PLEASE HELP ME I BEGG YOU!!!!!!!!

Delilah is correct; it is

Here, we want to check who was right

Mathematically, we can dilate a figure by reduction or enlargement by the use of a specific scale factor

When the scale factor is less than 1, it is a reduction

However, if the scale factor is greater than 1, it is an enlargement

The original point is (x,y)

From the image coordinates given, we see that the scale factor is 6/5 which is greater than 1

Thus, the dilation is an enlargement and Delilah was right

The constant of proportionality in the equation 3y = 2x is 2/3.

Two or more expressions with an Equal sign is called as Equation.

if y is directly proportional to x, this is expressed as:

y ∝ x

y = kx .................... 1

k = y/x

Given the expression 3y = 2x

Divide both sides by 3

3y/3 = 2x/3

y = 2/3 x ................ 2

Compare equation 1 and 2 to find "k"

kx = 2/3 x

k = 2/3

Hence,  the constant of proportionality in the equation 3y = 2x is 2/3.

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The midpoint has coordinates (19,19) as per the midpoint formula.

The statement is false.

The statement is false. The midpoint of the segment joining two points is determined by taking the average of their x-coordinates and the average of their y-coordinates. In this case, the two given points are (0,0) and (38,38).

To find the x-coordinate of the midpoint, we take the average of the x-coordinates of the two points:

(x1 + x2) / 2

= (0 + 38) / 2

= 38 / 2

= 19

Therefore, the x-coordinate of the midpoint is 19, which matches the statement. However, to determine if the statement is true or false, we also need to check the y-coordinate.

To find the y-coordinate of the midpoint, we take the average of the y-coordinates of the two points:

(y1 + y2) / 2

= (0 + 38) / 2

= 38 / 2

= 19

The y-coordinate of the midpoint is also 19. Therefore, the coordinates of the midpoint are (19,19), not 19 as stated in the statement. Since the midpoint has coordinates (19,19), the statement is false.

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Answer:

The answer to this question is $14,916

Step-by-step explanation:

18,469 - 3,553 = 14916

As he already has money for the car.

A bar model is shown in the linked picture.

5.2 x 10 ^5

Edit: I tried putting a 5 over the 10 in spaces but it didn’t work lol

Answer:

5.2x x 10^5

Step-by-step explanation:

Answer: Top left (-v + 8 <= -2.5)

Step-by-step explanation:

-12 <= -2.5 - 8

so
-12 <= -10.5

The equation of the function is y =  x - \(1\frac{1}{3}\)

The first point = (-6, \(-7\frac{1}{3}\))

The second point = (-4, \(-5\frac{1}{3}\))

Convert the mixed fraction to the simple fraction

The first point = (-6, -22/3)

The second point = (-4, -16/3)

The slope of the line is the change in y coordinates with respect to the change in x coordinates of the line

The slope of the line = \(\frac{y_2-y_1}{x_2-x_1}\)

= (-16/3 - (-22/3) / (-4 - (-6)

= 2 / 2

= 1

The point slope form is

\(y-y_1=m(x-x_1)\)

y - (-22/3) = 1(x - (-6))

y + 22/3 = x + 6

y = x+ 6 - 22/3

y = x+ -4/3

y = x - 4/3

Convert the simple fraction to mixed fraction

y =  x - \(1\frac{1}{3}\)

Hence, the equation of the function is y =  x - \(1\frac{1}{3}\)

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-6x+35 = -6x+35 has the same thing on each side: , so this has infinite solutions. Option c is correct.

An equation will have infinite solutions if both sides of the equal sign are the exact same thing, for instance . (You can test this with any value of x and find that they all work!)

So to find the equations that have infinite solutions, we need to see which have the same exact sides.

(Choice A)

-6x+35 = -6x-35 have the different thing on each side: , so this has no solution.

(Choice B)

6x+35  = -6x-35 does not have the same thing on each side, so it doesn’t have infinite solutions (it has 1).

(Choice C)

-6x+35 = -6x+35 has the same thing on each side: , so this has infinite solutions.

(Choice D)

6x+35=-6x+35 And finally,  has the different thing on each side: , so it has one solution.

