PLEASE HELP ASAP

Choose the expression that is equivalent to the quantity 7 raised to the negative second power times 7 raised to the third power end quantity all raised to the negative third power.

−76
1 divided by 7 raised to the third power
negative 1 divided by 7 raised to the sixth power
718

Answer:

\(2~cm\)

Step-by-step explanation:

\(Let ~ b~ be ~ base\)

\(Area=\frac{1}{2} bh\\\)

\(12=\frac{1}{2}b(12)\)

\(b=2\)

-----------------

hope it helps...

have a great day!

The quadratic function in the form A(x) = a·x² + b·x + c, that can be used to calculate the area is; A(x) = x² + 44·x - 2880

A quadratic function is a function that consists of variables that have exponents of 2 as the highest exponent.

The dimensions are;

A = The width of the door, w = x

The length of the door, l = x + 44

The area of the door, A = x × (x + 44) = x² + 44·x

The area of the door = 20 ft² = 2880 in²

Therefore;

x² + 44·x = 2880

The quadratic function is therefore;

x² + 44·x - 2880 = 0

The quadratic function is therefore;

A(x) = x² + 44·x - 2880

The solution of the quadratic function is found as follows;

x² + 44·x - 2880 = (x - 36)·(x + 80) = 0

x = 36 and x = -80

The possible value of x is therefore;

x = 36 inches

The length of the door, l = 36 + 44 = 80

The dimensions of the door are therefore;

Width = 36 inches

Length = 80 inches

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Answer:

he could by 2 pounds and still have a dollar left over because

15 11 6

-4 -5 -5 so yeah

11 6 1

The table which  represents a quadratic relationship is in option \(D\).

A quadratic relationship is a mathematical relation between two variables that follows the form of a quadratic equation.

Quadratic sequence \(=an^2 +bn+c\)

So, According to the definition mentioned above if table follows the  form of a quadratic equation then it is in quadratic relationship.

So,

To find out quadratic relationship,

We will find first difference in every table and then second difference (Second difference is the difference between the first difference).

We have,

Table A;

\(\left \begin{array}{ccccc}x& \ &f(x)&First\ Difference & Second\ Difference \\-2& &4&2-4=-2\\-1& &2&1-2=-1&-1+2=1\\0& \ &1&0.5-1=-0.5&-0.5+1=0.5\\1& &0.5&0.25-0.5=-0.25&-0.25+0.5=0.25\\2& &0.25&0.125-0.25=-0.125\\3& &0.125\end{array}\right\)

So, In the above table we can see that second difference  is not equal that means it is not in quadratic relationship.

Now,

Let Table D;

\(\left \begin{array}{ccccc}x& \ &f(x)&First\ Difference & Second\ Difference \\-2& &-23.4&\\-1& &-23.2&-23.2+23.4=-0.2&0.2-0.2=0\\0& \ &-23&-23+23.2=-0.2&0.2-0.2=0\\1& &-22.8&-22.8+23=-0.2&0.2-0.2=0\\2& &-22.6&-22.6+22.8=-0.2\\3& &-22.4&-22.4+22.6=-0.2\end{array}\right\)

So, here in this table, we can see that second difference  is equal that means it is in quadratic relationship.

Hence, we can say that the table which  represents a quadratic relationship is in option \(D\).

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We can Identify the Valid Equivalance values if the option c) 29,30,31 student clears the exam.

The values that the system or component being tested need to be able to accept are known as valid partitions. The "Valid Equivalence Partition" is the name given to this partition. The values that the component or system under test should reject are known as invalid partitions. The "Invalid Equivalence Partition" is the name of this partition.

For the purpose of the student passing the exam, the values of marks that they can obtain that are equal to or higher than the minimum required marks to pass the exam, which is 24 marks, are regarded real equivalency values. In this case, 29, 30, 31, and all mark values higher than 31 are valid equivalence values.

The appropriate selections are (c), 29, 30, and 31.

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Answer: y + 7x = -6

Step-by-step explanation:

Standard form: Ax + By = c, where a, b, and c are constants.

Distribute

y - 8 = -7x - 14

Add 8 and 7x to both sides:

y + 7x = -6

Hope it helps :)

The standard form of the equation is y = -7x-14

An equation is a mathematical statement that shows that two mathematical expressions are equal.

