The derivative of ln(sin(e)) with respect to x is:
dy/dx = (1/sin(e)) * cos(e).
The derivative of sin(cosx) with respect to x is:
dy/dx = cos(cosx) * (-sinx).
a) To find the derivative of y = sin(cosx), we use the chain rule. The derivative of sin(cosx) with respect to x is:
dy/dx = cos(cosx) * (-sinx)
b) To find the derivative of y = ln(sin(e)), we use the chain rule and the derivative of the natural logarithm. The derivative of ln(sin(e)) with respect to x is:
dy/dx = (1/sin(e)) * cos(e)c) To find the derivative of y = 4cscx, we use the derivative of the cosecant function. The derivative of 4cscx with respect to x is:
dy/dx = -4cscx * cotx
Simplifying the derivatives, we have:
a) dy/dx = -cos(cosx) * sinx
b) dy/dx = (cos(e))/(sin(e))
c) dy/dx = -4cotx
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Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Answer:
24/25
Step-by-step explanation:
Please see the attached image.
The cosine of an angle is the adjacent side relative to that angle over the hypotenuse.
Answer: 24/25
Which of the following domains are closed and which are bounded?
(a) {(x,y)∈R2:x2+y2≤1}
(b) {(x,y)∈R2:x2+y2<1}
(c) {(x,y)∈R2:x≥0}
(d) {(x,y)∈R2:x>0,y>0}
(e) {(x,y)∈R2:1≤x≤4,5≤y≤10}
(f) {(x,y)∈R2:x>0,x2+y2≤10}
(a) The domain closed and bounded.
(b) The domain bounded.
(c) The domain closed.
(d) The domain bounded.
(e) The domain closed and bounded.
(f) The domain closed and bounded.
In this question, we have been given some domains.
We need to check which domains are closed and which are bounded.
A domain of function is said to be closed if the region R contains all boundary points.
A bounded domain is nothing but a domain which is a bounded set.
(a) {(x,y)∈R2:x^2+y^2≤1}
The domain of x^2+y^2≤1 contains set of all points (x, y) ∈R2
so, the domain closed and bounded.
(b) {(x,y)∈R2:x2+y2<1}
The domain of x^2+y^2 < 1 contains set of all points (x, y) ∈R2
so, the domain is bounded.
(c) {(x,y)∈R2: x ≥ 0}
The domain of x ≥ 0 is R2 - {x < 0}
So, the domain is closed.
(d) {(x, y) ∈ R2 : x > 0,y > 0}
The domain is R2 - {(x, y) ≥ 0}
So, the domain is bounded.
(e) {(x, y) ∈ R2 : 1 ≤ x ≤ 4, 5 ≤ y ≤ 10}
The domain is closed and bounded.
(f) {(x,y)∈R2:x>0,x^2+y^2≤10}
The domain is closed and bounded.
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help. i can't find the answer anywhere and i hate doing slope
Answer:
put one point at (2, -4) and the other at (0, -1)
you can find the second point using the slope -3/2
A chainsaw needs a 50:1 gas:oil ratio, how much oil do you need if you add 3 gallons of gas? no links!! links will be reported
Answer:
3/50 of a gallon
Step-by-step explanation:
50 / 1 = 3 / x
cross-multiply:
50x = 3
x = 3/50
what is the remainder when 3 is synthetically divided into the polynomial -2x^2 + 7x -9
Answer:
-6
Step-by-step explanation:
-6 is the answer .
Hope it helps you
Answer:
-6
Step-by-step explanation:
The y-intercept of the graph of y=-7x+140y is located at (0, c) What is the value of c ?
The y-intercept of the graph is located at (0, 0). So, the value of c is 0.
What is graph?
A graph is a visual representation of data that displays the relationship between two or more variables. It consists of a set of points, called vertices or nodes, which are connected by lines or curves, called edges or arcs. The vertices represent the variables, while the edges represent the relationship between them.
To find the y-intercept of the graph of y = -7x + 140y, we need to substitute x = 0 into the equation and solve for y. This will give us the y-coordinate of the point where the graph intersects the y-axis.
Substituting x = 0, we get:
y = -7(0) + 140y
y = 140y
Simplifying the equation, we get:
139y = 0
Dividing both sides by 139, we get:
y = 0
Therefore, the y-intercept of the graph is located at (0, 0). So, the value of c is 0.
