 ) in an aorta with a crosssectional area of 1.36 cm2 if the flow speed is 48.5 cm/s. Answer in units of g/s.

Answers

Answer:

55.80 g/s

Explanation:

From the question,

Flow rate = density×Area×velocity.

φ = ρ×A×V................... Equation 1

Where φ = flow rate of blood, ρ = density of blood, A = cross sectional area of blood, V = velocity of blood.

Given: ρ = 0.846 g/cm³, A = 1.36 cm², V = 48.5 cm/s.

Substitute these values into equation 1

φ = 0.846×1.36×48.5

φ = 55.80 g/s

Hence, the flow rate of  the blood = 55.80 g/s

Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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This graph shows the velocity of particles A and B through time. The two lines intersect each other at point O. What is the acceleration of particles A and particle B at point O?

A.
It is -0.2 m/s2 for particle A and -0.05 m/s2 for particle B.
B.
It is 0.65 m/s2 for both particles.
C.
It is 0.68 m/s2 for both particles.
D.
It is -2 m/s2 for particle A and -0.50 m/s2 for particle B.

This graph shows the velocity of particles A and B through time. The two lines intersect each other at

Answers

Answer:

Option (D)

Explanation:

Since acceleration of an object = Change in velocity with the change in time

a = \(\frac{v_2-v_1}{t_2-t_1}\) = \(\frac{\triangle v}{\triangle t}\)

Here \((v_1,t_1)\) and \((v_2,t_2)\) are the two points on the line on the graph.

Therefore, slope of the line will represent the acceleration (constant) at any point lying on the line.

For particle A,

Two points on the line are (0, 2) and (1, 0)

a = \(\frac{2-0}{0-1}\)

\(a_1\) = -2 meter per sec²

Similarly, for the particle B,

There are two points (0, 1) and (2, 0) on the line.

\(a_2\) = \(\frac{1-0}{0-2}\) = \(-\frac{1}{2}\)

\(a_2=-0.5\) meter per sec²

Therefore, at any moment of time acceleration of the particle A will be (-2) meter per sec² and for particle B will be (-0.5) meter per sec².

Option (D) will be the correct option.

. A car traveling at 14 m/s encounters a patch of ice and takes 5.0 s to stop. What is the car's
acceleration?

Answers

Answer:-2.8m/s^2

Explanation:

vf=vi+at

0=14+a*5

a=-2.8m/s^2


In a DC generator, the generated emf is directly proportional to the

Answers

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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1. Towards the end of a 400m race, Faisal and Edward are leading and are both running at 6m/s. While Faisal is 72m from the finish line Edward is 100m from the finish line. Realising this and to beat Faisal, Edward decides to accelerate uniformly at 0.2 m/s2 until the end of the race while Faisal keeps on the same constant speed. Does Edward succeed in beating Faisal?

Answers

Answer:

  no

Explanation:

Faisal will finish the race in ...

  (72 m)/(6 m/s) = 12 s

In order to beat Faisal, Edward's average speed in those 12 seconds must exceed ...

  (100 m)/(12 s) = 8 1/3 m/s

To achieve that average speed, Edward's acceleration must be ...

  (8 1/3 m/s -6 m/s)/(12 s/2) = 7/18 m/s² ≈ 0.3889 m/s²

Accelerating at only 0.2 m/s², Edward will not beat Faisal.

_____

Additional comment

When acceleration is uniform, the average speed is reached halfway through the period of acceleration.

I don’t understand what it’s asking me to do

I dont understand what its asking me to do

Answers

Because the mass and displacement are already given in Kg and m, respectively, in the first part of your question, there is no need to convert them. However, in the second part of your question, you must use the given equation to calculate the spring constant.

if the table data is given in grams and  cm you have to convert it using the following conversion,

1. To convert grams to kilograms, we divide the mass values by 1000.

2. To convert centimeters to meters, we divide the displacement values by 100.

But here in the given table it's already given the mass in kg and the displacement in meters (m). so no need to convert it.

Now comes the second part of your question,

To calculate the spring constants for the given data, we can use the equation:

k = -mg/Δx

where:

k is the spring constant (in N/m),

m is the mass (in kg), and

Δx is the displacement of the spring (in m).

