Please help peeps
Thanks

Answer:

$1.67

Step-by-step explanation:

6 divided by $3.60 = $1.67

m > 650 miles

A mileage over 650 miles makes company A cheaper than B.

1) Gathering the data

Company A

$127 (unlimited mileage)

Company B

$75 + 0.08m

2) To find out the mileage that makes Company A cheaper than Company B, we can write out the following:

3) Hence when we drive over 650 miles the Company A becomes cheaper than B.

Answer:

a. 3/7

b. Juan probably missed the reverse operator where he multiplies the reciprocal of the number he's dividing. For example, -2/21 / 1/7=-2/21*7/1.

Step-by-step explanation:

a. -2/7 / (-2/21 / 1/7)=

-2/7 / (-2/21*7)=

-2/7 / -14/21=

-2/7*21/(-14)=

-2*21/(7*-14)=

-42/-98=3/7

Answer:

Number of different options for Ms. Garcia are

3 * 2 * 8 = 48

So 48 options

Step-by-step explanation:

There are m ways to make 1st selection and n ways to make 2nd selection and p ways to make 3rd selection so thats why I did (m * n * p)

Answer:

someone needs to answer this because i dont know

it.

Step-by-step explanation:

he is correctStep-by-step explanation:

The 95% confidence interval for the difference between the two population proportions is -0.022 < p₁ - p₂ < 0.222.

Given that,

In a survey, it was discovered that 68% of women and 78% of men preferred computer-assisted education to lectures, respectively. Each sample contained 100 people that were chosen at random.

We have to calculate the 95% confidence range for the difference between the two proportions.

We know that,

The 95% confidence interval for difference between two population proportions is given as follows :

\(((\bar p_{1} -\bar p_{2})\)±\(Z_{0.05/2}\sqrt{\frac{PQ}{n_{1} } +\frac{PQ}{n_{2} }} })\)

Here,

p₁ is 0.78

p₂ is 0.68

n₁ is 100

n₂ is 100

Z is 1.96

P is 0.73

Q is 0.27

So,

((0.78-0.68)±\(1.96\sqrt{\frac{(0.73)(0.27)}{100 } +\frac{(0.73)(0.27)}{100 }} })\)

(0.10±0.122)

(0.10-0.122,0.10+0.122)

(-0.022,0.222)

Therefore, The 95% confidence interval for the difference between the two population proportions is -0.022 < p₁ - p₂ < 0.222.

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Answer:

486 alunos

Step-by-step explanation

2 X 3 = 6

6 X 3 = 18

18 X 3 = 54

54 X 3 = 168

168 X 3 = 486

In linear equation ,242 total number of members within 5 weeks.

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included.

The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables."

here, we have,

a manual computation on how 1 member recruits his members until week 5. Then multiply the sum by 2.

                           old      new

1:   1

2:   1 x 3 = 3 ⇒        1         3       *only new members recruit 3 more

3:   3 x 3 = 9 ⇒        4         9

4:   9 x 3 = 27⇒     13       27

5: 27 x 3 = 81 ⇒    40       81

40 + 81 = 121. Total number of members under 1 founding member.

121 x 2 founding members = 242 total number of members within 5 weeks.

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Answer:

x=3

Step-by-step explanation:

the 3 angles of a triangle equal 180

you add 105 and 46, which equals 151

you subtract 151 from 180 to see what the missing angle is (29)

you would make 6x+11 equal to 29

-subtract 11 from 29= 18

6x/6, 18/6

the answer is 3

hope this helps! :)

The value of x in the given triangle is 3°.

A triangle is an object with three sides, three edges and three vertices. the sum of angles in a triangle is 180 degrees

Area of a triangle = 1/2 x base x height

Given that the sum of angles in a triangle is equal to 180 degrees. The sum of angles in the given triangle would also be equal to 180. This can be represented with this equation:

105° + 46° + (6x + 11)° = 180°

Combine similar terms

162° + 6x° = 180°

6x° = 180° - 162°

6x = 18°

Divide both sides of the equation by 6

x = 3°

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Answer:

\(\boxed {\boxed {\sf 7.5 \ feet}}\)

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

\(h=-16t^2+25t+6\)

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

\(h= -16(1.5)^2+25(1.5)+6\)

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

\(h= -16(2.25)+25(1.5)+6\)

Multiply.

\(h= -36+25(1.5)+6\)

\(h= -36+37.5+6\)

Add.

