Please help me with those questions please

Answer:

Since you are producing 3.6 mol CO2, you can calculate the starting moles of CH4 with the simple mole-to-mole ratio: 1 mol CH4 / 1 mol CO2 as a conversion factor. Taking 3.6 mol CO2 x 1 mol CH4 / 1 mol CO2 = 3.6 mol CH4 (after canceling out the moles of CO2 on the top and bottom of the calculation)

Explanation:

Answer:

b, their strong winds uproot many of the important plants

Explanation:

Answer:

B and BBr3

Explanation:

1) 3HBr + B = BBr3 + H2 (double all equation because H2)

2) 6HBr + 2B = 2BBr3 + 3H2

The simplest formula for the oxide of element X is XO₄.

To determine the simplest formula for the oxide of element X, we'll need to follow these steps:

1. Identify the atomic molar mass of element X and oxygen.
2. Convert the given mass of each element to moles.
3. Determine the mole ratio between element X and oxygen.
4. Simplify the mole ratio to the simplest whole numbers.

The atomic molar mass of element X is 100 g/mol, and the atomic molar mass of oxygen is 16 g/mol.

Step 1:
Element X: 100 g/mol
Oxygen: 16 g/mol

Step 2:
Convert the given mass of each element to moles:
Element X: (50.0 g) / (100 g/mol) = 0.50 moles
Oxygen: (32.0 g) / (16 g/mol) = 2.00 moles

Step 3:
Determine the mole ratio between element X and oxygen:
0.50 moles X / 0.50 = 1
2.00 moles O / 0.50 = 4

Step 4:
The simplest mole ratio is X1O4.

So, the simplest formula for the oxide of element X is XO₄.

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Answer:

Bromine

Explanation:

Br2 is an oxidizing agent, Na is a reducing agent.

The syringe heated up due to the formation of side product bromobenzene which leads to the whitish appearance.

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Answer: who is post malone

Explanation:

Answer:

Select the letter of the correct answer.

A vertical skateboard ramp is 12.5 feet high. The staircase leading to the top of the ramp is 15 feet long. How far away from the bottom of the ramp is the bottom of the staircase? Round your answer to the nearest tenth of a foot.

Press enter to interact with the item, and press tab button or down arrow until reaching the Submit button once the item is selected

A8.3 feet

B8.4 feet

C8.0 feet

D8.2 feet

Explanation:

so can someone help me please i only have 15 mins left !!!!!

Gasohol is a blend of gasoline and ethanol. To determine the maximum work that can be obtained by burning 1.003 mol of C2H5OH at 25°C and 1 atm, the Gibbs free energy equation can be utilized. What is Gibbs free energy equation? Gibbs free energy equation is a thermodynamic equation that quantifies the maximum quantity of work that may be obtained during a chemical reaction. T

he equation is as follows: ΔG = ΔH - TΔSThe values of ΔH and ΔS are calculated from thermodynamic tables or by calculating the enthalpy and entropy of the products and reactants, and the temperature, T, is usually specified in Kelvin. The change in Gibbs free energy, ΔG, is the maximum amount of energy that can be obtained from the reaction in the form of useful work if the reaction takes place at constant pressure and temperature. The reaction will proceed spontaneously if ΔG is negative. And if ΔG is positive, the reaction will not take place spontaneously. The solution to this problem is shown below:

First, let's figure out how much heat is produced when one mole of C2H5OH is burnt.ΔHrxn = [2(moles of CO2)(-393.5 kJ/mol) + 3(moles of H2O)(-285.8 kJ/mol)] - [(moles of C2H5OH)(-277.7 kJ/mol)]ΔHrxn = [2(2.006 mol)(-393.5 kJ/mol) + 3(3.009 mol)(-285.8 kJ/mol)] - [1.003 mol(-277.7 kJ/mol)]ΔHrxn = -2043.5 kJ/mol. Now, we'll figure out the entropy change for the reaction.ΔSrxn = [2(moles of CO2)(213.8 J/mol-K) + 3(moles of H2O)(69.9 J/mol-K)] - [(moles of C2H5OH)(160.7 J/mol-K)]ΔSrxn = [2(2.006 mol)(213.8 J/mol-K) + 3(3.009 mol)(69.9 J/mol-K)] - [1.003 mol(160.7 J/mol-K)]ΔSrxn = -104.3 J/mol-KThe temperature in Kelvin is 25°C.273 + 25 = 298 KΔG = ΔH - TΔSΔG = -2043.5 kJ/mol - (298 K)(-104.3 J/mol-K)/1000ΔG = -2032.6 kJ/mol. Therefore, the maximum work that can be obtained by burning 1.003 mol of C2H5OH is 2032.6 kJ/mol, which is the value of ΔG.

