Answers
Answer:
Hola, veo que quieres la respuesta, así que todo lo que tienes que hacer es traducir esto, EHHHHH me encontraste y la respuesta es un
Explanation:
ps this is a real answer
Related Questions
A spherical balloon is being inflated and the radius of theballoon is increasing at a rate of 2 cm/s.(A) Express the radius (r) of the balloon as a function of thetime (t).(B) If V is the volume of the balloon as a function of theradius, find Vor and interpret it.
Answers
Answer:
A.) r = 2t
B.) V = 33.5t^3
Explanation:
Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s
A) Express the radius (r) of the balloon as a function of the time (t).
Since the rate = 2 cm/s that is,
Rate = radius/ time
Therefore,
2 = r/t
Make r the subject of formula
r = 2t
(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.
Let assume that the balloon is spherical. Volume of a sphere is;
V = 4/3πr^3
Substitute r = 2t into the formula
V = 4/3π(2t)^3
V = 4/3π × 8t^3
V = 32/3 × πt^3
V = 33.5t^3
1 A magnetic field of 0,5 T passes through an conducting loop of area 10 cm². The field lines are at 70° to the plane of the loop. 1.1 Calculate the magnetic flux linkage. (Hint: First, calculate the angle between the field and the normal to the plane.) 1.2 Calculate the average emf that will be induced across the ends of the coil if it is removed from the field in 0,2 s. (Hint: It is removed from the field so final is zero.) 1.3 Calculate the induced current if the loop is connected to a circuit with a resistance of 2 Q. 2 A solenoid with 400 turns is rotated so that the magnetic flux linked x 10-4 Wb in 0,1 s. 3 with each turn changes from 5 x 10-4 Wb to Calculate the average emf across the ends of the solenoid. A wire loop with an area of 0,02 m² is positioned in a magnetic field in which the flux density changes from 0,1 T to 0,8 T in 0,4 s. The magnetic field is at an angle of 25° to the normal to the plane of the loop. 3.1 Calculate the induced emf. 3.2 Calculate the induced current if the loop is connected to a circuit with a resistance of 5 Q. F i C q 1 3
Answers
Magnetic flux linkage = magnetic field * area * cos(angle)
Plugging in the given values, we get:
Magnetic flux linkage = 0.5 T * 10 cm^2 * cos(20°) = 0.087 Wb
1.2 The average emf induced across the ends of the coil is given by:
Average emf = change in magnetic flux linkage / time
Since the coil is removed from the field, the final magnetic flux linkage is zero. Therefore, the change in magnetic flux linkage is equal to the initial magnetic flux linkage, which we calculated in part 1.1. Plugging in the given values, we get:
Average emf = 0.087 Wb / 0.2 s = 0.435 V
1.3 The induced current can be found using Ohm's law:
I = V / R
Plugging in the given values, we get:
I = 0.435 V / 2 Ω = 0.218 A
2. The average emf induced across the ends of the solenoid is given by:
Average emf = change in magnetic flux linkage / time
Since the magnetic flux linked changes from 5 x 10^-4 Wb to 15 x 10^-4 Wb, the change in magnetic flux linkage is:
Change in magnetic flux linkage = 15 x 10^-4 Wb - 5 x 10^-4 Wb = 10 x 10^-4 Wb
Plugging in the given values, we get:
Average emf = 10 x 10^-4 Wb / 0.1 s = 0.1 V
Therefore, the average emf across the ends of the solenoid is 0.1 V.
3.1 The induced emf can be found using Faraday's law:
Induced emf = -N * d(flux) / dt
Since the flux density changes from 0.1 T to 0.8 T, the change in flux density is:
Change in flux density = 0.8 T - 0.1 T = 0.7 T
How much voltage is required to run 0.054 A of current through a 152
resistor? Use AV = IR.
A. 3.6 x 10-3V
B. 2.8 x 102V
C. 1.2 V
D. 0.81 V
Answers
V = I • R
V = (0.054 A) • (152 ohms)
V = 8.208 volts
None of the listed choices is correct.
What is the KE of a 13kg boulder moving at 78.3m/s?
