PLEASE HELP ASAP!! :')
Hillary is presented with a piece of metal and asked to determine its physical properties. Which of the following groups does not represent the physical properties of the metal Hillary was given?
Group of answer choices

soluble in water and high melting point

malleability and reactivity

magnetism and low melting point

thermal conductivity and electrical conductivity

Answer:

1distance --------- lightyear

2power------------- watt

3energy ----------- joule

4resistance ------ Ohm

5Force---------------- Newton

Answer:

Reservoir.

Explanation:

Answer:

2P

Explanation:

See attached file

Answer:

To calculate the work done by a force, we can use the formula:

Work = ∫F dx

In this case, the force is given by Fx = (2x + 7) N, and the particle moves along the X-axis from X1 = 1 m to X2 = 5 m. Let's calculate the work done.

Work = ∫(2x + 7) dx

Integrating the function (2x + 7) with respect to x, we get:

Work = (x^2 + 7x) evaluated from X1 to X2

Plugging in the values X2 = 5 and X1 = 1 into the expression, we have:

Work = (5^2 + 7 * 5) - (1^2 + 7 * 1)

= (25 + 35) - (1 + 7)

= 60 - 8

= 52

Therefore, the work done by the force is 52 Joules (J).

Explanation:

The linear speed of the blade tip is approximately 114 m/s.

The radial acceleration of the blade tip is approximately 488 times the acceleration of gravity, g.

(a) To calculate the linear speed of the blade tip, we need to convert the rotational speed from revolutions per minute (RPM) to radians per second. One revolution is equivalent to 2π radians, so the angular velocity of the rotor is 550 rev/min x (2π/60) = 57.54 radians/second.

The linear speed of the blade tip is then the product of the angular velocity and the length of the blade, giving us 57.54 radians/second x 3.40 m = 195.6 m/s.  The blade tip is only a small fraction of the total length of the blade, so we can assume that the linear speed of the blade tip is approximately equal to the linear speed of the rotor at a radius of 3.40 m. Therefore, the linear speed of the blade tip is approximately 114 m/s.

(b) The radial acceleration of the blade tip is given by the formula ar = rω², where r is the radius of the blade and ω is the angular velocity of the rotor in radians per second. Substituting in the values given, we get ar = (3.40 m) x (57.54 radians/second)² = 11,976 m/s². To express this in terms of g, we divide by the acceleration due to gravity, g = 9.81 m/s², giving us ar/g ≈ 488.

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Answer:

20

Explanation:

i'm not so sure with my answer

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Impulse needed to stop the 1300 kg car driving at a speed of 18 km/h or 5 m/s is 6500 kg m/s.

Impulse of a moving body is the change in its momentum. The ability to make the applied force increasing the displacement of a body is called its momentum. It is the product of mass and velocity of the body.

Impulse is the product of force and time. Here, the impulse we need to calculate is required to stop the car. Hence the final momentum is zero.

Given = 1300 kg

velocity = 18 km/h = 5 m/s

then initial momentum = 1300 kg × 5 m/s = 6500 kg m/s.

Final momentum = 0

thus, impulse  = 6500 kg m/s - 0 = 6500 kg m/s

Therefore, the impulse of the car needed to stop it is 6500 kg m/s against the momentum.

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3,1 The value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The putty ball's mass has no effect on its acceleration, but it does have an effect on its weight and momentum.

4 The experiment can be repeated several times to ensure the reliability of the results.

3.1 The "change in velocity per second" for the putty ball can be calculated using the formula:

change in velocity = (final velocity - initial velocity) / time

In this case, the putty ball A is released from rest, so its initial velocity is zero. Its final velocity can be calculated using the equation of motion:

distance = 0.5 x acceleration x time²

where distance is the height of the building, and time is the time it takes for the ball to fall to the ground. We are given that the distance is h and the time is 2 minutes or 120 seconds. Using these values, we can solve for the acceleration:

h = 0.5 × a × t²

a = 2h / t²

Substituting h = XZ = 2.0 m and t = 0.125 s:

a = 2 x 2.0 / (0.125)² = 256 m/s²

Now, calculate the change in velocity per second:

change in velocity = (final velocity - initial velocity) / time

= (acceleration x time) / time

= acceleration

= 256 m/s²

Therefore, the value of the "change in velocity per second" for the putty ball is 256 m/s².

3.2 The acceleration of putty ball B will be equal to the acceleration of putty ball A. This is because the acceleration of an object is determined only by the force acting on it and its mass, according to Newton's second law of motion (F = ma). In this case, both putty balls are subject to the same gravitational force and experience the same air resistance (which is negligible), so their acceleration will be the same. The mass of the putty ball does not affect its acceleration, but it does affect its weight and momentum.

4 To ensure the reliability of the results, the experiment can be repeated multiple times, and the results can be compared and analyzed for consistency. The experiment can also be performed under controlled conditions, such as in a vacuum, to eliminate the effects of air resistance. The equipment used in the experiment should be calibrated and properly maintained to ensure accurate measurements. The experimenter should also take care to minimize sources of error, such as parallax error when reading the height of the building, and record all measurements and observations accurately.

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The force on the wall by a ball having a mass of 350 g is 140N.

Force is the product of mass and acceleration.

To calculate the force on the wall, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force on the wall is 140N.

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The coefficient of kinetic friction for the skier if the magnitude of frictional force is 25N will be 0.04638.

Kinetic friction can be defined as a force which acts between the moving surfaces. A object moving on the surface experiences a force in the opposite direction of the movement. The magnitude of the force will also depend on the coefficient of kinetic friction between the two objects.

F = μk Fn

where, F is the frictional force,

μk is the coefficient of kinetic friction,

Fn is the normal force

Fn = mass × acceleration due to gravity

Fn = 55 × 9.8

Fn = 539N

F = μk Fn

F = 25N,

25 = μk × 539

μk = 25/ 539

μk = 0.04638

Therefore, the coefficient of kinetic friction will be 0.04638.

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Answer:

the weight of the object decreases when it is taken from the Earth to the Moon

Explanation:

The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.

\(W =mg\)

where,

W = weight of the object

m = mass of the object

g = acceleration due to gravity on the planet

The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.

The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.

Hence, the weight of the object decreases when it is taken from the Earth to the Moon

Answer:

Both are aquatic animals and are hunters

Explanation:

(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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Answer:

B. O.4692 mm

Explanation:

I hope its help keep safe

Answer:

Its  D trust me it is

Explanation:

Answer:

9.807 m/s²

Explanation:

PLS make me brainliest

Answer:

\(\huge\boxed{\sf 9.8 \ m/s^2}\)

Explanation:

The acceleration due to gravity is g the value of which is 9.8 m/s².

\(\rule[225]{225}{2}\)

Hope this helped!

Explanation:

yooooooooo

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Explanation:i think its nuetrons

To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:

Lenses:

Place an object at different distances to the left of a lens with a focal length (f).

a) Object placed beyond 2f:

In this case, the object is placed far beyond twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.

SALTS:

Size: The image will be smaller than the object.

Attitude: The image will be inverted.

Location: The image will be located between the focal point and twice the focal length.

Type: The image will be real.

b) Object placed at 2f:

In this case, the object is placed at twice the focal length of the lens.

Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.

Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.

Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.

The image will be formed on the opposite side of the lens at twice the focal length.

SALTS:

Size: The image will be the same size as the object.

Attitude: The image will be inverted.

Location: The image will be located at twice the focal length.

Type: The image will be real.

c) Object placed between f and 2f:

In this case, the object is placed between the focal point and twice the focal length of the lens.

In this case, the object is placed far beyond twice the focal length of the mirror.

Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.

Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.

Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.

The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.

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Answer:

Efriction = 768.23 [kJ]

Explanation:

In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.

We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.

The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.

\(E_{pot}-E_{friction}=E_{kin}\)

where:

\(E_{pot}=m*g*h\\E_{kin}=\frac{1}{2}*m*v^{2}\)

m = mass = 56 [kg]

h = elevation = 1400 [m]

v = velocity = 5.6 [m/s]

\((56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]\)

the new volume of the gas is 3.49 L when An external force performs 180 J of work as it compresses the gas at constant pressure.

An ideal gas is a theoretical gas comprised of numerous randomly moving point particles that do not interact with one another. The ideal gas notion is valuable because it obeys the ideal gas law, which is a simplified equation of state, and is susceptible to statistical mechanics analysis. Work is pressure times change in volume.

Given,

initial Volume V₁ = 3.5 L

initial pressure P = 7.9 × 10⁴ Pa

Work = 180J

Work W = PΔV

180 J = 7.9 × 10⁴ Pa × ( 3.5L - V₂ )

2.27 × 10⁻³ =  0.0035m³ - V₂

3.5 - 2.27 × 10⁻³  = V₂

V₂ = 3.49 L

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Answer:

pretty sure its B if it isnt im so so sorry

Explanation:

Solution :

Given expression :

\($\mu_k$\)mgcosθ = mgsinθ − ma

Here, g = 9.8 \(m/s^2\) , a = 3.60 \(m/s^2\) , θ = 27°

Therefore,

\($\mu_k mg \cos \theta = mg \sin \theta - ma$\)

\($\mu_k mg \cos \theta = m(g \sin \theta - a)$\)

\($\mu_k g \cos \theta = (g \sin \theta - a)$\)

\($\mu_k =\frac{(g \sin \theta-a)}{g \cos \theta}$\)

Mow calculating the coefficient of kinetic friction as follows :

\($\mu_k=\frac{g \sin \theta-a}{g \cos \theta}$\)

\($\mu_k=\frac{9.8 \times \sin 27^\circ-3.60}{9.8 \times \cos 27^\circ}$\)

\($\mu_k=0.097$\)

These waves are traveling at the same speed.  The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."

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Answer:

If 2N = 30mm

Then ? =35mm

2N×(35mm÷30mm)

2N×1.167

= 2.33N

To get the additional force required, subtract 2N from 2.33N

2.33N - 2N

= 0.33N

∴ The additional force needed is 0.33N

Explanation:

With this question, we establish the principles of proportion. That is, if more less divides and vice versa. If 2N is stretching the material to 30mm, then how  more force will be needed to stretch the material to 35mm?

Answer:

africa

Explanation:

África África ooo

The time that would be taken is 1.6 s.

We know that the speed would be the ratio of the distance to the time that have been taken and that is how we would be able to solve the problem that we have in the case that is ahead of us in this question

We have that the speed is; Distance/Time

= 91 m/29s

= 3.1 m/s

At the same speed;

Time = Distance/Speed

= 5 m / 3.1 m/s

= 1.6 s

Hence we k now that the spaghetti would be able to take a time that is about 1.6 s

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