please help! ill give brainlyest! solve the absolute value equation

Answer:

Hi,

6

Step-by-step explanation:

the number divided by 5 has a remainder of 1 , its last digit is 1 or 6.

the number is divisible by 2, its last digit is 0 or 2,or 4, or 6 or 8.

Both conditions give : the last digit must be 6.

Answer:

5 movies

Step-by-step explanation:

90-30=60

60/12=5

Answer:

90 minus 12x is greater than or equal to 30

then solve and get x equals 5

The annual net income and annual yield are $3400 and 2.335 respectively

a) To find the annual net income, we need to subtract the annual expenses from the annual rental income. The annual rental income can be calculated as follows:

$3,875 * 6 months = $23,250

The annual net income would be:

$23,250 - $19,850 = $3,400

b) The annual yield can be calculated as the annual net income divided by the total cost of the property, including the down payment:

$3,400 / ($185,900 - $40,000) = 0.023 or 2.33%

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Answer:

The fourth graph

Step-by-step explanation:

X is increasing and Y is decreasing. The only graph that shows that is graph 4.

Answer:

The 4th graph

Step-by-step explanation:

Look for the most reasonable answer for the change in y and x. We can see that as x steadily increases, y steadily decreases. The only graph representing our scenario is the 4th graph, the graph where the line goes down to the lower-right direction.

Annabeth's bi-weekly gross earnings, including overtime compensation, would be $1,097.56.

Amount is a term used to describe a quantity or size of something. It is used to refer to a number of objects, items, or people, as well as a measure of money, time, or distance. Amount is also used to describe the total sum of money that is owed, received, or spent.

This amount is calculated by multiplying her hourly rate of $21.84 (which is determined by dividing her bi-weekly gross earnings of $913.45 by 40 hours) by 47 hours, which is the total number of hours worked in the week. Then, her overtime compensation of 7 hours is multiplied by her hourly rate of $21.84 multiplied by 1.5, which is the rate for time-and-a-half. The sum of these two amounts is her bi-weekly gross earnings with overtime, which is $1,097.56.

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Answer:

volume of the pramind is 90332 ans And like

First, we make the denominators of 1/4 and 3/8 the same as the LCM (= 8)

-> 1/4 = 1 x 2 / 4 x 2 = 2/8
-> 1 - ... = 2/8 + 3/8 = 5/8

The missing fraction = 1 - 5/8 = 3/8.

Given that random sample of 25 values is drawn from a mound-shaped and symmetrical distribution. The sample mean is 10 and the sample standard deviation is 2. H0 (null hypothesis) is accepted.

we can infer that -

95 % CI for mean  9.1744 to 10.8256

Since p >0.05 accept null hypothesis.

standard deviation sigma not known.  df = 24

H0:  x bar = 9.5

Ha: x bar not equals 9.5

t-statistic  1.250

P = 0.2234

We fail to reject null hypothesis

There is no statistical evidence at 5% level to fail to reject H0

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Answer:

Richard spent $14.

Step-by-step explanation:

I’m assuming the question is to find how much Richard spent.

Jordan spent $ 12

Total of the bill is $26

So $26 -$12 = $14.

Step-by-step explanation:

\(405 \times 405 = \sqrt{164025} \)

The value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

(1). angle B = 180 - (22 + 90) {sum of interior angles of a triangle}

angle B = 68°

Given that the triangle ∆ABC is similar to the triangle ∆PQR.

(2). PQ/7.5cm = 12cm/18cm

PQ = (12cm × 7.5cm)/18cm {cross multiplication}

PQ = 5cm

(3). 13cm/BC = 12cm/18cm

BC = (13cm × 18cm)/12cm {cross multiplication}

BC = 19.5cm

(4). area of ∆PQR = 1/2 × 12cm × 5cm

area of ∆PQR = 6cm × 5cm

area of ∆PQR = 30cm²

Therefore, the value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

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Answer:

The smallest possible value of Pr{X = 3} is  U = 0

Step-by-step explanation:

  The number of trial is  n = 3

  The mean is  E(X) = 1.8

Gnerally given that every probability value lies between 0  and 1 ,

let U be the smallest possible value of  Pr{X = 3}

it then mean that U= 0 because in the range which probability values can take , the smallest value is  zero

So

     The smallest possible value of Pr{X = 3} is  U = 0

Given:

Required:

To find the limit value of the given function.

