PLEASE HELP DUE TODAY NO LINKS WILL REPORT

Answer:

Longer than

Step-by-step explanation:

The lengths of sides A C and F E are congruent. The lengths of sides B C and D E are congruent. Therefore:

AC = FE, BC = DE

Also m∠C is greater than m∠E

∠C is the angle opposite to line AB and ∠E is the angle opposite to line DF. Since AC = FE, BC = DE and m∠C is greater than m∠E. The length of a side of a shape is proportional to its opposite angle, since the opposite angle of AB is greater than the opposite angle of DF  therefore AB is greater than DF

From the given two triangles under the given conditions of congruency, we can say that;

Line segment AB is longer than Line segment FD.

The image showing both triangles is missing and so i have attached it.

Therefore, we can say that line AB and line FD do not have the same length.

Now, we see that angle BCA is larger than angle DEF, and as such we can say that the line segment AB is longer than line segment FD.

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Brand B is the better buy because it offers the most ounces for the lowest price.

To compare the prices of the three brands, we need to convert them to a common unit of measurement. Brand A is priced at $4.89 for 54 ounces, Brand B is priced at $3.91 for 16 ounces, and Brand C is priced at $3.10 for 910 grams. Since 16 ounces is equivalent to 1 pound and 1 pound is equivalent to 453.59 grams, we can convert the weight of Brand B and C to ounces. 910 grams is equivalent to 2.01 pounds, which is equivalent to 32.16 ounces.

A.

54oz, convert to lb

54/16=3.375lb

find per lb

4.89/3.375=$1.4488888 per lb

B.

2 and 3/4=2.75, 3.91/2.75=$1.42181 per lb

C. 910/453.59=2.00621lb

3.10/2.00621=$1.545 per lb

compare

A: $1.4488888 per lb

B: $1.42181 per lb

C: $1.545 per lb

It is observed from the above calculation that Brand B have lowest price per unit on ounce.

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Answer:

Its A

Step-by-step explanation:

took the test a while ago

Answer:

10

Step-by-step explanation:

To find the median in a set of data, organize the data from least to greatest.

Here, our data is the homework scores, those being:

10, 7, 8, 12, 9, 11, 13

Let's organize them in ascending order, like so:

7, 8, 9, 10, 11, 12, 13

The next step in finding the median is figuring out which number is in the middle. Since the amount of data we have is an odd number (7), there will be only one number in the middle.

We can find that the number in the middle is 10.

Thus, the median of the scores is 10.

The required measure of the angle x is given as 117.38°.

A triangle is given with a measure of.
a = 50, b = 55 and c = 90ft

The triangle is a geometric shape that includes 3 sides and the sum of the interior angle should not be greater than 180°

Here,
Apply cosine formula,
c² = a² + b² -2abcosx
Substitute the value in the above expression,
90² = 50² + 55² - 2×50×55×cosx
cosx = -0.46
x = cos⁻¹[-0.46]
x = 117.38°

Hence, as a result, the measure of the angle x is 117.38°.

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The values of the constant λ that will make y = e^(λx) a solution of the differential equation y′′ −3y′ + 2y = 0 are λ = 1 and λ = 2.

To find the value(s) of the constant λ that will make y = e^(λx) a solution of the differential equation y′′ −3y′ + 2y = 0, we can substitute y = e^(λx) into the differential equation and solve for λ.

First, we need to find the first and second derivatives of y = e^(λx):

y′ = λe^(λx)

y′′ = λ^2e^(λx)

Now, we can substitute these derivatives into the differential equation:

λ^2e^(λx) − 3λe^(λx) + 2e^(λx) = 0

e^(λx)(λ^2 − 3λ + 2) = 0

Since e^(λx) cannot equal 0, we can set the expression in parentheses equal to 0 and solve for λ:

λ^2 − 3λ + 2 = 0

(λ − 1)(λ − 2) = 0

λ = 1 or λ = 2

Therefore, the values of the constant λ that will make y = e^(λx) a solution of the differential equation y′′ −3y′ + 2y = 0 are λ = 1 and λ = 2.

