PLEASE HELP!!!

A student takes 45.0 grams of N204 and combines it with 250mL of *..
NaOH.
1. Name each compound.
2. State whether each compound bonds via ionic, covalent, or metallic
bonds.
3. Find the molarity of the final solution.
4. Identify whether the final solution is concentrated or dilute.
5. Identify the percent composition of oxygen in the final solution.

The correct molecular formula for the compound magnesium chromate pentahydrate is as follows: MgCrO₄•5H₂O.

Molecular formula in chemistry is a notation indicating the number of atoms of each element present in a compound.

Chemical or molecular formula is a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule, using chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus (+) and minus (−) signs.

The chemical formula also reveals information about the types and number of atoms that make up a chemical compound or molecule.

For example; a chemical compound named magnesium chromate pentahydrate will have a chemical formula of MgCrO₄•5H₂O.

This tells us that the compound contains magnesium, chromium, oxygen, and hydrogen atoms.

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The percent composition of hydrogen is 18.3%.

What is percent composition?

The term percent composition refers to the percentage of a particular component in a compound. It is contained as the ratio of the mass of that component to the total mass multiplied by 100.

From the law of conservation of mass, total  mass of beryllium hydride(BeH2) =  85.2 g

Mass of hydrogen =  15.6 g

Percent composition of hydrogen =  15.6 g/ 85.2 g  × 100/1 = 18.3%

Answer:

324 meters

Explanation:

I don't really have an explanation

The bonds when surface tension occurs, water molecules form a weak bond with each other allowing a small bug to walk across the surface of a puddle. are referred to as hydrogen bonds.

Surface tension is the energy, often denoted as γ, necessary to increase the surface area of a liquid by a unit of area. Surface tension is a result of the cohesive forces that arise between the liquid's atoms and molecules. It's a property of liquids that makes them behave like an elastic sheet or membrane on their surface.

Hydrogen bonds are a type of chemical bond that occurs between a hydrogen atom bonded to an atom such as oxygen, nitrogen, or fluorine and another atom or electronegative group in a different molecule or chemical group.

The hydrogen bond is a type of dipole-dipole interaction that occurs when an electronegative atom or molecule attracts the positively charged hydrogen atom of another molecule or group. The hydrogen bond is a result of the difference in electronegativity between the hydrogen and the electronegative atom or group.

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The water and the solutes leave the capillaries at the arterial end because the blood pressure is the greater than the osmotic pressure at the arterial end.

The blood pressure is the greater than the osmotic pressure at the arterial end and the water molecules  and the solutes leave the capillaries at the arterial end. At the arterial end of capillary, the blood pressure is exceeds the limit of the the osmotic pressure, that will causes the  net movement of the fluid out of the capillary.

Thus, due to the higher blood pressure than the osmotic pressure the solutes and the water leaves the artial end.

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To select the appropriate pipette for each of the following volumes are P1000,  P20, P200, microsyringe.

A. 874 uL (microliters) - A P1000 pipette would be appropriate for this volume. P1000 pipettes can dispense volumes ranging from 100 μL to 1000 μL.

B. 57 uL (microliters) - A P20 pipette would be appropriate for this volume. P20 pipettes can dispense volumes ranging from 2 μL to 20 μL.

C. 340 uL (microliters) - A P1000 pipette or a P200 pipette would be appropriate for this volume. P1000 pipettes can dispense volumes ranging from 100 μL to 1000 μL, and P200 pipettes can dispense volumes ranging from 20 μL to 200 μL. Since the volume is closer to 200 μL, a P200 pipette might be more appropriate in this case.

D. 15 pL (picoliters) - A microsyringe with a nanoliter or picoliter volume range would be appropriate for this volume. Microliter syringes are not appropriate for volumes in the picoliter range. The appropriate syringe size would depend on the accuracy and precision required for the experiment.