Explanation:

Cancel out the same terms from the numerator and denominator.

Now apply the limit.

Final Answer:

The limit value of the given function is

The particular solution to the given nth order linear differential equation is \(y_p_(_x_) = 2e^(^1^0^x^)cos(x) + 5e^(^1^0^x^)sin(x) + C.\)

To find the particular solution of the given nth order linear differential equation L[y(x)] = cos(x) + 6x, we used the method of undetermined coefficients. We were given three conditions: L[y1(x)] = 8x when y1(x) = 56x, L[y2(x)] = 5sin(x) when y2(x) = 45, and L[y3(x)] = 5cos(x) when y3(x) = 25cos(x) + 50sin(x).

Assuming the particular solution has the form \(y_p_(_x_)\)= A cos(x) + B sin(x), we substituted it into the differential equation and applied the linear operator L. By matching the coefficients of cos(x), sin(x), and x, we obtained three equations.

From L[y1(x)] = 8x, we equated the coefficients of x and found A = 8. From L[y2(x)] = 5sin(x), the coefficient of sin(x) gave \(B^2\)= 5. From L[y3(x)] = 5cos(x), the coefficient of cos(x) gave\(A^3\)(1 - sin(x)cos(x)) = 5.

Solving these equations, we determined A = 2. Substituting A = 2 into the equation \(A^3\)(1 - sin(x)cos(x)) = 5, we simplified it to 8sin(x)cos(x) = 3. Then, using the identity sin(2x) = 2sin(x)cos(x), we found sin(2x) = 3/4.

To solve for x, we took the inverse sine of both sides, resulting in 2x = arcsin(3/4). Therefore, x = (1/2)arcsin(3/4).

Finally, we obtained the particular solution as \(y_p_(_x_) = 2e^(^1^0^x^)cos(x) + 5e^(^1^0^x^)sin(x) + C.\), where C is an arbitrary constant.

In summary, by matching the terms on the right-hand side with the corresponding terms in the differential equation and solving the resulting equations.

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The question probable may be:

Let LY) = an any\n)(x) + an - 1 y(n − 1)(x) + ... + a1 y'(x) + a0 y(x) where ao, aj, ..., an are fixed constants. Consider the nth order linear differential equation LY) 4e10x cos x + 6xe10x Suppose that it is known that L[yi(x)] = 8xe 10x when yı(x) = 56xe10x L[y2(x)] = 5e10x sin x when y2(x) 45e L[y3(x)] = 5e10x cos x when y3(x) 25e10x cos x + 50e 10x sin x e10x COS X Find a particular solution to (*).

The 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

To construct an 80% confidence interval estimate of the average browsing time for the population of crownfashion.com visitors this week, we can use the following formula:

Confidence Interval = \(\bar{X}\) ± Z \(\times\)  (σ/√n)

Where:

\(\bar{X}\) is the sample mean (average browsing time) = 13.6 minutes,

Z is the Z-score corresponding to the desired confidence level (80% confidence level corresponds to a Z-score of 1.28),

σ is the population standard deviation = 5.2 minutes,

n is the sample size = 49.

Plugging in these values, we can calculate the confidence interval as follows:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/√49)

Simplifying the expression:

Confidence Interval = 13.6 ± 1.28 \(\times\) (5.2/7)

Confidence Interval = 13.6 ± 1.28 \(\times\) 0.742857

Confidence Interval = 13.6 ± 0.951428

The lower bound of the confidence interval is 13.6 - 0.951428 = 12.648572, and the upper bound is 13.6 + 0.951428 = 14.548572.

Therefore, the 80% confidence interval estimate for the average browsing time is approximately 12.648572 minutes to 14.548572 minutes.

