Please help ill mark brainliest

Answer: 9.7

Step-by-step explanation: 97 divided by 10 is 9.7

Answer:

x = 4

Step-by-step explanation:

perpendicular lines have opposite and reciprocal slopes

the line y = 2 is a horizontal line, which means the slope is zero

also, y = 2 intersects the y-axis at 2

a line perpendicular to a horizontal line is a vertical line and, if it passes through the point (4,5) will intersect the x-axis at 4

therefore, the equation would be x = 4

Answer:

wait what are doing.

Step-by-step explanation:

.

Answer:

Step-by-step explanation:

Any multiple of the given equation is also a dependent linear equation

From the equation

-5x+7y=2

Multiplying all through by any number, say 2

2(-5x)+2(7y)=2(2)

-10x+14y=4 is a dependent linear equation for -5x+7y=2

If you don't fancy using a multiple, you can write the gradient equation y=mx+c

-5x+7y=2

7y=5x+2

Dividing all through by 7 gives the equation as

y=5x/7 + 2/7

We need to find the general solution of the above PDE. Let's solve the above PDE by the method of characteristic. Let us first solve the PDE by using the method of characteristics.

The method of characteristics is a well-known method that provides a solution to the first-order partial differential equations. To use this method, we first need to find the characteristic curves of the given PDE. Thus, the characteristic curves are given by $x = t + c_1$.

Now, we need to eliminate $t$ from the above equations in order to obtain the general solution. By eliminating $t$, we get the general solution as:$$u(x,y) = f(2x - 3y) + 3(x - 2y)$$ where $f$ is an arbitrary function of one variable. Hence, the general solution of the PDE $u_{xx} - 2u_{xy} - 3u_{yy} = 0$ is given by the above equation. Thus, the main answer to the given question is $u(x,y) = f(2x - 3y) + 3(x - 2y)$. In order to find the general solution of the PDE $u_{xx} - 2u_{xy} - 3u_{yy} = 0$, we first used the method of characteristics. The method of characteristics is a well-known method that provides a solution to the first-order partial differential equations.

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Answer: 50km/hour

Step-by-step explanation:

Answer:

50 km an hour

Step-by-step explanation:

if the person is traveling 100 km an hour, we can divide the distance by the time, to find out how fast they were traveling

100 divided by 2 = 50

the person was traveling 50 km an hour

Answer:

The length of the hypotenuse in the triangle ABC is 12 cm.

The sides and angles of a right-angled triangle are dealt with in Trigonometry. The ratios of acute angles are called trigonometric ratios of angles. The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

Given that, ABC is a right-angled triangle.

We know that cos θ =Adjacent/Hypotenuse

Here, cos x = 3/4 and that the length of the side adjacent to the angle x is 9 cm.

From triangle ABC,

cos x=BC/AC =9/b

⇒ 3/4 = 9/b

⇒ b=12 cm

Therefore, the length of the hypotenuse in the triangle ABC is 12 cm.

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Answer:

The answer is C.

Step-by-step explanation:

You can't have a negative number of peas or carrots, so A and B are out. 1

00+250=350 which is more than 300.

150+145 = 295 which is less than 300.

So the answer is C.

The solutions of an equation are the true values of the equation.

The only viable solution is (c) (150, 145)

Let x represent peas and y represents carrots.

So, the constraints are:

\(\mathbf{x , y \ge 0}\) ---- i.e. the values of x and y cannot be 0

\(\mathbf{x + y \le 300}\) ---- i.e. the sum of x and y cannot exceed 300

\(\mathbf{x , y \ge 0}\)  means that options (a) and (b) are wrong.

This is so, because:

(-25, 100) and (380, -160) contain negative values of x or y

\(\mathbf{x + y \le 300}\) means that option (d) is wrong.

This is so, because:

The sum of (100, 250) exceeds 300

Hence, the only viable solution is (c) (150, 145)

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Answer:

\(r=5.79898987...\\A=510.31110884...\)

Step-by-step explanation:

Challenging question!