Hence , -6x+35 = -6x+35 has the same thing on each side: , so this has infinite solutions.

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Answer:

50?

Step-by-step explanation:

Answer:

The age of son is 50.THANK YOU.

If the function x(t) = cos(2π100t + π/3) is sampled at the minimum sampling rate to avoid aliasing for 10 seconds, 2000 points are generated.

The function x(t) = cos(2π100t + π/3) is sampled at the minimum sampling rate to avoid aliasing for 10 seconds.

To avoid aliasing, we need to use the Nyquist-Shannon Sampling Theorem, which states that the minimum sampling rate should be twice the highest frequency in the signal. In this case, the highest frequency is 100 Hz.

Step 1: Calculate the minimum sampling rate.
Minimum sampling rate = 2 * highest frequency = 2 * 100 Hz = 200 Hz.

Step 2: Calculate the total number of points generated in 10 seconds.
A number of points = sampling rate * time duration = 200 Hz * 10 s = 2000 points.

So, 2000 points are generated when the function x(t) = cos(2π100t + π/3) is sampled at the minimum sampling rate to avoid aliasing for 10 seconds.

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The requried distance between points P(1,6) and Q(5,8) in simplest radical form is 2√5.

We can use the distance formula to find the distance between the two points:

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

where (x₁, y₁) = (1, 6) and (x₂, y₂) = (5, 8).

Substituting the values, we get:

d = √[(5 - 1)² + (8 - 6)²]

= √[4² + 2²]

= √(16 + 4)

= √20

= 2√5

Therefore, the distance between points P(1,6) and Q(5,8) in simplest radical form is 2√5.

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Here's a LaTeX code that represents the question and provides both a concise answer and a more detailed explanation:

```latex

\documentclass{article}

\begin{document}

\textbf{Question:} Show that a particle moving with constant motion in the Cartesian plane with position $(x(t), y(t))$ will move along the line $y(x) = mx + c$.

\textbf{Answer (Concise):} A particle with constant motion in the Cartesian plane will move along a straight line represented by the equation $y(x) = mx + c$, where $m$ is the slope and $c$ is the y-intercept.

\textbf{Answer (Detailed):}

Let's consider a particle moving with constant motion in the Cartesian plane, where its position is given by the functions $x(t)$ and $y(t)$. We want to show that this particle will move along the line represented by the equation $y(x) = mx + c$, where $m$ is the slope and $c$ is the y-intercept.

Since the particle has constant motion, its velocity $\mathbf{v}$ is constant. The velocity vector can be written as $\mathbf{v} = \left(\frac{dx}{dt}, \frac{dy}{dt}\right)$. Since the motion is constant, the derivative of $x(t)$ and $y(t)$ with respect to $t$ will be constant.

Let's assume that the particle's initial position is $(x_0, y_0)$. We can write the position functions as $x(t) = x_0 + v_xt$ and $y(t) = y_0 + v_yt$, where $v_x$ and $v_y$ are the constant velocities in the x and y directions, respectively.

Now, let's solve for $t$ in terms of $x$ using the equation for $x(t)$. We have $t = \frac{x - x_0}{v_x}$. Substituting this into the equation for $y(t)$, we get $y(x) = y_0 + v_y \left(\frac{x - x_0}{v_x}\right)$. Simplifying this equation gives us $y(x) = mx + c$, where $m = \frac{v_y}{v_x}$ and $c = y_0 - \frac{v_y x_0}{v_x}$.

Therefore, we have shown that a particle with constant motion in the Cartesian plane will move along the line represented by the equation $y(x) = mx + c$.

\end{document}

```

This LaTeX code generates a document with the question, a concise answer, and a more detailed explanation. It explains the concept of a particle with constant motion and how its position can be represented using functions in the Cartesian plane. The code also derives the equation of the line that the particle will move along and provides the values for slope ($m$) and y-intercept ($c$).

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Y in represents the following in this linear regression Y = α₀+α₁X+α₂X₂+ε: C. dependent variable.

