Answers
Answer:
Jupiter.
Explanation:
Jupiter has the fastest axial rotation time (day) in the list of answers, based on the fact that its day is only 10 hours long.
Related Questions
If the student’s estimate of the balloon’s volume was incorrect and the actual volume was 620 ml, would the amount of glucose that actually reacted be more than or less than the amount calculated in part (c)? Explain your response.
( C answer ) only 1.9 g of glucose reacted and only .0211 mol of co2 was formed.
Answers
The number of moles of CO2 produced is 0.021 moles
If the estimated volume of the balloon is wrong then the amount of glucose reacted must be more than is stated.
What is respiration equation?The respiration equation represents the chemical process of aerobic cellular respiration, which occurs in the mitochondria of cells and is the primary way in which cells generate energy in the form of ATP (adenosine triphosphate).
The equation of the reaction is;
C6H12O6 + 6O2 → 6CO2 + 6H2O + ATP
We know that;
Number of moles of glucose = 10 g/180 g/mol
= 0.056 moles
PV = nRT
n = PV/RT
n = 1 * 0.55/318 * 0.082
n = 0.021
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1. What was the immediate cause for the United States' entry into World
War II?
O The attack on Pearl Harbor by Japan
O The German invasion of Poland
O The formation of the Axis powers
O The rise to power of Adolf Hitler
Answers
The immediate cause for the United States' entry into World War II was the attack on Pearl Harbor by Japan on December 7, 1941.
What was World War II about?World War II was a global war that lasted from 1939 to 1945. It involved the majority of the world's nations, including all of the great powers, organized into two opposing military alliances: the Allies and the Axis.
Prior to this attack, the United States had maintained a policy of neutrality and had provided support to the Allies in the form of aid and supplies. However, the attack on Pearl Harbor, which resulted in the deaths of over 2,400 Americans, led to a declaration of war against Japan by the United States, and ultimately to the country's involvement in the larger global conflict.
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(3 sig figs) Given the chemical equation below, with 202 grams of Barium Oxide being produced how many grams of Aluminum Oxide would you need? 3 BaSO4 + Al203 —>
3 Ba0 + Al2(SO4)3
Answers
44.4 g is the mass of Aluminum Oxide is required for the given chemical reaction 3 BaSO\(_4\) + Al\(_2\)O\(_3\)—> 3 BaO + Al\(_2\)(SO\(_4\))\(_3\).
It is the most fundamental characteristic of matter as well as one of the essential quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A body's bulk remains constant at all times. only in rare instances where an enormous quantity of energy is supplied to or taken away from a body.
3 BaSO\(_4\) + Al\(_2\)O\(_3\)—> 3 BaO + Al\(_2\)(SO\(_4\))\(_3\)
moles of BaO =202/ 153.3
=1.32
moles of Al\(_2\)O\(_3\) = 1/3×1.32=0.44
mass of Al\(_2\)O\(_3\) = 0.44×101.9=44.4 g
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A solution of dextrose contains 25.0 g solute in 250.0 g water. How should the percentage by mass of dextrose in this solution be calculated?
Answers
Answer:
9.10% dextrose
Explanation:
To find the mass percent, you need to use the following equation:
mass (g) of solute
Mass Percent = --------------------------------- x 100%
mass (g) of solution
You can plug the given values into the equation and solve to find the mass percent of dextrose. But first, you need to calculate the mass of the solution.
Mass (solute): 25.0 g
Mass (solution): 250.0 g + 25.0 g = 275 g
25.0 grams
Mass Percent = ------------------------ x 100%
275 grams
Mass Percent = 0.0909 x 100%
Mass Percent = 9.10%
A solution of dextrose contains 25.0 g solute in 250.0 g water. 9.10% is the percentage by mass of dextrose in this solution.
A component's concentration in a combination or compound can be expressed as a mass percent, also known as a weight percent. It shows how much of the total mass of the solution or mixture is made up of the solute's (component's) mass. In chemistry, mass percent is frequently employed and stated as a percentage.
Mass Percent = mass (g) of solute/ mass (g) of solution x 100%
Mass (solute): 25.0 g
Mass (solution): 250.0 g + 25.0 g = 275 g
Mass Percent =25.0 grams / 275 grams x 100%
Mass Percent = 0.0909 x 100%
Mass Percent = 9.10%
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Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. ????????????H(????) → ????????+(????????) + ????H −(????????) + x1????????
Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????????H(????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x2????????
Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????+(????????) + ????H −(????????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x3????J
Procedure Reaction
1 a. In the glassware menu, take out a 50 mL graduated cylinder and a foam cup. From the tools menu, take out the scale. From the solutions stockroom, move the distilled water and solid NaOH onto the workbench.
b. Transfer 50.0 mL of water to the foam cup. To do this, drag the carboy of water onto the graduated cylinder. (Before you release the mouse button, the cursor will show a "plus sign" to indicate that it is the recipient). A transfer textbar will appear, enter "50.0" mL and click on pour. (You will notice that the graduated cylinder now reads 50.0 mL).
c. Weigh about 1 gram of solid sodium hydroxide pellets, NaOH(s), directly into the foam cup and record its mass to the nearest 0.01 gram. To do this, place the foam cup on the balance so it registers a mass, then click the "Tare" button. Drag the NaOH bottle onto the foam cup. (When you release the mouse, the bottle will be tipped to show that it is in the pour mode). Next, type "1.00" grams into the transfer bar and then click pour. Note that the balance now reads the mass of the transferred NaOH. You may now take the cup off of the scale.
d. Click on the graduated cylinder, record its temperature and then drag it onto the foam cup. (When you release the mouse, the graduated cylinder will be tipped to show that it is in pour mode.) Enter "50.0" mL in the transfer bar and then click pour. Record the highest temperature. e. Remove the foam cup and graduated cylinder from the workbench. (Right click on the item and select "remove.")
Reaction 2
a. Take the 0.5 M HCl from the strong acids cabinet and a fresh foam cup and a fresh 50 mL graduated cylinder from the glassware menu and place them on the workbench. The procedure for Reaction 2 is the same as for Reaction 1 except that 50.0 mL of 0.50 M hydrochloric acid solution is used in place of the water. After measuring 50.0 mL of the HCl solution into the graduated cylinder, proceed as before with steps b-e of the procedure for Reaction 1.
Reaction 3
a. Take out a 25 mL graduated cylinder, a fresh foam cup, the 1.0 M HCl and the 1.0 M NaOH. (If you are running out of room on the workbench, you may remove the previously used chemicals.) Use the graduated cylinder to measure and transfer 25.0 mL of 1.0 M HCl into the foam cup. Pour an equal volume of 1.0 M sodium hydroxide solution into a clean graduated cylinder.
b. Record the temperature of each solution to the nearest 0.1 oC. Pour the sodium hydroxide solution into the foam cup and record the highest temperature obtained during the reaction.
Data and Analysis
Reaction 1Reaction 2Reaction 3
Mass of solution* (g) 1.03g 1.03g
Initial temperature(°C) 25oC 25OC 25OC
Maximum temperature (°C) 30.3oC 37oC 31.7oC
Temperature change (∆T)
Heat energy q (kJ)
Moles of NaOH
Molar heat of reaction (-q/mol) also known as Enthalpy change,
DH (kJ/mol)
Answers
Source https://www.physicsforums.com/threads/calorimetry-help-chemistry.399653/
The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:
Reaction Calculation:Calculating the Reaction 1:
\(NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)\)
\(NaOH\) mass = \(1\ g\)
\(H_2O\) mass = \(50 \ mL = 50\ g\)
water heat of \(s_p\) = \(4.186\ \frac{ J}{ g\ ^{\circ}C}\)
\(\Delta T\) = final temp - initial temp \(= 30.3 - 25 = 5.3^{\circ} \ C\\\)
Therefore
Calculating the releasing heat
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 5.3 J
= 1109.3 J
Calculating the \(NaOH\) mass \(= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole\)
Calculating the releasing heat per mole:
\(\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ\)
Thus
\(\to X_1 = 44.4\ KJ\)
Calculating the Reaction 2:
\(NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\\)
Calculating the net ionic from the equation:
\(NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)\)
Calculating the \(NaOH\) mass:
\(= 1\ g = \frac{1 }{ 40} = 0.025\ mole\)
Calculating the \(HCl\) mass:
\(= 50\ mL = 50\ g\) [ density = 1 approx]
sp heat of the solution \(= 4.186 \frac{J}{g\ ^{\circ}C}\) [ assume the sp heat same as water]
\(\Delta T\) = final temp - initial temp \(= 36.97 - 25 = 11.97^{\circ} \ C\)
Calculating the releasing heat:
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 11.97 J
= 2505.3 J
Calculating the releasing heat per mole in \(NaOH\):
\(= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ\)
Thus
\(X_2 = 100.2 \ KJ\)
Calculating the Reaction 3:
\(Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ\)
Calculating the net ionic in the given equation
\(H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)\)
Calculating the volume of \(NaOH\):
\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)
Calculating the volume of HCl:
\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)
Calculating the total volume
\(= 50 \ mL = 50\ g\) { density = 1]
Calculating the sp heat in the solution
\(= 4.186 \frac{J}{ g \ ^{\circ} C}\) [ assumed the sp heat is the same as water]
\(\Delta T\) = final temp - initial temp \(= 31.7- 25 = 6.7^{\circ}\ C\)
Calculating the releasing heat
= mass × sp heat × \(\Delta T\)
= 50 × 4.186 × 6.7 J
= 1402.3 J
Calculating the releasing heat per mole in \(NaOH\):
\(=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ\)
Therefore
\(X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29\)
So, the difference is equal to zero.
