PLEASE HELP ME
The function f(x) = -2(4)^x+1 +140
represents the number of tokens a child has x hours after arriving at an arcade.
What is the practical domain and range of the function?
If necessary, round to the nearest hundredth.
The practical domain of the situation is ?
The practical range of the situation is ?
PLEASE SEE PHOTO FOR FUNCTION

Answer:

-16

Step-by-step explanation:

In this problem, we are adding a negative integer and a positive integer. From this, we already know that the sum will be negative. (- plus + = -)

Since 20 is positive, you can remove the plus sign so your equation looks like

20 - 36

Next, subtract to get -16

~theLocoCoco

Answer:

( -16 ) is the answer .

hope this will help you

Answer:

4b^4

Step-by-step explanation:

Work backwards, multiply 4b^5 to 2b, get 8b^6, divide by 2b^2 and get 4b^4

The relative frequency οf value οf 10 is 0.3.

The relative frequency is calculated as the prοduct οf the number οf times a given value οf the data appears in the set οf all οutcοmes divided by the tοtal number οf οutcοmes.

Here the given data set is 10, 14, 12, 16, 13, 14, 16, 10, 12, and 10.

Fοr value οf 10, the number οf times 10 οccured is 3 and tοtal number οf data set is 10.

Relative frequency,

=> Number οf times οf value οf 10/ Tοtal number οf data set

=> 3/10

=> 0.3.

Hence the relative frequency οf value οf 10 is 0.3.

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Answer:

Step-by-step explanation:

Answer:

A = 22.62°

B = 67.38°

c = 26

Step-by-step explanation:

\(a^2+b^2=c^2\\10^2+24^2=c^2\\100+576=c^2\\676=c^2\\26=c\)

\(\sin A=\frac{\text{Opposite}}{\text{Hypotenuse}}=\frac{10}{26}\\\\A=\sin^{-1}(\frac{10}{26})\\\\A\approx22.62^\circ\)<-- You can also use other trig ratios

\(B=180^\circ-(90^\circ+22.62^\circ)=180^\circ-112.62^\circ=67.38^\circ\)

There's no specific order in how to solve for A and B, so there may be more than one way to approach these solutions.

The value of x using the theorem of intersecting secants is 10

From the question, we have the following parameters that can be used in our computation:

intersecting secants

Using the intersecting secants equation, we have

8 * (8 + x) = 6 * (6 + 18)

Evaluate the like terms

So, we have

8 * (8 + x) = 6 * 24

Divide both sides by 8

8 + x = 6 * 3

So, we have

8 + x = 18

Subtract 8 from both sides

x = 10

Hence, the value of x is 10

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At x=2, the function in the graph is approaches to infinity. This is satisfied by equation 1 that models the rational function, hence option 1 is the correct answer.

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("="). For illustration, 2x - 5 = 13.

Two expressions are combined in an equation using an equal symbol ("="). The "left-hand side" and "right-hand side" of the equation are the two expressions on either side of the equals sign. Typically, we consider an equation's right side to be zero.

From given graph we can see that

At x=2, the function in the graph is approaches to infinity.

It means function is not defined at x=2

We know that a rational function is undefined when denominator is equal to zero.

For equation 1:

f(x)= 2(x+2)/(x-2)

Equating the denominator:

x-2=0

x=2

It means function is not defined at x=2

The y-intercept is: y= -2

The function is passing through the point (1,-6).

When we substitute x=1

Hence, option 1 is true.

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Answer:

32.4

Step-by-step explanation:

i knoiw it

Answer:

i think the answer is A: 0.0005

Step-by-step explanation:

i think so because when i divided alaska by rhode island, i got 500000000. so i guess you move the decimal

Answer:

16 ounces = 1 pound

meaning 2.5 pounds is added to the skull, 602.5 pounds.

Step-by-step explanation:

Answer:

have a good day

Step-by-step explanation:

hope it helps

Step 1

Pick two consecutive points and find the equation of a straight line.

(7,-1) and (5,0)

Equation of a straight line

y = mx + c

for (7,-1)

-1 = 7m + c ....................... equation 1

for (5,0)

0 = 5m + c ...................... equation 2

make c subject of relation from equation 2

c = -5m

Substitute c in equation 1

-1 = 7m - 5m

-1 = 2m

m = -1/2

c = -5(-1/2)

c = 5/2

From the equation above, the table shows a linear function.

Every x input in the equation, give the correct y output.