Given an equation, y-8 = -7(x+2)

We know that standard form of an equation of a line is y = mx+c

Converting into standard form,

y-8 = -7(x+2)

y-8 = -7x-14

y = -7x-14+8

y = -7x-6

Hence, The standard form of the equation is y = -7x-14

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Answer:

A

Step-by-step explanation:

Answer:

Steps:

given:

C(x) = 15x + 48,000

R(x) = 18x

15x + 48,000 = 18x

18x - 15x = 48,000

3x = 48,000

x = 48,000/3

x = 16,000

Check:

C(16,000) = 15×16,000 + 48,000 = 240,000 + 48,000 = 288,000

R(16,000) = 18×16,000 = 288,000

The area of the figure ABDECA, and the coordinates of the points on the quadrilateral are;

1. The area is about 15.16 units²

2. The coordinates of the points are;

(i) B(5, 8)

(ii) C(8.58, 4)

(ii) D(8,58, 1.21)

A quadrilateral is a four sided polygon.

1. The coordinate of the point C can be found as follows;

Let (x, y) represent the coordinates of the C, we get;

(x + 8)/2 = 5

x = 2 × 5 - 8 = 2

(y + 8)/2 = 6

y = 2 × 6 - 8 = 4

The coordinates ot the point C (2, 4)

The length of the segment BC = √((8 - 2)² + (8 - 4)²) = 2·√(13)

Length of the side AB = √((8 - 6)² + (8 - 11)²) = √(4 + 9) = √(13)

The area of the triangle ABC = (1/2) × 2·√(13) × √(13) = 13

CE is perpendicular to DE, let (a, b), represent the coordinates of the point E, therefore;

(4 - y)/(2 - x) = -(5 - x)/(6 - y)

y - 4 = (-4/7)(x - 2)

y - 6 = (7/4)(x - 5)

(-4/7)(x - 2) + 4 = (7/4)(x - 5) + 6

x = (17/5) = 3.4

y = (7/4)((17/5) - 5) + 6 = 3.2

The coordinates of the point E is (3.4, 3.2)

The length of the side DE = √((5 - 3.4)² + (6 - 3.2)²) = √(10.4)

Length of the side CE = √((3.2 - 2)² + (3.4 - 4)²) = √(1.8)

Area of the triangle ΔCDE = (1/2) × √(10.4) × √(1.8)

Area of the figure is therefore;

2. The equation of the line AB is; y - 6 = (1/3)·(x - (-1))

y - 6 = (1/3)·(x + 1)

y = (1/3)·(x + 1) + 6

The slope of the segment AE = (4 - 6)/(3 - (-1)) = -1/2

Slope of the segment BE = -1/(-1/2) = 2

Equation of BE is; y - 4 = 2·(x - 3)

y = 2·(x - 3) + 4 = (1/3)·(x + 1) + 6

Therefore, x = 5

y = (1/3)·(5 + 1) + 6 = 8

(ii) Area of the triangle EBC = 24 unit²

EB = (1/2) × √((5 - 3)² + (8 - 4)²) = √20

Therefore;

BC = 24/(√20) = 12/√5 = 12·√5/5 = √(28.8)

(x - 5)² + (y - 8)² = 28.8

y = 4, therefore;

(x - 5)² + (4 - 8)² = 28.8

(x - 5)² = 28.8 - (4 - 8)² = 12.8

x = √(12.8) + 5

(iii) The equation of the segment AD is; y - 4 = (-1/2)(x - 3)

x = √(12.8) + 5

Therefore;

y - 4 = (-1/2)((√(12.8) + 5) - 3)

y = (-1/2)((√(12.8) + 5) - 3) + 4 ≈ 1.21

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Answer: 3x+4-5x

Step-by-step explanation:

3x+4=5x

3x+4-5x=0

The probability of the event of getting exactly 5 heads in 8 tosses of a coin(assuming unbiased coin) is given by: Option C: 0.219 (approximately).

Binomial distributions consists of n independent Bernoulli trials.