\(\to X_2 = X_1 + X_3\)
This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)
Calculating the difference percentage:
\(= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%\)
The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of \(NaOH\).
\(\to 4 \times 1109.3\ J = 4437.2 \ J\\\\\)
Calculating the \(NaOH\) moles \(= \frac{4}{40} = 0.1\)
\(\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ\)
As a result, it has no bearing on the solution's molar heat.
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What is the speed of an electromagnetic wave that has a wavelength of 8.6 x 10-5 m?
Answers
Answer:
The speed of the given electromagnetic wave is 3 x 10⁸ m/s.
Explanation:
Electromagnetic wave is a type of energy that is commonly known as light energy. The speed of light in air is about 3 x 10⁸ meters per second (m/s).
All electromagnetic waves travel at the same speed which is equal to speed of light, approximately 3 x 10⁸ meters per second (m/s) through a vacuum or air.
Therefore, the speed of the given electromagnetic wave is 3 x 10⁸ m/s.
If the mass of 3.01 x1023 molecules of a pure substance is 8.0 g, which of the following could be the identity of the substance?
Answers
Answer:
8.0g
Explanation:
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When a substance undergoes a chemical reaction in a closed system, which of the following will NOT change? (select all that apply)
a. temperature
b. energy
c. density
d. mass
Answers
In a closed system, which is one where no matter can enter or leave, the total mass remains constant so mass will NOT change during a chemical reaction in a closed system and the correct option is option B and D.
In a closed system, the total mass remains constant according to the Law of Conservation of Mass, which states that mass cannot be created or destroyed in a chemical reaction. Therefore, during a chemical reaction in a closed system, the mass of the substances involved will not change.
There is no release or absorption of energy whereas the rearrangement of atoms and molecules can result in changes in density. It is important to note that while mass remains constant, the composition and arrangement of the substances can undergo significant transformations.
Thus, the ideal selection is option B and D.
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please help its difficult
Answers
Answer:
\(pounds\)
pounds pounds pounds
what properties of a natural resource make it useful for humans as a materials or energy source?
Answers
The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.
What are natural resources?The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.
Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.
Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.
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How many kilograms are there in 2642 gal. of a solution whose density youexperimentally determined to be 0.736 g/mL?
Answers
The formula for calculating the density of a substance will be used to get the required mass:
\(\text{Density=}\frac{Mass}{Volume}\)Given the following parameters;
\(\begin{gathered} \text{Density=0.736}\frac{g}{mL} \\ \text{Volume=2642gal} \end{gathered}\)Convert gallons to mL using the conversion rate.
\(\begin{gathered} 1\text{gal=}3785.41mL \\ 2642\text{gal}=(2642\cdot3785.41)=10,001,053.22mL \end{gathered}\)Substitute the given parameters into the formula as shown:
\(\begin{gathered} 0.736\text{g/ml}=\frac{Mass}{10,001,053.22mL} \\ \text{Mass}=10,001,053.22mL\times\frac{0.736g}{mL} \\ \text{Mass=}10,001,053.22\cancel{mL}\times\frac{0.736g}{\cancel{mL}} \\ \text{Mass}=7,360,775.17\text{grams} \end{gathered}\)Convert the mass in grams to kilograms
Recall that 1000g = 1kg
\(\begin{gathered} \text{Mass=}7,360,775.16grams\times\frac{1\operatorname{kg}}{1000\text{grams}} \\ \text{Mass}=\text{=}7,360,775.16\cancel{\text{grams}}\times\frac{1\operatorname{kg}}{1000\cancel{\text{grams}}} \\ \text{Mass}=7360.775\operatorname{kg} \end{gathered}\)Hence the required mass in kg that is in 2642 gal. of a solution whose density you experimentally determined to be 0.736 g/mL is 7360.775kg
11.0 mL of an unknown concentration of NaOH is titrated with 37.0 mL of 0.65 M HCI. What is the concentration of NaOH in molarity?