Answers
Answer:
39850.785 J
Explanation:
0.5 x m x v^2
0.5x13x78.3^2
Answer:
KE =
\( \frac{1}{2} m {v}^{2} \\ \)
Explanation:
\(ke = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} \times 13 \times {78 . 3}^{2} \\ ke = 39850.785j \\ \)
2. Who was the first person to"measure gravity?" (Hint: By "measuring gravity, we mean
"measuring the acceleration due to gravity.)
Answers
Answer:
The first person to "measure gravity" is sir Issac newton
Sketch a distance time graph for marcus
Answers
I will explain to Marcus that to sketch a distance-time graph, we need to plot the distance on the y-axis and time on the x-axis, then connect the plotted points with a line.
How can we sketch a distance time graph?Sketching a distance-time graph is a common way to visually represent the motion of an object over a period of time. To create a distance-time graph, we need to first determine the distance traveled by the object at various points in time. This can be done by measuring the distance traveled by the object over a given time interval or by using the object's speed and time to calculate the distance.
Once we have this information, we can plot the distance traveled on the y-axis and time on the x-axis, with each point representing the distance traveled at a specific time. So,, we connect the plotted points with a line, which gives us a visual representation of how the distance traveled by the object changes over time.
Also, by analyzing the slope and shape of the line, we can gain insights into the object's speed, direction, and acceleration, and use this information to better understand its motion.
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what is the symbol for specific latent heat of vaporization
Answers
Answer: L
Explanation: L is the specific latent heat for a particular substance (kJ kg−1 or in BTU lb−1), either Lf for fusion, or Lv for vaporization.
Draw lines to match the wave terms with the correct description.
Answers
Amplitude - Highest line
Trough - Lowest point
Crest - Distance between top and rest position
Oscillate - Back and forth motion
Amplitude - Distance between top of crest and rest position
Frequency - Number of waves per second
Wavelength - Distance between two crest or troughs
Compression - Where particles are close together
Rarefaction - Where particles are farthest apart
Incident wave - The wave that moves towards an object
Reflected wave - The wave that moves off an object
Superpose - When waves add or cancel out
Reflect - When a wave bounces off an object
What are the terms that describe waves?A wave is a disturbance that travels through a medium, carrying energy from one place to another without the permanent transfer of matter.
The terms that are used to describe a wave are;
Amplitude
Wavelength
Frequency
Period
Velocity
Crest
Trough
Polarization
Interference
Diffraction.
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0.8kg marble is shot out of the spring gun that had a k=625N/m. If uncompressed length of the spring is 0.75m and when compressed it measures 0.4m. The whole system has 85J of mechanical energy. What is the velocity of the marble as it leaves the gun? After 6s how far has the marble travelled?
Answers
Given data:
* The mass of the marble is m = 0.8 kg.
* The spring constant is k = 625 N/m.
* The uncompressed length of the spring is L= 0.75 m.
* The compressed length of spring is L' = 0.4 m.
* The net mechanical energy of the system is E = 85 J.
* The value of time given is t = 6 s.
Solution:
(a). The change in the length of spring during the compression is,
\(\begin{gathered} x=L-L^{\prime} \\ x=0.75-0.4 \\ x=0.35\text{ m} \end{gathered}\)The potential energy of the marble as it leaves the gun is,
\(U=\frac{1}{2}kx^2\)Substituting the known values,
\(\begin{gathered} U=\frac{1}{2}\times625\times0.35^2 \\ U=38.28\text{ J} \end{gathered}\)The kinetic energy of the marble as it leaves the gun in terms of the total mechanical energy is,
\(\begin{gathered} K=E-U \\ K=85-38.28 \\ K=46.72\text{ J} \end{gathered}\)The kinetic energy of the marble in terms of mass and velocity of the marble is,
\(\begin{gathered} K=\frac{1}{2}mv^2 \\ 46.72=\frac{1}{2}\times0.8\times v^2 \\ 46.72=0.4\times v^2 \\ v^2=\frac{46.72}{0.4} \end{gathered}\)By simplifying,
\(\begin{gathered} v^2=116.8 \\ v=10.8\text{ m/s} \end{gathered}\)Thus, the velocity of the marble as it leaves the gun is 10.8 meters per second or approximately 11 meters per second.