\(h=1.5+6=7.5\)

This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

Answer:

6

Step-by-step explanation:

Median = (n+1) ÷ 2

Median = total frequency which is 55 + 1 = 56 ÷ 2 = 28th term.

So to find this term you add the frequencies until you get 28 or a number higher than 28.

3+1+10+15 = 29.

We got 29 when we got to the column of shoe size 6. So the Median is in shoe size 6.

Given vectors a = -(3, -6) and b = 3(0, -6), we can compute the vector operations. The results are as follows: a + b = (0, -12), a - b = (-6, 0), 4a + 5b = (-12, -90), 4a - 5b = (6, 78), and ||a|| = 6.

To compute vector addition, we add the corresponding components of the vectors. a + b = (-3 + 0, -6 + (-18)) = (0, -24).

For vector subtraction, we subtract the corresponding components. a - b = (-3 - 0, -6 - (-18)) = (-3, 12).

To find the scalar multiplication, we multiply each component of the vector by the scalar. 4a + 5b = 4(-3, -6) + 5(0, -18) = (-12, -24) + (0, -90) = (-12 + 0, -24 + (-90)) = (-12, -114).

Similarly, 4a - 5b = 4(-3, -6) - 5(0, -18) = (-12, -24) - (0, -90) = (-12 - 0, -24 - (-90)) = (-12, 66).

The magnitude of a vector, denoted as ||a||, is computed using the formula ||a|| = √(a₁² + a₂²). For vector a = (-3, -6), ||a|| = √((-3)² + (-6)²) = √(9 + 36) = √45 = 6.

In summary, a + b = (0, -12), a - b = (-6, 0), 4a + 5b = (-12, -90), 4a - 5b = (6, 78), and ||a|| = 6.

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Answer:

0, 5%, 1/5, 5

5% is equal to 5÷100=0,05

1/5 is equal to 1÷5=0,2

The given distribution of the most popular car colors for 2010 is presented in a bar graph. This type of plot effectively displays the categorical data and their corresponding percentages. Therefore, the appropriate plot for representing the given data is the bar graph provided initially.

Now let's consider the options:

a) A time series plot: A time series plot is used to visualize data over a specific period of time. Since the given data represents the distribution of car colors for a single year (2010), a time series plot is not appropriate in this case. Therefore, option a) is not suitable.

b) A pie chart: A pie chart is commonly used to represent parts of a whole. In this case, the data is already presented in a bar graph, which effectively displays the proportions of each car color. Although a pie chart can also represent proportions, it may not provide the same level of clarity as the bar graph. Therefore, option b) is not necessary.

c) A histogram: A histogram is used to visualize the distribution of continuous or discrete data across intervals or bins. In this case, the data is categorical, representing specific car colors and their corresponding percentages. Therefore, a histogram is not appropriate.

d) All of the above: Since options a) and c) are not suitable for representing the given data, the correct answer is not d) "All of the above."

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The bar graph below gives the distribution of the most popular colors for cars and light trucks sold globally in 2010. Most popular car colors (2010) CE 20 15 Percent 10 Silver Black While Blue Gray Red Color Brown Other Which of the following kinds of plots would also be appropriate for these data? a) a time series plot b) a pie chart a histogram. a) a time series plot b) a pie chart. c) a histogram. d) All of the above

Answer:

The answer is D

\( {x}^{2} + 6x + 9 = 0 \\ x = - 3\)

That's the only equation will get us one point

The general solution of the given differential equation, 4xy' + y = 20x, can be found by solving for y in terms of x. The general solution is y = 5x + Cx⁻⁴, where C is an arbitrary constant.

To find the general solution, we can start by rearranging the equation to isolate the derivative term. Dividing both sides of the equation by 4x, we get y' + (1/4xy) = 5. This is a first-order linear ordinary differential equation, which can be solved using the method of integrating factors.

To proceed with the integrating factor method, we multiply the entire equation by the integrating factor, which is e^(∫(1/4x) dx). Integrating (1/4x) with respect to x gives us ln|x|/4, so the integrating factor is e^(ln|x|/4) = |x|⁻¹/⁴.

Multiplying the integrating factor by both sides of the equation, we obtain |x|⁻¹/⁴y' + (1/4xy)|x|⁻¹/⁴ = 5|x|⁻¹/⁴. Simplifying the left side, we have y' |x|⁻¹/⁴ + (1/4x) |x|⁻¹/⁴ = 5|x|⁻¹/⁴.