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3c+5=23 what is c? c=3 c=6 c=7 c=18
Answer:
c = 6
Step-by-step explanation:
Subtract 5 from both sides. This is to cancel out the + 5. You have 3c = 18Divide both sides by 3. 18/3 = 6, so c = 6.Answer:
First, rearrange the equation so you can get the like terms together
3c=23-5
3c=18
c=18/3
c=6
Step-by-step explanation:
I hope this is the answer, and if it helped give me brainliest
Can someone help with an explanation please
The percentage of the total hours did Andrea work is,
⇒ 27.1%
What is mean by Percentage?A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.
Given that;
Total number of hours to work is,
⇒ 5.8 + 8.1 + 7.3 + 8.7 hours
⇒ 29.9 hours
Here, Andre work 8.1 hours.
Hence, The percentage of the total hours did Andrea work is,
⇒ 8.1 / 29.9 × 100
⇒ 27.1%
Thus, The percentage of the total hours did Andrea work is,
⇒ 27.1%
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Two fair dice are rolled. Find the probability that
(a) the sum of the two numbers shown is 6.
(b) Both dice show the same number.
Please answer question B)
Answer:
b) 1/2
because 2 dies will have 12 faces
Answer:
cheapt
Step-by-step explanation:
k-8=-17 that is the answer to this problem
Answer:
k=-9
Step-by-step explanation:
k-8+8=-17+8
k=-9
Step-by-step explanation:
k-8=17
k-8+8=17+8
k=25
A student has taken three math tests so far this semester. His scores for the first three tests were 71, 75, and 79. Part A: Suppose his test scores continue to improve at the same rate. What will be the grade on the sixth and (final) test?
Answer:
The grade of this sixth and (final) test would be 91.
Step-by-step explanation:
This is an arithmetic series since each time the data is increasing by the common difference of 4, and we already know a₁ which is the first term in the sequence is 71, therefore we can say:
a₁ = 71
r = 4
a₆ = the sixth term that needs to be found out
n = 6
Formula of an arithemetic series:
aₙ = a₁ + r(n - 1)
a₆ = 71 + 4(6 - 1)
a₆ = 71 + 4(5)
a₆ = 71 + 20
a₆ = 91
Hence, the grade of this sixth and (final) test would be 91.
Hope this helps!
In triangle ABC, what is the measure of b if a = 6, C = 4,
and B = 75°?
A. 5.64
B. 6.29
C. 6.78
D. 7.02
Given:
In triangle ABC, a = 6, c = 4, and B = 75°.
To find:
The measure of b.
Solution:
According to the Law of Cosine:
\(b^2=a^2+c^2-2ac\cos B\)
Substituting the given values in the above formula, we get
\(b^2=(6)^2+(4)^2-2(6)(4)\cos (75^\circ)\)
\(b^2=36+16-48(0.2588)\)
\(b^2=52-12.4224\)
\(b^2=39.5776\)
Taking square root on both sides, we get
\(b=\sqrt{39.5776}\)
\(b=6.291073\)
\(b\approx 6.29\)
The measure of side b is 6.29 units.
Therefore, the correct option is B.
Using the following graph, write the equation of a line that is parallel to the given line and passes through the point (0, 0).
(Write your answer is slope intercept form. The y= is already typed for you, so only type the remainder of the equation using NO spaces!)
Answer:
y=-x
Step-by-step explanation:
Slope of the line = -1
Parallel line slope = -1, y intercept 0
y = -x
:]
Pleaseeee helppppp meee with thissss
Answer:
19.4
Step-by-step explanation:
4/x=7/34, 7x = 136, x=19.43, x = 19.4
How do you solve this algebraically? I'm a bit confused on how you separate the absolute value it into a piecewise function. Thanks
Function f(x) approaches to ∞ as x approaches to 2 from left and from the right.
The absolute values are separated into two function given as,
|a| = { a , if a≥0 and -a , if <0}
The expression that we have been given is
f(x) = 4|x/(x^2 – 4)|
the absolute expression can split in following two ways which are
|x/(x^2 - 4)| = {-[x/(x^2 – 4)] , if x<2 and [x/(x^2 – 4 )] if x≥2}
a) Lim x -> 2- f(x) = lim x -> 2- 4{-[x/(x^2 – 4)]}
= lim x -> 2- 4[x/(4 - x^2 )]
= 4[2/(4 – 4)]
= 8/0
= ∞ (because something divide by 0 is infinite)
b) Lim x -> 2+ f(x) = lim x -> 2+ 4[x/(x^2 – 4)]
= 4[2/(4 – 4)]
= 8/0
= ∞ (because something divide by 0 is infinite)
Hence f(x) approaches to ∞ as x approaches to 2 from the left and from the right.
