How would the calculation change if a typical comet in the Oort cloud is only 1 km in diameter?
When a typical comet in the Oort cloud is only 1 km in diameter, then the mass of the Oort cloud is changes to 4.18×10⁹ kg.
The mass of each comet int he Oort cloud is,
mass = density × Volume
volume of sphere = 4/3(π×r²) where, r = radius of the sphere
From the given,
diameter = 1 km
radius = Diameter / 2 = 1/2(D)
Volume of the comet = 4/3 (π×r²) = 4/3 (π× (1/2 (10)³)²)
= 4/3×(π) ×(1/8×10⁶)
Mass = density × volume, where density = 1000 kg/m³
= 1000 × 4/3×(π) ×(1/8×10⁶)
= 4.18 ×10⁹ kg
When the typical comet in the Oort cloud is only 12 km in diameter the mass of Oort cloud is 4.18×10⁹ kg.
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refer to question 12 on page 6/7: a type ii cepheid has an apparent magnitude of 12 and a pulsation period of 3 days. what is the approximate distance to this cepheid variable star?
If a type ii cepheid has an apparent magnitude of 12 and a pulsation period of 3 days. the approximate distance to this cepheid variable star is 0.14 parsecs.
What is the cepheid variable star about?
To determine the distance to a Cepheid variable star, you can use the period-luminosity relationship, which states that the intrinsic brightness (luminosity) of a Cepheid is directly proportional to the length of its pulsation period. In other words, the longer the period, the brighter the Cepheid.
To use this relationship to determine the distance to a Cepheid, you need to know its apparent magnitude (how bright it appears from Earth) and its pulsation period. You also need a reference value for the luminosity of a Cepheid with a known period, which can be obtained from observations of nearby Cepheid variables.
Using these values, you can calculate the distance to the Cepheid using the following formula:
distance = 10 ^ ((reference luminosity - apparent magnitude + 5) / 5)
Plugging in the values you provided, we get:
Distance = 10 ^ ((-2.5 - 12 + 5) / 5)
= 10 ^ (-9.5 / 5)
= 10 ^ (-1.9)
= 0.14 parsecs
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In hiking, what fitness component is required of you
How much impulse is needed to stop a 32g mass traveling at a velocity of 38 m/s?
Given:
Unknown:
Solve it and show your work
The impulse needed to stop the 32g mass traveling at a velocity of 38 m/s is -1.216 kg·m/s.
To find the impulse required to stop a mass, we can use the impulse-momentum principle, which states that the change in momentum of an object is equal to the impulse applied to it. The equation for impulse is given by:
Impulse = Change in momentum
The momentum of an object is defined as the product of its mass and velocity:
Momentum = mass × velocity
Given:
Mass (m) = 32g = 0.032 kg (since 1 g = 0.001 kg)
Velocity (v) = 38 m/s
To find the momentum of the mass before stopping, we can multiply the mass and velocity:
Initial momentum = mass × velocity
Initial momentum = 0.032 kg × 38 m/s
Now, since the mass comes to a stop, the final velocity (vf) is 0 m/s. Therefore, the final momentum is zero.
According to the impulse-momentum principle, the change in momentum is equal to the impulse applied. Thus, the impulse required to stop the mass can be calculated as:
Impulse = Final momentum - Initial momentum
Impulse = 0 - (0.032 kg × 38 m/s)
Impulse = -1.216 kg·m/s
The negative sign indicates that the impulse is in the opposite direction to the initial momentum.
Therefore, the impulse needed to stop the 32g mass traveling at a velocity of 38 m/s is -1.216 kg·m/s.
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Light requires 4.5 years to travel from the nearest star to earth. If we could travel there in a spaceship going 90% of the speed of light, the trip would require 5.0 years according to clocks on earth. How much time would pass for the passengers in the ship
Answer:
Time according to earth clock (T0) = 0.22 years (Approx)
Explanation:
Given:
Time taken by light = 4.5 years
Time taken by ship = 5 years
Speed of light = c
Speed of ship (v) = 90% of c = 0.9c
Find:
Time according to earth clock (T0) = ?
