please help!!! thank you! ​

Answer:

\((fof) = x - 5 - 5 \\ = x - 10\)

Answer:

No, it's just maximum of two tables that lost balloon so there is no way it affected each table.

Step-by-step explanation:

Number of balloons purchased= x

Number of tables = 8.

Each table has = x/8 balloons

If 2 balloons pop.

Let's assume it's just from a table

That table has( x/8 -2)

If it's from 2 table

The two table has

(X/8-1) for both tables

But the total balloon remaining = x-2

There is no particular equation that can describe the gallon on each table because it's only two balloons that popped.

Answer:

That expression is not true. To evenly distribute the balloons you use x/8. Then you subtract 2 balloons from that total amount. The subtraction must be done after the division. There will not be the same number of balloons at each table.

Step-by-step explanation:

It was the sample answer.

The future value of Tran Lee's savings after five years would be approximately $14,995.49.

To calculate the future value of Tran Lee's savings, we can use the formula for the future value of an ordinary annuity:

Future Value = Payment * [(1 + Interest Rate)^Number of Periods - 1] / Interest Rate

Given:

Payment (PMT) = $2,900 per year

Interest Rate (r) = 5% = 0.05 (decimal form)

Number of Periods (n) = 5 years

Substitute  these values into the formula, we get:

Future Value = $2,900 * [(1 + 0.05)^5 - 1] / 0.05

Calculating this expression, we find:

Future Value ≈ $14,995.49

Therefore, the future value of Tran Lee's savings after five years would be approximately $14,995.49.

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The future value of Tran Lee's savings after five years would be approximately $14,995.49.

To calculate the future value of Tran Lee's savings, we can use the formula for the future value of an ordinary annuity:

Future Value = Payment * [(1 + Interest Rate)^Number of Periods - 1] / Interest Rate

Given:

Payment (PMT) = $2,900 per year

Interest Rate (r) = 5% = 0.05 (decimal form)

Number of Periods (n) = 5 years

Substitute  these values into the formula, we get:

Future Value = $2,900 * [(1 + 0.05)^5 - 1] / 0.05

Calculating this expression, we find:

Future Value ≈ $14,995.49

Therefore, the future value of Tran Lee's savings after five years would be approximately $14,995.49.

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The first step of the writing process is to brainstorm ideas. One concept addressed in this unit is perimeter, which is the circumference of a shape's outside.

Some ideas for a brief essay on perimeter might include:

The next step is to organize the ideas into an outline. For this essay, a possible outline might be:

I. Introduction

II. How to Calculate the Perimeter

III. Real-world applications of perimeter

IV. Conclusion

With the outline in place, the next step is to write the essay. A possible essay based on this outline might be:

The circumference of a shape's outside is known as its perimeter. It is found by adding up the lengths of all the sides of the shape. Understanding perimeter is important in many subject areas, such as construction and landscaping, as well as in everyday life.

To calculate the perimeter of a shape, you first need to measure the lengths of all the sides. For example, to find the perimeter of a square, you would measure the length of each side and then add them up. To find the perimeter of a rectangle, you would measure the lengths of the two longer sides and the two shorter sides, and then add them up. The perimeter of a triangle is found by adding the lengths of all three sides.

Perimeter has many real-world applications. In construction, perimeter is used to calculate the amount of fencing or framing needed for a building. In landscaping, the perimeter is used to calculate the amount of mulch or sod needed to cover a certain area. It is important to accurately calculate perimeter in these fields, as it can affect the cost and success of a project.

In conclusion, understanding perimeter is important in many subject areas and in everyday life. It is useful for calculating the distance around the outside of a shape, and it has many real-world applications. By practicing and learning about perimeter, we can improve our problem-solving skills and better understand the world around us.

This assignment is incomplete, and a similar one is nowhere to be found. As a result, the essay does not include the answer to the missing question. However, a step-by-step guide on how to write the relevant essay is offered.

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Answer:

The formula for the area of a circle is:

A = πr^2

where A is the area and r is the radius.

In this case, we are given that the area is 4π cm². Solving for the radius, we get:

4π = πr^2

r^2 = 4

r = 2

So the radius of the circle is 2 cm.

The formula for the circumference of a circle is:

C = 2πr

Plugging in the value for the radius, we get:

C = 2π(2) = 4π

Therefore, the circumference of the circle is 4π cm.