Start by constructing a square in the lower-left quadrant of the circle (that isn't shaded) that is tangent to center C, OP, and OQ:

(See picture)

With the blue line constructed, we can conclude that the blue line (the blue line is the measure from the center of the inscribed circle to the center of the quarter circle) measures \(\sqrt{2} r\) due to the Pythagorean theorem.

The orange line is the radius of the inscribed circle, so adding the blue line and the orange line gives the radius of the quarter circle, so:

\(\sqrt{2}r +r=14\)

Solve the equation with a bit of algebra to get:

\(\sqrt{2} r+r=14\\r(\sqrt{2}+1)=14\\r=\frac{14}{\sqrt{2}+1 }\\r=5.79898987...\)

Now, we will find the area of the inscribed circle:

\(A=\pi r^2\\A=\frac{22}{7} *(5.79898987...)^2\\A=105.68889115...\)

And we will now find the area of the quarter circle...:

\(A_{2} =\pi r^2\\A_{2}=\frac{22}{7}*14^2\\A_2=616\)

...and we subtract both results...:

\(A_{3}= 616-105.68889115...\\A_3=510.31110884...\)

To get the area of the shaded region.

Not sure what does the last part ("correct to 3 s. f.") meant but that's all I can do.

Answer:

The set is (5, 6]

Step-by-step explanation:

Ok, let's see the different possibles notations to describe sets.

If we want to describe a discrete set, we use {}

Like in the set:

{1, 2, 3}

That set only contains the numbers 1, 2, and 3.

If we want to describe a continuous set that does not include the extremes, we use ()

For example:

(1, 3)

Contains all the numbers between 1 and 3, but does not include 1 and 3.

If we want to include the extremes, we need to use []

[1, 3]

This set is all the numbers between 1 and 3, including the values 1 and 3.

And we can mix these last two notations, so if we want a set that includes all the numbers between 5 and 6, not including 5 but including 6, we need to write:

(5, 6]

Answer:

C, D, F

Step-by-step explanation:

Exponent rules:

\(\dfrac{a^b}{a^c}=a^{b-c}\)

\(a^{-n}=\dfrac{1}{a^n}\)

\(\dfrac{1}{a^{-n}}=a^n\)

\(a^n \cdot b^n=(ab)^n\)

\(a^0=1\)

\((a^b)^c=a^{bc}\)

\(\textsf{A}\quad\dfrac{24^{-3}}{24^{-4}}=24^{-3-(-4)}=24^1=24\)

\(\textsf{B}\quad3^{-2} \cdot 8^{-5}=\dfrac{1}{3^2} \cdot \dfrac{1}{8^5}=\dfrac{1}{9} \cdot \dfrac{1}{32768}=\dfrac{1}{294912}\)

\(\textsf{C}\quad\left(\dfrac{1}{24^{-7}}\right)^{-1}=\left(24^7\right)^{-1}=24^{-7}\)

\(\textsf{D}\quad\dfrac{8^{-7}}{3^7}=\dfrac{1}{8^7 \cdot 3^7}=\dfrac{1}{(8 \cdot 3)^7}=\dfrac{1}{24^7}=24^{-7}\)

\(\textsf{E}\quad24^7 \cdot 24^0=24^7 \cdot 1=24^7\)

\(\textsf{F}\quad(24^3 \cdot 24^4)^{-1}=\left(24^{3+4}\right)^{-1}=(24^7)^{-1}=24^{-7}\)

Answer:

9200

Step-by-step explanation:

9.2x10^3 is the same as saying 9.2 multiply 10 three times

The correct choice is: C. Errors ≤ 0.05 for M ≤ 1

To estimate the absolute error in approximating cos(0.48) using the 3rd order Taylor polynomial centered at 0, we'll use the remainder term. The remainder term for a Taylor series is given by:

R_n(x) = (f^{(n+1)}(c) * (x - a)^{(n+1)}) / (n+1)!

