Please help solve…………………

The confidence level in this report of survey of student atheletes concerning their gambling-related behaviors is equals to 87.88%.

The confidence interval when calculated with the two tails methods then it can be used to test the two tail hypothesis for the same parameter provided that the confidence level. We have, National Collegiate Athletic Association (NCAA) take a survey of randomly selected student athletes concerning their gambling-related behaviors.

repoted participation of students, x = 3547

Sample size,n = 5594

Margin of error, E = 1% = 0.01

The sample proportion is a number of successes divided by the sample size, p-cap = 3547/5594

= 0.6341

The margin of error is for a confidence interval for a proportion, which is determined by using the following formula is

\(CL = Zα/₂ \sqrt{ \frac{ \hat{p} \: (1- \hat{p})}{n} }\)

= Zα/₂√(1 - 0.6341)0.6341/5594

= 0.0064 Zα/₂

This margin of error also has to be equal to 1% or

0.0064 Zα/₂ = 0.01

=> Zα/₂ = 0.01/0.0064 ~ 1.55

The confidence level is the probability of obtaining this value or less extreme, determine the probability using z- table,

P(-1.55< Z < 1.55) = P(Z < 1.55) - P(Z < -1.55)

= 0.9394 - 0.0606 = 0.8788 = 87.8

Thus the confidence level is 87.88%.

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Answer:

210° or 60°

Step-by-step explanation:

The correct expansion of Taylor series generated by the function f(x) will be \($$\begin{array}{r}=\frac{2 \pi}{5}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2-\frac{7}{12}(x-1)^3-\frac{7}{40}(x-5)^5 \\\text { first five non term }\}\end{array}$$\)

From the definition of Taylor series we know that the Taylor series of the function f at a is \($$\sum_{n=0}^\alpha \frac{f^n(a)}{n !}(n-a)^n=f(a)+f^{\prime}(a)(n-a)+\frac{f^{'''}(a)}{2 !}(n-a)^2$$\)

where \($f(x)=7 \tan ^{-1} x+\frac{\pi}{20}$\)

\($$\begin{aligned}f^{\prime}(x) & =\frac{7}{1+x^2} \\f^{\prime \prime}(x) & =\frac{7 \cdot(-1) 2 x}{\left(1+x^2\right)^2}=-\frac{14 x}{\left(1+x^2\right)^2} \\f^{\prime \prime \prime}(x) & =-\frac{\left(1+x^2\right)^2 \cdot 14-14 x \cdot 2\left(1+x^2\right) \cdot 2 x}{\left(1+x^2\right)^4} \\& =\frac{56 x^2\left(1+x^2\right)-14\left(1+x^2\right)^2}{\left(1+x^2\right)^4}\end{aligned}$$\)

\($\begin{aligned} & =\frac{56 x^2-14-14 x^2}{\left(1+x^2\right)^3}=\frac{42^2-14}{\left(1+x^2\right)^3} \\ f^N(x) & =\frac{\left(1+x^2\right)^3 \cdot 84 x-\left(42 x^2-14\right) 3\left(1+x^2\right)^2 \cdot 2 x}{\left(1+x^2\right)^6} \\ & =\frac{84 x\left(1+x^2\right)-6 x\left(42 x^2-14\right)}{\left(1+x^2\right)^4} \\ & =\frac{84 x+84 x^3-252 x^3+84 x}{\left(1+x^2\right)^4}=\frac{168 x-168 x^3}{\left(1+x^2\right)^4}\end{aligned}$\)

here a=1

\($$\begin{aligned}f(1) & =7 \tan ^{-1} 1+\frac{\pi}{20} \\& =\frac{7 \pi}{4}+\frac{\pi}{20}=\frac{35 \pi+\pi}{20}=\frac{36 \pi}{20}=\frac{9 \pi}{5} \\f^{\prime}(1) & =\frac{7}{1+1}=\frac{7}{2} \\f^{\prime \prime}(1) & =-\frac{14}{(1+1)^2}=-\frac{14}{4}=-\frac{7}{2} \\f^{\prime \prime \prime}(1) & =\frac{42-14}{(1+1)^3}=\frac{28}{8}=\frac{7}{2} \\f^{i v}(1) & =0\end{aligned}$$\)