Let's calculate the spring constants using the provided data:

Mass (kg): 0.05  0.1  0.2  0.3  0.4  0.5  0.6

Displacement of Spring (m): 0.012  0.027  0.065  0.1  0.135  0.17  0.199

Using the equation

k = -mg/Δx,

we can calculate the spring constant for each data point:

For the first data point (m = 0.05 kg, Δx = 0.012 m):

k = -0.05 kg * 9.8 m/s² / 0.012 m

k ≈ -40.833 N/m

Similarly, we can calculate the spring constants for the other data points:

For the mass of 0.05 kg, the spring constant is approximately -40.833 N/m.

For the mass of 0.1 kg, the spring constant is approximately -18.519 N/m.

For the mass of 0.2 kg, the spring constant is approximately -6.154 N/m.

For the mass of 0.3 kg, the spring constant is approximately -3.267 N/m.

For the mass of 0.4 kg, the spring constant is approximately -2.222 N/m.

For the mass of 0.5 kg, the spring constant is approximately -1.716 N/m.

For the mass of 0.6 kg, the spring constant is approximately -1.449 N/m.

Therefore, In the first part of the question, there is no need to convert the mass into kg and the displacement cm into m because it is already given in kg and m respectively, and in the second part question you have to calculate the spring constant using the given equation.

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Ashlyn threw a 1.6 kg ball. If she used 122 Joules of work to throw the ball, what was the initial velocity of the ball as it left her hand?​

Answers

Answer:

\(12.35\:\mathrm{m/s}\)

Explanation:

We can use the work-energy theorem to solve this problem. The work-energy theorem states that the work done on an object will be equal to that object's change in kinetic energy. Thus, we have the following equation:

\(W=\Delta KE,\\W=\frac{1}{2}mv^2-0,\\122=\frac{1}{2}\cdot 1.6\cdot v^2,\\v^2=152.5,\\v\approx \boxed{12.35\:\mathrm{m/s}}\)

The first person that answered is is correct just to let you know!

If a person weighs 692 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that planet?

Answers

Answer:

Approximately \(75.3\; \rm m \cdot s^{-2}\). (Approximately \(7.69\, g\), where \(g\) denotes the acceleration due to gravity on the surface of the earth.)

Explanation:

The weight of an object is the size of the overall gravitational pull on that object. If the mass of this person is \(m\), the weight of this person at a point with gravitational acceleration \(g\) would be \(m \cdot g\).

Let \(g_{0}\) denote the gravitational acceleration on the surface of the earth. The weight of this person on the surface of the earth would be \(m \cdot g_0\).

Let \(g_1\) denote the gravitational acceleration on the surface of that "nearby planet". The weight of this person on the surface of that planet would be \(m \cdot g_1\).

According to the question:

Weight of this person on the surface of the earth: \(692\; \rm N\). Therefore, \(m \cdot g_0 = 692\; \rm N\).Weight of this person on the surface of that nearby planet: \(5320\; \rm N\). Therefore: \(m \cdot g_1 = 5320\; \rm N\).

Take the quotient of these two equations:

\(\displaystyle \frac{m\cdot g_1}{m \cdot g_0} = \frac{5320 \; \rm N}{692\; \rm N}\).

\(\displaystyle \frac{g_1}{g_0} \approx 7.6879\).

\(g_1 \approx 7.6879 \, g_0\).

In other words, the gravitational acceleration on the surface of that nearby planet is approximately \(7.6879\) times the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth is approximately \(g \approx 9.8\; \rm m \cdot s^{-2}\). Therefore, the gravitational acceleration on the surface of that planet would be approximately \(7.6879\, g \approx 7.8679 \times 9.8\; \rm m \cdot s^{-2} \approx 75.3\; \rm m \cdot s^{-2}\).

Which is the process by which a solid changes to a liquid? O condensation O evaporation O melting sublimation​

Answers

Answer:

Melting

Explanation:

The process in which a solid changes to a liquid is called melting. This process is also termed as fusion. Due to application of heat and pressure, the internal energy of a solid increases and the molecules become far from each other due to which it starts to melt.

