Please help me, What is 640.31 written in expanded form?

Isolating the variable y in the second equation, we have:

Now, using this value of y in the first equation, we have:

The solution of the system is x = -8 and y = 1.

Answer:

Area of green trapezoid would be:

(length of two parallel sides × h) ÷ 2

( 5cm x 2cm) ÷ 2

= 5 square centimetres

Area of the orange trapezoid would be:

(length of two parallel sides x h) ÷ 2

(10.5 cm × 3) ÷ 2

( 31. 5) ÷ 2

(15. 75 square centimetres

NOTE: h represents height

The length of the rectangle is 6 meters longer than the width of the rectangle. Let's suppose the width is x meters. So, the length of the rectangle is (x + 6) meters.Area of rectangle is 28 square meters.Area of rectangle = length × width28 = (x + 6) × x.Solve for xx² + 6x - 28 = 0(x + 7)(x - 4) = 0x = -7 or 4

The negative value of x because it is not possible.So, the width of the rectangle is 4 meters.The length of the rectangle is (x + 6) meters= 4 + 6= 10 meters.The length of a rectangle is 6 meters longer than the width. If the area is 28 square meters, we need to find the dimensions of the rectangle. Let's suppose the width of the rectangle is x meters. We know that the length of the rectangle is 6 meters more than the width, so the length of the rectangle is (x + 6) meters.Area of a rectangle is the product of its length and width. So, the area of the rectangle is (x + 6) × x. We know that the area of the rectangle is 28 square meters. Therefore, we can write the following equation:28 = (x + 6) × x.To find the value of x, we need to solve this quadratic equation.28 = x² + 6x.Rearranging the terms, we get:

x² + 6x - 28 = 0

We can solve this equation by using the quadratic formula, but we will use the factoring method. We need to find two numbers whose product is -28 and whose sum is 6. These numbers are +7 and -4. Therefore, we can write:

x² + 7x - 4x - 28 = 0x(x + 7) - 4(x + 7) = 0(x + 7)(x - 4) = 0

Therefore, x + 7 = 0 or x - 4 = 0.If x + 7 = 0, then x = -7, which is not a valid solution because the width of the rectangle cannot be negative.If x - 4 = 0, then x = 4. Therefore, the width of the rectangle is 4 meters. The length of the rectangle is x + 6 = 4 + 6 = 10 meters. So, the dimensions of the rectangle are 4 meters by 10 meters.

Therefore, the width of the rectangle is 4 meters, and the length of the rectangle is 10 meters. The dimensions of the rectangle are 4 meters by 10 meters.

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Answer:

17/25

Step-by-step explanation:

sorry if I'm wrong

lay them out on.a piece of paper and circle every multiple of 2

The probability that the committee has a majority of women is approximately 0.0044.

To calculate the probability that the committee has a majority of women, we need to determine the number of ways we can select a committee with a majority of women and divide it by the total number of possible committees.

First, let's calculate the total number of possible committees. Since there are 63 senators in total (19 women + 44 men), we have 63 options for the first committee member, 62 options for the second, and so on.

Therefore, there are 63*62*61*60*59 = 65,719,040 possible committees.

Next, let's calculate the number of ways we can select a committee with a majority of women. Since there are 19 women in the NY Senate, we have 19 options for the first committee member, 18 options for the second, and so on.

Therefore, there are 19*18*17*16*15 = 28,7280 ways to select a committee with a majority of women.

Finally, let's calculate the probability by dividing the number of committees with a majority of women by the total number of possible committees:

287280/65719040 ≈ 0.0044.

In conclusion, the probability that the committee has a majority of women is approximately 0.0044.

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\(~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 30000\\ P=\textit{original amount deposited}\dotfill & \$20000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years \end{cases} \\\\\\ 30000 = 20000[1+(0.09)(t)] \implies \cfrac{30000}{20000}=1+0.09t\implies \cfrac{3}{2}=1+0.09t \\\\\\ \cfrac{3}{2}-1=0.09t\implies \cfrac{1}{2}=0.09t\implies \cfrac{1}{2(0.09)}=t\implies 5.6\approx t\)

Answer:

not equivalent to meteorologists ratio

Step-by-step explanation:

meteorologists ratio is

rainy days : sunny days = 2 : 5

last months weather is

rainy days : sunny days

= 10 : 20 ( divide both parts by LCM of 10 )

= 1 : 2 ← not equivalent to 2 : 5

To determine which point could be on the line that is perpendicular to Line MN and passes through point K, we need to analyze the slopes of the two lines.