(b). The force acting on the marble at the time of leave is,
\(\begin{gathered} F=kx \\ F=625\times0.35 \\ F=218.75\text{ N} \end{gathered}\)According to Newton's second law, the force acting on the marble in terms of the acceleration of the marble is,
\(\begin{gathered} F=ma \\ 218.75=0.8\times a \\ a=\frac{218.75}{0.8} \\ a=273.44ms^{-2} \end{gathered}\)By the kinematics equation, the distance traveled by the marble in 6 seconds is,
\(S=ut+\frac{1}{2}at^2\)where u is the initial velocity of the marble (when the marble is at rest in the compressed spring position),
The value of the initial velocity of the marble is u = 0 m/s.
Substituting the known values,
\(\begin{gathered} S=0+\frac{1}{2}\times273.44\times6^2 \\ S=4921.92\text{ m} \end{gathered}\)Thus, the distance traveled by the marble in 6 s is 4921.92 meters or approximately 4922 meters.
What are bones basically made of? (Choose the best answer?) *
Vitamins and minerals.
Non-organic materials.
Collagen and minerals.
Collagen and protein.
choose one
Answers
Answer:
collagen and protein
Explanation:
Made mostly of collagen, bone is living, growing tissue collagen is a protein that provides a soft framework and calcium photosphate site is a material that adds strength to hardness the framework.
Answer:
bones are made of collagen and protein
on what factors, current sensitivity voltage sensitivity of
a galvanometer depend?
Answers
\(\boxed{\underline{\bf \: ANSWER}}\)
The current sensitivity of a galvanometer depends upon the following factors :-
number of turns.coil area.restoring force per unit twist.magnetic field.___________
Hope it helps.
RainbowSalt2222
How are velocity, wavelength, and frequency related
Answers
Answer:
The wave velocity and the wavelength are related to the wave's frequency and period by vw=λT or vw=fλ. The time for one complete wave cycle is the period T. The number of waves per unit time is the frequency ƒ. The wave frequency and the period are inversely related to one another.
Explanation:
Newton's discovery concerning how fast an object will change speed is the:
1st Law
3rd Law
2nd Law
Universal Gravitation
Answers
Answer:
I think its the second law..
Explanation:
Answer:
its the second law.
hope this helps! :)
A nearby supernova could have all of the following effects EXCEPT Select one: A. Radioactive supernova ejecta causes radiation sickness. B. Gamma-radiation makes cancer rates rise. C. Significant depletion of the ozone layer. D. A massive electromagnetic pulse fries electronics on the surface. E. Cosmic ray particles cause satellites to malfunction
Answers
A nearby supernova could have all of the following effects except significant depletion of the ozone layer. A nearby supernova is a powerful and energetic event that releases a tremendous amount of energy and radiation into space.
While it can have several significant effects on Earth and its surroundings, one effect it is unlikely to have is a significant depletion of the ozone layer. The ozone layer is primarily affected by human-induced activities such as the release of ozone-depleting substances like chlorofluorocarbons (CFCs) and not by cosmic events like supernovae. However, the other effects mentioned in options A, B, D, and E can occur as a result of a nearby supernova. Radioactive supernova ejecta can emit radiation that can cause radiation sickness in living organisms, and gamma radiation from the explosion can increase cancer rates due to its ionizing nature. Additionally, a massive electromagnetic pulse (EMP) generated by a supernova can disrupt and damage electronic devices on the Earth's surface. Furthermore, cosmic ray particles from a supernova can interfere with satellite systems and cause malfunctions.
In conclusion, while a nearby supernova can have various effects on our environment and technology, including radiation sickness, increased cancer rates, electromagnetic pulse damage, and satellite malfunctions, it is not expected to cause significant depletion of the ozone layer.
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in an electrochemical cell if k=0.05 and q=0.10, what can you conclude about e cell and e°cell?
Answers
Answer:
Both E cell and E°cell are negative.Have a Nice Best Day : ) Please Give Me Brainliest
the planet earth orbits the sun within a period of one year. in this problem, you may assume the radius
Answers
The correct answer is 29883.3m/s
The pace at w.hich an object's position changes in relation to a frame of reference is known as its velocity, which is a time-dependent quantity. The speed and direction of an object's motion are its velocity. The rate at which an object's velocity changes in relation to time is defined as its acceleration.
The following kinematic equation can be used to connect velocity and acceleration:
v_1=v_0+at
Where v_1 denotes the ultimate velocity, v_0 denotes the starting velocity, a denotes the acceleration, and t is the passing of time.
