pleaSE help need soon please

PleaSE Help Need Soon Please

Answers

Answer 1

Answer:

53

Step-by-step explanation:

180-127=53


Related Questions

please help me with this :D

please help me with this :D

Answers

○=> Correct option :

\( \color{plum}\bold{(C)} \) Diameter of circle P is the same length as the radius of circle Q.

○=> Steps to derive correct option :

Given :

Diameter of circle P = 26 cm

Radius of circle P :

\( =\tt \frac{diameter}{2} \)

\( = \tt \frac{26}{2} \)

\(\color{plum} = \tt13 \: cm\)

Thus, radius of circle P = 13 cm

Diameter of circle Q = 52 cm

Radius of circle Q :

\( = \tt \frac{diameter}{2} \)

\( =\tt \frac{52}{2} \)

\( \color{plum}= \tt26 \: cm\)

Thus, radius of circle Q = 26 cm

Radius of circle R = 52 cm

Diameter of circle R :

\( =\tt radius \times 2\)

\( =\tt 52 \times 2\)

\(\color{plum} = \tt104 \: cm\)

Thus, the diameter of circle R = 104 cm

☆ Conclusion :

▪︎Diameter of circle P is the same length as the radius of circle Q.

Therefore, the correct option is (C) Diameter of circle P is the same length as the radius of circle Q.

how much force is needed to accelerate a 70kg car at 10m/s^2?​

Answers

Momentum (p) is equal to the product of an object's mass (m) and its change in velocity (v).

Change in velocity (v) results in change in momentum (p), which is equal to impulse. Impulse (J) is also equal to an applied force (F) over a period of time (t).

Combining p=mv and J=F t together:

m (v final - v initial) = F t

(2,500 kg) (70 m/s - 30 m/s) = F (10 s)

Solving for F we get:

10,000 N of force

what is the a, b, and c of the following quadratic y = - 4x ^ 2 + 5x - 3

Answers

Answer:

A = -4

B = 5

C = -3

Step-by-step explanation:

Standard form of a quadratic equation is y = Ax² + Bx + C

In the quadratic y = -4x² + 5x - 3, we can use this standard form to find A, B, and C.

Since -4 is the coefficient to x², A is -4.

Since 5 is the coefficient to x, B is 5.

Lastly, since -3 is the last term, C is -3.

So, the answer is:

A = -4

B = 5

C = -3

Rosie is x years old
Eva is 2 years older
Jack is twice Rosie’s age
A) write an expression for the mean of their ages.
B) the total of their ages is 42
How old is Rosie?

Answers

Answer:

Rosie is 10 years old

Step-by-step explanation:

A)

Rosie is x years old

Rosie's age (R) = x

R = x

Eva is 2 years older

Eva's age (E) = x + 2

E = x + 2

Jack is twice Rosie’s age

Jack's age (J) = 2x

J = 2x

B)

R + E + J = 42

x + (x + 2) + (2x) = 42

x + x + 2 + 2x = 42

4x + 2 = 42

4x = 42 - 2

4x = 40

\(x = \frac{40}{4} \\\\x = 10\)

Rosie is 10 years old

Mr. Sanchez surveyed classes to aid in planning the end-of-year party. For the first sample, Mr. Sanchez surveyed every third person on each first-period class roster. For the second sample, Mr. Sanchez surveyed his five honors math classes. Which statement about Mr. Sanchez’s samples is true? End-of-Year Party Survey Sample 1 Sample 2 Water Park 21 Water Park 36 Bowling/Arcade 36 Bowling/Arcade 28 Zoo 16 Zoo 24 Dance.

Answers

Answer:

b. Sample 2 is biased

Step-by-step explanation:

For the first sample, he seemingly took a small group of persons. He might have taken approximately 10-15 random persons. Even though the number is relatively small compared to the total amount of people he could survey and didnt. The sample is randomized and the number is decent enough to make a decision.

For the second sample, not only did he surveyed a small group of students, but also a very specific one: the 5 honors math classes. That group of persons isnt very randomized and the way they think globally might differ to the way all the classes think globally. As a result, the survey results may end up being biased.  