Here, f(x) is cos(x), x = 0.48, a = 0 (center), n = 3 (order), and c is a value between a and x.

Since f(x) = cos(x), the derivatives will cycle through the trigonometric functions. Specifically:

f(x) = cos(x)
f'(x) = -sin(x)
f''(x) = -cos(x)
f'''(x) = sin(x)
f''''(x) = cos(x)

Since n = 3, we need the 4th derivative, which is f''''(x) = cos(x). Since |cos(c)| is at most 1 for all c, we have:

|M| ≤ 1

Now, we can plug everything into the remainder term formula:

R_3(0.48) ≤ (1 * (0.48)^4) / (4!)

R_3(0.48) ≤ (0.48^4) / 24

R_3(0.48) ≤ 0.053130496

The absolute error in approximating cos(0.48) using the 3rd order Taylor polynomial centered at 0 is less than or equal to 0.053130496. Rounded to two decimal places, the error is ≤ 0.05. So, the correct choice is:

C. Errors ≤ 0.05 for M ≤ 1

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The term that describes a group of statements that executes as a single unit is a "block". A block of code is a program that is grouped together and treated as a single unit. So, the correct option is D.

In computer programming, a block is a group of statements or declarations that are enclosed within a set of curly braces ({ }). The block serves as a single unit that is executed together. Blocks are used to organize code and to apply control structures, such as loops and conditional statements, to multiple statements.

A block can contain any number of statements, which can include variable declarations, function calls, loops, conditional statements, and other constructs. The statements within a block are executed in sequence, one after another, unless a control statement is encountered that alters the normal sequence of execution.

For example, a while loop in Java consists of a block of code that is executed repeatedly while a certain condition is true:

while (condition) {

   // block of code to be executed while condition is true

}

In this example, the block of code inside the curly braces will be executed repeatedly while the condition specified in the while statement is true. The block can contain any number of statements, and these statements will be executed each time the loop iterates.

Another common use of blocks is to define functions or methods. A function or method is a block of code that can be called from other parts of the program, and can take inputs (arguments) and return outputs. For example, in Python, a function can be defined as follows:

def function(argument1, argument2):

   # block of code to be executed in the function

   return result

In this example, the block of code enclosed within the function definition is executed when the function is called. The function can take inputs (argument1 and argument2), which can be used within the function, and it can return a result using the return statement.

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The average speed during the interval between 1 second and 2 seconds is most nearly 8 m/s, which corresponds to option (E).

To determine the average speed during the interval between 1 second and 2 seconds, we need to find the displacement of the object during that time interval and divide it by the duration.

Looking at the graph, we can observe that the object's position increases from approximately 0 meters at 1 second to approximately 8 meters at 2 seconds.

Therefore, the displacement is 8 meters - 0 meters = 8 meters.

The duration of the time interval is 2 seconds - 1 second = 1 second.

To calculate the average speed, we divide the displacement by the duration:

Average speed = Displacement / Duration = 8 meters / 1 second = 8 m/s.

Therefore, the average speed during the interval between 1 second and 2 seconds is most nearly 8 m/s, which corresponds to option (E).

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Answer:

El piloto debe virar a 87.7° en la ciudad C para regresar a la ciudad A.

Step-by-step explanation:

Podemos encontrar el angulo que debe virar el piloto en la ciudad C para regresar a la ciudad A usando el Teorema del coseno:

\( (AC)^{2} = (AB)^{2} + (BC)^{2} - 2(AB)(BC)cos(50) \)

\( (AC)^{2} = (150 mi)^{2} + (100 mi)^{2} - 2(150 mi)(100 mi)cos(50) \)

\( (AC) = 115 mi \)

Ahora podemos encontrar el ángulo entre los puntos C y A (AC) usando la ley de los senos:

\( \frac{sin(50)}{AC} = \frac{sin(\alpha)}{AB} \)

\( \frac{sin(50)}{115 mi} = \frac{sin(\alpha)}{150 mi} \)

\( \alpha = 87.7 \)

Por lo tanto, el piloto debe virar a 87.7° en la ciudad C para regresar a la ciudad A.

