PLEASE HELP ME I AM BEGGING YOU :)) 15 POINTS
A student investigated the energy being transferred using the

joulemeter (J).

The reading on the joulemeter was always 20 J lower than the

calculated value.

Name the type of error in the investigation

Answer:

What shape is it? the formula is different depending on the shaping

Explanation:

Square P=4s

Rectangle P=2L+2W

Triangle a+b+c

Circle     P=C=2πr=πd

and so on

Answer:

Approximately \(69\; {\rm N}\) at approximately \(126^{\circ}\).

Explanation:

Assume that both angles in the question are relative to the positive \(x\)-axis (towards the positive horizontal direction.)

Horizontal component (\(x\)-component) of the two forces would be:

Note that the \(x\)-component of the \(90\; {\rm N}\) force is negative since this components points away from the positive \(x\!\)-direction.

Hence, the net force in the \(x\)-component would be:

\((50\; {\rm N}) \, \cos(30^{\circ}) + (90\; {\rm N}) \, \cos(160^{\circ}) \approx (-41.3) \; {\rm N}\).

(Again, this component is negative since it points away from the positive \(x\)-axis.)

Similarly, the vertical component (\(y\)-component) of the two forces would be:

Hence, the net force in the \(y\)-component would be:

\((50\; {\rm N}) \, \sin(30^{\circ}) + (90\; {\rm N}) \, \sin(160^{\circ}) \approx 55.8\; {\rm N}\).

Refer to the diagram attached. The resultant net force is the vector sum of the components. Apply the Pythagorean Theorem to find this net force:

\(\begin{aligned}(\text{net force}) &= \sqrt{(\text{$x$-component})^{2} + (\text{$y$-component})^{2}} \\ &\approx \sqrt{(-41.3)^{2} + (55.8)^{2})}\; {\rm N} \\ &\approx 69\; {\rm N}\end{aligned}\).

Find the angle of this net force relative to the positive \(x\)-axis using the inverse cosine function \(\arccos\):

\(\begin{aligned}\arccos\left(\frac{(\text{$y$-component})}{(\text{net force})}\right) &\approx \arccos\left(\frac{55.8\; {\rm N}}{69\; {\rm N}}\right) \\ &\approx 126^{\circ}\end{aligned}\).

(The units might need to be converted into degrees.)

The skater does indeed reach the same height on either side of the track With friction turned on.

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The car is going the same speed as the truck and the truck and car are at the same height can not be true. Therefore, option (B) is correct.

Mechanical energy can be defined as the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a body because of its position or motion.

The total mechanical energy can be considered conserved when the forces doing work are conservative in nature. The energy changes between different kinds of potential energy and kinetic energy but the total energy of the system remain constant.

Kinetic energy and the potential energy of the car and the semi-truck will depend on the masses of the objects. The semi-truck must have a greater mass than the car. Therefore, the car and the semi-truck must have different values of speed and height if they have the same total mechanical energy.

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The molecules in the solid door expands on hot days causing the difficulty in closure while the molecules contract on cooler days, causing the door to close just fine.

One of the effects of heat is expansion of solids. Once a substance is heated, its molecules spread out. In the case of a solid door, when the molecules in the door are heated on a hot day, they expand, causing difficulty when closing the door.

However, on a cold day, the molecules of the door contract and the door closes just fine without any difficulty.

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Answer:

Va = 64 / 25 = 2.56 m/sec

Vb = 64 / 22.5 = 2.84 m/s

At t = 45

Sa = 2.56 m/s * 45 s = 115 m

Sb = 2.84 m/s * 42.5 s = 121 m

The first option given is the correct description

Answer:

1. when in motion(moving) it is Kinetic energy

2. it is kinetic when moving and potential when at rest

3. by constantly kicking or moving the ball

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6.5 × 12.3

We have the final answer as

Hope this helps you

lan can decrease the magnetic force on the washers by increasing the distance between the magnet and the pile of metal washers.

A material or object that creates a magnetic field is called a magnet.

The most noteworthy characteristic of a magnet, a force that pulls on other ferromagnetic elements like iron, steel, nickel, cobalt, etc., as well as the ability to attract or repel other magnets, is caused by this invisible magnetic field.

The strength of the magnetic force produced by a magnet increases when the distance between the magnet and an object experiencing the magnetic force is reduced.

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Answer:

(a) The total weight of the climber is equal to her mass multiplied by the acceleration due to gravity. Therefore, W = mg = 62 kg x 10 m/s^2 = 620 N.

(b) The two conditions needed for equilibrium are that the net force acting on the climber is zero and the net torque acting on the climber is zero.