Answer:

The answer is sample one not two

Step-by-step explanation:

Proof

Mr. Sanchez surveyed classes to aid in planning the end-of-year party. For the first sample, Mr. Sanchez

Find the slope of the line that passes through the points A(-3, 1) and B(2, -5).

Answers

Answer:

\(m = \frac{ - 5 - 1}{2 - ( - 3)} = - \frac{6}{5} \)

Find the first three nonzero terms of the Maclaurin series for the function and the values of x for which the series converges absolutely. f(x)=(3cosx)ln(1+x) What are the first three nonzero terms of the Maclaurin series for f(x) ? (

Answers

The Maclaurin series for f(x) converges absolutely for x within the interval (-2/3, 2/3).

To find the Maclaurin series for the function f(x) = (3cos(x))ln(1+x), we can use the standard formulas for the Maclaurin series expansion of elementary functions.

First, let's find the derivatives of f(x) up to the third order:

f(x) = (3cos(x))ln(1+x)

f'(x) = -3sin(x)ln(1+x) + (3cos(x))/(1+x)

f''(x) = -3cos(x)ln(1+x) - (6sin(x))/(1+x) + (3sin(x))/(1+x)² - (3cos(x))/(1+x)²

f'''(x) = 3sin(x)ln(1+x) - (9cos(x))/(1+x) + (18sin(x))/(1+x)² - (12sin(x))/(1+x)³ + (12cos(x))/(1+x)² - (3cos(x))/(1+x)³

Next, we evaluate these derivatives at x = 0 to find the coefficients of the Maclaurin series:

f(0) = (3cos(0))ln(1+0) = 0

f'(0) = -3sin(0)ln(1+0) + (3cos(0))/(1+0) = 3

f''(0) = -3cos(0)ln(1+0) - (6sin(0))/(1+0) + (3sin(0))/(1+0)² - (3cos(0))/(1+0)² = -3

f'''(0) = 3sin(0)ln(1+0) - (9cos(0))/(1+0) + (18sin(0))/(1+0)² - (12sin(0))/(1+0)³ + (12cos(0))/(1+0)² - (3cos(0))/(1+0)³ = -9

Now we can write the first three nonzero terms of the Maclaurin series:

f(x) = f(0) + f'(0)x + (f''(0)/2!)x² + (f'''(0)/3!)x³ + ...

f(x) = 0 + 3x - (3/2)x² - (9/6)x³ + ...

Simplifying, we have:

f(x) = 3x - (3/2)x² - (3/2)x³ + ...

To determine the values of x for which the series converges absolutely, we need to find the interval of convergence. In this case, we can use the ratio test:

Let aₙ be the nth term of the series.

|r| = lim(n->infinity) |a_(n+1)/aₙ|

= lim(n->infinity) |(3/2)(xⁿ+1)/(xⁿ)|

= lim(n->infinity) |(3/2)x|

For the series to converge absolutely, we need |r| < 1:

|(3/2)x| < 1

|x| < 2/3

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Please help. Thank you sm!

Please help. Thank you sm!

Answers

A. The slope of this ramp is 4/15.

B. The new ordered pairs after the rotation are:

A' (3, -1)B' (6, -2)C' (1, -1)

How to calculate the slope of a line?

In Mathematics, the slope of any straight line can be determined by using the following mathematical equation;

Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = rise/run

By substituting the given parameters into the slope formula, the slope of this ramp can be  calculated as follows;

Slope (m) of ramp = 4/15.

By applying a rotation of 90° clockwise to the vertices of triangle ABC, the coordinates of the vertices of the image are as follows:

(x, y)                               →            (y, -x)

Coordinate A = (1, 3) → Coordinate A' = (3, -(1)) = (3, -1)

Coordinate B = (2, 1) → Coordinate B' = (1, -(2)) = (6, -2)

Coordinate C = (1, 1) → Coordinate C' = (1, -(1)) = (1, -1)

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When a fixed bridge is created, there must be at least_______of the bridge

Answers

Answer: One abutment

Step-by-step explanation: When a fixed bridge is created, there must be at least one abutment of the bridge.

Remind???? anybody, or nobody???