Hence, the correct option is (c) "melting".

Answer:

c. melting

Explanation:

took the quiz on edge

The engine of a locomotive exerts a constant force of 6.8 105 N to accelerate a train to 80 km/h. Determine the time (in min) taken for the train of mass 1.1 107 kg to reach this speed from rest.

Answers

Answer:

t = 6 minutes

Explanation:

Given that,

Force,\(F=6.8\times 10^5\ N\)

Initial speed of the train, u = 0

Final speed of the train, v = 80 km/h = 22.22 m/s

The mass of the train, \(m=1.1\times 10^7\ kg\)

We need to find the time taken by the train to come to rest. We know that,

F = ma

\(F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{1.1\times10^7\times (22.22-0)}{6.8\times 10^5}\\\\t=359.44\ s\)

or

t = 6 minutes (approx)

So, the required time is equal to 6 minutes.

True or false quarterbacks should not expect to have bad passes

Answers

Answer:

false

Explanation:

False ..................

Which of the substances listed in the table on the first page would heat up more quickly if an equal amount
of heat energy were applied to all of the substances at the same time? Explain your answer.

Answers

If an equal amount of heat energy is applied to all the substances at the same time, aluminum will heat up more quickly compared to the other substances.

What is Specific Heat ?

Specific heat is the amount of heat energy required to raise the temperature of a substance by a certain amount, usually one degree Celsius or one Kelvin, per unit mass of the substance. It is a physical property that determines how much energy is needed to change the temperature of a material. Different materials have different specific heat values, which can be used to predict how they will behave when heated or cooled.

Looking at the table, we can see that water has the highest specific heat capacity of all the substances listed, at 4.18 J/g°C. This means that it requires more energy to raise the temperature of water compared to the other substances. Therefore, if an equal amount of heat energy is applied to all the substances at the same time, water will heat up more slowly compared to the other substances.

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an 80-n uniform plank leans against a frictionless wall as shown. the vertical component of force at point p applied to the plank by the floor is:

Answers

The net torque needed to balance is 120N

Weight of the plank W = 80N

Length of the inclined plane S = \(\sqrt{9 + 16}\) = 5

Cos θ = 3/5

Net torque needed to balance is τ = W Cos θ s/2

τ = 120 N

The study's subject also refers to torque as a moment, moment of force, rotational force, or turning effect. It is possible to think of torque as the linear force's rotational counterpart. It stands for a force's capacity to alter the body's rotational motion. Archimedes' studies on the use of levers, which are reflected in his well-known saying, "Give me a lever and a place to stand. and I shall move the Earth." similar, led to the development of the concept. a linear force pushes, similar to that. A torque is a movement that twists about or pulls an object. a certain axis. When the strength of the force is multiplied by the angle at which the line of action is perpendicular, torque is the outcome.

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as the distance between 2 objects increased, the gravitational force between them

Answers

Answer:

Becomes weaker

Explanation:

Hope this helps :)

A circuit that has only one branch for electrons to follow is a(n) ____.
Question 1 options:

circuit diagram

electron circuit

parallel circuit

series circuit

Answers

Answer: series circuit

Explanation:

First 2 answers are garbage.  In Parallel circuits electrons have 2 or more paths to follow.  In Series circuits, there is only one path.

How could you change the design of the experiment to determine the size of the magnetic field around the magnet that was taped down?

Answers

As the free magnet is brought slowly approaching the magnet that is fixed, a pull toward the fixed magnet will eventually become apparent.

In plain terms, what exactly is a magnetic field?

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

A magnetosphere example is what?

Compass, motor, refrigerator magnets, railroad tracks, and modern roller coasters are all examples of objects that use magnetic force. Charges that travel across its areas feel a force. All moving charges produce a magnetic field.

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A vector has the components Ax=29 m and Ay= 18 m. What is the magnitude of this vector? What angle does this vector make with the positive x axis?

Answers

The magnitude of the vector is approximately 35.85 m.

The angle that this vector makes with the positive x-axis is approximately 32 degrees.