Bernoulli trials are those trials which end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining binomial distribution with parameters n and p, then it is written as

\(X \sim B(n,p)\)

The probability that out of n trials, there'd be x successes is given by

\(P(X =x) = \: ^nC_xp^x(1-p)^{n-x}\)

The expected value and variance of X are:

\(E(X) = np\\ Var(X) = np(1-p)\)

For this case, we've got:

Each coin flip is a bernoulli distribution as it has two possible outcomes (assuming any other outcome like coin landing standing straight etc ignored). Take success = getting head in a flip, and failure = not getting success= not getting head = getting tail as the outcome of the flip.

Now, each of those 8 flips are independent in terms of result of each other (assuming coin stays unbiased).

If we take:

X = number of heads out of those 8 flips = number of successes in those 8 bernoulli trials, then:

\(X \sim B(n = 8, p)\)

where p is the probability of success = P(Getting head in an unbiased coin with head or tail as only possible outcomes) = 1/2 = 0.5 (as head can come in 1 way, and total outcomes is 2, all equally likely).

Thus, we get:

\(X \sim B(n = 8, p=0.5)\)

Now, P(Exactly 5 heads in those 8 flips) = P(X = 5)

Using the probability function of the binomial distribution, we get:

\(P(X = 5) = \: ^8C_5(0.5)^5(0.5)^{8-5} = \dfrac{8\times 7\times 6\times 5\times 4}{5 \times 4 \times 3\times 2 \times 1} \times (0.5)^8 \approx 0.219\)

Thus, the probability of the event of getting exactly 5 heads in 8 tosses of a coin(assuming unbiased coin) is given by: Option C: 0.219 (approximately).

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Answer:

b

Step-by-step explanation:

Basically the line in the centers of each are obviously not lined up, so they cant be the same, A is out, it looks to be about 6 points lower. B stays as a choice, Class A's median score is obviously lower than Class B's, as the line in the box is further behind. So C is out, and Class B's line, lines up with 85, not 70

Answer:

b

Step-by-step explanation:

enjoy

Answer:

a= -1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

The values of variables in the equation are a= -1, b=-9, c=9, d=3, e=3, f=2, g=1.5

Two or more expressions with an Equal sign is called as Equation.

The given equation is 3x/2x-6 + 9/6-2x = 3x/2x-6 + 9/-1(2x-6)

We have to find the values of variables

3x/2x-6 + 9/6-2x = 3x/2x-6 + 9/-1(2x-6)

so a=-1

= 3x/2x-6 - 9/(2x-6)

b=-9

=3x-9/2x-6

c=9

=3(x-3)/2(x-3)

d=3, e=3 and f=2

=3/2

g=1.5

Hence, the values of variables in the equation are a= -1, b=-9, c=9, d=3, e=3, f=2, g=1.5

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Answer:A school bus provides a safe way of transportation for your child. Learn resources to talk to your child about school bus and bus stop safety.

Step-by-step explanation:

Answer:

-2,1,6,13,22

Step-by-step explanation:

cn = n^2 -3

Let n=1

c1 = 1^2 -3 = 1-3 = -2

Let n=2

c2 = 2^2 -3 = 4-3 = 1

Let n=3

c3 = 3^2 -3 = 9-3 = 6

Let n=4

c4 = 4^2 -3 = 16-3 = 13

Let n=5

c5 = 5^2 -3 = 25-3 = 22

Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

\(D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}\)

The odd multiples of 9, \(m\), in the range \(2\le m \le 82\) form the set

\(\{9,27,45,63,81\}\)

Each member of the set is a term of the arithmetic progression

\(U_n=18n+9\)

where the values of \(n\) range from 0 to 4, or \(0\le n\le 4\)

Putting these facts together, we get the result

\(D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}\)

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Answer:

(2,-1)

Step-by-step explanation:

We can use substitution to solve this system of equations. Since x is already solved for in the second equation, we can substitute 2y + 4 for x in the first equation:

4(2y + 4) + 2y = 6

Simplifying the left side:

8y + 16 + 2y = 6

Combining like terms:

10y + 16 = 6

Subtracting 16 from both sides:

10y = -10

Dividing both sides by 10:

y = -1

Now that we know y, we can use the second equation to find x:

x = 2y + 4

x = 2(-1) + 4

x = 2

Therefore, the solution to the system of equations is (x, y) = (2, -1).

The correct answer choice is (2, -1).

We don't have claim to strength of composite B is smaller than the strength of composite B by at least 2 [N].

