Answer:
hj means has a job
nj means no job
Step-by-step explanation:
A pattern for a skirt calls for 1 7/8 yd of fabric. If Mary
Kate wants to make one skirt for herself and one for her
twin, how much fabric will she need?
Answer:
Mary Kate will need 3 6/8 yd of fabric.
Step-by-step explanation:
If Mary wants to make one skirt for herself AND her twin, that is equal to 2 skirts.
So if one skirt calls for 1 7/8 yd of fabric, multiply it by 2:
1 7/8 x 2
Convert 1 7/8 to an improper fraction and add 1 as a denominator for 2:
15/8 x 2/1 = 30/8
30/8 simplified is 3 6/8
Brainliest please?
formula area of the square
The real roots for the equation x4 – x3 10x2 – 16x – 96 = 0 are –2 and 3. what are the nonreal solutions? –i, i –2i, 2i –4i, 4i –16i, 16i
The Non-real solutions for the equation \(x^{4} -x^{3}+10x^{2} -16x-96=0\) are (-4i, 4i).
Non-real solution:
An answer to a mathematical equation with the root of a negative number that cannot be determined using solely real numbers—i.e., numbers that can be described along a single axis—is referred to as a non-real solution.
If a quadratic has a negative discriminant, then the quadratic equation has a Non-real solution.
Given,
\(x^{4} -x^{3}+10x^{2} -16x-96=0\)
On factorizing the above equation, we get
\((x-3)(x-2)(x^{2} +16)=0\)
Applying Zero Product Property,
\(x^{2} +16 = 0\) or \(x-3=0\) 0r \(x+2=0\)
Taking \(x^{2} +16 = 0\), we get
\(x^{2} =-16\)
x = ± \(\sqrt{-16}\)
x = ± 4i [∵ i = √-1]
Hence,
The Non-real solutions for the equation \(x^{4} -x^{3}+10x^{2} -16x-96=0\) are (-4i, 4i).
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Answer:
C
Step-by-step explanation:
edge 2026
What order do I put the numbers in
We have following associations:
m ∠ADC + m ∠CDB = 180° → Definition of linear pair∠ADC is supplementary to ∠CDB → Definition of supplementary angles 2 · m ∠BDC = 180° → Substitution property of equalitym ∠BDC = 90° → Division property of equalityHow to complete the proof of a geometric theorem
In this question we need to fill the blanks of a given proof by understanding and taking advantage of the most important axioms and theorems of Euclidean geometry and real algebra. In this case, a linear pair is the combination of two angles whose sum equals 180°, and those angles are always supplementary.
Thus, we have following associations:
m ∠ADC + m ∠CDB = 180° → Definition of linear pair∠ADC is supplementary to ∠CDB → Definition of supplementary angles 2 · m ∠BDC = 180° → Substitution property of equalitym ∠BDC = 90° → Division property of equalityTo learn more on Euclidean theorem: https://brainly.com/question/13104788
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Given the triangle ABC at points A = ( 2, 2 ) B = ( 4, 5 ) C = ( 6, 3 ), and if the triangle is first reflected over the y axis, and then over the x axis, find the new point A''.
Given
The triangle ABC at points A = (2, 2) B = (4, 5) C = (6, 3).
To find:
Which of the following is an arithmetic sequence that could be modeled by an explicit formula expressed as a linear function? A. −1, −8, −27, −64, −125, … B. −5, −2, 3, 10, 19, … C. −5, −1, 3, 7, 11, … D. 1/2, 1/4, 1/8, 1/16, 1/32, …
Answer:
C
Step-by-step explanation:
Given
- 5, - 1, 3, 7, 11
There is a common difference d between consecutive terms, that is
11 - 7 = 7 - 3 = 3 - (- 1) = - 1 - (- 5) = 4
This indicates the sequence is arithmetic with explicit formula
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 5 and d = 4 , thus
\(a_{n}\) = - 5 + 4(n - 1) = - 5 + 4n - 4 = 4n - 9
What is the value of x? Enter your answer in the box. x =
Answer:
By using the given information in the diagram, the value of x is 20.
Step-by-step explanation:
From looking at the diagram, the triangles appear to be similar. This means that they are going to have the same ratios between each side.
We are given two measurements on one side of the triangle, 11 and 121. We can find the ratio of these sides by dividing 121 by 11.
121 ÷ 11 = 11
So, the ratio between the two triangles is 11 which means that the ratio for the rest of the sides of the triangle is going to have a ratio of 11. Knowing this, we can turn this into a equation to find the value of x.
\(\frac{121}{11} = \frac{5x+10}{10}\)
Cross multiply the terms.