\($\begin{aligned} f^{\prime v}(1) & =0 \\ f^v(x) & =\frac{\left(1+x^2\right)^4\left(168-504 x^2\right)-\left(168-168 x^3\right)}{4\left(1+x^2\right)^3 \cdot 2 x} \\ & =\frac{\left.\left(1+x^2\right)^8\right)\left(168-504 x^2\right)-8 x\left(168-168 x^3\right)}{\left(1+x^2\right)^5} \\ f^v(1) & =\frac{2(168-504)-8(168-168)}{2^5}\end{aligned}$\)

\(=-\frac{336}{24}=-\frac{42}{2}=-21\)

Taylor series polyromin of \($7 \tan ^{-1} x+\frac{\pi}{20}$\) is \($f(1)+f^{\prime}(1)(x-1)+\frac{f^{\prime \prime}(1)}{2 !}(x-1)^2+\frac{f^{\prime \prime \prime}(1)}{3 !}(x-1)^3$$$+\frac{f^{12}(1)}{4 !}(x-1)^4+\frac{f^2(1)}{5 !}(x-1)^5+\cdots \cdot$$\)

\($=\frac{9 \pi}{5}+\frac{7}{2}(x-1)+\frac{-\frac{7}{2}}{2 !}(x-1)^2+\frac{-\frac{7}{2}}{3 !}(x-1)^3$$+0+\frac{-21}{5 !}(x-5)^5$\)

first five non-zero term

\($=\frac{9 \pi}{5}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2-\frac{7}{12}(x-1)^3+0-\frac{21}{120}(x-5)^5$$=\frac{9 \pi}{5}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2-\frac{7}{12}(x-1)^3-\frac{7}{40}(x-5)^5$\)

(first five non zero term)

The correct question should be

Use the definition to find the first five nonzero terms of the Taylor series generated by the function \(f(x)=7 \tan ^{-1} x+\frac{\pi}{20}\) about the point  a=1

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Answer:

53

Step-by-step explanation:

Answer:

\(\sqrt[2]{3^7}\)

Step-by-step explanation:

\(\sqrt[2]{3^7}\)

The top number is the power and the bottom of the fraction is the root

According to the given inforamtion, the equation of the line that passes through (-4,7) and is perpendicular to \(y=\frac{4}{5}x-\frac{3}{5}\) is \(y=-\frac{5}{4}x+2\).

This same slope seems to be the amount "m" multiplication on the x, and indeed the y-intercept is "b" that whenever a straight line is given by the equation "y = mx + b." (that is, the point where the line crosses the vertical y-axis). The logical name for this useful line equation variety is "slope-intercept form."

We must ascertain the new line's slope. Given that the slope of the given line is \(\frac{4}{5}\), the negative reciprocal of the slope of the perpendicular line will be \(\frac{4}{5}\), that is \(-\frac{5}{4}\).

We can now determine the equation of the new line using the point-slope form of a line:

\(y - y_1 = m(x - x_1)\)

where m is the slope we just found and \((x_1, y_1) = (-4,7)\) is the given point. Substituting in the values, we get:

\(y - 7 = -\frac{5}{4}(x + 4)\)

To write this in slope-intercept form \(y=mx+b\), we can simplify and solve for y:

\(y - 7 &= -\frac{5}{4}(x + 4) \\\\y &= -\frac{5}{4}x - 5 + 7 \\\\y &= -\frac{5}{4}x + 2 \\\)

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The domain of the relation of the graph representing a relation where x represents the independent variable and y represents the dependent variable is {−4, −2, 0, 3, 5}.

The domain of a relation is the set of all possible input values (independent variable) for which the relation is defined.

Looking at the given points, the x-coordinates are -4, -2, 0, 3, and 5. So, the possible input values are -4, -2, 0, 3, and 5.

Therefore, the domain of the relation is {−4, −2, 0, 3, 5}.

Hence, the correct option is {−4, −2, 0, 3, 5}.

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Answer: 7.2

Step-by-step explanation:

Necesitas convertir 12% a un decimo y te da 0.12 luego multipicas eso por 60 y la respuesta es 7.2

Answer:

6666

Step-by-step explanation:

(a) The closed form for ∑2 is 2.

(b) The closed form expression for ∑3 is 24.

(c) The closed form for the sum ∑n = 0(― 1)² ― 1 is n(1 - n) / 2.

(d) The value of -3 matches the manual computation of the four terms.

Our closed form solution is correct.

To find the closed form for ∑2, we can use the formula for the sum of the first n terms of an arithmetic series:

∑2 = n(a + l) / 2

In this case, a = 2 (the first term) and l = 2 (the last term) since we are summing a series of 2's.

