please help!!!!!!!!!!

Answers

Answer 1

Solution

For this case we can find the maximum with the vertex of the quadratic function and we have:

\(V_x=-\frac{b}{2a}=-\frac{-17000}{2(-100)}=85\)

And the correspongind value of y would be:

\(R(85)=17000(85)-100(85)^2=722500\)

so then the answer would be:

TechSmith has a maximum revenue whener the company produces and sells 85 million downloads of recording software in a year

The maximum revenue that TechSmith attains in a year from producing and selling recording software is:

722500 dollars

Please Help!!!!!!!!!!

Related Questions


How many different samples of size 3 can be selected from a population of size 11?
A) 11
B) 33
C) 165
D) 3,960

Answers

Answer: C) 165

Step-by-step explanation:

\(\displaystyle\\C_{11}^3=\\\\\frac{11!}{(11-3)!3!} =\\\\\\\frac{8!*9*10*11}{8!*1*2*3} =\\\\\\\frac{9*10*11}{2*3} =\\\\3*5*11=\\\\15*11=\\\\165\)

A school librarian ordered new books for the library. Of the new books ordered 1/3 are science 2/5 are biography and the rest of the books are fiction. What fraction of the books ordered are fiction?

Answers

Answer: 4/15

Step-by-step explanation:

1/3= 5/15

2/5= 6/15

5+6=11 So, 11/15

15-11=4

Meaning that there are 4/15 of the books are fiction

Solve
2x = -16

a.-8
b.8
c.1/8
d.-1/8

Answers

Answer:

A

Step-by-step explanation:

The correct answer will be A

Have a great day

PLEASE HELP ME WITH THIS

PLEASE HELP ME WITH THIS

Answers

Answer:

7=0

Step-by-step explanation:

a part, share, or number considered in comparative relation to a whole.

2x+8y=12. 3x-8y=11 solve

Answers

Answer:

x = 23/5 and y = 7/20

Step-by-step explanation:

2x + 8y = 12 and 3x - 8y = 11 are two given equations

Now,

Step 1:

2x + 8y = 12 ...(1)

3x - 8y = 11 ...(2)

Step 2:

From equation (2) we get the value of x

i.e.,

3x - 8y = 11

3x = 8y + 11

x = 8y + 11/3

Step 3:

Now,

Put the value of x = 8y + 11/3 in equation (1) we get,

i.e.,

2x + 8y = 12

2(8y + 11/3) + 8y = 12

16y + 22/3 + 8y = 12

16y + 22 + 8y(3)/3 = 12

16y + 22 + 24y/3 = 12

16y + 24y + 22 = 12 * 3

40y = 36 - 22

40y = 14

y = 14/40

y = 7/20

Step 4:

Now,

Substitute the value of y = 7/20 in equation (2) we get,

i.e.,

3x - 8y = 11

3x - 8(7/20) = 11

3x - 56/20 = 11

3x - 14/5 = 11

3x = 11 + 14/5

3x = 11 * 5 + 14/5

3x = 55 + 14/5

3x = 69/5

x = 69/3 * 5

x = 23/5

PLS LOOK AT PIC AND HELP ME!! I’m being timed pls help :((

PLS LOOK AT PIC AND HELP ME!! Im being timed pls help :((

Answers

A the y intercept will shift 7 up

The weights of four similar packs of tomatoes are listed below.

Pack A: 2.456 pounds
Pack B: 2.457 pounds
Pack C: 2.454 pounds
Pack D: 2.459 pounds

Malcolm rounds the weights to the nearest hundredth pound. Which weight does
not round to 2.46 pounds?

A 2.456 pounds
B 2.457 pounds
C 2.454 pounds
D 2.459 pounds

Answers

Answer:

The weight that does not round to 2.46 pounds is C 2.454 pounds.

Step-by-step explanation:

Based on the given information, the weights of the four similar packs of tomatoes are as follows:

Pack A: 2.456 poundsPack B: 2.457 poundsPack C: 2.454 poundsPack D: 2.459 pounds

Malcolm rounds the weights to the nearest hundredth pound. To round to the nearest hundredth pound, we look at the digit in the hundredths place. If it is 5 or greater, we round up the digit in the tenths place. If it is less than 5, we leave the digit in the tenths place as it is. Therefore, we can obtain the rounded weights as follows:

Pack A: 2.46 poundsPack B: 2.46 poundsPack C: 2.45 poundsPack D: 2.46 pounds

From the above rounded weights, we see that Pack C rounds to 2.45 pounds and does not round to 2.46 pounds. Therefore, the weight that does not round to 2.46 pounds is C 2.454 pounds.

will give brainliest to correct answer

will give brainliest to correct answer

Answers

The sequence that represents the arithmetic sequence will be {-6, 1, 8, 15, 22,...}. Then the correct option is A.