Answers
The concentration of NaOH in molarity is calculated to be equal to 2.186 M.
What is meant by concentration?Concentration of chemical substance expresses the amount of substance present in any mixture.
In a neutralization reaction between NaOH and HCl, the number of moles of HCl will be equal to the number of moles of NaOH.
n(NaOH) = n(HCl)
n is the number of moles.
n(HCl) = M(HCl) x V(HCl)
M is the molarity and V is the volume in liters.
n(HCl) = 0.65 M x 0.037 L = 0.02405 moles HCl
Since the number of moles of NaOH is the same as the number of moles of HCl, we can use the following formula to find the concentration of NaOH:
M(NaOH) = n(NaOH) / V(NaOH)
V(NaOH) = 11.0 mL / 1000 mL/L = 0.011 L
M(NaOH) = n(NaOH) / V(NaOH) = n(HCl) / V(NaOH)
M(NaOH) = 0.02405 moles / 0.011 L = 2.186 M
Therefore, the concentration of NaOH in molarity is 2.186 M.
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Can you help me solve number 3 ? Thank you
Answers
You are out hiking on a cold snowy day. You put on your battery-heated socks. In which direction is the thermal energy flowing?
There is no thermal energy in this scenario.
Thermal energy is moving from the air to your socks
Thermal energy is moving from your feet to your socks
Thermal energy is moving from your socks to your feet
Answers
The correct answer is that thermal energy is moving from your feet to your socks. The battery-heated socks work by using the heat generated by your body to warm your feet in cold weather.
The body produces heat, which is converted into thermal energy, and moves from your feet to the socks.
In order to warm your feet and make them more comfortable in cold weather, the socks use thermal energy. The thermal energy is only transferred in one direction, from your feet to the socks.
No more energy is produced because the battery-heated socks utilise your body's thermal energy to keep your feet warm.
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P4+O2=P2O3
What’s the balance of this equation?
Answers
Explanation:
P₄+O₂=P₂O₃; non-balanced
P₄+O₂=2P₂O₃; to add '2' on the right side; non-balanced
P₄+3O₂=2P₂O₃. to add '3' before O₂ in the left side; balanced
An experiment shows that 113 mL gas sample at pressure of 721mmHg changed to 901 mmHg.
What is the new volume?
Answers
Answer:
90.4 mL
Explanation:
Step 1: Given data
Initial volume of the gas (V₁): 113 mLInitial pressure of the gas (P₁): 721 mmHgFinal volume of the gas (V₂): ?Final pressure of the gas (P₂): 901 mmHgStep 2: Calculate the final volume of the gas
According to Boyle's law, the volume of a gas is inversely proportional to the pressure. We can calculate the final volume of the gas using the following expression.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 721 mmHg × 113 mL / 901 mmHg
V₂ = 90.4 mL
the valency of magnesium is 2 why
Answers
The valency of magnesium is 2 because it has two valence electrons in its outermost shell. Magnesium belongs to the second group of the periodic table, which means it has two electrons in its outermost shell or valence shell. In order to achieve a stable configuration, magnesium tends to lose these two valence electrons to form a positively charged ion with a charge of 2+. This makes magnesium a bivalent or divalent element with a valency of 2.
Answer:
Because the outer shell of magnesium contains 2 atoms
A female spinach plant with flat (Ff) leaves is crossed with (pollination and fertilization occur) a male spinach plant with crinkly (ff) leaves. Explain what genes and traits the offspring will inherit. (Use the punnett square from your previous questions)
Your explanation should:
Identify the type of reproduction.
Compare the genetic variation among offspring (cause and effect)
Include a model to support your written response.
PLEASE HELP 100PTS
Answers
Answer:
the genes and traits of the offspring is a 50/50 chance.
Explanation:
The type of reproduction has 2 parents involved
At 20C what is the molar mass of a gas with a denisty of 1.02g/L at 2.13atm
Answers
The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.The molar mass of an element or compound is the mass of one mole of that substance. A mole is the SI unit for the amount of a substance.