(c)(i) The moment about her feet due to her weight is equal to the weight of the climber multiplied by the distance between her feet and the cliff. Therefore, M = W x d = 620 N x 0.9 m = 558 Nm.

(ii) To determine the tension in the rope, we need to resolve the forces acting on the climber in the horizontal and vertical directions. In the horizontal direction, the tension in the rope is balanced by the force of friction between the climber's feet and the cliff. Therefore, T = F.

In the vertical direction, the climber's weight is balanced by the normal force of the cliff and the tension in the rope. Therefore, N + Tcos(60) = W.

Since the climber is in equilibrium, the net torque acting on her must be zero. Therefore, the torque due to the tension in the rope must be equal and opposite to the torque due to the climber's weight. Therefore, Tsin(60) x 1.2 = M.

Substituting the values we have, we get:

N + Tcos(60) = W

Tsin(60) x 1.2 = M

Solving for T, we get:

N = W - Tcos(60) = 620 N - T(0.5)

Substituting this into the second equation, we get:

Tsin(60) x 1.2 = M

Tsin(60) = M / 1.2 = 558 Nm / 1.2 m = 465 N

Substituting this value of T into the first equation, we get:

N = 620 N - T(0.5) = 620 N - 465 N(0.5) = 388 N

Therefore, the tension in the rope is 465 N and the normal force of the cliff on the climber is 388N

The total power dissipated by the circuit is 36W. We can solve this circuit using a combination of Ohm's Law and Kirchhoff's Laws.

(a) To find the effective resistance of the circuit, we can first simplify the circuit by combining the two parallel resistors:

1/Req = 1/2Ω + 1/3Ω

1/Req = 5/6Ω

Req = 6/5Ω

Now, we can combine the two series resistors with Req: Req_tot = 6/5Ω + 4Ω = 14/5Ω

Therefore, the effective resistance of the circuit is 14/5Ω, or 2.8Ω.

(b) Using Ohm's Law, we can find the current through each resistor if we know the voltage across it. Since the 3Ω resistor has a voltage difference of 6V across it, the current through it is:

I = V/R = 6V/3Ω = 2A

Using Kirchhoff's Current Law (KCL), we know that the current through the 2Ω resistor is the same as the current through the 3Ω resistor. Therefore, the current through the 2Ω resistor is also 2A.

(c) Using Kirchhoff's Voltage Law (KVL), we know that the sum of the voltage drops across each resistor must be equal to the battery voltage. Therefore, we can calculate the battery voltage by adding the voltage drops across each resistor: V_battery = V_2Ω + V_3Ω + V_4Ω

We know the current through each resistor, so we can use Ohm's Law to calculate the voltage drop across each resistor:

V_2Ω = IR = (2A)(2Ω) = 4V

V_3Ω = IR = (2A)(3Ω) = 6V

V_4Ω = IR = (2A)(4Ω) = 8V

Substituting these values, we get:

V_battery = 4V + 6V + 8V = 18V

Therefore, the battery voltage is 18V.

(d) To calculate the total power dissipated by the circuit, we can use the formula:

P = IV

We know the current through each resistor, so we can use Ohm's Law to calculate the voltage drop across each resistor, and then use the formula above to calculate the power dissipated by each resistor:

P_2Ω = (2A)(4V) = 8W

P_3Ω = (2A)(6V) = 12W

P_4Ω = (2A)(8V) = 16W

The total power dissipated by the circuit is the sum of the power dissipated by each resistor:

P_tot = P_2Ω + P_3Ω + P_4Ω = 8W + 12W + 16W = 36W

Therefore, the total power dissipated by the circuit is 36W.

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Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

\(x = x_{o}+v_{o,x} \cdot t\)

\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}\)

Where:

\(x_{o}\), \(y_{o}\) - Initial horizontal and vertical position of the projectile, measured in meters.

\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical speed of the projectile, measured in meters per second.

\(t\) - Time, measured in seconds.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(x\), \(y\) - Current horizontal and vertical position of the projectile, measured in meters.

Given that \(x_{o} = 0\,m\), \(y_{o} = 80\,m\), \(v_{o,x} = 360\,\frac{m}{s}\), \(v_{o,y} = 0\,\frac{m}{s}\) and \(g = -9.807\,\frac{m}{s^{2}}\), the kinematic equations are, respectively:

\(x = 360\cdot t\)

\(y = 80-4.094\cdot t^{2}\)

(a) If \(y = 0\,m\), the time taken for the projectile to reach the water is:

\(80 - 4.094\cdot t^{2} = 0\)

\(t = \sqrt{\frac{80}{4.094} }\,s\)

\(t \approx 4.420\,s\)

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If \(t \approx 4.420\,s\), the horizontal scope of the projectile is:

\(x = 360\cdot (4.420)\)

\(x = 1591.2\,m\)

The horizontal scope of the projectile is 1591.2 meters.