Left f(x, y) = √(y+cos^{2}x). Then fx(x, y) = \(-\frac{1}{\sqrt{y-\cos^{2}x}}\sin x\cos x\) and fy(x, y) = \(\frac{1}{2\sqrt{y-\cos^2x}}\). Both fx and fy are continuous functions for y >0 , so f is Differentiable at (0, 0) by this theorem. So the linear approximation of f at (0, 0) is f(x, y) ≈ f(0, 0)+fx(0, 0)(x-0)+fy(0, 0)(y-0)= 1+1/2y.

In the given question, we have to verify the linear approximation at (0, 0).

f(x, y) = √(y+cos^{2}x) ≈ 1 + 1/2y

Let f(x, y) = √(y+cos^{2}x)

f(x, y) ≈ f(a, b)+fx(a, b)(x-a)+fy(y-b)

f(x) = \(-\frac{1}{\sqrt{y-\cos^{2}x}}\sin x\cos x\)

f(y) = \(\frac{1}{2\sqrt{y-\cos^2x}}\)

f(x, y) ≈ 1+0(x-0)(1/2)(y-0)

f(x, y) ≈ 1+1/2y

Hence, left f(x, y) = √(y+cos^{2}x). Then fx(x, y) = \(-\frac{1}{\sqrt{y-\cos^{2}x}}\sin x\cos x\) and fy(x, y) = \(\frac{1}{2\sqrt{y-\cos^2x}}\). Both fx and fy are continuous functions for y >0 , so f is Differentiable at (0, 0) by this theorem. So the linear approximation of f at (0, 0) is f(x, y) ≈ f(0, 0)+fx(0, 0)(x-0)+fy(0, 0)(y-0)= 1+1/2y.

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The complete question is:

Verify the linear approximation at (0, 0). f(x, y) = √(y+cos^{2}x) ≈ 1 + 1/2y

Left f(x, y) = √(y+cos^{2}x). Then fx(x, y) =.............. and fy(x, y) = ............. Both fx and fy are continuous functions for y >............ , so f is Differentiable at (0, 0) by this theorem. We have fx(0, 0) =........... and fy(0, 0) =............. , so the linear approximation of f at (0, 0) is f(x, y) ≈ f(0, 0)+fx(0, 0)(x-0)+fy(0, 0)(y-0)=........

Answer:

2000

Step-by-step explanation:

Number of shares after split is 5/2 times the pre split value =800*5/2 = 2000

Answer:

962.084375 meters² or 306.25π

Step-by-step explanation:

A diameter is a line that goes straight through the center of the circle. Since it goes through the center, it creates 2 radii. This splits the diameter into 2 separate parts, and since the diameter is 25 meters, that means that the radius will be 25/2 = 17.5 meters.

The formula for the area of a circle is pi • r²

Since we know the radius (17.5), we can solve this expression:

pi • 17.5²

pi • 306.25

If we use 3.1415 for pi, we get962.084375 meters²

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The amount of discount on each $500 Millville Water District bond is $18.87.

What is discount?

Discount refers to a reduction in the original price of a product or service. It is often used as an incentive to encourage customers to buy, especially in retail and e-commerce businesses.

If the Millville Water District bonds are selling at 96.225, it means that the market price of one bond is 96.225% of its face value.

To calculate the market price of a $500 bond, we need to multiply $500 by 0.96225:

Market price of one bond = $500 x 0.96225 = $481.13

Therefore, the market price of one $500 Millville Water District bond is $481.13.

To calculate the discount on each bond, we need to subtract the market price from the face value of the bond, and the result will be the amount of the discount:

Discount = Face value of bond - Market price of bond

Discount = $500 - $481.13 = $18.87

Therefore, the amount of discount on each $500 Millville Water District bond is $18.87.

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Answer:

B

Step-by-step explanation:

Edge 2021.

If the value of a polynomial is 0 when x = 5, then the expression x - 5 must be a factor of the polynomial.

To understand why, let's consider the process of evaluating a polynomial at a specific value of x.

When we substitute x = 5 into the polynomial, if the result is 0, it means that (x - 5) is a factor of the polynomial. This is because when we divide the polynomial by (x - 5), the remainder is 0.

In other words, if the polynomial evaluates to 0 when x = 5, it indicates that (x - 5) divides evenly into the polynomial, making it a factor.

Thus, the other expressions (-5x, 5x, x + 5) are not necessarily factors of the polynomial when the value of x is 5.

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The 50th partial sum s50 of the alternating series is an underestimate of the total sum. This is because the alternating series test theorem states that the alternating series converges to a value between the last negative term and the last positive term.

Thus, the alternating series can be overestimated by using the last positive term and underestimated by using the last negative term. Let's consider an example. Suppose we have the alternating series $$1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6} + \cdots$$

The last positive term is $$\frac{1}{5}$$ and the last negative term is $$-\frac{1}{6}$$.