It's defined as the amount of a substance that contains the same number of entities as there are atoms in 12 grams of carbon-12.Molar mass (M) = mass (m) ÷ amount of substance (n)So, M = m/n
Where m is the mass in grams and n is the number of moles. The unit of molar mass is grams per mole (g/mol).
The ideal gas law is used to calculate the molar mass of a gas. The ideal gas law is:P V = n R T,Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Convert the density to grams per liter: 1.02 g/L.
The density is mass/volume, thus 1.02 g/L means that 1 liter of the gas weighs 1.02 g.
This means that 1 mole of gas will occupy 22.4 L (at standard temperature and pressure, STP).Calculate the number of moles of gas using PV = nRT.P = 2.13 atmV = 22.4 L (at STP)R = 0.0821 L·atm/K·molT = 273.15 K + 20 K = 293.15 K
Thus, n = PV/RT = (2.13 atm × 22.4 L)/(0.0821 L·atm/K·mol × 293.15 K) = 0.973 mol
Calculate the molar mass (M) using M = m/n.m = density × volume = 1.02 g/L × 22.4 L = 22.848 gM = m/n = 22.848 g/0.973 mol = 23.5 g/mol Convert to units of grams per mole: 23.5 g/mol
The molar mass of a gas with a density of 1.02 g/L at 2.13 atm and a temperature of 20°C is 47.9 g/mol.
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A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution
Answers
Answer:
\(\rho_s=1.07g/cc^3\)
Explanation:
From the question we are told that:
Mass \(M=5.29g\)
Volume \(V=5.00mL=>5.0cc^3\)
Generally the equation for Specific Gravity momentum is mathematically given by
\(Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w\)
\(g=\frac{ \rho_s} { \rho_w}\)
\(\rho_s=\frac{ g} { \rho_w}\)
\(\rho_s=\frac{ 5.29} { 5}\)
\(\rho_s=1.07g/cc^3\)
The specific gravity of this solution is = 1.06.
Specific gravity of a solution:The specific gravity of a solution is the mass of a unit volume of a substance to the mass of a unit volume of a given reference material.
Therefore specific gravity of the solution can be calculated as follows:
\(sg = \frac{density. of . substance}{density . of . water} \)
But, density of substance (salt): mass/volume
mass = 5.29g
volume = 5.00mL
Therefore density = 5.29/5
= 1.06g/ml
But density of water is = 1 g/ ml
Therefore, specific gravity = 1.06/1
= 1.06
The specific gravity of a solution is 1.06.
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Determine the number of atoms of C in 25.6 grams of C₁₂H₂₂O₁₁
Answers
There are 5.403×10\(^23\) atoms of carbon in 25.6 grams of sucrose which is in relation with the number of moles.
What is a mole?Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.
It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.
It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass in grams present in one mole of atoms is its atomic mass.
Number of atoms of carbon can be determined by calculating number of moles of carbon which is 25.6/242.3=0.074 moles .As 1 mole has 6.022×10\(^23\) atoms
∴0.074 moles has 4.503×10²² moles
Number of carbon atoms in 1 molecule of sucrose is 12
∴number of carbon atoms in 4.503×10²² molecules is 12×4.503×10²²=5.403×10²³ atoms
Therefore, there are 5.403×10²³ atoms in 25.6 g of sucrose.
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Calculate the number of grams of platinum in 0.00808 moles Pt.
Answers
Answer:
1.58 g Pt
Explanation:
one mole of platinum weighs 195.09 grams (195.09 g/mol).
to convert moles of platinum to grams, we simply multiply the given moles of platinum by 195.09 to convert it to grams.
0.00808 x 195.09 = 1.576 g
electrons have ---------------------- charge
Answers
Answer:
.k;
Explanation:
A powder contains feso47h2o
Answers
The mass of FeSO4*7H2O in the sample is 1.21 grams.
Calculate moles of Fe2O3
moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3
moles of Fe2O3 = 0.348 grams / 159.69 g/mole = 0.00218 moles
Calculate moles of Fe
4 Fe + 3O2 → 2Fe2O3
For 4 moles of Fe consumed there is 2 moles of Fe2O3 produced
This means it has a ratio 2:1
So 0.00218 moles of Fe2O3 produced , there is 2*0.00218 = 0.00436 moles of Fe consumed
Calculate moles of FeSO4*7H2O
Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2
For 1 mole of Fe consumed there is 1 mole of FeSO4*7H2O produced
This means for 0.00436 moles there is 0.00436 moles of Fe2SO4*H2O produced
Calculate the mass of FeSO4*7H2O in the sample
mass of FeSO4*7H2O = 0.00436 moles * 278.01 g/mole = 1.212 g
The mass of FeSO4*7H2O in the sample is 1.21 grams.