Answers

Answer:

wdym? like the app remind?

Answer:

you have to download the remind app

You want to put a logo on each cell phone holder you make. Sew-on logos cost 2.30 for 10. Stick-on logos cost 9.40 for 100. Divide the cost by the number of logos for both types

Answers

Answer:

\(Rate = \$0.23\)   and    \(Rate = \$0.094\)

Step-by-step explanation:

Given

Sew-on logos

Cost = $2.30

Units = 10

Stick-on logos

Cost = $9.40

Units = 100

Required

Divide cost by units, in both cases

When we divide cost by units, it gives the unit rate.

i.e.

\(Rate = \frac{Cost}{Units}\)

FOR SEW-ON LOGOS

Substitute $2.30 for Cost and 10 for Units

\(Rate = \frac{\$2.30}{10}\)

\(Rate = \$0.23\)

FOR STICK-ON LOGOS

Substitute $9.40 for Cost and 100 for Units

\(Rate = \frac{\$9.40}{100}\)

\(Rate = \$0.094\)

Hence, the solution is

\(Rate = \$0.23\)   and    \(Rate = \$0.094\)

Which inequalities are true? Select the four correct answers.
O<
0 V8
OVE <3
V> 7
口<2
O /> 8
01

Which inequalities are true? Select the four correct answers.O&lt;0 V8OVE &lt;3V&gt; 7&lt;2O /&gt; 801

Answers

Step-by-step explanation:

Check the attached photo out

Which inequalities are true? Select the four correct answers.O&lt;0 V8OVE &lt;3V&gt; 7&lt;2O /&gt; 801

Formalize the following in terms of atomic propositions r, b, and w, first making clear how they correspond to the
English text. (a) Berries are ripe along the path, but rabbits have not been seen in the area.
(b) Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.
(c) If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.
(d) It is not safe to walk along the path, but rabbits have not been seen in the area and the berries along the path are ripe.
e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to
pave been seen in the area.
Walking is not safe on the path whenever rabbits have been seen in the area and berries are ripe along the path.

Answers

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.

Given information and corresponding atomic propositions:

We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:

r: Rabbits have been seen in the area.

b: Berries are ripe along the path.

w: Walking on the path is safe.

Now, let us formalize each of the given statements in terms of these atomic propositions:

a) Berries are ripe along the path, but rabbits have not been seen in the area.

b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.

c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.

d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.

e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.

The formalizations in terms of atomic propositions are:

a) b ∧ ¬r.b) ¬r ∧ w ∧

b.c) (b → w) ∧ (¬r → w).

d) ¬w ∧ ¬r ∧

b.e) (¬r ∧ ¬b) → w.b ∧

Berries are ripe along the path, but rabbits have not been seen in the area.

This is formalized by using the ∧(logical and) operator.

(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.

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Please help quicklyy! :(

Please help quicklyy! :(

Answers

Answer:

the 1st one

Step-by-step explanation:

What is the value of x?

Enter your answer in the box.

X =

What is the value of x?Enter your answer in the box.X =

Answers

the angle is a reflex angle

reflex angle is when two sum of angles is 90

equating both angle to 90

What is the value of x?Enter your answer in the box.X =

X = 90

That should be the answer

Jay has a 50 gallon water tank. he fills the tank with a garden hose at a rate of 8.2 gallons per minute. there are 9 gallons of water in the tank. what is the maximum amount of time jay can add water without causing the tank to overflow?

Answers

The maximum amount of time required to add water without causing the tank to overflow is 5 minutes.

Given that Jay fills the tank with a garden hose at a rate of 8.2 gallons per minute. This means Jay is filling the water tank at a speed of 8.2 gallons / minute.

Also, the water tank is of 50 gallon and 9 gallons of water in the tank is already filled, which means

Volume of water tank = 50 - 9

= 41 gallons

Now, the time required in filling the water tank is:

Time = Distance / Speed

Time = 41 / 8.2

Time = 5 minutes

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I’ll mark as BRANLIEST!!

15 POINTS!!!

Ill mark as BRANLIEST!!15 POINTS!!!

