Please help i dont understand how to do this, and if you answer please show your work for it
Calculate the mass of (the ^ means exponent)
7.06 x 10^23 He atoms
1.07 x 10^23 Mg atoms
4.06 x 10^22 molecules of O2
8.19 x 10^24 molecules CO
Calculate the volume of
2800 g of C6H1206
45 moles of H2O
9.2 grams of Fe
2.8 x 10^26 particles of Al2O3
5.6 moles of H2SO3
Answers
The Avogadro's number is used to obtain the required results as;
1) 4.69 g
2) 4.26 g
3) 2.158 g
4) 381 g
5) 348.5 L
6) 1008 L
7) 3.6 L
8) 4.7 * 10^4 g
9) 112 L
What is the Avogadro’s number?The Avogadro’s number could be used to deduce the amount of substance. Let us recall that in the theory of Professor Avogadro, the mole is the number of elementary entities of a substance. In this case these elementary entities is a reference to the atoms, molecules and ions that could be found in the substance. With that in mind, we shall now carry out the calculations.
1) 6.02 * 10^23 atoms of helium has a mass of 4g
7.06 x 10^23 He atoms of He has a mass of 4.69 g
2) 6.02 * 10^23 atoms of Mg has a mass of 24 g
1.07 x 10^23 Mg atoms has a mass of 4.26 g
3) 6.02 * 10^23 molecules of O2 has a mass of 32 g/mol
4.06 x 10^22 molecules of O2 has a mass of 2.158 g
4) 6.02 * 10^23 molecules of CO has a mass of 28 g
8.19 x 10^24 molecules CO has a mass of 381 g
5) Number of moles = 2800g/180 g/mol = 15.56 moles
Given that 1 mole occupies 22.4 L
15.56 moles occupies 348.5 L
6) Given that 1 mole occupies 22.4 L
45 moles occupies 1008 L
7) Number of moles of Fe = 9.2 g/56 = 0.16 moles
Given that 1 mole occupies 22.4 L
0.16 moles occupies 3.6 L
8) 6.02 * 10^23 particles have a mass of 102 g
2.8 x 10^26 particles have a mass of 4.7 * 10^4 g
9) Given that 1 mole occupies 22.4 L
5 moles of the acid occupies 112 L
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Related Questions
Explain why understanding the process of combustion requires using an atomic model of mass and not a continuous one.
Answers
Answer:
Combustion is a rapid exothermic chemical reaction between oxygen, O₂, and a substance which is known as the fuel that is initiated by an ignition (heat) source to produce carbon dioxide and water vapor other oxides and combustion products
With the continuous model, which is the model seen with the naked eye, that have uniform parts, the combustion of coal that produces no flammable vapors and hence no flame, the combustion of hydrogen gas which is nearly colorless and the combustion of gasoline that produces a bright flame, burns without flame will be taken as different processes
Explanation:
Cast iron is a popular metal for several cooking needs, both vegetables and meats across culinary traditions. One material science question that engineers designing more efficient cookware might ask is how to ensure an optimal, balanced heat transfer. In order to see what they are trying to improve upon,
consider a pan that has a thickness of 0.125 inches and a radius of 5 inches. What is the heat transfer rate for each increase in 1 degree Celsius?
Note that the heat transfer rate Q is found by using the material’s thermal conductance (W/ mK or BTU / s-ft -°F) k, the area of the surface the heat flows through A, the thickness of the material L, and the temperature difference ∆.
Q=kA( ∆/L)
Answers
The heat transfer rate for each degree Celsius rise is 32656 J.
Do you define the term heat transfer coefficient?Heat is transferred between materials in direct physical contact through a process called conduction that involves molecular collisions. A material's thermal conductivity, cross-sectional area, and temperature differential are all directly related to its heat transfer rate. Varies inversely with material thickness. To the question asked:
The heat transfer coefficient Q is:
Q=kA(ΔT/L)
among them,
k = thermal conductivity of material - 52 (W/m K)
Area of the surface of heat flow A:
A = πr²
= 3.14*5*5
A = 78.5 square inches
Temperature difference ΔT = 1 degree Celsius.
Material thickness L = 0.125 inch
set the value.