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Answer:

In the context of transaction processing, the acronym ACID refers to the four key properties of a transaction: atomicity, consistency, isolation, and durability. Atomicity. All changes to data are performed as if they are a single operation

Electrons.

Neutrons and Protons are contained with the positive nucleus, whilst negatively charged electrons surround it.

Answer:

HOPE IT HELPS....

Explanation:

Water has a very large heat capacity, so it takes a lot of energy to change the temperature. Warmer water will be less dense and move upward to the top of the test tube to boil while the colder water can stay at the bottom. Water does not conduct heat through it very much and ice conducts the heat through much less.

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \(\frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}\)

We're only talking about molar mass and time (t) here so we'll just concentrate on \(\sqrt{\frac{M2}{M1} } = \frac{t2}{t1}\). Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

\(\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}\)

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

\((\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2\)

\({\frac{M2}{131} } = (0.47)^2\)

\({\frac{M2}{131} } = 0.22\)

M2= 0.22 x 131

M2= 28.93 g/mol

Answer:

choice D. Ionic, because valence electrons are transferred.

Explanation:

The amount of heat needed to raise the temperature of 295g of ethanol by 87 degrees Celsius is 61,738 joules.

The amount of heat  can be calculated using the formula :Q = m * c * ΔT Where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. In this case, the mass of ethanol is 295g, the specific heat capacity of ethanol is 2.4 J/g°C, and the change in temperature is 87°C. Substituting the values into the formula: Q = 295g * 2.4 J/g°C * 87°C Q = 61,738 joules Therefore, the amount of heat needed to raise the temperature of 295g of ethanol by 87 degrees Celsius is 61,738 joules.

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Answer:

true

Explanation:

In the ground state of an atom of silver (Ag), the number of electrons with the quantum number l = 1 is 18.

The lowest possible energy that an atom has is called the ground state. The electrons in the ground state of an atom are in their lowest energy orbitals. Electrons are in the ground state when they are not moving (not in motion). In an atom of silver (Ag), the electron configuration is [Kr] 4d10 5s1. The values of quantum numbers can be determined as:

n= 5 (From 5s1, the value of n is 5.)

l= 0, 1, 2, 3, 4 (For d orbitals, the value of l = 2,

hence for s orbital, l= 0 and for p orbital l = 1.)

ml = -1, 0, +1 (For p orbitals, the value of ml = -1, 0, +1.)

ms = +1/2 or -1/2 (There are two spin states of the electron, ms = +1/2 or -1/2.)

In the case of l = 1 (for p orbital), ml can be either -1, 0, or +1.

Hence, there are three possible orbitals (px, py, pz). Each orbital can accommodate two electrons. Therefore, the total number of electrons with l = 1 (for p orbital) is 3 × 2 = 6. The remaining electrons with l = 0 (for s orbital) and l = 2 (for d orbital) are 2 and 10, respectively.

Therefore, the total number of electrons in the ground state of an atom of silver (Ag) with the quantum number l = 1 is 6. Answer: c) 18.

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The neutral atom fluorine-19 has 9 protons, 10 neutrons, and 9 electrons.

Fluorine-19 is a neutral atom that has 9 protons and 10 neutrons in its nucleus. This means that the atomic number of fluorine-19 is 9, as it has 9 protons. Additionally, the mass number of fluorine-19 is 19, as it has 10 neutrons in its nucleus.As a neutral atom, the number of electrons in fluorine-19 is equal to the number of protons, which is 9. This means that fluorine-19 has 9 electrons orbiting around its nucleus. These electrons are distributed in different energy levels or shells, with the first shell having 2 electrons and the second shell having 7 electrons.Fluorine is a highly reactive element that is a member of the halogen family. It has a unique ability to form a single covalent bond with almost all other elements, except for helium, neon, and argon. This makes it an essential element in many organic and inorganic compounds.Knowing these values allows us to better understand the chemical behavior of fluorine and its role in various chemical reactions.