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Factor this polynomial expression.
15x2 - 2x-8
O A. (5x + 4)(3x - 2)
B. (5x-2)(3x+4)
O C. (5x+2)(3x - 4)
D. (5x-4)(3x + 2)
Answer:
I have made it in above picture
hope it helps
Answer:
D. (5x-4)(3x + 2)
Step-by-step explanation:
1/2 - x + 3/2 = x - 4
what is the solution for X in the equation?
Answer: x= 3
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Neo mixes 600ml of black paint with white paint in order to get grey paint. He thinks the colour came out too dark, so he decreases the amount of black paint in the ratio 7:12. Calculate how much black paint it would be.
Let us consider the black paint in the mixture = 7x
and white paint in the mixture = 12x
total quantity of mixture = 600ml
according to the question , black : white paint = 7 : 12
quantity of black paint = \(\frac{7}{19}\) × 600= 221.052
quantity of white paint = \(\frac{12}{19}\) × 600 = 378.94
{ 221.052ml black paint + 378.94 ml white paint = 599.99 ml grey paint }
Ans :- It would be 221.052 ml of black paint
Madison is reeling in her string at a steady rate the linear equation 3y - 9x = -81 can be used to find y the number of feet of kite string she still needs to reel in after x seconds after the points (0, -27). And (-9,0) on the line? Show your work
Point ( 0 , -27 ) on the line and ( -9 , 0 ) are not on the line
Given :
Madison is reeling in her string at a steady rate the linear equation 3y - 9x = -81 can be used to find y the number of feet of kite string she still needs to reel in after x seconds .
Points ( 0 , -27 )
when x = 0
3y - 9 * 0 = -81
3y - 0 = -81
3y = -81
y = -81 / 3
y = -27
so point ( 0 , -27 ) on the line .
when y = 0
3 * 0 - 9x = -81
0 - 9x = -81
-9x = -81
x = 81/9
x = 9
so ( -9 , 0 ) are not on the line
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A research request agreement includes all of the following items EXCEPT A. the scales for the measures. B. the decision problem confronting the manager. C. the target population from which a sample will be drawn. D. an approximation of the time and expense of the research report. E. All of the above are included in a research request agreement.
The correct answer is D. an approximation of the time and expense of the research report.
A research request agreement typically includes all of the following items:
A. the scales for the measures: This refers to the specific measurement scales or instruments that will be used to collect data in the research.
B. the decision problem confronting the manager: This outlines the specific problem or issue that the research aims to address and provide insights for decision-making.
C. the target population from which a sample will be drawn: This defines the specific group or population that the research will focus on and from which a representative sample will be selected.
D. an approximation of the time and expense of the research report: This item is not typically included in a research request agreement. The time and expense of the research report are usually discussed separately during project planning and budgeting.
Therefore, the correct answer is D. an approximation of the time and expense of the research report.
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Evaluate ၂ = my ds where is the right half of the circle 2? + y2 = 4
The value of the integral ∫(2 - y^2) ds over the right half of the circle x^2 + y^2 = 4 is 2θ + sin(2θ) + C, where θ represents the angle parameter and C is the constant of integration.
The value of the integral ∫(2 - y^2) ds over the right half of the circle x^2 + y^2 = 4 can be calculated using appropriate parameterization and integration techniques.
To evaluate this integral, we can parameterize the right half of the circle by letting x = 2cosθ and y = 2sinθ, where θ ranges from 0 to π. This parameterization ensures that we cover only the right half of the circle.
Next, we need to express ds in terms of θ. By applying the arc length formula for parametric curves, we have ds = √(dx^2 + dy^2) = √((-2sinθ)^2 + (2cosθ)^2)dθ = 2dθ.
Substituting the parameterization and ds into the integral, we obtain:
∫(2 - y^2) ds = ∫(2 - (2sinθ)^2) * 2dθ = ∫(2 - 4sin^2θ) * 2dθ.
Simplifying the integrand, we get ∫(4cos^2θ) * 2dθ.
Using the double-angle identity cos^2θ = (1 + cos(2θ))/2, we can rewrite the integrand as ∫(2 + 2cos(2θ)) * 2dθ.
Now, we can integrate term by term. The integral of 2dθ is 2θ, and the integral of 2cos(2θ)dθ is sin(2θ). Therefore, the evaluated integral becomes:
2θ + sin(2θ) + C,
where C represents the constant of integration.