From the given data we calculate μ₁s₁ and μ₂s₂ mean and standard deviation of samples A and B respectively.

μ₁ = 464.7, s₁ = 13.42 composite A

μ₂ = 479.49, s₂ = 13.38 composite B

n₁ : n₂ < 30 then we will use t-table.

Null hypothesis  H₀:μ₂-μ₁ ≥ 2

Alternative hypothesis Hₐ : μ₂ - μ₁ < 2

assuming CI 95%

α = 5% = 0.05

and degree of freedom is n₁ + n₂ - 2 = 9 + 9 - 2 = 16

then for the one tail t(c) = 1.746  

now we will compute t(s),

t(s) = (μ₂ - μ₁ - 2)/ sp×√1/n₁ + 1/n₂

sp²= (n₁ - 1) × s₁² + (n₂ - 1) × s₂² / n₁ + n₂ - 2

    = 8 × (13.42)² + 8 × (13.38)²/ 16

     = (8 × 180.1 + 8 × 179) / 16

sp² = 179.55

sp = 13.40

Therefore

t(s) = (479.49 - 464.7 - 2)/ 13.40 ×√1/9+1/9

     = 12.79 / 13.40 × 0.4714

     = 12.79 / 6.32

t(s) = 2.02

t(s) > t(c)

t(s) is rejection region.

Therefore we reject H₀

so we don't have evidence to claim to strength pf composite B is smaller than the strength of composite B at least 2 [N].

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There are 4 hundred billions in the number 432,845,979,484.

To determine how many hundred billions are in the number 432,845,979,484, we need to consider the place value of the hundred billions digit.

The number 432,845,979,484 has 12 digits, and we count the digits from right to left, starting with the units place. The digit in the hundred billions place is the seventh digit from the right.

Let's break down the number:

4 hundred billions (4 x 100,000,000,000)

3 ten billions (3 x 10,000,000,000)

2 billions (2 x 1,000,000,000)

8 hundred millions (8 x 100,000,000)

4 ten millions (4 x 10,000,000)

5 millions (5 x 1,000,000)

9 hundred thousands (9 x 100,000)

7 ten thousands (7 x 10,000)

9 thousands (9 x 1,000)

4 hundreds (4 x 100)

8 tens (8 x 10)

4 units (4 x 1)

As we can see, there are 4 hundred billions in the number 432,845,979,484.

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The value of angle x is 149°

Angles in parallel lines are angles that are created when two parallel lines are intersected by another line called a transversal.

Since MN and OP are parallel lines, we can introduce a transverse that will cut through Q and extend the parallel lines of MN and OP

Therefore;

The adjascent angle of N will be

180-138 = 42°

This means that angle Q is divided into 42° and 31° i.e 42+31 = 73°

This means the adjascent angle of P is 31°( alternate angles)

Therefore x = 180-31

x = 149°

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Answer: the second one

Step-by-step explanation:

Relations in the options (a), (b) and (e) are the Equivalence relations as, the relations are reflexive, symmetric and transitive all.

Given, five relations as,

a) {(a, b) | a and b are the same age}

b) {(a, b) | a and b have the same parents}

c) {(a, b) | a and b share a common parent}

d) {(a, b) | a and b have met}

e) {(a, b) | a and b speak a common language}

we have to find which of them are equivalence relations

a) as, (a , a) ∈ R ∀ a hence, Reflexive.

also, if (a , b) ∈ R then (b , a) ∈ R ∀ a, b. Hence, Symmetric.

and if (a , b) ∈ R & (b , c) ∈ R then (a , c) ∈ R ∀ a, b, c. Hence, Transitive.

So, R = {(a, b) | a and b are the same age} is an equivalence relation.

b) as, (a , a) ∈ R ∀ a hence, Reflexive.

also, if (a , b) ∈ R then (b , a) ∈ R ∀ a, b. Hence, Symmetric.

and if (a , b) ∈ R & (b , c) ∈ R then (a , c) ∈ R ∀ a, b, c. Hence, Transitive.

So, R = {(a, b) | a and b have the same parents} is an equivalence relation.

c) as, (a , a) ∈ R ∀ a hence, Reflexive.

also, if (a , b) ∈ R then (b , a) ∈ R ∀ a, b. Hence, Symmetric.

and if (a , b) ∈ R & (b , c) ∈ R then (a , c) need not to be in R for some a, b, c. Hence, Non - Transitive.