In Mathematics and Geometry, a regression line is a statistical line that best describes the behavior of a data set. This ultimately implies that, a regression line simply refers to a line which best fits a set of data.

In Mathematics and Geometry, the general functional form of a linear regression can be modeled by this mathematical equation;

Y = α₀+α₁X+α₂X₂+ε

Where:

In conclusion, Y represent the dependent variable or response variable in a linear regression.

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The antiderivative of 7ex is 7ex, and the antiderivative of 6 sec2(x) is 6 tan(x). Thus, the most general antiderivative is F(x) = 7ex + 6 tan(x) + C, where C represents the constant of integration.

To find the antiderivative of the given function f(x) = 7ex 6 sec2(x), we integrate each term separately. The antiderivative of 7ex is simply 7ex, as the exponential function ex is its own antiderivative.

Next, we consider the antiderivative of 6 sec2(x). The derivative of the tangent function tan(x) is sec2(x), so the antiderivative of sec2(x) is tan(x). However, there is a coefficient of 6 in front of sec2(x), so the antiderivative becomes 6 tan(x).

Combining these results, we have F(x) = 7ex + 6 tan(x) as the antiderivative of the original function f(x) = 7ex 6 sec2(x). The "+ C" at the end represents the constant of integration, as any constant added to the antiderivative remains undetermined. Therefore, the most general antiderivative of f(x) is F(x) = 7ex + 6 tan(x) + C, where C is a constant.

To verify this result, we can differentiate F(x) and confirm that it indeed yields the original function f(x). Taking the derivative of F(x) with respect to x will give us back 7ex 6 sec2(x), thus confirming the correctness of the antiderivative.

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Let * be the binary operation on Z defined by a * b = a + 2b. To prove whether the set E of even integers is closed under the binary operation *, we need to show that for any two even integers a and b, their sum a + 2b is also an even integer.

Let a and b be two even integers, which means they can be written as a = 2m and b = 2n for some integers m and n. Then, the result of the binary operation * is:

a * b = a + 2b = 2m + 4n = 2(m + 2n)

Since m and 2n are both integers, their sum (m + 2n) is also an integer. Therefore, a * b can be written as 2 times an integer, which means it is an even integer.

Thus, we have shown that for any two even integers a and b, their binary operation * result a * b is also an even integer. Therefore, the set E of even integers is closed under the binary operation *.

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Answer:

Mark brainly then I will answer..

The distributive law is the law to apply to have the following equivalence:

(¬p∨r)∧(¬q∨r)≡(¬p∧¬q)∨r.

Hence, the correct option is (D) Distributive law.

What is Distributive Law?

The distributive property is the most commonly used property of the number system.

Distributive law is the one which explains how two operations work when performed together on a set of numbers. This law tells us how to multiply an addition of two or more numbers.

Here the two operations are addition and multiplication. The distributive law can be applied to any two operations as long as one is distributive over the other.

This means that the distributive law holds for the arithmetic operations of addition and multiplication over any set.

For example, the distributive law of multiplication over addition is expressed as a(b+c)=ab+ac,

where a, b, and c are numbers.

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Answer:

Yes, the rule is that x-coordinates cannot repeat, but it does not matter with y-coordinates

Step-by-step explanation:

If you graph this, it will pass the vertical line test. Please mark the brainliest if this helped!

-3/2

slope = rise/run

We can use the two points to calculate rise (y value change) and run (x value change)

slope = (-6)/4 = -3/2

If 7 is less than a number, x, it means that x is greater than 7. The symbol for representing greater than is >

Thus, the inequality that matches the given situation is

x >7

Option c is correct

Answer:

x = - 3/2

(the dash by the 3/2 is to show that it is negative, and is part of the answer)

Answer:

x= -3/2

Step-by-step explanation:

Answer:

66 cm

Step-by-step explanation:

Answer:

∠ A ≈ 77.8°

Step-by-step explanation:

Using the Sine rule in Δ ABC

\(\frac{BC}{sinA}\) = \(\frac{AB}{sinC}\)

\(\frac{37}{sinA}\) = \(\frac{29}{sin50}\) ( cross- multiply )