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Answer:

4665.97

Explanation:

To differentiate between the ETC being blocked at the first step and the second step, the compound that can help differentiate between the two steps is cytochrome c. The correct option is c.

If the ETC is blocked at the first step (ubiquinone ⇒ Complex III), cytochrome c would be in its reduced state.

On the other hand, if the ETC is blocked at the second step (Complex III ⇒ cytochrome c), cytochrome c would be in its oxidized state.

Therefore, the correct option is c

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Complete question:

We have established that an inhibitor causing the accumulation of reduced ubiquinone could block the ETC at any of three possible steps.

1. ubiquinone⇒ Complex III

2. Complex III ⇒cytochrome c

3. cytochrome c⇒ Complex IV

What would be different if the ETC were blocked at the first step listed compared with the second step listed? You would find that ubiquinone was reduced in both cases, but there would be a differentiating factor.

You can differentiate between the first step listed and the second step listed by knowing the oxidation state of which compound.

a. Complex III

b. Complex IV

c. ubiquinone

d. Complex I

e. Complex II

f. cytochrome c

The sulfide ion (S²⁻) is larger than the chloride ion (Cl⁻).

According to the question , sulfide ion (S²⁻) is larger than the chloride ion (Cl⁻) .  the atomic number of sulfur 16 and chlorine is 17

sulfur .

atomic number of sulfur is 16,

now, S²⁻  = 18 electrons

Cl⁻ = 18 electrons

The no. of electrons in S²⁻ and Cl⁻ are same 18 electrons. But S²⁻ ion has one proton less than Cl⁻ ion. So, the attractive force between the nucleus and electron is more that's the reason Cl⁻ ion is smaller  than S²⁻

Thus , the sulfide ion (S²⁻) is larger than the chloride ion (Cl⁻).

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When we say a chemical equation is balanced, we mean that the law of conservation of mass is valid.

A chemical equation is said to be balanced if the number of atoms in each element on both the reactant and product sides of the equation is equal. This means that the law of mass conservation is followed, and the total number of atoms of each element is conserved during the chemical reaction.

Adjusting the coefficients of the reactants and products to reach the same amount of atoms of each element on both sides is what balancing a chemical equation entails.

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In the conditions found in a patient 10 hours after aspirin ingestion, where acidosis may be present, the H2CO3/HCO3- system may not work effectively as a buffer.

The effectiveness of the H2CO3/HCO3- system as a buffer depends on the pKa of the weak acid and the pH of the solution. In the case of a patient 10 hours after aspirin ingestion, the conditions may not be suitable for the H2CO3/HCO3- system to work effectively as a buffer.

Aspirin, or acetylsalicylic acid, is metabolized in the body to salicylic acid, which can cause acidosis and decrease the pH of the blood. This decrease in pH can shift the equilibrium of the H2CO3/HCO3- system, affecting its buffering capacity.

Explanation:

The H2CO3/HCO3- system acts as a buffer in the blood by maintaining a stable pH. Carbonic acid (H2CO3) is a weak acid that can dissociate into bicarbonate ions (HCO3-) and hydrogen ions (H+). The bicarbonate ions can act as a reservoir for H+ ions, preventing large changes in pH. The effectiveness of this buffer system is determined by the pKa of carbonic acid, which is around 6.1.

However, when aspirin is ingested, it undergoes metabolism in the body to salicylic acid. Salicylic acid can cause an increase in H+ ions and lead to acidosis, a condition characterized by a decrease in blood pH. Acidosis shifts the equilibrium of the H2CO3/HCO3- system towards the formation of more carbonic acid (H2CO3) and decreases the concentration of bicarbonate ions (HCO3-). As a result, the buffering capacity of the H2CO3/HCO3- system may be compromised, and it may not effectively maintain the pH within the desired range.

Therefore, in the conditions found in a patient 10 hours after aspirin ingestion, where acidosis may be present, the H2CO3/HCO3- system may not work effectively as a buffer. Additional medical intervention may be required to restore and maintain the appropriate pH balance in the body.