Calculate the length of the Earth's orbit around the Sun to get started. For this issue, a circle rather than an ellipse can be used to represent the Earth's orbit.
Circumference = C=πD=2πR
=2π(1.5×10km)
=9.424π×10^8
Do a dimensional analysis to convert the speed of the Earth around the Sun from miles per hour to metres per second:
s_earth= 9.424π×10^8/1year × (1year×100m×1day×1hour×1min)/(1km×365days×24hours×3600seconds)
=29883.3m/s
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The fact that objects fall to earth at the same speed is called
Answers
Answer:
The Equivalence Principle of Gravity
Explanation:
The fact that objects fall to earth at the same speed is called the Equivalence Principle of Gravity.
What is the Equivalence Principle of Gravity?According to the Equivalence Principle of Gravity, all things fall at the same rate when there is little to no air resistance. The value of the acceleration caused by gravity is demonstrated by the force of gravity equation to be a constant that is independent of the mass of the item.
According to Einstein's equivalence principle, it is unnecessary to distinguish between gravitational and inertial forces because they are comparable in nature.
The inertia force acts in the opposite direction of an object's accelerating force.As a result, the Einstein equivalence principle can be expressed as "the effects of gravity are exactly identical to the effects of acceleration."Therefore, the Equivalence Principle of Gravity states that all objects descend to Earth at the same rate.
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DUE IN 15 MIN!
Which law would you use to compare CO and CO2? Explain. Without doing any calculations, determine which of the two compounds has the
highest percent by mass of oxygen in the compound
Answers
CO2 has the highest percent by mass of oxygen in the compound.
What is Compound?
A compound is a substance composed of two or more elements chemically bonded together in a fixed ratio. The elements in a compound lose their individual properties and form a new substance with unique properties. Compounds can be formed through chemical reactions and can be broken down into their constituent elements through chemical means.
To compare CO and CO2, we would use the law of multiple proportions. This law states that when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in the ratio of small whole numbers. In other words, the ratio of the masses of the two elements in each compound will be a small whole number ratio.
For example, in CO, the ratio of the mass of oxygen to carbon is 16:12, or 4:3. In CO2, the ratio of the mass of oxygen to carbon is 32:12, or 8:3. These ratios are not small whole numbers, which suggests that the two compounds are not related by simple ratios, and therefore cannot be explained by the law of multiple proportions.
However, we can still compare the percentage by mass of oxygen in each compound. The formula for the percent by mass of oxygen in a compound is:
% mass of O = (mass of O in compound / molar mass of compound) x 100%
For CO, the molar mass is 28 g/mol, and the mass of O is 16 g/mol, so the percent by mass of oxygen is:
% mass of O = (16 g/mol / 28 g/mol) x 100% = 57.14%
For CO2, the molar mass is 44 g/mol, and the mass of O is 32 g/mol, so the percent by mass of oxygen is:
% mass of O = (32 g/mol / 44 g/mol) x 100% = 72.73%
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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
Answers
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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a child is pulling an empty cart attached by a rope that is parallel to the ground. the cart is moving with constant velocity, and its mass is 1.5 kg. suppose a mass of 7.5 kg is added to the sled, and its velocity stays the same. by what factor does the tension in the rope change?
Answers
The tension in the rope is changed by 75 N
Tension is the force that is transmitted through a body which can be a rope or a wire which is pulled from both sides. Whenever there is a rope being pulled from one side then according to Newton's third law, equal force is exerted by the rope on the other side. This transmission of forces is known as tension in that rope.
Given,
Mass 1 = m₁ = 1.5 kg
Mass 2 = m₂ = 7.5 kg + 1.5 kg = 9 kg
g = 10 m/s² = acceleration due to gravity
Tension in the rope when mass 1.5 kg is attached to the string,
T₁ = m₁g = 1.5 * 10 = 15 kg
Tension in the rope when mass 1.5 kg is attached to the string,
T₂ = m₂g = 9*10 = 90 kg
The change that tension undergoes
T₂ - T₁ = 90 - 15 = 75
Therefore, the factor by which the tension in the rope changes is 75 N
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Steve does 80 J of work to a rope threaded through a pulley and attached to a crate of anvils. The tension of the rope is 10 N and the crate rises 4 m while Steve pulls. What is the efficiency of the pulley? [Hint: how much work was done on the crate?]
a) (A) 0.07 or 7 %
b) (B) 0.2 or 20 %
c) (C) 0.5 or 50 %
d) (D) 1 or 100 %
Answers
Answer:
The Answer is (B)
Explanation:
The diagonals of a non-isosceles trapezoid divide the midline (median) into three segments, whose lengths are 8 cm, 3 cm, and 8 cm. How long are the parallel sides? From this information, is it possible to infer anything about the distance that separates the parallel sides? Explain.