1210 = 55x + 110
Subtract 110 from both sides of the equation.
1210 - 110 = 55x + 110 - 110
1100 = 55x
Divide 55 from both sides of the equation.
1100/55 = 55x/55
20 = x
So, the value of x is 20.
find the measure of the indicated angle to the nearest degree
B. 47°
hope this helps :)
Answer:
A) 71°
Step-by-step explanation:
indicated angle =
\(sin^{-1} \frac{51}{54} = sin^{-1}0.94\)
Suppose "n" can't equal 0 or 1. Show that substitution v=y^(1-n) transforms the Bernoulli equation dy/dx + P(x)y=Q(x)y^(n)into the linear equation dv/dx + (1-n)P(x)v(x)=(1-n)Q(x).
Answer:v = y(1-n)dv/dx = (1-n)y-n dy/dxso dy
Step-by-step explanation:
Write and solve an equation to solve the problem. lisa is 4 centimeters taller than her friend lan. lan is 8 centimeters taller than jim. every month, their heights increase by 2 centimeters. in 4 months, the sum of lan's and jim's heights will be 170 centimeters more than lisa's height. how tall is lan now? let h be lan's height today in centimeters.
After solving an equation as per given relation of Lan, Lisa and Jim height ,now Lan's height is 174centimeters.
As given ,
Let h be Lan's height today in centimeters.
As per the relation between Lan, Lisa and Jim height we have,
Lan=h cm
Lisa=h + 4
Jim=h -8
After 4 months, every month their heights increase by 2 cm
Lan=h + 8
Lisa=h + 4 +8
Jim=h -8 +8
Required equation for given condition:
Lan + Jim=170 +Lisa
⇒h +8 + h -8 + 8=170 + h + 4+8
⇒2h+8=h+182
⇒h=174cm
Therefore, after solving an equation as per given relation of Lan, Lisa and Jim height ,now Lan's height is 174centimeters.
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What is the volume of this container?
Answer:
480 in³
Step-by-step explanation:
The formula to find the volume of a container is L×B×H (Length×Breadth×Height). So to make this simpler, label the bigger container as 'A' and the smaller container 'B'.
Container 'A' (Volume):
Length×Breadth×Height
5 in×8 in×10 in = 400 in³
Container 'B' (Volume):
Length×Breadth×Height
4 in×4 in×5 in = 80 in³
To find the total volume, add both values together:
400 in³+ 80 in³ = 480 in³
Answer: 480 in³
Hope this helps!
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there are 10 balls in order, 5 yellow, 3 green, 2 black. what is the probability that 2 black balls are not next to each other
The probability that 2 black balls are not next to each other can be calculated by finding the total number of ways to arrange the balls and subtracting the number of ways where the black balls are next to each other.
First, let's find the total number of ways to arrange the balls. This can be done using the formula for permutations of a multiset:
Total number of ways = 10! / (5! * 3! * 2!) = 2520
Next, let's find the number of ways where the black balls are next to each other. We can do this by treating the two black balls as one unit and calculating the number of ways to arrange the 9 units (5 yellow, 3 green, 1 black unit):
Number of ways with black balls next to each other = 9! / (5! * 3! * 1!) = 504
Finally, we can subtract the number of ways with the black balls next to each other from the total number of ways to get the number of ways where the black balls are not next to each other:
Number of ways with black balls not next to each other = 2520 - 504 = 2016
Therefore, the probability that 2 black balls are not next to each other is 2016/2520 = 0.8.
Answer: 0.8.
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What is the activation energy of a reaction if it has the following rate constants? Rate Constant Temperature 6.20 x 10-4 s-1 700 K 2.39 X 10-2 s-1 760 K'
The activation energy of the reaction is approximately 126.8 kJ/mol. The calculation was done using the Arrhenius equation and the natural logarithm of the rate constants at the two temperatures.
To calculate the activation energy of a reaction, we can use the Arrhenius equation:
k = A * e⁽⁻ᴱᵃ/ᴿᵀ⁾
where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.
We have two rate constants at different temperatures, so we can set up two equations:
k₁ = A * e⁽⁻ᴱᵃ/ᴿᵀ₁⁾
k₂ = A * e⁽⁻ᴱᵃ/ᴿᵀ₂⁾
We want to solve for Ea, so we can take the natural logarithm of both sides of each equation:
ln(k₁) = ln(A) - Ea/RT₁
ln(k₂) = ln(A) - Ea/RT₂
We can subtract the second equation from the first to eliminate ln(A):
ln(k₁) - ln(k₂) = Ea/R * (1/T₂ - 1/T₁)
Now we can solve for Ea:
Ea = -R * (ln(k₁) - ln(k₂)) / (1/T₂ - 1/T₁)
Plugging in the given values, we get:
Ea = -8.314 J/mol/K * (ln(6.20 x 10⁻⁴) - ln(2.39 x 10⁻²)) / (1/760 K - 1/700 K)
Ea ≈ 126.8 kJ/mol
Therefore, the activation energy of the reaction is approximately 126.8 kJ/mol.