Answers

9514 1404 393

Answer:

  not a function

Step-by-step explanation:

When any x-value (input) maps to more than one y-value (output), the relation is not a function.

Here, 9 maps to 2 different y-values (4 and 5), so the relation is not a function.

find the product of (4x-3)(x+2)​

Answers

To find the product of (4x-3)(x+2), you can use the distributive property to multiply each term in the first bracket by each term in the second bracket. The result is:

(4x-3)(x+2) = 4x(x+2) - 3(x+2) = 4x^2 + 8x - 3x - 6 = 4x^2 + 5x - 6

A point q on a segment with endpoints a (2, −1) and c (4, 2) partitions the segment in a 4:1 ratio. find q. you must show all work to receive credit

Answers

The coordinates of the point q on the segment with endpoints a (2, −1) and c (4, 2) which partitions the segment in a 4:1 ratio. are (2, 7/5).

We can solve this question by using the section formula, which states that if we have a line segment with endpoints (x1, y1) and (x2, y2) and we want to find a point on the segment that divides it in the ratio of m:n, then the coordinates of the point can be found using the following formula:

q(x,y) = ((mx2 + nx1) / (m + n), (my2 + ny1) / (m + n))

In our case,

m=4, n=1

x1=2, x2=4

y1=-1 ,y2=2

By using the given values in the formula mentioned above, we get the coordinates of q as:

q(x,y)=( [4*4+1*2]/5 ,[4*2+1*-1]/5 )

q(x,y)=( 18/5), (7/5)

So the x coordinate of q is: 18/5

the y coordinate of q is: 7/5

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60 Points for a rapid reply -calculate the measure of the central angle in the regular dodecagon {12 sides}

60 Points for a rapid reply -calculate the measure of the central angle in the regular dodecagon {12

Answers

Answer:

Maybe 30°

Cause 12:4 is 3

3x10 30

The central angle of a regular dodecagon is 30 degrees. Option A is the correct option.

The central angle - The angle created at the polygon's center by two adjacent radii—the lines that connect the polygon's center to its vertices—is known as the central angle.

We know it is a regular dodecagon, which means all the sides will be of equal size.

As it is a dodecagon there will be a total of 12 equal central angles added to give an angle of 360 degrees.

Let's assume the central angle is x.

12x = 360

x = 360/12

x = 30

Hence, the central angle in a regular dodecagon is 30 degrees.

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a pizza shop delivered 8 pepperoni pizzas to a college on the first night of final exams. the total cost of the pizzas was $56. a small pizza costs $3 and contains 4 ounces of pepperoni. a medium pizza costs $5 and contains 9 ounces of pepperoni. a large pizza cost $11 and contains 12 ounces of pepperoni. the owner of the pizza shop used 4 pounds 12 ounces of pepperoni in making the pizzas. how many pizzas of each size were delivered to the college?

Answers

From the word problem given, the number of pizzas each that were delivered are:

1 small7 medium; and2 large.
What is the calculation justifying the above solution?

Step I

Let a = number of small pizzas delivered

Let b = number of medium pizzas delivered

Let c = number of large pizzas delivered

Step 2 - Creating relevant expressions based on number and type ordered, we have:

a + b + c = 8.............................1

3a + 5b + 11c = 56..................2
4a + 9b + 12C = 4 * 8 + 12.....3a

We can rewrite (3) as
4a + 9b + 12C = 44 ....3b

Step 3

Multiply both sides of (1) by 4

We have

4a +4b +4c = 32

If we remove (1) from (3) we have

4a + 9b + 12C = 44

-
4a +4b +4c = 32
5b +8C = 12......................(4)

Multiply both sides of (1) by 3 and subtract from (2), and we have:

3a + 3b + 3c = 24, removing this from (2) we have

3a + 5b + 11c = 56

-
3a + 3b + 3c = 24
2b + 8c = 32.....................(5)

Step 4 - Subtract (4) from (5)

2b + 8c = 32
-
5b + 8c = 12
-3b = 20

b = - 20/3

= - 6.67
Since we cannot have negative values, we work with absolute value to get:

b \(\approx\) 7

Since b = 7

2(7) + 8c = 32
8c = 32 - 14
c = 18/8

c \(\approx\) 2


Plug in that back into a we have

a + b + c = 8
a + 7 + 2 = 8

a = 8-9
a = -1 (recall we must have absolute values)
a therefore = 1.

Hence the number of pizzas that were ordered are:

1 small
7 medium; and

2 large.

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At December 31, 2016, Carla Vista Co. Imports reported this information on its balance sheet:
Accounts receivable $581,900
Less: Allowance for doubtful accounts 36,370
During 2017, the company had the following transactions related to receivables.
1. Sales on account $2,965,700
2. Sales returns and allowances 67,586
3. Collections of accounts receivable 2,568,800
4. Write-offs of accounts receivable deemed uncollectible 42,560
5. Recovery of bad debts previously written off as uncollectible 14,110
Required:
Prepare the journal entries to record each of these five transactions. Assume that no cash discounts were taken on the collections entered.

Answers

The journal entries to record each of these five transactions are illustrated below.

1) Debit Accounts Receivable $2,965,700

  Credit Sales Revenue $2,965,700

2) Debit Sales Returns and Allowances $67,586

   Credit Accounts Receivable $67,586

3) Debit Cash $2,568,800

   Credit Accounts Receivable $2,568,800

4) Debit Allowance for Doubtful Accounts $42,560

   Credit Accounts Receivable $42,560

5) Debit Accounts Receivable $14,110

   Credit Allowance for Doubtful Accounts $14,110

In accounting, a journal entry is a formal record of a business transaction that shows the accounts affected and the amounts involved. In this case, we have five transactions related to accounts receivable for Carla Vista Co. Imports that need to be recorded using journal entries.

When a company sells goods on account, it records an increase in accounts receivable and an increase in revenue. In this case, the journal entry for the $2,965,700 in sales on account would be:

If a customer returns goods or receives an allowance, the company must reduce both its revenue and its accounts receivable. The journal entry for the $67,586 in sales returns and allowances would be:

When a company collects on its accounts receivable, it reduces the balance in its accounts receivable account and increases its cash balance. The journal entry for the $2,568,800 collected would be:

If a company determines that it is unlikely to collect on an accounts receivable balance, it may write it off as uncollectible. This reduces both its accounts receivable and its net income. The journal entry for the $42,560 write-off would be:

If a previously written-off accounts receivable is later collected, the company must reverse the write-off and record the collection as normal. The journal entry for the $14,110 recovery would be:

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Math part 4 question 4

Math part 4 question 4

Answers

The function shown in graph is nether odd nor even function.

Explain about the odd and even function?

If f(−x)=f(x) for all x with in domain of f, then a function f is even. If f(x)=f(x) for every x in f's domain, a function f is odd.

An even function has a graph that is symmetrical when compared towards the y-axis. An odd function's graph is symmetric with regard to the origin. After thought about the y-axis, the graph of the even function remains unchanged. An odd function's graph is oriented in opposite directions but is located at a comparable distance from the origin. We can visually distinguish between evenly balanced odd functions using the same criterion.

In the given graph.

The graph of the function is nether increasing nor decreasing as, the y value of the function is going along both y - axis and -y axis.

Thus, the function shown in graph is nether odd nor even function.

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Find the 85th term of the arithmetic sequence – 25, -37, -49, ...

Answers

Answer:

a(85) = -1033

Step-by-step explanation:

Explicit Arithmetic Sequence:

an = a1 + d(n-1)

d = -12 (by -37 + 25)

a(85) = -25 + -12(85-1)

a(85) = -1033

Answer:

-1033

Step-by-step explanation:

pls mark as brainliest

large reservoirs of oil found underground are under very high pressure, which allows the oil to be pumped to the surface. all oil fields contain some water, and as water is pumped back into a well to maintain high pressure, the water content increases. suppose the proportion of water ???? in a randomly selected barrel of oil pumped to the surface has a normal distribution with mean ????

Answers

In the context of oil fields, the proportion of water (denoted as ρ) in a randomly selected barrel of oil pumped to the surface can be assumed to have a normal distribution.