Q=kA(ΔT/L)
Q = 52*78.5 (1/0.125)
Q = 32656 J
Therefore, the heat transfer coefficient is 32656 J for each degree Celsius increase.
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With every increase in degree Celsius, there is a 32656 J heat transfer cofficient.
What does the term "heat transfer coefficient" means?Via a process called conduction, which involves molecular collisions, heat is transported between materials that are in direct physical touch. The rate of heat transmission through a material depends on its thermal conductivity, cross-sectional area, and temperature differential. inversely relates to material thickness. To the query posed:
The heat transfer coefficient Q is:
Q=kA(ΔT/L)
According to the given data:k = the thermal conductivity of material - 52 (W/m K)
Area of the surface of heat flow A:
A = πr²
= 3.14*5*5
A = 78.5 square inches
Temperature difference ΔT = 1 degree Celsius.
Material thickness L = 0.125 inch
set the value.
Q=kA(ΔT/L)
Q = 52*78.5 (1/0.125)
Q = 32656 J
Therefore, the heat transfer coefficient is 32656 J for each degree Celsius increase.
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Phosphorus burns in presence of chlorine to form phosphorus penta chloride.
Answers
Phosphorus burns in presence of chlorine to form phosphorus penta chloride. The balanced chemical equation for the reaction is given below:
\(\rm 2P + 5Cl_{2} \rightarrow 2PCl_{5}\)
What is phosphorous pentachloride?The chemical compound having the formula PCl₅ is called phosphorus pentachloride. Together with PCl₃ and POCl₃, it is one of the most significant phosphorus chlorides. As a chlorinating agent, PCl₅ is employed.
Although commercial samples can be yellow and tainted with hydrogen chloride, it is a colorless, water-sensitive, and moisture-sensitive solid. The phosphorus chloride structures are always consistent with the VSEPR theory.
The environment has an impact on PCl₅'s structural makeup. A neutral molecule with trigonal bipyramidal geometry and (D₃h) symmetry, PCl₅ is gaseous and molten.
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Your question is incomplete. But your complete question probably was:
Phosphorus burns in presence of chlorine to form phosphorus penta chloride. Write the balanced equation for the reaction.
please help thank you
Answers
The following reaction is second-order in A and first-order in B: 2A+B→A
2
B What is the reaction rate if k=2.55M
−2
s
−1
and [A]=0.30M[B]=1.10M ? Hint: Write down the correct differential rate law based on the order with respect to A and B, then plug in the concentrations and k to calculate rate (R). Your Answer: Answer units Question 3 ( 5 points) If the rate constant of a reaction is 5.8×10
−3
s
−1
, what is the concentration after 30 seconds if the initial concentration was 5.0M ? Hint: What is the order of the reaction given the units of the rate constant?
Answers
The values of k = 2.55 M^(-2) s^(-1), [A] = 0.30 M, and [B] = 1.10 M, the reaction rate is approximately 1.320 M/s.
The rate law for the given reaction is expressed as rate = k[A]^2[B], where k is the rate constant, [A] is the concentration of A, and [B] is the concentration of B.
Given:
k = 2.55 M^(-2) s^(-1)
[A] = 0.30 M
[B] = 1.10 M
Plugging in the values into the rate law equation, we have:
rate = (2.55 M^(-2) s^(-1))(0.30 M)^2(1.10 M)
Calculating this expression, we find that the reaction rate is approximately 1.320 M/s.
Therefore, with the given concentrations and rate constant, the reaction is proceeding at a rate of approximately 1.320 M/s.
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a. Rub the magnet along the nail or knitting needle. Now try picking up the paper clip or tack. Could your nail pick it up? How many can it pick up at once?
b. Now try to make your magnet stronger by rubbing the magnet along the nail or knitting needle for a longer time. Rub only in one direction, not back and forth. This will increase the number of atoms that line up with the magnet. Try to pick up paper clips or thumbtacks. How many can it pick up now?
Answers
Answer:
ight i'll answer both rq
Explanation:
a. Rub the magnet along the nail or knitting needle. Now try picking up the paper clip or
tack. Could your nail pick it up? How many can it pick up at once?
after rubbing the magnet with the nail, it could pick up 7 small paper clips.
b. Now try to make your magnet stronger by rubbing the magnet along the nail or knitting
needle for a longer time. Rub only in one direction, not back and forth. This will increase
the number of atoms that line up with the magnet. Try to pick up paper clips or
thumbtacks. How many can it pick up now?
after rubbing it a second time but for a longer period, it could pick up around 10, almost lifting the 11th.