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9. Which graph can be used to find the solution to the system of equations?
y = x-1
9y = 6x – 15
Ella completed the following work to test the equivalence of two expressions. What conclusion can you draw from Ella’s work? The expressions are equivalent because Ella got a different result when she substituted zero for f. The expressions are equivalent because Ella got the same result when she substituted zero for f. The expressions are not equivalent even though Ella got the same result when she substituted zero for f. The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Answser its c the expressions are no equivalent even though ella got the same result when she substituded zero for f
Step-by-step explanation:
this is correct for egenuity october 2020 d is wrong
Answer:
its C
Step-by-step explanation:
I NEED HELP PLEASE!!!!!!!
1) How long is it from 9:15 am to 4:48 pm? h
2) Find the value of 4n if n=7
3) Solve the equation 3y=21
4) Change the index notation of a⁴ to its factors
A financial manager made two new investments—one in the oil industry and one in municipal
bonds. After a one-year period, each of the investments will be classified as either successful
or unsuccessful. Consider the making of the two investments as a random experiment.
a. how many sample points exist for this experiment?
b. Show a tree diagram and list the sample points.
c. let o = the event that the oil industry investment is successful and M = the event that
the municipal bond investment is successful. list the sample points in o and in M.
d. list the sample points in the union of the events (o ∪ M ).
The union of the two events (oil industry investment is successful and municipal bond investment is successful) contains three sample points: (Oil Industry investment is successful, Municipal Bond investment is successful), (Oil Industry investment is unsuccessful, Municipal Bond investment is successful), (Oil Industry investment is successful, Municipal Bond investment is unsuccessful).
a. There are four sample points for this experiment: (oil industry investment is successful, municipal bond investment is successful), (oil industry investment is unsuccessful, municipal bond investment is successful), (oil industry investment is successful, municipal bond investment is unsuccessful), (oil industry investment is unsuccessful, municipal bond investment is unsuccessful).
b. The tree diagram for this experiment is shown below:
Investment
|
|
--------------
| |
Oil Industry Municipal Bond
Sample Points:
• (Oil Industry investment is successful, Municipal Bond investment is successful)
• (Oil Industry investment is unsuccessful, Municipal Bond investment is successful)
• (Oil Industry investment is successful, Municipal Bond investment is unsuccessful)
• (Oil Industry investment is unsuccessful, Municipal Bond investment is unsuccessful)
c. The sample points in o (oil industry investment is successful) are:
• (Oil Industry investment is successful, Municipal Bond investment is successful)
• (Oil Industry investment is successful, Municipal Bond investment is unsuccessful)
The sample points in M (municipal bond investment is successful) are:
• (Oil Industry investment is successful, Municipal Bond investment is successful)
• (Oil Industry investment is unsuccessful, Municipal Bond investment is successful)
d. The sample points in the union of the events (o ∪ M ) are:
• (Oil Industry investment is successful, Municipal Bond investment is successful)
• (Oil Industry investment is unsuccessful, Municipal Bond investment is successful)
• (Oil Industry investment is successful, Municipal Bond investment is unsuccessful)
The union of the events can be expressed mathematically as:
o ∪ M = {(Oil Industry investment is successful, Municipal Bond investment is successful), (Oil Industry investment is unsuccessful, Municipal Bond investment is successful), (Oil Industry investment is successful, Municipal Bond investment is unsuccessful)}
To calculate the union of the two events, we can use the formula for the union of two sets:
A ∪ B = {x | x ∈ A ∨ x ∈ B}
In this case, A = o and B = M, so the union of the two events can be expressed as:
o ∪ M = {x | x ∈ o ∨ x ∈ M}
= {(Oil Industry investment is successful, Municipal Bond investment is successful), (Oil Industry investment is unsuccessful, Municipal Bond investment is successful), (Oil Industry investment is successful, Municipal Bond investment is unsuccessful)}
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the parking space outside sky towers measures 2x-1 meters x+2 meters . what is rhe cost of cleaning the parking area if the cleaner has to be paid rs 50 per m^2
Answer:
Rs 100x² + 150x - 100
Step-by-step explanation:
Area of the parking space = Length * Width
Area of the space = (2x-1)(x+2)
Expand
Area of the space = 2x² + 4x - x - 2
Area of the space = (2x²+3x - 2) sq. m
Since 1sq.m = Rs 50'
(2x²+3x - 2) sq. m= z
z = 50 (2x²+3x - 2)
z = 100x² + 150x - 100
hence the cost of the parking spsce is Rs.100x² + 150x - 100
Match each system of equations to the inverse of its coefficient matrix, A-1, and the matrix of its solution, X.
The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.
Given that the system of equations are shown in given figure.
The first system of equations are
\(\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end\)
By writing in matrix AX=b, we get
Coefficient matrix \(A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right]\) and \(B=\left[\begin{array}{l}150&-100&600\end{array}\right]\)
Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get
\(\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end\)
\(\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end\)
\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end\)
For a solution Consider [A B] and apply row operations, we get
\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end\)
Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right]\)
The second system of equations are
\(\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end\)
Similarly, we will find for second system of equations
\(\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end\)
\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end\)
\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end\)
\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end\)
Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right]\)
The third system of equations are
\(\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end\)
Similarly, we will find for third system of equations
\(\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end\)
\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end\)
\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end\)
get
\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end\)
Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right]\)
Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.
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If you know the answer to this let me know pls!
Answer:
I think it is C.
Step-by-step explanation:
Have a good day. :-)
Dave is making a rectangle garden bed after assembling it he finds that the bed has a width of three fourths of a foot and a length of nine and one-third feet as shown what is the area of the garden in square feet express your answer in simplest form
Answer:
7 square feet
Explanation:
The width of the rectangle is 3/4 ft and the length is 9 1/3 ft.
First, we need to convert 9 1/3 ft to a fraction, so
\(9\frac{1}{3}=9+\frac{1}{3}=\frac{9(3)+1}{3}=\frac{27+1}{3}=\frac{28}{3}\)Then, the length of the rectangle is 28/3 ft
Now, we can calculate the area of the garden as
\(\begin{gathered} \text{Area = Width x Length} \\ \text{Area = }\frac{3}{4}\times\frac{28}{3}=\frac{3\times28}{4\times3}=\frac{84}{12}=7 \end{gathered}\)Therefore, the area is 7 square feet.
TIME SENSITIVE I REALLY NEED HELP
Which function is continuous at x = 18?
Answer:
The answer is D.
Step-by-step explanation:
a) Plugging x = 18 gets numerator 0^2/18 = 0 that not continuous.
b) Plugging x = 18 the denomiator becomes a value/0 making it undefined.
c) Plugging x = 18 gets tan(2pi) = 0/1 which is 0
d) f(x) = 36 is should be a straight lines at y =36. I think. Best option is D.
Please help I need the answer right now!!!
Find the perimeter of parallelogram ABCD with vertices A(-2,2) B(4,2) C(-6,-1) D(0,-1)
Answer:
I Believe it is A sorry if i`m wrong
Step-by-step explanation:
The play area in a local park has the dimensions shown at the right. What is the area of the park? 25 m 24 m 30 m What is the base of the triangle? What is the height of the triangle? PLEASE HELP
Answer:
Base is 30 m, height is 24 m, area is 360 sq m
Step-by-step explanation:
It gives you the base and height. (The base is the bottom or bottom line of something.)
Area of a triangle is always half the base times the height.
.5 * 30 * 24 = 360
The Height of the triangle is 24 m.
The base of Triangle is 37 m.
What is Pythagoras Theorem?The Pythagoras theorem which is also referred to as the Pythagorean theorem explains the relationship between the three sides of a right-angled triangle. According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides of a triangle.
Using Pythagoras theorem,
In a small Triangle
H² = P² + B²
25²= 24² + B²
625 = 576 + B²
B² = 49
B= 7 m
So, the base of Triangle is (30+ 70= 37 m
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Find the slope of the tangent line to the given polar curve at point specified by the value the theta. r = 5 + 8 cos theta, theta = pi/3
The slope of the tangent line to the polar curve r = 5 + 8cos(θ) at the point specified by θ = π/3 is -√3/4.
To find the slope of the tangent line, we first need to express the polar equation in Cartesian form. The conversion formulas are x = rcos(θ) and y = rsin(θ). For the given equation r = 5 + 8cos(θ), we can rewrite it as:
x = (5 + 8cos(θ))cos(θ)
y = (5 + 8cos(θ))sin(θ)
Next, we differentiate both x and y with respect to θ to find dx/dθ and dy/dθ. Using the chain rule, we get:
dx/dθ = (-8sin(θ) - 8cos(θ)sin(θ))
dy/dθ = (8cos(θ) - 8cos^2(θ))
Now, we can find dy/dx, the slope of the tangent line, by dividing dy/dθ by dx/dθ:
dy/dx = (dy/dθ) / (dx/dθ) = ((8cos(θ) - 8cos^2(θ)) / (-8sin(θ) - 8cos(θ)sin(θ)))
Substituting θ = π/3 into the equation, we find:
dy/dx = ((8cos(π/3) - 8cos^2(π/3)) / (-8sin(π/3) - 8cos(π/3)sin(π/3)))
Simplifying the expression, we get:
dy/dx = (-√3/4)
Therefore, the slope of the tangent line to the polar curve at the point specified by θ = π/3 is -√3/4.
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f(x)=g(x)
f(x)=-¾x²+3x+1
g(x)=(sqrt x)-1
what is the solution to f(x)=g(x)
1. x=0
2. x=1
3. x=2
4. x=4
Answer:
(d) x = 4
Step-by-step explanation:
You want the solution to the system of equations using the given graph.
f(x) = -3/4x² +3x +1g(x) = (√x) -1f(x) = g(x)GraphThe solution to the equation f(x) = g(x) is the x-coordinate of the point(s) on their graphs where the curves intersect.
The graph shows the point of intersection of the two functions is (4, 1). This is the solution you have marked in the supplied image.
x = 4
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g a particular telephone number is used to receive both voice calls and fax messages. suppose that 25% of the incoming calls involve fax messages, and consider a sample of 25 incoming calls. what is the probability that
The probability is 0.2137
Explanation:
Given a particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls involve fax messages, and consider a sample of 25 incoming calls.
The probability that in a sample of 25 incoming calls, exactly 5 of them involve fax messages is calculated as follows;
P(X = 5) = 25C5(0.25)⁵(0.75)²⁰= 53130(0.25)⁵(0.75)²⁰= 0.2137
Therefore, the probability that in a sample of 25 incoming calls, exactly 5 of them involve fax messages is 0.2137.
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select the correct answer from the drop-down menu Given: W(-1,1),X(3,4),Y(6,0) and Z(2,3) are the vertices of quadrilateral WXYZ Prove: WXYZ is a square using the distance formula I found ________
The quadrilateral WXYZ is not a square using the distance formula
Proving WXYZ is a square using the distance formulaFrom the question, we have the following parameters that can be used in our computation:
W(-1,1),X(3,4),Y(6,0) and Z(2,3)
The lengths of the sides can be calculated using the following distance formula
Length = √[Change in x² + Change in y²]
Using the above as a guide, we have the following:
WX = √[(-1 - 3)² + (1 - 4)²] = 5
XY = √[(3 - 6)² + (4 - 0)²] = 5
YZ = √[(6 - 2)² + (0 - 3)²] = 5
ZW = √[(2 + 1)² + (3 - 1)²] = 13
The sides that are congruent are WX, XY and YZ
This means that WXYZ is not a square
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what number is 12% of 315
Answer:
12% of 315 is 37.8 :) Tag me if I'm wrong
Answer:
x = 37.80
Step-by-step explanation:
The decimal form of 12% is 0.12. An easy way of converting percentage into decimal by moving the decimal point two places to the left. Hence, 12% = 0.12.
The given statement, "What number is 12% of 315" can be expressed algebraically as:
x = 0.12 × 315.
x = 37.80
Therefore, 37.80 is 12% of 315.
Let f (x) = αx−α−1 for x ≥ 1 and f (x) = 0 otherwise, where α is a positive parameter. Show how to generate random variables from this density from a uniform random number generator
The random variable from of the function f (x) = αx−α−1 for x ≥ 1 and f (x) = 0, where α is a positive parameter is X = (1 - U)^(-1/α).
Explanation; -
Generate random variables from the given density function f(x) = αx^(-α-1) for x ≥ 1 and f(x) = 0 otherwise, using a uniform random number generator, you can follow the inverse transform method. Here are the steps:
1. Find the cumulative distribution function (CDF) F(x) by integrating f(x) with respect to x:
F(x) = ∫f(x)dx = ∫αx^(-α-1)dx from 1 to x, which yields F(x) = 1 - x^(-α).
2. Set F(x) equal to a uniformly distributed random variable U (0 ≤ U ≤ 1):
U = 1 - x^(-α).
3. Solve for x to find the inverse of the CDF F^(-1)(U):
x = (1 - U)^(-1/α).
4. Generate random variables by plugging in uniformly distributed random numbers (from a uniform random number generator) into F^(-1)(U):
X = (1 - U)^(-1/α).
By following these steps, you can generate random variables from the given density function using a uniform random number generator.
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