(c) If \(t = 2\,s\), the height that remains to descend is:

\(y = 80-4.094\cdot (2)^{2}\)

\(y = 63.624\,m\)

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Consider a pipe 45.0 cm long that is open at both ends, and use v=344 m/s for the speed of sound.

1. First, convert the length of the pipe from centimeters to meters: 45.0 cm = 0.45 m.
2. The fundamental frequency for an open pipe can be found using the formula: f1 = v / (2 * L), where f1 is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.
3. Plug the values into the formula: f1 = 344 m/s / (2 * 0.45 m).
4. Calculate the fundamental frequency: f1 = 344 m/s / 0.9 m = 382.22 Hz.

So, for a 45.0 cm long pipe open at both ends with a speed of sound at 344 m/s, the fundamental frequency is 382.22 Hz.

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Answer:

comets

Explanation:

Comets have a tail unlike any other answer choice and it has a core of ice and dust. Many think comets do not orbit the sun, but they do. They orbit in a eliptical orbit, so they take a long time to orbit back to the sun.

Answer:

D. Electrons mover from one to another

Explanation:

Static electricity occurs when electrons are transferred from one object to another.

Answer:

1 = The answers are 6, 60, 600, or 6

Explanation:

Answer:

It is going through a phase change when it is flat.

Explanation:

During the horizontal line segments, there is no change in temperature, so kinetic energy remains constant. However, all the energy that is absorbed or released is related to changes in potential energy.

In a system using a single movable pulley, the mechanical advantage (MA) is equal to 2. This means that the load being lifted will experience a gain in force of two times the input force applied.

A movable pulley is one that is attached to the load being lifted and is free to move along with it.

When a force is applied to lift the load, the movable pulley changes its position, effectively reducing the force required to lift the load.

The key concept behind the mechanical advantage is that the load is distributed between the input force and the pulley.

In a single movable pulley system, the load is divided between the input force and the pulley itself.

The input force only needs to overcome half of the load's weight since the pulley contributes an equal amount of force in the opposite direction. This results in an MA of 2, indicating a doubling of force.

For example, if a load weighs 100 pounds, an input force of 50 pounds would be sufficient to lift it.

The movable pulley helps distribute the load's weight, reducing the force required by half.

Overall, using a single movable pulley provides a mechanical advantage of 2, allowing the load to be lifted with less force compared to lifting it directly.

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Part A: The radius of curvature of the lens surface is approximately 3.17 m. Part B: The focal length of the lens is approximately 1.59 m.

Part A:

To find the radius of curvature of the lens surface, use the formula for the radius of the nth bright ring in a planoconvex lens:

r = √(n × λ × f),

where r = radius of the nth bright ring, λ = wavelength of light, and f = focal length of the lens.

In this case, n = 42 (since the last bright ring is observed at the edge), λ = 580 nm (converted to meters, so λ = 580 × 10⁻⁹ m).

Rearranging the formula, solve for f:

f = r² / (n × λ).

Plugging in the values:

f = (0.021 m²) / (42 × 580 × 10⁻⁹ m).

Calculating this expression gives:

f = 3.17 m.

Therefore, the radius of curvature of the lens surface is approximately 3.17 m.

Part B:

The focal length of the lens can be determined using the formula:

f = R / 2,

where R = radius of curvature.

Plugging in the value for the radius of curvature obtained in Part A:

f = 3.17 m / 2.

Calculating this expression gives:

f = 1.59 m.

Therefore, the focal length of the lens is approximately 1.59 m.

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The mobility of the light source depends on the interaction between the magnetic and electric forces.

Cathode ray refers to the electron beam that moves from the negatively charged cathode to the positively charged anode at the other end of the vacuum tube.

J. J. Thomson demonstrated that the identical beam deflections produced tubes with cathodes composed of varied materials and containing a range of gases prior to evacuation.

This discovery is significant because the interaction of the magnetic and electric forces determines the mobility of the light source.

Therefore, the interaction of the magnetic and electric forces determines how mobile the light source is.

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Answer:

I hope 2 amperes of current passes

Explanation:

Thermal conductivity is a measure that refers to the rate at which heat is transferred by conduction through a unit cross-section area of a material.

or in simpler terms how well a substance conducts heat.

its formula is seen in the attachment. hope this helps.