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(i) The initial-boundary value problem for the given scenarios are as follows:

a) Scenario a:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 10, u(L, t) = 10 (constant temperature at the ends)

b) Scenario b:

PDE: ∂u/∂t = k * ∂²u/∂x²

Initial condition: u(x, 0) = 100 (boiling water temperature)

Boundary conditions: u(0, t) = 0 (temperature at x=0), ∂u/∂x(L, t) = 0 (thermal insulation at x=L)

(iii) The solution for the temperature distribution as time approaches infinity can be found by solving the appropriate steady state equation.

(i) The initial-boundary value problem formulation states the partial differential equation (PDE) governing the temperature distribution in the aluminum bar, along with the initial condition and boundary conditions.

In scenario (a), both ends of the bar are immersed in a medium with a constant temperature of 10 degrees Celsius, while in scenario (b), the end at x=0 is immersed in a medium with temperature 0 degrees Celsius and the end at x=L is insulated.

(ii) As time approaches infinity, the temperature distribution in the bar tends to reach a steady state.

In scenario (a), the temperature throughout the bar will eventually approach a constant value of 10 degrees Celsius, since both ends are immersed in a medium with that temperature.

In scenario (b), the temperature at x=0 will approach 0 degrees Celsius, while the temperature at x=L will remain constant due to thermal insulation.

(iii) To find the solution as time approaches infinity, we need to solve the appropriate steady state equation.

In scenario (a), the steady state equation is ∂²u/∂x² = 0, which implies that the temperature gradient is zero throughout the bar, resulting in a constant temperature of 10 degrees Celsius.

In scenario (b), the steady state equation is ∂²u/∂x² = 0 with the boundary condition u(0) = 0, which implies a linear temperature distribution from 0 degrees Celsius at x=0 to a constant temperature at x=L due to insulation.

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Answer:

C

Explanation:

d=300

t=6hr

speed=?

speed=300/6

speed=50m/hr the important thing in this question is to get the right units

The molecule that contains 6 atoms comprising a single functional group is Hexanol, under the condition that the given molecule is that of an alcohol.

Its molecules contain 6 carbon atoms. The finishing -ol states an alcohol (the OH functional group), and the hex- stem presents  that there are six carbon atoms in the LCC. The OH group is assembled to the second carbon atom.
Functional groups are considered as specified groups of atoms within molecules that are the reason for characteristic chemical reactions of those molecules . Some examples of functional groups include alcohols, aldehydes, ketones, carboxylic acids, esters, ethers, halogens, amines and amides.
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The complete question
Name a molecule that contains 6 carbon atoms with a single functional group that is an alcohol

It will take approximately 3.5 minutes to plate out 2.19 g of chromium metal from a solution of Cr3+ using a current of 55.2 amps in an electrolyte cell.

To calculate the time it will take to plate out 2.19 g of chromium metal using a current of 55.2 amps in an electrolyte cell, we can use Faraday's law of electrolysis.

First, we need to calculate the number of moles of Cr3+ ions that will be reduced to form the chromium metal. The molar mass of Cr is 52 g/mol, so 2.19 g of Cr is equivalent to 0.0421 moles (2.19 g / 52 g/mol).

Next, we need to determine the number of electrons required for the reduction of each Cr3+ ion to form Cr. From the half-reaction equation for the reduction of Cr3+ to Cr, we know that 3 electrons are required.

Using Faraday's law, we can calculate the total charge (Q) required to reduce 0.0421 moles of Cr3+ ions to form Cr:

Q = nF
where n is the number of moles of Cr3+ ions (0.0421 mol) and F is the Faraday constant (96,485 C/mol).

Q = 0.0421 mol x 3 x 96,485 C/mol = 11,726 C

Finally, we can calculate the time (t) required to plate out 2.19 g of chromium metal using a current of 55.2 amps:

t = Q / I
where I is the current (55.2 A).

t = 11,726 C / 55.2 A = 212.5 seconds or approximately 3.5 minutes

Therefore, it will take approximately 3.5 minutes to plate out 2.19 g of chromium metal from a solution of Cr3+ using a current of 55.2 amps in an electrolyte cell.

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Answer:

4.214 × 10^23 molecules.