What is an arithmetic sequence?

Arithmetic succession or arithmetic sequential is a numerical series in which the difference between subsequent terms is uniform.

Let's check all the options, then we have

A.  {-6, 1, 8, 15, 22,...}, then the common difference is given as,

d = 1 - (-6) = 8 - 1 =

d = 7 =  7

B.  {64, 32, 16, 8, 4,...}, then the common difference is given as,

d = 32 - 64 = 16 - 32
d = -32 ≠ - 16

C.  {1, 2, 4, 8, 16,...}, then the common difference is given as,

d = 1 - 2 = 2 - 4

d = - 1 ≠ - 2

D.  {1, 3, 6, 10, 15,...}, then the common difference is given as,

d = 1 - 3 = 3 - 6

d = - 2 ≠ - 3

The sequence that represents the arithmetic sequence will be {-6, 1, 8, 15, 22,...}. Then the correct option is A.

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Test the claim that the mean GPA of night students is larger than 2.2 at the .10 significance level.

Answers

This question is incomplete, the complete question is;

Test the claim that the mean GPA of night students is larger than 2.2 at the .10 significance level.

The test is based on a sample of 55 people, the sample mean GPA was 2.23 with a standard deviation of 0.06

Answer:

P-value is less than the significance level.

We reject null hypothesis.

Therefore, there is enough evidence to conclude that the mean GPA of night students is larger than 2.2

Step-by-step explanation:

Given the data in the question;

Claim : The mean GPA of night student is larger than 2.2

μ = 2.2

sample size n = 55

sample mean x' = 2.23

standard deviation s = 0.06

Hypothesis

Null hypothesis            H₀ : μ ≤ 2.2

Alternative hypothesis H₁ : μ > 2.2

Right-tailed Test.

Significance Level ∝ = 0.10

so critical value \(t_{(0.10, df=54)\) = 1.297

Test Statistic

T\(_{cal\) = (x'-μ) / (s/√n)

we substitute

T\(_{cal\) = (2.23 - 2.2 ) / (0.06 / √55)

= 0.03 / 0.00809

T\(_{cal\)  = 3.71

T\(_{cal\)  is greater than critical value, so it falls in the rejection region;

p-value = P( t > 3.71 ) = 0.000245

P-value is less than the significance level.

We reject null hypothesis.

Therefore, there is enough evidence to conclude that the mean GPA of night students is larger than 2.2

Help please!
S = 180m
How many strides would a runner take during a 1-hour run (60 min)

Help please!S = 180mHow many strides would a runner take during a 1-hour run (60 min)

Answers

The number of strides the runner will make during 1 hour run will be =

10,800.

How to calculate the total number of strides made by the runner in a hour?

To calculate the distance or number of strides made by the runner in an

hour, the graph given above is considered as follows;

The y-axis which represents the number of strides is plotted against the x-axis which is the number of hours.

From the graph

20 minutes= 3600 strides

60 minutes = X strides

make X the subject of formula;

x= 3600×60/20

= 216000/20

= 10,800

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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFraction radians and 2Pi radians. The student uses the steps below to find cos Theta. Which of the following explains whether the student is correct? The student made an error in step 3 because a is positive in Quadrant IV; therefore, cosine theta = StartFraction a Over StartRoot a squared + b squared EndRoot EndFraction = StartFraction a StartRoot a squared + b squared EndRoot Over a squared + b squared EndFraction. The student made an error in step 3 because cosine theta = StartFraction negative b Over StartRoot a squared + b squared EndRoot EndFraction = Negative StartFraction b StartRoot a squared + b squared EndRoot Over a squared + b squared EndFraction. The student made an error in step 2 because r is negative in Quadrant IV; therefore, r = Negative StartRoot a squared + b squared EndRoot. The student made an error in step 2 because using the Pythagorean theorem gives r = plus-or-minus StartRoot (a squared) minus (b squared) EndRoot = StartRoot a squared minus b squared EndRoot.