29 × sinA = 37 × sin50° ( divide both sides by 29 )

sinA = \(\frac{37sin50}{29}\) , then

A = \(sin^{-1}\) ( \(\frac{37sin50}{29}\) ) ≈ 77.8° ( to 1 dec. place )

By using the method of reduction of order as in differential equation to find a second linearly independent solution of the: Equation x2y" + xy' – 9y = 0 (x > 0); yı(x) = x3 has general solution is y(x) = c1x^3 + c2x^(-2),

Equation  4y" – 4y' + y = 0; yı(x) = ex/2 general solution is y(x) = c1exp(x/2) + c2*exp(-x/2),

Equation x2y" – x(x + 2)y' + (x + 2)y = 0 (x > 0); yı(x) = x has general solution  y2(x) = (C3x^(3/2) + C4)e^(-x).

Equation (x + 1)y" - (x + 2)y' + y = 0 (x > -1); yı(x) = ex has the general solution y(x) = c1ex + [c2 - ln(|2x + 1|)/2]ex.

Using the method of reduction of order, assume a second solution of the form y2(x) = u(x)y1(x). Then we have:

y'1(x)u(x) + y1(x)u'(x) = 0

u'(x) = -y'1(x)u(x)/y1(x)

Integrating both sides:

ln|u(x)| = -ln|y1(x)| + C

u(x) = K/x^3

Plugging this into the differential equation:

x^2y'' + xy' - 9y = 0

x^2[u''(x)y1(x) + 2u'(x)y1'(x) + u(x)y1''(x)] + x[u'(x)y1(x) + u(x)y1'(x)] - 9u(x)y1(x) = 0

Simplifying and dividing by x^2y1(x):

u''(x) - 6/x^2 u(x) = 0

Equation r(r-1) - 6 = 0, which has roots r = 3 and r = -2. Therefore, the general solution is y(x) = c1x^3 + c2x^(-2).

Using the method of reduction of order, assume a second solution of the form y2(x) = u(x)y1(x). Then we have:

y'1(x)u(x) + y1(x)u'(x) = 0

u'(x) = -y'1(x)u(x)/y1(x)

Integrating both sides:

ln|u(x)| = -2ln|y1(x)| + C

u(x) = Kexp(-x/2)

Plugging this into the differential equation:

4y'' - 4y' + y = 0

4[u''(x)y1(x) + 2u'(x)y1'(x) + u(x)y1''(x)] - 4[u'(x)y1(x) + u(x)y1'(x)] + u(x)y1(x) = 0

Simplifying and dividing by 4y1(x):

u''(x) - u(x)/4 = 0

equation r^2 - 1/4 = 0, has roots r = 1/2 and r = -1/2. Therefore, the general solution is y(x) = c1exp(x/2) + c2*exp(-x/2).

Let y2(x) = v(x)y1(x), where v(x) is a function to be determined.

Then, y'2(x) = v'(x)y1(x) + v(x)y'1(x) and y"2(x) = v"(x)y1(x) + 2v'(x)y'1(x) + v(x)y"1(x).

Substituting y1(x) and y2(x) into the given differential equation, we get:

x^2(v"(x)y1(x) + 2v'(x)y'1(x) + v(x)y"1(x)) - x(x+2)(v'(x)y1(x) + v(x)y'1(x)) + (x+2)v(x)y1(x) = 0

Simplifying and dividing by x^2y1(x), we obtain:

v"(x) + (2/x - (x+2)/x^2)v'(x) + ((x+2)/x^2 - 1/x^2)v(x) = 0

Let u(x) = v'(x). Then, the above equation can be written as a first-order linear differential equation:

u'(x) + (2/x - (x+2)/x^2)u(x) + ((x+2)/x^2 - 1/x^2)v(x) = 0

Using an integrating factor of exp(∫[(2/x - (x+2)/x^2)dx]), we get:

u(x)/x^2 = C1 + C2∫exp(-2lnx)exp((x+2)/x)dx

u(x)/x^2 = C1 + C2/x^2e^(x+2)

v(x) = C3x^(1/2)e^(-x) + C4x^(-3/2)e^(-x)

Therefore, the second linearly independent solution is:

y2(x) = (C3x^(3/2) + C4)e^(-x)

41. (x + 1)y" - (x + 2)y' + y = 0, one solution y1(x) = ex.