The margin of error indicated by the interval is half of the width of the confidence interval, which is (14.548572 - 12.648572) / 2 = 0.95 minutes.

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The function is increasing over the interval (-3,-1).

A table with x and f(x) values are given as:

x         f(x)

-6         34

-5          3

-4        -10

-3         -11

-2         -6

-1           -1

0           -2

1            -15

We have to check whether this function is increasing or not in the intervals  (–6, –3), (–3, –1), (–3, 0), (–6, –5).

A function is said to be increasing over an interval (x, y), if for x < y, it follows that f(x) < f(y).

Consider the intervals one-by-one.

For (-6, -3), we have the function values in between which are  34 > 3 > -10 > -11. So in this interval the function is not increasing but decreasing over the x-values in (-6, -3).

For (-3, -1), the corresponding function values are -11 < -6 < -1. Here the function values are increasing over the x-values in the interval (-3, -1).

For (-3,0), the corresponding function values are -11 < -6 < -1 >-2. Since we got -1 > -2 in the interval (-3,0), the function is not increasing here also.

For (-6,-5), the corresponding function values are 34 > 3. So the function is not increasing but decreasing.

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The function f(x) = arcsin(\(x^2\)- 2x) is increasing for x > 1. To determine where the function f(x) = arcsin(\(x^2\) - 2x) is increasing, we need to find the intervals where its derivative, f'(x), is positive.

First, find the derivative of the inner function, g(x) = \(x^2\) - 2x:
g'(x) = 2x - 2
Now, find the derivative of the outer function, h(u) = arcsin(u), where u = g(x):
h'(u) = 1/√(1 - \(u^2\))
Using the chain rule, the derivative of f(x) is the product of the derivatives of the inner and outer functions:
f'(x) = h'(g(x)) * g'(x) = (1/√(1 - \((x^2 - 2x)^2)\)) * (2x - 2)
To find where f(x) is increasing, we need to determine where f'(x) > 0. Since the denominator of the fraction is always positive, we only need to focus on the numerator:
2x - 2 > 0
Solving for x, we get:
x > 1

The complete question is:-

Determine where f(x) = arcsin (\(x^{2}\) − 2x) is increasing.

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83% of pupils passed the test as a group.

An equation in which two ratios are made equal is known as a percentage. As an illustration, you could express the ratio as 1: 3 if there is 1 guy and 3 girls (for every one boy there are 3 girls)

It is claimed that two ratios are in proportion if they are the same. A/B Equals C/D if the four elements are a, b, c, and d in that order. The terms a and d are referred to as extremes, whereas b and c are referred to as medium terms. The ratio equates the product of extremes to the product of means.

Results in total: 65% of the review was finished.

The desired results were 55% exam pass.

The percentage is as follows:

p = 55/65 x 100%

  = 82.3%.

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Answer:

25h + 12

Explanation:

21h -10h + 14h + 16 -9 +5  ( group term )

25h + 12                             ( simplified )

Answer:

\(25h+12\)

Step-by-step explanation:

To do this, we need to combine like terms:

\(21h-10h+14h+16-9+5\)

Combine terms that have "h" with each other.

\(11h+14h+16-9+5\)

\(25h+16-9+5\)

Now, combine the rest of the terms that don't have "h".

\(25h+7+5\)

\(25h+12\)

Answer:

23,247 us liquid gallons

Answer:

23.25 Gallons

Step-by-step explanation:

3.8 liters are in one gallon so if you were to convert them, you would have to divide the liters by how many liters it takes to convert into a gallon,

So the answer is 23.25 G

Hope this helps! :)

a) The relationship between b and c is that c cannot be zero.

b) b can be any nonzero constant and c is equal to 2.5 in this case.

In two dimensions, the compatibility equations for strain are,0

∂εx/∂y + ∂γxy/∂x = 0

∂εy/∂x + ∂γxy/∂y = 0

where εx and εy are the normal strains in the x and y directions, respectively, and γxy is the shear strain.

Using the given strain field, we can calculate the strains,

εx = -4.5cx² + 10.5cy

εy = 1.5cx² - 7.5cy²

γxy = 1.5bxy

Taking partial derivatives and plugging them into the compatibility equations, we get,

⇒ -9cx + 0 = 0

⇒ 0 + (-15cy) = 0

These equations must be satisfied for the strain field to be compatible. From the first equation,

We get cx = 0, which means c cannot be zero.

From the second equation, we get cy = 0,

Which means b can be any nonzero constant.

For part b:

We are asked to find the displacements u and v corresponding to the given strain field at points (3, 7), assuming they are zero at point (0, 0) and using c = 2.5.

To find the displacement components,

We need to integrate the strains with respect to x and y. We get,

u = ∫∫εx dx dy = ∫(10.5cy) dy = 5.25cy²

v = ∫∫εy dx dy = ∫(1.5cx² ) dx - ∫(7.5cy²) dy = 0.5cx³ - 2.5cy³

Plugging in the values of c and b, we get,

u = 5.25(2.5)(7)²  = 767.62

v = 0.5(2.5)(3)³ - 2.5(7)³ = -8583.75

Therefore,

The displacements at points (3, 7) are u = 767.62 and v = -8583.75.

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Using strong induction, we can prove that the square root of -2 is irrational by showing that it cannot be expressed as a fraction of coprime odd integers.

To prove that √-2 is irrational using strong induction, we need to show that for any natural number n, if the square root of -2 can be expressed as a fraction a/b, where a and b are coprime integers, then a and b must be odd.

We can start by using the base case, n = 1. Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers.

Now, let's assume that for all n ≤ k, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. We want to prove that this also holds for n = k+1.

Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers with a and b odd. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd.

By strong induction, we have proven that for any natural number n, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Therefore, √-2 is irrational.

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Answer:

C. 80 square centimeters

Step-by-step explanation:

Edge 2021

The lateral surface area of the given square pyramid is 80 cm².

The lateral surface of an object is its entirety, excluding its base and top (when they exist).

Boundary - layer surface zone equals lateral surface area. This is to be contrasted from the total surface area, which includes the lateral surface area along with the base and top regions.

Given that, a square pyramid has side lengths each measuring 8 centimeters.

The height of the pyramid is 3 centimeters.

The lateral area of a square pyramid = 2al = 2a√[(a²/4) + h²]

= 2×8√[(8²/4) + 3²]

= 16√[(64/4) + 9]

= 16√[16 + 9]

= 16×5

= 80 cm²

Therefore, the lateral area of the pyramid is 80 cm².

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The one-sample chi-square test is used to determine whether the distribution of a single categorical variable significantly differs from what would be expected by chance. The statement is True.

The one-sample chi-square test is a statistical test used to determine if there is a significant difference between the observed frequency and the expected frequency in a single categorical variable. It compares the observed frequency distribution of a variable to the expected frequency distribution, assuming that the null hypothesis is true.

This test compares observed frequencies to expected frequencies and calculates a chi-square statistic to assess the significance of the difference.

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In a pin-hole camera model, the three-dimensional (3D) points P, Q, and R in the scene correspond to their respective two-dimensional (2D) image points p, q, and r on the camera's image plane.

Given the coordinates of these points in the 3D scene and their corresponding image points, along with the focal length, pixel size, and image size, we can calculate various parameters. The image coordinate center is at the center pixel with indices (500,500).

For the stereo camera system, the second camera is placed parallel to the first one, with its lens center at C=(10,0,0) in the 3D scene. To find the disparity of point P in the second camera, we need to determine the difference in its image position compared to the first camera. Disparity is the horizontal shift between corresponding points in the two images. By calculating the difference in the x-coordinate of point P's image position in the two cameras, we can find the disparity.

To determine the 3D coordinates (X, Y, Z) of point V in the scene, given its image coordinates in both cameras, we can use triangulation. Triangulation involves finding the intersection point of two rays, each originating from the camera center and passing through the respective image point. By considering the known parameters of the cameras, we can compute the 3D coordinates of point V using its image coordinates in both cameras.

For the stereo camera system, the disparity of point P can be found by calculating the difference in its image position between the two cameras. To determine the 3D coordinates of point V, we can use triangulation by considering the image coordinates in both cameras along with the known camera parameters.

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The calculation of image disparity in the second camera and coordinates of a point in 3D scene involves concepts of geometry and trigonometry. The coordinates can be computed using formulas derived from rules of similar triangles.

The given question involves the operations of a pin-hole camera and a stereo camera system. The process of imaging and finding disparities in the cameras with different lens centers is a part of computer vision in Robotics. For the first part of the question where we need to find the disparity of a certain point P, Q, and R in the second camera, the disparity can be computed using geometry and trigonometry. It entails looking at how the image's position changes when moving from one camera to another.

For the second part, where we need to find the coordinates of a point V in 3D scene. The coordinates of point V can be obtained from the disparity between two locations of point V from the first and the second camera. Using similar triangles, we can compute the coordinates as:

X = Z * (x1 - x2) / (f * pixel size)

Y = Z * (y1 - y2) / (f * pixel size)

Z = f * Base line / ((x1 - x2) * pixel size)

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Mia can create a scale drawing of a football field using a scale of 1:1,000. The scale drawing will provide a Visual representation of the field, allowing for easier analysis and planning.

To create a scale drawing of a football field using a scale of 1:1,000, Mia can follow these steps:

1. Determine the dimensions: The football field's dimensions are given as 120 yards by 53 1/3 yards. Convert the fractional measurement to a decimal for simplicity. In this case, 1/3 yard is approximately 0.333 yards.

2. Decide on the units: Since the scale is 1:1,000, Mia needs to determine the unit of measurement she will use in her scale drawing. For consistency, she can choose to use feet as the unit.

3. Calculate the scaled dimensions: To create the scale drawing, Mia needs to scale down the dimensions of the football field. Since the scale is 1:1,000, she can divide the actual dimensions by 1,000 to obtain the scaled dimensions. The scaled dimensions would be 120 yards / 1,000 = 0.12 yards (or 0.36 feet) for the length and 53.333 yards / 1,000 = 0.053333 yards (or 0.16 feet) for the width.

4. Draw the scaled football field: Using a ruler and a grid paper, Mia can draw a rectangle with dimensions of 0.12 feet by 0.053333 feet (or inches, depending on the size of the grid paper). She can label the sides of the rectangle with the corresponding measurements in feet.

5. Add additional markings: Mia can add other markings to the scale drawing, such as the goal posts, yard markers, and any other important features of the football field. She can refer to the actual measurements and proportions of these elements to ensure accuracy.

By following these steps, Mia can create a scale drawing of a football field using a scale of 1:1,000. The scale drawing will provide a visual representation of the field, allowing for easier analysis and planning.

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Answer:

y=2

Step-by-step explanation:

Hey there!

The answer is y=2 because the x-axis is not defined (there's no value for it as the line didn't pass through it)

The value of the (f⁻¹)'(1) = -3/4.


To find (f⁻¹)'(1), we use the chain rule. The chain rule states that, for a function y = f(g(x)), then y' = f'(g(x))*g'(x). In our case, y is f⁻¹ and g is f.

Therefore,
(f⁻¹)'(1) = f'(f⁻¹(1)) * (f⁻¹)'(1). We are given

f(-3) = 1, f(1) = -4, f'(-3) = 4, and f'(-4) = -3.

Therefore, we can solve for (f⁻¹)'(1). We start by solving for f⁻¹(1). We know that f(1) = -4, so f⁻¹(1) = -4.

Plugging this into our equation, we get (f⁻¹)'(1) = f'(-4)*(f⁻¹)'(1).

We are given f'(-4) = -3,

so (f⁻¹)'(1) = (-3)*(f⁻¹)'(1).

Solving this equation, we get (f⁻¹)'(1) = -3/4.

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Answer:

2

Step-by-step explanation:

Mode means the number in an array that is the most common. The most common number (mode) in this array is 2, with 3 entries.