Espero que te sea de utilidad!

El piloto debe virar con un ángulo de 61° 42' 12'' para regresar a la ciudad A.

Dado que un avión vuela desde la ciudad A hacia la ciudad B, a una distancia de 150 millas, y después vira con un ángulo de 50° y se dirige hacia la ciudad C, a una distancia de 100 millas, para determinar con que ángulo debe virar el piloto en la ciudad C para regresar a la ciudad A se debe realizar el siguiente cálculo, aplicando las teorías del seno y el coseno:

Por lo tanto, el piloto debe virar con un ángulo de 61° 42' 12'' para regresar a la ciudad A.

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Answer:

Step-by-step explanation:

\(F = \frac{9}{5}C+32\)

Subtract 32 from both sides

\(F-32= \frac{9}{5}C\\\)

Multiply both side by 5/9

\(\frac{5}{9}(F-32)=( \frac{5}{9})* \frac{9}{5}C\\\\ \frac{5}{9}(F-32)=C\\\)

F= 41

\(\frac{5(41-32)}{9}=C\\\\ \frac{5*9}{9}=C\\\\ \frac{45}{9}=C\\\\C = 5\\\\\)

41° F = 5° C

Answer:

125 questions

Answer:

125 questions

Step-by-step explanation:

Answer:

  14.5 cm

Step-by-step explanation:

The distance in km is ...

  (87 km)×1/600000 = 0.000145 km

Each km is 10^5 cm, so this is ...

  (0.000145 km)(10^5 cm/km) = 14.5 cm

Answer:

 90°

Step-by-step explanation:

∆GFD is an isosceles right triangle, so angle FDG is 45°. Segment DF bisects angle EDG, so that angle is 90°.

Arc AG is the other half of the semicircle AGE that includes 90° arc GE.

So, arc AG is 90°.

__

Comment on the problem

"a" and "b" are irrelevant to arc AG. They come into play for arc CE.

Answer:

x+ 4x-85 = 90

Step-by-step explanation:

The two angles are complementary so they add to 90 degrees

x+ 4x-85 = 90

Combine like terms

5x - 85 = 90

Add 85 to each side

5x = 175

Divide by 5

5x/5 =175/5

x =35

Answer:

x (4-85)  =  -81x

Step-by-step explanation:

Equation: x (4-85)

Answer: x (4-85)

1: Find the missing side

2: add the other numbers

Hope this helps.

Answer:

Step-by-step explanation:

To find the normal plane and osculating plane, we first need to find the required derivatives.

x = 5t, y = t^2, z = t^3

dx/dt = 5, dy/dt = 2t, dz/dt = 3t^2

So, the velocity vector v and acceleration vector a are:

v = <5, 2t, 3t^2>

a = <0, 2, 6t>

Now, let's evaluate them at t = 1 since the point (5, 1, 1) is given.

v(1) = <5, 2, 3>

a(1) = <0, 2, 6>

The normal vector N is the unit vector in the direction of a:

N = a/|a| = <0, 1/√10, 3/√10>

Using the point-normal form of the equation for a plane:

normal plane equation = 0(x-5) + 1/√10(y-1) + 3/√10(z-1) = 0

Simplifying this equation we get:

5x + 2y + 3z = 30

The osculating plane can be found using the formula:

osculating plane equation = r(t) · [(r(t) x r''(t))] = 0

where r(t) is the position vector, and x is the cross product.