We assume that the second solution has the form y2(x) = v(x)ex.

We can then find y2'(x) and y2''(x) as follows:

y2'(x) = v'(x)ex + v(x)ex

y2''(x) = v''(x)ex + 2v'(x)ex + v(x)ex

We can substitute y1(x) and y2(x) into the differential equation and simplify using the above expressions for y2'(x) and y2''(x):

(x + 1)[v''(x)ex + 2v'(x)ex + v(x)ex] - (x + 2)[v'(x)ex + v(x)ex] + v(x)ex = 0

Simplifying and dividing by ex, we get:

xv''(x) + (2x + 1)v'(x) = 0

This is a first-order linear differential equation, which we can solve using separation of variables:

v'(x) = -1/(2x + 1) dv/dx

Integrating both sides

v(x) = C1 - ln(|2x + 1|)/2

where C1 is a constant of integration.

Therefore, the second linearly independent solution is:

y2(x) = v(x)ex = [C1 - ln(|2x + 1|)/2]ex

So, the general solution is:

y(x) = c1ex + [c2 - ln(|2x + 1|)/2]ex

where c1 and c2 are constants of integration.

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____The given question is incomplete, the complete question is given below:

In each of Problems 38 through 42, a differential equation and one solution yı are given. Use the method of reduction of or- der as in Problem 37 to find a second linearly independent solution y2. 38. x2y" + xy' – 9y = 0 (x > 0); yı(x) = x3 39. 4y" – 4y' + y = 0; yı(x) = ex/2 40. x2y" – x(x + 2)y' + (x + 2)y = 0 (x > 0); yı(x) = x 41. (x + 1)y" - (x + 2)y' + y = 0 (x > -1); yı(x) = ex

The standard deviation of the monthly amount charged is 346.41

Step 1: Identify the values of a and b, where [a , b] is the interval over which the continuous uniform distribution is defined.

Since it takes between 300 and 1500 minutes to be seated at the restaurant, we have:

a = 300

b = 1500

Step 2: Calculate the variance using the formula Var(x) = \(\frac{(b-a)^{2} }{12}\)

Using the formula for the variance and the values identified in step 1

(a = 300 , b = 1500), we have:

Var(x) = \(\frac{(b-a)^{2} }{12}\)

         = \(\frac{(1500 - 300)^{2} }{12}\)

         = 1440000/12

         = 120,000

the variance is 120,000

Step 3: Calculate the standard deviation by taking the square root of the variance. σ = \(\sqrt{Var(x)}\)

The standard deviation is the square root of the result from step 2 (variance = 120,000)

σ = \(\sqrt{Var(x)}\)

σ = \(\sqrt{120000}\)

   = 346.41

The standard deviation of the monthly amount charged is 346.41

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Raven can travel 5.71 miles or less under her limit.

Inequality is defined as the relation which makes a non-equal comparison between two given functions. If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality.

Let x b the number of miles Raven travels, we can write an expression relating the amount he spends. So there:

3.00 + 0.50= 3.50

Consider that total cost per mile be less than equal to the amount the Raven can spend:

3.50x ≤ 20

We can determine x;

x ≤ 5.71

Therefore, Raven can travel 5.71 or less under her limit.

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Answer:

Anica has 2 boxes completely filled in & 3 stuffed animals left.

Step-by-step explanation:

No. of stuffed animals Anica has = 13

No. of animals in each box = 5

No. of boxes used total = ?

No. of boxes used in total = 13/5 = 2.6 boxes. (take it as 2)

Let's take the number of boxes used as 2. So, now Anica has put in 10 of her animals in ( 5 × 2 = 10). She has 3 animals remaining ( 13 - 10 = 3 ).

Answer:

2 n 3r

Step-by-step explanation:

Answer:

I think the answer is 24 minutes!

Step-by-step explanation:

I hope this helps!

Answer:6+89

Step-by-step explanation:439+3947+v=90