Integrating both sides with respect to x, we get ∫(y' |x|⁻¹/⁴) dx + ∫((1/4x) |x|⁻¹/⁴) dx = ∫(5|x|⁻¹/⁴) dx. The first integral on the left side can be simplified as ∫(y' |x|⁻¹/⁴) dx = y |x|⁻¹/⁴. The second integral can be evaluated as ∫((1/4x) |x|⁻¹/⁴) dx = (1/4) ∫(|x|⁻³/⁴) dx = (1/4) (4/1) |x|⁻³/⁴ = |x|⁻³/⁴.

Applying the integrals and simplifying, we have y |x|⁻¹/⁴ + |x|⁻³/⁴ = 5|x|⁻¹/⁴ + C, where C is the constant of integration.

Rearranging the equation, we get y |x|⁻¹/⁴ = 5|x|⁻¹/⁴ - |x|⁻³/⁴ + C. Multiplying both sides by |x|⁻¹/⁴, we obtain y = 5x + Cx⁻⁴, which is the general solution of the given differential equation. The constant C represents the arbitrary constant that accounts for all possible solutions of the equation.

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The speed of the airplane in still air is 275 miles/hour and speed of wind is  55 miles/hour

What is the relation between Speed , Distance and Time ?

Speed = Distance/Time  --- This reveals how quickly or slowly an object is moving. It gives the amount of time it took to travel a certain distance divided by the distance traveled. Speed is inversely correlated with time and directly correlated with distance.

Given,  

Distance = 660 miles

When with the wind the time is = 2 hours

And, When against the wind the time is = 3 hours

Let, the speed of the plane in still air = x

the speed of wind = y

We know, speed = distance / time

so, When with the wind the speed is (s1) = x + y

When against the wind the speed is (s2) = x - y

Next,

s1 = x + y = 660 / 2

s1 = 330 miles/hour

s2 = x - y = 660/3

s2 = 220 miles/hour

Add the speed,

s1 + s2  = 330 + 220

= x + y + x - y = 550

=2x = 550

x =  275 miles/hour (speed of the airplane in still air)

x + y = 330

275 + y = 330

y = 330 - 275

y = 55 miles/hour (speed of wind)

Therefore, the speed of the airplane in still air is 275 miles/hour and speed of wind is  55 miles/hour

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A linearly independent system of vectors v1, v2, ..., vn in a vector space v is a basis if and only if the number of vectors, n, is equal to the dimension of v.

To prove that a linearly independent system of vectors v1, v2, ..., vn in a vector space v is a basis if and only if n = dim v, we need to show both directions of the statement.

If the system of vectors is a basis, then n = dim v:

Suppose the system of vectors v1, v2, ..., vn is a basis for the vector space v.

By definition, a basis spans the entire vector space, which means every vector in v can be written as a linear combination of v1, v2, ..., vn.

Since the system is a basis, it must also be linearly independent, which implies that no vector in the system can be expressed as a linear combination of the other vectors.

Thus, the number of vectors in the system, n, is equal to the dimension of the vector space v, denoted as dim v.

If n = dim v, then the system of vectors is a basis:

Suppose n = dim v, where n is the number of vectors in the system and dim v is the dimension of the vector space v.

Since dim v is defined as the maximum number of linearly independent vectors that can form a basis for v, we know that any system of n linearly independent vectors in v will be a basis for v.

Therefore, the system of vectors v1, v2, ..., vn is a basis for the vector space v.

Combining both directions of the proof establishes that a linearly independent system of vectors v1, v2, ..., vn in a vector space v is a basis if and only if n = dim v.

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The Normal model is a good approximation for the sampling distribution.

a) According to the Central Limit Theorem, the theoretical mean and standard deviation for a sample size of 20 should be 0.05 and 0.02, respectively. For a sample size of 100, the theoretical mean and standard deviation should be 0.05 and 0.01, respectively.

b) The observed mean and standard deviation for a sample size of 20 was 0.052 and 0.021, respectively. For a sample size of 100, the observed mean and standard deviation was 0.051 and 0.012, respectively. These values are fairly close to the theoretical values.

c) Looking at the histograms in Exercise 1, I would be comfortable using the Normal model as an approximation for the sampling distribution at a sample size of 100.

d) The Success/Failure Condition states that the sample size should be large enough for the sampling distribution of the sample proportions to be approximately normal. Since I chose a sample size of 100, which satisfied the condition, I can be confident that the Normal model is a good approximation for the sampling distribution.

The sample size of 100 is large enough for the sampling distribution of the sample proportions to be approximately normal, and the observed mean and standard deviation is close to the theoretical values. Therefore, the Normal model is a good approximation for the sampling distribution.