What is the magnitude of this vector?

To find the magnitude of the vector with components Ax=29 m and Ay=18 m, we use the Pythagorean theorem:

|A| = √(Ax^2 + Ay^2)

|A| = √(29^2 + 18^2)

|A| = √(841 + 324)

|A| = √1165

|A| =  34.13 m

To find the angle that this vector makes with the positive x-axis, we can use the inverse tangent function:

θ = tan^-1(Ay/Ax)

θ = tan^-1(18/29)

θ = 31.82 degrees

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Mike rides his horse with a constant speed of 20 km/h. How far can he travel in 4 hours?

Answers

Answer:

Mike can travel 80 Km in 4 hours

What are the effects of electric current. What are the factors affecting the heat produced in a conductor.

Answers

Answer:

i got u

Explanation:

Effects of Electric Current:

Electric current is the flow of electric charges in a conductor. When a current passes through a conductor, it produces several effects, some of which include:

1. Heating effect: The heating effect of electric current occurs when the current passes through a conductor, and the resistance of the conductor converts some of the electrical energy into heat. This effect is utilized in electric heaters, electric stoves, and incandescent light bulbs.

2. Magnetic effect: When an electric current passes through a conductor, it produces a magnetic field around the conductor. This effect is utilized in devices like motors and generators.

3. Chemical effect: Electric current can also cause chemical reactions to occur. This effect is utilized in batteries and electrolysis.

4. Electric shock: When electric current passes through the human body, it can cause an electric shock, which can be fatal.

Factors Affecting the Heat Produced in a Conductor:

When an electric current flows through a conductor, some of the electrical energy is converted into heat due to the resistance of the conductor. The amount of heat produced in the conductor is dependent on several factors, including:

1. Current: The higher the current flowing through the conductor, the greater the amount of heat produced.

2. Resistance: The higher the resistance of the conductor, the greater the amount of heat produced.

3. Time: The longer the current flows through the conductor, the greater the amount of heat produced.

4. Material: Different materials have different resistances and will therefore produce different amounts of heat for the same current flowing through them.

5. Cross-sectional area: The larger the cross-sectional area of the conductor, the less the amount of heat produced for the same current flowing through it.

6. Temperature: The temperature of the conductor also affects the amount of heat produced. As the temperature of the conductor increases, its resistance also increases, and more heat is produced for the same current flowing through it.

true or false a liter is a metric unit of volume

Answers

To find

True or false

Explanation

Liter is the SI unit of volume. Thus it is the metric unit of volume.

Conclusion

The given statement is true.

if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?

Answers

A 3rd harmonic of a tube open at both ends will have displacement antinodes at both ends.

In a tube of length L with two open ends, the longest standing wave has displacement antinodes (pressure nodes) at both ends. The fundamental or first harmonic is what it is known as. The second harmonic is the longest standing wave in a tube of length L with two open ends.

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if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the

A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?

Answers

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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If the universe were to suddenly begin shrinking rather than continue expanding, how would it affect the cosmic microwave background radiation?
A. It would decrease in temperature.
B. It would blue-shift.
C. It would red-shift.
D. It would increase in temperature.

Answers

If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).

The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.

If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.

Therefore, the correct answer is B. It would blue-shift.

You hit a hockey puck and it slides across the ice at nearly a constant speed.Is a force keeping it in motion?Explain.

Answers

Answer:

Explanation:

When the puck is sliding on the ice, there is no force being exerted on the puck to keep it moving forward. Instead, inertia keeps the puck moving forward. Friction between the puck and the ice gradually slows the puck down. You hit a hockey puck and it slides across the ice at nearly a constant speed

At constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.

According to Newton's second law of motion, the force applied to a an object is directly proportional to the product of mass and acceleration of the object.

F = ma

Acceleration is the change in the velocity of an object per change in time of motion.

At constant velocity, the acceleration of an object is zero.When acceleration of an object is zero, the force on the object is zero.A constant speed (magnitude only) and change in the direction of the object, implies a change in velocity of the object.at changing velocity, the acceleration on an object is positive, and hence net force acts on the object.

Thus, we can conclude that at constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.

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