First, let's find the slope of Line MN using the given points (2, 3) and (-3, 2):

Slope of Line MN = (2 - 3) / (-3 - 2) = -1 / -5 = 1/5

Since the lines are perpendicular, the slope of the perpendicular line will be the negative reciprocal of the slope of Line MN. Therefore, the slope of the perpendicular line is -5/1 = -5.

Now let's check the given points to see which one satisfies the condition of having a slope of -5 when passing through point K (3, -3):

For point (0, -12):

Slope = (-12 - (-3)) / (0 - 3) = -9 / -3 = 3 ≠ -5

For point (2, 2):

Slope = (2 - (-3)) / (2 - 3) = 5 / -1 = -5 (Matches the slope of the perpendicular line)

For point (4, 8):

Slope = (8 - (-3)) / (4 - 3) = 11 / 1 = 11 ≠ -5

For point (5, 13):

Slope = (13 - (-3)) / (5 - 3) = 16 / 2 = 8 ≠ -5

Therefore, the point (2, 2) could be on the line that is perpendicular to Line MN and passes through point K.

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Based on the given parameters, we can calculate the maximum values of the construction site. The gross floor area is 9,800m², with 1,800m² allocated for lift lobby and corridor, and 200m² for lift machine room and water tank. The construction cost is $8,000/m².

The design and tendering period is 6 months, and the construction period is 16 months. The expected usage is rental at $200/m² per month, with a letting void of 2 months. The interest rate for short-term finance is 12% per annum, and the initial yield is 5%.

To calculate the maximum values of the construction site, we need to consider various factors. The gross floor area, floor area allocation, and construction cost determine the overall cost of construction. The design and tendering period and construction period provide information on the timeline of the project.

The expected usage and rental rate help estimate the potential income from renting out the space. The letting void represents the period when the space may remain unoccupied, impacting the potential income.

The interest rate for short-term finance is relevant for determining the financing costs associated with the construction project. The initial yield indicates the expected return on investment based on the rental income.

To obtain the maximum values, a comprehensive analysis considering all these factors is required. This analysis would involve calculating the total construction cost, estimating the potential rental income, factoring in the letting void and financing costs, and assessing the initial yield.

Without specific values or formulas provided, it is not possible to provide the exact maximum values based on the given parameters. A detailed financial analysis would be necessary to determine the precise figures.

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There are two types of classifications for triangles, Classification according to internal angles and Classification according to the length of its sides.

A geometrical shape with three vertices, angles and sides, whose sum of internal angles is 180° is considered as a triangle.

Classification of triangles :-

There are two ways to classify triangles,

1) Based on the Angle :-

a) Acute Angled Triangle :- A triangle that has all three angles less than 90° is an acute angle triangle.

b) Right-Angled Triangle :- A triangle that has one angle that measures exactly 90° is a right-angle triangle.

c) Oblique Angled Triangle :- A triangle that has one angle that measures more than 90° is an obtuse angle triangle.

2) Based on the Sides :-

a) Scalene Angled Triangle :- A triangle that has all three sides of different lengths is a scalene triangle.

b) Isosceles Angled Triangle :- A triangle that has two sides of the same length and the third side of a different length is an isosceles triangle.

c) Equilateral Angled triangle :- A triangle that has all three sides of the same length is an equilateral triangle.

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A parametrization for the line segment with endpoints (-4,5) and (-9,-10) is given by x = -4 - 5t and y = 5 - 15t, where 0 ≤ t ≤ 1.

To find a parametrization for the given line segment with endpoints (-4,5) and (-9,-10), we can use the parametric form of the equation of a straight line, which is given by x = x1 + t(x2 - x1) and y = y1 + t(y2 - y1), where (x1,y1) and (x2,y2) are the endpoints of the line segment and t is a parameter that varies from 0 to 1.

Taking (x1,y1) = (-4,5) and (x2,y2) = (-9,-10), we get the following parametric equations for the line segment:

x = -4 + t(-9 - (-4)) = -4 - 5t

y = 5 + t(-10 - 5) = 5 - 15t

The parameter t varies from 0 to 1, so as t ranges from 0 to 1, the point (x,y) traces out the line segment joining the points (-4,5) and (-9,-10).

Therefore, a parametrization for the line segment with endpoints (-4,5) and (-9,-10) is given by x = -4 - 5t and y = 5 - 15t, where 0 ≤ t ≤ 1.

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Answer:

Y= -2x +40

Step-by-step explanation:

Answer:

-82

Step-by-step explanation:

84/21=4

-25x4=-100

-3x-6=18

-100+18=-82

The required image of (−4,−4) after dilation by a scale factor of 5 centered at the origin is (-20, -20).

A point is transformed when it is moved from where it was originally to a new location. Translation, rotation, reflection, and dilation are examples of different transformations.