Answers
The parallel sides measure 35 cm in length. We are unable to draw any conclusions about the separation between the parallel sides based on the information provided.
Let AB and CD be the parallel sides of a non-isosceles trapezoid ABCD (See picture). The diagonals AC and BD should meet at P and Q, respectively. Let E represent the midpoint of the PQ segment, which is also the trapezoid's midline.
As stated in the problem statement, let's now assign the three midline segments the labels EF = 8 cm, FG = 3 cm, and GH = 8 cm.
We are aware that a trapezoid's diagonals separate one another proportionally. This is,
\(\frac{BQ}{QC} = \frac{AP}{PD}\)
Call this the common ratio, r.
We know that AP ≠ PD and BQ ≠ QC since the trapezoid is non-isosceles. Hence, r ≠ 1.
In addition, triangles ABQ and CDQ are similar, as are triangles ABP and CDP. This is due to the fact that they both share angles B and D, respectively, and that their corresponding sides are proportional as a result of the proportional division of the trapezoid by the diagonals.
Triangles are identical to one another, hence we can write:
\(\frac{PD}{QC} =\frac{AB}{CD}\) and \(\frac{AQ}{BQ}=\frac{AB}{CD}\)
When we multiply these equations, we obtain:
\((\frac{AP}{PD}) *(\frac{BQ}{QC} )=(\frac{AB}{CD} )^2\)
Substituting r for \((\frac{AP}{PD})\) and \((\frac{BQ}{QC} )\), we get:
\(r^2 = (\frac{AB}{CD} )^2\)
Taking the square root of both sides and simplifying, we get:
\(r = \frac{AB}{CD}\) or \(r = -\frac{AB}{CD}\)
Since r ≠ 1, we can eliminate the possibility of \(r = \frac{AB}{CD}\). Therefore, \(r = -\frac{AB}{CD}\).
This demonstrates that the trapezoid's diagonals cross each other externally.
Let's calculate the length of the parallel sides using the information provided.
From the similarity of triangles ABP and CDP, we have:
\(\frac{AP}{CD} = \frac{BP}{DP}\)
Substituting AP = 8 cm, CD = 8 cm + 3 cm + 8 cm = 19 cm, and BP = AB - AP, we get:
\(\frac{8}{19} = \frac{(AB - 8)}{DP}\)____________(1)
The resemblance between triangles ABQ and CDQ also yields the following:
\(\frac{BQ}{CD} = \frac{AQ}{CQ}\)
Substituting BQ = 8 cm, CD = 19 cm, and AQ = AB - BQ, we get:
\(\frac{8}{19} = \frac{(AB - 8)}{CQ}\)__________________(2)
Adding the equations (1) and (2), we get:
\(\frac{16}{19} = \frac{AB}{(DP + CQ)}\)
Substituting DP + CQ = PQ = 3 cm + 8 cm + 8 cm = 19 cm, we get:
AB = 16 cm
Therefore, the length of the parallel sides is AB + CD = 16 cm + 19 cm = 35 cm.
From the given information, we cannot infer anything about the distance that separates the parallel sides.
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what is the name of the phobias of space?
Answers
Answer:
Astrophobia
Explanation:
heop it help
if your weight is 600 Newton on the earth how far should you go from the centre of the earth so that it will be 300 Newton
Answers
Given :
Our weight is 600 Newton on the earth.
To Find :
How far should you go from the center of the earth so that it will be 300 Newton.