Answer:
A. After rubbing the magnet with the nail, it could pick up 7 small paper clips.
B. After rubbing it a second time but for a longer period, it could pick up around 10 small paper clips, almost lifting the 11th one.
What is the density of a salt solution if 75.0 ml of the solution has a mass of 32.0 g?
Answers
Answer:
0.43 g/ml
Explanation: Density is d = M/V, where d is density, M is mass, and V is volume: therefore d= 32 g/75ml = 0.4266 = 0.43 g/ml
1. Which of the following factors does not affect the voltage produced in a voltaic cell?
A. concentrations of lons
B. pressure
C. metal of the electrodes
Answers
The voltage is the potential difference between the two ends of the conductor. The factor that does not affect the voltage produced in a voltaic cell is pressure. The correct option is B.
What is a Voltaic cell?A voltaic cell uses a chemical reaction to convert electrochemical energy to electrical energy. It consists of cathode and ions which flow through the cathode and anode.
The pressure has nothing to do with the Electrochemical devices.
The factor does not influence the voltage produced in a voltaic cell is pressure. The correct option is B.
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salt plus water. two compounds mixed together to form a solution. The water is the solvent; the salt is the solution. students have been tasked with separating the two compound from solution.
Answers
Answer:
Evaporation
Explanation:
Students are to mix the solvent to dilute completely,and get and evaporation dish,candle(heat),tripod stand...pour the solution in the evaporation dish and place it on tripod stand above the candle wait for some time the water will change into gas and to get the water they have to cover the evaporating and direct it to a different container to get the water and salt
During a titration, 40. 0 ml of 0. 25M NaOH were required to neutralize 50. 0ml of HCI. What's the concentration of the HCI solution?
Answers
The concentration of the HCI solution is 0.20M.
During a titration, the concentration of one solution is used to determine the concentration of another solution. The equation for this is:
M1V1 = M2V2
Where M1 is the concentration of the first solution, V1 is the volume of the first solution, M2 is the concentration of the second solution, and V2 is the volume of the second solution.
In this case, we are given the volume and concentration of the NaOH solution (V1 and M1) and the volume of the HCI solution (V2), and we are asked to find the concentration of the HCI solution (M2).
Plugging in the given values into the equation, we get:
(0.25M)(40.0ml) = (M2)(50.0ml)
Solving for M2, we get:
M2 = (0.25M)(40.0ml) / (50.0ml)
M2 = 0.20M
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How many moles of hydrochloric acid does
1.505x10^24 atoms of hydrochloric acid make?
Answers
Answer:
2.499 mol HCl
General Formulas and Concepts:
Chemistry - Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:
Step 1: Define
1.505 × 10²⁴ atoms HCl (Hydrochloric acid)
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
\(1.505 \cdot 10^{24} \ atoms \ HCl(\frac{1 \ mol \ HCl}{6.022 \cdot 10^{23} \ atoms \ HCl} )\) = 2.49917 mol HCl
Step 4: Check
We are given 4 sig figs. Follow sig fig rules and round.
2.49917 mol HCl ≈ 2.499 mol HCl
The specific heat capacity of water is 1.00 cal/g °C. 700.00 cal is required to raise the temperature of 25.0g water from 22.0°C to 50°C.
What is the final temperature of the above water sample if 1.00kcal of heat is provided?
Answers
When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.
What does "specific heat" mean?The amount of energy required to raise a substance's temperature is measured in terms of specific heat. It is the amount of energy (measured in joules) required to increase a substance's temperature by one degree Celsius per gram.
We must first determine the water sample's original temperature. The formula is as follows:
Q = mcΔT
Inputting the values provided yields:
700.00 cal = 25.0 g x 1.00 cal/g °C x (50°C - 22.0°C)
When we simplify this equation, we obtain:
ΔT = 700.00 cal / (25.0 g x 1.00 cal/g °C) = 28.0°C
Therefore, the initial temperature of the water sample is 22.0°C + 28.0°C = 50.0°C.