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Answer:

no there is no bonds between the two of these

Anions and cations are ions, which are atoms or molecules that have gained or lost electrons. Anions are ions that have an extra electron, giving them a negative charge. Cations are ions that have lost an electron, giving them a positive charge.

Anions are formed when nonmetal atoms gain electrons, while cations are formed when metal atoms lose electrons. For example, chlorine (Cl) is a nonmetal and can gain an electron to form chloride (Cl-), which is an anion. On the other hand, sodium (Na) is a metal and can lose an electron to form sodium ions (Na+), which are cations.

Anions and cations play an important role in many chemical reactions, such as the formation of ionic compounds. For example, the combination of sodium cations (Na+) and chloride anions (Cl-) forms the ionic compound sodium chloride, or common table salt.

Anions and cations also play a key role in biological systems, such as in the movement of ions across cell membranes, which is necessary for processes such as nerve impulse transmission and muscle contraction.

Anions and cations are also used in many industrial processes, such as in the production of aluminum from bauxite ore, which involves the removal of the cations aluminum (Al3+) from the anions bauxite (AlO(OH)4-).

In summary, anions and cations are ions that have gained or lost electrons, respectively. They play an important role in chemical reactions, biological systems, and industrial processes. Examples of anions include chloride (Cl-), nitride (N3-), and oxide (O2-), while examples of cations include sodium (Na+), potassium (K+), and calcium (Ca2+).

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Explanation:

Hey there!

The volume of an object: The volume of a water displaced by the object.

So, at first we need to find the volume of a water displaced by the object.

On the first figure the initial volume of a water is 60.5ml . Similarly, in second figure when an object is immersed then its volume is 90ml.

Now, volume of a water displaced =?

We have;

Displaced volume = final volume - initial volume.

Or, displaced volume = (90 - 60.5) ml.

= 29.5ml.

As per the condition, volume of a water displaced by the object = volume of an object.

Therefore, the volume of an object is 29.5ml.

Hope it helps...

Answer: 391 g

Explanation:

For this problem, we need to know that molarity is. Molarity is moles of solute/liters of solution. it is also denoted as M=n/V, which is also mol/L. We are given that the molarity is 3.0 M and the liter is 1.5 L. All we have to do is plug in 3.0 and 1.5 into our formula and solve for moles.

\(3.0M=\frac{n}{1.5L}\)

\(n=4.5 mols\)

Now that we have moles, we can convert moles to grms by using the molar mass of LiBr.

\(4.5 mols*\frac{86.844 g}{1 mol} =391g\)

Answer:

C.) increasing digestion

Explanation:

hope this helps:)

Answer:

C.  increasing digestion

Explanation:

Answer:

8.1293534120006496

Explanation:

hope this helps

Answer:

boiling water

Explanation:

its hotter

Answer:

FIGURE 11.5 (a) When a solution of silver nitrate is added to a solution of sodium chloride, the silver ions combine with the chloride ions to form a precipitate of silver chloride. The sodium and the nitrate ions are nonparticipating spectator ions.

Answer:

\(T_2=261.46\ K\)

Explanation:

It is given that,

Original temperature, \(T_1=323^{\circ}C=596.15\ K\)

Original volume, \(V_1=2.85\ L\)

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure, \(V\propto T\)

It would means, \(\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\)

T₂ = ?

\(T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.25\times 596.15}{2.85}\\\\T_2=261.46\ K\)

So, the new temperature is 261.46 K.

The percentage of women with hypertension, defined as a diastolic blood pressure level above 90 mmHg, can be calculated using the standard normal distribution table.

To find the percentage, we need to calculate the z-score for a diastolic blood pressure of 90 mmHg using the formula:

z = (x - μ) / σ

where x is the diastolic blood pressure value, μ is the mean, and σ is the standard deviation.