A dilation with a scale factor of k, centered at the origin, will take a point (x,y) in the pre-image to the point (kx,ky) in the image.

Given the required image of (−4,−4) after dilation by a scale factor of 5 centered at the origin.

For x-coordinate:

- 4 × 5 = -20

For y-coordinate:

- 4 × 5 = -20

Thus, the required coordinates are (-20, -20).

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The value of the expression "true && !false" can be determined by evaluating each part separately and then combining the results.

1. The "!" symbol represents the logical NOT operator, which negates the value of the following expression. In this case, "false" is negated to "true".

2. The "&&" symbol represents the logical AND operator, which returns true only if both operands are true. Since the first operand is "true" and the second operand is "true" (as a result of the negation), the overall expression evaluates to "true".

Therefore, the value of the expression "true && !false" is "true".

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Answer:

your questions is not complete yet please send full questions and write your question ⁉️ so I will solve your problem

Answer:

X = 1

Step-by-step explanation:

\(2x + 8 = 4x + 6 \\ collect \: the \: like \: terms \\ 8 - 6 = 4x - 2x \\ 2 = 2x \\ x = 1\)

Answer:

x = 1

Step-by-step explanation:

first subtract 6 from both sides

2x + 8 = 4x + 6

     -6           -6

2x + 2 = 4x

Now get the variable on to one side by subtracting 2x from both sides

2x + 2 = 4x

-2x         -2x

2 = 2x

Now divide both sides by two to get the value of x

2 (÷ 2) = 2x (÷ 2)

1 = x

x = 1

to check your work, plug in one for x

2x + 8 = 4x + 6

2(1) + 8 = 4(1) + 6

2 + 8 = 4 + 6

10 = 10

this statement is true which means the solution is true

Hope this helps!

A definite integral is said to be improper if one or both of the limits of integration are infinite, or if the integrand function has a vertical asymptote within the interval of integration.

In other words, an improper integral is one that cannot be evaluated using the usual techniques of integration, such as the fundamental theorem of calculus, because it involves infinite limits or a function that is not integrable over the interval.

For example, the definite integral of f(x) = 1/x from 1 to infinity is an improper integral because the upper limit of integration is infinity, which is not a finite number. Similarly, the definite integral of f(x) = ln(x) from 0 to 1 is an improper integral because the lower limit of integration is 0, and the function has a vertical asymptote at x=0.

To evaluate improper integrals, we use limit processes to determine whether the integral converges (has a finite value) or diverges (has an infinite value). If the integral converges, we can find its value by taking the limit of a related integral as one or both of the limits of integration approach infinity or zero.

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The curve joining the points P1, P2, P3, and so on is called the involute of a circle.

To construct the locus of the free end of the coir for unwinding through an angle of 360 degrees, as well as the normal and tangent at any point on the curve.

Here are the steps for construction:

1. Draw a line PQ that is tangent to the circle and is equal to the circumference of the circle. This line represents the coir being unwound.

2. Divide both the circle and the tangent line into the same number of equal parts. Label these divisions on the circle as 1, 2, 3, and so on. Similarly, label the divisions on the tangent line as 1', 2', 3', and so on.

3. Draw tangents at points 1, 2, 3, and so on on the circle. Mark the points where these tangents intersect the tangent line as P1, P2, P3, and so on.

The distance from each point Pi to the corresponding point i' on the tangent line should be the same as the distance from the center of the circle to the point i on the circle.

4. The curve joining the points P1, P2, P3, and so on is called the involute of a circle. This curve represents the locus of the free end of the coir as it unwinds.

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The process involves creating an initial circle that represents the drum, then using this to draw a horizontal line that's the same length as your first circle's circumference. Divide both into segments and draw lines (tangents) from one set of segments to the other. Points along these lines represent an unwound thread and create the involute when joined up. Tangents and normals can also be drawn onto this curve.

This question pertains to the mathematical concept of a curve locus, specifically the spiral curve produced by unwinding a coir from a drum. To draw this spiral curve (or 'involute'), start by sketching a circle representing the drum (with diameter 30mm). Next, calculate the circumference of this circle and draw a horizontal line of equivalent length. Then, divide this line and the circumference of your circle into the same number of equal sections. For each section in your circle, draw a line from the point of division to an equivalent point on your horizontal line. These lines are your tangents. Mark points on these lines which correspond to the distances covered by the unwound thread. Finally, join these points to create the involute of the circle.

For the part about drawing a normal and a tangent at any point on the curve: Pick a point on the curve. Remember that the tangent at a point on an involute is perpendicular to the line from the point to the centre of the original circle. A normal at any point on a curve is simply a line drawn perpendicular to the tangent at that point.

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Answer:

5.5, 5¼, 5 1/5 and 5.1.

Explanation:

To list the height from greatest to least, we convert each of them to a decimal.

Therefore, the weights are: 5.1, 5.2, 5.5 and 5.25

Arranging them from greatest to least gives:

5.5, 5.25, 5.2 and 5.1 which is equivalent to: 5.5, 5¼, 5 1/5 and 5.1.

Answer:

Explanation:

The equivalent if the expression:

is

This is:

There are no values of $b$ for which the base-$b$-representation of $2013$ ends in the digit $3$. For a number to end in the digit $3$ in base-$b$ representation, it must be congruent to $3$ modulo $b$.

We can rewrite $2013$ as $2 \cdot 10^3 + 0 \cdot 10^2 + 1 \cdot 10^1 + 3 \cdot 10^0$. Now, if $2013$ is congruent to $3$ modulo $b$, it means that $2 \cdot 10^3 + 0 \cdot 10^2 + 1 \cdot 10^1 + 3 \cdot 10^0$ is also congruent to $3$ modulo $b$.

Simplifying the expression, we have $2000 + 0 + 10 + 3$. Since the base-$b$-representation is formed by multiplying each digit by the corresponding power of $b$, we can rewrite the expression as $2 \cdot b^3 + 1 \cdot b^1 + 3 \cdot b^0$. We can now observe that the constant term $3 \cdot b^0$ will always be congruent to $3$ modulo $b$. However, the other terms $2 \cdot b^3$ and $1 \cdot b^1$ will not be congruent to $3$ modulo $b$ for any positive value of $b$. Therefore, the base-$b$-representation of $2013$ cannot end in the digit $3$ for any value of $b$.

Hence, there are no values of $b$ for which the base-$b$-representation of $2013$ ends in the digit $3$.

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Answer:

99 (I am not sure if this is correct)

Step-by-step explanation

75/4.75 so we can see how many miles per mile and then we would round the answer we got would be 16 and then muiltiply by 6.25 and round it to the nearest mile so i got 99. (unless I missed calculated)

.....um...i think u can't do this

Answer:

u should probably contact support or the creator of this site

Step-by-step explanation:

When slave starting a disabled vehicle, the term that serves an important safety consideration is c. The slaving vehicle engine must be running while connecting the slave cable

The dead car is started while the live vehicle's engine is running by inserting a slave cable into the receptacle on each vehicle.

Vehicles with manual transmissions rely heavily on the clutch slave cylinder. When the pedal is depressed, the clutch is disengaged and the transmission is shifted thanks to the slave and clutch master cylinders.

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The function g(x) = cot(x) = cos(x)/sin(x) has a domain of all real numbers except for the values where sin(x) = 0. The range of the function is also all real numbers, excluding 0.

The cotangent function, cot(x), is defined as the ratio of the cosine of x to the sine of x. To determine the domain, we need to identify the values of x where the denominator, sin(x), becomes zero. Since division by zero is undefined, these values must be excluded from the domain.

The sine function, sin(x), is equal to zero at x = nπ, where n is an integer. Therefore, the domain of cot(x) is all real numbers except for x = nπ, where n is an integer.

To find the range of cot(x), we need to consider the values of cos(x) and sin(x). The cosine function, cos(x), can take any value between -1 and 1, inclusive. The sine function, sin(x), can also take any value between -1 and 1, inclusive. Therefore, the ratio of cos(x)/sin(x), or cot(x), can take any real value except for zero.

The domain of the function g(x) = cot(x) is all real numbers except for x = nπ, where n is an integer. The range of the function is all real numbers except for zero.

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If we assume that each plant needs one seed to grow, then the number of seeds needed will be equal to the number of plants. The farmer will need 36,000 corn seeds to plant one acre of land.

To find the number of seeds the farmer needs, we first need to determine the area of one acre. One acre is equal to 43,560 square feet. The field shown in the question may have a different area, but we'll assume it's one acre for the purposes of this problem.

Now, we know that the farmer wants to plant 36,000 corn plants per acre. If we assume that each plant needs one seed to grow, then the number of seeds needed will be equal to the number of plants.

Therefore, the farmer will need 36,000 corn seeds to plant one acre of land.we know that the farmer wants to plant 36,000 corn plants per acre.

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Answer:

B

Step-by-step explanation:

to express degrees in radian measure , then

radian = degree × \(\frac{\pi }{180}\) , then

radian = 18° × \(\frac{\pi }{180}\) ( cancel 18 and 180 by 18 )

         = \(\frac{\pi }{10}\)