Solution :
Acceleration due to gravity at depth d is given by :
\(g' = g( 1 - \dfrac{d}{R_e})\)
At earth surface, mg = 600 N ...1)
At depth d, mg' = 300 N ...2)
Dividing 1) and 2), we get :
\(\dfrac{g}{g'} = \dfrac{600}{300}\\\\\dfrac{g}{g'} = 2\\\\g = 2g'\\\\g = 2\times g\times ( 1 - \dfrac{d}{R_e} )\\\\1 - \dfrac{d}{R_e} = \dfrac{1}{2} \\\\d = \dfrac{R_e}{2}\)
Therefore, we should go in the depth of distance half the radius of earth.
State Schrodinger equation.
Answers
Hi!Schrodinger equation is written as HΨ = EΨ, where h is said to be a Hamiltonian operator.
A force acts on a moving rubber ball.
How many of the following changes could happen to the ball because of the force?
• a change in direction
• a change in shape
• a change in mass
• a change in speed
A 1
B 2
C 3
D 4
Answers
Answer:
B
Explanation:
because it would change the direction and speed
Question 14 (2 points)
Which statement best describes why the universe could be considered an isolated system? (2 points)
Оа
All matter that enters the universe remains contained within the universe.
Ob
Energy and matter are created in the universe; when new energy is created, old energy exits.
In the universe, all energy and matter are contained; no energy or matter enters or exits.
Ос
Od
The universe is a contained system where no energy exits.
Answers
Answer:
I believe it is actually C
Explanation:
Matter and energy cannot be created or destroyed so A is incorrect
Since energy cannot be created, B is incorrect
while C and D both sound correct, D does not mention entering while C does so I believe C is correct. When i submit this answer into my quiz, i will add if i am right.
In the universe, all energy and matter are contained; no energy or matter enters or exits - the statement best describes why the universe could be considered an isolated system.
What is isolated system?A thermodynamic system is said to be isolated if it cannot exchange either mass or energy with the outside world. In contrast to a closed system, energy can't move across isolated systems. Energy can move freely within and outside of closed systems; they are only closed to matter.
As both energy and matter can not exit from a universe, we can consider universe as a isolated system.
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Light waves can be easily blocked but ______ waves pass through all substances? ( fill in the blank)
Answers
The force of electrostatic repulsion between two small positively charged objects, A and B, is 3.6 x 10⁻⁵ N when AB = 0.12m. What is the force of repulsion if AB is increased to 0.24 m
Answers
Given data:
* The electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=3.6\times10^{-5}\text{ N}\)* The distance between the charged bodies in the initial state is,
\(d=0.12\text{ m}\)* The distance between the charged bodies in the final state is,
\(\begin{gathered} d^{\prime}=0.24\text{ m} \\ d=2\times0.12 \\ d^{\prime}=2d \end{gathered}\)Solution:
According to Coulomb's law, the electrostatic force of repulsion between the charged bodies in the initial state is,
\(F=\frac{kq_1q_2}{d^2}\)where k is the electrostatic force constant, q_1 is the charge on the first charged body and q_2 is the charge on the second charged body,
The electrostatic force of repulsion between the charged bodies in the final state is,
\(\begin{gathered} F^{\prime}=\frac{kq_1q_2}{(2d)^2} \\ F^{\prime}=\frac{kq_1q_2}{4d^2} \\ F^{\prime}=\frac{1}{4}\times\frac{kq_1q_2}{d^2} \\ F^{\prime}=\frac{F}{4} \end{gathered}\)Substituting the known values,
\(\begin{gathered} F^{\prime}=\frac{3.6\times10^{-5}}{4} \\ F^{\prime}=0.9\times10^{-5}\text{ N} \end{gathered}\)Thus, the electrostatic force of repulsion between the charged bodies in the final state is,
\(\text{0}.9\times10^{-5}\text{ N}\)Can barium metal be prepared from the electrolysis of its aqueous salt solution?
Answers
Yes, barium metal can be prepared from the electrolysis of its aqueous salt solution.
The process involves passing an electric current through a solution of barium chloride. The positively charged cations are attracted to the cathode and the negatively charged anions are attracted to the anode.
At the cathode, barium cations react with the electrons to form barium metal. At the anode, chlorine gas is produced from the anions. The barium metal produced is then collected at the cathode.
This process is known as electrolytic reduction and is used to produce a variety of metals, including barium. The electrolysis of barium salt solution is an effective and efficient method for producing barium metal.
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