We also know that there is only one term, so n = 1.

Substituting these values into the formula, we have:

∑2 = 1(2 + 2) / 2

= 4 / 2

= 2

The formula for the sum of the first n terms of an arithmetic series is:

∑n = n(a + l) / 2

In this case, we have a = 3 (the first term), l = 13 (the last term), and n = 3 (the number of terms).

Substituting these values into the formula, we get:

∑3 = 3(3 + 13) / 2

= 3(16) / 2

= 48 / 2

= 24

The formula we developed in class is:

∑n = n(a + a + (n - 1)d) / 2

In this case, we have a = 0 (the first term) and d = -1 (the common difference).

Substituting these values into the formula, we get:

∑n = n(0 + 0 + (n - 1)(-1)) / 2

= n(0 - n + 1) / 2

= n(1 - n) / 2

To test the closed form solution for ∑3 = 0(― 1)² ― 1, we substitute n = 3 into the closed form expression we derived in part (c):

∑3 = 3(1 - 3) / 2

= 3(-2) / 2

= -6 / 2

= -3

Now, let's manually compute the sum of the first four terms of ∑3 = 0(― 1)² ― 1:

0(― 1)² ― 1 + 1(― 1)² ― 1 + 2(― 1)² ― 1 + 3(― 1)² ― 1

= 0 - 1 - 2 - 3

= -6

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Answer:

angle x is 69. angle y is 69 as well

Step-by-step explanation:

The true statements are

The function g(x) is given as:

\(g(x) = -12(\frac 13)^x\)

Set x = 0, to determine the y-intercept

\(g(0) = -12(\frac 13)^0\)

g(0) = -12

From the table, we y-intercept of f(x) is

f(0) = -12

This means that they have the same y-intercept

Because the functions have negative initial values, they would approach negative infinity as x approaches negative infinity

Hence, the true statements are (d) and (e)

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On comparing, we get {a} = 0 and {b} = 4.

The general form of a complex number is -

z = a + ib

Given is the number as -

√-16

We can write the number √-16 in the form of (a + ib) as follows. We have -

√-16

√(- 1 x 16)

√(i² x 16)

√i² x √16

i√16

0 + i√16

0 + 4i

Therefore, on comparing, we get {a} = 0 and {b} = 4.

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The true statement are

2. <1 + <3 = 180 because form a straight angle.

3.  ∠3 ≅ ∠6 because they are alternate interior angles.

4. ∠1 and ∠6 are supplementary because ∠3 ≅ ∠6 and m∠1 + m∠3 = 180°.

What are parallel lines?

Two lines in a plane are said to be parallel if they do not intersect when extended infinitely in both directions.

As, from the figure

1. <3 = <2 because of vertically opposite angle.

Hence, it is false

2. <1 + <3 = 180 because form a straight angle.

Hence, it is true.

3.  ∠3 ≅ ∠6 because they are alternate interior angles.

Hence, it is true.

4. ∠1 and ∠6 are supplementary because ∠3 ≅ ∠6 and m∠1 + m∠3 = 180°.

Hence, it is true.

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The answer to the given expression is 2

To "solve" or "isolate" a variable is to place it on its own side of the equation.

All other variables or constants should be moved to the opposite side of the equation using inverse operations. The operations must be applied to both sides of the equation in order to maintain the equation's balance.

Given : x = 5 and y = 7

To find :  \(\frac{y^{2} - x }{y + 3x}\)

When we substitute the values mentioned above in this above expression we get;

\(\frac{7^{2}- 5 }{ 7+ 3X5}\)

⇒ \(\frac{49 - 5}{ 7 + 15}\)

⇒ \(\frac{44}{22}\)

On dividing it with 22 we get

\(\frac{44}{22}\) = 2

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La rama de las matemáticas que se encarga de recolectar, organizar, analizar e interpretar la información se llama estadística.

La medida de tendencia central que se obtiene al sumar todos los datos y dividir el resultado entre el número total de datos se llama media aritmética. La fórmula para calcular la media aritmética es:

media = (x1 + x2 + ... + xn) / n

Por ejemplo, si tenemos el conjunto de datos {3, 5, 7, 9, 11}, podemos calcular la media aritmética de la siguiente manera:

media = (3 + 5 + 7 + 9 + 11) / 5 = 7

Por lo tanto, la media aritmética de este conjunto de datos es 7.

Las medidas de dispersión se utilizan para medir la variabilidad o dispersión de un conjunto de datos. Hay varias medidas de dispersión, entre las cuales se incluyen:

Rango: es la diferencia entre el valor máximo y el valor mínimo de un conjunto de datos. La fórmula para calcular el rango es:

rango = valor máximo - valor mínimo

Por ejemplo, si tenemos el conjunto de datos {3, 5, 7, 9, 11}, el valor máximo es 11 y el valor mínimo es 3, por lo que el rango es:

rango = 11 - 3 = 8

Desviación estándar: es una medida de dispersión que indica cuánto se alejan los datos de la media aritmética.

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Answer:

no

Step-by-step explanation:

if the y 79 was changed to 49 then yes(in that case y=x^2) but the x 7 y 79 messes the relationship up.

Answer:

See below

Step-by-step explanation:

Given polynomial is: \( 17x^2 - x\)

a. Terms: \( 17x^2, \: \&\: - x\)

b. 17 and - 1

c. Binomial or quadratic polynomial

Answer:

10x² - 12

Step-by-step explanation:

4x² - 7 + 6x² - 5 (combine like terms)

10x² - 12

Answer:

10x² - 12

Step-by-step explanation:

(4x² - 7) + (6x² - 5)

4x² + 6x² = 10x²

-7 -5 = -12

= 10x² - 12

The expression is equivalent to 20q^17w^19.

Expression in mathematics is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given that;

10q^5w^7/2w^3•4(q^6)^2/w^-5

Now,

To simplify the expression, we can use the following rules of exponents:

To multiply two powers with the same base, add their exponents

\($$\frac{10q^5w^7}{2w^3} \times \frac{4(q^6)^2}{w^{-5}}$$$$= \frac{10q^5w^7}{2w^3} \times \frac{4q^{12}}{\frac{1}{w^5}}$$$$= \frac{10q^5w^7}{2w^3} \times \frac{4q^{12}w^5}{1}$$$$= \frac{10 \times 4 q^5 q^{12} w^7 w^5}{2 w^3}$$$$= \frac{40 q^{17} w^{12}}{2 w^3}$$$$= 20 q^{17} w^{9}$$\)

Therefore, by the expression the answer will be 20q^17w^19.

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Answer:ni

Step-by-step explanation:

Answer:

\(m=\frac{1}{2}\)

Step-by-step explanation:

Slope Formula: \(m=\frac{y_2-y_1}{x_2-x_1}\)

Step 1: Find 2 points

(0, 2) y-int

(-4, 0) x-int

Step 2: Plug into slope formula to find slope m

\(m=\frac{2-0}{0-(-4)}\)

\(m=\frac{2}{0+4}\)

\(m=\frac{2}{4}\)

\(m=\frac{1}{2}\)

Answer:

  384

Step-by-step explanation:

We assume your function is supposed to be ...

  f(x) = 12(2^x)

When x=5, the value is ...

  f(5) = 12(2^5) = 12(32) = 384

There will be 384 insects after 5 weeks.

The equation of the line parallel to the line  7x - 4y = - 5 and passing through (16, - 4) is y = (7/4)x - 32.

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

We know lines parallel to each other have the same slope which is

7x - 4y = - 5 ⇒ - 4y = - 7x - 5 ⇒ y = (7/4)x + (5/4) to our required line will also have the same slope passing through the point  (16, - 4).

Therefore, - 4 = 16(7/4) + b.

- 4 = 28 + b.

b = - 32.

Therefore, y = (7/4)x - 32 is the required line.

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Answer:

B

Step-by-step explanation:

25/10=2.5

Answer:

2.5

Step-by-step explanation:

Answer:

wpic

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

Answer:

sum

Step-by-step explanation:

quotient is the result of division

sum is the result of addition

product is the result of multiplication

difference is the result of subtraction

its ez math

The distance between the fire and station B is 10.7miles

The sine rule states that if a, b and c are the lengths of the sides of a triangle, and A, B and C are the angles in the triangle; with A opposite a, etc., then a/sinA=b/sinB=c/sinC.

The angle at A = 90- 35

= 55°

The angle at B = 90-49

= 41°

Angle at the fire = 180-(41+55)

= 180-96 = 84°

Using sine rule

sin84/13 = sin55/x

xsin84 = 13sin55

0.995x = 10.65

x = 10.65/0.995

x = 10.7 miles

Therefore the distance between the fire and station B is 10.7 miles.

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