Therefore, the alternating series converges to a value between

$$\frac{1}{5}$$ and $$-\frac{1}{6}$$.

So, if we take the 50th partial sum s50, which is a sum of the first 50 terms of the series, we are using the last negative term as the last term. Therefore, s50 is an underestimate of the total sum of the series.

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So, the probability that a randomly selected cell phone that has been recalled came from site 3 is 2.5 or 25%.

We can use Bayes' theorem to calculate the probability that a phone that has been recalled came from site 3. Bayes' theorem states that:

P(A|B) = P(B|A) * P(A) / P(B)

where:

P(A|B) is the probability of event A occurring given that event B has occurred (in this case, the probability that a phone came from site 3 given that it has been recalled)

P(B|A) is the probability of event B occurring given that event A has occurred (in this case, the probability that a phone has been recalled given that it came from site 3)

P(A) is the prior probability of event A occurring (in this case, the probability that a phone came from site 3)

P(B) is the prior probability of event B occurring (in this case, the probability that a phone has been recalled)

So, in this case, we have:

P(site 3 | recalled) = P(recalled | site 3) * P(site 3) / P(recalled)

We know that:

P(recalled | site 3) = 9%,

P(site 3) = 10%

We also know that:

P(recalled) = P(recalled | site 1) * P(site 1) + P(recalled | site 2) * P(site 2) + P(recalled | site 3) * P(site 3)

= (5% * 60%) + (7% * 30%) + (9% * 10%) = 3% + 2.1% + 0.9% = 6%

So, we can now calculate the probability that a phone that has been recalled came from site 3 as:

P(site 3 | recalled) = (9% * 10%) / 6% = 0.15 / 0.06 = 2.5

So the probability that a randomly selected cell phone that has been recalled came from site 3 is 2.5 or 25%.

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The value of the test statistic is -8.2542.

We have,

p'= 0.87, p= 0.93 and n= 1232

We know, the equation for the Test statistic for a population proportion  is mathematically given as

z = (p' - p)/ √p(1-p)/ n

So, z= (0.87 - 0.93)/ √0.93(1-0.93)/ 1232

z = (-0.06) / 0.007269

z = -8.2542

So, the value of the test statistic is -8.2542.

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Based on the information given the number of milliliters of milk does it contain is 42,000 mL.

1 liter=1000 ml

Using this formula

Number of milliliters=Number of liters×1,000 ml

Where:

Number of liters=42 liters

Let plug in the formula

Number of milliliters=42 liters×1,000 ml

Number of milliliters=42,000 ml

Inconclusion  the number of milliliters of milk does it contain is 42,000 mL.

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To find the points satisfying the necessary conditions for the given problem, we need to solve the system of equations formed by the constraints and find the critical points of the objective function. The necessary conditions include satisfying the constraints and determining the critical points where the gradient of the objective function is zero or undefined.

The given problem involves minimizing the function f(x1, x2, x3) = (x1-1)^2 + (x2+2)^2 + (x3-2)^2 subject to the constraints 2x1 + 3x2 - 1 = 0 and x1 + x2 + 2x3 - 4 = 0.

To satisfy the constraints, we solve the system of equations:

2x1 + 3x2 - 1 = 0

x1 + x2 + 2x3 - 4 = 0

After solving the system, we obtain the values of x1, x2, and x3 that satisfy the constraints.

To find the critical points, we take the partial derivatives of the objective function with respect to x1, x2, and x3 and set them to zero. Solving these equations will give us the critical points.

The explanation of the solution to this problem requires performing the calculations and solving the system of equations. However, I can assist you with step-by-step instructions if you provide the desired method (e.g., substitution, elimination, etc.) for solving the system and finding the critical points.

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The apparent weight of the rock when submerged in water is 70 N.

When an object is submerged in a fluid, it experiences an upward buoyant force due to the displacement of the fluid. This buoyant force reduces the apparent weight of the object.

To calculate the apparent weight of the rock when submerged in water, we need to determine the buoyant force acting on it. The buoyant force is equal to the weight of the fluid displaced by the rock.

The volume of the rock is given as 0.00312 m^3. This volume represents the volume of water displaced by the rock when submerged.

The weight of the fluid displaced is equal to the weight of the water with the same volume. The density of water is approximately 1000 kg/m^3, so the weight of the displaced water is:

Weight of displaced water = density × volume × acceleration due to gravity

                        = 1000 kg/m^3 × 0.00312 m^3 × 9.8 m/s^2

                        ≈ 30.816 N

Since the buoyant force is equal to the weight of the displaced water, the apparent weight of the rock when submerged in water is:

Apparent weight = Weight in air - Weight of displaced water

              = 100 N - 30.816 N

              = 69.184 N

Rounding to the nearest Newton, the apparent weight of the rock when submerged in water is 70 N.

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Answer:7

Step-by-step explanation:

100/20 = 5

35/5 = 7

Analyzing the function f(x) = -2•x³ + 5•x² - 3•x + 1, using the criteria f(x) = f(-x) for even functions and f(x) = -f(-x) for odd functions, gives the correct option as the option

A. Neither even or odd

An even function satisfy the equation f(x) = f(-x)

An even function is one that is symmetrical about the y-axis

An odd function satisfy the equation f(x) = -f(-x)

The shape graph of an odd function is inverted as it crosses the y-axis.

Analyzing the function f(x) = -2•x³ + 5•x² - 3•x + 1 gives;

f(1) = -2•1³ + 5•1² - 3•1 + 1 = -1

f(-1) = -2•(-1)³ + 5•(-1)² - 3•(-1) + 1 = 11

f(1) ≠ f(-1)

-f(-1) = -2•(-1)³ + 5•(-1)² - 3•(-1) + 1 = 11

f(1) ≠ -f(-1)

The function is therefore;

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Answer: so if 45,000 is 45 % then it would be 10,000

Step-by-step explanation:

Answer:

(2/3,0)(-2,0)

Step-by-step explanation:

Answer:

(3x-2)(x+2)

if u are solving,

x=0.667

x=-2

Therefore, the length of the given curve, y = x²/32 + 4 In x, 2 ≤ x ≤ 4 is 3.454 units

The length of the curve, y = x²/32 + 4 In x from x = 2 to x = 4 will be computed by using the following formula:

L = ∫[a, b]√[1+{f'(x)}²]dx.

The length of the curve y = x²/32 + 4 In x, 2 ≤ x ≤ 4 can be calculated using the following steps;

Firstly, compute f'(x) for the given curve:

y = x²/32 + 4 In x (take the derivative of the given curve with respect to x)dy/dx = x/16 + 4/x ...(i)

Now, let f'(x)² = {dy/dx}² and substitute the value of dy/dx from equation (i), we get;f'(x)² = {x/16 + 4/x}².

Now, √[1 + {f'(x)}²] = √[1 + {x²/256} + 8/ x²], then we integrate with respect to x using the limits

x = 2 to x = 4.

L = ∫[2,4]√[1+{f'(x)}²]dx

= ∫[2,4]√[1+{(x/16 + 4/x)}²]dx= ∫[2,4]√[1+{(x²/256)+(8/x²)+(1/8)}]dx

To compute the above integral, let {x²/256 + 8/x² + 1/8} = u, then we have;

x/8 - 1/2x³ + C = du/(2√u)

Now, integrate the expression with respect to x and use the limits of integration, we have;

L = ∫[2,4]√[1+{(x/16 + 4/x)}²]dx

= ∫[2,4]√[1+{(x²/256)+(8/x²)+(1/8)}]dx

= ∫[33/32, 33/16](1/2)du/√u

= (√u)|_[33/32]^[33/16]

= √(33/16 + 1/8) - √(33/32 + 1/8)= √417/128 - √273/256

= (17/8)√3 - (3/8)√273 or 3.454 unit (approximate value).

Therefore, the length of the given curve, y = x²/32 + 4 In x, 2 ≤ x ≤ 4 is 3.454 units (approximate value).]

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Answer:

19xy + 16z

Step-by-step explanation:

combine like terms

7xy +1 2xy= 19xy

8z - 2z + 10z = 16z

The option that explains the point (1, 1400) is (c) the person surveyed took a day trip

From the graph, we have the following representations:

The point (1,1400) implies that

x = 1 and y = 1400

This means that

The number of days on vacation is 1 and the total cost of vacation is 1400

Hence, the option that explains the point (1, 1400) is (c) the person surveyed took a day trip

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If the population standard deviation of a sample increases without other changes, the confidence interval is most likely to widen.

This is because the standard deviation is a measure of the spread of the data, so if it increases, the data points are more spread out from the mean. As a result, the range of values that could reasonably contain the true population parameter (i.e., the confidence interval) needs to be wider to account for the increased variability in the sample.
If the population standard deviation of a sample increases without other changes, the confidence interval is most likely to become wider.
When standard deviation increases, it indicates more variability in the data. As a result, the confidence interval, which is a range of values that estimates the true population parameter with a certain level of confidence, needs to be wider to account for the increased variability. This ensures that the true population parameter is still captured within the interval with the same level of confidence.

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Answer:

Step-by-step explanation: