PLEASE HELP I AM SO BEHIND ON SCHOOLWORK AND I HAVE TO GET IT ALL DONE BY FRIDAY!!
Which physical adaptation increases an organism’s chances of finding a suitable habitat?

Responses

the long legs of wading birds

the venom of snakes

the croak of frogs

the quills of a porcupine

Answer:

To the best of my knowledge, it is because of the amount of gamma rays is given off.

Explanation:

While both are isotopes, Potassium 40 gives off fewer gamma rays compared to Cobalt 60. Potassium 40 isn't really harmful to humans, but Cobalt 60 (I believe) is used in chemotherapy.

Explanation:

the volume will decrease..

decrease in temperature causes a decrease in the kinetic energy of the particles of the gas molecules

and the particles will be moving at a slower rate

The long term survival of any species of organism is possible only if the organisms can adapt the environment it living and to reproduce.

Not all kind of living things are fittest to survive in the world to live. Some of them are pray of their predators. Some are unhealthy to survive  while some others are competing to find food and shelter.

There are many organisms which have some natural adaptations, like some  strategies or physical peculiarities to hide from their predators and survive for ling time. For example, chameleon can hide from others by their color mimicking know as camoflouge.

The fittest one will survive and will be able to maintain their population through reproduction. Therefore, the organisms which can adapt to the environment it lives can survive for ling time.

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If the sample of magnesium used in a lab was contaminated with another metal that doesn't react with hydrochloric acid, then the results obtained in the experiment would be affected.

This is because the data collected during the experiment would reflect the reaction between hydrochloric acid and the contaminated sample instead of pure magnesium. As a result, the following changes in results might have been observed:

1. The mass of the contaminated sample would be higher than the mass of pure magnesium.

2. The rate of reaction between the contaminated sample and hydrochloric acid would be slower than the reaction between pure magnesium and hydrochloric acid.

3. The volume of hydrogen gas collected from the reaction would be lower than the volume of hydrogen gas collected in the reaction between pure magnesium and hydrochloric acid.

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The concentration of H2O2 after a total of 9.6 minutes have passed is approximately 0.03125 M.

Since the reaction is first order in H2O2, the decay of concentration follows an exponential decay model. The first-order rate equation is given by:

ln([H2O2]t/[H2O2]0) = -kt

where [H2O2]t is the concentration at time t, [H2O2]0 is the initial concentration, k is the rate constant, and t is the time.

Given that the concentration decreases from 0.500 M to 0.250 M in the first half-life of 3.2 min, we can calculate the rate constant (k):

ln(0.250/0.500) = -k * 3.2 min

Solving for k:

k = -ln(0.250/0.500) / 3.2 min

Now, we can use the obtained rate constant to find the concentration of H2O2 after a total of 9.6 minutes have passed:

[H2O2]t = [H2O2]0 * e^(-kt)

Plugging in the values:

[H2O2]t = 0.500 M * e^(-k * 9.6 min)

Calculating the concentration:

[H2O2]t = 0.500 M * e^(-k * 9.6 min) ≈ 0.03125 M

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A potassium atom's ground state electron configuration is 1s2, 2s2, 2p6, 3s2, 3p6, 4s1.

An atom's electron configuration is a picture of how electrons are arranged in relation to orbital shells and subshells. Consequently, this is potassium's electron configuration.

Making Electron Configurations in Writing. Write the energy level (the period) first, then the subshell that needs to be filled, and finally the superscript, which indicates how many electrons are in that subshell. The atomic number, Z, is the sum of all the electrons.

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Answer:

704 meters

Explanation:

1 Kilometer = 1000 meters

0.704 km * 100m/ 1 km = 704 m

Amino acid threonine is classified as polar neutral amino acid. This amino acid is polar due to the hydroxyl group attached to its side chain.

Both the one-letter acronym T and the three-letter abbreviation Thr are used to refer to threonine. Because it cannot be synthesised by the human body, essential amino acids must be obtained from diet or supplements. A polar neutral amino acid is threonine. This amino acid is polar because of the hydroxyl group on the side chain, but it lacks an acid or amine group that may be charged. Neutral polar amino acids are neither basic nor acidic, as their name implies. This indicates that they have precisely one amino group and one carboxyl group in their side chains (hence the name "amino acid"). In reality, the bulk of amino acids—polar and non-polar—are neutral.

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Answer:

The correct answer is - B. New Moon.

Explanation:

The change of moon disc from all black to all light to all dark again is called the lunar cycle. It takes almost 30 days (29.53059 to be precise). The time from all black to all light or all light to all black is almost 15 days. All black moon is termed as the new moon and all light is termed as the full moon.

As given that the full moon is shown happening on the eleventh of the month then what moon would be around 25 which is 14 days later that should be in waxing gibbous phase and almost new moon.

Thus, the correct answer is - B. new moon.

Answer:

The answer is "Option B"

Explanation:

From the query, the following knowledge is derived:  

Yield in percentage = 47%  

Performance of theory = 4860 g  

Actual yield Rate =?  

The percentage return is defined simply by the ratio between both the real return as well as the conceptual return multiplied by the 100. It's also represented as numerically:

\(Rate = \frac{Existing \ Rate} {Theoretical \ Rate} \times 100\)

Now We can obtain the percent yield as followed using the above formula:  

\(\text{Yield in percentage}= \frac{Actual \ yield \ Rate} {Theorical \ Rate} \times 100\)

\(47\% = \frac{Actual \ yield \ Rate}{4860}\)

The value of the Actual yield Rate =\(47\% \times 4860\)

                                                        \(= \frac{47}{100} \times 4860 \\\\ = 2284.2 g\)

The Actual yield Rate= 2284.2 g.

Answer:

B. One element changes into another.

Explanation:

We can see from the equation that uranium is changed to thorium and helium. Transmutation is the process by which one element is changed to another through radioactive decay, nuclear bombardment, or other similar processes.

Answer:b

Explanation:

Explanation:

a)phenotype= 100% big

b) genotype=1:2:1 (FF-25%, Ff-50%, ff-25%)

phenotype=3:1 (big=75%, small= 25%)

Answer:

• Write the chemical formulae of the following:-

1) Magnesium Chloride = MgC12.

2) Aluminium Chloride = A1C13 .

3) Calcium Nitrate = CaO

4) Calcium Carbonate = CaCo3

5) Copper Nitrate = Cu ( No3)2.

Explanation:

Hope this helps you !!

The chemical formulae of the given compounds are as follows:

A chemical formulae a set of chemical symbols showing the elements present in a compound and their relative proportions in that chemical compound.

The information provided by a chemical formula include:

The chemical formulae of the given compounds are as follows:

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The cation which is lower in relative energy (kcal/mol) is the tertiary cation. The values are different because of the difference in the hybridization state and geometry of the cationic carbon in the primary and tertiary cation structures.

Structurally, the tertiary cation has a carbon atom that is attached to three alkyl groups, while the primary cation has only one alkyl group. Hence, the tertiary cation is more stable and lower in relative energy. The bond angles made by the methyl hydrogens and the cationic carbon (H-Cmethyl-Ccation) in the tertiary cation structure are around 109.5°.

This is because the carbon atom in the tertiary cation is sp³ hybridized and forms tetrahedral geometry, which results in bond angles of around 109.5°.In the primary cation, the bond angles between the methyl hydrogens and the cationic carbon (H-Cmethyl-Ccation) are close to 180°. This is because the carbon atom in the primary cation is sp² hybridized and forms planar trigonal geometry, which results in bond angles close to 180°.

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The notation for the enthalpy of the solution is ∆Hsol. The correct answer is option ∆Hsol.

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Ammonia gas is sample of matter is a single substance.

Ammonia is a colorless gas with a sharp,irritating odor. It is extremely soluble in water and is lighter than air. Ammonia was first isolated by Joseph Priestley in 1774 with the aid of a pneumatic trough filled with mercury instead of water.

N2(g) + 3 H2(g) à 2 NH3(g)

Ammonia production is the largest consumer of nitrogen and is the gatewaycompound to most other nitrogen compounds produced industrially. Enormous quantities of ammonia are produced worldwide.

The majority of all ammonia and ammonium nitrate produced is for use as fertilizer. Approximately 70% of all NH3 produced is directly used for fertilizer. Farmers inject the pressurized liquid ammonia into the soil.

Ammonia is so soluble in water and has such a high affinity for polar groups such as hydroxyl groups that the ammonia is almost instantly taken up by the soil and very little is lost to the atmosphere.

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Answer

b. 4.2 x 10²⁴

Explanation

Given:

Moles of H2O = 7 moles

Avogadro's Number is 6 x 10²³

What to find:

The number of articeles of H2O present in 7 moles of H2O.

Solution:

1 mole f any substanc contains 6 x 10²³ partcicles

Therefore 7 moles of H2O will contain

The correct answer is option:

b. 4.2 x 10²⁴

Answer:

Recycling scrap copper is more sustainable than extracting copper from copper ores due to the following reasons:

Reduces energy consumption: Recycling scrap copper requires less energy compared to mining, extracting, and processing copper ores. This results in a reduction in greenhouse gas emissions and a decrease in energy consumption.

Conservation of natural resources: Recycling scrap copper conserves natural resources because it reduces the need for mining copper ores. Mining copper ores often leads to the destruction of ecosystems, soil erosion, and the emission of harmful pollutants into the environment.

Reduction in landfill waste: Recycling scrap copper helps to reduce the amount of waste in landfills. Copper is a valuable resource, and recycling it ensures that it is reused instead of ending up in landfills.

Cost-effective: Recycling scrap copper is often cheaper than extracting copper from copper ores. This is because recycling eliminates the cost of mining, extracting, and processing copper ores.

Preservation of water resources: Extracting copper from copper ores requires large amounts of water, which can lead to water shortages in some regions. Recycling scrap copper requires less water, thus helping to preserve water resources.

Overall, recycling scrap copper is more sustainable than extracting copper from copper ores because it reduces energy consumption, conserves natural resources, reduces landfill waste, is cost-effective, and helps to preserve water resources.

Explanation:

The empirical formula of the compound is C10H6N2.A compound contains only carbon (C), hydrogen (H), and nitrogen (N). Combustion of 42.0 mg of the compound produces 40.2 mg CO2 and 49.3 mg H2O.Find the empirical formula of the compound.

We need to calculate the amount of carbon, hydrogen, and nitrogen in the given compound.The amount of carbon in 40.2 mg of CO2 (carbon dioxide) is:

40.2 mg CO2 × (1 mol CO2 / 44.01 g CO2) × (1 mol C / 1 mol CO2) × (12.01 g C / 1 mol C)

= 10.8 mg C

The amount of hydrogen in 49.3 mg of H2O (water) is:

49.3 mg H2O × (1 mol H2O / 18.02 g H2O) × (2 mol H / 1 mol H2O) × (1.01 g H / 1 mol H)

= 5.50 mg H

Now, calculate the amount of nitrogen by subtracting the total mass of carbon and hydrogen from the mass of the given compound:

42.0 mg - 10.8 mg - 5.50 mg

= 25.7 mg NN

= 25.7 mg / 14.01 g/mol

= \(1.83 × 10⁻³ mol N\)

To find the empirical formula, divide the number of moles of each element by the smallest number of moles (the limiting reactant). In this case, the smallest number of moles is the number of moles of nitrogen (N), so we'll divide the number of moles of carbon and hydrogen by this value.

C =\((10.8 mg / 12.01 g/mol) / 1.83 × 10⁻³ mol\)

≈ 4.93H

=\((5.50 mg / 1.01 g/mol) / 1.83 × 10⁻³ mol\)

≈ \(3.02N = (1.83 × 10⁻³ mol) / 1.83 × 10⁻³ mol\)

= 1

The empirical formula of the compound is C4.93H3.02N. However, empirical formulas should have whole number subscripts, so we'll multiply all the subscripts by a factor to make them whole numbers.

C4.93H3.02N × (1/0.0142)

≈ C10H6N2

Therefore, the empirical formula of the compound is C10H6N2.

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Answer:

Moving the balls closer together. The distance decreases and force increases.

Formula

\(\ell=\frac{n h}{2 \pi}\)

\(\ell = angular \: momentum\)

\(n = principal quantum number \\ h = Planck's constant \\ \pi = pi\)

Mass NF₃ at STP : 50.06 g

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

15.8 L at STP, mol NF₃ :

\(\tt \dfrac{15.8}{22.4}=0.705\)

mass NF₃ (MW=71 g/mol) :

\(\tt mass=mol\times MW\\\\mass=0.705\times 71\\\\mass=50.06~g\)

A firework specialist would be required to be knowledgeable in inorganic chemistry, according to the statement.

In contrast to charcoal, which is a manmade product made from wood, coal is a naturally occurring mineral that develops over the course of millions of years. Even though coal in its natural condition is never used by itself in a grill or smoker, it is frequently added onto charcoal briquettes to boost their energy density.

As an acute pro government treatment, it is now most frequently used in healthcare setting to treat drug overdoses. Other advantages of activated charcoal are claimed to include less wind and flatulence, decreased cholesterol levels, and enhanced renal function.

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Strong heating has no effect on this substance. Long-term storage at room temperature is possible, but it must be kept dry because it interacts fast with moisture and water in the air.

On a large scale, it can be produced via the reaction of silicon or silicon carbide with iodine when heated to roughly 200 °C. The interaction of silane with iodine vapor at temperatures between 130 and 150 °C is of more academic interest because a variety of compounds, including iodosilane SiH3I, diiodosilane SiH2I2, and triiodosilane SiHI3, are produced. The liquid forms of these compounds are colorless at normal temperatures. [3] Iodoform, a related carbon compound that is a yellow solid at ambient temperature, can be easily separated from the final one.

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The product obtained when ethyne (also known as acetylene) is treated with KMnO4/H+ is two carboxylic acids.

when ethyne reacts with KMnO4 in the presence of an acid catalyst (H+), it undergoes oxidative cleavage, resulting in the formation of two carboxylic acids. The reaction involves the addition of two molecules of water across the triple bond of ethyne. The intermediate formed is glyoxal, which further undergoes oxidation to yield two molecules of carboxylic acids. The mechanism of the reaction starts with the addition of two molecules of water across the triple bond of ethyne, forming an enol intermediate. The enol tautomerizes to the corresponding ketone, which is further oxidized by KMnO4/H+ to form a carboxylic acid. This process is repeated for the second molecule of ethyne, resulting in the formation of two different carboxylic acids.

It's important to note that the specific carboxylic acids obtained will depend on the reaction conditions and the nature of the substituents on the ethyne molecule. The oxidation of the ketone intermediate can lead to the formation of various carboxylic acids, depending on the functional groups present. Therefore, without further information about the specific reactants and reaction conditions, it is not possible to determine the exact carboxylic acids formed in this reaction.

In summary, when ethyne is treated with KMnO4/H+, the main product obtained is two carboxylic acids. The reaction proceeds through the oxidative cleavage of the triple bond, resulting in the formation of two different carboxylic acids. The specific carboxylic acids produced will depend on the reaction conditions and the substituents present in the ethyne molecule.

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Answer:

5.81×10²² molecules of oxygen.

Explanation:

This a reaction of decomposition:

2KClO₃ →  2KCl + 3O₂

2 moles of potassium chlorate can produce 2 moles of potassium chloride and 3 moles of oxygen.

We determine the amount of salt.

7.89 g. 1mol /122.55g = 0.0644 moles.

If 2 moles of salt, can produce 3 moles of oxygen.

0.0644 moles of salt may produce (0.0644 . 3) /2 = 0.0966 moles.

Let's count the molecules.

1 mol oxygen contains 6.02×10²³ molecules

Then, 0.0966 moles may contain (0.0966 . NA) = 5.81×10²² molecules

Answer:

frequency =7.32 x 1019 hertz

To find the frequency  you must time speed of light (3 x 10^8) times wavelength

Answer:

phosphorus (P)

Explanation:

this is because when we add

2+2+6+2+3

we get 15

15 is also the atomic number so when we check the periodic table, we know phosphorus has an atomic number of 15 therefore the answer is phosphorus.  

At a fixed temperature and pressure, a cylinder contains equal volumes of O2 and an unknown gas. The identity of the unknown gas CO.

The number of moles of a given substance is calculated by dividing the mass by the molar mass.

The number of moles of O₂ = \(\mathbf{=\dfrac{20.0 \ g}{32 \ g/mol}}\)

= 0.625 moles.

Based on the given assumption, at fixed temperature and pressure;

The molar mass of the unknown gas can be estimated as:

\(\mathbf{= \dfrac{mass}{number \ of \ moles}}\)

\(\mathbf{= \dfrac{17.5 \ g}{0.625 \ moles}}\)

= 28 g/mol

Therefore, we can conclude that the unknown gas is CO.

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