So, R = {(a, b) | a and b share a common parent} is not an equivalence relation.

d) as, (a , a) ∈ R ∀ a hence, Reflexive.

also, if (a , b) ∈ R then (b , a) ∈ R ∀ a, b. Hence, Symmetric.

and if (a , b) ∈ R & (b , c) ∈ R then (a , c) need not to be in R for some a, b, c. Hence, Non - Transitive.

So, R = {(a, b) | a and b have met} is not an equivalence relation.

e) as, (a , a) ∈ R ∀ a hence, Reflexive.

also, if (a , b) ∈ R then (b , a) ∈ R ∀ a, b. Hence, Symmetric.

and if (a , b) ∈ R & (b , c) ∈ R then (a , c) ∈ R ∀ a, b, c. Hence, Transitive.

So, R = {(a, b) | a and b speak a common language} is an equivalence relation.

Hence, the relations in options (a) , (b) and (e) are the equivalence relations.

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Vector v and w have lengths of 11 and contain elements of 21, 10, 32, 2, -3, 4, 5, 6, 7, 4, -22 and -18, 72, 11, -9, 10, 2, 34, -5, 18, 9, 2 respectively. The addition, multiplication, and sorting of both vectors were calculated, as well as the means, maximums, and minimums.

a) The lengths of the vectors v and w are both 11.

b) Vector v contains the elements 21, 10, 32, 2, -3, 4, 5, 6, 7, 4, -22 and vector w contains the elements -18, 72, 11, -9, 10, 2, 34, -5, 18, 9, 2.

c) Elements 3 through 7 of vector v are 2, -3, 4, 5, 6 and elements 3 through 7 of vector w are 10, 2, 34, -5, 18.

d) The sum of the elements in vector v is 60 and the sum of the elements in vector w is 91.

e) The mean of vector v is 5.454545454545455 and the mean of vector w is 8.272727272727273.

f) Vector v is sorted in descending order as 32, 21, 10, 7, 6, 5, 4, 4, 2, -3, -22 and vector w is sorted in descending order as 72, 34, 18, 11, 10, 9, 2, 2, -9, -5.

g) The addition of vectors v and w is 53, 82, 28, 2, 7, 13, 6, 8, -7, 4, -20.

h) The multiplication of vectors v and w is -378, 720, 352, -18.

i) Elements in vector v that are greater than zero are 21, 10, 32, 2, 4, 5, 6, 7, 4.

j) Elements in vector w that are less than zero are -18, -9, -5.

k) Vector v multiplied by 6 is 126, 60, 192, 12, -18, 24, 30, 36, 42, 24, -132.

l) The maximum of vector v is 32 and the minimum of vector v is -22. The maximum of vector w is 72 and the minimum of vector w is -9.

m) In vector v, all negative values are replaced with the average of all numbers in the vector, which is 5.454545454545455. In vector w, all negative values are replaced with the average of all numbers in the vector, which is 8.272727272727273.

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Cos 45 = 7/x

0.707 = 7/x

x= 9.9

sin 45= 7/x

0.707= 7/x

x = 9.9

Answer:10.546

Step-by-step explanation:

0.76+9.786=10.546

Answer:

Step-by-step explanation:

The y-intercept exists where x = 0; plug in 0 for all the x's and solve the equation for y:

\(y=-7(0)^2-10(0)+3\) and

y = 3. The coordinate that represents this is (0, 3)

Answer:

0.182.

Step-by-step explanation:

There are a total of 11 chocolates in the box.

Prob(First chocolate picked is milk) = 5/11.

Prob(Second chocolate picked is milk) = 4/10 = 2/5.

So the required probability = 5/11 * 2/5

= 10/55

= 0.182.

Answer: 10w

Step-by-step explanation:

Based on the business information, we can establish that the cash value in a balance sheet is Bs. 33,500.

To find the cash value in a balance sheet we must perform the following procedure:

We must find the difference between the passives and assets of the business as shown below:

Assets

Passives

According to the above, the operation is as follows:

According to the above, the cash value in a balance sheet would be Bs. 33,500.

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Answer:

6n+2

Step-by-step explanation: