Please help me with this

Answer:

23

Step-by-step explanation:

seven years ago his father is 40yrs old and Richard is 16 so add seven for his present age it will be 23

Answer:

18-19

Step-by-step explanation:

The study of hypnosis and its relationship to hysteria was the starting point for the development of psychoanalysis by Sigmund Freud.

The study of hypnosis and hysteria in the late 19th century by Sigmund Freud and his contemporaries led to the development of psychoanalysis, a form of psychotherapy that emphasizes the role of unconscious thoughts and feelings in shaping behavior. Through his work with patients suffering from hysteria, Freud became interested in the idea that psychological conflicts could be traced back to early childhood experiences, and that these conflicts could be resolved through the exploration of unconscious thoughts and feelings. This eventually led to the development of psychoanalysis as a theory and practice for the treatment of psychological disorders.

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Answer:

He should have said that his small brother had 100 small building bricks, but lost 5 in total now.

Answer:

1/2x plus 1/3

Step-by-step explanation:

Answer:

the guy above me is correct

Step-by-step explanation:

Answer:

Both

Step-by-step explanation:

both???????????????????????????

using exponents, On simplifying the equation, we get =4m+8.

The PEMDAS order of operations must be followed when you want to simplify a mathematical equation without using parenthesis (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction). There are no parenthesis in the expression, so you may start looking for exponents. If it does, first make that simpler.

Work simplification is to develop better work processes that boost output while cutting waste and costs.

Simplifying an expression is the same as solving a mathematical issue. When you simplify an equation, you essentially try to write it as simply as you can. There shouldn't be any more multiplication, dividing, adding, or deleting to be done when the process is finished.

Given equation,

m-(8-3m)

=m-8+3m

=4m+8

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Answer:

225

Step-by-step explanation:

Answer:

225

Step-by-step explanation:

7.50 times 30 = 225

Answer:

\(y = \frac{3}{2} x + 13\)

Step-by-step explanation:

1) Use point-slope formula \(y-y_1 = m (x-x_1)\) to find the slope-intercept form (or y = mx + b form) of the equation. m represents the slope, and \(x_1\) and \(y_1\) represent the x and y values of a point the line intersects. So, substitute \(\frac{3}{2}\) for m, -4 for \(x_1\), and 7 for \(y_1\). Then, simplify and isolate y on the left side like so:

\(y-(7) = \frac{3}{2} (x - (-4)) \\y -7 = \frac{3}{2} (x + 4) \\y - 7 = \frac{3}{2} x + 6\\y = \frac{3}{2} x + 13\)

To make logistic regression work in this case, we would need to formulate the hypothesis and apply it to the given training examples.
The hypothesis for logistic regression can be written as follows:
hθ(x) = g(θ^T * x)
Where:
- hθ(x) is the predicted probability that the house is expensive (class 1) given the features x.
- θ is the vector of coefficients that we want to estimate.
- x is the vector of features, in this case, the depth and frontage of the house.

The function g(z) is the sigmoid function, which maps any real-valued number to a value between 0 and 1. It is defined as follows:
g(z) = 1 / (1 + e^(-z))

To apply this hypothesis to the training examples, we would calculate the predicted probabilities for each example and compare them to the actual class labels. We can then use a cost function, such as the cross-entropy loss function, to measure the error between the predicted probabilities and the actual class labels. The goal is to find the values of θ that minimize this error.
By using an optimization algorithm, such as gradient descent, we can iteratively update the values of θ to minimize the cost function and find the optimal parameters for our logistic regression model.
Overall, the full hypothesis for logistic regression in this case is:
hθ(x) = g(θ₀ + θ₁ * depth + θ₂ * frontage)

Where θ₀, θ₁, and θ₂ are the coefficients that we need to estimate.

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The critical point of the function is (0, 2). The discriminant D(x,y) to be -256*(2-y)^3*6^(2(x+2y)).

The function is given as (x,y) = 6^(x2−y2+4y) and we are required to find the critical points of the function.

We will have to find the partial derivatives of the function with respect to x and y respectively.

We will then have to equate the partial derivatives to zero and solve for x and y to obtain the critical points of the function.

Partial derivative of the function with respect to x:

∂/(∂x) (x,y) = ∂/(∂x) 6^(x2−y2+4y) = 6^(x2−y2+4y) * 2xln6... (1)

Partial derivative of the function with respect to y

:∂/(∂y) (x,y) = ∂/(∂y) 6^(x2−y2+4y) = 6^(x2−y2+4y) * (-2y+4)... (2)

Now, equating the partial derivatives to zero and solving for x and y:

(1) => 6^(x2−y2+4y) * 2xln6 = 0=> 2xln6 = 0=> x = 0(2) => 6^(x2−y2+4y) * (-2y+4) = 0

=> -2y + 4 = 0

=> y = 2

Therefore, the critical point of the function is (0, 2).