This means that the distribution of ρ follows a bell-shaped curve with a symmetric shape around its mean (denoted as μ). The mean represents the average proportion of water in the barrels of oil.

The normal distribution is a common assumption in statistics due to its well-understood properties and prevalence in various natural phenomena.

By assuming a normal distribution for ρ, we can make statistical inferences and predictions about the water content in the oil based on sample data and the known characteristics of the normal distribution.

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What is the cost of one Daisy ? And what is the cost of one strawflower ? Please answer

What is the cost of one Daisy ? And what is the cost of one strawflower ? Please answer

Answers

Answer:

$60 to $100.

1 Ounce Package $17.95

1/4 Pound Package $29.95 58%

1 Pound Package $94.95 67%

Step-by-step explanation:

A server earns X dollars per hour at a restaurant in addition to money made from tips. If during a 6-hour shift, the server earns $164.50 in tips, what is the minimum amount the server must earn per hour to make at least $184 total during the shift?

a. $4.00
b. $3.75
c. $3.50
d. $3.25

Answers

Answer:

$3.25

Step-by-step explanation:

184-164.50=19.50

19.50÷6=3.25

f(x) = x2 − x − ln(x)
(a) Find the interval on which f is increasing. (Enter your answer using interval notation.)
Find the interval on which f is decreasing. (Enter your answer using interval notation.)
(b) Find the local minimum and maximum value of f.
(c) Find the inflection point.

Answers

(a) The interval on which f is increasing: (0, ∞)

The interval on which f is decreasing: (0, 1)

(b) Local minimum: At x = 1, f(x) has a local minimum value of -1.

There is no local maximum value.

(c) Inflection point: At x ≈ 0.293, f(x) has an inflection point.

The function f(x) = x^2 - x - ln(x) is a quadratic function combined with a logarithmic function.

To find the interval on which f is increasing, we need to determine where the derivative of f(x) is positive. Taking the derivative of f(x), we get f'(x) = 2x - 1 - 1/x. Setting f'(x) > 0, we solve the inequality 2x - 1 - 1/x > 0. Simplifying it further, we obtain x > 1. Therefore, the interval on which f is increasing is (0, ∞).

To find the interval on which f is decreasing, we need to determine where the derivative of f(x) is negative. Solving the inequality 2x - 1 - 1/x < 0, we get 0 < x < 1. Thus, the interval on which f is decreasing is (0, 1).

The local minimum is found by locating the critical point where f'(x) changes from negative to positive. In this case, it occurs at x = 1. Evaluating f(1), we find that the local minimum value is -1.

There is no local maximum in this function since the derivative does not change from positive to negative.

The inflection point is the point where the concavity of the function changes. To find it, we need to determine where the second derivative of f(x) changes sign. Taking the second derivative, we get f''(x) = 2 + 1/x^2. Setting f''(x) = 0, we find x = 0. Taking the sign of f''(x) for values less than and greater than x = 0, we observe that the concavity changes at x ≈ 0.293. Therefore, this is the inflection point of the function.

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Estimate ΔyΔy using differentials.
y=cos(5x),=/30,x=0.055
(Give your answer to three decimal places.)

Answers

The estimated change in yy using differentials is -0.00679. This means that if xx is increased by 0.005, then yy is estimated to decrease by 0.00679. The differential of yy is dy=-5sin(5x)dxdy=−5sin⁡(5x)dx. We are given that y=cos(5x)=π/30y=cos⁡(5x)=π/30 and x=0.055x=0.055.

We want to estimate ΔyΔy, which is the change in yy when xx is increased by 0.005. We can use the differential to estimate ΔyΔy as follows:

Δy≈dy≈dy=-5sin(5x)dx

Plugging in the values of y, x, and dxdx, we get:

Δy≈-5sin(5(0.055))(0.005)≈-0.00679

Therefore, the estimated change in yy using differentials is -0.00679.

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Help please I really don’t understand SOS Due today

Help please I really dont understand SOS Due today

Answers

Answer:

Step-by-step explanation:

28 > 6x - 2

28 + 2 > 6x - 2 + 2

30 > 6x

5 > x or x < 5

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