Computation:
Time dilation is ,
\(T(Difference) = \frac{T0}{\sqrt{1-\frac{v^2}{c^2} } }\\\\ (5-4.5)= \frac{T0}{\sqrt{1-\frac{(0.9c)^2}{c^2} } }\\\\ 0.5=\frac{T0}{\sqrt{1-0.81} }\\\\T0 =0.2179\)
Time according to earth clock (T0) = 0.22 years (Approx)
A 5.0 kg block with a speed of 3.0 m/s collides with a 10
kg block that has a speed of 2.0 m/s in the same direction.After the
collision, the 10 kg block travels in the original direction with a
speed of 2.5 m/s. (a) What is the velocity of the 5.0 kg block immediately after the collision? (b) By how much does the total kinetic
energy of the system of two blocks change because of the collision? (c) Suppose, instead, that the 10 kg block ends up with a
speed of 4.0 m/s. What then is the change in the total kinetic energy? (d) Account for the result you obtained in
(a) The first block moves at 4.0 m/s in the same direction right after colliding.
(b) the system's total kinetic energy changes by 28.75 J
(c) the system's total kinetic energy changes by -1.25 J
Given;
First block's mass, m1, is 5 kg.
u1 = 3.0 m/s is the first block's starting speed.
m2 weight of the second block is 10.0 kg.
u2 = 2.0 m/s is the second block's initial speed.
v2 = 2.5 m/s is the second block's final speed.
Immediately following the impact, the first block block's Part (A) velocity is as follows:
Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.
(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)
35= 2.5v₁ + 25
2.5v₁ = 35-25
2.5v₁ = 10
v₁ = 10/2.5
v₁ = 4
2.5 m/s in the same direction for v1.
Change in the system's overall kinetic energy, part (B):
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)
ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).
ΔK = 71.25 J - 42.5 J
ΔK = 28.75 J
Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s
Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)
35 = 2.5v₁ + 40
2.5v₁ = -5
2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s
Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.
K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)
K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).
ΔK = 41.25 - 42.5 J
ΔK = -1.25 J
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PLEASE HELP ASAPP!!!
1. You drive to your friend's house, and the trip odometer in your car shows that you travelled a
total distance of 12 km. The trip took you 15 minutes. You know by looking at a map that the
actual straight-line distance to your friend's house is 8 km. Calculate (in km/hour)
a. What is your average speed for the trip
b. What is your average velocity for the trip
Answer:
hello
Explanation:
for average speed the total distance is important so.
and you must convert min to hour 15 min is 1/4 or 0.25 hour
\(s = \frac{x}{t} = \frac{12}{0.25} = 48 \frac{km}{h} \)
for average velocity the straight line distance is important so
\(v = \frac{d}{t} = \frac{8}{0.25} = 32 \frac{km}{h} \)
hope you understand
why is gravity on earth important
How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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You lift a 5 kg object 3 m above the ground.
How much GPE does it have?
How much work was done lifting it?
• How much KE does the object have just before hitting the ground
• if it is dropped?
(a) The amount of gravitational potential energy possessed by the object at the given height is 147.
(b) The kinetic energy, KE the object have just before hitting the ground is 147 J.
How much GPE does it have?The amount of gravitational potential energy possessed by the object at the given height is calculated as follows;
GPE = mgh
where;
m is the mass of the objectg is acceleration due to gravityh is heightGPE = 5 kg x 9.8 m/s² x 3 m
GPE = 147 J
Based on the law of conservation of energy, the amount of kinetic energy possessed by the object just before hitting the ground will the same as the gravitational potential energy at the initial height.
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You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
20N
10N
40N
30N
Balanced or Unbalanced?
Answer:
Unbalanced
Explanation:
can a body have an east velocity while expressing westward acceleration
Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.
Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.
Hope this helped!
PRACTICE
2.13 A 500 ft long 24 AWG soft copper wire is carrying a current of
100 mA. What is the voltage dropped across the wire?
ᴀ 500ᴏʜᴍ long 24 ᴀᴡɢ soft copper wire carrying a current of 100ma\s from the standard american wire gauge system table, 25.7 ᴏʜᴍ's per 1000 ft at 20°ᴄ that means 24 awg wire has 25.ohm per 1000ft\s calculate the resistance for 500ft.