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction

Answers

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

\(cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}\)

Step-by-step explanation:

Given

\(P\ (a,b)\)

\(r = \± \sqrt{(a)^2 + (b)^2}\)

\(cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}\)

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

\(r = \sqrt{(a)^2 + (b)^2}\)

Since a belongs to the x axis and b belongs to the y axis;

\(cos\theta\) is calculated as thus

\(cos\theta = \frac{a}{r}\)

Substitute \(r = \sqrt{(a)^2 + (b)^2}\)

\(cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}\)

\(cos\theta = \frac{a}{\sqrt{a^2 + b^2}}\)

Rationalize the denominator

\(cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}\)

\(cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}\)

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

Answer:

a on e2020 :)

Step-by-step explanation:

- 2.5(4w - 4) = -6 Check:​

Answers

Answer:

Step-by-step explanation:

- 2.5(4w - 4) = -6

-2.5×4w+2.5×4=-6

-10w+10=-6

-10w=-6-10

-10w=-16

Cancel the -sign from both side soqe get

10w=16

W=16/10

W=1.6

So the value of w is 1.6

What is the relationship between climate change and the regularity of droughts​

Answers

Climate change is closely related to the frequency and severity of droughts. As global temperatures increase due to climate change, evaporation rates increase, which results in dry soils, reduced snowpack, and reduced water availability for agriculture and other uses. This, in turn, leads to more frequent and more severe droughts, as well as longer dry spells between precipitation events. Additionally, climate change can alter precipitation patterns, causing some regions to experience increased drought while others experience more frequent flooding. Therefore, climate change and droughts are interconnected, and addressing climate change is an essential component of adapting to and mitigating the impact of droughts.

Answer:

more hotter temperature & less rain can increase regularity of droughts because new water may not be added to reservoirs (places where cities get their drinking water from)

I need help, I can’t seem to get the concept

I need help, I cant seem to get the concept

Answers

Answer:

x=8

Step-by-step explanation:

Hello

As they are similar we can write

\(\dfrac{18}{12}=\dfrac{9}{6}=\dfrac{6}{4}=\dfrac{12}{x} \ so\\\\x = \dfrac{2*12}{3}=2*4=8\)

Hope this helps

Answer:

x = 8

Step-by-step explanation:

The sides of the polygon are similar, meaning each side corresponds with the same side of the smaller polygon.

ex. PQ≈TU , QR≈UV , etc.

Because of this the sides RS and VW are also similar, the polygon is simply being scaled down by 1.5

9÷1.5 = 6 , 6÷1.5 = 4

therefore the side length VW is a scaled down version of RS meaning you take the length of RS , which is 12 , and divide it by 1.5

12 ÷ 1.5 = 8

Hope this helped!

the probability of an airline flight arriving on time at a certain airport is 84%, use a normal approximate to find the probability that more than 240 in a random sample of 400 commercial airline flights at the airport will arrive on time​

Answers

The probability that more than 240 flights in a random sample of 400 commercial airline flights will arrive on time is approximately 1 or 100%.

To solve this problem using a normal approximation, we need to calculate the mean (μ) and standard deviation (σ) of the binomial distribution and then use the normal distribution to approximate the probability.

Given:

Probability of an airline flight arriving on time (success): p = 0.84

Number of trials (flights): n = 400

Number of flights arriving on time (successes): x > 240

First, we calculate the mean and standard deviation of the binomial distribution using the following formulas:

Mean (μ) = n * p

Standard Deviation (σ) = √(n * p * (1 - p))

μ = 400 * 0.84 = 336

σ = √(400 * 0.84 * 0.16) = √(53.76) ≈ 7.33

Now, we can use the normal distribution to find the probability that more than 240 flights will arrive on time. Since we're interested in the probability of x > 240, we will calculate the probability of x ≥ 241 and then subtract it from 1.

To use the normal distribution, we need to standardize the value of 240:

z = (x - μ) / σ

z = (240 - 336) / 7.33

z ≈ -13.13

Now, we can find the probability using the standard normal distribution table or a calculator. Since the value of z is extremely low, we can approximate it as:

P(x > 240) ≈ P(z > -13.13)

From the standard normal distribution table or calculator, we find that P(z > -13.13) is essentially 1 (close to 100%).

Therefore, the probability that more than 240 flights in a random sample of 400 commercial airline flights will arrive on time is approximately 1 or 100%.

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What is the equation of the line that is parallel to the given line and passes through the point (-3,2)?

3x - 4y = -17
3x - 4y = -20
4x + 3y = -2
4x + 3y = -6

What is the equation of the line that is parallel to the given line and passes through the point (-3,2)?3x

Answers

Answer:

Step-by-step explanation:

(0, 3) (3, -1)

(-1 - 3)/(3 -0)= -4/3

y - 2 = -4/3(x + 3)

y - 2 = -4/3x - 4

y = -4/3x - 2

3(y = -4/3x - 2)

3y = -4x - 6

4x + 3y = -6

answer is option 4

A partially completed equation for a line is shown below. If the line passes through the point (-4, 6). Write the equation for the line.

y=-3x+by=−3x+b

Answers

Answer:

Nice

Step-by-step explanation:

Karma..... ;)

Nice hope this helps

Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 45 feet from point A and 69 feet from point B. The angle A C B is 52'. How far apart are points A and B?
Select one:
a. 93.3 feet
b. 69.8 feet
c. 76.7 feet
d. 103.5 feet
e. 54.4 feet

Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a

Answers

The value of distance between points A and B is 54.4 feet.

What is the law of cosine?

The Law of Cosines is used to find the remaining parts of an oblique (non-right) triangle when either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are known as the law of cosines states: c²=a²+b²−2ab cos C .

Solution:

Using the law of cosines we get:

(AB)²=(AC)²+(BC)²-2AC×BC×cos(C)

(AB)²= (45)²+(69)²-2(45)(69)cos(52°)

(AB)² = 2025 + 4761 - 3823.2577

∴ AB = 54.4 feet

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Please help!!!!! See picture below.

Please help!!!!! See picture below.

Answers

Answer:

your answer will be A !!!

Step-by-step explanation:

hope it helps you

have a great day/night!!

Answer:

A is the correct answer of this question

hope it helps and your day will be full of happiness

Pls help! Mr Douglass trains a group of student athletes. He wants to know how they are improvising in the number of sit ups they can do. The following dot plots show the number of sit ups each student was able to do last month and this month.

By how much did the mean number of sit ups increase from last month to this month?

Pls help! Mr Douglass trains a group of student athletes. He wants to know how they are improvising in

Answers

Last month mean: 31
This month mean: 38.5
38.5-31=7.5
The mean number of sit ups increased from last month to this month is 7.5

Does anyone know the value of x and y?!?!

Does anyone know the value of x and y?!?!

Answers

Answer:

x=4 and y=2

Step-by-step explanation:

I'm not 100% sure but I substituted different numbers into the equation:

If x=4 and y=2 then 4+2=6 and 3x2=6 so it would be 6=6

Another option is x=7 and y=3 then 7+2=9 and 3x3=9 so it would be 9=9

I'm more confident with x=4 and y=2 because of the small size of the triangle.

I hope this helps! Good luck! :)

X is 4 y is 2 ʕ•ᴥ•ʔʕ•ᴥ•ʔʕ•ᴥ•ʔʕ•ᴥ•ʔʕ•ᴥ•ʔ

A triangular pane of glass has a height of 32 inches and an area of 352 square inches. What is the length of the base of the pane?

Answers

The required length of the base of the triangular pane of glass is 22 inches.

We know that the formula for the area of a triangle is:

Area = 1/2 * base * height

We are given that the height of the triangular pane of glass is 32 inches and the area is 352 square inches. Substituting these values into the formula, we get:

352 = 1/2 * base * 32

Multiplying both sides by 2 and dividing by 32, we get:

base = 22

Therefore, the length of the base of the triangular pane of glass is 22 inches.

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Four different exponential functions are represented below.
Drag the representation of each function into order from greatest y-intercept to least y-
intercept.

Four different exponential functions are represented below.Drag the representation of each function into

Answers

The graph of the function y = 2x⁴ - 5x³ + x² - 2x + 4 is plotted and attached.

How to solve

We have the 4 functions as shown in the image attached.

The y - intercept is the point where the graph intercepts the y - axis.

Function [1] -

y = 4 + 2x

y - intercept is 4

Function [2] -

y = 5ˣ + 1

y - intercept is 2.

Function [3] -

the y-intercept is 1.

Function [4] -

the y - intercept is at -1.

Therefore, the greatest y-intercept is of function -

f(x) = 2x + 4

and the least y-intercept is of the function shown in graph [4] or function [4].

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Four different exponential functions are represented below.Drag the representation of each function into

Answer:

Carlos puts $3 into his bank account and it grows by 50% each year

f(x)=4^x+1

(The Table)

(The Graph)

Helpppp!

Find the equation of the line that is perpendicular to y=-1/2x+5., and passes through (-2,-5).