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a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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Answer:

It is 1 cent cheaper  to pay 5.46 for 7 apples.

Step-by-step explanation:

Find the unit rate:

5.46 /7 = 0.78

This is the cost for 1 apple

3.95/5 = 0.79

This is the cost for 1 apple

Answer:

5 apples for 3.95 is the better deal

Step-by-step explanation:

If you divide 7 by 5.46 you should get roughly 1.28, so $1.28 per apple

and if you divide 5 by 3.95 you should get roughly 1.26, meaning $1.26 per apple. You can verify this by multiplying 1.26 by 5 and 1.28 by 7

Answer:

x         y

1          15

2         30

3         45

4         60

5         75

Step-by-step explanation:

Hope this works!

Answer:

x         y

1     =     15

2     =   30

3    =     45

4    =     60

5    =     75

Step-by-step explanation:

Plz mark brainliest!!!

Answer:  (x, y) = (-9, 7)

In other words, x = -9 and y = 7 pair up together to form the solution.

======================================================

Explanation:

Add the equations straight down

We end up with -3y = -21 which solves to y = 7. I divided both sides by -3.

Then use this value of y to find x.

7x+5y = -28

7x+5(7) = -28

7x+35 = -28

7x = -28-35

7x = -63

x = -63/7

x = -9

Or you could say

-7x-8y = 7

-7x-8(7) = 7

-7x - 56 = 7

-7x = 7+56

-7x = 63

x = 63/(-7)

x = -9

---------------

In summary we found that x = -9 and y = 7 pair up together.

The ordered pair solution is (x, y) = (-9, 7)

To verify this answer, plug those coordinates into each of the original equations. You should get the same thing on both sides when you simplify fully. I'll let you do this verification.

A visual way to check the answer is to graph the equations on the same xy grid. The two lines intersect at (-9, 7)

GeoGebra and Desmos are two graphing apps I recommend. Both are free.

In quantitative research, data collection from the same respondents at 2 or more points (waves) in time is referring to "longitudinal."

A method for gathering and interpreting numerical data is known as quantitative research. It can be used to discover patterns and averages, to make predictions, to verify causal linkages, and to generalize results to larger groups.

Some features regarding quantitative research are-

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\(36\) students registered in Math Trail only,\(50\) students  registered in Amazing Race only and \(36\) students who did not registered in both events.

We have according to question

Total number of students\(=150\)

Number of students in Math Trail\(=64\)

Number of students in Amazing Race\(=78\)

Number of students registered in both\(=28\)

To find: Number of students  registered in Math Trail only and in Amazing Race only. And number of students  who did not registered in both events.

Now, Number of students  registered in Math Trail only

\(=64-28\\=36\)

Number of students  registered in Amazing Race only

\(=78-28\\=50\)

Number of students who did not registered in both events

\(=56+78-28\\=114\\150-114=36\)

Therefore \(36\) students registered in Math Trail only,\(50\) students  registered in Amazing Race only and \(36\) students who did not registered in both events.

The area of the flower bed in square yards is 28 Square yards.

The area of the rectangular flower bed in square yards, we need to convert the measurements from feet to yards. There are 3 feet in 1 yard, so:

Length in yards = 21 feet / 3 = 7 yards

Width in yards = 12 feet / 3 = 4 yards

Now we can calculate the area in square yards:

Area = Length × Width

Area = 7 yards × 4 yards

Area = 28 square yards

Therefore, the area of the flower bed in square yards is 28 square yards.

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Then f(x) = 3x + 5

3 × 2 + 5

6 + 5 = 11 Ans. ( Opt. D )

Answer:

this is six times bigger larger

Answer:

Step-by-step explanation:

The wheel has diameter 60 cm = 0.60 m, and thus circumference π(0.60 m) ≈ 5.923 m.