Next, we will compute the discriminant D(x, y):

D(x, y) = f_{xx}(x, y)f_{yy}(x, y) - [f_{xy}(x, y)]^2 = [6^(x2−y2+4y) * 4ln6][6^(x2−y2+4y) * (-2) + 6^(x2−y2+4y)^2 * 16] - [6^(x2−y2+4y) * 4ln6 * (-2y+4)]^2= -256*(2-y)^3*6^(2(x+2y))

Hence, the discriminant D(x,y) to be -256*(2-y)^3*6^(2(x+2y)).

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1   Y is distributed as N(aμ + b, a^2σ^2), as desired.

2  We have shown that under these conditions, E[XY] = E[X]E[Y].

To prove that Y is distributed as N(aμ + b, a^2σ^2), we need to show that the mean and variance of Y match those of a normal distribution with parameters aμ + b and a^2σ^2, respectively.

First, let's find the mean of Y:

E(Y) = E(aX + b) = aE(X) + b = aμ + b

Next, let's find the variance of Y:

Var(Y) = Var(aX + b) = a^2Var(X) = a^2σ^2

Therefore, Y is distributed as N(aμ + b, a^2σ^2), as desired.

We can use the definition of covariance to prove that E[XY] = E[X]E[Y]. By the properties of expected value, we know that:

E[XY] = ∫∫ xy f(x,y) dxdy

where f(x,y) is the joint probability density function of X and Y.

Then, we can use the fact that X and Y are independent to simplify the expression:

E[XY] = ∫∫ xy f(x) f(y) dxdy

= ∫ x f(x) dx ∫ y f(y) dy

= E[X]E[Y]

where f(x) and f(y) are the marginal probability density functions of X and Y, respectively.

Therefore, we have shown that under these conditions, E[XY] = E[X]E[Y].

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The measure of <1 is 147 degree.

Given:

m∠2 = 12x - 15

m∠7 = 3x + 21

Since angles 2 and 7 are alternate Exterior angles, they are congruent.

So, 12x - 15 = 3x + 21

12x - 3x = 21 + 15

9x = 36

x = 4

So, <2 = 12x - 15= 48 - 15 = 33

Now, <1 + <2 = 180 (Linear Pair)

<1 + 33 = 180

<1 = 147 degree

Thus, the measure of <1 is 147 degree.

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The ways are the \(C_{20} ^{90}\) which are we  there to select the applicants who will be hired with the help of combination.

According to the statement

we have to find that the number of ways are there to select the applicants who will be hired.

So, For this purpose, we know that the

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter.

Here we use the combination.

And from the given information:

20 applicants from a pool of 90 applications will be hired.

And according to this the combination becomes:

\(C_{20} ^{90}\)

then solve it

\(C_{20} ^{90} = \frac{90!}{20! (70!)}\)

\(C_{20} ^{90} = \frac{90*89*88*87*86*85*84*83*82!}{20*19*18*17*16*15*14!}\)

Then after solve it

\(C_{20} ^{90} = \frac{89*11*87*43*14*83*82!}{19*14!}\)

Now open another factorial

\(C_{20} ^{90} = \frac{89*11*87*43*14*83*82*81*80*79*78*77*76*75*74*73*72*71}{19*14*13*12*11*10*9*8*7*6*5*4*3*2*1}\)

Now solve this then

\(C_{20} ^{90} = {89*11*87*43*83*82*79*15*74*73*71}\).

So, The ways are the \(C_{20} ^{90}\) which are we  there to select the applicants who will be hired with the help of combination.

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The one mean Z test can be used for small samples of size less than 15 when the population standard deviation is known.

The one-mean z-test is a hypothesis test that is used to test a hypothesis about the mean of a population when the population standard deviation is known, and the sample size is large (typically greater than 30).

When the sample size is small (less than 15), the one-mean z-test is not appropriate because the assumptions of the test may not be met.

When the sample size is small, we typically use a t-test instead of a z-test to test a hypothesis about the population mean.

Specifically, we use a one-sample t-test when the population standard deviation is unknown, and the sample size is small (typically less than 30).

The one-sample t-test uses a t-distribution to calculate the p-value and test the null hypothesis about the population mean.

It is important to note that the sample size of 15 is not a hard and fast rule for when to switch from the z-test to the t-test.

The decision of which test to use depends on the specific context and the assumptions of the test.

In general, if the population standard deviation is unknown and the sample size is small (less than 30), then we use the t-test. If the population standard deviation is known and the sample size is large (greater than 30), then we use the z-test.

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Answer:74 blue beads and 90 purple beads

Step-by-step explanation:

first you need to take the total number of beads 164 divide by the 2 colors so 164÷2=86 then you subtract the 8 more purple from 1/2 of 86 and you get 74 then you add 8 more to the other half of 82 and get 90 purple and 74 blue.

The level of Q that will yield the maximum net benefits is 4.92, and the maximum level of benefits is 96.

To find the level of Q that maximizes net benefits, we need to calculate the difference between the total benefits (B(Q)) and the total costs (C(Q)). In this case, the net benefits (NB) can be represented as NB(Q) = B(Q) - C(Q).Given B(Q) = 40Q - 2\(Q^2\) and C(Q) = 4 + 2\(Q^2\), we can substitute these expressions into the net benefits equation:
NB(Q) = (40Q - 2\(Q^2\)) - (4 + 2\(Q^2\))
Simplifying, we get:
NB(Q) = 40Q - 2\(Q^2\) - 4 - 2\(Q^2\)
NB(Q) = -4\(Q^2\) + 40Q - 4
To find the level of Q that maximizes net benefits, we need to find the value of Q that maximizes NB(Q). This can be done by finding the maximum point of the quadratic function. In this case, the maximum point occurs at the vertex of the quadratic.
The formula for the x-coordinate of the vertex of a quadratic function of the form a\(x^2\) + bx + c is given by x = -b / (2a). In our case, a = -4 and b = 40.

Calculating the x-coordinate of the vertex:
Q = -40 / (2 * -4)
Q = 40 / 8
Q = 5
Therefore, the level of Q that yields the maximum net benefits is Q = 5. Plugging this value back into the net benefits equation, we can calculate the maximum level of benefits:
NB(5) = -4\((5)^2\) + 40(5) - 4
NB(5) = -4(25) + 200 - 4
NB(5) = -100 + 200 - 4
NB(5) = 96
Hence, the maximum level of benefits is 96.

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Answer:

conclusion of representative is incorrect

Step-by-step explanation:

The total random samples of 200 homes in Miami uses 3 boxes of tissues per home.

This is true only for Miami. Miami's population is not the correct representation of the population of USA.

Also, there are several other factors such as population group residing in Miami, their education level, heath etc.  plays a major role as a variable. These variables in case of USA will be entirely different.

Hence, conclusion of representative is incorrect

Answer:

5 x S = M (S=Students, M = money); 5 x 25 = 100

Answer:

Baguette is very important

Step-by-step explanation:

they don't have bidet but baguette

Answer:

honestly i think its a pretty country, its pretty nice and wish i could go.  

Step-by-step explanation:

The equation y = 3x +a / 2x - 5 can be expressed in terms of a and y as x = (a - 5y) / (2y-3)

Given equation y = 3x + a / 2x - 5

= y(2x - 5) = 3x + a

= 2xy - 5y = 3x + a

= 2xy - 3x = a - 5y

= x(2y-3) = a - 5y

Hence, x = (a - 5y) / (2y - 3)

First, we will move the denominator 2x-5 and multiply it by y giving us 2xy-5y. Next, we will move all the terms which contain only a and y to one side and the rest remaining to another side, giving us 2xy - 3x = a - 5y. Since we need to express the equation in terms of x we take it as common from left-hand side of the equation and the remaining part we move to the right-hand side as the denominator. Hence we get our equation in terms of a and y as x = (a - 5y) / (2y - 3).

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Answer:

hfjf fnnc v jud dbhj  ejem emd  jfbf

Step-by-step explanation:

Answer:

The answer is x = \(\frac{-5}{3}\).

Step-by-step explanation:

First, we expand the brackets. Therefore:

\(2x+6 = -4x+(-4)\)

\(2x+6 = -4x -4\)

Then, we separate the like terms:

\(2x+4x = -4-6\)

Then we add the like terms up and solve for x:

\(6x = -10\)

Therefore:

\(x = \frac{-10}{6}\)

which, simplified, is:

\(x = \frac{-5}{3}\).

Answer:

1. I assume you just pick some arbitrary x and y numbers to plug in the equation. but if you answer part b and c first, part a might be easier for what values to choose.

2. if you do a quick browser search for how to find the max height of a parabola, then you can learn how to.

3. research on Browser. you can also just make y = 0.

vertex is max height, both zeros is just solving the equation for the x values. axis of symmetry is just the vertex point with a line through it.

Answer:(60 + 12)(60 – 12)

Step-by-step explanation:

a) The equation for the elasticity is\(\frac{1000p}{p^2 + 4p + 4}\).

b) The elasticity at p = 9 is approximately 74.38, indicating elastic demand.

c)\(\frac{d(TR) }{dp } =\frac{3p^2 + 8p + 4}{500 }\)the value(s) of p for which total revenue is a maximum.

a) To find the elasticity of the demand function, we use the formula:

E(p) =\(\frac{ p }{q}\)* (\(\frac{dq }{dp}\))

where p is the price and q is the quantity demanded.

Given the demand function q = D(p) = \(\frac{(p + 2)^2}{ 500}\), we can find the derivative of q with respect to p:

\(\frac{dq }{dp}\) = \(\frac{2(p + 2) }{ 500}\)

Now we can substitute the values into the elasticity formula:

E(p) =\(\frac{ p }{q}\)* (dq / dp)

     = (\(\frac{p }{\frac{((p + 2)^2 )}{500} }\)) * \(\frac{2(p + 2) }{ 500}\)

     = \(\frac{(p * 2(p + 2)) }{ ((p + 2)^2) * 500}\)

Simplifying further, we get:

E(p) =\(\frac{ (1000p) }{ (p^2 + 4p + 4)}\)

b) To find the elasticity at p = 9, we substitute the value of p into the elasticity equation:

E(9) =\(\frac{ (1000(9)) }{((9^2 + 4(9) + 4))}\)

     = \(\frac{9000 }{ (81 + 36 + 4)}\)

     =\(\frac{ 9000}{ 121}\)

     = 74.38

Since the elasticity at p = 9 is greater than 1, the demand is elastic. Elasticity greater than 1 means that a percentage change in price leads to a larger percentage change in quantity demanded.

c) To find the value(s) of p for which total revenue is a maximum, we need to find the maximum of the total revenue function.

Total revenue (TR) is given by the product of price (p) and quantity demanded (q):

TR = p * q

Substituting the given demand function into the total revenue equation:

TR = \(\frac{p * ((p + 2)^2}{500}\)

   =\(\frac{ (p^3 + 4p^2 + 4p) }{500}\)

To find the maximum, we take the derivative of TR with respect to p and set it equal to zero:

\(\frac{d(TR) }{dp } =\frac{3p^2 + 8p + 4}{500 }\)

Solving this equation for p will give us the value(s) of p for which total revenue is a maximum.

Unfortunately, the equation is not factorable, so we can use numerical methods such as graphing or approximation techniques to find the value(s) of p for which total revenue is a maximum.

In summary, the equation for the elasticity is E(p) = \(\frac{1000p}{p^2 + 4p + 4}\). The elasticity at p = 9 is approximately 74.38, indicating elastic demand. To find the value(s) of p for which total revenue is a maximum, further calculations or approximation methods are needed.

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Answer:

41% or 41/100

Step-by-step explanation:

Since percentage (%) means out of 100 using fractions would be the easiest

18/100 + 23/100 = 41/100 or 41%

41/100 is non-reducible.

to check you did the right math, all percentages should equal 100

44/100 + 15/100 = 59/100

59/100 + 41/100 = 100/100

your answer is 41% or 41/100

hope this helps:)

Answer: 7/4

Step-by-step explanation: To find the slope of a line, pick any two integer points, in this scenario the only two are (3,4) and (-1,-3). The slope is the rise over run, so think about it. To get from (-1,-3) to )3,4) you need to rise 7 units (difference in y coordinates) and from there you need to run 4 units, so it is 7/4. Keep in mind that rising up is positive for y and running to the right is positive for x.

Answer:

\(\frac{7}{4}x\)

Step-by-step explanation:

How do you find slope on a graph? The slope is "rise/run" where "rise" is how much y spaces are moved to the next point and "run" is the how much spaces are moved to the next x point.

Step One: In this case, the point moves up 7 spaces to the next point, so that's the "rise" and then it moves 4 spaces to the right to the next point, so that's the "run"

Step Two: When we put it together, it is 7/4x. The x is just an indication that this is slope, and you don't have to worry about it until you learn how to plug it in.

Answer:

See below

Step-by-step explanation:

(a+11)9

a*9=9a

11*9=99

a+11 is the simplified version.

-hope it helps