Answers

Considering the definition of perpendicular line, the equation of of perpendicular line is y=2x -1.

Linear equation

A linear equation o line can be expressed in the form y = mx + b

where

x and y are coordinates of a point.m is the slope.b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.

Perpendicular line

Perpendicular lines are lines that intersect at right angles or 90° angles. If you multiply the slopes of two perpendicular lines, you get –1.

Equation of perpendicular line in this case

The line is y= -1/2x+5

If you multiply the slopes of two perpendicular lines, you get –1. In this case, the line has a slope of  -1/2. So:

-1/2× slope perpendicular line= -1

slope perpendicular line= (-1)÷ (-1/2)

slope perpendicular line= 2

So, the perpendicular line has a form of: y= 2x + b

The line passes through the point (-2, -5). Replacing in the expression for perpendicular line:

-5= 2×(-2) + b

-5= -4 + b

-5 +4= b

-1= b

Finally, the equation of of perpendicular line is y=2x -1.

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An arrow is shot from 3 ft above the top of a hill with a vertical upward velocity of 108 ​ft/s. If it strikes the plain below after 9.5 ​s, how high is the​ hill?
If the arrow is launched at t​0, then write an equation describing velocity as a function of time?

Answers

The height of the hill is approximately 25.73 ft. Where v0 is the initial velocity (108 ft/s), g is the acceleration due to gravity \((-32.2 ft/s^2)\),

To find the height of the hill, we can use the formula for the vertical position of an object under constant acceleration:

h = h0 + v0t + 1/2at^2

where h is the final height, h0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity (-32.2 ft/s^2).

In this case, we are given that the initial height h0 is 3 ft, the initial velocity v0 is 108 ft/s, and the time t is 9.5 s. We want to find the height of the hill, which we can denote as h_hill. The final height is the height of the plain, which we can denote as h_plain and assume is zero.

At the highest point of its trajectory, the arrow will have zero vertical velocity, since it will have stopped rising and just started to fall. So we can set the velocity to zero and solve for the time it takes for that to occur. Using the formula for velocity under constant acceleration:

v = v0 + at

we can solve for t when v = 0, h0 = 3 ft, v0 = 108 ft/s, and a = -32.2 ft/s^2:

0 = 108 - 32.2t

t = 108/32.2 ≈ 3.35 s

Thus, it takes the arrow approximately 3.35 s to reach the top of its trajectory.

Using the formula for the height of an object at a given time, we can find the height of the hill by subtracting the height of the arrow at the top of its trajectory from the initial height:

h_hill = h0 + v0t + 1/2at^2 - h_top

where h_top is the height of the arrow at the top of its trajectory. We can find h_top using the formula for the height of an object at the maximum height of its trajectory:

h_top = h0 + v0^2/2a

Plugging in the given values, we get:

h_top = 3 + (108^2)/(2*(-32.2)) ≈ 196.78 ft

Plugging this into the first equation, we get:

h_hill = 3 + 108(3.35) + 1/2(-32.2)(3.35)^2 - 196.78

h_hill ≈ 25.73 ft

If the arrow is launched at t0, the equation describing velocity as a function of time would be:

v(t) = v0 - gt

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There are 28 students in a class.
16 of the students are girls.
What proportion are boys?
Write your answer in two ways.

Answers

Answer:

3:7

Step-by-step explanation:

Given:

There are 28 students in a class16 of the students are girls.

To Find:

What proportion of the students are boys.

Formula used:

No. of boys = Total students - No. of girls

Using the formula, we have

No. of boys = 28 - 16 = 12

Proportion of boys = 12/28 = 3/7

So, proportion of boys = 3:7.

Sixty men can build a wall in 40days but though they begin the work together, 55 men quit every ten days. The Time needed to build the wall is?​

Answers

It would take 370 days to build the wall with the given conditions.

If 60 men can build a wall in 40 days, then the total man-days required to build the wall is:

60 men x 40 days = 2400 man-days

However, 55 men quit every ten days, which means that after 10 days, there are only 60 - 55 = 5 men left to work on the wall. After 20 days, there are only 5 - 55 = -50 men left, which means that the remaining 5 men cannot work any faster than they were already working. Therefore, we can assume that the remaining 5 men complete the wall on their own.