At t = 1, the position vector r(1) is <5, 1, 1>, v(1) is <5, 2, 3>, and a(1) is <0, 2, 6>.

r(1) x v(1) = <-1, 22, -5>

r(1) x a(1) = <12, -6, -10>

v(1) x a(1) = <-12, 0, 10>

Substituting these values into the formula, we get:

osculating plane equation = (x-5, y-1, z-1) · <12, -6, -10> = 0

Simplifying this equation we get:

3x - 15y + 5z = 5

Therefore, the equations for the normal plane and osculating plane at (5, 1, 1) are:

(a) 5x + 2y + 3z = 30

(b) 3x - 15y + 5z = 5

Here's a possible implementation of the DivideByThree function in C:

int DivideByThree(int number) {

   int count = 0;

   while (number > 0) {

       if (number % 10 == 3) {

           count++;

       }

       number /= 10;

   }

   return count;

}

This function takes an integer number as input and returns the quotient of the division by 3 by counting how many times the number 3 appears in the original number. The function works as follows:

Initialize a counter variable count to 0.

While number is greater than 0, do the following:

a. If the last digit of number is 3 (i.e., number % 10 == 3), increment count.

b. Divide number by 10 to remove the last digit.

Return the final value of count.

For example, if we call DivideByThree(123456333), the function will count three occurrences of the digit 3 in the input number and return the value 1. If we call DivideByThree(33333), the function will count five occurrences of the digit 3 and return the value 1. If there are no occurrences of the digit 3 in the input number, the function will return 0.

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If there are 60 apples in total, then green are 15 .

Given:

in a basket of red and green apples, green apples are only 1/3 as common as red apples.

if there are 60 apples in total, how many are green = ?

x is the number of red apples

y is the number of green apples

x/3= y;

x=3y

x+y= 60

3y+y=60;

4y=60;

that means y=60/4

y = 15

Hence there are 15 green apples.

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Answer:

Step-by-step explanation:

\(\frac{cos A}{cos B} =\frac{\frac{AC}{AB} }{\frac{BC}{AB} } =\frac{AC}{AB} \times \frac{AB}{BC} =\frac{AC}{BC} =\frac{3}{3} =1\)

The value of cosA divided by cosB is equal to 1.

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are numerous distinctive trigonometric identities that relate to a triangle's side length and angle.

It is given that in the right-angle triangle ABC the three sides are AB = 4.24, BC = 3 and AC = 3.

The value of cosine is the ratio of the base of the right-angle triangle and the hypotenuse of the right-angle triangle.

The value of cosA is calculated as below:-

cosA = 4.24 / 3

The value of cosB is calculated as below:-

cosB = 4.24 / 3

Calculating the ratio of cosA and cosB.

cosA / cosB =  [ 4.24 / 3 ] ÷ [ 4.24 / 3 ]

cosA / cosB = 1

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For the matrix the true statement is given by option d. Both A and B are false.

Let's analyze each statement of the matrix as follow,

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R⁵.

This statement is false.

The domain of the transformation T is not R⁵.

The domain of T is determined by the dimensionality of the vectors x that can be input into the transformation.

Here, the matrix A is a 3 times 5 matrix, which means the transformation T(x) = Ax can only accept vectors x that have 5 elements.

Therefore, the domain of T is R⁵, but rather a subspace of R⁵.

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto.

This statement is also false.

The transformation x → Ax can still be onto (surjective) even if A is a 3 times 2 matrix.

The surjectivity of a transformation depends on the rank of the matrix A and the dimensionality of the vector space it maps to.

It is possible for a 3 times 2 matrix to have a rank of 2,

and if the codomain is a vector space of dimension 3 or higher, then the transformation can be onto.

Therefore, as per the matrix both statements are false, the correct answer is d. Both A and B are false.

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The above question is incomplete, the complete question is:

Which of the following best characterizes the following statements:

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R^5

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto

a. Only A is true

b. Only B is true

c. Both A and B are true

d. Both A and B are false

Answer:

D

Step-by-step explanation:

They reason is because it makes sense. Do some more research and you will understand