Answer: x = -2, \(\frac{2 }{3}\)

Step-by-step explanation:

     Given:

0 = –3x² – 4x + 4

    The quadratic formula:

\(\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}\)

    Substitute known values:

* a = -3, b = -4, c = 4

\(\displaystyle x=\frac{-(-4)\pm\sqrt{(-4)^2-4(-3)(4)} }{2(-3)}\)

    Simplify with multiplication:

\(\displaystyle x=\frac{4\pm\sqrt{16+48} }{-6}\)

    Simplify:

\(\displaystyle x=\frac{4\pm\sqrt{64} }{-6}\)

\(\displaystyle x=\frac{4+8 }{-6}\),    \(\displaystyle x=\frac{4-8 }{-6}\)

\(\displaystyle x=\frac{12 }{-6}\),    \(\displaystyle x=\frac{-4 }{-6}\)

Answer:

3¹²

Step-by-step explanation:

Move 3⁻² to the numerator using the negative exponent rule

1/b-n = bⁿ

(3⁵)² ⋅ 3²

Multiply the exponents

3¹⁰ · 3²

Multiply by adding the exponents

3¹⁰⋅ 3²

3¹²

Step-by-step explanation:

I think you are 100℅ clear.

Answer:

3x

Step-by-step explanation:

Answer:

-x/2+3/2<5/2=

-x/2+3/2=5/2

subtracting 3/2 from both sides,

-x/2=2/2

simplifying, 2/2=1

-x/2=1

to get rid of the denominator of 2 you must multiply by 2. also to make the answer positive you must multiply both sides by -1,

therefore: x>-2

Step-by-step explanation:

A residual plot is a scatterplot in which the residuals (vertical distances between the predicted and actual values) are plotted against the independent variable. A residual is defined as the difference between the predicted value (based on the regression equation) and the actual value.

Residual plots are a valuable tool for checking the adequacy of the model. It helps us check whether the assumptions of linearity, independence, equal variance, and normality are met or not.

The most basic way to create a residual plot is to plot the residuals against the fitted values. If the points in the residual plot are randomly scattered around the horizontal axis, then the assumption of linearity has been met.

If the points show a pattern, such as a curved line, then the assumption of linearity has been violated.To create a residual plot, follow these steps:

Step 1: Estimate the regression equation and obtain the predicted values (ŷ) and residuals (e). ŷ = b0 + b1X

Step 2: Plot the residuals on the vertical axis and the independent variable (X) on the horizontal axis

.Step 3: Look for patterns in the residual plot. If the points are randomly scattered around the horizontal axis, then the assumptions of linearity, independence, equal variance, and normality are met. If there is a pattern, such as a curved line, then the assumptions have been violated. A residual plot can be used to detect outliers, influential observations, and nonlinearity.

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The trigonometric identities equivalent to cos(2·x)/cos(x) are;

cos(x) - (sin(x))/(tan (x))

2·cos(x) - sec(x)

Trigonometric identities are equations of trigonometric functions that are correct for the values of the input and output variables in the equations.

The trigonometric identity for cos(2·x) is specified as follows;

cos(2·x) = cos²x - sin²x

Therefore;

cos(2·x)/(cos(x)) = (cos²x - sin²x)/(cos(x))

(cos²x)/(cos(x)) = cos(x)

sin²(x)/(cos(x) = sin(x) × sin(x)/(cos(x)) = sin(x)·tan(x)

(cos²x - sin²x)/(cos(x)) = (cos²x)/(cos(x)) - sin²(x)/(cos(x)

(cos²x)/(cos(x)) - sin²(x)/(cos(x) = cos(x) - sin(x)·tan(x)

cos(2·x) = 2·cos²x - 1

Therefore; cos(2·x)/cos(x) = (2·cos²x - 1)/cos(x)

(2·cos²x - 1)/cos(x) = 2·cos(x) - 1/cos(x)

2·cos(x) - 1/cos(x) = 2·cos(x) - sec(x)

cos(2·x) = 1 - 2·sin²x

cos(2·x)/cos(x) = (1 - 2·sin²x)/cos(x)

(1 - 2·sin²x)/cos(x) = sec(x) - 2·sin(x)

The expressions equivalent to cos(2·x)/cos(x) are therefore;

cos x - (sin x)·(tan x) and 2·cos x - sec x, which are I and III

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Answer:

C, $640

Step-by-step explanation:

the problem mentions cubic feet so we're dealing with volume

volume of a rectangular prism = l x w x h

volume of a triangular prism is half of the volume of a rectangular prism or 1/2 (l x w x h)

so... input the values!