The number of man-days required for the first 10 days is:

60 men x 10 days = 600 man-days

The number of man-days required for the second 10 days is:

5 men x 10 days = 50 man-days

The total number of man-days required for the first 20 days is:

600 man-days + 50 man-days = 650 man-days

The remaining work can be completed by the 5 men in:

2400 man-days - 650 man-days = 1750 man-days

Therefore, the total time needed to build the wall is:

20 days + 1750 man-days / 5 men = 20 + 350 days = 370 days

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100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

Answers

Answer:

\(BC=5.1\)

\(B=23^{\circ}\)

\(C=116^{\circ}\)

Step-by-step explanation:

The diagram shows triangle ABC, with two side measures and the included angle.

To find the measure of the third side, we can use the Law of Cosines.

\(\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}\)

In this case, A is the angle, and BC is the side opposite angle A, so:

\(BC^2=AB^2+AC^2-2(AB)(AC) \cos A\)

Substitute the given side lengths and angle in the formula, and solve for BC:

\(BC^2=7^2+3^2-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-42\cos 41^{\circ}\)

\(BC^2=58-42\cos 41^{\circ}\)

\(BC=\sqrt{58-42\cos 41^{\circ}}\)

\(BC=5.12856682...\)

\(BC=5.1\; \sf (nearest\;tenth)\)

Now we have the length of all three sides of the triangle and one of the interior angles, we can use the Law of Sines to find the measures of angles B and C.

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c} $\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

In this case, side BC is opposite angle A, side AC is opposite angle B, and side AB is opposite angle C. Therefore:

\(\dfrac{\sin A}{BC}=\dfrac{\sin B}{AC}=\dfrac{\sin C}{AB}\)

Substitute the values of the sides and angle A into the formula and solve for the remaining angles.

\(\dfrac{\sin 41^{\circ}}{5.12856682...}=\dfrac{\sin B}{3}=\dfrac{\sin C}{7}\)

Therefore:

\(\dfrac{\sin B}{3}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin B=\dfrac{3\sin 41^{\circ}}{5.12856682...}\)

\(B=\sin^{-1}\left(\dfrac{3\sin 41^{\circ}}{5.12856682...}\right)\)

\(B=22.5672442...^{\circ}\)

\(B=23^{\circ}\)

From the diagram, we can see that angle C is obtuse (it measures more than 90° but less than 180°). Therefore, we need to use sin(180° - C):

\(\dfrac{\sin (180^{\circ}-C)}{7}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin (180^{\circ}-C)=\dfrac{7\sin 41^{\circ}}{5.12856682...}\)

\(180^{\circ}-C=\sin^{-1}\left(\dfrac{7\sin 41^{\circ}}{5.12856682...}\right)\)

\(180^{\circ}-C=63.5672442...^{\circ}\)

\(C=180^{\circ}-63.5672442...^{\circ}\)

\(C=116.432755...^{\circ}\)

\(C=116^{\circ}\)

\(\hrulefill\)

Additional notes:

I have used the exact measure of side BC in my calculations for angles B and C. However, the results will be the same (when rounded to the nearest degree), if you use the rounded measure of BC in your angle calculations.

20. Sketch the level curve of the function f(x, y) that contains the point (5,0).

f(x, y) is shown in the picture attached.​

20. Sketch the level curve of the function f(x, y) that contains the point (5,0).f(x, y) is shown in

Answers

At the given point,

\(f(5,0) = \dfrac1{\sqrt{5^2 + 0^2 - 9}} = \dfrac1{\sqrt{16}} = \dfrac14\)

Then the level curve is

\(\dfrac1{\sqrt{x^2 + y^2 - 9}} = \dfrac14 \\\\ \implies \sqrt{x^2 + y^2 - 9} = 4 \\\\ \implies x^2 + y^2 - 9 = 4^2 \\\\ \implies x^2 + y^2 = 25 = 5^2\)

which is a circle centered at the origin with radius 5 - quite easy to sketch.

Which is the correct equation for a line that passes through the points (-2,7) and (2,-5)?
y=3x+5
y=1/3x+3
y= -3x-12
y= -3x+1

Answers

Answer:

y= -3x+1

Step-by-step explanation:

x1= -2 x2=2 y1=7 y2=-5

using the formula

(y-y1)/(x-x1)=(y2-y1)/(x2-x1)

(y-7)/(x-(-2))=(-5-7)/(2-(-2))

(y-7)/(x+2)=(-5-7)/(2+2)

(y-7)/(x+2)=(-12)/4

(y-7)/(x+2)=-3

cross multiply

y-7=-3(x+2)

y-7=-3x-6

y=-3x-6+7

y=-3x+1

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