In conclusion, the value of the integral ∫(2 - y^2) ds over the right half of the circle x^2 + y^2 = 4 is given by 2θ + sin(2θ) + C.
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ten plus 8 to the third power divided by 16
Answer: 42
Step-by-step explanation:
10+8^3/10
Exponets first
8^3=512
Then Divide
512/16=32
Finally add
32+10=42
Use Order of Operations
Someone help please
Answer:
\(6^\frac{1}{10}\)
What is the value of y?
Enter your answer in the box.
I would like to know the answer to problem 3 please.
Remember that
The length of the diagonal of the inscribed square is equal to two times the radius of the circle
In this problem
The radius is 2 units
therefore
The length of the diagonal is 4 units
The answer is the option BSimplify: -(-x + 1) -x − 1 x − 1 -x + 1 x + 1
Answer:
x -1
Step-by-step explanation:
-(-x + 1)
Distribute the minus sign
- 1 * -x + -1 (-x)
x -1
Steps to solve:
-(-x + 1)
~Distribute the negative sign
(- * -x) + (- * 1)
~Simplify
x - 1
Best of Luck!
Find the value of X
The value of x when the tangents intersect is 24.
How to find angles when tangent intersect?The theorem of tangent intersection states that the the measure of the angle formed by two tangents that intersect at a point outside a circle is equal to one-half the positive difference of the measures of the intercepted arcs.
Therefore, let's use the theorem to find the value of x in the circle as follows:
61 = 1 / 2 × ((10x + 1) - (5x - 1))
61 = 1 / 2 × (10x - 5x + 1 + 1)
61 = 1 / 2 × (5x + 2)
61 = 1 / 2 (5x + 2)
61 = 5 / 2 x + 1
61 - 1 = 5 / 2 x
60 = 5 / 2 x
cross multiply
5x = 120
divide both sides by 5
x = 120 / 5
x = 24
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hello please help i’ll give brainliest
Answer:
b. option Is the correct answer
Which is a simplified form of the expression -5(y – 2) – 7y?
A. -12y + 10
B. 2y - 10
C. -2y + 10
D. 12y - 10
Answer:
the answer is B
Step-by-step explanation:
-5(y-2)-7y
-5y-10-7y
+7y +7y
answer: 2y-10
Answer:
A. (-12y+10)
Step-by-step explanation:
-5(y-2) - 7y can be simplified to:
-5y + 10 - 7y when you factor the parenthesis.
If you add the y's together, the answer should be:
-12y + 10.
.
pretzelmania, incorporated, issues 7%, 10-year bonds with a face amount of $67,000 for $67,000 on january 1, 2024. interest is paid annually on december 31.
The journal enetry,
Debit cash is $67,000
Debit discount on payable is $670
Credit bonds payable is $66,330
(Recorded on bonds )
Debit Interest expense is $46,90
Debit discount on bonds payable is $46.9
credit cash is $4643.1..
Bonds payable
Bonds issued when the market price equals the standard rate are issued at face value. In other words, the cash received is face value.
Interest paid on the par Bond includes only the indicated. Interest rate calculated based on the number of annual payments.
We have given that
face amount, F = $67,000
Annually paid interest= $67,000
rate of bond, r = 7%
time bond, n = 10 year
market bond of interest= 7%
Coupon ammount = 7% of 67000 =$ 4690
we have to calculate bond issue and first interest payment .
bond price= C×[1 - (1 + r)⁻ⁿ] /r + F/(1+r)ⁿ
= 4690[ 1 - (8)¹⁰]/7 + 67000/(8)¹⁰
=669.99 + 0.000062 = 669.9901 ~ 670
Interest Expense = Principal * Rate * Time
=> Interest Expense = $67,000×7% ×1
= $46,90
discount or primum on bond payable
= interest expense - $66,330×7% × 1
= $46,90- $4643.1 = $46.9
date General
General journal debit credit
January, cash $67,000 $66,330
2024 Bonds
payable
Discount on
bond $670
payable
December
31, cash $4643.1
2024 interest
expense $46,90
Discount on
bond $46.9
payable
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Complete Question:.Pretzelmania, Inc., issues 7%, 10-year bonds with a face amount of $67,000 for $67,000 on January 1, 2024. The market interest rate for bonds of similarrisk and maturity is 7%. Interest is paid annually on December 31.Record the bond issue and first interest payment on December 31 . (If no entry is required for a transaction/event, select "No journal entry required" in thefirst account