Complete question: A powder contains FeSO4⋅7H2O (molar mass=278.01 g/mol), among other components. A 3.930 g sample of the powder was dissolved in HNO3 and heated to convert all iron to Fe3+. The addition of NH3 precipitated Fe2O3⋅xH2O, which was subsequently ignited to produce 0.348 g Fe2O3. What was the mass of FeSO4⋅7H2O in the 3.930 g sample?
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i. using proper arrow formalism, draw a mechanism for the formation of hcocl (reaction i), followed by a mechanism for the formation of hcon(ch3)2 (reaction ii). to simplify your work, use your organic chemistry textbook as reference. you may do this by hand or using chemdraw.
Answers
Reaction i: Formation of HCOCI
The reaction mechanism involves the reaction between HCl and CO in the presence of a catalyst. The steps involved are:
Initiation: HCl dissociates to form a hydrogen radical (H*) and a chlorine radical (Cl*) in the presence of light.
HCl + light → H* + Cl*
Propagation:
The hydrogen radical reacts with CO to form HCO* (formyl radical).
H* + CO → HCO*
The formyl radical reacts with HCl to form HCOCI and a chlorine radical.
HCO* + HCl → HCOCI + Cl*
Termination:
The reaction terminates when the radicals react with each other to form stable products.
H* + Cl* → HCl
HCO* + HCO* → CO₂ + H₂
Reaction ii: Formation of HCON(CH₃)₂
The reaction mechanism involves the reaction between dimethylamine and phosgene. The steps involved are:
Formation of the intermediate:
Phosgene reacts with dimethylamine to form an intermediate, N,N-dimethylcarbamoyl chloride.
COCl₂ + (CH₃)₂NH → (CH₃)₂NCOCl
Formation of the product:
The intermediate reacts with water to form HCON(CH₃)₂ and HCl.
(CH₃)₂NCOCl + H₂O → HCON(CH₃)₂ + HCl
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Which strand of hydrocarbons is used to produce plastic?
O Strand 2
O Strand 3
O Strand 4
●Strand 1
Answers
The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.
Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.
Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.
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BRAINLIEST WITH THE RIGHT ANSWER
Families are grouped by _____________.
Does each family react the same?
Answers
Answer: All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods.
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Explanation:
True or False: The statement below is an interpretation.
"A gas was produced and we saw many bubbles."
O True
O False
Answers
A salt with a high melting point can be obtained from reaction between metal and
acid solution. The metal that used in this reaction is iron and the acid solution is
hydrochloric acid.
a. What is the chemical name of salt above?
Answers
Iron (II) chloride and hydrogen gas
Chemical name:
FeCl2 (aq) + H2 (g)
A 1.5 kg object with a heat capacity of 6.2 J/(g oC) increases in temperature from 10.3 C to 41.9 C. How much heat was absorbed in joules?
Answers
The heat absorbed in joules is 2938800J.
The phrase "specific heat" can also refer to the ratio between a substance's specific heat capacities at a given temperature and those of a reference substance at a reference temperature, such as water at 15 °C.
In-depth measurements of heat capacity with different denominators are connected to specific heat capacity as well. Instead, the molar heat capacity, whose SI unit is the joule per kelvin per mole is obtained when the amount of substance is quantified in terms of moles.
The volumetric heat capacity, whose SI unit is joule per kelvin per cubic metre is obtained if the amount is assumed to be the volume of the sample.
It is given that in the question that
Mass of the substance = 15kg = 15000g
Specific heat of the substance = 6.2 J/ g°C
Increase in temperature from 10.3 °C to 41.9 °C
Change in temperature =41.9 °C - 10.3 °C = 31.6°C
We have to find the heat absorbed
The amount of heat (q) which is absorbed (or evolved) by a substance of mass (m) in order to bring a temperature change of (ΔT) is :
\(q = mc\)Δ\(T\) = 15000g× 6.2J/ g°C x 31.6°C = 2938800J
The heat absorbed in joules is 2938800J.
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