Inputting the values provided yields:
1.00 kcal = 25.0 g x 1.00 cal/g °C x (T - 50.0°C)
When we simplify this equation, we obtain:
T - 50.0°C = 1.00 kcal / (25.0 g x 1.00 cal/g °C) = 40.0°C
Therefore, When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.
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Question 14 PM2.5 is defined as ________
- the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air greater than or equal to 2.5 micrometers in diameter. Question 15 Carbon dioxide (CO2) is a criteria air pollutant. - True - False Question 16 Roughly percent of emissions of carbon monoxide in Santa Clara County come from mobile sources (select the choice closest to the correct answer). - 50 - 75 - 25 Question 17
The term "photochemical smog" is most synonymous with which of the following criteria air pollutants? - lead (Pb) - carbon monoxide (CO) - sulfur dioxide ( SO2) - ozone (O3) Question 18 "Attainment" of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards. - True - False
Answers
: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.
Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.
Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.
Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.
Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.
Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.
Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.
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What has 1 silicon atom surrounded by 4 oxygen atoms?
Answers
Silicon Oxide would probably be it.
15.90g of sodium chloride solution was made to react with 12.10g of lead
trioxonitrate (V) to produce white precipitate of lead chloride solution and
8.40g of sodium trioxonitrate (V). Determine the mass of the white
precipitate of lead chloride and show that this reaction can be used to verify
the law of conservation of matter.
Answers
The two main postulates that was given by Antoine Lavoisier are, oxygen play an important role in combustion and the other is mass of the reactant and product is conserved. Therefore the mass of PbCl\(_2\) is 19.6g.
What is law of conservation of mass?According to Law of conservation of mass, mass can neither be created nor be destroyed. Mass can only be transformed from one form to another. The law of conservation of mass was given by Antoine Lavoisier. Every reaction in nature follow the law given by Antoine Lavoisier that is mass is always conserved.
NaCl + Pb (NO\(_3\)) \(_2\)(aq) → PbCl\(_2\) (s) ↓ + 2 NaNO\(_3\) (aq)
Mass of NaCl =15.90 Grams
Mass of Pb (NO\(_3\)) \(_2\)=12.10grams
According to law of conservation f mass
mass of reactant = mass of product
Substituting the values we get
15.90g + 12.10g = mass of PbCl\(_2\)+ 8.40g
mass of PbCl\(_2\) =19.6g
Therefore the mass of PbCl\(_2\) is 19.6g.
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Help what is the answer?
Answers
The specific heat of mercury calculated from her data is 0.13 J/g°C.
Specific heat is a measure of how much energy is required to heat a substance. This is the amount of energy (in joules) required to heat 1 gram of a substance by 1°C. Different substances have different specific heats.
To answer this question, use the heat slaughter formula:
Q =mCΔT
In the question:
Heat energy: Q = 30.1 J
Mass of mercury: m = 12.5 g
T1 = 21.2
T2 = 39.6°C
Temperature:
ΔT = T2 –T1
∆T = 39.6 – 21.2
∆T = 18.4°C
The specific heat of mercury is?
Q =mCΔT
C = Q/mΔT
C = 30.1/12.5 x 18.4
C =30.1/230
C = 0.13 J/g°C
So, the specific heat of mercury is 0.13 J/g°C.
Question:
In the laboratory a student finds that it takes 30.1 Joules to increase the temperature of 12.5 grams of liquid mercury from 21.2 to 39.6 degrees Celsius.
The specific heat of mercury calculated from her data is_____J/g°C.
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Which of the following statements on HPLC modes is true? A. Increasing the polarity of the mobile phase decreases the elution time of polar compounds in normal-phase HPLC B. A non-polar stationary phase is used in normal-phase HPLC C. Compounds have a lower attraction to the mobile phase than to the stationary phase in displacement development D. A polar stationary phase is used in reversed-phase HPLC E. More polar compounds elute first in normal-phase HPLC
Answers
The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).
The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.
There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.
More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.
Thus, the correct option is E.
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A bar of copper (Copper = 0.385 J/g.°C) and a bar of aluminum (Aluminum = 0.897 J/g.°C) have the same mass. Which requires more energy to increase the temperature from 20°C to 30 °C?
Answers
Answer:
Aluminum
Explanation:
Which of the following appliances increase CFC's in the atmosphere?
(2 Points)
A.Refrigerators
B.Microwave ovens
C.Washing machines
D.Televisions
Answers
Answer:
Television cause it has a satellite
Write the electron configuration for the metal in group 5A and the alkali metal in period 2
Will give brainliest if answered fast :)
Answers
Answer:
metal in group 5A is bismuth
electronic configuration : 1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^6 4f^14 5d^10 6s^2 6p3
alkali metal in period 2 is lithium
1s^2 2s^ 1
Explanation:
HELP ME!!!! (1 point)
When Neils Bohr observed that unique wavelengths of light and color were released when different gases were exposed to electrical current, this led him to develop a new model of the atom that reflected what he had discovered about the location of the electrons in an atom. Which statement is most consistent with his proposed model of the atom based on these findings?
a. Electrons were able to move freely throughout the nucleus
b. Electrons were bound tightly inside the nucleus of the atom
c. Electrons were in orbits of both fixed size and energy
d. Electrons were scattered randomly throughout the atom
PERSONAL REQUEST (optional): When you place the answer please include an explanation that shows how the answer connects to the overall question. Thank you! :)
Answers
Electrons were in orbits of both fixed size and energy.
The main features of Niels Bohr's proposed atomic model are listed below.
In an atom, a positively charged nucleus is surrounded by negatively charged electrons. These electrons travel along distinct circular trajectories called orbits or shells.According to this atomic model, each of the circular routes, which have set energy levels, is referred to as an orbital shell.The integers n=1, 2, 3,... indicate the energy levels of electrons in various orbits and are referred to as quantum numbers. These numbers correspond to the shells K, L, M, and N for the integers 1, 2, and 3, respectively. Since it is nearest to the nucleus and has the lowest energy level of an electron (n=1), it is sometimes referred to as the ground state.An electron can go to a higher energy orbital shell by receiving energy (or photons), and it can move to a lower energy level or orbital shell by losing energy.To learn more about Niels Bohr's refer the link:
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a sample of nitrogen gas expands in volume from 1.7 to 5.8 l at constant temperature. calculate the work done in joules if the gas expands
Answers
The work done in joules if the gas expands is zero.
The magnitude of work done when a gas expands is equal to the product of the pressure times the change in the volume of the gas. By definition, we can say that, one joule work done is done when a force of one newton is used to move an object to one meter.
For a gas transformation at constant temperature, if the pressure p is constant then the work done is equal to ;
W= p Δv
Δv = change in volume of the gas.
Δv= 5.8L- 1.7L (Given in question)
= 4.1 L = 4.1 * 10⁻³ m³
a) When the gas expands in vacuum, the pressure is zero: p=0 atm, so the work done is zero:
W= p Δv
=(0)(4.1)
= 0 joules
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Microscopic interface asymmetry and spin-splitting of electron subbands in semiconductor quantum structures. Solid State Commun
Answers
The microscopic interface asymmetry of grown semiconductor heterostructures.
The dispersion of restricted electrons. beginning from a multiband envelope formulation we practice matrix perturbation theory to derive specific expressions. Interface asymmetry, which in the conduction band Hamiltonian appear as a warping and a spin-splitting term. The warping term consequences in an inequivalence of the dispersion.
The microscopic interface asymmetry of grown semiconductor heterostructures that gives upward thrust to heavy-light hole coupling even at 0 in-plane wave vector, modifies also the dispersion of restricted electrons. beginning from a multiband envelope method we practice matrix perturbation principle to derive explicit expressions as a result of this interface asymmetry, which inside the conduction band.
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Determine the limit of the following functions. If needed, enter
DNE, INF, or -INF.
Answers
By applying these methods, we can determine the **limit** of a function and identify if it approaches a finite value, infinity, or if it does not exist.
The limit of the following functions is determined as follows:
For each function, we evaluate the limit by analyzing the behavior of the function as the input approaches a certain value, typically denoted by 'x' or 'a'. The limit can be a finite value, positive or negative infinity (INF or -INF), or it may not exist (DNE) if the function exhibits oscillation or approaches different values from different directions.
To calculate the limit, we use various techniques such as direct substitution, factoring, rationalizing, or applying limit rules such as the limit of a sum, product, quotient, or composition of functions.