In one complete revolution, a point on the edge of the wheel covers this distance, so that the wheel has an angular speed of

(13.2 m/s) * (1/5.923 rev/m) ≈ 2.229 rev/s

There are 60 seconds to each minute, and 60 minutes to each hour, so converting to rev/h gives

(2.229 rev/s) * (60 s/min) * (60 min/h) ≈ 8024 rev/h

The statement that correctly identifies the triangle Jackson is describing is: Triangle Jackson is an equilateral triangle. In an equilateral triangle, all three angles are acute, meaning they are less than 90 degrees.

Additionally, an equilateral triangle has three equal sides. Therefore, an equilateral triangle satisfies both conditions mentioned by Jackson: three acute angles and three equal sides. It's important to note that in other types of triangles, such as scalene or isosceles triangles, the angles may not all be acute or the sides may not all be equal. However, an equilateral triangle specifically fits Jackson's description of a triangle with three acute angles and three equal sides.

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Step-by-step explanation:

-5x+2y= 4         <==== Multiply entire equation by -3 to get:

15x-6y = -12  

2x+3y= 6          <====  Multiply entire equation by 2 to get :

4x+6y = 12    Add the two underlined equations to eliminate 'y'

19x = 0     so x = 0

sub in x = 0 into any of the equations to find:  y = 2

(0,2)

Six semicircles lie in the interior of a regular hexagon with a side length of 2 so that the diameters of the semicircles coincide with the sides of the hexagon. The zone of the shaded locale is around 10.3923 square units.

 We will approach this problem by first finding the region of the hexagon and after that subtracting the zones of the six semicircles from it. The zone of a customary hexagon with side length 2 can be found utilizing the equation:

Region of hexagon = (3√3/2) x side\(^{2}\)

Substituting the given esteem of side length, we get:

Area of hexagon = (3√3/2) x 2\(^{2}\) = 6√3

The range of a crescent is half the region of the comparing circle. So, the zone of each crescent is:

Range of semicircle = 1/2 x π x radius\(^{2}\) = 1/2 x π x 1^\(^{2}\)= π/2

There are six semicircles, so the whole range of the semicircles is:

Add up to the zone of semicircles = 6 x π/2 = 3π At long last, able to find the zone of the shaded locale by subtracting the region of the semicircles from the range of the hexagon:

Zone of shaded locale = Range of hexagon - Add up to a range of semicircles

= 6√3 - 3π

≈ 10.3923 thus, the zone of the shaded locale is around 10.3923 square units. 

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The conditions that must be met to use the normal approximation for the confidence level are np>5 and n(1-p)>5

Sampling Distribution: A sampling distribution is a probability distribution of a statistic that is obtained through repeated sampling of a specific population. It describes a range of possible outcomes for a statistic, such as the mean or mode of some variable, of a population.

Given that the sampling distribution of the population proportion is based on a binomial distribution.

The conditions that must be met to use the normal approximation for the confidence level are np>5 and n(1-p)>5

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Answer:

(x,y)=(-2,-1)

Step-by-step explanation:

4x - y = -7: 8x-2y=-14

8x-2y=-14

-8x + 4y = 12

add these two:

2y=-2

y=-1

plug in the y:

-8x-4=12

-8x=16

x=-2

Using the Bayes' theorem, we find the probability that the transferred ball was white given that the second ball drawn was white to be 52/89, or approximately 0.5843.

To solve this problem, we can use Bayes' theorem, which relates the conditional probability of an event A given an event B to the conditional probability of event B given event A:

P(A|B) = P(B|A) * P(A) / P(B)

where P(A|B) is the probability of event A given that event B has occurred, P(B|A) is the probability of event B given that event A has occurred, P(A) is the prior probability of event A, and P(B) is the prior probability of event B.

In this problem, we want to find the probability that the transferred ball was white (event A) given that the second ball drawn was white (event B). We can calculate this probability as follows:

P(A|B) = P(B|A) * P(A) / P(B)

P(B|A) is the probability of drawing a white ball from urn b given that the transferred ball was white and is now in urn b. Since there are now six white balls and three black balls in urn b, the probability of drawing a white ball is 6/9 = 2/3.

P(A) is the prior probability of the transferred ball being white, which is the number of white balls in urn a divided by the total number of balls in urn a, or 6/13.

P(B) is the prior probability of drawing a white ball from urn b, which can be calculated using the law of total probability:

P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)

where P(B|not A) is the probability of drawing a white ball from urn b given that the transferred ball was black and P(not A) is the probability that the transferred ball was black, which is 7/13.

To calculate P(B|not A), we need to first calculate the probability of the transferred ball being black and then the probability of drawing a white ball from urn b given that the transferred ball was black.

The probability of the transferred ball being black is 7/13. Once the transferred ball is moved to urn b, there are now five white balls and four black balls in urn b, so the probability of drawing a white ball from urn b given that the transferred ball was black is 5/9.

Therefore, we can calculate P(B) as follows:

P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)

= (2/3) * (6/13) + (5/9) * (7/13)

= 89/117

Now we can plug in all the values into Bayes' theorem to find P(A|B):

P(A|B) = P(B|A) * P(A) / P(B)

= (2/3) * (6/13) / (89/117)

= 52/89

Therefore, the probability that the transferred ball was white given that the second ball drawn was white is 52/89, or approximately 0.5843.

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The electric field at a point inside the smaller cylinder, at a distance of r = 1.23 m from the z-axis, is then given by:

E = Q / (2πε0rℓ) = (8.96 × 10^-8 C) / (2π)(8.85 × 10^-12 C

To find the electric field at a point inside a pair of infinite concentric cylinders, we can use Gauss's law, which states that the electric flux through any closed surface is proportional to the charge enclosed within the surface. For a cylindrical geometry, we choose a cylindrical Gaussian surface of radius r and height h, with its axis coincident with the z-axis, and calculate the electric flux through the surface.

Since the cylinders are infinite in extent, the electric field is uniform and radial at any point inside them. Let's choose the Gaussian surface to be a cylinder of radius r and height h, as shown in the figure below:

          ++++++++ ++++++++

        ++        ++++     ++

      ++          +++      ++

     +             ++        +

    |                         |

    |                         |

    |                         |

    |                         |

    |                         |

    |                         |

    +                         +

     +                       +

      ++                   ++

        ++               ++

          ++++++++++++++

         <----- h ----->        

The electric flux through this cylindrical surface is given by:

Φ = ∫ E · dA

where E is the electric field, dA is an element of area on the cylindrical surface, and the integral is taken over the entire surface.

Since the electric field is radial, the dot product E · dA reduces to E dA cos θ, where θ is the angle between E and dA. Since E and dA are perpendicular, cos θ = 1, so we have:

Φ = ∫ E dA = E ∫ dA = E (2πrh)

where the integral reduces to the surface area of the cylinder. The charge enclosed within the cylinder is given by:

Q = σ A = σ (2πrℓ)

where σ is the charge density (charge per unit area) and A is the area of the end caps of the cylinder.

Applying Gauss's law, we have:

Φ = Q / ε0

where ε0 is the permittivity of free space. Substituting our expressions for Φ, Q, and A, we get:

E (2πrh) = σ (2πrℓ) / ε0

Simplifying and solving for E, we get:

E = σ r / ε0

Since the charge density σ is uniform and equal to the total charge divided by the surface area of the cylinder, we have:

σ = Q / (2πrℓ)

Substituting this expression for σ into our equation for E, we get:

E = Q / (2πε0rℓ)

Let's now apply this formula to the given problem. We have two concentric cylinders of radii r1 = 2.74 m and r2 = 3.87 m, with a charge density of σ = 5.15 nC/m2. The height of each cylinder is infinite, so we can choose any value for ℓ. Let's choose ℓ = 1 m, so that the charge on each cylinder is:

Q = σ A = σ (2πrℓ) = (5.15 × 10^-9 C/m2) (2π)(2.74 m)(1 m) = 8.96 × 10^-8 C

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The distributive property of multiplication over addition is A (B + C) = AB + AC.

Properties of Numbers.

Numbers are have 5 main properties of operation which are:

Given,

Here we have to write the distributive property of multiplication over addition of a conditional statement.

Basically, the distributive property defines the distributing ability of operation over another mathematical operation within a bracket.

It can be either distributive property of multiplication over addition or distributive property of multiplication over subtraction.

Here we need to write the distributive property of multiplication over addition of a conditional statement.

So, The distributive property of multiplication over addition is expressed as

=> A × (B + C) = AB + AC.

Let us verify this property with the help of an example.

For example:

The expression 2(1 + 4) using the distributive law of multiplication over addition.

=> 2(1 + 4) = (2 × 1) + (2 × 4)

⇒ 2 + 8 = 10

Hence, the distributive property of multiplication over addition is stated.

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024.00% is the effective tax rate .

The percentage of income that a person or a business pays in taxes is known as the effective tax rate. The average tax rate that is applied to both earned and unearned income, such as stock dividends, is known as the effective tax rate for individuals.

An income tax is a charge levied against people or organizations in relation to the income or profits they make. In most cases, income tax is calculated as the sum of the tax rate and the amount of taxable income. The type of taxpayer and the type of income are two factors that can affect the tax rate. Individuals (or family units) and corporations are subject to income taxes. The basis for calculating individual income tax is the income received. Since the burden is presumably on the individuals who pay it, it is typically categorized as a direct tax. Income taxes are assessed against both businesses and people based on their profits. Taxable income can be earned from a variety of sources, including earnings, salaries, dividends, interest, royalties, and rent.

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Answer:

Step-by-step explanation:

see attached image

use Pythagorean to solve the other leg of a triangle

b = \(\sqrt{12^2 - 10^2}\)

b = \(\sqrt{44}\)

b = 6.6 units

Answer:

The mass of 3.5 moles of Ca (Sodium)  is 140 g to two significant figures.

Answer:

february

plzz mark as a brainlist

Answer:

Part A: 15.55

Part B: 0.45

Step-by-step explanation:

Part A:

The giraffe is already 14.29 so when you add the length of its tongue (equation 14.29 + 1.26) then that would equal 15.55

Part B:

The giraffe is trying to eat some leaves that are 16 feet above the ground so you would subtract 16 - 15.55 to see how much farther it needs to reach, so the answer is 0.45.

(This is what I got, I apologize if I get this wrong. If I messed up on something, someone please correct me, thank you and have a nice day!)

Answer:

Part A:   It can reach 15.55 feet.

Part B:   Need to reach 0.45 feet farther to get to the leaves of a 16 feet tree.

Step-by-step explanation:

giraffe + tongue = reach

      14.29 + 1.26 = 15.55

tree height - giraffe reach = extra distance

16 - 15.55 = 0.45 feet

The expression obtained by simplifying is 3\(x^{3}\) + 17\(x^{2}\) + 21x - 9.

What is an expression?

A mathematical expression consists of its own components, at least two additional variables or integers, and one or more arithmetic operations.

We are given an expression as

(\(x^{2}\) + 6x + 9) (3x - 1)

Now, for simplifying the expression, we will multiply the terms.

So, we get

⇒ (\(x^{2}\) + 6x + 9) (3x - 1)

⇒ 3\(x^{3}\) - \(x^{2}\) + 18\(x^{2}\) - 6x + 27x - 9

Now, by combining the like terms, we get

⇒ 3\(x^{3}\) + 17\(x^{2}\) + 21x - 9

Hence, the expression obtained by simplifying is 3\(x^{3}\) + 17\(x^{2}\) + 21x - 9.

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Question: Simplify the following

(x² + 6x + 9) (3x - 1)