Please help me with this!

Answer:

Here we try the method of trial and error to find out if the equations have a common answer as zero

Step-by-step explanation:

Now,

(a) x²-4=0

(b) x²=-4

(c) 3x²+12=0

(d) 4x²=16

(e) 2(x-2)2=0

Here if we check the first equation i.e x²-4=0

Equating - 2²-4=4-4

=0

2²-4= 4-4

=0

So option (a) is true

Now x²=-4

Substituting, - 2²=4 & 2²=4

So here we get 4≠-4

Therefore, (b) is not true

Now 3x²+12=0

3(-2)²+12= 3(4)+12

=12+12= 24

3(2)²+12= 12+12

= 24

4x²=16

Substituting, 4(-2)²= 4(4)= 16

4(2)²= 4(4)= 16

So option (d) is also true

Now, 2(x-2)2=0

Substituting, 2(-2-2)2= 2(-4)2

4(-4)= - 16

2(2-2)2= 2(0)2

=4(0)=0

Here when we put x=-2, we get - 16

when we put x=2, we get 0

So the following equation is true only for x=2 and not x=-2

I hope this helps ;)

Answer:

Math notes

Step-by-step explanation:

Here are some of my notes from my class but you can use them to answer your questions and if you need help with a question just tell me!!

It looks like I help to put the link in the chat because it doesn't let my submit it.

Hopes this helps!!

Answer:

m∠A = 31

b = 13.3

Step-by-step explanation:

The difference quotient for the given function is 9 -2/h.

The difference quotient for the given function can be calculated as:

[f(x+h) - f(x)]/h

= [(3(x+h)² - 2(x+h) + 5) - (3x² - 2x + 5)]/h

= (3x² + 6xh + 3h² - 2x - 2h + 5 - 3x² + 2x - 5)/h

= (6xh + 3h² - 2h)/h

= (6x + 3h -2)/h

Simplifying the expression further, we get:

(6x + 3h -2)/h = 6 + 3h/h -2/h

= 6 + 3 -2/h

= 9-2/h

Therefore, the difference quotient for the given function is 9 -2/h.

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"Your question is incomplete, probably the complete question/missing part is:"

Find the difference quotient [f(x+h)-f(x)]/h, where h≠0, for the function below.

f(x)=3x² -2x+5. Simplify your answer as much as possible.

The required white effective interest rate is 0.71% more than his nominal interest rate.

Compound interest is the interest on deposits computed on both the initial principal and the interest earned over time.

Here,

White Effective interest R,
\(R=(1+i/m)^m)-1\\R=(1+0.1362/4)^4)-1\\R =0.1433*100=\)
R = 14.33 percent

So

Difference in interest = 14.33%-13.62%
                                    =0.71%

Thus, the required white effective interest rate is 0.71% more than his nominal interest rate.

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Answer:

13.25

Step-by-step explanation:

Answer:

13.25

Step-by-step explanation:

I did the ixl

Answer:

#5 the sum would be on the right side because it is positive

Answer:

We have a prism with a volume of 16y⁴ + 16y³ + 48y² cubic units.

Its volume is equal to the area of its base times its height.

Of course, for those to be the base area and height of this prism, they would have to multiply to 16y⁴ + 16y³ + 48y² cubic units.

Let's test each of these answers to see which gives us the correct volume.

--------------------------------------------------------------------------------------------------

a base area of 4y square units and height of 4y² + 4y + 12 units

We find the volume by multiplying the base area by the height...

4y(4y² + 4y + 12)

Distribute the 4y to each term inside the parentheses.

16y³ + 16y² + 48y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 8y² square units and height of y² + 2y + 4 units

We find the volume by multiplying the base area by the height...

8y²(y² + 2y + 4)

Distribute the 8y² to each term inside the parentheses.

8y⁴ + 16y³ + 32y²

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 12y square units and height of 4y² + 4y + 36 units

We find the volume by multiplying the base area by the height...

12y(4y² + 4y + 36)

Distribute the 12y to each term inside the parentheses.

48y³ + 48y² + 432y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 16y² square units and height of y² + y + 3 units

We find the volume by multiplying the base area by the height...

16y²(y² + y + 3)

Distribute the 16y² to each term inside the parentheses.

16y⁴ + 16y³ + 48y²

The volume fits, so these could be the base area and height of our prism.

--------------------------------------------------------------------------------------------------

D. a base area of 16y² square units and height of y² + y + 3 units

--------------------------------------------------------------------------------------------------

Step-by-step explanation:

An inverse-square central force field is  \(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\).

From Newton's second law of motion,

mass × acceleration = Force acting on the mass

Resolving the force F along x and y directions and applying Newton's second law of motion,

Using,

\(r = \sqrt{x^2+y^2}\)

​

Therefore,

\(m\frac{d^2x}{dt^2} =-|F|cos \theta\)

\(mx^{''} = -\frac{k}{x^2+y^2} \frac{x}{\sqrt{x^2+y^2} } \\\\mx^{''} = - \frac{kx}{(x^2+y^2)^\frac{3}{2} }\\ \\mx^{''} = - \frac{kx}{r^3}\)

Where \(r = \sqrt{x^2+y^2}\)

​ and cos⁡θ = \(\frac{x}{\sqrt{x^2+y^2} }\)

Similarly using,

\(r = \sqrt{x^2+y^2}\)

we get,

 \(m\frac{d^2y}{dt^2} = -|F|sin\theta\)

\(mx^{''} = -\frac{k}{x^2+y^2} \frac{x}{\sqrt{x^2+y^2} } \\\\mx^{''} = - \frac{kx}{(x^2+y^2)^\frac{3}{2} }\\ \\mx^{''} = - \frac{kx}{r^3}\)

Where \(r = \sqrt{x^2+y^2}\)

​ and sinθ = \(\frac{y}{\sqrt{x^2+y^2} }\)

Therefore we showed that holds

\(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\)

Hence the answer is an inverse-square central force field is  \(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\).

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An equation that mode the relationship between thee two variable is y=2x+3 .

Let x represent the number of 6-month period worked

Let y represent the total number of paid vacation day

According to the question,

When he started work, he was given three paid day of vacation. For each six-month period he pay at the job, his vacation is increased by two day.

Each year has 2 six-month periods. After 4.4 years Roberto will have worked 8.8 six-month periods. He will have been given vacation days for each of the 8 whole working periods he has completed. x=8 y=2*8+3 y=19

An equation that mode the relationship between thee two variable is y=2x+3 (Total vacation time equals 2 days times x plus the 3 days he was given at the start).

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Answer:

Number>2

Step-by-step explanation:

If number is 1 then 6×1=6

6×4=24

which is less than 50

If number is 2 then 6×2=12

12×4=48
which is less than 50

Answer:

what the hecker is that.

okay so your simplifying it, 12? i think.

Answer:

Step-by-step explanation:

Without a domain you cannot answer this question.  We can find the maximum value of the function if the spread of acceptable input values (x-values) is specified and the range is likewise specified.

For example, if acceptable input values x are {0, 2} and acceptable input values y are {4, 5}, then the maximum value of p would be 3(2) + 2(5), or 16.

Rounded to the nearest whole number, the container is approximately 52% full.

To find the percentage that the shipping container is full, we need to compare the volume of the shipped goods to the total volume of the container.

Given dimensions:

Length = 35 ft

Width = 8 ft

Height = 9 ft 9 in

We need to convert the height to feet by dividing the inches by 12:

Height = 9 ft + (9/12) ft = 9.75 ft

Total volume of the container:

Volume = Length × Width × Height

Volume = 35 ft × 8 ft × 9.75 ft

Volume = 2730 ft³

Volume of the shipped goods:

Given as 1420 ft³

To find the percentage filled, we divide the volume of the shipped goods by the total volume of the container and multiply by 100:

Percentage filled = (Volume of shipped goods / Total volume of container) × 100

Percentage filled = (1420 ft³ / 2730 ft³) × 100

Percentage filled ≈ 52.0%

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The initial solution has a concentration of 0.50 moles of lithium acetate per liter of solution (M).

To dilute 250 ml of this solution to a final volume of 750 ml, we need to multiply the initial concentration by the ratio of the final volume to the initial volume:
C1V1 = C2V2
0.50 M x 0.250 L = C2 x 0.750 L
C2 = (0.50 M x 0.250 L) / 0.750 L
C2 = 0.17 M
Therefore, the final concentration of the diluted solution is 0.17 M.
After diluting 250 mL of a 0.50 M lithium acetate solution to a volume of 750 mL, the concentration of the solution can be calculated using the dilution formula: M1V1 = M2V2. Here, M1 is the initial concentration (0.50 M), V1 is the initial volume (250 mL), M2 is the final concentration, and V2 is the final volume (750 mL). By solving for M2, you'll find that the concentration of the diluted solution is approximately 0.17 M.

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Answer:

14 1/8 feet by 18 3/8.

Step-by-step explanation:

I took 1 5/8 feet and added it to both...

The new dimensions of the garden will be 18 3/8 feet and 14 1/8 feet.

It is a polygon with four sides. The total interior angle is 360 degrees. A rectangle's opposite sides are parallel and equal, and each angle is 90 degrees. Its diagonals are all the same length and intersect in the center.

The dimensions of a rectangular garden are 12 1/2 feet by 16 3/4 feet. If 1 5/8 feet is added to all the sides.

Then the length will be

L = 16  3/4 + 1  5/8

L = 17  (3/4 + 5/8)

L = 17  11/8

L = 18  3/8 feet

Then the width will be

W = 12  1/2 + 1  5/8

W = 13  (1/2 + 5/8)

W = 13  9/8

W = 14  1/8 feet

The new dimensions of the garden will be 18 3/8 feet and 14 1/8 feet.

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The table shows the total cost to be a member of the gym for different numbers of months.



Number of months. total costs

3. $53.97

6. $77.94

12. $125.88



Create a function that gives the total cost C, in dollars to be a member of the gym given the number of months M of membership.

_____________________________________

Total cost = M* (factor per month ) + b

_____________________________________

The expression for a linear equation is

*The slope-intercept form.

y = mx + b

m= (y2-y1)/ (x2-x1) (I)

y-intercept is (0, b)

*and the point-slope form

y- y1 = m(x-x1) (II)

________________________

Point 1 (3, 53.97)

Point 2 (12, 125.88)

Replacing in (II)

The slope m = (y2- y1)/ (x2-x1) = (125.88- 53.97)/(12-3) = 7.99

y - 53.97 = 7.99* (x- 3)

y = 7.99 x - 7.99* 3 + 53.97

y = 7.99x + 30

____________________

Verifying

y = 7.99x + 30

x= 3

y = 7.99*3 + 30

y= 53.97

x= 6

y = 7.99*6 + 30

y= 77.94

x= 12

y = 7.99*12 + 30

y= 125.88

_________________________

Answer

The linear function is y = 7.99x + 30

Answer: a, -1/2x-6=y

Step-by-step explanation:

Answer:

-5/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

(3x + 4)(5x - 2)(4x - 3) = 60x^3 + 11x^2 - 74x + 24 =>

a  = 60

b = 11

c = -74

d = 24

Answer:

"In

In a 30-60-90 triangle, the sides are in a ratio of 1:√3:2.

So, the hypotenuse of the triangle is 62 = 12 ft long.

The longer leg of the triangle is 6√3 = 10.8 ft long (to the nearest tenth of a foot)

Answer:

-2 = -3x + 5

-2 -5 = -3x

-7 = -3x

-7/-3 = x

x=7/3

Answer: Geometric and common difference is 1/3

Step-by-step explanation:

Answer:

10 minutes.

Step-by-step explanation:

Plane A = 1 ton of fuel left

Plane B = 21 tons of fuel Left

Fuel transfer = 1 ton per minute

In order for them to have the same amount of fuel,

We add up the fuel left in Plane A and Plane B

= 21 + 1 = 22 tons

This means each plane will equally have 11 tons

How long it will take to refuel plane A until both planes have the same amount of fuel is calculated as:

Plane B will transfer 10 tons of fuel to Plane A which would give plan A a total of 11 tons.

Since transfer rate = 1 ton per minute

= 1 ton = 1 minute

10 tons = 10 minutes.

Answer:

94.5 ft

Step-by-step explanation:

4x13 = 52

5x5 = 25

2.5x7 = 17.5

52+25+17.5 = 94.5ft

- Gage Millar, Algebra 2 tutor

Answer:

x = -0.25

Step-by-step explanation:

2+5x-3x+6x

5x-3x+6x = -2

8x = -2

x = -2/8

x = -0.25

Answer: 2+8x

step by step solution

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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\(\\ \sf\Rrightarrow f(x)=\sqrt{x+2}-6\)

\(\\ \sf\Rrightarrow f(-2)\)

\(\\ \sf\Rrightarrow \sqrt{-2+2}-6\)

\(\\ \sf\Rrightarrow 0-6\)

\(\\ \sf\Rrightarrow -6\)

And

\(\\ \sf\Rrightarrow f(-1)\)

\(\\ \sf\Rrightarrow \sqrt{-1+2}-6\)

\(\\ \sf\Rrightarrow \sqrt{1}-6\)

\(\\ \sf\Rrightarrow 1-6\)

\(\\ \sf\Rrightarrow -5\)

And

\(\\ \sf\Rrightarrow f(2)\)

\(\\ \sf\Rrightarrow \sqrt{2+2}-6\)

\(\\ \sf\Rrightarrow \sqrt{4}-6\)

\(\\ \sf\Rrightarrow 2-6\)

\(\\ \sf\Rrightarrow -4\)

And

\(\\ \sf\Rrightarrow f(7)\)

\(\\ \sf\Rrightarrow \sqrt{7+2}-6\)

\(\\ \sf\Rrightarrow \sqrt{9}-6\)

\(\\ \sf\Rrightarrow 3-6\)

\(\\ \sf\Rrightarrow -3\)