By applying these methods, we can determine the **limit** of a function and identify if it approaches a finite value, infinity, or if it does not exist.
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Amines have basic properties because of the presence of
a. a positive charge on the nitrogen atom
b. the ability of the nitrogen atom to give up hydrogen atoms
c. a sulfhydryl functional group
d. an unshared pair of electrons on the nitrogen atom
Answers
Amines have basic properties because of the presence of an unshared pair of electrons on the nitrogen atom.The correct answer is option (d).
Amines are organic compounds that contain a nitrogen atom bonded to one or more carbon atoms. The basic properties of amines are attributed to the presence of an unshared pair of electrons on the nitrogen atom. This unshared pair of electrons is available for bonding with a proton (H+) from an acid, resulting in the formation of a positively charged ammonium ion.When an amine reacts with an acid, such as hydrochloric acid (HCl), the unshared pair of electrons on the nitrogen atom accepts a proton from the acid, forming a positively charged ammonium ion.
This protonation of the amine increases its positive charge and leads to the basic nature of amines. In contrast, options a, b, and c are incorrect because they do not adequately explain the basic properties of amines. A positive charge on the nitrogen atom (option a) is a result of protonation, not the cause of basicity. The ability of the nitrogen atom to give up hydrogen atoms (option b) does not contribute to the basicity of amines. Option c, a sulfhydryl functional group, is unrelated to the basic properties of amines. Hence option (d) is the correct answer.
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a massive object can distort the light of more distant objects behind it through the phenomenon that we call .target 1 of 6 2. blank are defined as subatomic particles that have more mass than neutrinos but do not interact with 2 of 6 3. the of spiral galaxies provide strong evidence for the existence of dark 3 of 6 4. matter made from atoms, with nuclei consisting of protons and neutrons, represents what we call blank 4 of 6 5. models show that the of the universe is better-explained when we include the effects of dark matter along with the effects of luminous 5 of 6 6. matter consisting of particles that differ from those found in atoms is generally referred to as ____
Answers
1. Gravitational lensing is the phenomenon that we call a massive object that can distort the light of more distant objects behind it.
2. WIMPs (weakly interacting massive particles) are defined as subatomic particles that have more mass than neutrinos but do not interact with normal matter.
3. The rotation curves of spiral galaxies provide strong evidence for the existence of dark matter.
4. Baryonic matter made from atoms with nuclei consisting of protons and neutrons, represents what we call ordinary matter.
5. Models show that the evolution of the universe is better-explained when we include the effects of dark matter along with the effects of luminous matter.
6. Matter consisting of particles that differ from those found in atoms is generally referred to as exotic matter.
What is dark matter? Dark matter is a kind of matter that scientists assume to exist since it does not interact with light and cannot be seen through telescopes. Dark matter is believed to account for approximately 27% of the matter in the universe. Dark matter interacts gravitationally with visible matter and radiation, but it doesn't interact with electromagnetism, making it completely invisible to telescopes that observe electromagnetic radiation, such as radio waves, infrared light, visible light, ultraviolet light, X-rays, and gamma rays.
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Which of the following cannot be used to show diffusion?
Select one:
a. A drop of food coloring added to water.
b. Moths attracted to a flame.
c. Students leaving school at the end of the day.
d. The spreading of the gases from a car's exhaust.
Answers
Moths being attracted to a flame cannot be used as an analogy for diffusion.
DiffusionIt is the movement of molecules from the region of higher concentration of the molecule to the region of lower concentration of the same molecule.
A drop of food coloring added to water will diffuse out until the entire water is covered by the coloring.
Students leaving school at the end of the day can be likened to diffusion because they move from regions of concentration to regions of lower concentration.
The spreading of exhaust gases is a diffusion.
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Pretty Pudgey.. can i get a owaowa?
Answers
Answer:
owaowa
Explanation:
what is the question. is there no question or is this just free points?
Explanation:
What is responsible for an inherited trait? a. Environment b. Cells C. Dna d. Nutrition
Answers
Answer:DNA
Explanation:Dna
Need help what is the answer
Answers
Answer:
11.009306 or 11.009
Explanation:
boron 11 has atomic mass of 11.009306