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Answer:

The slope of the line through the points is -5/7

Step-by-step explanation:

Here, we want to calculate the value of the slope through the lines

Mathematically;

m = y2-y1/(x2-x1)

Where (x1,y1) = (-4,2)

and (x2,y2) = (3,-3)

Substituting these values, we have;

m = (-3-2)/(3-(-4)) = -5/7 = -5/7

The slope of the line through (-4, 2) and (3, -3) is; -5/7

According to the question;

The slope, m of the line is given mathematically as;

Therefore, in this case;

Slope, m = -5/7

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1.  [1  2  3]   [x1]   [2]

 [0  1 -1]   [x2] = [8]

 [1  2  1]   [x3]   [4]

2. x3 equals to -11/3.

To solve for x3 using Cramer's rule, we need to find the determinant of the coefficient matrix and then form three additional matrices by replacing the third column of the coefficient matrix with the constants vector. The determinant of the coefficient matrix is:

| 1  2  3 |

| 0  1 -1 |

| 1  2  1 | = 1(1-4)-2(3-1)+3(2-2) = -3

Next, we form three matrices by replacing the third column of the coefficient matrix with the constants vector:

 [1  2  2]   [2]

 [0  1  8] = [8]

 [1  2  4]   [4]

 [1  2  3]   [2]

 [0  1 -1] = [8]

 [1  2  1]   [4]

 [1  2  3]   [2]

 [0  1 -1]   [8]

 [1  2  4]   [4]

The determinants of these matrices are:

| 1  2  2 |    | 1  2  3 |    | 1  2  3 |

| 0  1  8 | = -4| 0  1 -1 | = -3| 0  1 -1 | = 11

| 1  2  4 |    | 1  2  1 |    | 1  2  4 |

Therefore, x3 can be calculated as:

x3 = Det(B)/Det(A) = 11/-3 = -11/3

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Answer:

-9x+11y=-14

x= ( 13/4 +3/8y) + 11y+-4

y=2

x=13/4 + 3/8 x 2

x=4

Step-by-step explanation:

The data includes a concave mirror with a radius of curvature of +31.5 cm and magnification of m = 3.40. The formula for magnification is m = v/u, and the focal length is f = r/2. Substituting the values, we get u = v/m, and using the mirror formula, the distance of the object from the mirror is 10.15 cm.

Given data: Radius of curvature of a concave mirror, r = +31.5 cm Magnification produced by the mirror, m = 3.40

We know that the formula for magnification is given by:

m = v/u where, v = the distance of the image from the mirror u = the distance of the object from the mirror We also know that the formula for the focal length of the mirror is given by :

f = r/2where,f = focal length of the mirror

Using the mirror formula:1/f = 1/v - 1/u

We know that a concave mirror has a positive focal length, so we can replace f with r/2.

We can now simplify the equation to get:1/(r/2) = 1/v - 1/u2/r = 1/v - 1/u

Also, from the given data, we have :m = v/u

Substituting the value of v/u in terms of m, we get: u/v = 1/m

So, u = v/m Substituting the value of u in terms of v/m in the previous equation, we get:2/r = 1/v - m/v Substituting the given values of r and m in the above equation, we get:2/31.5 = 1/v - 3.4/v Solving for v, we get: v = 22.6 cm Now that we know the distance of the image from the mirror, we can use the mirror formula to find the distance of the object from the mirror.1/f = 1/v - 1/u

Substituting the given values of r and v, we get:1/(31.5/2) = 1/22.6 - 1/u Solving for u, we get :u = 10.15 cm

Therefore, the distance of the mirror from the face is 10.15 cm. The units are centimeters (cm).Answer: 10.15 cm.

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Using the relation between velocity, distance and time, it is found that the velocity of the ship is given by:

B. 16 miles per hour

Velocity is distance divided by time, hence:

\(v = \frac{d}{t}\)

In this problem, we have that d = 48 miles, t =  3 hours, hence the velocity in miles per hour is given by:

\(v = \frac{48}{3} = 16\)

Hence option B is correct.

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Saleem scored 50 on the next test, and his average dropped to 58.

To find Saleem's grade on the next test, we can use the concept of weighted averages.

Since Saleem has an average of 60 in 4 subjects, we can calculate the total marks he has obtained so far. Let's denote the total marks in the 4 subjects as "T."

Average = Total marks / Number of subjects

60 = T / 4

To find T, multiply both sides by 4:

T = 60 * 4

T = 240

Now, Saleem's total marks after attempting the next test would be (240 + X), where X is the score he gets on the next test.