In this case, x = 90 mmHg, μ = 70.2 mmHg, and σ = 10.8 mmHg.

Substituting these values into the formula, we get:

z = (90 - 70.2) / 10.8 = 1.833

Next, we need to find the corresponding area under the standard normal curve for a z-score of 1.833. By referring to the standard normal distribution table or using a calculator, we find that the area to the left of 1.833 is approximately 0.9664.

To determine the percentage of women with hypertension, we subtract this area from 1 and multiply by 100:

Percentage = (1 - 0.9664) × 100 ≈ 3.36%

Therefore, approximately 3.36% of women have hypertension based on the given diastolic blood pressure criteria.

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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A spectrophotometry experiment involves spectrophotometer, blank solution ,sample solutions and cuvette .

Spectrophotometry is a method to measure how much a chemical substance absorbs light by measuring the intensity of light as a beam of light passes through sample solution. The basic principle is that each compound absorbs or transmits light over a certain range of wavelength.

This measurement can also be used to measure the amount of a known chemical substance. Spectrophotometry is one of the most useful methods of quantitative analysis in various fields such as chemistry, physics, biochemistry, material and chemical engineering and clinical applications.

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Answer:fluorine

Explanation:

The correct answer is option A: This is an ionization process.

The statement which best describes the following chemical reaction is this is an ionization process.

The complete chemical reaction is given below.

In this reaction, the ionization of sodium is taking place.

Na(g) → Na⁺(g) e⁻

Ionization refers to a process or chemical reaction during which cations or anions are formed by the loss or gain of electrons.

If an atom loses an electron then it forms a cation i.e. positively charges atom and when it gains electrons then anions are formed i.e. negatively charged atoms.

In the above mention case, the parent sodium atom loses one electron and forms a cation. The overall process is called the ionization process.

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The mass balance equation is 0.15 M = [H₃PO₄] + [H₂PO₄⁻] + [HPO₄²⁻] + [PO₄³⁻] and the charge balance equation is [H₃O⁺] + [K⁺] + [Na⁺] = [H₂PO₄⁻] + 2 × [HPO₄²⁻] + 3× [PO₄³⁻] + [OH⁻]  for a solution containing 0.10 m KH2PO4 and 0.050 m Na2HPO4.

To find out the mass balance and the charge equation

Let's record all the reactions that result in the formation of the solutions and the equilibria that exist within them to aid in our ability to identify the ions that are there. Two soluble salts are dissolving in these reactions.

KH₂PO₄(s) → K⁺ (aq) + H₂PO₄⁻ (aq)

Na₂HPO₄  →  2Na⁺ + HPO₄²⁻

and the processes of acid-base dissociation for H₂PO₄⁻ , HPO₄²⁻ and H₂O

H₂PO₄⁻ + H2O  →   H3O⁺ + HPO₄²⁻

H₂PO₄- + H2O  →  OH⁻ + H₃PO₄

HPO₄²⁻ + H₂O  →   H3O⁺ + PO₄³⁻

2H2O  → H₃O⁺ + OH⁻

Please take note that the base dissociation reaction for HPO4 2⁻  was left out because its byproduct, H2PO4 ⁻, was previously taken into consideration in another reaction. Simple mass balance equations exist for K+ and Na+.

[K⁺] = 0.1M   [Na⁺] = 0.1M

However, the mass balance equation for phosphate requires some consideration. The same ions are produced in solution by H2PO4 and HPO4.

As a result, we can consider that the solution originally contains 0.15 M KH2PO4, which results in the mass balance equation shown below.

0.15 M = [H₃PO₄] + [H₂PO₄⁻] + [HPO₄²⁻] + [PO₄³⁻]

Hence final charge balance equation is

[H₃O⁺] + [K⁺] + [Na⁺] = [H₂PO₄⁻] + 2 × [HPO₄²⁻] + 3× [PO₄³⁻] + [OH⁻]

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