Explanation:

Number of molecules in a substance can be calculated by multiplying the number of moles in that substance by Avagadro's number, which is 6.02 × 10^23.

That is, no. of molecule = n × Avagadro constant

In this case, there are 0.7 moles of fructose. Hence;

number of molecules = 0.7 × 6.02 × 10^23

no. of molecule = 4.214 × 10^23 molecules.

keep working on it keep going don't give up on your hopes and dreams just keep doing it's good you got this

Answer:

light bends and makes effects in the water

Explanation:

Answer:

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

From the question

velocity = 134 km/h

time = 7.5 hr

We have

distance = 134 × 7.5

We have the final answer as

Hope this helps you

Answer:

Explanation:

Sodium bicarbonate,

NaHCO

3

, will decompose to form sodium carbonate,

Na

2

CO

3

, water, and carbon dioxide,

CO

2

2

NaHCO

3(s]

→

Na

2

CO

3(s]

+

CO

2(g]

+

H

2

O

(g]

Notice that you have a

2

:

1

mole ratio between sodium bicarbonate and sodium carbonate. This means that the reaction will produce half as many moles of the latter than whatever number of moles of the former underwent decomposition.

Use sodium carbonate's molar amss to determine how many moles you'd get in that sample

0.685

g

⋅

1 mole NaHCO

3

84.007

g

=

0.008154 moles NaHCO

3

Now, if the reaction were to have a

100

%

yield, it would produce

0.008154

moles NaHCO

3

⋅

1 mole Na

2

CO

3

2

moles NaHCO

3

=

0.004077 moles Na

2

CO

3

Use the molar mass of sodium carbonate to determine how many grams would contain this many moles

0.004077

moles

⋅

105.99 g

1

mole

=

0.4321 g Na

2

CO

3Sodium bicarbonate,

NaHCO

3

, will decompose to form sodium carbonate,

Na

2

CO

3

, water, and carbon dioxide,

CO

2

2

NaHCO

3(s]

→

Na

2

CO

3(s]

+

CO

2(g]

+

H

2

O

(g]

Notice that you have a

2

:

1

mole ratio between sodium bicarbonate and sodium carbonate. This means that the reaction will produce half as many moles of the latter than whatever number of moles of the former underwent decomposition.

Use sodium carbonate's molar amss to determine how many moles you'd get in that sample

0.685

g

⋅

1 mole NaHCO

3

84.007

g

=

0.008154 moles NaHCO

3

Now, if the reaction were to have a

100

%

yield, it would produce

0.008154

moles NaHCO

3

⋅

1 mole Na

2

CO

3

2

moles NaHCO

3

=

0.004077 moles Na

2

CO

3

Use the molar mass of sodium carbonate to determine how many grams would contain this many moles

0.004077

moles

⋅

105.99 g

1

mole

=

0.4321 g Na

2

CO

3

By using the given data, the percent yield for sodium carbonate (Na₂CO₃) is equal to 127.

Percent yield of any data can be calculated as:

% yield = (Actual value / Theoretical value) × 100

In the question actual yield of sodium carbonate is given, which is equal to 2.04 grams. And in the table theoretical yield of sodium carbonate also given, which is equal to 1.60 grams.

Now putting these value in the above equation, we get:

% yield = (2.04 / 1.60) × 100 = 127

Hence, percent yield of sodium carbonate (Na₂CO₃) is 127.

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The conductivity decreases initially as acid and base neutralize, passes through a minimum at the highest salt concentration, and then increases again as acidity increases and salt concentration decreases.

The conductivity decreases as the volume of H₂SO₄ is added to the barium hydroxide because the acid and base are neutralizing each other, forming salt and water which are poor conductors.

As the volume of acid added increases, the conductivity passes through a minimum because the salt concentration is at its highest point and then increases again as the acid and base are no longer neutralizing and the salt concentration begins to decrease.

In addition, the addition of sulfuric acid leads to the formation of more dissolved ions in solution, which increases the conductivity. The increase in concentration of these ions can be attributed to the protonation of the hydroxide ions and the formation of sulfate ions. As the acidity increases further, the conductivity increases again.

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Your question seems incomplete, but I suppose the question was:

"Explain why the conductivity decreases, passes through a minimum, and then increases as the volume of H₂SO₄ added to the barium hydroxide."