Answer:

T₂ = 1937.68 N

Explanation:

First, we will calculate the weight of the object:

\(W = mg = (478\ kg)(9.81\ m/s^2)\\W = 4689.18\ N\)

Now, we will calculate the resultant tension in the ropes. Since the ropes are perpendicular. Therefore,

\(T = \sqrt{T_1^2+T_2^2}\\\)

where,

T = Resultant Tension

T₁ = Tension in rope 1

T₂ = Tension in rope 2

According to the given condition tension in the first rope is 2.2 times the tension in the second rope:

T₁ = 2.2 T₂

Therefore

\(T = \sqrt{(2.2T_2)^2 + T_2^2}\\\\T = 2.42T_2\)

Now, the weight of the object must be equal to the resultant tension for equilibrium:

\(T = W\\2.42T_2 = 4689.18\ N\\\\\)

T₂ = 1937.68 N

Answer:

Option A:  F/4

Explanation:

Centripetal force, \(F = \frac{mv^{2} }{r}\)

Where v = speed

r = radius

Since Kinetic Energy, \(E_{k} = 0.5 mv^{2}\)

Writing centripetal force in terms of kinetic energy, \(F = \frac{2 E_k}{r}\)

If the initial radius of the circle, r₁ =r

The doubled radius, r₂ = 2r

If the initial kinetic energy, \(KE_1 = E_{k}\)

The halved kinetic energy,  \(KE_2 = 0.5E_{k}\)

Therefore, the new Centripetal force becomes:

\(F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}\)

The kinetic energy for photons can not be determined while the kinetic energies for electrons, neutrons, and α particles are  3762 eV, 130 eV, and 8.08 eV respectively.

(a) For photons, the de Broglie wavelength is not related to their kinetic energy, as they do not have mass. Therefore, we cannot determine the kinetic energy of a photon using its de Broglie wavelength.

(b) To find the kinetic energy of electrons with a de Broglie wavelength of 0.14 nm, we use the formula:

E = h^2 / (2 * m_e * λ^2)
where E is the kinetic energy, h is the Planck's constant (6.626 x 10^-34 Js), m_e is the electron's mass (9.11 x 10^-31 kg), and λ is the de Broglie wavelength (0.14 nm or 1.4 x 10^-10 m).

E ≈ 6.026 x 10^-19 J or 3762 eV

(c) For neutrons with a de Broglie wavelength of 0.14 nm, we use the same formula but replace m_e with the neutron's mass (1.675 x 10^-27 kg).

E ≈ 2.088 x 10^-22 J or 130 eV

(d) For α particles (helium nuclei) with a de Broglie wavelength of 0.14 nm, we again use the same formula but replace m_e with the α particle's mass (6.646 x 10^-27 kg).

E ≈ 1.293 x 10^-21 J or 8.08 eV

In summary, the kinetic energies are:
(a) Photons: Cannot be determined
(b) Electrons: 3762 eV
(c) Neutrons: 130 eV
(d) α particles: 8.08 eV

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Oscillation is a fundamental factor in sound generation for synthesizers, as they use electronic circuits to generate and control oscillations of various frequencies and waveforms to create different sounds. So, this statement is false

In a synthesizer, an electronic instrument, oscillation is an essential factor in sound generation. Oscillators in a synthesizer generate periodic waveforms, which are then processed and shaped to create various sounds. These oscillations form the basis of the electronic sound produced by the instrument.

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Could someone help me? A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s . After 3s in the air, the canon hits its target. How far away was the canon from its target?

A high jumper leaves the ground with an initial velocity of 10 m/s rightward at an angle of 15 degrees . What is the high jumper's initial horizontal velocity?

Answer:

4b: comets

5a: supercluster

5b: they just changed 4b's solar system for milky way. I think it is still comets. if not, then just say black holes.

Answer:

25.0 less force

Explanation:

The ampacity of feeders over 600 volts supplying transformers and utilization equipment must be at least the sum of the combined nameplate ratings of the transformers and 125 percent of the potential designed load of the utilization equipment.

Electrical regulations and standards provide guidelines to ensure the safe and efficient operation of electrical systems. In the case of feeders over 600 volts supplying transformers and utilization equipment, the ampacity requirement is specified to prevent overloading and potential damage to the electrical system.

The ampacity refers to the current-carrying capacity of the feeders, and it is crucial to determine the appropriate ampacity to safely handle the combined load of the transformers and utilization equipment.

To calculate the required ampacity, you need to consider two factors: Combined nameplate ratings of the transformers and  125 percent of the potential designed load of the utilization equipment.

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Complete question is:

According to electrical regulations and standards, what is the requirement for the ampacity of feeders over 600 volts supplying transformers and utilization equipment?