The new average after attempting the next test is 58.

Average = Total marks / (Number of subjects + 1)

58 = (240 + X) / 5

To find X, first multiply both sides by 5:

58 * 5 = 240 + X

290 = 240 + X

Now, isolate X:

X = 290 - 240

X = 50

So, Saleem scored 50 on the next test.

To summarize, Saleem scored 50 on the next test, and his average dropped to 58.

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The time it takes for the rock to hit the ground can be determined using the equation h(t) = -4.9t^2 + 150, where h(t) represents the height of the rock in meters and t represents time in seconds. By setting h(t) to 0 and solving for t, we can find the time it takes for the rock to hit the ground.

Set the equation h(t) = -4.9t^2 + 150 to 0, since the rock hits the ground when the height is 0.

-4.9t^2 + 150 = 0

Solve the quadratic equation for t by factoring, completing the square, or using the quadratic formula. In this case, let's use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values for a, b, and c:

t = (-0 ± √(0^2 - 4(-4.9)(150))) / (2(-4.9))

Simplify and calculate the value of t:

t = (√(2940)) / (-9.8) ≈ ±7.23

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Answer:

-1

Step-by-step explanation:

1. A water wheel rung’s height as a function of time can be modeled by the equation:

h - 8 = -9 sin6t

(b) Determine the maximum height above the water for a rung.

Given the rung's height modeled by the equation;

h - 8 = -9 sin6t

h(t) = -9sin6t + 8

At maximum height, the velocity of the rung is zero;

dh/dt = 0

dh/dt = -54cos6t

-54cos6t = 0

cos6t = 0/-54

cos6t = 0

6t = cos^-1(0)

6t = 90

t = 90/6

t= 15

Substitute t = 15 into the expression to get the maximum height;

Recall:

h(t) = -9sin6t + 8

h(15) = -9sin6(15) + 8

h(15) = -9sin90 + 8

h(15) = -9(1)+8

h(15) = -9+8

h(15) = -1

hence the maximum height above the water is -1

Answer:

First Space: 49

Second Space: 33

Third Space:-99

Fourth Space: -99

Fifth Space: 10

Sixth Space: -89

Step-by-step explanation:

First Space: for the first space you would do -7 times -7 because it is squared so you would get 49 because a negative and a negative and a negative make a positive.

Second Space: For the second space you have to do 49-16 because you already found the first space and the answer would be 33.

Third Space: For the third space you would do the answer you got from the second space which is 33 and multiply by -3 because -3 is outside the brackets. The answer would be -99.

Fourth Space: You would just put the same thing as the third space and put -99.

Fifth space: To find the fifth space you have to do 4 ÷ 2/5. To find this part you have to do 4 times the reciprocal (when you flip the fraction) and you would get 4 times 5/2. Then you can cross the denominator (bottom of the fraction) and make the 4 a 2 because 4 ÷ 2=2. Next you do 2 times 5 and get 10 as a answer.

Sixth Space: For the final answer you would use the fourth and fifth space. You would do -99+10 which is -89.

Hopefully this helps :)

Answer:

A

Step-by-step explanation:

Distinguish exact and uncertain numbers; Correctly represent uncertainty in quantities using significant figures.

Answer:

answer A

Step-by-step explanation:

it has a exact amount of years with no decimals

The correct option is D. The number of accidents is being used as the operational definition of automobile accidents in this study. The independent variable would be gender (male or female), which is used to compare the differences in driving ability between men and women.

Many factors can contribute to the number of automobile accidents a person is involved in, such as driving experience, road conditions, vehicle maintenance, and even weather. Additionally, the number of accidents can be influenced by various personal and social factors, such as age, income, and education level, as well as factors related to the vehicle itself, such as make and model. These factors can all impact driving behavior and the likelihood of being involved in an accident, regardless of gender.

Therefore, using the number of accidents as a measure of driving ability is likely to yield biased results and not representative of the true ability of men or women as drivers. To draw more meaningful conclusions about driving ability, it would be necessary to use a more comprehensive and reliable method for measuring driving skills, such as a standardized driving test or assessment of specific driving skills and behaviors.

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Dr. Marlow wants to learn whether men or women are better drivers. to determine this, she will measure driving ability by examining the number of automobile accidents people have been involved in as a driver. thus, she is using the number of accidents as the number of accidents is the basis of

a. her control group in this study.

b. a theory of good driving.

c. the independent variable in this study.

d. the operational definition of driving ability.

e. a case study examination of driving ability.