rectangular prism = 4 x 8 x 3 = 96 cu.ft

triangular prism = 4 x 8 x 5 = 160 cu.ft ( side note: since the triangular prism is directly on top of the rectangular one, the two prisms share same w and l )

together the barn's volume is 256 cu.ft or 96+160

we know 1 cu.ft is $2.5 so we multiply 256 with 2.5

256 x 2.5 = 640 or C!!!!!!!!!

lmk if u got any questions :>

Answer:B

Step-by-step explanation:

If we compare both sides of the equation we get,

D. a = 4, b = 6 and c = 5

Answer:

7(x-y)

Step-by-step explanation:

difference of x and y=x-y

product of 7=7 times the expression

so,

Answer is 7(x-y)

Answer:

10:35 is the ratio

Step-by-step explanation:

2 x 5 = 10

7 x 5 = 35

a) The mean of the data-set is of 2.

b) The range of the data-set is of 4 units, which is of around 4.3 MADs.

The mean of a data-set is obtained as the sum of all observations in the data-set divided by the number of observations in the data-set, which is also called the cardinality of the data-set.

The dot plot shows how often each observation appears in the data-set, hence the mean of the data-set is obtained as follows:

Mean = (1 x 0 + 5 x 1 + 3 x 2 + 5 x 3 + 1 x 4)/(1 + 5 + 3 + 5 + 1)

Mean = 2.

The range is the difference between the largest observation and the smallest, hence:

4 - 0 = 4.

4/0.93 = 4.3 MADs.

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Answer:

Sample size n \(\simeq\) 1269.15

Step-by-step explanation:

From the information given ,

At 99% of confidence interval,

the level of significance ∝ = 1 - 0.99

the level of significance ∝ =  0.01

the critical value for 99% of confidence interval is:

\(\mathtt{\dfrac{\alpha }{2} = \dfrac{0.01}{2}}\)

= 0.005

\(\mathtt {z_{\alpha/2} = z_{0.005/2} }\)

The value for z from the standard normal tables

= 2.58

The Margin of error E= 3% = 0.03

The formula to  determine the sample size n used can be expressed as follows:

\(\mathtt { n = (\dfrac{z_{\alpha/2}}{E})^2 \ \hat p (1 - \hat p) }\)

where;

\(\mathtt{\hat p }\) = 22% = 0.22

Then:

\(\mathtt { n = (\dfrac{2.58}{0.03})^2 \ \times 0.22 \times (1 - 0.22) }\)

\(\mathtt { n = (86)^2 \ \times 0.22 \times (0.78) }\)

\(\mathtt { n = 7396 \ \times 0.22 \times (0.78) }\)

n = 1269.1536

Sample size n \(\simeq\) 1269.15

Answer:

A) Symmetric Property Of Equality

Step-by-step explanation:

\(The\ symmetric\ property\ of\ equality\ just\ says\ that\ , if\ the\ LHS=RHS; then; RHS=LHS\)

\(Here,\\-5=x\\x=-5\)

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\(\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right]\) ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\(\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]\)

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\(\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right]\) ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\(\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]\)

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\(\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right]\) ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\(\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]\)

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

a.) a possible coordinate for the third vertex is (3.67, 0) or (-3.67, 0).

b.) No, there is no other point that could be the third vertex.

a. To find a possible coordinate for the third vertex, we need to consider the distance between the two given points and the given perimeter of the triangle. The two given points are (0, 0) and (3, 0), which means they lie on the x-axis.

Since the triangle has a perimeter of 11 units, we can calculate the length of one side by dividing the perimeter by 3, since a triangle has three sides of equal length.

The length of one side is 11 / 3 = 3.67 units (rounded to two decimal places). Since the two given points lie on the x-axis, the third vertex must lie somewhere on the line parallel to the x-axis and at a distance of 3.67 units away from either of the given points.

Let's consider the point (0, 0). If we move 3.67 units in either the positive or negative direction on the x-axis, we get two possible coordinates for the third vertex: (3.67, 0) or (-3.67, 0). These points complete the triangle with the given perimeter of 11 units.

Therefore, a possible coordinate for the third vertex is (3.67, 0) or (-3.67, 0).

b. No, there is no other point that could be the third vertex. Since the two given points are on the x-axis, any other point on the grid would either increase the perimeter of the triangle or create a degenerate triangle with zero area.

If we choose a point above or below the x-axis, it would increase the distance between that point and the x-axis, resulting in a longer side length and a larger perimeter than 11 units.

If we choose a point on a different line parallel to the x-axis, the distance between the two given points and the third point would be different, resulting in sides of unequal band an unequal perimeter.

Therefore, the only possible points for the third vertex are (3.67, 0) and (-3.67, 0) in order to satisfy both the given perimeter of 11 units and the condition that the triangle is non-degenerate.

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