25.7x500/1000 =12.85\s thus, the resistance is 12.85ohms
.Why not define voltage?Voltage is the pressure from the power source of an electrical circuit that drives charged electrons (current) through a conducting loop, allowing them to perform tasks like lighting a lamp.
What is voltage defined simply?A quantitative measure of the potential difference in charge between two sites in an electrical field is voltage, also known as electromotive force.
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A motor vehicle has a mass of 1.8 tonnes and its wheelbase is 3 m. The centre of gravity of the vehicle is situated in the central plane 0.9 m above the ground and 1.7 m behind the front axle. When moving on the level at 90 km/h the brakes applied and it comes to a rest in a distance of 50 m.
Calculate the normal reactions at the front and rear wheels during the braking period and the least coefficient of friction required between the tyres and the road. (Assume g = 10 m/s2)
Answer:
normal reaction, front: 11,175 Nnormal reaction, rear: 6,825 Nminimum coefficient of friction: 0.625Explanation:
The speed in meters per second is ...
(90 km/h)(1000 m/km)(1 h/(3600 s)) = 25 m/s
The braking acceleration can be found from ...
a = v²/(2d) = (25 m/s)²/(2×50 m) = 6.25 m/s²
Then the braking force is ...
F = Ma = (1800 kg)(6.25 m/s²) = 11,250 N
The torque on the center of gravity is ...
T = (11,250 N)(0.90 m) = 10,125 N·m
__
If we let x and y represent the normal forces on the front and rear wheels, respectively, then we have ...
x + y = (10 m/s²)(1800 kg) = 18000 . . . . . newtons
1.7x -1.3y = 10,125 . . . . . . . . . . . . . . . . . . . newton-meters
The latter equation balances the torque due to the wheel normal forces with the torque due to braking forces.
Multiplying the first equation by 1.3 and adding that to the second, we have ...
3.0x = (1.3)(18,000) + 10,125
x = 33,525/3 = 11,175 . . . . . . . . . . . newtons normal force on front tyres
y = 18000 -11175 = 6,825 . . . . . . . .newtons normal force on back tyres
The least coefficient of friction is the ratio of horizontal to vertical acceleration, 6.25/10 = 0.625.
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 53.5 N and it is acting with an effective lever arm of 2.25 cm , what is the torque that the muscle produces on the wrist
Answer:
1.20Nm
Explanation:
Given data
Force= 53.5N
Perpendicular distance= 2.25cm= 2.25/100= 0.0225m
The expression for the torque is given as
Torque= Force* Perpendicular distance
Torque= 53.5*0.0225
Torque= 1.20Nm
Hence the toque produced is 1.20Nm
Una anciana camina 0.30 km en 10 minutos dando la vuelta un centro comercial calcule su rapidez media 
De acuerdo con la información podemos inferir que la rapidez media de la anciana es de 0.03 km/min.
¿Cómo calcular la rapidez media de la anciana?Para calcular la rapidez media, dividimos la distancia recorrida por el tiempo empleado. En este caso, la anciana caminó 0.30 km en 10 minutos. Para obtener la rapidez media, dividimos 0.30 km entre 10 minutos, lo que nos da un valor de 0.03 km/min. Por lo tanto, la anciana tiene una rapidez media de 0.03 km/min.
La rapidez media se expresa en unidades de distancia divididas por unidades de tiempo. En este caso, la anciana recorrió una distancia de 0.30 km en un tiempo de 10 minutos, lo que nos da una rapidez media de 0.03 km/min. Esto significa que en promedio, la anciana camina 0.03 kilómetros por minuto durante su recorrido alrededor del centro comercial.
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Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
An ice skater is moving in a circle at a constant speed. Which of the following best explains the forces acting on the ice skater.
Please give answer I’ll give brainiest
A. Ice skater is moving so the forces acting on her must be unbalanced
B.the ice skater has a constant speed so the forces acting on her must be unbalanced
C. The ice skater had a changing cellos the forces acting on her must be unbalanced
D.not enough information to answer the question
a certain compact disc (CD) contains 783.216 megabytes of digital information 4
Answer:
"a certain compact disc (CD) contains 783.216 megabytes of digital information 4"
In the diagram below, if A's magnitude is 16 N and B's is 25 N, what is the magnitude of C?
How much current is in a circuit with a 1.5 V battery and three
2-ohm resistances (bulbs) in series?
Answer: 0.25A
Explanation: To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the total resistance of the circuit is the sum of the individual resistances of the three bulbs in series, which gives us:
R = 2 + 2 + 2 = 6 ohms
The voltage of the battery is given as 1.5V.
So, using Ohm's Law, we can calculate the current in the circuit as:
I = V / R = 1.5 / 6 = 0.25 amps
Therefore, the current in the circuit is 0.25 amps.
The current in the circuit is 0.25 A.
Voltage across the circuit, v = 1.5 V
Resistance in each resistors, R = 2Ω
Since, the resistors are connected in series combination, their effective resistance,
R' = 3R
R' = 3 x 2
R' = 6Ω
According to Ohm's law, if the temperature and all other physical factors remain constant, the voltage across a conductor is directly proportional to the current that is flowing through it.
So, according to Ohm's law,
V = IR
Therefore, current flowing through the given circuit,
I = V/R
I = 1.5/6
I = 0.25 A
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The inhabitants of a small island begin exporting beautiful clothmade from a rare plant that grows only on their island. Seeing howpopular the small quantity that they export has been, they steadilyraise their prices. A clothing maker from New York, thinking thathe can save money by "cutting out the middleman," decides to travelto the small island and buy the cloth himself. Ignorant of thelocal custom of offering strangers outrageous prices and thennegotiating down, the clothing maker accepts (much to everyone'ssurprise) the initial price of 400 tepizes/m^2. The price of thiscloth in New York is 120 dollars/yard^2.If the clothing maker bought 500m^2 of this fabric, how muchmoney did he lose? Use = 0.625Express your answer in dollars tothree significant figures.
Answer:
Lost Money = $ 53200
Explanation:
First, we calculate the selling price of the cloth:
Selling Price = (Area of Bought Fabric)(Unit Price in America)
Selling Price = (500 m²)($ 120/yard²)(1 yard/0.9144 m)²
Selling Price = $ 71759.4
Now, we calculate the amount that the cloth maker paid (cost) for buying the fabric from America:
Cost = (Area of Fabric Bought)(Unit Selling Price)
Cost = (500 m²)(400 tepizes/ m²)($ 0.625/1 tepize)
Cost = $ 125000
Hence, the money lost is given as:
Lost Money = Cost - Selling Price
Lost Money = $ 125000 - $ 71759.4
Lost Money = $ 53240
Rounding off to 3 significant figures, we get:
Lost Money = $ 53200
A. 10g
B.33g
C.40g
D.42g
Answer:
From the graph, it looks like 40 g
Explanation:
See where the NaCl line crosses the red vertical line = 40 gm
An 8.00-cm-diameter, 360 g solid sphere is released from rest at the top of a 2.00-m-long, 16.0 incline. It rolls, without slipping, to the bottom.
What is the sphere's angular velocity at the bottom of the incline?
What fraction of its kinetic energy is rotational?
Rotational kinetic energy makes for 0.94 of total kinetic energy.
How do you calculate a ball's rate of descent down a slope?To determine how the ramp's height affects the ball's speed, we may change the potential energy equation to be equal to the kinetic energy equation: mgh=12mv2 m g h = 1 2 m v 2 where m is the ball's mass, g is the ramp's height, and v is the ball's speed.
mgh = (1/2)mv² + (1/2)Iω²
A solid sphere possesses a (2/5)mr2 moment of inertia.
Substituting in the given values and solving for v, we get:(1/2)(0.36 kg)(9.81 m/s²)(2 m) = (1/2)(0.36 kg)v² + (1/2)(2/5)(0.36 kg)(0.04 m)²ω²
Simplifying and solving for v, we get:
v = 3.43 m/s
To find the angular velocity, we use the relationship between linear velocity and angular velocity:
v = rω
ω = v/r = (3.43 m/s)/(0.04 m) = 85.8 rad/s
The sphere at the bottom has the following kinetic energy:
(1/2)mv² = (1/2)(0.36 kg)(3.43 m/s)² = 0.89 J
The rotational kinetic energy is:
(1/2)Iω² = (1/2)(2/5)(0.36 kg)(0.04 m)²(85.8 rad/s)² = 0.84 J
The proportion of rotating kinetic energy is thus:
0.84 J / 0.89 J = 0.94
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study island genticsBelow is a Punnett square for the color of a hybrid rose. The allele y is for dark yellow and the allele Y is for pale yellow.
Y y
y Yy yy
y Yy yy
If a rose with the genotype Yy is pale yellow in color, which alelle is dominant?
A.
dark yellow, y
B.
dark yellow, Y
C.
pale yellow, Y
D.
pale yellow, y
If a rose with the genotype Yy is pale yellow in color, then there is not complete dominance for neither allele and it is a case of incomplete dominance. Nonetheless, since allele Y is for pale yellow and the hybrid has this phenotype, then it is partially dominant (pale yellow, Y, option 3).
What is incomplete dominance?Incomplete dominance is a genetic phenomenon in which one of the two alleles present for a given gene locus is expressed more strongly when compared to the other allele, which is called partially dominant and partially recessive alleles, respectively.
Conversely, complete dominance is due to the presence of an allele that completely masks the expression of the recessive allele in heterozygous hybrid individuals.
Therefore, with this data, we can see that incomplete dominance is associated with the expression of both alleles in the heterozygous hybrid individuals.
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Two equal masses are floating in space. The distance between their centers is X. How would the gravitational force between them change if the mass of one of the objects was cut in half?
Group of answer choices
The force would be one-half as much.
The force would be one-fourth as much.
The force would be twice as much.
The force would be the same.
The force would be one-fourth as much.
What is force?
Force is a push upon an object resulting from its interaction with another object. It is a vector quantity that is described by both magnitude and direction. Forces cause an object to accelerate.
Therefore, The force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. So if one of the objects has its mass halved, the gravitational force between them will decrease by a factor of (1/2)^2 = 1/4.
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An air jet is flying with a constant speed at an angle of 30° above the horizontal as indicated in the figure below. The weight ⃗ of jet has magnitude W = 86 500 N and its engine provide a forward thrust ⃗ of magnitude T = 103 000 N. In addition, the lift force ⃗ (directed perpendicular to the wings) and the force ⃗ of air resistance (directed opposite to the motion) act on the jet. Determine the magnitude of ⃗ and ⃗ . (5)
To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.
The weight ⃗ can be resolved into two components:
- the vertical component, Wsin(30°), acting downward
- the horizontal component, Wcos(30°), acting to the left
The forward thrust ⃗ can also be resolved into two components:
- the vertical component, Tsin(30°), acting upward
- the horizontal component, Tcos(30°), acting to the right
Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.
The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.
Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.
4. When scientists calculate the trajectory a satellite takes on its way to
study a planet, what do you think they use?
5 points
A Speed and velocity
B. Velocity and acceleration
O C. Speed, velocity, and acceleration
O D. Speed only
When scientists calculate the trajectory a satellite takes on its way to
study a planet, they use C. Speed, Velocity, and acceleration.
A trajectory, often known as a flight path, is the route taken by an object moving under the influence of gravity. Typically, the phrase is applied when referring to projectiles or satellites. A parabola curve is usually a decent approximation of the trajectory form when an object is propelled for in a short distance.
When scientists calculate the trajectory a satellite takes on its way to
study a planet they take the speed, velocity, and acceleration into consideration.
The formula for calculating the trajectory can be expressed as:
\(\mathbf{y = h + xtan (\alpha) - \dfrac{gx^2 }{2V_o^2cos^2 (\alpha)}}\)
where;
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The energy that something has because of its position--a book held 20 feet above the ground has more of this than a book held 5 feet off the ground.
The most common types of energy an object can have are:
- Kinetic energy: energy related to the movement. If an object has velocity, it has kinetic energy. The faster the object, higher is its kinetic energy.
- Potential energy: energy related to the height, to gravity. The higher (bigger height) an object is from a reference point, higher is its potential energy.
So the energy of a book held 20 feet above ground being higher than the energy of a book held 5 feet above ground, this energy is the potential energy.
Therefore the correct option is the third one.